Re: [R] rggobi is crashing R-2.7.0

2008-05-07 Thread Mark Kimpel
Hard as it is for me to imagine, the ggobi windows stay open and functional
while R (in emacs) has crashed in the background after throwing the error
messages. As a perhaps naive Linux user, I thought that if a parent process
crashed any processes it spawned would crash too. I guess not in this case.

Ubuntu currently is distributing graphviz 2.16.1

Thanks,
Mark

On Wed, May 7, 2008 at 12:14 AM, Michael Lawrence [EMAIL PROTECTED]
wrote:



 On Tue, May 6, 2008 at 6:06 PM, Mark Kimpel [EMAIL PROTECTED] wrote:

  R crashed just after the warnings were issued, but ggobi kept running
  (if that makes sense).


 I am not sure if that makes sense; GGobi should exit when the R process
 does.

 I have Graphviz and Rgraphiz installed and use Rgraphviz regularly without
  a problem, so I'm not sure why it didn't load. Mark
 

 Which version of graphviz? I am not sure which version the Ubuntu binary
 expects, but this may be a binary compatibility issue.

 That said, I am not sure if the GraphLayout plugin is the reason for R
 crashing...


 
 
  On Tue, May 6, 2008 at 4:37 PM, Michael Lawrence [EMAIL PROTECTED]
  wrote:
 
  
  
   On Tue, May 6, 2008 at 10:32 AM, Mark Kimpel [EMAIL PROTECTED]
   wrote:
  
I am running 64-bit Ubuntu 8.04 and when I invoke rggobi the
interactive
graph displays but R crashes. See my sessionInfo() and a short
example
below. Ggobi and rggobi installed without complaints. Mark
   
 sessionInfo()
R version 2.7.0 Patched (2008-05-04 r45620)
x86_64-unknown-linux-gnu
   
locale:
   
LC_CTYPE=en_US.UTF-8;LC_NUMERIC=C;LC_TIME=en_US.UTF-8;LC_COLLATE=en_US.UTF-8;LC_MONETARY=C;LC_MESSAGES=en_US.UTF-8;LC_PAPER=en_US.UTF-8;LC_NAME=C;LC_ADDRESS=C;LC_TELEPHONE=C;LC_MEASUREMENT=en_US.UTF-8;LC_IDENTIFICATION=C
   
attached base packages:
[1] stats graphics  grDevices utils datasets  methods   base
   
other attached packages:
[1] rggobi_2.1.9   RGtk2_2.12.5-3 graph_1.18.0
   
loaded via a namespace (and not attached):
[1] cluster_1.11.10 tools_2.7.0
   
   
 a - matrix(rnorm(1000), nrow = 10)
   
 g - ggobi(a)
   
** (R:25146): CRITICAL **: Error on loading plugin library
plugins/GraphLayout/plugin.la: libgvc.so.3: cannot open shared
object file:
No such file or directory
   
** (R:25146): CRITICAL **: Error on loading plugin library
plugins/GraphLayout/plugin.la: libgvc.so.3: cannot open shared
object file:
No such file or directory
   
** (R:25146): CRITICAL **: can't locate required plugin routine
addToToolsMenu in GraphLayout

   
  
   It's not clear to me - did R crash or did you just receive these
   warnings? These warnings are due to a missing graphviz, so the GraphLayout
   plugin fails to load.
  
  
   
--
Mark W. Kimpel MD ** Neuroinformatics ** Dept. of Psychiatry
Indiana University School of Medicine
   
15032 Hunter Court, Westfield, IN 46074
   
(317) 490-5129 Work,  Mobile  VoiceMail
(317) 663-0513 Home (no voice mail please)
   
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  --
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  Indiana University School of Medicine
 
  15032 Hunter Court, Westfield, IN 46074
 
  (317) 490-5129 Work,  Mobile  VoiceMail
  (317) 663-0513 Home (no voice mail please)
 
  **
 




-- 
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Indiana University School of Medicine

15032 Hunter Court, Westfield, IN 46074

(317) 490-5129 Work,  Mobile  VoiceMail
(317) 663-0513 Home (no voice mail please)

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Re: [R] figure margins too large for a barplot in png, pdf ok

2008-05-07 Thread Alexy Khrabrov

On May 6, 2008, at 10:30 PM, Prof Brian Ripley wrote:

What were H  W?  For png() they are (by default) in pixels, for  
pdf() in inches.


You haven't told us your OS, but I guess Mac OS.  Please update to R  
2.7.0: that offers you two new png() devices for higher-quality  
plots, and various other improvements.  (If you want to use the  
cairo-based png() at other than 72dpi, use R-patched or remember  
that the pointsize is mistakenly in pixels.)


For some reason, R 2.6.2 on Mac OSX (indeed) stopped doing png at all,  
even for plot(1:10).  I've been using a postcard printer with A5 size  
in between, was wondering if that affected things -- and changed that  
in Page Setup to US Letter, to no avail.  H an W were 600 x 800,  
resp., and most importantly this same code worked with R 2.6.0 before...


In any case, simply went and installed the 2.7.0, recompiled littler,  
and it all works fine now, just as before.  (Hope the 4/22 build for  
Mac OSX incorporates Simon's recentmost fixes.)  Thanks!


Cheers,
Alexy

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[R] use list elements to subtract values from the dataframe

2008-05-07 Thread Dirkheld

Hi,

I have a dataframe wf existing of a header with different labels and beneath
the values of those labels :
wf:
label1  label2  ...
0,450,21
0,100,45 
  

I have a list
fl - c(label2,label3,..)

Isn't possible to use the list elements in the list in order to subtract
values from the dataframe? like :
wf$fl[[1]] 
When I do in R I get :NULL
fl[[1]] gives  label2  so no problem here...

While wf$label1 works fine.



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Re: [R] Significance analysis of Microarrays (SAM)

2008-05-07 Thread Eleni Christodoulou
Thanks Martin,

I also posted the question on the bioconductor list but I have no reply yet.
In the meanwhile I found out that instead of saying
d=list(data.matrix2,y,censored)

I should specify the arguments:
d=list(x=data.matrix2,y=y,censoring.status=censored)

Strange, huh? Anyway, it solves the problem.

Thanks once again,
Eleni



On Tue, May 6, 2008 at 6:43 PM, Martin Morgan [EMAIL PROTECTED] wrote:

 Hi Eleni --

 Although samr is not a Bioconductor package, you might have more luck
 asking on the Bioconductor mailing list, http://bioconductor.org. The
 obvious place to start, and probably you have already done this, is to
 ensure that the class of the objects passed to the function agree with
 the classes described on the function help page.

 Martin

 Eleni Christodoulou [EMAIL PROTECTED] writes:

  Dear list,
 
  I am trying to perform a significance analysis of a microarray
 experiment
  with survival data using the {samr} package. I have a matrix containing
 my
  data which has 17816 rows corresponding to genes, and 286 columns
  corresponding to samples. The name of this matrix is data.matrix2. Some
 of
  the first values of this matrix are:
  data.matrix2[1:3,1:5]
   GSM36777  GSM36778 GSM36779 GSM36780 GSM36781
  [1,] 1.009274 1.0740659 1.048540 1.015946 1.022650
  [2,] 1.007992 0.8768410 0.962442 1.111742 1.121150
  [3,] 0.981853 0.9606492 1.024987 1.053302 1.063408
 
   I also have the time in which each patient-sample is examined for
 relapse.
  This information is in vector y, which has length 286, and is declared
 in
  months. Indicatively:
  y[1:5]
  [1] 101 118   9 106  37
 
  Finally, I have a variable censored, which is 1 if the patient has
 relapsed
  when examined at the examined time and 0 if not. Indicatively:
  censored[1:5]
  [1] 0 0 1 0 1
 
 
  I am trying to perform the following sam analysis:
  d=list(data.matrix2,y,censored)
  samr.obj=samr(d,resp.type=Survival, nperms=20)
 
  When I am running the above commands I  get the error:
  Error in check.format(y, resp.type = resp.type, censoring.status =
  censoring.status) :
Error in input response data: response type  Survival  specified;
 error in
  censoring indicator
  In addition: Warning message:
  In is.na(x) : is.na() applied to non-(list or vector) of type 'NULL'
 
 
  I really cannot understand what  is wrong with my code.  Could anyone
 please
  help me with this?
 
  Thank you all,
  Eleni
 
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 PO Box 19024 Seattle, WA 98109

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[R] Solution of function

2008-05-07 Thread Megh Dal
Hi,
   
  I want to find solution of function :  f(x,y) = x'Cx - a under constraints :
   
  0  x,y  p
  0  x-y q
   
  where a, p,q are given constants and x = (x, y) and C is a 2X2 matrix (given)
   
  Can anyone suggest me any R function to do that?
   
   

   
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Re: [R] rggobi is crashing R-2.7.0

2008-05-07 Thread Michael Lawrence
On Tue, May 6, 2008 at 11:11 PM, Mark Kimpel [EMAIL PROTECTED] wrote:

 Hard as it is for me to imagine, the ggobi windows stay open and
 functional while R (in emacs) has crashed in the background after throwing
 the error messages. As a perhaps naive Linux user, I thought that if a
 parent process crashed any processes it spawned would crash too. I guess not
 in this case.


Well running it within Emacs may explain it. We actually aren't spawning a
new GGobi process - just dynamically linking the GGobi library and starting
it that way.



 Ubuntu currently is distributing graphviz 2.16.1


Do you have libgvc.so.3 on your system?

Michael


 Thanks,
 Mark


 On Wed, May 7, 2008 at 12:14 AM, Michael Lawrence [EMAIL PROTECTED]
 wrote:

 
 
  On Tue, May 6, 2008 at 6:06 PM, Mark Kimpel [EMAIL PROTECTED] wrote:
 
   R crashed just after the warnings were issued, but ggobi kept running
   (if that makes sense).
 
 
  I am not sure if that makes sense; GGobi should exit when the R process
  does.
 
   I have Graphviz and Rgraphiz installed and use Rgraphviz regularly
   without a problem, so I'm not sure why it didn't load. Mark
  
 
  Which version of graphviz? I am not sure which version the Ubuntu binary
  expects, but this may be a binary compatibility issue.
 
  That said, I am not sure if the GraphLayout plugin is the reason for R
  crashing...
 
 
  
  
   On Tue, May 6, 2008 at 4:37 PM, Michael Lawrence [EMAIL PROTECTED]
   wrote:
  
   
   
On Tue, May 6, 2008 at 10:32 AM, Mark Kimpel [EMAIL PROTECTED]
wrote:
   
 I am running 64-bit Ubuntu 8.04 and when I invoke rggobi the
 interactive
 graph displays but R crashes. See my sessionInfo() and a short
 example
 below. Ggobi and rggobi installed without complaints. Mark

  sessionInfo()
 R version 2.7.0 Patched (2008-05-04 r45620)
 x86_64-unknown-linux-gnu

 locale:

 LC_CTYPE=en_US.UTF-8;LC_NUMERIC=C;LC_TIME=en_US.UTF-8;LC_COLLATE=en_US.UTF-8;LC_MONETARY=C;LC_MESSAGES=en_US.UTF-8;LC_PAPER=en_US.UTF-8;LC_NAME=C;LC_ADDRESS=C;LC_TELEPHONE=C;LC_MEASUREMENT=en_US.UTF-8;LC_IDENTIFICATION=C

 attached base packages:
 [1] stats graphics  grDevices utils datasets  methods
 base

 other attached packages:
 [1] rggobi_2.1.9   RGtk2_2.12.5-3 graph_1.18.0

 loaded via a namespace (and not attached):
 [1] cluster_1.11.10 tools_2.7.0


  a - matrix(rnorm(1000), nrow = 10)

  g - ggobi(a)

 ** (R:25146): CRITICAL **: Error on loading plugin library
 plugins/GraphLayout/plugin.la: libgvc.so.3: cannot open shared
 object file:
 No such file or directory

 ** (R:25146): CRITICAL **: Error on loading plugin library
 plugins/GraphLayout/plugin.la: libgvc.so.3: cannot open shared
 object file:
 No such file or directory

 ** (R:25146): CRITICAL **: can't locate required plugin routine
 addToToolsMenu in GraphLayout
 

   
It's not clear to me - did R crash or did you just receive these
warnings? These warnings are due to a missing graphviz, so the 
GraphLayout
plugin fails to load.
   
   

 --
 Mark W. Kimpel MD ** Neuroinformatics ** Dept. of Psychiatry
 Indiana University School of Medicine

 15032 Hunter Court, Westfield, IN 46074

 (317) 490-5129 Work,  Mobile  VoiceMail
 (317) 663-0513 Home (no voice mail please)

 **

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 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

   
   
  
  
   --
   Mark W. Kimpel MD ** Neuroinformatics ** Dept. of Psychiatry
   Indiana University School of Medicine
  
   15032 Hunter Court, Westfield, IN 46074
  
   (317) 490-5129 Work,  Mobile  VoiceMail
   (317) 663-0513 Home (no voice mail please)
  
   **
  
 
 


 --
 Mark W. Kimpel MD ** Neuroinformatics ** Dept. of Psychiatry
 Indiana University School of Medicine

 15032 Hunter Court, Westfield, IN 46074

 (317) 490-5129 Work,  Mobile  VoiceMail
 (317) 663-0513 Home (no voice mail please)

 **


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[R] i-best, grep function

2008-05-07 Thread Monna Nygård

Hi,

I'm trying to use the i-best software. Does anyone have experience from this, I 
can't get it to work with my data.

Here is the code: 

T1 - read.delim(file=S://SEDIM//Yvonne//2_5//T1.txt,col.names= 
c(Dye/Sample_Peak, Sample_File_Name, Size, Height, Area_in_Point, 
Area_in_BP, Data_Point, Begin_Point,Begin_BP, End_Point, 
End_BP, Width_in_Point, Width_in_BP, User_Comments, User_Edit))
T1 - subset(T1, Size  1000  Size  50)
T1.B - cbind(T1[grep(^B, as.character(T1$Color),perl=T),3],T1[grep(^B, 
as.character(T1$Color),perl=T),5])
T1.B - cbind(T1.B, T1.B[,2]/sum(T1.B[,2]))


It works alright until the last two lines.  I try to grep the columns 3 and 5, 
but the outcome is 
 T1.B
 [,1] [,2]. 
I don´t quite understand the code of as.character(t1$Color), perl=T. Could 
anyone please explane what this does, I havn´t found it anyware and I am so 
stuck. Maybe I'm doing something else wrong as well..

I would really appreciate some help, thank you.

Yvonne


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Re: [R] Installing A2R in Windows

2008-05-07 Thread Romain Francois

Hello Kate,

Sorry I've only seen that thread. I've not been using A2R for some time, 
and never really found the time to release it properly, in CRAN for 
example. I'll try to allocate some time to that.


If you have the sufficient tools installed 
(http://www.murdoch-sutherland.com/Rtools/), installing the package on 
windows is very similar to installing it on linux.


Cheers,

Romain

Prof Brian Ripley wrote:

On Tue, 6 May 2008, Kate wrote:


Thanks. I used the command you mention and it works fine in Linux. But I
need to get it to work for Windows XP as well (currently running
R-2.7.0). Any idea if it's possible?


Yes, same commmand works -- I've just tested it.  You need the tools 
installed, or to submit to Uwe Ligges' win-builder (mentioned in the 
manual).




On Tue, May 6, 2008 at 5:18 PM, Prof Brian Ripley 
[EMAIL PROTECTED]

wrote:
  How did you install it?

  You need to get A2R_0.0-4.tar.gz and do R CMD INSTALL
  A2R_0.0-4.tar.gz, after reading the 'R Installation and
  Administration manual, especially the sections for your OS.

  The package in A2R/lastVersion/ was built for Unix on R
  2.2.1. An expert might be able to get it working, but we
  don't even know your OS and R version.



On Tue, 6 May 2008, Kate wrote:

Hi there,

I've tried to install the A2R package using the files from
http://addictedtor.free.fr/packages/A2R/lastVersion/

This is the error I get when trying to load the library:
library(A2R)
Error in library(A2R) :
 'A2R' is not a valid package -- installed  2.0.0?

Can anyone please help? Thanks.
Kate

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PLEASE do read it.

--
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Professor of Applied Statistics,
 http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
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Re: [R] Regarding nls()

2008-05-07 Thread Karl Ove Hufthammer
Spencer Graves:

 Bates' condemnation of R^2 has merit, but I would not go as far as
 he did in the comment cited below (dated 13 Aug 2000).  A standard
 definition of R^2 is as follows:
 
 R^2 = (1 - var(prediction error) / var(obs)).
 
 I can name several different ways of getting a negative R^2 in
 this case.  When that happens, it says the model is worse than useless,
 and you would be better off using the training set mean.
 
 If I have an audience who wants an R^2 in an application where it
 is not clear what it even means, I try to briefly explain some of the
 difficulties while asking what question they are trying to solve using
 R^2.  Their answers will help me make a recommendation, which may
 include selecting which of the possible generalizations of R^2 to use.

