Re: os.path.normpath question
Bart wrote:
> I'm using this and ran across backslash issues in one of my paths.
>
> archpath = os.path.normpath('E:\foo\FTP\HLS\archive')
>
> was translating to:
>
> E:\lsfprod\law\uch_interfaces\FTP\HLSrchive
>
> which caused me to start using the 'raw' declaration before the path
> string like this:
>
> archpath = os.path.normpath(r'E:\foo\FTP\HLS\archive')
>
> Is this the right way to use this?
>
If you want to use raw strings for Windows paths then you need to be aware
that you cannot end a raw string with a backslash.
In most cases you can just use forward slashes instead and then you don't
need to worry about escaping them:
archpath = os.path.normpath('E:/foo/FTP/HLS/archive')
Or better still, don't put hardwired paths into your application, put them
all in a config file.
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Re: os.path.normpath question
Bart wrote:
> I'm using this and ran across backslash issues in one of my paths.
>
> archpath = os.path.normpath('E:\foo\FTP\HLS\archive')
>
> was translating to:
>
> E:\lsfprod\law\uch_interfaces\FTP\HLSrchive
>
> which caused me to start using the 'raw' declaration before the path
> string like this:
>
> archpath = os.path.normpath(r'E:\foo\FTP\HLS\archive')
>
> Is this the right way to use this?
Yes, but os.path.normpath() has nothing to with it. It's just how Python
translates any string literal to a string object, see
http://docs.python.org/reference/lexical_analysis.html#string-literals
Peter
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os.path.normpath question
I'm using this and ran across backslash issues in one of my paths.
archpath = os.path.normpath('E:\foo\FTP\HLS\archive')
was translating to:
E:\lsfprod\law\uch_interfaces\FTP\HLSrchive
which caused me to start using the 'raw' declaration before the path
string like this:
archpath = os.path.normpath(r'E:\foo\FTP\HLS\archive')
Is this the right way to use this?
--
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Re: More precise document on os.path.normpath()
Peng Yu wrote: After I tried os.path.normpath(), it is clear that the function doesn't return the trailing '/', if the path is a directory. But this fact is not documented. Should this be documented in future release of python. Also, I found the documentation of some functions in os.path are not clear. I have to try them in order to understand them for corner cases. I'm wondering if I can join the people who maintain the document to help improve it. os.path is designed for OS-agnostic path manipulation. The textual representation of the output of os.path is irrelevant. If a trailing '/' doesn't affect the ability to open the directory or file or os.path.join or whatever, it is irrelevant to os.path. If the trailing / does affect those abilities, though, it is a bug in os.path. -- http://mail.python.org/mailman/listinfo/python-list
Re: More precise document on os.path.normpath()
On Nov 23, 5:59 pm, Benjamin Kaplan wrote: > On Mon, Nov 23, 2009 at 8:52 PM, Peng Yu wrote: > > After I tried os.path.normpath(), it is clear that the function > > doesn't return the trailing '/', if the path is a directory. But this > > fact is not documented. Should this be documented in future release of > > python. > > > Also, I found the documentation of some functions in os.path are not > > clear. I have to try them in order to understand them for corner > > cases. I'm wondering if I can join the people who maintain the > > document to help improve it. > > Just file a bug report listing what part you find unclear and what you > suggest they put to clarify it. The documentation does not and should not try to document every little detail of every function. For that matter, nor should comp.lang.python. Python is open source, anyone can look at the implementation to see how it behaves. The source code is the right place to seek answers about arcane minutae like when os.path.normpath appends a backslash. Not the Python docuementation, and definitely not this newsgroup. Carl Banks -- http://mail.python.org/mailman/listinfo/python-list
Re: More precise document on os.path.normpath()
On Mon, Nov 23, 2009 at 8:52 PM, Peng Yu wrote: > After I tried os.path.normpath(), it is clear that the function > doesn't return the trailing '/', if the path is a directory. But this > fact is not documented. Should this be documented in future release of > python. > > Also, I found the documentation of some functions in os.path are not > clear. I have to try them in order to understand them for corner > cases. I'm wondering if I can join the people who maintain the > document to help improve it. > -- Just file a bug report listing what part you find unclear and what you suggest they put to clarify it. > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list
More precise document on os.path.normpath()
After I tried os.path.normpath(), it is clear that the function doesn't return the trailing '/', if the path is a directory. But this fact is not documented. Should this be documented in future release of python. Also, I found the documentation of some functions in os.path are not clear. I have to try them in order to understand them for corner cases. I'm wondering if I can join the people who maintain the document to help improve it. -- http://mail.python.org/mailman/listinfo/python-list
os.path.normpath() for URLs?
Hi, I'm currently trying to parse relative URLs, but I want to make them absolute. In other words, I want to normalize the URLs. However, I don't want to have to write this logic myself if it is already provided. I was thinking of somehow tricking os.path.normpath() as a last resort. This is for subversion URLs, for those wondering. Basically, I need to turn the following URL: svn://myserver/foo/bar/trunk/../tags Into this: svn://myserver/foo/bar/tags Does anyone know a way I can do this? Thanks. -- http://mail.python.org/mailman/listinfo/python-list
Re: os.path.normpath bug?
