[R] Determine restricted variable in SVAR and SVEC?

2009-10-09 Thread Arif Chandra


How to determine restricted variable in SVAR and SVEC? There are some values 
which set to be zero and others set to be NA.. How to determine values that set 
to be 0? Thanks
 
Regards,
Arif  
_

 Facebook.

k-basics.aspx?ocid=PID23461::T:WLMTAGL:ON:WL:en-id:SI_SB_2:092009
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Re: [R] Plot nls line on plot?

2009-10-09 Thread Christian Ritz
Hi Doug,

you can add the fitted curve using the following general paradigm:

## Plotting the data
plot(p~z)


## Defining grid of z values
## (100 values ensures a smooth curve in your case)
zValues - seq(min(z), max(z), length.out = 100)


## Adding predicted values corresponding to the grid values
lines(zVal, predict(fit, data.frame(z = zValues)))



Christian

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[R] problem with CPU usage

2009-10-09 Thread venkata kirankumar
Hi all,
I have a problem with CPU usage  while running the Rgui.exe

problem is
while I am running scripts on  Rgui  its taking 100% of CPU is there any
posibility to reduce the cpu consumption
are any package I can use to reduce CPU consumption
can any one help me out from this problem because
while running these scripts I am not able to do any other work

and there is no recursive functions and  all loops are ending properly

Thanks in advance
kiran

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Re: [R] Parameters of Beta distribution

2009-10-09 Thread Karl Ove Hufthammer
In article 5df5755d-a376-439a-b7f2-9901441db...@comcast.net, 
dwinsem...@comcast.net says...
 In insurance situation there is typically a cap on the covered losses  
 and there is also typically an amount below which it would not make  
 sense to offer a policy. So a minimum and a maximum are sensible  
 assumptions about loss distributions in may real modeling situations.
 
But a continuous distribution would then not be a reasonable 
distribution. More precisely, one would typically have a mixture of a 
continuous and a discrete distribution, with some point probability mass 
at the max.

-- 
Karl Ove Hufthammer

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[R] Substituting the extracted coefficients into the formula, exctracted from the result of nls()

2009-10-09 Thread Primoz PETERLIN
Dear all,

Here I come with another stupid question.  Suppose I want to use nls()
to fit a series of data (here modelled by generated points), then plot
the points and the fitting curve. I figured out some way of doing it:

x - runif(1:20, 0, 10)
y - 0.1*x^2 - rep(3, length(x)) + rnorm(length(x), sd = 0.5)

yfit - nls(y ~ a*x^2 + b*x + c,
start = list(a = 1, b = 1, c = 1),
trace = TRUE)

plot(x, y)
curve(coef(yfit)[1]*x^2 + coef(yfit)[2]*x + coef(yfit)[3], 0, 10,
  add = TRUE)

However, this code is rather fortranesque, and most likely there
exists a much more elegant way in R/S, something like abline() which
exists for straight lines. Since both the formula and the coefficients
are available as a result of nls() (here as formula(yfit) and
coef(yfit)), I thought there ought to be a way something along the
following lines:

f - substitute(formula(yfit), as.list(coef(yfit)))
curve(f, ...)

However, this snippet of code doesn't work. Am I thinking into the
correct direction at all?

Thanks in advance.

All the best,
Primož

-- 
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Lipičeva 2, SI-1000 Ljubljana, Slovenija.primoz.peter...@mf.uni-lj.si
Tel +386-1-5437612, fax +386-1-4315127,  http://biofiz.mf.uni-lj.si/~peterlin/
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Re: [R] about function *lapply*

2009-10-09 Thread Duncan Murdoch

On 09/10/2009 12:42 AM, guangchuang yu wrote:

I used *lapply* and *for* to call the function *GetC* respectively. The
output is different!!! I can't figured out how this happen! It's so wierd.



x=lapply(ipi.go,GetC, ont = BP, org=cell.cycle)
unlist(x)

*IPI00011654 IPI00013683
cell cycle cell cycle*


categorate=list()
for (i in 1:length(ipi.go)) {

+ x = GetC(ipi.go[i], ont=BP, org=cell.cycle)


lapply will apply the function to ipi.go[[i]], not ipi.go[i].

Duncan Murdoch


+ x - list(x)
+ names(x) - names(ipi.go[i])
+ categorate - c(categorate, x)
+ }

unlist(categorate)

*IPI3865 IPI00011654 IPI00013475 IPI00013683
cell cycle cell cycle cell cycle cell cycle
*



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Re: [R] error message - unexpected input

2009-10-09 Thread Jim Lemon

On 10/09/2009 07:15 AM, David Winsemius wrote:


On Oct 8, 2009, at 3:28 PM, Danielle Dandreaux wrote:
...
The syntax line that appears to be causing problems is: 
dataname=Igt2model.txt and the error message is: Error: unexpected 
input in dataname=



Hi Danielle,
This sort of error often occurs when the line is a continuation and 
there is something like a trailing comma missing on the previous line.


Jim

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Re: [R] Bringing dbf Data With SQL

2009-10-09 Thread Jim Lemon

On 10/09/2009 07:17 AM, Michael Yutzi wrote:

I have a heavy DATA saved in dbf format.

What I want is to bring that data to R with SQL statements. Like: I want
columns 1, 4, 5 and only when column 4  30.

Sorry asking it here instead of keep searching in manuals, but it seems that
there are too many ways of doing it. So what's the appropriate package that
I need to work it, considering also that im dealing with lots of gigas so
the faster way, better.

I would really appreciate helps
Thanks since now
   

Hi Michael,
Let's say your table is named lotsadata and the attributes are labeled 
one, two and so on. Does:


SELECT one four five
 FROM lotsadata
 WHERE four30.

do what you want?

