Re: searching an XML doc
On Jan 15, 9:33 pm, Gowri [EMAIL PROTECTED] wrote:
Hello,
I've been reading about ElementTreee and ElementPath so I could use
them to find the right elements in the DOM. Unfortunately neither of
these seem to offer XPath like capabilities where I can find elements
based on tag, attribute values etc. Are there any libraries which can
give me XPath like functionality?
Thanks in advance
Create your query like:
ns0 = '{http://a.b.com/phedex}'
query = '%srequest/%sstatus' % (ns0, ns0)
Also, although imperfect, some people have found this useful:
http://gflanagan.net/site/python/utils/elementfilter/elementfilter.py.txt
[CODE]
test = '''phedexData xmlns=http://a.b.com/phedex;
xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;
xsi:schemaLocation=http://a.b.com/phedex requests.xsd
!-- Low priority replication request --
request id=1234 last_update=1060199000.0
status
approvedT1_RAL_MSS/approved
approvedT2_London_ICHEP/approved
disapprovedT2_Southgrid_Bristol/
disapproved
pending/
move_pending/
/status
subscription open=1 priority=0 type=replicate
items
dataset/PrimaryDS1/ProcessedDS1/
Tier/dataset
block/PrimaryDS2/
ProcessedDS2/Tier/block/block
/items
/subscription
/request
/phedexData
'''
from xml.etree import ElementTree as ET
root = ET.fromstring(test)
ns0 = '{http://a.b.com/phedex}'
from rattlebag.elementfilter import findall, data
#http://gflanagan.net/site/python/utils/elementfilter/
elementfilter.py.txt
query0 = '%(ns)srequest/%(ns)sstatus' % {'ns': ns0}
query1 = '%(ns)srequest/%(ns)[EMAIL PROTECTED]replicate]/%
(ns)sitems' % {'ns': ns0}
query2 = '%(ns)[EMAIL PROTECTED]/%(ns)sstatus/%(ns)sapproved' %
{'ns': ns0}
print 'With ElementPath: '
print root.findall(query0)
print
print 'With ElementFilter:'
for query in [query0, query1, query2]:
print
print '+'*50
print 'query: ', query
print
for item in findall(root, query):
print 'item: ', item
print 'xml:'
ET.dump(item)
print '-'*50
print
print 'approved: ', data(root, query2)
[/CODE]
[OUTPUT]
With ElementPath:
[Element {http://a.b.com/phedex}status at b95ad0]
With ElementFilter:
++
query: {http://a.b.com/phedex}request/{http://a.b.com/phedex}status
item: Element {http://a.b.com/phedex}status at b95ad0
xml:
ns0:status xmlns:ns0=http://a.b.com/phedex;
ns0:approvedT1_RAL_MSS/ns0:approved
ns0:approvedT2_London_ICHEP/ns0:approved
ns0:disapprovedT2_Southgrid_Bristol/
ns0:disapproved
ns0:pending /
ns0:move_pending /
/ns0:status
++
query: {http://a.b.com/phedex}request/{http://a.b.com/
[EMAIL PROTECTED]
==replicate]/{http://a.b.com/phedex}items
item: Element {http://a.b.com/phedex}items at b95eb8
xml:
ns0:items xmlns:ns0=http://a.b.com/phedex;
ns0:dataset/PrimaryDS1/ProcessedDS1/
Tier/ns0:
dataset
ns0:block/PrimaryDS2/
ProcessedDS2/Tier
/block/ns0:block
/ns0:items
++
query: {http://a.b.com/[EMAIL PROTECTED]/{http://a.b.com/
phedex}status/
{http://a.b.com/phedex}approved
item: Element {http://a.b.com/phedex}approved at b95cd8
xml:
ns0:approved xmlns:ns0=http://a.b.com/phedex;T1_RAL_MSS/
ns0:approved
item: Element {http://a.b.com/phedex}approved at b95cb0
xml:
ns0:approved xmlns:ns0=http://a.b.com/phedex;T2_London_ICHEP/
ns0:approved
--
approved: ['T1_RAL_MSS', 'T2_London_ICHEP']
INFO End logging.
[/OUTPUT]
--
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Re: searching an XML doc
Hi Gerard, I don't know what to say :) thank you so much for taking time to post all of this. truly appreciate it :) -- http://mail.python.org/mailman/listinfo/python-list
Re: searching an XML doc
grflanagan wrote:
On Jan 15, 9:33 pm, Gowri [EMAIL PROTECTED] wrote:
I've been reading about ElementTreee and ElementPath so I could use
them to find the right elements in the DOM. Unfortunately neither of
these seem to offer XPath like capabilities where I can find elements
based on tag, attribute values etc. Are there any libraries which can
give me XPath like functionality?
Create your query like:
ns0 = '{http://a.b.com/phedex}'
query = '%srequest/%sstatus' % (ns0, ns0)
lxml supports the same thing, BTW, and how to work with namespaces is
explained in the tutorial:
http://codespeak.net/lxml/dev/tutorial.html#namespaces
Stefan
--
http://mail.python.org/mailman/listinfo/python-list
searching an XML doc
Hello, I've been reading about ElementTreee and ElementPath so I could use them to find the right elements in the DOM. Unfortunately neither of these seem to offer XPath like capabilities where I can find elements based on tag, attribute values etc. Are there any libraries which can give me XPath like functionality? Thanks in advance -- http://mail.python.org/mailman/listinfo/python-list
Re: searching an XML doc
Gowri schrieb: Hello, I've been reading about ElementTreee and ElementPath so I could use them to find the right elements in the DOM. Unfortunately neither of these seem to offer XPath like capabilities where I can find elements based on tag, attribute values etc. Are there any libraries which can give me XPath like functionality? lxml does that. Diez -- http://mail.python.org/mailman/listinfo/python-list
Re: searching an XML doc
On Jan 15, 3:49 pm, Diez B. Roggisch [EMAIL PROTECTED] wrote: Gowri schrieb: Hello, I've been reading about ElementTreee and ElementPath so I could use them to find the right elements in the DOM. Unfortunately neither of these seem to offer XPath like capabilities where I can find elements based on tag, attribute values etc. Are there any libraries which can give me XPath like functionality? lxml does that. Diez Hi Diez I was trying lxml out and was unable to find any examples that would help me parse an XML file with namespaces. For example, my XML file looks like this: phedexData xmlns=http://a.b.com/phedex; xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance; xsi:schemaLocation=http://a.b.com/phedex requests.xsd !-- Low priority replication request -- request id=1234 last_update=1060199000.0 status approvedT1_RAL_MSS/approved approvedT2_London_ICHEP/approved disapprovedT2_Southgrid_Bristol/disapproved pending/ move_pending/ /status subscription open=1 priority=0 type=replicate items dataset/PrimaryDS1/ProcessedDS1/Tier/dataset block/PrimaryDS2/ProcessedDS2/Tier/block/block /items /subscription /request /phedexData If my Xpath query is //request, it obviously would not work. Is there some sort of namespace registration etc. that is to be done before issuing a query? Example code would help a lot. -- http://mail.python.org/mailman/listinfo/python-list