I would like to recommend the following two articles on R²:

Model Comparisons and R²
Richard Anderson-Sprecher 
The American Statistician, Vol. 48, No. 2. (May, 1994), pp. 113-117. 
http://www.jstor.org/stable/2684259

Cautionary Note about R²
Tarald O. Kvalseth 
The American Statistician, Vol. 39, No. 4, (Nov., 1985), pp. 279-285. 
http://www.jstor.org/stable/2683704

-- 
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Re: [R] use list elements to subtract values from the dataframe

2008-05-07 Thread jim holtman
What you want is:

wf[[fl[1]]]

'fl' is a vector, so you should only be using a single '[' for indexing.

On Wed, May 7, 2008 at 3:20 AM, Dirkheld [EMAIL PROTECTED] wrote:

 Hi,

 I have a dataframe wf existing of a header with different labels and beneath
 the values of those labels :
 wf:
 label1  label2  ...
 0,450,21
 0,100,45
   

 I have a list
 fl - c(label2,label3,..)

 Isn't possible to use the list elements in the list in order to subtract
 values from the dataframe? like :
 wf$fl[[1]]
 When I do in R I get :NULL
 fl[[1]] gives  label2  so no problem here...

 While wf$label1 works fine.



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What is the problem you are trying to solve?

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[R] Fwd: Re: Solution of function

2008-05-07 Thread Megh Dal
Forgot to send one copy to R help. Sorry

Megh Dal [EMAIL PROTECTED] wrote:  Date: Wed, 7 May 2008 02:45:09 -0700 (PDT)
From: Megh Dal [EMAIL PROTECTED]
Subject: Re: [R] Solution of function
To: Berwin A Turlach [EMAIL PROTECTED]

  Hi Berwin,
   
  Thanks for having look on my problem. However on ipop() function I see 
following:
   
  ipop solves the quadratic programming problem :
min(c'*x + 1/2 * x' * H * x)
subject to: 
b = A * x = b + r
l = x = u 
   
  But my problem is not to find maxima or minima rather to get solution at that 
defined region. How to modify that function for my problem?

Berwin A Turlach [EMAIL PROTECTED] wrote:
  G'day Megh,

On Wed, 7 May 2008 01:11:34 -0700 (PDT)
Megh Dal wrote:

 I want to find solution of function : f(x,y) = x'Cx - a under
 constraints : 
 0  x,y  p
 0  x-y q
 
 where a, p,q are given constants and x = (x, y) and C is a 2X2
 matrix (given) 
 Can anyone suggest me any R function to do that?

ipop() in package kernlab
solve.QP in package quadprog
Depending on the form of C, package LowRankQP could also be of interest.

HTH.

Cheers,

Berwin

=== Full address =
Berwin A Turlach Tel.: +65 6515 4416 (secr)
Dept of Statistics and Applied Probability +65 6515 6650 (self)
Faculty of Science FAX : +65 6872 3919 
National University of Singapore 
6 Science Drive 2, Blk S16, Level 7 e-mail: [EMAIL PROTECTED]
Singapore 117546 http://www.stat.nus.edu.sg/~statba


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Re: [R] unable to use functions require DLL from package base

2008-05-07 Thread A.N.

Thanks, I had indeed several versions of R and removed the older ones and it
worked.







I suspect you have more than one version of R installed and are mixing 
them up.  Those symbols have been in package stats for quite a while.

Try starting R with --vanilla, and if that works, clean out your startup 
files (see ?Startup).  If not, remove all your R installations and 
reinstall R 2.7.0 (or R-patched).

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Re: [R] i-best, grep function

2008-05-07 Thread Richard . Cotton
 T1 - read.delim(file=S://SEDIM//Yvonne//2_5//T1.txt,col.names= 
 c(Dye/Sample_Peak, Sample_File_Name, Size, Height, 
 Area_in_Point, Area_in_BP, Data_Point, Begin_Point, 
 Begin_BP, End_Point, End_BP, Width_in_Point, Width_in_BP, 
 User_Comments, User_Edit))
 T1 - subset(T1, Size  1000  Size  50)
 T1.B - cbind(T1[grep(^B, as.character(T1$Color),perl=T),3],
 T1[grep(^B, as.character(T1$Color),perl=T),5])
 T1.B - cbind(T1.B, T1.B[,2]/sum(T1.B[,2]))
 
 
 It works alright until the last two lines.  I try to grep the 
 columns 3 and 5, but the outcome is 
  T1.B
  [,1] [,2]. 
 I don´t quite understand the code of as.character(t1$Color), perl=T.

T1 is a data frame, and T1$Color is one of the columns.

as.character converts the column T1$Color from type factor to type 
character (i.e. a vector of strings).

grep(^B, as.character(T1$Color),perl=T) means 'find all strings in the 
vector T1$Color that begin with the letter (capital) B'.  ^B is an 
example of a regular expression.  There is a very good guide to them here: 
http://www.regular-expressions.info/quickstart.html

The relevant help pages in R are ?grep and ?regexp.  Don't worry about the 
parameter perl=TRUE; there are subtle variations on regular expression 
syntax, and it just means that you follow PERL-style syntax.

Regards,
Richie.

Mathematical Sciences Unit
HSL


ATTENTION:

This message contains privileged and confidential inform...{{dropped:21}}

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[R] How do I write a power of matrices?? [was: How do I write a sum of matrixes??]

2008-05-07 Thread Alberto Monteiro

Jorge Ivan Velez wrote:
 
 I think the function could be better but try this:
 
 # Function: M is your matrix and n MUST be an integer0
 mat.pow-function(M,n) {
   result-M
 if(n1){
for ( iter in 2:n) result-M%*%result
result
}
 else {result}
   result
  }
 
There are much more efficient ways to compute a power,
just check:
http://en.wikipedia.org/wiki/Exponentiation_by_squaring

Or, translating the pseudo-code to R:

mat.pow - function(M, n) {
  result - diag(1, ncol(M))
  while (n  0) {
if (n %% 2 == 1) {  
  result - result %*% M
  n - n - 1
}
M - M %*% M
n - n / 2
  }
  return(result)
}

# The matrix
m -  rbind(c(1,1,0), c(0,1,1), c(0,0,1))
 
# Goal m^6 = m x m x m x m x m x m
goal=  m %*% m %*% m %*% m %*% m %*% m
 
# matpow
res=mat.pow(m,6)
 
# Check point
all.equal(goal,res)

This algorithm would be fast, unless n is a _very_ big number.

Alberto Monteiro

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[R] Aling elmentos into Windows with TK

2008-05-07 Thread ermimi

Hello!!

I would like create a window that has diferent element as:

http://bioinf.wehi.edu.au/~wettenhall/RTclTkExamples/checkboxes.html
http://bioinf.wehi.edu.au/~wettenhall/RTclTkExamples/radiobuttons.html

I know as make it, but I don´t know as I could (align the diferent elemnts
to left, right, top, bottom) or (put in a coordinates into windows).

If anybody know as I could make it, I would like you say me.

Thank you very much, Luismi
A greetings
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Re: [R] i-best, grep function

2008-05-07 Thread Peter Dalgaard
[EMAIL PROTECTED] wrote:
 T1 - read.delim(file=S://SEDIM//Yvonne//2_5//T1.txt,col.names= 
 c(Dye/Sample_Peak, Sample_File_Name, Size, Height, 
 Area_in_Point, Area_in_BP, Data_Point, Begin_Point, 
 Begin_BP, End_Point, End_BP, Width_in_Point, Width_in_BP, 
 User_Comments, User_Edit))
 T1 - subset(T1, Size  1000  Size  50)
 T1.B - cbind(T1[grep(^B, as.character(T1$Color),perl=T),3],
 T1[grep(^B, as.character(T1$Color),perl=T),5])
 T1.B - cbind(T1.B, T1.B[,2]/sum(T1.B[,2]))


 It works alright until the last two lines.  I try to grep the 
 columns 3 and 5, but the outcome is 
  T1.B
  [,1] [,2]. 
 I don´t quite understand the code of as.character(t1$Color), perl=T.
 

 T1 is a data frame, and T1$Color is one of the columns.
   
With all due respect: I think you missed the point: T1$Color is NOT one
of the columns (look at the col.names).

So T1$Color is NULL and things go downhill from there.

But what is i-best This looks like a plain R issue.

-p
 as.character converts the column T1$Color from type factor to type 
 character (i.e. a vector of strings).

 grep(^B, as.character(T1$Color),perl=T) means 'find all strings in the 
 vector T1$Color that begin with the letter (capital) B'.  ^B is an 
 example of a regular expression.  There is a very good guide to them here: 
 http://www.regular-expressions.info/quickstart.html

 The relevant help pages in R are ?grep and ?regexp.  Don't worry about the 
 parameter perl=TRUE; there are subtle variations on regular expression 
 syntax, and it just means that you follow PERL-style syntax.

 Regards,
 Richie.

 Mathematical Sciences Unit
 HSL
   


-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Re: [R] list manipulation

2008-05-07 Thread Thompson, David (MNR)
 Beautiful! Thanks Jim.

DaveT.
-Original Message-
From: jim holtman [mailto:[EMAIL PROTECTED] 
Sent: May 6, 2008 07:33 PM
To: Thompson, David (MNR)
Subject: Re: [R] list manipulation

The reason for the NULLs is that is the output of the lapply you are
executing.  If you don't want to see the value, then use 'invisible'
or assign to an object since you are executing this at the command
level, the default is to print the value.

invisible(lapply(...))

On Tue, May 6, 2008 at 2:35 PM, Thompson, David (MNR)
[EMAIL PROTECTED] wrote:
 Hello,

 I have a set of one-liners (many thanks to previous 
responses from this
 list) that I use to look at newly imported data sets with 
functions like
 dim(), names(), str(), etc. within lapply(). Generally, 
these commands
 work for me but, I am apparently still missing some aspect of list
 manipulation. I don't understand why I get a set of NULL 
list elements
 at the end of each output as demonstrated below. How can I 
generate this
 (and similar) result(s) without all the trailing NULLs?

  lapply(ls(pattern='bn'), function(x) cat(x, dim(get(x)), \t,
 names(get(x)), \n))
 bn1993 2885 11   oplt rplt rsiz tree bd ht oaz odst raz rdst spr
 bn1994 3158 7oplt tree bd ht spr stat dam
 bn1995 734 7 oplt tree bd ht spr stat dam
 bn1996 293 7 oplt tree bd ht spr stat dam
 bn1997 264 7 oplt tree bd ht spr stat dam
 bn1998 768 7 oplt tree bd ht spr stat dam
 bn1999 654 7 oplt tree bd ht dbh stat dam
 bn2003 1407 9oplt tree bd94 ht94 ht99 ht02 ht03 stat dam
 [[1]]
 NULL

 [[2]]
 NULL

 [[3]]
 NULL

 [[4]]
 NULL

 [[5]]
 NULL

 [[6]]
 NULL

 [[7]]
 NULL

 [[8]]
 NULL

 Thanx, DaveT.
 *
 Silviculture Data Analyst
 Ontario Forest Research Institute
 Ontario Ministry of Natural Resources
 [EMAIL PROTECTED]
 http://ofri.mnr.gov.on.ca

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-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?


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[R] Citation in the literature

2008-05-07 Thread Sébastien

Hello everyone,

Very quick question: How should I cite the use of R in a publication ?

Thanks in advance.

Sebastien

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Re: [R] Citation in the literature

2008-05-07 Thread ronggui
 citation()

To cite R in publications use:

  R Development Core Team (2008). R: A language and environment for
  statistical computing. R Foundation for Statistical Computing,
  Vienna, Austria. ISBN 3-900051-07-0, URL http://www.R-project.org.

A BibTeX entry for LaTeX users is

  @Manual{,
title = {R: A Language and Environment for Statistical Computing},
author = {{R Development Core Team}},
organization = {R Foundation for Statistical Computing},
address = {Vienna, Austria},
year = {2008},
note = {{ISBN} 3-900051-07-0},
url = {http://www.R-project.org},
  }

We have invested a lot of time and effort in creating R, please cite
it when using it for data analysis. See also 'citation(pkgname)'
for citing R packages.



On Wed, May 7, 2008 at 9:03 PM, Sébastien [EMAIL PROTECTED] wrote:
 Hello everyone,

  Very quick question: How should I cite the use of R in a publication ?

  Thanks in advance.

  Sebastien

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 http://www.R-project.org/posting-guide.html
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-- 
HUANG Ronggui, Wincent

Bachelor of Social Work, Fudan University, China

Master of sociology, Fudan University, China

Ph.D. Candidate, CityU of HK,
http://www.cityu.edu.hk/sa/psa_web2006/students/rdegree/huangronggui.html

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Re: [R] Citation in the literature

2008-05-07 Thread Marc Schwartz

Sébastien wrote:

Hello everyone,

Very quick question: How should I cite the use of R in a publication ?

Thanks in advance.

Sebastien


See the FAQs:

  http://cran.r-project.org/doc/FAQ/R-FAQ.html#Citing-R


This is also referenced in the startup banner in an R console:

...

R is a collaborative project with many contributors.
Type 'contributors()' for more information and
'citation()' on how to cite R or R packages in publications.

...


HTH,

Marc Schwartz

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Re: [R] fft: characteristic function to distribution

2008-05-07 Thread Thomas Steiner
Thank you Prof Ripley for your answer.

  The characteristic function is the inverse Fourier transform of the
  distribution function. The characteristic function of a normaly
  distributed random variable is exp(-t^2/2).
 

 The fft is a discrete Fourier transforn, not a continuous one.

This is correct. I try to approximate the continous normal
distribution with infinite support by a set of discrete and bounded
points. A real discrete baby example would be the bernoulli
distribution:

p=0.4
t=seq(-0.01,1.001,length=100)
char=1-p+p*exp(1i*t)
cdf=stepfun(c(0,1),c(0,1-p,1))
plot(t,cdf(t),type=l,col=red,ylim=range(cdf(t),Re(fft(char)[2:99])))
lines(t,fft(char),col=blue)

This is more or less like the normal example.

 Further in each case where the normalizing constants are placed and the
 units of frequecy differ from source to source.

 ?fft has references to exactly what it computes: please consult them.

I read the documentation/help page. More details there would be
helpful. For example an example (it says example*s*) something where
explicit expressions are known (as I tried it here).
Another possible improvement could be to make for example the
following sentence nicer/clearer: (the inverse has a + in the
exponent of e, but here, we do not divide by 1/length(x)).
I did not consult the two given references (two old but surely valuable books).

Enough prattled. Can you give a working example where the cummulative
distribution function and the fourier transform are explicitly known?

I cannot add any value neither to wonderful R nor to this helpful
function. But perhaps my question isn't that stupid and you can give a
hint to proceed. Thank you very much in advance,
Thomas

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[R] CRAN and Multiple Linear Regression

2008-05-07 Thread Anja und Th. Sponsel
Hello

I have to solve a multiple linear regression. Most programs like Excel
or Mathlab only support 5-10 dimensions. Now I have installed CRAN and
I have no clue what to do next. At the moment I am entering my data
into an excelsheet (for quick copy- paste). The Y-array will be 20
columns (=dimensions) and 128 rows (=variables). The X-array may also
be 128 rows in Excel.

Which package do I need - or does it work without any package?

What commands do I have to enter? I'm not familiar with CRAN and I
didn't find any example.

Best regards,
 Thomas

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Re: [R] Not to draw the xaxis ticks in ggplot2

2008-05-07 Thread hadley wickham
On Tue, May 6, 2008 at 11:44 PM, ronggui [EMAIL PROTECTED] wrote:
 library(ggplot2)
  (p- qplot(mpg, wt, data=mtcars))
  What I am doing is to set color of the ticks to hide them.
  grid.gedit(gPath(xaxis, ticks), gp=gpar(col=white))

  It should be a better way to achieve the purpose. Thanks.

Agreed.  I've added it to my ggplot2 customisation to do list.

Thanks,

Hadley

-- 
http://had.co.nz/

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Re: [R] categorical data analysis

2008-05-07 Thread Greg Snow
The last example in ?fisher.test is not a 2x2 table, in fact it uses levels 
with a natural ordering similar to the original question.  Why would this not 
be applicable to the situation?


From: [EMAIL PROTECTED] [EMAIL PROTECTED] On Behalf Of David Winsemius [EMAIL 
PROTECTED]
Sent: Wednesday, May 07, 2008 7:34 AM
To: [EMAIL PROTECTED]
Subject: Re: [R] categorical data analysis

Simon Blomberg [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:

 But see these posts:

 http://finzi.psych.upenn.edu/R/Rhelp02a/archive/119079.html

 http://finzi.psych.upenn.edu/R/Rhelp02a/archive/119080.html

 Simon.

Interesting reading, but the OP specifically said he was not dealing with
2x2 tables, so neither fisher.test nor the suggested alternatives would
be applicable to his data situation.