Jim

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Re: [R] problem with CPU usage

2009-10-09 Thread Paul Hiemstra

Hi,

If you work on Windows you can reduce the priority of the Rgui.exe 
process. You can do this in the task manager, right click  Priority.


cheers,
Paul

venkata kirankumar wrote:

Hi all,
I have a problem with CPU usage  while running the Rgui.exe

problem is
while I am running scripts on  Rgui  its taking 100% of CPU is there any
posibility to reduce the cpu consumption
are any package I can use to reduce CPU consumption
can any one help me out from this problem because
while running these scripts I am not able to do any other work

and there is no recursive functions and  all loops are ending properly

Thanks in advance
kiran

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--
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Department of Physical Geography
Faculty of Geosciences
University of Utrecht
Heidelberglaan 2
P.O. Box 80.115
3508 TC Utrecht
Phone:  +3130 274 3113 Mon-Tue
Phone:  +3130 253 5773 Wed-Fri
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[R] Creating a Clustered-Stacked Column Chart

2009-10-09 Thread zhijie zhang
 Hi all,
   In R, is there some functions or ways to create a Clustered-Stacked
Column Chart as the example in the following page
http://peltiertech.com/Excel/ChartsHowTo/ClusterStack.html?
  I have browsed the R Graph Gallery (http://addictedtor.free.fr/graphiques/)
and searched the R site, and didnot find an appropriate method to do it.
  Anybody has met this problem before?
  Thanks a lot.

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[R] Trendline for a subset of data

2009-10-09 Thread Steve Murray

Dear all,

I am using abline(lm ...) to insert a linear trendline through a portion of my 
data (e.g. dataset[,36:45]). However, I am finding that whilst the trendline is 
correctly displayed and representative of the data portion I've chosen, the 
line continues to run beyond this data segment and continues until it 
intersects the vertical axes at each side of the plot.

How do I display the line so that it only runs between point 36 and 45 (as 
shown in the example above) as doesn't continue to display a line throughout 
the rest of the plot space?

Many thanks,

Steve
  
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[R] Get subset of n dimensional matrix

2009-10-09 Thread Mark McDowall
I want to select a subset of an array, but I want to make a function so that
it can handle any number of dimensions.

This is probably best described with an example

 x - 1:100
 dim(x) - c(10,10)
 x
  [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
 [1,]1   11   21   31   41   51   61   71   8191
 [2,]2   12   22   32   42   52   62   72   8292
 [3,]3   13   23   33   43   53   63   73   8393
 [4,]4   14   24   34   44   54   64   74   8494
 [5,]5   15   25   35   45   55   65   75   8595
 [6,]6   16   26   36   46   56   66   76   8696
 [7,]7   17   27   37   47   57   67   77   8797
 [8,]8   18   28   38   48   58   68   78   8898
 [9,]9   19   29   39   49   59   69   79   8999
[10,]   10   20   30   40   50   60   70   80   90   100

 vList - vector(list, 2)
 vList[[1]] - c(4:6)
 vList[[2]] - c(4:6)
 x[vList[[1]],vList[[2]]]
 [,1] [,2] [,3]
[1,]   34   44   54
[2,]   35   45   55
[3,]   36   46   56

but if:

 x - 1:1000
 dim(x) - c(10,10,10)

I would would have to increase the returning call:
x[vList[[1]],vList[[2]],vList[[3]]]

What I would like to be able to do is pass x the list of lists and have it
return the required points.

Anyone have any clues on how to get over this hurdle?

Thank you

Mark

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Re: [R] I can not install DAAG package . help

2009-10-09 Thread Yanyuan Zhu
Hello David, seems there's sth wrong with my R.
I used to start R with Emacs+ESS, so i didn't find the error message till
today i ran R in an terminal :


si...@simon-t400:~$ R
R version 2.9.2 (2009-08-24)
Copyright (C) 2009 The R Foundation for Statistical Computing
ISBN 3-900051-07-0

R is free software and comes with ABSOLUTELY NO WARRANTY.
You are welcome to redistribute it under certain conditions.
Type 'license()' or 'licence()' for distribution details.

  Natural language support but running in an English locale

R is a collaborative project with many contributors.
Type 'contributors()' for more information and
'citation()' on how to cite R or R packages in publications.

Type 'demo()' for some demos, 'help()' for on-line help, or
'help.start()' for an HTML browser interface to help.
Type 'q()' to quit R.


 Warning: you have multiple copies of the following packages:
Error: could not find function installed.packages
[Previously saved workspace restored]

And then i run installed.packages(), get a lot of information flushing on
my terminal 

so what should i do about it ? thanks

On Thu, Oct 8, 2009 at 8:53 PM, David Winsemius dwinsem...@comcast.netwrote:


 On Oct 8, 2009, at 4:27 AM, Yanyuan Zhu wrote:

  I use R on my Ubuntu 9.04 laptop, which was installed by aptitude
 install
 way


 The is an R-SIG-Debian which is going to have more people with knowledge of
 your particular OS.

  Now i'm learning a book of R which needs MASS and DAAG installed.
 So i followed the instructions:

  install.packages(MASS)
 library(MASS)


 MASS works fine.


 But that doesn't tell you very much because MASS was part of the R
 distribution. So your hope to derive comfort is ill-conceived.


 But DAAG doesn't. Anyone who could help would be appreciated a lot !

 Below are my error outpus :

  install.packages(DAAG)

 Warning in install.packages(DAAG) :
  argument 'lib' is missing: using
 '/home/simon/R/i486-pc-linux-gnu-library/2.9'
 --- Please select a CRAN mirror for use in this session ---
 Loading Tcl/Tk interface ... done
 also installing the dependency ‘randomForest’

 trying URL '
 http://ftp.ctex.org/mirrors/CRAN/src/contrib/randomForest_4.5-30.tar.gz'
 Content type 'application/x-gzip' length 70247 bytes (68 Kb)
 opened URL
 ==
 downloaded 68 Kb

 trying URL 'http://ftp.ctex.org/mirrors/CRAN/src/contrib/DAAG_1.00.tar.gz
 '
 Content type 'application/x-gzip' length 2172778 bytes (2.1 Mb)
 opened URL
 ==
 downloaded 2.1 Mb


 Warning: you have multiple copies of the following packages:
 Error: could not find function installed.packages
 Execution halted


 Is it really true that the interpreter cannot find that function? That
 would be pretty unusual and would suggest your copy of R was broken.  What
 do you get with:

  installed.packages()

 On my system the list is very long but on yours it should be considerably
 shorter.