On 14 Giu, 22:35, Michael Hoffman <[EMAIL PROTECTED]> wrote: > Intentional. > > http://en.wikipedia.org/wiki/Path_(computing)#Universal_Naming_Conven... > -- > Michael Hoffman Got it. Thank you. -- http://mail.python.org/mailman/listinfo/python-list
Re: os.path.normpath bug?
billiejoex wrote:
> Hi there,
> I've noticed that os.path.normpath does not collapse redundant
> separators if they're located at the beginning of the string:
>
>>>> print os.path.normpath('/a//b//c')
> \a\b\c
>>>> print os.path.normpath('//a//b//c')
> \\a\b\c
>
> Is it intentional or is it a bug?
Intentional.
http://en.wikipedia.org/wiki/Path_(computing)#Universal_Naming_Convention
--
Michael Hoffman
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os.path.normpath bug?
Hi there,
I've noticed that os.path.normpath does not collapse redundant
separators if they're located at the beginning of the string:
>>> print os.path.normpath('/a//b//c')
\a\b\c
>>> print os.path.normpath('//a//b//c')
\\a\b\c
Is it intentional or is it a bug?
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Re: os.path.normpath
placid wrote: > Hi all, > > I was just wondering if there is a anti-os.path.normpath function? For > example if i have the path "C:\Program Files\Games" i want to > anti-os.path.normpath is so that it becomes "C:\\Program Files\\Games" > ? > > Cheers Ahh ignore my post. I was using abspath, and normpath is what i what. Doh, stupid me! Cheers -- http://mail.python.org/mailman/listinfo/python-list
os.path.normpath
Hi all, I was just wondering if there is a anti-os.path.normpath function? For example if i have the path "C:\Program Files\Games" i want to anti-os.path.normpath is so that it becomes "C:\\Program Files\\Games" ? Cheers -- http://mail.python.org/mailman/listinfo/python-list
Re: os.path.normpath
Hari Sekhon wrote .. > [EMAIL PROTECTED] wrote: > > [EMAIL PROTECTED] wrote: > > > >> I am using a windows box and passing a string like "../foo/../foo2" > to > >> normpath which then returns "..\\foo2". But if this string is going > >> into a webpage link it should really be "../foo". > >> > >> Is there any way to tell os.path.normpath to act like we are an a unix > >> style box? > >> > > > > Use posixpath.normpath() instead. > > > > > I can't seem to find posixpath in the docs, but I can import posixpath > and a dir shows it does indeed have a normpath. Quoting: http://www.python.org/doc/2.3.5/lib/node750.html it says: posixpath -- Implementation of os.path on POSIX. What it provides is therefore documented by os.path module. The posixpath module is still accessible on non POSIX platforms though. Graham -- http://mail.python.org/mailman/listinfo/python-list
Re: os.path.normpath
[EMAIL PROTECTED] wrote: [EMAIL PROTECTED] wrote: I am using a windows box and passing a string like "../foo/../foo2" to normpath which then returns "..\\foo2". But if this string is going into a webpage link it should really be "../foo". Is there any way to tell os.path.normpath to act like we are an a unix style box? Use posixpath.normpath() instead. I can't seem to find posixpath in the docs, but I can import posixpath and a dir shows it does indeed have a normpath. -h -- http://mail.python.org/mailman/listinfo/python-list
Re: os.path.normpath
[EMAIL PROTECTED] wrote: > I am using a windows box and passing a string like "../foo/../foo2" to > normpath which then returns "..\\foo2". But if this string is going > into a webpage link it should really be "../foo". > > Is there any way to tell os.path.normpath to act like we are an a unix > style box? Use posixpath.normpath() instead. -- http://mail.python.org/mailman/listinfo/python-list
Re: os.path.normpath
At Wednesday 9/8/2006 15:45, [EMAIL PROTECTED] wrote:
I am using a windows box and passing a string like "../foo/../foo2" to
normpath which then returns "..\\foo2". But if this string is going
into a webpage link it should really be "../foo".
You could just .replace('\\','/') on the resulting string. Or use the
urlparse module.
Is there any way to tell os.path.normpath to act like we are an a unix
style box?
The fact than '/' is used as a path separator both on unix and on
HTTP URLs should be considered as a mere coincidence (in fact it isn't...)
URLs dont necesarily point to a real file on a real file system (Zope
is an example).
Gabriel Genellina
Softlab SRL
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Re: os.path.normpath
[EMAIL PROTECTED] wrote: > But if this string is going into a webpage link http://docs.python.org/lib/module-urlparse.html rd -- http://mail.python.org/mailman/listinfo/python-list
os.path.normpath
I am using a windows box and passing a string like "../foo/../foo2" to normpath which then returns "..\\foo2". But if this string is going into a webpage link it should really be "../foo". Is there any way to tell os.path.normpath to act like we are an a unix style box? What about in the new python 2.5 Path class? Nathan -- http://mail.python.org/mailman/listinfo/python-list