--
David Winsemius

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Re: [R] Solution of function

2008-05-07 Thread Peter Dalgaard
Megh Dal wrote:
 Hi,

   I want to find solution of function :  f(x,y) = x'Cx - a under constraints :

   0  x,y  p
   0  x-y q

   where a, p,q are given constants and x = (x, y) and C is a 2X2 matrix 
 (given)

   Can anyone suggest me any R function to do that?

   
Not likely. What you have (if C is  positive definite) is the
intersection between the boundary of an ellipse and the interior of a
parallelepiped, where the center of the ellipse and one corner of the
parallelepiped is at (0,0).

This is the union of between zero and three curve segments (hmm, maybe
only two) and I don't think any of the standard solvers and minimizers
can come up with that kind of result.

-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Re: [R] CRAN and Multiple Linear Regression

2008-05-07 Thread Abhijit Dasgupta
Multiple linear regression is handled by the function lm() in the 
default installation of R. This takes inputs as lm(y~x1+x2+x3).


If you're going to be using R regularly, there are several books which 
cover the basic statistical analyses available in R (and then some), 
including those by Peter Daalgard and by Brian Ripley, who are very 
regular contributors to this list.


Abhijit

Anja und Th. Sponsel wrote:

Hello

I have to solve a multiple linear regression. Most programs like Excel
or Mathlab only support 5-10 dimensions. Now I have installed CRAN and
I have no clue what to do next. At the moment I am entering my data
into an excelsheet (for quick copy- paste). The Y-array will be 20
columns (=dimensions) and 128 rows (=variables). The X-array may also
be 128 rows in Excel.

Which package do I need - or does it work without any package?

What commands do I have to enter? I'm not familiar with CRAN and I
didn't find any example.

Best regards,
 Thomas

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Re: [R] ggplo2: x_discrete labels size/direction

2008-05-07 Thread hadley wickham
  PS Perhaps it'd still be really useful to be able to change text direction
  in labels.
  Hadley, what do you think?

Agreed.  I've added it to my ggplot2 customisation to do list.

Thanks,

Hadley


-- 
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Re: [R] Importing data

2008-05-07 Thread John Kane
First step would be to read the manual on the R site
R Data Import/Export describes the import and export
facilities available either in R itself or via
packages which are available from CRAN

Then if that does not solve the problem you need to
explain in detail what the problems are, preferably
with the code that you are using.  See the
instructions at the bottom of the post.
--- Yemi Oyeyemi [EMAIL PROTECTED] wrote:

 Hi everyone, please I'm having problem importing
 data from Stata and excel. Help me out.
   Thanks
 

 -
 [[elided Yahoo spam]]
   [[alternative HTML version deleted]]
 
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 reproducible code.


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[R] p values for polychor

2008-05-07 Thread andrew collier
hello,

i have been using cor.test() for calculating the correlation coefficient  and p 
values for some data. however, since the data consist of two dichotomous 
sequences (actually just binary data), i understand that simply using the 
pearson correlation is not sufficient. however, having done a bit of research i 
found that the 
tetrachoric correlation is what i am after. found the polycor package and the 
polychor routine, which seem to do precisely what i want. however, i don't get 
p values out of polychor, just the standard deviation.

so, in a rather naive way i have tried to write a function which will return a 
list with similar fields as what one gets from cor.test(). not being terribly 
strong with statistics though, i am not sure whether this is entirely correct. 
could someone tell me if i am on the right track... or point out where i am 
going wrong?

tetrachoric.test - function(x, y) {
p - polychor(x, y, std.err = TRUE)
#
p$statistic - p$rho / sqrt(c(p$var))
#
p$estimate - p$rho
p$p.value = 2 * (1 - pnorm(abs(p$statistic)))

p
}

the assumption is that the p value is the integration of the two tails of the 
distribution?

 x - as.integer(runif(20)  0.5)
 y - as.integer(runif(20)  0.5)
 p - tetrachoric.test(x, y)   
 p$statistic
[1] -0.2616866
 p$p.value
[1] 0.7935631
 p$var
  [,1]
[1,] 0.1452105

thanks for any help!

best regards,
andrew.

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Re: [R] categorical data analysis

2008-05-07 Thread David Winsemius
Greg Snow [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:

 The last example in ?fisher.test is not a 2x2 table, in fact it uses
 levels with a natural ordering similar to the original question. 
 Why would this not be applicable to the situation? 

Apologies. Clearly I misunderstood the R implementation. My parsing of 
the fisher.test code (influenced by having just read the Campbell 
article) lead me to erroneously conclude that it was only applicable to 
2x2 tables. I see now that the error message says _at_least_ 2 rows 
and columns and that the error check is an inquality. 

-- 
David Winsemius
 
 
 From: [EMAIL PROTECTED] [EMAIL PROTECTED] On
 Behalf Of David Winsemius [EMAIL PROTECTED] Sent: Wednesday,
 May 07, 2008 7:34 AM To: [EMAIL PROTECTED]
 Subject: Re: [R] categorical data analysis
 
 Simon Blomberg [EMAIL PROTECTED] wrote in
 news:[EMAIL PROTECTED]:
 
 But see these posts:

 http://finzi.psych.upenn.edu/R/Rhelp02a/archive/119079.html

 http://finzi.psych.upenn.edu/R/Rhelp02a/archive/119080.html

 Simon.
 
 Interesting reading, but the OP specifically said he was not dealing
 with 2x2 tables, so neither fisher.test nor the suggested
 alternatives would be applicable to his data situation.
 
 --
 David Winsemius
 
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 R-help@r-project.org mailing list
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Re: [R] Importing data

2008-05-07 Thread Juan Manuel Barreneche
i usually import data from exel, using read.table or read.csv (which implies 
that i have to save exel files as .txt or .csv)

JM

El Miércoles, 7 de Mayo de 2008 11:25, John Kane escribió:
 First step would be to read the manual on the R site
 R Data Import/Export describes the import and export
 facilities available either in R itself or via
 packages which are available from CRAN

 Then if that does not solve the problem you need to
 explain in detail what the problems are, preferably
 with the code that you are using.  See the
 instructions at the bottom of the post.

 --- Yemi Oyeyemi [EMAIL PROTECTED] wrote:
  Hi everyone, please I'm having problem importing
  data from Stata and excel. Help me out.
Thanks
 
 
  -
  [[elided Yahoo spam]]
  [[alternative HTML version deleted]]
 
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  reproducible code.

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Re: [R] CRAN and Multiple Linear Regression

2008-05-07 Thread Peter Dalgaard
Abhijit Dasgupta wrote:
 Multiple linear regression is handled by the function lm() in the
 default installation of R. This takes inputs as lm(y~x1+x2+x3).

 If you're going to be using R regularly, there are several books which
 cover the basic statistical analyses available in R (and then some),
 including those by Peter Daalgard and by Brian Ripley, who are very
 regular contributors to this list.
Thanks for saving me a shameless plug (notice that the double a comes
last, though...).

For people just out to get their feet wet, there's also a collection of
shorter and longer documents in the contributed section on CRAN,
http://cran.r-project.org/other-docs.html . I particularly like Jason
Owen's The R Guide as a kickstart document. As far as I can tell, you
can just skip things that rely on math that you haven't heard of (such
as matrix algebra) without getting lost.

-pd


 Abhijit

 Anja und Th. Sponsel wrote:
 Hello

 I have to solve a multiple linear regression. Most programs like Excel
 or Mathlab only support 5-10 dimensions. Now I have installed CRAN and
 I have no clue what to do next. At the moment I am entering my data
 into an excelsheet (for quick copy- paste). The Y-array will be 20
 columns (=dimensions) and 128 rows (=variables). The X-array may also
 be 128 rows in Excel.

 Which package do I need - or does it work without any package?

 What commands do I have to enter? I'm not familiar with CRAN and I
 didn't find any example.

 Best regards,
  Thomas

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Re: [R] Importing data

2008-05-07 Thread Neil Shephard



Yemi Oyeyemi wrote:
 
 Hi everyone, please I'm having problem importing data from Stata and
 excel. Help me out.
   Thanks
 
 

You don't provide...

a) the code that you've tried

b) the error message that relates to the problem you are having

...without these people have little information on what _exactly_  your
problem is.  Please read the R-help posting guide as advised in the
signature of every mail that appears on the list.  For clarity its...
 
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code. 

In this instance you would also do well to read the R Data Import/Export
manual at http://cran.r-project.org/doc/manuals/R-data.html and pay
particular attention to section 3 titled Importing from other Statistical
Systems
(http://cran.r-project.org/doc/manuals/R-data.html#Importing-from-other-statistical-systems).

This would lead you to the read.dta() and write.dta() functions for
respectively reading and writing Stata formatted data sets.

Neil
-- 
View this message in context: 
http://www.nabble.com/Importing-data-tp17104951p17106184.html
Sent from the R help mailing list archive at Nabble.com.

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Re: [R] Importing data

2008-05-07 Thread Wensui Liu
import stata data should be straight. take a look at foreign package


On Wed, May 7, 2008 at 9:30 AM, Yemi Oyeyemi [EMAIL PROTECTED] wrote:
 Hi everyone, please I'm having problem importing data from Stata and excel. 
 Help me out.
   Thanks


  -
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Re: [R] use of sequence on ridge regression

2008-05-07 Thread Prof Brian Ripley

What do you mean by 'the sequence option'?

The authot of lm.ridge

On Wed, 7 May 2008, Rodrigo Briceño wrote:


Dear R users. I have a doubt about the use of the sequence option on
Ridge regression. I'm trying to understand the use of this option when
variables are highly linear correlated. I'm running a model where the
variables HtShoes and Ht have high VIF values. My program is written
below, but I'm not sure about the correct way of using the sequence
option:

library (faraway)
data (seatpos)
attach (seatpos)
spos.mod - lm(hipcenter ~ .,seatpos) summary (spos.mod)
library(MASS)
lm.ridge(hipcenter ~ .,seatpos)
plot(lm.ridge(hipcenter ~ .,seatpos, lambda = seq(0,0.1,0.001)))
select(lm.ridge(hipcenter ~ ., seatpos,lambda = seq(0,0.1,0.001)))

Any advice will be appreaciated. Rodrigo B.

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[R] function in nls argument

2008-05-07 Thread Fernando Moyano
Greetings R users, maybe there is someone who can help
me with this problem:

I define a function optim.fun and want as output the
sum of squared errors between predicted and measured
values, as follows:

optim.fun - function (ST04, SM08b, ch2no, a, b, d, E)
{
predR -
(a*SM08b^I(2)+b*SM08b+d)*exp(E*((1/(283.15-227.13))-(1/(ST04+273.15-227.13
abserr - abs(ch2no-predR)
qnum - quantile(abserr, probs=0.95, na.rm=T) 
  
is.na(abserr) - (abserr  qnum)
errsq - sum(abserr^2, na.rm=T)
errsq
}

Then I want to optimize parameters a,b,d and E as to
minimize the function output with the following:

optim.model-nls(nulldat ~ optim.fun(ST04, SM08b,
ch2no, a, b, d, E), data=tower,
start=list(a=-0.003,b=0.13,d=0.50, E=400), na.action =
na.exclude )

were nulldat=0
At this point I get the following error message:

Error in qr.default(.swts * attr(rhs, gradient)) : 
  NA/NaN/Inf in foreign function call (arg 1)
Warning messages:
1: In if (na.rm) x - x[!is.na(x)] else if
(any(is.na(x))) stop(missing values and NaN's not
allowed if 'na.rm' is FALSE) ... :
  the condition has length  1 and only the first
element will be used
(this warning is repeated 12 times)

Question: what does the error mean? What am I doing
wrong?
Thanks a bunch.
Nano
Jen, Germany
Max Planck for Biogeochemistry




  


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Re: [R] categorical data analysis - fisher.exact for 2x2 and greater

2008-05-07 Thread Dr. Jeff Miller
Hi Simon and all,

I'm pretty sure that you are correct about this. I think it is a
misconception to say that the fisher exact test is only for a 2 by 2 table.
It is presented that way in textbooks because, for a 2x2 table, it is easy
to perform.  For larger tables, it becomes complex quickly due to the rate
at which the permutations increase.

 When I use it for larger tables, it is hit or miss as to whether R will be
able to do it.  It's not uncommon to get an error implying that R is out of
memory. 

Check out Agresti's Categorical Data Analysis on the use of the fisher exact
for larger than 2x2 tables, and check out the R archives (and Google search)
for all the posts about the error message people run into sometimes.

On April 29th, Marc Schwartz replied to my question about this as follows:

Take a look at the 'workspace' argument in ?fisher.test and review the
second paragraph in Details:

For 2 by 2 cases, p-values are obtained directly using the (central or
non-central) hypergeometric distribution. Otherwise, computations are based
on a C version of the FORTRAN subroutine FEXACT which implements the network
developed by Mehta and Patel (1986) and improved by Clarkson, Fan and Joe
(1993). The FORTRAN code can be obtained from
http://www.netlib.org/toms/643. Note this fails (with an error message) when
the entries of the table are too large. (It transposes the table if
necessary so it has no more rows than columns. One constraint is that the
product of the row marginals be less than 2^31 - 1.)



Thank you,
Jeff



-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of Greg Snow
Sent: Wednesday, May 07, 2008 9:55 AM
To: David Winsemius; [EMAIL PROTECTED]
Subject: Re: [R] categorical data analysis

The last example in ?fisher.test is not a 2x2 table, in fact it uses levels
with a natural ordering similar to the original question.  Why would this
not be applicable to the situation?


From: [EMAIL PROTECTED] [EMAIL PROTECTED] On Behalf
Of David Winsemius [EMAIL PROTECTED]
Sent: Wednesday, May 07, 2008 7:34 AM
To: [EMAIL PROTECTED]
Subject: Re: [R] categorical data analysis

Simon Blomberg [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:

 But see these posts:

 http://finzi.psych.upenn.edu/R/Rhelp02a/archive/119079.html

 http://finzi.psych.upenn.edu/R/Rhelp02a/archive/119080.html

 Simon.

Interesting reading, but the OP specifically said he was not dealing with
2x2 tables, so neither fisher.test nor the suggested alternatives would
be applicable to his data situation.

--
David Winsemius

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Internal Virus Database is out-of-date.


11:27 AM
 

Internal Virus Database is out-of-date.


11:27 AM

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[R] predict lmer

2008-05-07 Thread May, Roel
Hi,
 
I am using lmer to analyze habitat selection in wolverines using the
following model:
 
(me.fit.of -
lmer(USED~1+STEP+ALT+ALT2+relM+relM:ALT+(1|ID)+(1|ID:TRKPT2),data=vdata,
control=list(usePQL=TRUE),family=poisson,method=Laplace))
 
Here, the habitat selection is calaculated using a so-called discrete
choice model where each used location has a certain number of
alternatives which the animal could have chosen. These sets of locations
are captured using the TRKPT2 random grouping. However, these sets are
also clustered over the different individuals (ID). USED is my binary
dependent variable which is 1 for used locations and zero for unused
locations. The other are my predictors.
 
I would like to predict the model fit at different values of the
predictors, but does anyone know whether it is possible to do this? I
have looked around at the R-sites and in help but it seems that there
doesn't exist a predict function for lmer???
 
I hope someone can help me with this; point me to the right functions or
tell me to just forget it
 
Thanks in advance!
 
Cheers Roel
 
Roel May
Norwegian Institute for Nature Research
Tungasletta 2, NO-7089 Trondheim, Norway


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Re: [R] use of sequence on ridge regression

2008-05-07 Thread Rodrigo Briceño
Nice to meet you Brian. The question is about the numbers that appears 
after lambda (0,0, 0.1, 0.0001). I know that seq is a set of values used 
for testing which value fits best. But I'm not sure if I need to put 
whatever I think or what. I tried also with a set of 5 values and I get 
an error. Is there a maximum allowed?

plot(lm.ridge(hipcenter ~ .,seatpos, lambda = seq(0,0.1,0.001)))
select(lm.ridge(hipcenter ~ ., seatpos,lambda = seq(0,0.1,0.001)))

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Prof Brian Ripley wrote:
 What do you mean by 'the sequence option'?

 The authot of lm.ridge

 On Wed, 7 May 2008, Rodrigo Briceño wrote:

 Dear R users. I have a doubt about the use of the sequence option on
 Ridge regression. I'm trying to understand the use of this option when
 variables are highly linear correlated. I'm running a model where the
 variables HtShoes and Ht have high VIF values. My program is written
 below, but I'm not sure about the correct way of using the sequence
 option:

 library (faraway)
 data (seatpos)
 attach (seatpos)
 spos.mod - lm(hipcenter ~ .,seatpos) summary (spos.mod)
 library(MASS)
 lm.ridge(hipcenter ~ .,seatpos)
 plot(lm.ridge(hipcenter ~ .,seatpos, lambda = seq(0,0.1,0.001)))
 select(lm.ridge(hipcenter ~ ., seatpos,lambda = seq(0,0.1,0.001)))

 Any advice will be appreaciated. Rodrigo B.