 Warning: you have multiple copies of the following packages:
 Error: could not find function installed.packages
 Execution halted

 The downloaded packages are in
   ‘/tmp/Rtmp7w4WPA/downloaded_packages’
 Warning messages:
 1: In install.packages(DAAG) :
  installation of package 'randomForest' had non-zero exit status
 2: In install.packages(DAAG) :
  installation of package 'DAAG' had non-zero exit status

  library(DAAG)

 Error in library(DAAG) : there is no package called 'DAAG'
 --
 ---
 Yanyuan Zhu
 Doctoral Candidate
 School of Economics  Management, Tongji University



 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT




-- 
---
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Doctoral Candidate
School of Economics  Management, Tongji University
MSN messenger:caoanroad4...@hotmail.commessenger%3acaoanroad4...@hotmail.com
E-mail: caoanroad4...@gmail.com
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Re: [R] I can not install DAAG package . help

2009-10-09 Thread Yanyuan Zhu
Hello joris, when i type the command:
 ?installed.packages
seems it works fine and shows me the man page of install.packages()

Then i followed ur instructions by first removing DAAG
 remove.packages(DAAG)
Warning in remove.packages(DAAG) :
  argument 'lib' is missing: using
/home/simon/R/i486-pc-linux-gnu-library/2.9
Error in .find.package(pkgs, lib) : there is no package called 'DAAG'


Then i try to install randomForest first
 install.packages(randomForest)
Warning in install.packages(randomForest) :
  argument 'lib' is missing: using
'/home/simon/R/i486-pc-linux-gnu-library/2.9'
trying URL '
http://ftp.ctex.org/mirrors/CRAN/src/contrib/randomForest_4.5-30.tar.gz'
Content type 'application/x-gzip' length 70247 bytes (68 Kb)
opened URL
==
downloaded 68 Kb


 Warning: you have multiple copies of the following packages:
Error: could not find function installed.packages
Execution halted

The downloaded packages are in
‘/tmp/Rtmppr7kcy/downloaded_packages’
Warning message:
In install.packages(randomForest) :
  installation of package 'randomForest' had non-zero exit status







so what should i do ? thanks

-- Forwarded message --
From: joris meys jorism...@gmail.com
Date: Thu, Oct 8, 2009 at 8:25 PM
Subject: Re: [R] I can not install DAAG package . help
To: Yanyuan Zhu caoanroad4...@gmail.com
Cc: r-help@r-project.org


Quite a strange error. The function installed.packages should be in
the utils package.
Try ?installed.packages and see if you get a help file. If it doesn't
find that function, there is a problem with your R installation.

It might be something went wrong with downloading the package itself.
DAAG is 2.6 Mb at my computer.

Remove DAAG by remove.packages(DAAG)
Check whether randomForest is installed. If so, remove that one as well.

Now install randomForest first, and then DAAG. If this doesn't work,
post the log and error message again.

Kind regards
Joris

On Thu, Oct 8, 2009 at 10:27 AM, Yanyuan Zhu caoanroad4...@gmail.com
wrote:
 I use R on my Ubuntu 9.04 laptop, which was installed by aptitude
install
 way
 Now i'm learning a book of R which needs MASS and DAAG installed.
 So i followed the instructions:

install.packages(MASS)
library(MASS)

 MASS works fine.

 But DAAG doesn't. Anyone who could help would be appreciated a lot !

 Below are my error outpus :

 install.packages(DAAG)
 Warning in install.packages(DAAG) :
  argument 'lib' is missing: using
 '/home/simon/R/i486-pc-linux-gnu-library/2.9'
 --- Please select a CRAN mirror for use in this session ---
 Loading Tcl/Tk interface ... done
 also installing the dependency ‘randomForest’

 trying URL '
 http://ftp.ctex.org/mirrors/CRAN/src/contrib/randomForest_4.5-30.tar.gz'
 Content type 'application/x-gzip' length 70247 bytes (68 Kb)
 opened URL
 ==
 downloaded 68 Kb

 trying URL 'http://ftp.ctex.org/mirrors/CRAN/src/contrib/DAAG_1.00.tar.gz'
 Content type 'application/x-gzip' length 2172778 bytes (2.1 Mb)
 opened URL
 ==
 downloaded 2.1 Mb


  Warning: you have multiple copies of the following packages:
 Error: could not find function installed.packages
 Execution halted

  Warning: you have multiple copies of the following packages:
 Error: could not find function installed.packages
 Execution halted

 The downloaded packages are in
‘/tmp/Rtmp7w4WPA/downloaded_packages’
 Warning messages:
 1: In install.packages(DAAG) :
  installation of package 'randomForest' had non-zero exit status
 2: In install.packages(DAAG) :
  installation of package 'DAAG' had non-zero exit status

 library(DAAG)
 Error in library(DAAG) : there is no package called 'DAAG'


 --
 ---
 Yanyuan Zhu
 Doctoral Candidate
 School of Economics  Management, Tongji University
 MSN messenger:caoanroad4...@hotmail.commessenger%3acaoanroad4...@hotmail.com
messenger%3acaoanroad4...@hotmail.commessenger%253acaoanroad4...@hotmail.com

 E-mail: caoanroad4...@gmail.com
 BLOG http://yyzhu.net

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[R] svy / weighted regression

2009-10-09 Thread Laust
Dear list,

I am trying to set up a propensity-weighted regression using the
survey package. Most of my population is sampled with a sampling
probability of one (that is, I have the full population). However, for
a subset of the data I have only a 50% sample of the full population.
In previous work on the data, I analyzed these data using SAS and
STATA. In those packages I used a propensity weight of 1/[sampling
probability] in various generalized linear regression-procedures, but
I am having trouble setting this up. I bet the solution is simple, but
I’m a R newbie. Code to illustrate my problem below.

