Re: problem with Sorting from Array
On Wed, Feb 2, 2011 at 10:30 PM, shanti bhushan wrote: > Dear All, > > funtion "textPosValue " will give me key ,type and pos values from the > arrays. > This an embedded application code . > I want to execute some thing when key ==0 && type ==0 please let me > if (key ==0 && type ==0) // i > want The logical-AND operator in Python is spelled "and", not "&&" as in C-like languages. Also, comments start with a "#", not with "//" (though you probably already know this and seem to have merely had a momentary lapse). I can offer no definitive guidance as to where the conditional belongs due to your code's purpose being rather opaque. I would hazard a guess that it should go near where you change the values of `key` and `type` (since the condition depends upon them) and outside of any nested loop (since you mentioned nothing about repetition). Cheers, Chris -- http://blog.rebertia.com -- http://mail.python.org/mailman/listinfo/python-list
problem with Sorting from Array
Dear All,
funtion "textPosValue " will give me key ,type and pos values from the
arrays.
This an embedded application code .
I want to execute some thing when key ==0 && type ==0 please let me
know
where to put such code i am getting confused with it
def textPosValue(data):
str_arr1=[" 0",".@/:1","abc2",
"def3","ghi4",
"jkl5","mno6",
"pqrs7","tuv8",
"wxyz9" ]
str_arr2=[" 0",".@/:1","ABC2",
"DEF3","GHI4",
"JKL5","MNO6",
"PQRS7","TUV8",
"WXYZ9" ]
str_arr3=["0","1","2",
"3","4","5",
"6","7","8",
"9" ]
str_arr4=[" 0",".@/:1","?[] 2",
"!<> 3",",&\ 4",
"()~ 5","'{}` 6",
";$|^ 7","_#% 8",
"-*+=9" ]
str=[str_arr1,str_arr2,str_arr3,str_arr4]
k=1
first=0
SecPos=0
sts=0
try:
for first in range(4):
for SecPos in range(10):
#print "first,SecPos,str[first]
[Secpos]",first,SecPos,str[first][SecPos]
sts=str[first][SecPos].find(data)
#print sts
if (sts < 0):
continue
else:
k=0
break
if (k==0):
print sts
break
return first, SecPos, sts
except IndexError:
return -1,-1,-1
for ch in "43.88.79.132" :
type,key,Pos=textPosValue(ch)
for i in range(type):
cat,data=remote_keypress("green")
send_sircs(cat,data)
sleep(0.5)
for j in range(Pos+1):
if (key ==0 && type ==0) // i
want
to execute some thing when , key ==0 && type ==0 , is it the right
position??
cat,data=remote_keypress("space")
send_sircs(cat,data)
sleep(0.5)
cat,data=remote_keypress("violet")
send_sircs(cat,data)
sleep(0.5)
cat,data=remote_keypress(key)
send_sircs(cat,data)
sleep(0.5)
sleep(0.5)
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Re: problem with sorting
Duncan Booth: > Both this and raj's suggestion create a single sorted list. Your suggestion > creates two lists: the unsorted one and a separate sorted one. In most > cases the difference is probably insignificant, but if you have a *lot* of > values it might make a difference. The good thing of Python 3.0 is that it forces you to do the right thing here :-) Bye, bearophile -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with sorting
[EMAIL PROTECTED] wrote: > On Mar 28, 1:57ÿam, raj <[EMAIL PROTECTED]> wrote: >> To ankit: >> >> Well, sort() doesn't return the sorted list. It returns None. Why not >> this straightforward way? >> dvals = dict.values() >> dvals.sort() >> print dvals > > Why not sorted( dict.values() ). > If you are going to do it that way then it may be preferable to use itervalues: print sorted(dict.itervalues()) Both this and raj's suggestion create a single sorted list. Your suggestion creates two lists: the unsorted one and a separate sorted one. In most cases the difference is probably insignificant, but if you have a *lot* of values it might make a difference. -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with sorting
On Mar 28, 1:57 am, raj <[EMAIL PROTECTED]> wrote: > To ankit: > > Well, sort() doesn't return the sorted list. It returns None. Why not > this straightforward way? > dvals = dict.values() > dvals.sort() > print dvals Why not sorted( dict.values() ). Can it return the right things from the right things in order from the givens? ( dvals , values, sort, print ).decode() -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with sorting
To ankit: Well, sort() doesn't return the sorted list. It returns None. Why not this straightforward way? dvals = dict.values() dvals.sort() print dvals -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with sorting
On Mar 28, 5:38 am, [EMAIL PROTECTED] wrote:
> >>> dict = {'M':3, 'R':0, 'S':2}
> >>> print dict
>
> {'S': 2, 'R': 0, 'M': 3}
>
> now if I wanted sorted values in list, i am not able to do this>>> print
> dict.values().sort()
>
> None
>
> it returns None instead of [0, 2, 3]
The sort method works by sorting 'in place'. That means it doesn't
return the sorted value, but just sorts the sequence.
>>> t = {'M':3, 'R':0, 'S':2}
>>> x = t.values()
>>> x.sort()
>>> x
[0, 2, 3]
or you can use sorted(), which does return the sorted sequence:
>>> sorted(t.values())
[0, 2, 3]
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Re: problem with sorting
On Mar 28, 5:38 am, [EMAIL PROTECTED] wrote:
> >>> dict = {'M':3, 'R':0, 'S':2}
> >>> print dict
>
> {'S': 2, 'R': 0, 'M': 3}
>
> now if I wanted sorted values in list, i am not able to do this>>> print
> dict.values().sort()
>
> None
>
> it returns None instead of [0, 2, 3]
Try:
from pprint import pprint as pp
pp(my_dict)
It works well for other built-in types too.
P.S it is not good to use a name, dict, that already has a use in
Python.
- Paddy.
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problem with sorting
>>> dict = {'M':3, 'R':0, 'S':2}
>>> print dict
{'S': 2, 'R': 0, 'M': 3}
now if I wanted sorted values in list, i am not able to do this
>>> print dict.values().sort()
None
it returns None instead of [0, 2, 3]
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