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[R] help with the unique function

2008-05-07 Thread ravi
Hi,
The unique function is easy to understand and use. Beyond that, I want to get 
also the frequency of repetition of each individual row in a data frame
Let me explain with an example :
x-data.frame(a=c(1,2,3,1,2),b=c(2,3,4,2,3),c=c(10,20,30,10,20))
xu-unique(x)
We have,
 x
  a b  c
1 1 2 10
2 2 3 20
3 3 4 30
4 1 2 10
5 2 3 20
 xu
  a b  c
1 1 2 10
2 2 3 20
3 3 4 30

I want to get the following data frame :
  a b  c    Freq
1 1 2 10    2
2 2 3 20    2
3 3 4 30    1
That is, in addition to the unique rows, I want to get the frequency of 
repetion of each individual row.
I will appreciate all the help that I can get.
Thank You,
Ravi

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Re: [R] help with the unique function

2008-05-07 Thread Jorge Ivan Velez
Hi Ravi,

Try this:

x-data.frame(a=c(1,2,3,1,2),b=c(2,3,4,2,3),c=c(10,20,30,10,20))
cbind(unique(x),lapply(x,table)$c)[,-4]
a b  c Freq
1 1 2 102
2 2 3 202
3 3 4 301


HTH,

Jorge


On Wed, May 7, 2008 at 12:11 PM, ravi [EMAIL PROTECTED] wrote:

 Hi,
 The unique function is easy to understand and use. Beyond that, I want to
 get also the frequency of repetition of each individual row in a data frame
 Let me explain with an example :
 x-data.frame(a=c(1,2,3,1,2),b=c(2,3,4,2,3),c=c(10,20,30,10,20))
 xu-unique(x)
 We have,
  x
   a b  c
 1 1 2 10
 2 2 3 20
 3 3 4 30
 4 1 2 10
 5 2 3 20
  xu
   a b  c
 1 1 2 10
 2 2 3 20
 3 3 4 30

 I want to get the following data frame :
   a b  cFreq
 1 1 2 102
 2 2 3 202
 3 3 4 301
 That is, in addition to the unique rows, I want to get the frequency of
 repetion of each individual row.
 I will appreciate all the help that I can get.
 Thank You,
 Ravi

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Re: [R] help with the unique function

2008-05-07 Thread Erik Iverson

ravi -

This may get you started

count.reps - function(df) {
  hash  - do.call(paste, c(df, sep = \r))
  cbind(unique(df), Freq = unclass(table(hash)))
}

test - data.frame(a = rep(1:10, 2), b = rep(1:10, 2))
count.reps(test)

Best,
Erik Iverson

ravi wrote:

Hi,
The unique function is easy to understand and use. Beyond that, I want to get 
also the frequency of repetition of each individual row in a data frame
Let me explain with an example :
x-data.frame(a=c(1,2,3,1,2),b=c(2,3,4,2,3),c=c(10,20,30,10,20))
xu-unique(x)
We have,

x

  a b  c
1 1 2 10
2 2 3 20
3 3 4 30
4 1 2 10
5 2 3 20

xu

  a b  c
1 1 2 10
2 2 3 20
3 3 4 30

I want to get the following data frame :
  a b  cFreq
1 1 2 102
2 2 3 202
3 3 4 301
That is, in addition to the unique rows, I want to get the frequency of 
repetion of each individual row.
I will appreciate all the help that I can get.
Thank You,
Ravi

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Re: [R] help with the unique function

2008-05-07 Thread Marc Schwartz

ravi wrote:

Hi,
The unique function is easy to understand and use. Beyond that, I want to get 
also the frequency of repetition of each individual row in a data frame
Let me explain with an example :
x-data.frame(a=c(1,2,3,1,2),b=c(2,3,4,2,3),c=c(10,20,30,10,20))
xu-unique(x)
We have,

x

  a b  c
1 1 2 10
2 2 3 20
3 3 4 30
4 1 2 10
5 2 3 20

xu

  a b  c
1 1 2 10
2 2 3 20
3 3 4 30

I want to get the following data frame :
  a b  cFreq
1 1 2 102
2 2 3 202
3 3 4 301
That is, in addition to the unique rows, I want to get the frequency of 
repetion of each individual row.
I will appreciate all the help that I can get.
Thank You,
Ravi


As usual in R, there are several options:

 table(apply(x, 1, paste, collapse = ,))

1,2,10 2,3,20 3,4,30
 2  2  1

or:

 table(interaction(x, sep = ,, drop = TRUE))

1,2,10 2,3,20 3,4,30
 2  2  1


So:

 cbind(unique(x),
Freq = as.vector(table(apply(x, 1, paste, collapse = ,
  a b  c Freq
1 1 2 102
2 2 3 202
3 3 4 301

or:

 cbind(unique(x),
Freq = as.vector(table(interaction(x, sep = ,, drop = TRUE
  a b  c Freq
1 1 2 102
2 2 3 202
3 3 4 301


HTH,

Marc Schwartz

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[R] PC configuration you are using

2008-05-07 Thread Endre Domiczi
Hello,

As I mentioned in the previous message we are developing solution for
wholesale companies to analyze their sales transactions by associative
rules. I would very much appreciated if the community could give us
some hint of what is a typical PC configuration of a professional
statist (processor, RAM, HDD...)?

Thanks a lot in advance and I highly appreciate your feedback!

Kind regards,
endre

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Sevana Oy, http://www.sevana.fi
Email : [EMAIL PROTECTED]
GSM   : +372 53485178
Skype : emddom

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Re: [R] Solution of function

2008-05-07 Thread Megh Dal
I think I should be clear exactly what I want :

take following example :

a = b = seq(1, 5, by=500)
 v = matrix(0, nrow=length(a), ncol=length(a))
 for (i in 1:length(a))
   {
for (j in 1:length(a))
   {
d = c(17989*a[i], -18109*b[j])
v[i,j] = t(d) %*% matrix(c(0.0001741, 0.0001280, 0.0001280,
0.0002570), nrow=2) %*% d
   }
   }
 library(rgl)
 open3d()
 persp3d(a,b,v,col=green,alpha=0.7,aspect=c(1,1,0.5))
shade - outer(a, b, function(x,y) (0  (x-y))  ((x-y)  2))
  persp3d(a,b,v,col=ifelse(shade, red, green), alpha=0.7,aspect=c(1,1,0.5))


Here you see that the surface is the plot of a x'Cx for different values of 
components of x. And the red region is the portion of that plot that satisfy 0 
x-y  2..

Now suppose user choose a point on red portion of that surface. Now I have to 
tell (through some computationally efficient way) what is the corresponding 
component values of x.

Any suggestion please?



 
Peter Dalgaard [EMAIL PROTECTED] wrote: Megh Dal wrote:
 Hi,

   I want to find solution of function :  f(x,y) = x'Cx - a under constraints :

   0  x,y  p
   0  x-y q

   where a, p,q are given constants and x = (x, y) and C is a 2X2 matrix 
 (given)

   Can anyone suggest me any R function to do that?

   
Not likely. What you have (if C is  positive definite) is the
intersection between the boundary of an ellipse and the interior of a
parallelepiped, where the center of the ellipse and one corner of the
parallelepiped is at (0,0).

This is the union of between zero and three curve segments (hmm, maybe
only two) and I don't think any of the standard solvers and minimizers
can come up with that kind of result.

-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907




   
-
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[R] how to define .Renviron to work with different R-versions

2008-05-07 Thread Poornima Reddy
Hi,

I have a simple R script for printing arguments
cat  printargs.R  EOF
args = commandArgs()
print(args)
q()
EOF

   To run this script, first I set PATH to ~/src/R-2.6.2 and execute 
R --no-save  printargs.R

   I want to run this script with different R versions by defining an
.Renviron file in the same directory as printargs.R

   cat  .Renviron  EOF
   R_VERISON=R-2.7.0
   R_HOME=~/src/${R_VERSION}
   PATH=${R_HOME}/bin:${PATH}
   R_LIBS=${R_HOME}/library
   EOF

   Now when I run  R --no-save  printargs.R, I get
   Error in gzfile(file, rb) : cannot open the connection
   In addition: Warning message:
   In gzfile(file, rb) :  cannot open compressed file
'/home/ppreddy/src//library/base/R/base.rdx', probable reason 'No such
file or directory'
   Execution halted

   I do not know for sure, if I can define R_VERSION, R_HOME, and PATH
in .Renviron. All I have seen is defining R_LIBS/JAV_HOME in r-help
archives.
   So, please explain how to use the .Renviron to work with
R-different R-versions and also Should I place .Renviron in the home
dir instead of cwd?

Thanks,
Poornima.

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Re: [R] help with the unique function

2008-05-07 Thread Ted Harding
On 07-May-08 16:31:23, Erik Iverson wrote:
 ravi -
 This may get you started
 
 count.reps - function(df) {
hash  - do.call(paste, c(df, sep = \r))
cbind(unique(df), Freq = unclass(table(hash)))
 }
 
 test - data.frame(a = rep(1:10, 2), b = rep(1:10, 2))
 count.reps(test)

That doesn't work: It muddles the Association of the unique
values with the counts:

  A-sample(c(0,1),100,replace=TRUE)
  B-sample(c(0,1),100,replace=TRUE)
  C-sample(c(0,1),100,replace=TRUE)
  sum((A==0)(B==0)(C==0))  ## [1] 26
  sum((A==0)(B==0)(C==1))  ## [1]  9
  sum((A==0)(B==1)(C==0))  ## [1] 10
  sum((A==0)(B==1)(C==1))  ## [1]  7
  sum((A==1)(B==0)(C==0))  ## [1] 15
  sum((A==1)(B==0)(C==1))  ## [1] 11
  sum((A==1)(B==1)(C==0))  ## [1]  5
  sum((A==1)(B==1)(C==1))  ## [1] 17

  test-data.frame(A=A,B=B,C=C)
  count.reps(test)
#A B C Freq
# 1  0 0 1   26
# 2  0 1 09
# 3  1 0 1   10
# 4  1 0 07
# 5  1 1 1   15
# 6  0 0 0   11
#14  1 1 05
#25  0 1 1   17

So the freqencies come out in the order I found them (binary
counting: ABC=000,001,010,011,100,101,110,111) but with the
(A,B,C) values in a quite different order.

I can't, myself, make out why this is happening, but no doubt
someone else can, and may sugest a correction!

Ted.








 Best,
 Erik Iverson
 
 ravi wrote:
 Hi,
 The unique function is easy to understand and use. Beyond that, I want
 to get also the frequency of repetition of each individual row in a
 data frame
 Let me explain with an example :
 x-data.frame(a=c(1,2,3,1,2),b=c(2,3,4,2,3),c=c(10,20,30,10,20))
 xu-unique(x)
 We have,
 x
   a b  c
 1 1 2 10
 2 2 3 20
 3 3 4 30
 4 1 2 10
 5 2 3 20
 xu
   a b  c
 1 1 2 10
 2 2 3 20
 3 3 4 30
 
 I want to get the following data frame :
   a b  cFreq
 1 1 2 102
 2 2 3 202
 3 3 4 301
 That is, in addition to the unique rows, I want to get the frequency
 of repetion of each individual row.
 I will appreciate all the help that I can get.
 Thank You,
 Ravi
 
 __
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 PLEASE do read the posting guide
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E-Mail: (Ted Harding) [EMAIL PROTECTED]
Fax-to-email: +44 (0)870 094 0861
Date: 07-May-08   Time: 18:02:09
-- XFMail --

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Re: [R] predict lmer

2008-05-07 Thread Bert Gunter
?fixef

gets you the coefficient vector, from which you can make your predictions.

-- Bert Gunter
Genentech

-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of May, Roel
Sent: Wednesday, May 07, 2008 7:23 AM
To: r-help@r-project.org
Subject: [R] predict lmer

Hi,
 
I am using lmer to analyze habitat selection in wolverines using the
following model:
 
(me.fit.of -
lmer(USED~1+STEP+ALT+ALT2+relM+relM:ALT+(1|ID)+(1|ID:TRKPT2),data=vdata,
control=list(usePQL=TRUE),family=poisson,method=Laplace))
 
Here, the habitat selection is calaculated using a so-called discrete
choice model where each used location has a certain number of
alternatives which the animal could have chosen. These sets of locations
are captured using the TRKPT2 random grouping. However, these sets are
also clustered over the different individuals (ID). USED is my binary
dependent variable which is 1 for used locations and zero for unused
locations. The other are my predictors.
 
I would like to predict the model fit at different values of the
predictors, but does anyone know whether it is possible to do this? I
have looked around at the R-sites and in help but it seems that there
doesn't exist a predict function for lmer???
 
I hope someone can help me with this; point me to the right functions or
tell me to just forget it
 
Thanks in advance!
 
Cheers Roel
 
Roel May
Norwegian Institute for Nature Research
Tungasletta 2, NO-7089 Trondheim, Norway


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Re: [R] predict lmer

2008-05-07 Thread Bert Gunter
Sorry, my reply below may be too terse. You'll need to also construct the
appropriate design matrix to which to apply the fixef() results to.

If newDat is a data.frame containing **exactly the same named regressor and
response columns** as your original vdata dataframe, and if me.fit.of is
your fitted lmer object as you have defined it below, then

 model.matrix(terms(me.fit.of),newDat) %*% fixef(me.fit.of)

gives your predictions. Note that while the response column in newDat is
obviously unnecessary for prediction (you can fill it with 0's,say), it is
nevertheless needed for model.matrix to work. This seems clumsy to me, so
there may well be better ways to do this, and **I would appreciate
suggestions for improvement.*** 


Cheers,
Bert



-Original Message-
From: bgunter 
Sent: Wednesday, May 07, 2008 9:53 AM
To: May, Roel; r-help@r-project.org
Subject: RE: [R] predict lmer

?fixef

gets you the coefficient vector, from which you can make your predictions.

-- Bert Gunter
Genentech

-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of May, Roel
Sent: Wednesday, May 07, 2008 7:23 AM
To: r-help@r-project.org
Subject: [R] predict lmer

Hi,
 
I am using lmer to analyze habitat selection in wolverines using the
following model:
 
(me.fit.of -
lmer(USED~1+STEP+ALT+ALT2+relM+relM:ALT+(1|ID)+(1|ID:TRKPT2),data=vdata,
control=list(usePQL=TRUE),family=poisson,method=Laplace))
 
Here, the habitat selection is calaculated using a so-called discrete
choice model where each used location has a certain number of
alternatives which the animal could have chosen. These sets of locations
are captured using the TRKPT2 random grouping. However, these sets are
also clustered over the different individuals (ID). USED is my binary
dependent variable which is 1 for used locations and zero for unused
locations. The other are my predictors.
 
I would like to predict the model fit at different values of the
predictors, but does anyone know whether it is possible to do this? I
have looked around at the R-sites and in help but it seems that there
doesn't exist a predict function for lmer???
 
I hope someone can help me with this; point me to the right functions or
tell me to just forget it
 
Thanks in advance!
 
Cheers Roel
 
Roel May
Norwegian Institute for Nature Research
Tungasletta 2, NO-7089 Trondheim, Norway


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Re: [R] help with the unique function

2008-05-07 Thread Phil Spector

Another way to produce the data frame is

subset(as.data.frame(table(x)),Freq0)

   - Phil Spector
 Statistical Computing Facility
 Department of Statistics
 UC Berkeley
 [EMAIL PROTECTED]


On Wed, 7 May 2008, ravi wrote:


Hi,
The unique function is easy to understand and use. Beyond that, I want to get 
also the frequency of repetition of each individual row in a data frame
Let me explain with an example :
x-data.frame(a=c(1,2,3,1,2),b=c(2,3,4,2,3),c=c(10,20,30,10,20))
xu-unique(x)
We have,

x

  a b  c
1 1 2 10
2 2 3 20
3 3 4 30
4 1 2 10
5 2 3 20

xu

  a b  c
1 1 2 10
2 2 3 20
3 3 4 30

I want to get the following data frame :
  a b  c    Freq
1 1 2 10    2
2 2 3 20    2
3 3 4 30    1
That is, in addition to the unique rows, I want to get the frequency of 
repetion of each individual row.
I will appreciate all the help that I can get.
Thank You,
Ravi

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Re: [R] categorical data analysis - fisher.exact for 2x2 and greater

2008-05-07 Thread Brian S Cade
Jeff and others:

Paul Mielke and Ken Berry at Colorado State University developed very fast 
Fortran routines for doing Fisher exact tests (as well as some others like 
Chi-square and Zelterman's statistics).   Their book (Permutation Methods: 
A Distance Function Approach, 2nd ed.  2007. Springer) indicates that 
these algorithms were only efficient for = 5 conditional loops so 2x2, 
3x2, 4x2, 5x2, 6x2, 3x3, and 2x2x2 were feasible back in the 1990's.   I'm 
not sure whether more recent computing capability permits larger tables 
now. 