Thanks
Laust

# loading survey
library(survey)

# creating data
listc - 
c(Denmark,Finland,Norway,Sweden,Denmark,Finland,Norway,Sweden)
listw - c(1,2,1,1,1,1,1,1)
listd - c(0,0,0,0,1000,1000,1000,2000)
listt - c(75,50,90,190,5000,5000,5000,1)
list.cwdt - c(listc, listw, listd, listt)
country - data.frame(country=listc,weight=listw,deaths=listd,yrs_at_risk=listt)

# running a frequency weighted regression to get the correct point
estimates for comparison
glm - glm(deaths ~ country + offset(log(yrs_at_risk)),
weights=weight, data=country, family=poisson())
summary(glm)
regTermTest(glm, ~ country)

# running survey weighted regression
svy - svydesign(~0,,data=country, weight=~weight)
svyglm - svyglm(deaths ~ country + offset(log(yrs_at_risk)),
design=svy, data=country, family=poisson())
summary(svyglm)
# point estimates are correct, but standard error is way too large
regTermTest(svyglm, ~ country)
# test indicates no country differences

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[R] Naming objects in a list

2009-10-09 Thread P.Branco

Hello,

I am trying to run a for-loop in which I want to add glm output objects
sequentially into a list. I do not know how to give names to each object in
a list. I tried this :

 
List.glm - list()

for(i in 1:n)

list.glm - list(list.glm, glm(,,,))

 

but it is obviously unsuited…

Best regards,

Paulo
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Re: [R] Naming objects in a list

2009-10-09 Thread jim holtman
A couple of ways:

List.glm - list()

for(i in 1:n)  list.glm[[i]] -glm(,,,)


OR

List.glm - lapply(1:n, function(x) glm(,,,))

On Fri, Oct 9, 2009 at 7:54 AM, P.Branco pjlbra...@yahoo.com wrote:

 Hello,

 I am trying to run a for-loop in which I want to add glm output objects
 sequentially into a list. I do not know how to give names to each object in
 a list. I tried this :


 List.glm - list()

 for(i in 1:n)

 list.glm - list(list.glm, glm(,,,))



 but it is obviously unsuited…

 Best regards,

 Paulo
 --
 View this message in context: 
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What is the problem that you are trying to solve?

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Re: [R] About finding NA values sources

2009-10-09 Thread Rene
Dear All,

 

In R, is there a way (or a function) I can quickly check whether all the NA
values in one new created numerical variable happened are because of  nbsp;
or something else in the original dataset? And how can we easily group these
NAs separately based on different  reason (e.g. some NA are because of
nbsp; ,  some are because of there are extra text inside, etc).

 

Thanks heaps. 

 

Rene.


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[R] QQ plot

2009-10-09 Thread Madan Sigdel

Dear list
 
I want to plot the QQ plot with some distributions like geometrical , lognormal 
and truncated normal  with confidence bands. does this options available. 
Iam new to R. If you have any scripts and examples please kindly suggest me.
 
thank you
madan

 


  
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Re: [R] Plot with CART results

2009-10-09 Thread Terry Therneau
-begin included message ---
With rpart we can get several terminals and  draw it in the TREE plot.
Now I am trying to draw a plot like this: x-axis is each terminal's
value, and y-axis is those observe values. Does anyone has idea what
gramma should I use? Thanks in advance.
-end --

It sounds like you want to plot predicted versus observed.
  fit - rpart(y ~ .
  plot(predict(fit), y)

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Re: [R] Get subset of n dimensional matrix

2009-10-09 Thread Henrique Dallazuanna
Try this:

x - array(1:1000, rep(10, 3))
vList - list(i = 4:6, j = 4:6, ... = 4:6)
do.call('[', c(list(x), vList))

On Fri, Oct 9, 2009 at 7:18 AM, Mark McDowall
markmcdowa...@googlemail.com wrote:
 I want to select a subset of an array, but I want to make a function so that
 it can handle any number of dimensions.

 This is probably best described with an example

 x - 1:100
 dim(x) - c(10,10)
 x
      [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
  [1,]    1   11   21   31   41   51   61   71   81    91
  [2,]    2   12   22   32   42   52   62   72   82    92
  [3,]    3   13   23   33   43   53   63   73   83    93
  [4,]    4   14   24   34   44   54   64   74   84    94
  [5,]    5   15   25   35   45   55   65   75   85    95
  [6,]    6   16   26   36   46   56   66   76   86    96
  [7,]    7   17   27   37   47   57   67   77   87    97
  [8,]    8   18   28   38   48   58   68   78   88    98
  [9,]    9   19   29   39   49   59   69   79   89    99
 [10,]   10   20   30   40   50   60   70   80   90   100

 vList - vector(list, 2)
 vList[[1]] - c(4:6)
 vList[[2]] - c(4:6)
 x[vList[[1]],vList[[2]]]
     [,1] [,2] [,3]
 [1,]   34   44   54
 [2,]   35   45   55
 [3,]   36   46   56

 but if:

 x - 1:1000
 dim(x) - c(10,10,10)

 I would would have to increase the returning call:
 x[vList[[1]],vList[[2]],vList[[3]]]

 What I would like to be able to do is pass x the list of lists and have it
 return the required points.

 Anyone have any clues on how to get over this hurdle?

 Thank you

 Mark

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[R] Any reference to Tukeyline algorithm?

2009-10-09 Thread shanmukha patel
Hi, 
I am using line function to plot the line. And I would like to understand 
Tukeyline algorithm. Since, the line function is calling the Tukeyline 
algorithm(which is compiled code) using foreign function interface, I am not 
able to look into the source code of this algorithm. Can somebody help me out, 
so that I can refer the same.

Thanks in advance!!!

Thanks, 
Shanmukh.




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Re: [R] Trendline for a subset of data

2009-10-09 Thread David Winsemius


On Oct 9, 2009, at 5:50 AM, Steve Murray wrote:



Dear all,

I am using abline(lm ...) to insert a linear trendline through a  
portion of my data (e.g. dataset[,36:45]). However, I am finding  
that whilst the trendline is correctly displayed and representative  
of the data portion I've chosen, the line continues to run beyond  
this data segment and continues until it intersects the vertical  
axes at each side of the plot.


