class 'Exception', unable to use 'super' to call superclass initializer
Hi, environment: Python 2.4, GNU/Linux, kernel 2.6.12.2 having subclassed 'Exception' I'm trying to call the initialiser __init__(...) of the superclass Exception with 'super(..).__init__(..)' . However, trying to do so results in a 'TypeError: super() argument 1 must be type, not classobj'. Now, if I use 'Exception.__init__(..)' instad of super(..)... ,everything works just as one would expect. Why does 'super(..).__init__(..)' fail? thank you for any suggestions chriss Here is some example code to illustrate the point: class WorkingException(Exception): def __init__(self, message): # works as I would expect Exception.__init__(self, message) class BrokenException(Exception): def __init__(self, message): # fails with a typeError super(BrokenException, self).__init__(self, message) # - case 1 - try: raise WorkingException(Hello WorkingException) except WorkingException, e: print e # - case 3 - try: raise BrokenException(Hello BrokenException) except BrokenException, e: print e -- http://mail.python.org/mailman/listinfo/python-list
Re: class 'Exception', unable to use 'super' to call superclass initializer
chriss wrote: Hi, environment: Python 2.4, GNU/Linux, kernel 2.6.12.2 having subclassed 'Exception' I'm trying to call the initialiser __init__(...) of the superclass Exception with 'super(..).__init__(..)' . However, trying to do so results in a 'TypeError: super() argument 1 must be type, not classobj'. Now, if I use 'Exception.__init__(..)' instad of super(..)... ,everything works just as one would expect. Why does 'super(..).__init__(..)' fail? AFAICT, the Exception hierarchy are still old-style classes while super() only works on new-style classes. -- Robert Kern [EMAIL PROTECTED] In the fields of hell where the grass grows high Are the graves of dreams allowed to die. -- Richard Harter -- http://mail.python.org/mailman/listinfo/python-list
Re: class 'Exception', unable to use 'super' to call superclass initializer
chriss wrote: Hi, environment: Python 2.4, GNU/Linux, kernel 2.6.12.2 having subclassed 'Exception' I'm trying to call the initialiser __init__(...) of the superclass Exception with 'super(..).__init__(..)' . However, trying to do so results in a 'TypeError: super() argument 1 must be type, not classobj'. Now, if I use 'Exception.__init__(..)' instad of super(..)... ,everything works just as one would expect. Why does 'super(..).__init__(..)' fail? Exceptions do not inherit from 'object'; they are old-style classes. super() can be used only with new-style classes (which subclass 'object'). -Peter -- http://mail.python.org/mailman/listinfo/python-list
Re: class 'Exception', unable to use 'super' to call superclass initializer
Peter Hansen wrote: chriss wrote: Hi, environment: Python 2.4, GNU/Linux, kernel 2.6.12.2 having subclassed 'Exception' I'm trying to call the initialiser __init__(...) of the superclass Exception with 'super(..).__init__(..)' . However, trying to do so results in a 'TypeError: super() argument 1 must be type, not classobj'. Now, if I use 'Exception.__init__(..)' instad of super(..)... ,everything works just as one would expect. Why does 'super(..).__init__(..)' fail? Exceptions do not inherit from 'object'; they are old-style classes. super() can be used only with new-style classes (which subclass 'object'). -Peter That explains it all right. Thank you very much for your answer. chriss -- http://mail.python.org/mailman/listinfo/python-list