Brian

Brian S. Cade

U. S. Geological Survey
Fort Collins Science Center
2150 Centre Ave., Bldg. C
Fort Collins, CO  80526-8818

email:  [EMAIL PROTECTED]
tel:  970 226-9326



Dr. Jeff Miller [EMAIL PROTECTED] 
Sent by: [EMAIL PROTECTED]
05/07/2008 09:56 AM

To
'Greg Snow' [EMAIL PROTECTED], 'David Winsemius' 
[EMAIL PROTECTED], [EMAIL PROTECTED]
cc

Subject
Re: [R] categorical data analysis - fisher.exact for 2x2 and greater






Hi Simon and all,

I'm pretty sure that you are correct about this. I think it is a
misconception to say that the fisher exact test is only for a 2 by 2 
table.
It is presented that way in textbooks because, for a 2x2 table, it is easy
to perform.  For larger tables, it becomes complex quickly due to the rate
at which the permutations increase.

 When I use it for larger tables, it is hit or miss as to whether R will 
be
able to do it.  It's not uncommon to get an error implying that R is out 
of
memory. 

Check out Agresti's Categorical Data Analysis on the use of the fisher 
exact
for larger than 2x2 tables, and check out the R archives (and Google 
search)
for all the posts about the error message people run into sometimes.

On April 29th, Marc Schwartz replied to my question about this as follows:

Take a look at the 'workspace' argument in ?fisher.test and review the
second paragraph in Details:

For 2 by 2 cases, p-values are obtained directly using the (central or
non-central) hypergeometric distribution. Otherwise, computations are 
based
on a C version of the FORTRAN subroutine FEXACT which implements the 
network
developed by Mehta and Patel (1986) and improved by Clarkson, Fan and Joe
(1993). The FORTRAN code can be obtained from
http://www.netlib.org/toms/643. Note this fails (with an error message) 
when
the entries of the table are too large. (It transposes the table if
necessary so it has no more rows than columns. One constraint is that the
product of the row marginals be less than 2^31 - 1.)



Thank you,
Jeff



-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] 
On
Behalf Of Greg Snow
Sent: Wednesday, May 07, 2008 9:55 AM
To: David Winsemius; [EMAIL PROTECTED]
Subject: Re: [R] categorical data analysis

The last example in ?fisher.test is not a 2x2 table, in fact it uses 
levels
with a natural ordering similar to the original question.  Why would this
not be applicable to the situation?


From: [EMAIL PROTECTED] [EMAIL PROTECTED] On 
Behalf
Of David Winsemius [EMAIL PROTECTED]
Sent: Wednesday, May 07, 2008 7:34 AM
To: [EMAIL PROTECTED]
Subject: Re: [R] categorical data analysis

Simon Blomberg [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:

 But see these posts:

 http://finzi.psych.upenn.edu/R/Rhelp02a/archive/119079.html

 http://finzi.psych.upenn.edu/R/Rhelp02a/archive/119080.html

 Simon.

Interesting reading, but the OP specifically said he was not dealing with
2x2 tables, so neither fisher.test nor the suggested alternatives would
be applicable to his data situation.

--
David Winsemius

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Internal Virus Database is out-of-date.


11:27 AM
 

Internal Virus Database is out-of-date.


11:27 AM

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Re: [R] use list elements to subtract values from the dataframe

2008-05-07 Thread Julian Burgos

Try
get(paste(wf$,fl[[1]],sep=))

See ?get

Julian


Dirkheld wrote:

Hi,

I have a dataframe wf existing of a header with different labels and beneath
the values of those labels :
wf:
label1  label2  ...
0,450,21
0,100,45 
  


I have a list
fl - c(label2,label3,..)

Isn't possible to use the list elements in the list in order to subtract
values from the dataframe? like :
wf$fl[[1]] 
When I do in R I get :NULL

fl[[1]] gives  label2  so no problem here...

While wf$label1 works fine.





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[R] help with updating to R2.7

2008-05-07 Thread ravi
Hi,
From R 2.6, I would like to update to R2.7. I would like to have some tips on 
the recommended method of installing the latest versions of an entire list of 
packages in R2.7 - i.e. all the packages that I have presently installed in 
R2.6.
I am hoping that there is an easier method than fetching the packages 
individually as I did, to begin with, for R2.6.
Additionally, I would like to install R2.7 on another pc which is not connected 
to the internet. I have previously installed R2.6 on it by fetching the zip 
files from another pc and installed them from the local zip files. I would like 
to know if there is a method of transferring an entire installation 
(base+selected packages) from one pc to another. Will there be a special 
problem if the first is a win vista pc and the 2nd has win 2000?
One problem that I have in continuing to use R2.6 is in getting compatible 
versions of a new package that happens to attract my interest. For example, I 
was interested in getting the arm package for R2.6.1. I could not find the 
package in the R Binaries list on CRAN webpage. In the packages list, I did 
find old versions in the arm archive. However, the files were in 
.tar.gz format. How does one install from this format? It does not appear 
to be as straightforward as in installing from the zip format files.Recently, I 
had the same problem in installing a compatible version of the norm package 
also. I am interested to know how I can tackle these problems.
I will appreciate all the help that I can get.
Thanks,
Ravi

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[R] dlm with constant terms

2008-05-07 Thread Stoyanov, Tsvetan (MSCIBARRA)
Hi,
I am trying to figure how to use dlm with constant terms
(possibly time-dependent) added to both equations
y_t = c_t + F_t\theta_t + v_t
\theta_t = d_t + G_t\theta_{t-1} + w_t,
in the way that S-PLUS Finmetrics does?

Is there any straightforward way to transform the above to
the default setup?
Thanks,
Tsvetan


NOTICE: If received in error, please destroy and notify sender. Sender does not 
intend to waive confidentiality or privilege. Use of this email is prohibited 
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Re: [R] PC configuration you are using

2008-05-07 Thread Jorge Ivan Velez
Hi Endre,

I'm not sure if my configuration is typical. I'm running XP SP2, 4GB RAM and
Intel Core 2-Duo Processor of 2.4 GHz with 200GB HDD. My R version is R
2.7.0 Patched.

HTH,

Jorge


On Wed, May 7, 2008 at 12:49 PM, Endre Domiczi [EMAIL PROTECTED] wrote:

 Hello,

 As I mentioned in the previous message we are developing solution for
 wholesale companies to analyze their sales transactions by associative
 rules. I would very much appreciated if the community could give us
 some hint of what is a typical PC configuration of a professional
 statist (processor, RAM, HDD...)?

 Thanks a lot in advance and I highly appreciate your feedback!

 Kind regards,
 endre

 --
 Endre Domiczi, CEO
 Sevana Oy, http://www.sevana.fi
 Email : [EMAIL PROTECTED]
 GSM   : +372 53485178
 Skype : emddom

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Re: [R] Estimating QAIC using glm with the quasibinomial family

2008-05-07 Thread Darren Gillis
Thank you for the rapid response.  I have no trouble in following your
example, but I was specificly interested in calculating QAIC and QAICc from
a glm fitted with the family=quasibinomial option.  This provides an
estimate of dispersion, but does not contain an explicit value for AIC or
log-likelihood.  Do you have any insights into how to deal with the output
from this specific option?  Or are you suggesting not to use
family=quasibinomial when faced with potential overdispersion?  Regardless,
thank you again for your response.

Cheers, Darren


-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of Kunio takezawa
Sent: Tuesday, May 06, 2008 8:41 PM
To: r-help@r-project.org
Subject: Re: [R] Estimating QAIC using glm with the quasibinomial family

R-users
E-mail: r-help@r-project.org

My question is: Will this calculation be valid with the residual 
deviance returned by the glm() function using the quasibinomial family 
as reported in R?

   Let me show you a simple example, assuming c=2.5:

function ()
{
   xx - c(1,2,3,4,5,6,7,8,9,10)
   yy - c(1,0,1,0,0,1,0,1,1,1)
   data1 - data.frame(x=xx, y=yy)
   out1 - glm(y~x, data=data1, family=binomial)
   print(out1)
   aic0 - out1$aic
   print(aic0)
   print(aic0)

   dev1 - out1$deviance
   aic1 -  dev1+ 2*2
   print(aic1)
   print(aic1)

   c1 - 2.5
   qaic1 -  dev1/c1+ 2*2
   print(qaic1)
   print(qaic1)
}

The result is:

Call:  glm(formula = y ~ x, family = binomial, data = data1)

Coefficients:
(Intercept)x
-0.7300   0.2131

Degrees of Freedom: 9 Total (i.e. Null);  8 Residual
Null Deviance:  13.46
Residual Deviance: 12.63AIC: 16.63
[1] aic0
[1] 16.63054
[1] aic1
[1] 16.63054
[1] qaic1
[1] 9.052216

   I hope that this R program will be of some help to you.

K. Takezawa

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[R] algorithmic or automatic differentiation

2008-05-07 Thread Erin Hodgess
Hi R People:

Is there a package for automatic differentiation, please?

thanks in advance,
Erin


-- 
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: [EMAIL PROTECTED]

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Re: [R] rggobi is crashing R-2.7.0

2008-05-07 Thread Paul Johnson
On Tue, May 6, 2008 at 12:32 PM, Mark Kimpel [EMAIL PROTECTED] wrote:
 I am running 64-bit Ubuntu 8.04 and when I invoke rggobi the interactive
  graph displays but R crashes. See my sessionInfo() and a short example
  below. Ggobi and rggobi installed without complaints. Mark

   sessionInfo()
  R version 2.7.0 Patched (2008-05-04 r45620)
  x86_64-unknown-linux-gnu


In the R 2.7 release notes, there is a comment about a change in the
GUI libraries and it says that one must recompile everything that
relies on R.  If your R 2.7 was an upgrade, not a fresh install, it
could explain why this is happening.  If there's some old library or R
package sitting around, it could account for this.

The part that concerned me about the R release note is that they don't
give a very clear guide on how far back in the toolchain we are
supposed to go.  Certainly, ggobi has to be rebuilt from scratch.  But
are any of the things on which ggobi depends needing recompliation as
well.

pj


-- 
Paul E. Johnson
Professor, Political Science
1541 Lilac Lane, Room 504
University of Kansas

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Re: [R] rggobi is crashing R-2.7.0

2008-05-07 Thread Mark Kimpel
Uninstalling and reinstalling ggobi via Synaptic solved the problem, at
least for the demo data mtcars. Rotation works fine. No crashes on exit.

Thanks for the good advice.

Mark

On Wed, May 7, 2008 at 2:12 PM, Paul Johnson [EMAIL PROTECTED] wrote:

 On Tue, May 6, 2008 at 12:32 PM, Mark Kimpel [EMAIL PROTECTED] wrote:
  I am running 64-bit Ubuntu 8.04 and when I invoke rggobi the interactive
   graph displays but R crashes. See my sessionInfo() and a short example
   below. Ggobi and rggobi installed without complaints. Mark
 
sessionInfo()
   R version 2.7.0 Patched (2008-05-04 r45620)
   x86_64-unknown-linux-gnu
 

 In the R 2.7 release notes, there is a comment about a change in the
 GUI libraries and it says that one must recompile everything that
 relies on R.  If your R 2.7 was an upgrade, not a fresh install, it
 could explain why this is happening.  If there's some old library or R
 package sitting around, it could account for this.

 The part that concerned me about the R release note is that they don't
 give a very clear guide on how far back in the toolchain we are
 supposed to go.  Certainly, ggobi has to be rebuilt from scratch.  But
 are any of the things on which ggobi depends needing recompliation as
 well.

 pj


 --
 Paul E. Johnson
 Professor, Political Science
 1541 Lilac Lane, Room 504
 University of Kansas




-- 
Mark W. Kimpel MD ** Neuroinformatics ** Dept. of Psychiatry
Indiana University School of Medicine

15032 Hunter Court, Westfield, IN 46074

(317) 490-5129 Work,  Mobile  VoiceMail
(317) 663-0513 Home (no voice mail please)

**

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Re: [R] help with updating to R2.7

2008-05-07 Thread Gabor Grothendieck
There are a few different methods discussed in the README to the batchfiles
distribution.  Home page at:

http://batchfiles.googlecode.com


On Wed, May 7, 2008 at 12:51 PM, ravi [EMAIL PROTECTED] wrote:
 Hi,
 From R 2.6, I would like to update to R2.7. I would like to have some tips 
 on the recommended method of installing the latest versions of an entire 
 list of packages in R2.7 - i.e. all the packages that I have presently 
 installed in R2.6.
 I am hoping that there is an easier method than fetching the packages 
 individually as I did, to begin with, for R2.6.
 Additionally, I would like to install R2.7 on another pc which is not 
 connected to the internet. I have previously installed R2.6 on it by fetching 
 the zip files from another pc and installed them from the local zip files. I 
 would like to know if there is a method of transferring an entire 
 installation (base+selected packages) from one pc to another. Will there be a 
 special problem if the first is a win vista pc and the 2nd has win 2000?
 One problem that I have in continuing to use R2.6 is in getting compatible 
 versions of a new package that happens to attract my interest. For example, I 
 was interested in getting the arm package for R2.6.1. I could not find the 
 package in the R Binaries list on CRAN webpage. In the packages list, I did 
 find old versions in the arm archive. However, the files were in 
 .tar.gz format. How does one install from this format? It does not 
 appear to be as straightforward as in installing from the zip format 
 files.Recently, I had the same problem in installing a compatible version of 
 the norm package also. I am interested to know how I can tackle these 
 problems.
 I will appreciate all the help that I can get.
 Thanks,
 Ravi

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[R] pivoting - summing up factors

2008-05-07 Thread juanita choo
Hi
I would like to know how to pivot a table that will sum the number of plants
(a or b) for each location (x,y,z)
I have read on the listserve similar questions but which involve summing up
numbers rather than factors.  I have also read about the R package reshape
on the listserve but wanted to know if there's a way to do it easily without
the package
Thanks for the help!

location  plant
 x a
 x b
 x b
 y b
 y b
 y a
 z a
 z a

into a table like this


   xy   z
a 11   2
b 22   0

[[alternative HTML version deleted]]

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] pivoting - summing up factors

2008-05-07 Thread jim holtman
Is this what you want:

 x
  location plant
1x a
2x b
3x b
4y b
5y b
6y a
7z a
8z a

 table(x$plant,x$location)

x y z
  a 1 1 2
  b 2 2 0



On Wed, May 7, 2008 at 2:56 PM, juanita choo [EMAIL PROTECTED] wrote:
 Hi
 I would like to know how to pivot a table that will sum the number of plants
 (a or b) for each location (x,y,z)
 I have read on the listserve similar questions but which involve summing up
 numbers rather than factors.  I have also read about the R package reshape
 on the listserve but wanted to know if there's a way to do it easily without
 the package
 Thanks for the help!

 location  plant
  x a
  x b
  x b
  y b
  y b
  y a
  z a
  z a

 into a table like this


   xy   z
 a 11   2
 b 22   0

[[alternative HTML version deleted]]

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?

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Re: [R] pivoting - summing up factors

2008-05-07 Thread Yasir Kaheil

assuming what you have is a dataframe called x
try:
table(Plant=x$plant,Location=x$location)
 Location
Plant x y z
a 1 1 2
b 2 2 0

or simply:
table(x$plant,x$location)
   
x y z
  a 1 1 2
  b 2 2 0

thanks


juanita choo wrote:
 
 Hi
 I would like to know how to pivot a table that will sum the number of
 plants
 (a or b) for each location (x,y,z)
 I have read on the listserve similar questions but which involve summing
 up
 numbers rather than factors.  I have also read about the R package reshape
 on the listserve but wanted to know if there's a way to do it easily
 without
 the package
 Thanks for the help!
 
 location  plant
  x a
  x b
  x b
  y b
  y b
  y a
  z a
  z a
 
 into a table like this
 
 
xy   z
 a 11   2
 b 22   0
 
   [[alternative HTML version deleted]]
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
 
 


-
Yasir H. Kaheil, Ph.D.
Catchment Research Facility
The University of Western Ontario 

-- 
View this message in context: 
http://www.nabble.com/pivoting---summing-up-factors-tp17112158p17112407.html
Sent from the R help mailing list archive at Nabble.com.

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[R] coxph - weights- robust SE

2008-05-07 Thread willy . wynant . chum
Hi,

I am using coxph with weights to represent sampling fraction of subjects. 
Our simulation results show that the robust SE of beta systematically 
under-estimate the empirical SD of beta. 
Does anyone know how the robust SE are estimated in coxph using weights? 
Is there any analytical formula for the “weighted” robust SE?

Any help is appreciated!

Thanks so much in advance

Willy

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[R] 2D correlation/convolution ?

2008-05-07 Thread H. Paul Benton

What is the command for 2D fft? Or 2D convolution and or auto-correlation?