How do I display the line so that it only runs between point 36 and  
45 (as shown in the example above) as doesn't continue to display a  
line throughout the rest of the plot space?




?segments


Many thanks,

Steve



David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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[R] celebrating revision 50000

2009-10-09 Thread Romain Francois

Hello,

Today, Brian Ripley commited the revision 5 of R's svn repository.

I took this as an opportunity to do some data analysis of the log and 
posted some code and graphics on my blog: 
http://romainfrancois.blog.free.fr/index.php?post/2009/10/09/celebrating-R-commit-5


The plots of the number of commits per day (and per month) indicates a 
peak in 2002.


Here are the top 20 modified files :

 most.updated - head( sort( table( data$file ), decreasing=TRUE ), 20 )
 cat( sprintf( %40s:  %6d, names(most.updated), most.updated ), 
sep =\n )

 /trunk/NEWS:5449
   /trunk/date-stamp:2219
 /trunk/BUGS:1485
 /trunk/src/gnuwin32/CHANGES: 994
/trunk/configure: 979
/trunk/doc/manual/R-FAQ.texi: 948
   /trunk/doc/manual/R-exts.texi: 814
  /trunk/doc/manual/R-admin.texi: 666
 /trunk/src/main/names.c: 634
  /trunk/tests/reg-tests-1.R: 621
/trunk/src/gnuwin32/Makefile: 542
  /trunk/FAQ: 471
/trunk/doc/html/faq.html: 458
   /trunk/src/include/Defn.h: 455
 /trunk/configure.ac: 447
 /trunk/src/scripts/check.in: 433
 /trunk/src/library/tools/R/QC.R: 397
 /branches/unlabeled-1.1139.4/date-stamp: 386
   /trunk/src/main/connections.c: 349
  /trunk/src/main/plot.c: 325


The most modified file extensions (the second element indicates files 
without extensions) :


 head( sort( table( data$extension ), decreasing=T ) , 24 )

  Rd cR   po   in   moh
   3676633999298492522110215 8806 6280 6147
texi  gmo html save  potf  win   m4
5274 3705 1920 1668 1285 1148 1060 1041
  pl   ac  afm   pm  macy packages   sh
 910  527  482  461  402  384  311  215

The number of commits per author :

 sort( table( simple$author ), decreasing=T )

 ripleymaechler  hornik  pd murdoch   iacus
  20523   10207674446551370 915
 leisch jmcluke   ihaka murrell   bates
743 643 618 481 379 350
   rgentlem tlumleyurbaneks (no author)  duncan   r
299 274 274 203 172  96
 thomas  lyndonpaul   guido  martyn plummer
 63  54  48  39  39  26
   deepayan  falconmike
 20  18   1


Many thanks to the R core team for these 50 000 commits.

Romain

--
Romain Francois
Professional R Enthusiast
+33(0) 6 28 91 30 30
http://romainfrancois.blog.free.fr
|- http://tr.im/BcPw : celebrating R commit #5
|- http://tr.im/ztCu : RGG #158:161: examples of package IDPmisc
`- http://tr.im/yw8E : New R package : sos

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Re: [R] Substituting the extracted coefficients into the formula, exctracted from the result of nls()

2009-10-09 Thread Henrique Dallazuanna
If you want curve with substitute(...), you can try something about like this:

f - eval(parse(text = paste(substitute(, formula(yfit)[3], ,
as.list(coef(yfit))), sep = )))
curve(f, ...)

2009/10/9 Henrique Dallazuanna www...@gmail.com:
 Try with predict:

 plot(x, y)
 lines(0:10, predict(yfit, list(x = 0:10)))

 2009/10/9 Primoz PETERLIN primozz.peter...@gmail.com:
 Dear all,

 Here I come with another stupid question.  Suppose I want to use nls()
 to fit a series of data (here modelled by generated points), then plot
 the points and the fitting curve. I figured out some way of doing it:

 x - runif(1:20, 0, 10)
 y - 0.1*x^2 - rep(3, length(x)) + rnorm(length(x), sd = 0.5)

 yfit - nls(y ~ a*x^2 + b*x + c,
            start = list(a = 1, b = 1, c = 1),
            trace = TRUE)

 plot(x, y)
 curve(coef(yfit)[1]*x^2 + coef(yfit)[2]*x + coef(yfit)[3], 0, 10,
      add = TRUE)

 However, this code is rather fortranesque, and most likely there
 exists a much more elegant way in R/S, something like abline() which
 exists for straight lines. Since both the formula and the coefficients
 are available as a result of nls() (here as formula(yfit) and
 coef(yfit)), I thought there ought to be a way something along the
 following lines:

 f - substitute(formula(yfit), as.list(coef(yfit)))
 curve(f, ...)

 However, this snippet of code doesn't work. Am I thinking into the
 correct direction at all?

 Thanks in advance.

 All the best,
 Primož

 --
 Primož Peterlin,   Inštitut za biofiziko, Med. fakulteta, Univerza v 
 Ljubljani
 Lipičeva 2, SI-1000 Ljubljana, Slovenija.        primoz.peter...@mf.uni-lj.si
 Tel +386-1-5437612, fax +386-1-4315127,  
 http://biofiz.mf.uni-lj.si/~peterlin/
 F8021D69 OpenPGP fingerprint: CB 6F F1 EE D9 67 E0 2F  0B 59 AF 0D 79 56 19 
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 --
 Henrique Dallazuanna
 Curitiba-Paraná-Brasil
 25° 25' 40 S 49° 16' 22 O




-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O

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Re: [R] QQ plot

2009-10-09 Thread John Fox
Dear Madan,

Please see the qq.plot() function in the car package.

