Re: urllib.urlopen: Errno socket error

2006-11-09 Thread frifri007 

[EMAIL PROTECTED] a écrit :

 Hi,

 I'm just trying to read from a webpage with urllib but I'm getting
 IOErrors. This is my code:

 import urllib
 sock = urllib.urlopen(http://www.google.com/;)

 and this is the error:

 Traceback (most recent call last):
   File pyshell#5, line 1, in module
 sock = urllib.urlopen(http://www.google.com/;)
   File C:\Python25\lib\urllib.py, line 82, in urlopen
 return opener.open(url)
   File C:\Python25\lib\urllib.py, line 190, in open
 return getattr(self, name)(url)
   File C:\Python25\lib\urllib.py, line 325, in open_http
 h.endheaders()
   File C:\Python25\lib\httplib.py, line 856, in endheaders
 self._send_output()
   File C:\Python25\lib\httplib.py, line 728, in _send_output
 self.send(msg)
   File C:\Python25\lib\httplib.py, line 695, in send
 self.connect()
   File C:\Python25\lib\httplib.py, line 679, in connect
 raise socket.error, msg
 IOError: [Errno socket error] (10060, 'Operation timed out')

 I'm behind my company's firewall. Would that cause a problem? If it
 does, How do I get around it?


See the documentation for urllib.urlopen:


In a Windows environment, if no proxy environment variables are set,
proxy settings are obtained from the registry's Internet Settings
section.

Remove Proxy configuration under IE and try again
(don't use Ie anymore ;0)

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Re: urllib.urlopen: Errno socket error

2006-10-17 Thread kgrafals 
Dennis,

I tried a ProxyHandler with the following code ...

proxy_support = urllib2.ProxyHandler({})
opener = urllib2.build_opener(proxy_support)
urllib2.install_opener(opener)

... but it's giving me the same result.

Then I tried to tunnel using code from ...

http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/213238

... but it too gave me an error ...

Traceback (most recent call last):
  File pyshell#7, line 1, in module
tunnel.run(tunnel_this)
  File C:/Python25/My Python/PyTunnel.py, line 124, in run
Threads.append( thread_it(tid=0,proxy=self.get_proxy(),\
  File C:/Python25/My Python/PyTunnel.py, line 81, in get_proxy
proxy.connect((self._phost,self._pport))
  File string, line 1, in connect
gaierror: (11001, 'getaddrinfo failed')

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urllib.urlopen: Errno socket error

2006-10-16 Thread kgrafals 
Hi,

I'm just trying to read from a webpage with urllib but I'm getting
IOErrors. This is my code:

import urllib
sock = urllib.urlopen(http://www.google.com/;)

and this is the error:

Traceback (most recent call last):
  File pyshell#5, line 1, in module
sock = urllib.urlopen(http://www.google.com/;)
  File C:\Python25\lib\urllib.py, line 82, in urlopen
return opener.open(url)
  File C:\Python25\lib\urllib.py, line 190, in open
return getattr(self, name)(url)
  File C:\Python25\lib\urllib.py, line 325, in open_http
h.endheaders()
  File C:\Python25\lib\httplib.py, line 856, in endheaders
self._send_output()
  File C:\Python25\lib\httplib.py, line 728, in _send_output
self.send(msg)
  File C:\Python25\lib\httplib.py, line 695, in send
self.connect()
  File C:\Python25\lib\httplib.py, line 679, in connect
raise socket.error, msg
IOError: [Errno socket error] (10060, 'Operation timed out')

I'm behind my company's firewall. Would that cause a problem? If it
does, How do I get around it?

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Re: urllib.urlopen: Errno socket error

2006-10-16 Thread Salvatore 
Hello,

Try to increase the time out : socket.settimeout(n)
and catch the timeout error when it occurs

Regards



[EMAIL PROTECTED] a écrit :

 Hi,

 I'm just trying to read from a webpage with urllib but I'm getting
 IOErrors. This is my code:

 import urllib
 sock = urllib.urlopen(http://www.google.com/;)

 and this is the error:

 Traceback (most recent call last):
   File pyshell#5, line 1, in module
 sock = urllib.urlopen(http://www.google.com/;)
   File C:\Python25\lib\urllib.py, line 82, in urlopen
 return opener.open(url)
   File C:\Python25\lib\urllib.py, line 190, in open
 return getattr(self, name)(url)
   File C:\Python25\lib\urllib.py, line 325, in open_http
 h.endheaders()
   File C:\Python25\lib\httplib.py, line 856, in endheaders
 self._send_output()
   File C:\Python25\lib\httplib.py, line 728, in _send_output
 self.send(msg)
   File C:\Python25\lib\httplib.py, line 695, in send
 self.connect()
   File C:\Python25\lib\httplib.py, line 679, in connect
 raise socket.error, msg
 IOError: [Errno socket error] (10060, 'Operation timed out')

 I'm behind my company's firewall. Would that cause a problem? If it
 does, How do I get around it?

-- 
http://mail.python.org/mailman/listinfo/python-list

Re: urllib.urlopen: Errno socket error

2006-10-16 Thread kgrafals 
Hi Salvatore,

Even if I catch the exceptions in a loop it goes on forever.

- ken

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