Thanks,

Paul

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[R] Advanced R/S-Plus Course by XLSolutions Corp / May 2008 in San Francisco Boston

2008-05-07 Thread Sue Turner
Please check out these upcoming courses offered by  XLSolutions
Corporation.

**Payments due after the class

R/Splus Advanced Programming course: May 29-30, 2008 in  San Francisco -
4 seats left.


R/Splus Advanced Programming course: May 29-30, 2008 in  Boston - 2
seats left.


R/Splus Fundamentals and Programming Techniques: June 19-20  in Boston


Payment due AFTER the class
Email us for group discounts.
Email Sue Turner: [EMAIL PROTECTED]
Phone: 206-686-1578
Visit us: www.xlsolutions-corp.com/courselist.htm
Please let us know if you and your colleagues are interested in this
class to take advantage of group discount. 

Register now to secure your seat!

Cheers,
Elvis Miller, PhD
Manager Training.
XLSolutions Corporation
206 686 1578
www.xlsolutions-corp.com

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[R] Problem installing tseries under FC7 x86_64

2008-05-07 Thread Michael Steinbeck-Reeves
I have just installed the 64 bit version of R, using yum. The version
is: 2.6.2-1.fc7.1.x86_64.

I installed zoo without any major problem and the same with quadprog (a
few warnings). However, when I came to install tseries I get the
following:

 install.packages()
Warning in install.packages() :
  argument 'lib' is missing: using
'/home/xx/R/x86_64-redhat-linux-gnu-library/2.6'
trying URL
'http://cran.uk.r-project.org/src/contrib/tseries_0.10-14.tar.gz'
Content type 'application/x-gzip' length 171219 bytes (167 Kb)
opened URL
==
downloaded 167 Kb

* Installing *source* package 'tseries' ...
** libs
gcc -m64 -std=gnu99 -I/usr/include/R -I/usr/include/R
-I/usr/local/include-fpic  -O2 -g -pipe -Wall
-Wp,-D_FORTIFY_SOURCE=2 -fexceptions -fstack-protector
--param=ssp-buffer-size=4 -m64 -mtune=generic -c arma.c -o arma.o
gcc -m64 -std=gnu99 -I/usr/include/R -I/usr/include/R
-I/usr/local/include-fpic  -O2 -g -pipe -Wall
-Wp,-D_FORTIFY_SOURCE=2 -fexceptions -fstack-protector
--param=ssp-buffer-size=4 -m64 -mtune=generic -c bdstest.c -o bdstest.o
bdstest.c:25:15: error: R.h: No such file or directory
bdstest.c: In function ‘freeall’:
bdstest.c:86: warning: implicit declaration of function ‘Free’
bdstest.c: In function ‘evalc’:
bdstest.c:172: warning: implicit declaration of function ‘Rprintf’
bdstest.c: In function ‘fkc’:
bdstest.c:289: warning: implicit declaration of function ‘Calloc’
bdstest.c:289: error: expected expression before ‘int’
bdstest.c:289: warning: assignment makes pointer from integer without a
cast
bdstest.c:290: error: expected expression before ‘int’
bdstest.c:290: warning: assignment makes pointer from integer without a
cast
bdstest.c:295: error: expected expression before ‘struct’
bdstest.c:295: warning: assignment makes pointer from integer without a
cast
bdstest.c:300: error: expected expression before ‘short’
bdstest.c:300: warning: assignment makes pointer from integer without a
cast
bdstest.c:307: error: expected expression before ‘short’
bdstest.c:307: warning: assignment makes pointer from integer without a
cast
bdstest.c:309: warning: implicit declaration of function ‘error’
bdstest.c:352: warning: implicit declaration of function ‘qsort’
make: *** [bdstest.o] Error 1
ERROR: compilation failed for package 'tseries'
** Removing '/home/x/R/x86_64-redhat-linux-gnu-library/2.6/tseries'

The downloaded packages are in
/tmp/RtmpocpCZU/downloaded_packages
Warning message:
In install.packages() :
  installation of package 'tseries' had non-zero exit status

I realise that R.h is missing and is not on my machine anywhere. What
have I missed?

Thanks,

Michael

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[R] cross-correlation lag.plot?

2008-05-07 Thread tom soyer
Hi,

Does anyone know if R has a function that is similar to lag.plot but instead
of auto-correlation, it plots cross-correlation with lags?

Thanks,

-- 
Tom

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[R] solution to differences in sequential and marginal ANOVA using a mixed model

2008-05-07 Thread Bill Shipley
Yesterday I posted the following question to the help list.  Thanks to John
Fox (copied below) who pointed out the solution.

 

Original question:

 

I have come across a result that I cannot explain, and am hopingthat someone
else can provide an answer.  A student fitted a mixed model  usingthe lme
function: out- lme(fixed=Y~A+B+A:B, random=~1|Site).  Y is a continuous
variable while A and B are factors.  The data set is balanced with the same
number of observations in each combination of A and B.  There are two
hierarchical levels: Site and plots nested in site. 

He tried two different ways of getting theANOVA table: anova(out) and
anova(out, type=marginal). Since the data were balanced, these two ways
should (I think) give the same output since they correspond to Type I and
III sums of squares in the SAS terminology.  At least, this is the case with
normal (i.e. not mixed) linear models.  However, he finds very different
results of these two types of ANOVA tables.  Why?

 

Response of John Fox:

 

Dear Bill,

 

I expect that the problem is in the contrasts that your student used for A
and B, though I haven't thought specifically about the context of a mixed
model. If he or she used the default contr.treatment(), then the contrasts
for different factors (and the interaction) are not orthogonal in the row
basis of the model matrix and hence are not orthogonal, even for balanced
data. Using, e.g., contr.sum() should provide A, B, and A:B contrasts that
are orthogonal to each other.

 

Indeed, changing to an appropriate type of contrast did solve the problem!
My problem was in forgetting that R uses treatment contrasts by default
while SPLUS uses Helmert contrasts by default (which would have worked as
well as sum contrasts).


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Re: [R] rggobi is crashing R-2.7.0

2008-05-07 Thread Michael Lawrence
On Wed, May 7, 2008 at 11:40 AM, Mark Kimpel [EMAIL PROTECTED] wrote:

 Uninstalling and reinstalling ggobi via Synaptic solved the problem, at
 least for the demo data mtcars. Rotation works fine. No crashes on exit.

 Thanks for the good advice.


I am pretty sure what Paul is referring to is the graphics device stuff.
GGobi does not link against R anyway, so R would not be the problem here.

The reason rebuilding GGobi fixed it, is that your GGobi binary was linked
against an old version of graphviz. The new version broke binary
compatibility, thus you needed to install a GGobi binary built against the
new version.


 Mark

 On Wed, May 7, 2008 at 2:12 PM, Paul Johnson [EMAIL PROTECTED] wrote:

  On Tue, May 6, 2008 at 12:32 PM, Mark Kimpel [EMAIL PROTECTED] wrote:
   I am running 64-bit Ubuntu 8.04 and when I invoke rggobi the
 interactive
graph displays but R crashes. See my sessionInfo() and a short
 example
below. Ggobi and rggobi installed without complaints. Mark
  
 sessionInfo()
R version 2.7.0 Patched (2008-05-04 r45620)
x86_64-unknown-linux-gnu
  
 
  In the R 2.7 release notes, there is a comment about a change in the
  GUI libraries and it says that one must recompile everything that
  relies on R.  If your R 2.7 was an upgrade, not a fresh install, it
  could explain why this is happening.  If there's some old library or R
  package sitting around, it could account for this.
 
  The part that concerned me about the R release note is that they don't
  give a very clear guide on how far back in the toolchain we are
  supposed to go.  Certainly, ggobi has to be rebuilt from scratch.  But
  are any of the things on which ggobi depends needing recompliation as
  well.
 
  pj
 
 
  --
  Paul E. Johnson
  Professor, Political Science
  1541 Lilac Lane, Room 504
  University of Kansas
 



 --
 Mark W. Kimpel MD ** Neuroinformatics ** Dept. of Psychiatry
 Indiana University School of Medicine

 15032 Hunter Court, Westfield, IN 46074

 (317) 490-5129 Work,  Mobile  VoiceMail
 (317) 663-0513 Home (no voice mail please)

 **

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Re: [R] cross-correlation lag.plot?

2008-05-07 Thread Erin Hodgess
Hi!

Try ?ccf

HTH,
Erin


On 5/7/08, tom soyer [EMAIL PROTECTED] wrote:
 Hi,

 Does anyone know if R has a function that is similar to lag.plot but instead
 of auto-correlation, it plots cross-correlation with lags?

 Thanks,

 --
 Tom

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-- 
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: [EMAIL PROTECTED]

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Re: [R] Problem installing tseries under FC7 x86_64

2008-05-07 Thread Gavin Simpson
On Wed, 2008-05-07 at 21:09 +0100, Michael Steinbeck-Reeves wrote:
 I have just installed the 64 bit version of R, using yum. The version
 is: 2.6.2-1.fc7.1.x86_64.

Could it be that you don't have the development headers for R? Try:

yum install R-devel

as root in a console and then try installing tseries within R.

HTH

G

 
 I installed zoo without any major problem and the same with quadprog (a
 few warnings). However, when I came to install tseries I get the
 following:
 
  install.packages()
 Warning in install.packages() :
   argument 'lib' is missing: using
 '/home/xx/R/x86_64-redhat-linux-gnu-library/2.6'
 trying URL
 'http://cran.uk.r-project.org/src/contrib/tseries_0.10-14.tar.gz'
 Content type 'application/x-gzip' length 171219 bytes (167 Kb)
 opened URL
 ==
 downloaded 167 Kb
 
 * Installing *source* package 'tseries' ...
 ** libs
 gcc -m64 -std=gnu99 -I/usr/include/R -I/usr/include/R
 -I/usr/local/include-fpic  -O2 -g -pipe -Wall
 -Wp,-D_FORTIFY_SOURCE=2 -fexceptions -fstack-protector
 --param=ssp-buffer-size=4 -m64 -mtune=generic -c arma.c -o arma.o
 gcc -m64 -std=gnu99 -I/usr/include/R -I/usr/include/R
 -I/usr/local/include-fpic  -O2 -g -pipe -Wall
 -Wp,-D_FORTIFY_SOURCE=2 -fexceptions -fstack-protector
 --param=ssp-buffer-size=4 -m64 -mtune=generic -c bdstest.c -o bdstest.o
 bdstest.c:25:15: error: R.h: No such file or directory
 bdstest.c: In function ‘freeall’:
 bdstest.c:86: warning: implicit declaration of function ‘Free’
 bdstest.c: In function ‘evalc’:
 bdstest.c:172: warning: implicit declaration of function ‘Rprintf’
 bdstest.c: In function ‘fkc’:
 bdstest.c:289: warning: implicit declaration of function ‘Calloc’
 bdstest.c:289: error: expected expression before ‘int’
 bdstest.c:289: warning: assignment makes pointer from integer without a
 cast
 bdstest.c:290: error: expected expression before ‘int’
 bdstest.c:290: warning: assignment makes pointer from integer without a
 cast
 bdstest.c:295: error: expected expression before ‘struct’
 bdstest.c:295: warning: assignment makes pointer from integer without a
 cast
 bdstest.c:300: error: expected expression before ‘short’
 bdstest.c:300: warning: assignment makes pointer from integer without a
 cast
 bdstest.c:307: error: expected expression before ‘short’
 bdstest.c:307: warning: assignment makes pointer from integer without a
 cast
 bdstest.c:309: warning: implicit declaration of function ‘error’
 bdstest.c:352: warning: implicit declaration of function ‘qsort’
 make: *** [bdstest.o] Error 1
 ERROR: compilation failed for package 'tseries'
 ** Removing '/home/x/R/x86_64-redhat-linux-gnu-library/2.6/tseries'
 
 The downloaded packages are in
 /tmp/RtmpocpCZU/downloaded_packages
 Warning message:
 In install.packages() :
   installation of package 'tseries' had non-zero exit status
 
 I realise that R.h is missing and is not on my machine anywhere. What
 have I missed?
 
 Thanks,
 
 Michael
 
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Re: [R] predict lmer

2008-05-07 Thread Kingsford Jones
One question that arises is: at what level is the prediction desired?
Within a given ID:TRKPT2 level?  Within a given ID level?  At the
marginal level (which Bert's code appears to produce).  Also, there is
the question:  how confident can you be in your predictions.  This
thread discusses possible ways to get prediction intervals:

https://stat.ethz.ch/pipermail/r-sig-mixed-models/2008q2/thread.html#841

Finally, why assume a Poisson error distribution for a binary response?

Kingsford Jones

On Wed, May 7, 2008 at 10:13 AM, Bert Gunter [EMAIL PROTECTED] wrote:
 Sorry, my reply below may be too terse. You'll need to also construct the
  appropriate design matrix to which to apply the fixef() results to.

  If newDat is a data.frame containing **exactly the same named regressor and
  response columns** as your original vdata dataframe, and if me.fit.of is
  your fitted lmer object as you have defined it below, then

   model.matrix(terms(me.fit.of),newDat) %*% fixef(me.fit.of)

  gives your predictions. Note that while the response column in newDat is
  obviously unnecessary for prediction (you can fill it with 0's,say), it is
  nevertheless needed for model.matrix to work. This seems clumsy to me, so
  there may well be better ways to do this, and **I would appreciate
  suggestions for improvement.***


  Cheers,
  Bert




  -Original Message-
  From: bgunter
  Sent: Wednesday, May 07, 2008 9:53 AM
  To: May, Roel; r-help@r-project.org
  Subject: RE: [R] predict lmer

  ?fixef

  gets you the coefficient vector, from which you can make your predictions.

  -- Bert Gunter
  Genentech

  -Original Message-
  From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
  Behalf Of May, Roel
  Sent: Wednesday, May 07, 2008 7:23 AM
  To: r-help@r-project.org
  Subject: [R] predict lmer



 Hi,

  I am using lmer to analyze habitat selection in wolverines using the
  following model:

  (me.fit.of -
  lmer(USED~1+STEP+ALT+ALT2+relM+relM:ALT+(1|ID)+(1|ID:TRKPT2),data=vdata,
  control=list(usePQL=TRUE),family=poisson,method=Laplace))

  Here, the habitat selection is calaculated using a so-called discrete
  choice model where each used location has a certain number of
  alternatives which the animal could have chosen. These sets of locations
  are captured using the TRKPT2 random grouping. However, these sets are
  also clustered over the different individuals (ID). USED is my binary
  dependent variable which is 1 for used locations and zero for unused
  locations. The other are my predictors.

  I would like to predict the model fit at different values of the
  predictors, but does anyone know whether it is possible to do this? I
  have looked around at the R-sites and in help but it seems that there
  doesn't exist a predict function for lmer???

  I hope someone can help me with this; point me to the right functions or
  tell me to just forget it

  Thanks in advance!

  Cheers Roel

  Roel May
  Norwegian Institute for Nature Research
  Tungasletta 2, NO-7089 Trondheim, Norway


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[R] help with regsubsets

2008-05-07 Thread Edwards, David J
Hi,
 
I'm new to R and this mailing list, so I will attempt to state my question as 
appropriately as possible. 
 
I am running R version 2.7 with Windows XP and have recently been exploring the 
use of the function regsubsets in the leaps package in order to perform 
all-subsets regression. 
 
So, I'm calling the function as:
 
sub=regsubsets(X,Y,nbest=5,nvmax=maxnv,method=exhaustive,really.big=F)
 
I'm dealing with 14 observations and 23 variables and I'm aware of the linear 
dependencies that arise in these situations.  I also know that regsubsets 
performs a branch-and-bound algorithm and that at times it is necessary to 
reorder the variables. 
 
However, anytime I get the message: Reordering variables and trying again the 
R^2 for a model chosen by regsubsets does not match the R^2 I get from fitting 
the same model using the usual linear model function (lm).  If I don't get the 
Reordering variables and trying again message, I don't have any problems with 
R^2 (i.e. regubsets and lm match). 
 
Just for example, suppose the best 1-variable model chosen by regsubsets gives 
me an R^2 of 0.665. Fitting that same model using lm gives me an R^2 of 0.6317. 
 
 
Does anyone have any insight on why this may be happening? 
 

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Re: [R] dlm with constant terms

2008-05-07 Thread Giovanni Petris

 Date: Wed, 07 May 2008 13:03:14 -0400
 From: Stoyanov, Tsvetan (MSCIBARRA) [EMAIL PROTECTED]
 Importance: normal
 Priority: normal
 Thread-topic: dlm with constant terms
 Thread-index: AciwZDz3Kl800OdmR4CQkEC8PUECZg==
 
 Hi,
 I am trying to figure how to use dlm with constant terms
 (possibly time-dependent) added to both equations
   y_t = c_t + F_t\theta_t + v_t
   \theta_t = d_t + G_t\theta_{t-1} + w_t,
 in the way that S-PLUS Finmetrics does?
 