I hope this helps,
 John



 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
 Behalf Of Madan Sigdel
 Sent: October-09-09 8:54 AM
 To: r-help@r-project.org
 Subject: [R] QQ plot
 
 
 Dear list
 
 I want to plot the QQ plot with some distributions like geometrical ,
 lognormal and truncated normal  with confidence bands. does this options
 available.
 Iam new to R. If you have any scripts and examples please kindly suggest
me.
 
 thank you
 madan
 
 
 
 
 
   [[alternative HTML version deleted]]

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Re: [R] Trendline for a subset of data

2009-10-09 Thread Mark Difford

Hi Steve,

 However, I am finding that ... the trendline ... continues to run beyond
 this data segment 
 and continues until it intersects the vertical axes at each side of the
 plot.

Your best option is probably Prof. Fox's reg.line function in package car.

##
library(car)
?reg.line
reg.line

Regards, Mark.


smurray444 wrote:
 
 
 Dear all,
 
 I am using abline(lm ...) to insert a linear trendline through a portion
 of my data (e.g. dataset[,36:45]). However, I am finding that whilst the
 trendline is correctly displayed and representative of the data portion
 I've chosen, the line continues to run beyond this data segment and
 continues until it intersects the vertical axes at each side of the plot.
 
 How do I display the line so that it only runs between point 36 and 45 (as
 shown in the example above) as doesn't continue to display a line
 throughout the rest of the plot space?
 
 Many thanks,
 
 Steve
 
 _
 View your other email accounts from your Hotmail inbox. Add them now.
 http://clk.atdmt.com/UKM/go/167688463/direct/01/
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-- 
View this message in context: 
http://www.nabble.com/Trendline-for-a-subset-of-data-tp25818425p25821972.html
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Re: [R] Creating a Clustered-Stacked Column Chart

2009-10-09 Thread John Kane
I don't think I've seen an R version, probably because the technique is not 
very good for displaying data.  

Have a look at http://chartsgraphs.wordpress.com/tag/r-and-excel/ for an 
alternative method of displaying the data using lattice.

--- On Fri, 10/9/09, zhijie zhang rusers...@gmail.com wrote:

 From: zhijie zhang rusers...@gmail.com
 Subject: [R] Creating a Clustered-Stacked Column Chart
 To: r-h...@stat.math.ethz.ch
 Received: Friday, October 9, 2009, 5:31 AM
  Hi all,
    In R, is there some functions or ways to
 create a Clustered-Stacked
 Column Chart as the example in the following page
 http://peltiertech.com/Excel/ChartsHowTo/ClusterStack.html?
   I have browsed the R Graph Gallery (http://addictedtor.free.fr/graphiques/)
 and searched the R site, and didnot find an appropriate
 method to do it.
   Anybody has met this problem before?
   Thanks a lot.
 
     [[alternative HTML version deleted]]
 
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 mailing list
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Re: [R] Trendline for a subset of data

2009-10-09 Thread Steve Murray

 cb247343-29ec-495a-ba8e-d5a466bab...@comcast.net
Content-Type: text/plain; charset=iso-8859-1
Content-Transfer-Encoding: quoted-printable
MIME-Version: 1.0


Thanks for flagging up the 'segments' command. However=2C I'm having troubl=
e getting it to work - this is probably due to me misunderstanding the docu=
mentation for this command.

The plot section of my script appears as follows:

test3 - 36:45
plot(data_means=2C type=3Db=2C pch=3D4=2C ylab=3D=2C xlab=3D=2C xaxt=
=3Dn=2C yaxt=3Dn=2C col=3D3=2C ylim=3Dc(250=2C380))
abline(lm(data_means[36:45] ~ test3)=2C lty=3D2)


As you can see=2C I'm only plotting points 36 to 45 from the object 'data_m=
eans'. This intentionally results in much white space along the x-axis unti=
l point 36 is reached. However=2C when inserting the trendline=2C this runs=
 along the entire length of the x-axis instead of just through points 36 to=
 45. Ideally=2C a line which slightly overshoots the data subset would look=
 the best=2C but one constrained to the extents of the 36:45 would also do =
the job just fine.

So=2C my question is=2C how do I use 'segments' (or otherwise) to create a =
linear trendline which only extends through points 36:45? (and overshoots a=
t either end very slightly=2C if possible=2C rather than running along the =
entire length of the x-axis).

Many thanks again=2C

Steve


 CC: r-help@r-project.org
 From: dwinsem...@comcast.net
 To: smurray...@hotmail.com
 Subject: Re: [R] Trendline for a subset of data
 Date: Fri=2C 9 Oct 2009 09:27:43 -0400


 On Oct 9=2C 2009=2C at 5:50 AM=2C Steve Murray wrote:


 Dear all=2C

 I am using abline(lm ...) to insert a linear trendline through a
 portion of my data (e.g. dataset[=2C36:45]). However=2C I am finding
 that whilst the trendline is correctly displayed and representative
 of the data portion I've chosen=2C the line continues to run beyond
 this data segment and continues until it intersects the vertical
 axes at each side of the plot.

 How do I display the line so that it only runs between point 36 and
 45 (as shown in the example above) as doesn't continue to display a
 line throughout the rest of the plot space?


 ?segments

 Many thanks=2C

 Steve


 David Winsemius=2C MD
 Heritage Laboratories
 West Hartford=2C CT

  =0A=
_=0A=
View your other email accounts from your Hotmail inbox. Add them now.=0A=

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Re: [R] proto and get()

2009-10-09 Thread Gabor Grothendieck
In further offline discussion with the poster it was explained that
the purpose of this is to display the icon object and not to return an
instantiatedProtoMethod which was what the code was attempting to do.
That is in proto, g$icon is not the icon object. It is the icon method
instantiated with the g object, essentially a currying operation in
which the object is plugged into the first arguement of icon and the
resulting function (no longer a method since its now been
instantiated) returned. To get what the poster desires, namely the
icon object itself, one would do this instead of g$icon:

   with(g, icon)

On Thu, Oct 8, 2009 at 7:44 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
 This may be a bug in objects of class instantiatedProtoMethod.   I
 tried it with the devel version of proto and got no error so you could
 try that.  I will send it to you offline for your try.

