Re: simple question on persisting variable values in a list
On Nov 20, 9:41 pm, [EMAIL PROTECTED] wrote:
> On Nov 20, 3:25 pm, [EMAIL PROTECTED] wrote:
>
>
>
> > Hi,
>
> > I am an unabashed noob.
>
> > I am trying to build a list to store values that are generated through
> > a loop. However, every time I append the variable to the list, I'd
> > like to reset the variable, but have the value persist in the loop. I
> > understand why this doesn't work because it's a reference not a
> > literal value but have been unsuccessful at using copy.copy() or
> > anything else to accomplish this:
>
> > for char in splitlines[r]:
>
> > if char == "\n":
> > temp = copy.deepcopy(templine)
> > individline.append(temp)
> > templine = ""
> > else:
> > templine += char
>
> > results.append(individline)
>
> > This just gives me the last element in splitlines[r] - what i want is
> > to persist each line that is parsed from splitlines[] into the results
> > list.
>
> > Appreciate any help,,,
>
> Not sure if this is what you want, but here's what I did:
>
>
>
> >>> x = 'blah\nblah\n'
> >>> lst = []
> >>> templine = ''
> >>> for char in x:
>
> if char == '\n':
> temp = templine
> lst.append(temp)
> templine = ''
> else:
> templine += char
No need for all that code, because you're reimplementing the 'split'
method of strings:
x = 'blah\nblah\n'
lst = x.split('\n')[:-1]
--
Paul Hankin
--
http://mail.python.org/mailman/listinfo/python-list
Re: simple question on persisting variable values in a list
On Nov 20, 3:25 pm, [EMAIL PROTECTED] wrote: > Hi, > > I am an unabashed noob. > > I am trying to build a list to store values that are generated through > a loop. However, every time I append the variable to the list, I'd > like to reset the variable, but have the value persist in the loop. I > understand why this doesn't work because it's a reference not a > literal value but have been unsuccessful at using copy.copy() or > anything else to accomplish this: > > for char in splitlines[r]: > > if char == "\n": > temp = copy.deepcopy(templine) > individline.append(temp) > templine = "" > else: > templine += char > > results.append(individline) > > This just gives me the last element in splitlines[r] - what i want is > to persist each line that is parsed from splitlines[] into the results > list. > > Appreciate any help,,, Not sure if this is what you want, but here's what I did: >>> x = 'blah\nblah\n' >>> lst = [] >>> templine = '' >>> for char in x: if char == '\n': temp = templine lst.append(temp) templine = '' else: templine += char >>> lst ['blah', 'blah'] Mike -- http://mail.python.org/mailman/listinfo/python-list
simple question on persisting variable values in a list
Hi, I am an unabashed noob. I am trying to build a list to store values that are generated through a loop. However, every time I append the variable to the list, I'd like to reset the variable, but have the value persist in the loop. I understand why this doesn't work because it's a reference not a literal value but have been unsuccessful at using copy.copy() or anything else to accomplish this: for char in splitlines[r]: if char == "\n": temp = copy.deepcopy(templine) individline.append(temp) templine = "" else: templine += char results.append(individline) This just gives me the last element in splitlines[r] - what i want is to persist each line that is parsed from splitlines[] into the results list. Appreciate any help,,, -- http://mail.python.org/mailman/listinfo/python-list