 Is there any straightforward way to transform the above to
 the default setup?

I think you can do it by extending the state vector and defining a new
dlm with

\theta^*_t = (1  1  \theta_t')'

F^*_t = [c_t  0  F_t],

G^*_t = [100 ]
[010 ]
[0   d_t  G_t]

W^*_t = [0   0   0 ]
[0   0   0 ]
[0   0  W_t]

m^*_0 = (1  1  m_0)

C^*_0 = [e   0   0 ]
[0   e   0 ]
[0   0  C_0]

The 'e' on the diagonal of C^*_0 should be zero, but since the matrix
must be nonsingular youcan put a very small number, such as e = 1e-8. 

Best,
Giovanni Petris


 Thanks,
 Tsvetan
 
 
 NOTICE: If received in error, please destroy and notify sender. Sender does 
 not intend to waive confidentiality or privilege. Use of this email is 
 prohibited when received in error.
 
 

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Associate Professor
Department of Mathematical Sciences
University of Arkansas - Fayetteville, AR 72701
Ph: (479) 575-6324, 575-8630 (fax)
http://definetti.uark.edu/~gpetris/

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Re: [R] Gravity (spatial interaction) models in R

2008-05-07 Thread Farley, Robert

There may already be tools for gravity model APPLICATION, which is
simply an exercise in normalization.  Perhaps if I describe the gory
details, someone will recognize the problem by another name.
  

A singly constrained gravity model is simply an exercise in normalizing
the rows of a matrix (your F-Factors) to match a vector (your
Productions).


A doubly constrained model (Fratar or Furness) is simply an
iterative exercise of normalizing Rows (Productions) and Columns
(Attractions), stopping when the maximum error is within some predefined
limit.


I'm only a newbie, but from what I've seen on the list, this should be
simple to do


As to calibrating F-Factor functions: one often chooses a functional
F-Factor form, then adjusts the coefficients, until the weighted trip
length distribution of the resulting trip table matches the observed
data.




 
Robert Farley
Metro
www.Metro.net 
 
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Roger Bivand
Sent: Tuesday, May 06, 2008 06:37
To: [EMAIL PROTECTED]
Subject: Re: [R] Gravity (spatial interaction) models in R

Melanie Murphy mamurphy at turbonet.com writes:

 
 I was wondering if anyone has developed (or is developing) an
 implementation for gravity models (spatial interaction) in R.  I
 conducted several searches on the CRAN website with no luck.
Currently
 I am estimating parameters via linearization.

There isn't anything (yet) in the Spatial task view on CRAN, and I'm not
aware
of the topic coming up on the R-sig-geo list either. The nearest sign of
transport planning is perhaps the emme2 package for interfacing EMME/2
software.
As you are aware, there are many almost equivalent ways of fitting
gravity
models, so many R functions are feasible. But no dedicated functions so
far, I'm
afraid - if I'm wrong, please let me know, and I'll update the task
view.

Roger

 
 Thank you in advance
 
 Melanie Murphy


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[R] Sweave, xtable and font size

2008-05-07 Thread Peter Jepsen
Hi,

I'm using Sweave with xtable to generate Latex tables. My problem is that some 
of the tables are too wide, and I would like to use the tiny font for these 
tables, but not for the others nor for the text. I can't work out how to 
accomplish that. 

The Latex code below does what I want it to, but I have to insert the \tiny{ 
and the closing  } by hand. It originated from these commands in my .Rnw-file:

yearmale, results=tex=
yearmale - with(chol, table(year,male))
yearmale - rowpct(yearmale) yearmale, results=tex= 
print(xtable(yearmale,caption=My caption))
$

LATEX CODE:

\begin{table}[ht]
\begin{center}
\tiny{
\begin{tabular}{rlll}
  \hline
  Kvinder  Mænd  Total \\
  \hline
1998  1335 (75\%)  437 (25\%)  1772 (100\%) \\
  1999  1232 (74\%)  425 (26\%)  1657 (100\%) \\
  2000  1427 (74\%)  502 (26\%)  1929 (100\%) \\
  2001  1407 (74\%)  493 (26\%)  1900 (100\%) \\
  2002  1493 (71\%)  611 (29\%)  2104 (100\%) \\
  2003  1684 (75\%)  566 (25\%)  2250 (100\%) \\
  2004  1565 (73\%)  567 (27\%)  2132 (100\%) \\
  2005  1629 (74\%)  586 (26\%)  2215 (100\%) \\
  2006  1448 (72\%)  553 (28\%)  2001 (100\%) \\
  2007  1582 (73\%)  590 (27\%)  2172 (100\%) \\
  Total  14802 (74\%)  5330 (26\%)  20132 (100\%) \\
   \hline
\end{tabular}
}
\caption{My caption}
\end{center}
\end{table}


Can anybody help me? Thank you in advance.

Best regards,
Peter.

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Re: [R] Sweave, xtable and font size

2008-05-07 Thread Duncan Murdoch

On 07/05/2008 7:34 PM, Peter Jepsen wrote:

Hi,

I'm using Sweave with xtable to generate Latex tables. My problem is that some of the tables are too wide, and I would like to use the tiny font for these tables, but not for the others nor for the text. I can't work out how to accomplish that. 


The Latex code below does what I want it to, but I have to insert the \tiny{ and the 
closing  } by hand. It originated from these commands in my .Rnw-file:

yearmale, results=tex=
yearmale - with(chol, table(year,male))
yearmale - rowpct(yearmale) yearmale, results=tex= 
print(xtable(yearmale,caption=My caption))

$


See ?print.xtable.  You can use

print(xtable(yearmale,caption=My caption), size=\\tiny)

Duncan Murdoch



LATEX CODE:

\begin{table}[ht]
\begin{center}
\tiny{
\begin{tabular}{rlll}
  \hline
  Kvinder  Mænd  Total \\
  \hline
1998  1335 (75\%)  437 (25\%)  1772 (100\%) \\
  1999  1232 (74\%)  425 (26\%)  1657 (100\%) \\
  2000  1427 (74\%)  502 (26\%)  1929 (100\%) \\
  2001  1407 (74\%)  493 (26\%)  1900 (100\%) \\
  2002  1493 (71\%)  611 (29\%)  2104 (100\%) \\
  2003  1684 (75\%)  566 (25\%)  2250 (100\%) \\
  2004  1565 (73\%)  567 (27\%)  2132 (100\%) \\
  2005  1629 (74\%)  586 (26\%)  2215 (100\%) \\
  2006  1448 (72\%)  553 (28\%)  2001 (100\%) \\
  2007  1582 (73\%)  590 (27\%)  2172 (100\%) \\
  Total  14802 (74\%)  5330 (26\%)  20132 (100\%) \\
   \hline
\end{tabular}
}
\caption{My caption}
\end{center}
\end{table}


Can anybody help me? Thank you in advance.

Best regards,
Peter.

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Re: [R] Estimating QAIC using glm with the quasibinomial family

2008-05-07 Thread Kunio takezawa
R-users
E-mail: r-help@r-project.org

but I was specificly interested in calculating QAIC and QAICc from
a glm fitted with the family=quasibinomial option.

If you use family=quasibinomial(link = logit) in glm(),
the program will be:

function ()
{
   xx - c(1,2,3,4,5,6,7,8,9,10)
   yy - c(1,0,1,0,0,1,0,1,1,1)
   data1 - data.frame(x=xx, y=yy)
   out1 - glm(y~x, data=data1, family=quasibinomial(link = logit))
   print(out1)
   aic0 - out1$aic
   print(aic0)
   print(aic0)

   dev1 - out1$deviance
   aic1 -  dev1+ 2*2
   print(aic1)
   print(aic1)

   c1 - 2.5
   qaic1 -  dev1/c1+ 2*2
   print(qaic1)
   print(qaic1)
}

The result is:
Call:  glm(formula = y ~ x, family = quasibinomial(link = logit),
data = data1)

Coefficients:
(Intercept)x
-0.7300   0.2131

Degrees of Freedom: 9 Total (i.e. Null);  8 Residual
Null Deviance:  13.46
Residual Deviance: 12.63AIC: NA
[1] aic0
[1] NA
[1] aic1
[1] 16.63054
[1] qaic1
[1] 9.052216

   As you pointed out, glm() does not output the value of either AIC or
QAIC.
You are supposed to calculate those values. I guess that it is because AIC
is not
appropriate for this case, and the concept of QAIC has not been authorized
yet.

K. Takezawa

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[R] anova p value extraction

2008-05-07 Thread Paul Benton
hello all,

Quick question, how do I get the p value out of the anova?

Thanks,

Paul

 pb-aov(as.numeric(diff[5,16:33]) ~ grF)
 summary(pb)
Df Sum SqMean Sq F value  Pr(F)
grF  3 2.7860e+10 9.2867e+09  4.2236 0.02534 *
Residuals   14 3.0783e+10 2.1988e+09
---
Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
 str(summary(pb))
List of 1
 $ :Classes 'anova' and 'data.frame':   2 obs. of  5 variables:
  ..$ Df : num [1:2] 3 14
  ..$ Sum Sq : num [1:2] 2.79e+10 3.08e+10
  ..$ Mean Sq: num [1:2] 9.29e+09 2.20e+09
  ..$ F value: num [1:2] 4.22   NA
  ..$ Pr(F) : num [1:2] 0.0253 NA
 - attr(*, class)= chr [1:2] summary.aov listof
 attr(summary(pb), Pr(F))
NULL

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[R] SVD for a 500, 000* 500, 000 matrix (singular value decomposition)

2008-05-07 Thread kayj

Hi,


I tried to run SVD on a  500,000* 500,000 matrix and i get a message that it
can  not allocate a vector of length 270 mb 

doe snayone know how to solve this problem? any ideas on other softwares
where I can do this? 
I appreciate your help
thanks 
-- 
View this message in context: 
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Re: [R] anova p value extraction

2008-05-07 Thread H. Paul Benton
Yea the anova object seems to be odd. It's not S4 so that's why I tried 
originally the attr() funtion but

summary(pb)$Pr(F)

Error: unexpected '' in summary(pb)$Pr(
 summary(pb)$Pr

NULL
 summary(pb)@Pr(F)

Error: unexpected '' in summary(pb)@Pr(
 summary(pb)@Pr(F)

Error: no slot of name Pr for this object of class summary.aov
In addition: Warning message:
trying to get slot Pr from an object (class summary.aov) that is
not an S4 object


Research Programmer  Technician
The Scripps Research Institute
Mass Spectrometry Core Facility
  o The
 /
o Scripps
 \
  o Research
 /
o Institute



[EMAIL PROTECTED] wrote:
  Hi: it's probably the Pr( F) element so just access it by

 sum-summary(whatever).

 then sum$Pr(F) will probably work. But make sure that's it because 
 usually the name is pval or pvalue etc so I'm
 surprised about the weird name.




 On Wed, May 7, 2008 at  8:47 PM, Paul Benton wrote:

 hello all,

 Quick question, how do I get the p value out of the anova?

 Thanks,

 Paul

 pb-aov(as.numeric(diff[5,16:33]) ~ grF)
 summary(pb)
 Df Sum SqMean Sq F value  Pr(F)
 grF  3 2.7860e+10 9.2867e+09  4.2236 0.02534 *
 Residuals   14 3.0783e+10 2.1988e+09
 ---
 Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
 str(summary(pb))
 List of 1
  $ :Classes 'anova' and 'data.frame':   2 obs. of  5 variables:
   ..$ Df : num [1:2] 3 14
   ..$ Sum Sq : num [1:2] 2.79e+10 3.08e+10
   ..$ Mean Sq: num [1:2] 9.29e+09 2.20e+09
   ..$ F value: num [1:2] 4.22   NA
   ..$ Pr(F) : num [1:2] 0.0253 NA
  - attr(*, class)= chr [1:2] summary.aov listof
 attr(summary(pb), Pr(F))
 NULL

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Re: [R] anova p value extraction

2008-05-07 Thread Jorge Ivan Velez
Hi Paul,

Perhaps

# Data set
set.seed(123)
x=rnorm(100)
y=x+2*rnorm(100)

# ANOVA
AOV=anova(lm (y ~ x))
p1=AOV$Pr(F)[1]
p1

or

# ANOVA 2
AOV1=aov(y ~ x)
p2=unlist(summary(AOV1))[Pr(F)1]
p2


HTH,

Jorge



On Wed, May 7, 2008 at 8:47 PM, Paul Benton [EMAIL PROTECTED] wrote:

 hello all,

 Quick question, how do I get the p value out of the anova?

 Thanks,

 Paul

  pb-aov(as.numeric(diff[5,16:33]) ~ grF)
  summary(pb)
Df Sum SqMean Sq F value  Pr(F)
 grF  3 2.7860e+10 9.2867e+09  4.2236 0.02534 *
 Residuals   14 3.0783e+10 2.1988e+09
 ---
 Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
  str(summary(pb))
 List of 1
  $ :Classes 'anova' and 'data.frame':   2 obs. of  5 variables:
  ..$ Df : num [1:2] 3 14
  ..$ Sum Sq : num [1:2] 2.79e+10 3.08e+10
  ..$ Mean Sq: num [1:2] 9.29e+09 2.20e+09
  ..$ F value: num [1:2] 4.22   NA
  ..$ Pr(F) : num [1:2] 0.0253 NA
  - attr(*, class)= chr [1:2] summary.aov listof
  attr(summary(pb), Pr(F))
 NULL

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Re: [R] anova p value extraction

2008-05-07 Thread Abhijit Dasgupta
What works, amazingly, is
summary(pb)$Pr(F) [note the quotes]

Abhijit

On Wed, 07 May 2008 18:17:09 -0700
H. Paul Benton [EMAIL PROTECTED] wrote:

 Yea the anova object seems to be odd. It's not S4 so that's why I tried 
 originally the attr() funtion but
 
 summary(pb)$Pr(F)
 
 Error: unexpected '' in summary(pb)$Pr(
  summary(pb)$Pr
 
 NULL
  summary(pb)@Pr(F)
 
 Error: unexpected '' in summary(pb)@Pr(
  summary(pb)@Pr(F)
 
 Error: no slot of name Pr for this object of class summary.aov
 In addition: Warning message:
 trying to get slot Pr from an object (class summary.aov) that is
 not an S4 object
 
 
 Research Programmer  Technician
 The Scripps Research Institute
 Mass Spectrometry Core Facility
   o The
  /
 o Scripps
  \
   o Research
  /
 o Institute
 
 
 
 [EMAIL PROTECTED] wrote:
   Hi: it's probably the Pr( F) element so just access it by
 
  sum-summary(whatever).
 
  then sum$Pr(F) will probably work. But make sure that's it because 
  usually the name is pval or pvalue etc so I'm
  surprised about the weird name.
 
 
 
 
  On Wed, May 7, 2008 at  8:47 PM, Paul Benton wrote:
 
  hello all,
 
  Quick question, how do I get the p value out of the anova?
 
  Thanks,
 
  Paul
 
  pb-aov(as.numeric(diff[5,16:33]) ~ grF)
  summary(pb)
  Df Sum SqMean Sq F value  Pr(F)
  grF  3 2.7860e+10 9.2867e+09  4.2236 0.02534 *
  Residuals   14 3.0783e+10 2.1988e+09
  ---
  Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
  str(summary(pb))
  List of 1
   $ :Classes 'anova' and 'data.frame':   2 obs. of  5 variables:
..$ Df : num [1:2] 3 14
..$ Sum Sq : num [1:2] 2.79e+10 3.08e+10
..$ Mean Sq: num [1:2] 9.29e+09 2.20e+09
..$ F value: num [1:2] 4.22   NA
..$ Pr(F) : num [1:2] 0.0253 NA
   - attr(*, class)= chr [1:2] summary.aov listof
  attr(summary(pb), Pr(F))
  NULL
 
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  PLEASE do read the posting guide 
  http://www.R-project.org/posting-guide.html
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Re: [R] anova p value extraction

2008-05-07 Thread H. Paul Benton
yep That worked Jorge. Thanks!

summary(pb)$Pr(F)1
NULL
 summ-summary(pb)
 class(unlist(summ))

[1] numeric
 unlist(summ)[Pr(F)1]

   Pr(F)1
0.02533637
 names(summ)
NULL 



Jorge Ivan Velez wrote:

 Hi Paul,

 Perhaps

 # Data set
 set.seed(123)
 x=rnorm(100)
 y=x+2*rnorm(100)

 # ANOVA
 AOV=anova(lm (y ~ x))
 p1=AOV$Pr(F)[1]
 p1
  
 or

 # ANOVA 2
 AOV1=aov(y ~ x)
 p2=unlist(summary(AOV1))[Pr(F)1]
 p2


 HTH,

 Jorge



 On Wed, May 7, 2008 at 8:47 PM, Paul Benton [EMAIL PROTECTED] 
 mailto:[EMAIL PROTECTED] wrote:

 hello all,

 Quick question, how do I get the p value out of the anova?