 On Thu, Oct 8, 2009 at 1:02 PM, baptiste auguie
 baptiste.aug...@googlemail.com wrote:
 Dear all,

 In mucking around with ggplot2, I've hit the following snag,

 library(ggplot2)

 # this returns a grob, OK
 GeomAbline$icon()
 # lines[GRID.lines.9]

 # this returns the function icon, OK
 GeomAbline$icon
 # proto method (instantiated with ): function (.)
 # linesGrob(c(0, 1), c(0.2, 0.8))
 # environment: 0x13e6800

 Now I want to wrap this in a function,

 getIcon - function(geom){
  st - paste(Geom, firstUpper(geom), sep=)

  g - get(st, 2)

  g$icon()
 }

 getIcon(abline) # still OK
 # lines[GRID.lines.10]

 but ...

 getIcon - function(geom){
  st - paste(Geom, firstUpper(geom), sep=)

  g - get(st, 2)

  g$icon
 }
 getIcon(abline)
 # proto method (instantiated with ):
 # Error in get(icon, env = g, inherits = TRUE) : object 'g' not found

 So, it seems that I'm being too naive about using get on a proto
 object or something along those lines.

 I'd be grateful if proto experts could help me extract the icon
 function from this object.

 Best regards,

 baptiste

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Re: [R] odfWeave XML error in post-processing

2009-10-09 Thread Duncan Temple Lang

Hi Rob.

Without the file content_1.xml or any information
from the R call stack (e.g. options(error = recover)
and then run the command and dynamically explore the
state of affairs when the error occurs), there is
no way for us to know what the problem might be.

Somehow, the XML parser appears to be seeing a
 token
and token is not a legitimate XML element name. It may also be
seeing apos; which would identify an XML entity.

Assuming that this is what the XML parser is seeing,
the question is how they got into the document.

So we need more to start diagnosing the problem.

  D.

Rob James wrote:
 I've been happily building a file with odfWeave, and just as the hour
 draws nigh for it to be sent off, odfWeave or XML throws  the following
 catastrophic error:
 
 
 ...this is the tail of entirely uneventful processing of input file.
 
 31 : term xml(label=LR_Fall_Model_Results)
  32 : term verbatim(label=LR_Model_Fall_graph)
  33 : term xml(label=LR_OMC_tab)
 
 'content_1.xml' has been Sweaved
 
 Removing content.xml
 
 Post-processing the contents
 xmlParseStartTag: invalid element name
 Entity 'apos' not defined
 Entity 'apos' not defined
 
 
 This triplet of errors XMLParse, and duplicate Entity lines is
 reported several times, then XML or odfWeave  packs up its toys, and
 goes home without an output file.
 
 I'd (desperately) love any insights anyone might have.
 
 Thanks,
 
 Rob
 
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[R] Problems with code containing a for loop

2009-10-09 Thread Antje##

The following code isn't working and we can't figure out why..

letters = c(A,B,C,D,E,F,G,H,I,J) 
numbers = 1:3 
 
for(i in 1:6){   #6 letters
for (j in 1:3) {   #3 numbers 
for (k in -1:1) { #answer -1,right or +1
 
  fn = paste (i,j,k,.bmp,sep=)
  bmp(file = fn)
  plot(x = 10, y = 10, ylim=c(0,1), xlim=c(0,1),
axes=FALSE, ylab=, xlab=) 
  text(0.5,0.5, text = paste(letters[i], +,
numbers[j],=, letters [i+j+k]) 
  dev.off()
 }
   }
   }

We get the following errors: 
Error: unexpected symbol in:
  text(0.5,0.5, text = paste(letters[i], +,
numbers[j],=, letters [i+j+k]) 
  dev.off
  }
Error: unexpected '}' in  }
}
Error: unexpected '}' in}
}
Error: unexpected '}' in}
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[R] Tobit model

2009-10-09 Thread mrsilva
 

Hi all, 

I'm from Brazil. 

I fit a Tobit model to FLUID MILK CONSUMPTION (DEPENDENT VARIABLE) 

 data using survreg (attached).  

I am confused about the output interpretation and I would like yours
explanations. 

Thanks, 

Marcio Roberto Silva __
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Re: [R] Handling missing data

2009-10-09 Thread premmad

I have one column 
x
97
94
91
90
NA 
NA
NA 
NA 
I tried 
book$r-ifelse(book$x!=NA,book$x+20,10)
I expect to get the result as follows
107
104
91
90
10
10
10
10
But what i was getting is empty column of variable r.How to solve this 

-- 
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[R] Re place many rows in a table with new rows in one step

2009-10-09 Thread Zhen Lin

I tried this:
(c is the column vector with indices of those rows I want to replace)

table[c,]-replace(table[c,],c,newRows)

but it does not work and the error is:
new columns would leave holes after existing columns

Can anyone help please?

Thanks
-- 
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[R] Help producing plot for assessing forecasting accuracy

2009-10-09 Thread Jay Ulfelder
Dear colleagues,

I'm trying (and failing) to write the script required to generate a
chart that would help me assess the forecasting accuracy of a logistic
regression model by plotting the cumulative proportion of observed
events occurring in cases across the range of possible predicted
probabilities. In other words, let:

x = any value on 0-1 scale

phat_i = predicted probability of event Y from logit model for case i

y_i = observed outcome (0/1) for case i

Y_cond = sum(y_i) conditional on phat_i = x

Y_tot = total number of events observed in sample

What I'm trying to plot is (Y_cond)/(Y_tot) across all values of x. I
would be grateful for any guidance you can offer, and I'm sorry if
I've overlooked some really simple solution; I'm fairly new to R and
learning by doing.