 Thanks,

 Paul

  pb-aov(as.numeric(diff[5,16:33]) ~ grF)
  summary(pb)
Df Sum SqMean Sq F value  Pr(F)
 grF  3 2.7860e+10 9.2867e+09  4.2236 0.02534 *
 Residuals   14 3.0783e+10 2.1988e+09
 ---
 Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
  str(summary(pb))
 List of 1
  $ :Classes 'anova' and 'data.frame':   2 obs. of  5 variables:
  ..$ Df : num [1:2] 3 14
  ..$ Sum Sq : num [1:2] 2.79e+10 3.08e+10
  ..$ Mean Sq: num [1:2] 9.29e+09 2.20e+09
  ..$ F value: num [1:2] 4.22   NA
  ..$ Pr(F) : num [1:2] 0.0253 NA
  - attr(*, class)= chr [1:2] summary.aov listof
  attr(summary(pb), Pr(F))
 NULL

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Re: [R] use of sequence on ridge regression

2008-05-07 Thread Rodrigo Briceño
Sorry to bother with this topic, but I'm still not clear about the
meaning of the value set that is used on lambda values. Is there a
correct way of doing that? My doubt is how to choose those 3 values
that appear in the example.
Thanks.

On Wed, May 7, 2008 at 9:29 AM, Prof Brian Ripley [EMAIL PROTECTED] wrote:
 On Wed, 7 May 2008, Rodrigo Briceño wrote:


  Nice to meet you Brian. The question is about the numbers that appears
  after lambda (0,0, 0.1, 0.0001). I know that seq is a set of values used
  for testing which value fits best. But I'm not sure if I need to put
  whatever I think or what. I tried also with a set of 5 values and I get
  an error. Is there a maximum allowed?
 

  So you mean the set of values of lambda?  It is just a set to be use for a
 plot and for searching in the select() methods.

  There is an R function called sequence(), and it is not the same as seq().




 
  plot(lm.ridge(hipcenter ~ .,seatpos, lambda = seq(0,0.1,0.001)))
  select(lm.ridge(hipcenter ~ ., seatpos,lambda = seq(0,0.1,0.001)))
 
  __
 
  Rodrigo Briceño
  Project Manager
  Sanigest Internacional
 
  +506  22-91-12-00 ext. 113   Oficina Costa Rica
  +506  22-32-08-30  Fax
  +506  88-86-11-77  Celular
  [EMAIL PROTECTED]
  www.sanigest.com
 
  MSN: [EMAIL PROTECTED]
  SKYPE: rbriceno1087
 
  _
 
  This communication contains legal information which is privileged and
  confidential. It is for the exclusive use of the address and
  distribution, dissemination, copying or use by others is strictly
  prohibited. If you have received this communication by error, please
  delete the original message and e-mail us.
 
 
  Esta comunicación contiene información legal privilegiada y confidencial
  para el uso exclusivo del destinatario. La distribución, diseminación,
  copia u otro uso por terceras personas es estrictamente prohibida. Si
  usted ha recibido esta comunicación por error, le rogamos borrar el
  mensaje original y comunicárnoslo a esta misma dirección.
 
 
 
  Prof Brian Ripley wrote:
   What do you mean by 'the sequence option'?
 
   The authot of lm.ridge
 
   On Wed, 7 May 2008, Rodrigo Briceño wrote:
 
 Dear R users. I have a doubt about the use of the
 sequence option on
 Ridge regression. I'm trying to understand the
 use of this option when
 variables are highly linear correlated. I'm
 running a model where the
 variables HtShoes and Ht have high VIF values. My
 program is written
 below, but I'm not sure about the correct way of
 using the sequence
 option:
 
 library (faraway)
 data (seatpos)
 attach (seatpos)
 spos.mod - lm(hipcenter ~ .,seatpos) summary
 (spos.mod)
 library(MASS)
 lm.ridge(hipcenter ~ .,seatpos)
 plot(lm.ridge(hipcenter ~ .,seatpos, lambda =
 seq(0,0.1,0.001)))
 select(lm.ridge(hipcenter ~ ., seatpos,lambda =
 seq(0,0.1,0.001)))
 
 Any advice will be appreaciated. Rodrigo B.
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained,
 reproducible code.
 
 
 
 
 


  --
  Brian D. Ripley,  [EMAIL PROTECTED]
  Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
  University of Oxford, Tel:  +44 1865 272861 (self)
  1 South Parks Road, +44 1865 272866 (PA)
  Oxford OX1 3TG, UKFax:  +44 1865 272595

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Re: [R] cross-correlation lag.plot?

2008-05-07 Thread David Stoffer

http://www.stat.pitt.edu/stoffer/tsa2/Examples.htm


tom soyer wrote:
 
 Hi,
 
 Does anyone know if R has a function that is similar to lag.plot but
 instead
 of auto-correlation, it plots cross-correlation with lags?
 
 Thanks,
 
 -- 
 Tom
 
   [[alternative HTML version deleted]]
 
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-
The power of accurate observation is commonly called cynicism 
by those who have not got it.  George Bernard Shaw
-- 
View this message in context: 
http://www.nabble.com/cross-correlation-lag.plot--tp17114046p17117624.html
Sent from the R help mailing list archive at Nabble.com.

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Re: [R] categorical data analysis

2008-05-07 Thread David Winsemius
David Winsemius [EMAIL PROTECTED] wrote in 
news:[EMAIL PROTECTED]:

 raymond chiruka [EMAIL PROTECTED] wrote in
 news:[EMAIL PROTECTED]: 
 
 i am trying to carry out a categorical data analysis but my problem
 is that when in i use the chi squared  test some of my  expected
 values are less than 5. is there a  test that can handle this
 situation. the data is not a 2*2 table. its more from the social
 sciences where you have from strongly agree to strongly disagree. i
 know i can collapse vthe tables but there is a loss of information .
 is the a test vthat i can for this kind of data. thanks in advancde.
  
 In addition to Snow's suggestion of fisher.test, you may want to look 
 more closely at:
 ?chisq.test
snip

Another possibility for the analysis of ordered catergorical response 
might be proportional odds regression. The MASS package has polr:

library(MASS)
?polr

polr(formula, data, weights, start, ..., subset, na.action,
 contrasts = NULL, Hess = FALSE, model = TRUE,
 method = c(logistic, probit, cloglog, cauchit))

Arguments
formula: a formula expression as for regression models, of the form 
response ~ predictors. The response should be a factor (preferably an 
ordered factor), which will be interpreted as an ordinal response, with 
levels ordered as in the factor.  
-
My copy of VenablesRipley's MASS is an older version and neither the 
index nor the TOC tells me where to find worked examples. Harrell's 
Regression Modeling Strategies has a case study illustrating the use of  
his lrm function. So you might also look at:

library(Design)
?lrm
-- 
David Winsemius

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Re: [R] algorithmic or automatic differentiation

2008-05-07 Thread David Winsemius
Erin Hodgess [EMAIL PROTECTED] wrote in 
news:[EMAIL PROTECTED]:

 Is there a package for automatic differentiation, please?
 

Have you looked at Goedman, Grothendieck, Hojsgaard, and Pinkus' Ryacas?

From the Ryacas documentation:
Analytical derivatives of functions can be evaluated with the D() and 
deriv() functions:

 yacas(D(x) Sin(x))

expression(cos(x))

-- 
David Winsemius

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Re: [R] algorithmic or automatic differentiation

2008-05-07 Thread Simon Blomberg
No, computer algebra systems such as yacas do symbolic differentiation.
Automatic differentiation is a numerical technique that can be used to
find derivatives of functions that can be implemented as computer
programs, through successive uses of the chain rule on the computer code
itself. It would be cool if R could either do AD or interface to an AD
package. R can be used with ADmodelbuilder (see
http://otter-rsch.ca/admbre/examples/glmmadmb/glmmADMB.html) , a
proprietry program, but an open source solution would be nice.

Cheers,

Simon.


On Thu, 2008-05-08 at 03:09 +, David Winsemius wrote:
 Erin Hodgess [EMAIL PROTECTED] wrote in 
 news:[EMAIL PROTECTED]:
 
  Is there a package for automatic differentiation, please?
  
 
 Have you looked at Goedman, Grothendieck, Hojsgaard, and Pinkus' Ryacas?
 
 From the Ryacas documentation:
 Analytical derivatives of functions can be evaluated with the D() and 
 deriv() functions:
 
  yacas(D(x) Sin(x))
 
 expression(cos(x))
 
-- 
Simon Blomberg, BSc (Hons), PhD, MAppStat. 
Lecturer and Consultant Statistician 
Faculty of Biological and Chemical Sciences 
The University of Queensland 
St. Lucia Queensland 4072 
Australia
Room 320 Goddard Building (8)
T: +61 7 3365 2506
http://www.uq.edu.au/~uqsblomb
email: S.Blomberg1_at_uq.edu.au

Policies:
1.  I will NOT analyse your data for you.
2.  Your deadline is your problem.

The combination of some data and an aching desire for 
an answer does not ensure that a reasonable answer can 
be extracted from a given body of data. - John Tukey.

__
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[R] Replicating Rows

2008-05-07 Thread mwittmann


Hi, 

 I have a data matrix in which there are 1000 rows by 30 columns. The first
column of each row is a numeric indicating the number of trips taken to a
particular location with location attributes in the following column entries for
that row. 

I want to repeat each row based on the number of trips taken (as indicated by
the number in the first column)...i.e., if 1,1 indicates 4 trips, I want to
replicate row 1 four times, and do this for each entry of column 1. 

I have played with rep command with little luck. Can anyone help? This is
probably very simple. 

Thank you,

mw


Marion Wittmann, Ph.D. candidate
Environmental Science and Management
University of California
Santa Barbara, CA 93106-5131

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] algorithmic or automatic differentiation

2008-05-07 Thread Erin Hodgess
Thanks to all!

Sincerely,
Erin

On Wed, May 7, 2008 at 10:35 PM, Simon Blomberg [EMAIL PROTECTED] wrote:
 No, computer algebra systems such as yacas do symbolic differentiation.
 Automatic differentiation is a numerical technique that can be used to
 find derivatives of functions that can be implemented as computer
 programs, through successive uses of the chain rule on the computer code
 itself. It would be cool if R could either do AD or interface to an AD
 package. R can be used with ADmodelbuilder (see
 http://otter-rsch.ca/admbre/examples/glmmadmb/glmmADMB.html) , a
 proprietry program, but an open source solution would be nice.

 Cheers,

 Simon.


 On Thu, 2008-05-08 at 03:09 +, David Winsemius wrote:
  Erin Hodgess [EMAIL PROTECTED] wrote in
  news:[EMAIL PROTECTED]:
 
   Is there a package for automatic differentiation, please?
  
 
  Have you looked at Goedman, Grothendieck, Hojsgaard, and Pinkus' Ryacas?
 
  From the Ryacas documentation:
  Analytical derivatives of functions can be evaluated with the D() and
  deriv() functions:
 
   yacas(D(x) Sin(x))
 
  expression(cos(x))
 
 --
 Simon Blomberg, BSc (Hons), PhD, MAppStat.
 Lecturer and Consultant Statistician
 Faculty of Biological and Chemical Sciences
 The University of Queensland
 St. Lucia Queensland 4072
 Australia
 Room 320 Goddard Building (8)
 T: +61 7 3365 2506
 http://www.uq.edu.au/~uqsblomb
 email: S.Blomberg1_at_uq.edu.au

 Policies:
 1.  I will NOT analyse your data for you.
 2.  Your deadline is your problem.

 The combination of some data and an aching desire for
 an answer does not ensure that a reasonable answer can
 be extracted from a given body of data. - John Tukey.


 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




-- 
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: [EMAIL PROTECTED]

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Re: [R] Replicating Rows

2008-05-07 Thread Jorge Ivan Velez
Hi Marion,

Try this:

set.seed(123)
mydf=data.frame(trips=rpois(10,5), matrix(rnorm(10*5),ncol=5))
mydf
sapply(mydf[,-1],rep,mydf[,1])


HTH,

Jorge


On Wed, May 7, 2008 at 11:41 PM, [EMAIL PROTECTED] wrote:



 Hi,

  I have a data matrix in which there are 1000 rows by 30 columns. The
 first
 column of each row is a numeric indicating the number of trips taken to a
 particular location with location attributes in the following column
 entries for
 that row.

 I want to repeat each row based on the number of trips taken (as indicated
 by
 the number in the first column)...i.e., if 1,1 indicates 4 trips, I want
 to
 replicate row 1 four times, and do this for each entry of column 1.

 I have played with rep command with little luck. Can anyone help? This is
 probably very simple.

 Thank you,

 mw


 Marion Wittmann, Ph.D. candidate
 Environmental Science and Management
 University of California
 Santa Barbara, CA 93106-5131

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
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 http://www.R-project.org/posting-guide.html
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[[alternative HTML version deleted]]

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Re: [R] use of sequence on ridge regression

2008-05-07 Thread Prof Brian Ripley

On Wed, 7 May 2008, Rodrigo Briceño wrote:


Sorry to bother with this topic, but I'm still not clear about the
meaning of the value set that is used on lambda values. Is there a
correct way of doing that? My doubt is how to choose those 3 values
that appear in the example.


I think you have not yet read the help for seq(): try printing out
seq(0,0.1,0.001).  There are not '3 values' here, but 3 arguments to a 
function.


'lambda' values start at 0 (no shrinkage), and how large you want them to 
be is problem-specific.  How many you ask for (101 here) is also 
problem-specific, but around 100 values is often used.




Thanks.

On Wed, May 7, 2008 at 9:29 AM, Prof Brian Ripley [EMAIL PROTECTED] wrote:

On Wed, 7 May 2008, Rodrigo Briceño wrote:



Nice to meet you Brian. The question is about the numbers that appears
after lambda (0,0, 0.1, 0.0001). I know that seq is a set of values used
for testing which value fits best. But I'm not sure if I need to put
whatever I think or what. I tried also with a set of 5 values and I get
an error. Is there a maximum allowed?



 So you mean the set of values of lambda?  It is just a set to be use for a
plot and for searching in the select() methods.

 There is an R function called sequence(), and it is not the same as seq().






plot(lm.ridge(hipcenter ~ .,seatpos, lambda = seq(0,0.1,0.001)))
select(lm.ridge(hipcenter ~ ., seatpos,lambda = seq(0,0.1,0.001)))

__

Rodrigo Briceño
Project Manager
Sanigest Internacional

+506  22-91-12-00 ext. 113   Oficina Costa Rica
+506  22-32-08-30  Fax
+506  88-86-11-77  Celular
[EMAIL PROTECTED]
www.sanigest.com

MSN: [EMAIL PROTECTED]
SKYPE: rbriceno1087

_

This communication contains legal information which is privileged and
confidential. It is for the exclusive use of the address and
distribution, dissemination, copying or use by others is strictly
prohibited. If you have received this communication by error, please
delete the original message and e-mail us.


Esta comunicación contiene información legal privilegiada y confidencial
para el uso exclusivo del destinatario. La distribución, diseminación,
copia u otro uso por terceras personas es estrictamente prohibida. Si
usted ha recibido esta comunicación por error, le rogamos borrar el
mensaje original y comunicárnoslo a esta misma dirección.



Prof Brian Ripley wrote:
 What do you mean by 'the sequence option'?

 The authot of lm.ridge

 On Wed, 7 May 2008, Rodrigo Briceño wrote:

   Dear R users. I have a doubt about the use of the
   sequence option on
   Ridge regression. I'm trying to understand the
   use of this option when
   variables are highly linear correlated. I'm
   running a model where the
   variables HtShoes and Ht have high VIF values. My
   program is written
   below, but I'm not sure about the correct way of
   using the sequence
   option:

   library (faraway)
   data (seatpos)
   attach (seatpos)
   spos.mod - lm(hipcenter ~ .,seatpos) summary
   (spos.mod)
   library(MASS)
   lm.ridge(hipcenter ~ .,seatpos)
   plot(lm.ridge(hipcenter ~ .,seatpos, lambda =
   seq(0,0.1,0.001)))
   select(lm.ridge(hipcenter ~ ., seatpos,lambda =
   seq(0,0.1,0.001)))

   Any advice will be appreaciated. Rodrigo B.

   __
   R-help@r-project.org mailing list
   https://stat.ethz.ch/mailman/listinfo/r-help
   PLEASE do read the posting guide
   http://www.R-project.org/posting-guide.html
   and provide commented, minimal, self-contained,
   reproducible code.








 --
 Brian D. Ripley,  [EMAIL PROTECTED]
 Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
 University of Oxford, Tel:  +44 1865 272861 (self)
 1 South Parks Road, +44 1865 272866 (PA)
 Oxford OX1 3TG, UKFax:  +44 1865 272595


__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.



--
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595__
R-help@r-project.org mailing list
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