Regards,
Jay

-- 
Jay Ulfelder, Ph.D.
Research Director
Political Instability Task Force
Science Applications International Corp. (SAIC)
jay_ulfel...@stanfordalumni.org
(301) 588-8478 [home office]
(301) 580-8736 [mobile]

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[R] Help with printing fixed width

2009-10-09 Thread sahil seth
Hello R users,
I am writing a summary() for a custom class, and am to display the integers
right justified,
Say where x is the vector with integers, I am using the following:
cat(\t,format(x),\t...other columns)

this way I am trying to pass the format(x), to the cat function to display
it,
but still I am getting a kink(b/w the 9th and 10th row).
   6  81  170  251  1.998026e-08
   7  26  93  119  4.937587e-10
   8  96  209  305  8.750939e-11
   9  94  211  305  1.758285e-11
 10  88  205  293  6.47853e-12
 11  82  244  326  7.943691e-20
 12  57  145  202  4.964509e-10
Thanks,
-- 
Regards,
Sahil Seth
JHSPH

[[alternative HTML version deleted]]

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Re: [R] Handling missing data

2009-10-09 Thread jim holtman
What you want is:

book$r-ifelse(is.na(book$r), 10,book$x+20)

On Fri, Oct 9, 2009 at 5:46 AM, premmad mtechp...@gmail.com wrote:

 I have one column
 x
 97
 94
 91
 90
 NA
 NA
 NA
 NA
 I tried
 book$r-ifelse(book$x!=NA,book$x+20,10)
 I expect to get the result as follows
 107
 104
 91
 90
 10
 10
 10
 10
 But what i was getting is empty column of variable r.How to solve this

 --
 View this message in context: 
 http://www.nabble.com/Handling-missing-data-tp25539335p25818365.html
 Sent from the R help mailing list archive at Nabble.com.

 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

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Re: [R] Problems with code containing a for loop

2009-10-09 Thread Erik Iverson
Because you missed your closing parens in the text function call. The closing 
parens is closing the paste function, you need one more.  I don't know what 
you're trying to do here, but I am guessing there's a faster way?  

 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
 On Behalf Of Antje##
 Sent: Friday, October 09, 2009 10:37 AM
 To: r-help@r-project.org
 Subject: [R] Problems with code containing a for loop
 
 
 The following code isn't working and we can't figure out why..
 
 letters = c(A,B,C,D,E,F,G,H,I,J)
 numbers = 1:3
 
 for(i in 1:6){   #6 letters
 for (j in 1:3) {   #3 numbers
 for (k in -1:1) { #answer -1,right or +1
   fn = paste (i,j,k,.bmp,sep=)
   bmp(file = fn)
   plot(x = 10, y = 10, ylim=c(0,1), xlim=c(0,1),
 axes=FALSE, ylab=, xlab=)
   text(0.5,0.5, text = paste(letters[i], +,
 numbers[j],=, letters [i+j+k])
   dev.off()
  }
}
}
 
 We get the following errors:
 Error: unexpected symbol in:
   text(0.5,0.5, text = paste(letters[i], +,
 numbers[j],=, letters [i+j+k])
   dev.off
   }
 Error: unexpected '}' in  }
 }
 Error: unexpected '}' in}
 }
 Error: unexpected '}' in}
 --
 View this message in context: http://www.nabble.com/Problems-with-code-
 containing-a-for-loop-tp25823173p25823173.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
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Re: [R] Handling missing data

2009-10-09 Thread Erik Iverson
1) No need to post multiple times to the list
2) use the is.na function to test if a value is missing, not == or != 

 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
 On Behalf Of premmad
 Sent: Friday, October 09, 2009 5:05 AM
 To: r-help@r-project.org
 Subject: Re: [R] Handling missing data
 
 
 I have one column
 x
 97
 94
 91
 90
 NA
 NA
 NA
 NA
 I tried
 i tried  this
 book$r-ifelse(book$x!=NA,book$x+20,10)
 expected result
 107
 104
 101
 100
 10
 10
 10
 10
 
 But got empty column of variable r.How to work with missing values of
 numeric variables.
 Why the numeric variable missing is assigned NA but not .,help in easy
 work
 for us.
 --
 View this message in context: http://www.nabble.com/Handling-missing-data-
 tp25539335p25818365.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
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 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
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Re: [R] Help with printing fixed width

2009-10-09 Thread jim holtman
try using 'sprintf'

On Fri, Oct 9, 2009 at 8:36 AM, sahil seth sahiils...@gmail.com wrote:
 Hello R users,
 I am writing a summary() for a custom class, and am to display the integers
 right justified,
 Say where x is the vector with integers, I am using the following:
 cat(\t,format(x),\t...other columns)

 this way I am trying to pass the format(x), to the cat function to display
 it,
 but still I am getting a kink(b/w the 9th and 10th row).
   6      81      170      251      1.998026e-08
   7      26      93      119      4.937587e-10
   8      96      209      305      8.750939e-11
   9      94      211      305      1.758285e-11
     10      88      205      293      6.47853e-12
     11      82      244      326      7.943691e-20
     12      57      145      202      4.964509e-10
 Thanks,
 --
 Regards,
 Sahil Seth
 JHSPH

        [[alternative HTML version deleted]]

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-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

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Re: [R] Problems with code containing a for loop

2009-10-09 Thread xavier . chardon
A parenthesis is missing. You can figure that out easily watching the first 
error.

text(0.5,0.5, text = paste(letters[i], +, numbers[j],=, letters [i+j+k]))

Xavier


- Mail Original -
De: Antje## ann3bu...@hotmail.com
À: r-help@r-project.org
Envoyé: Vendredi 9 Octobre 2009 17h36:34 GMT +01:00 Amsterdam / Berlin / Berne 
/ Rome / Stockholm / Vienne
Objet: [R]  Problems with code containing a for loop


The following code isn't working and we can't figure out why..

letters = c(A,B,C,D,E,F,G,H,I,J) 
numbers = 1:3 
 
for(i in 1:6){   #6 letters
for (j in 1:3) {   #3 numbers 
for (k in -1:1) { #answer -1,right or +1
 
  fn = paste (i,j,k,.bmp,sep=)
  bmp(file = fn)
  plot(x = 10, y = 10, ylim=c(0,1), xlim=c(0,1),
axes=FALSE, ylab=, xlab=) 
  text(0.5,0.5, text = paste(letters[i], +,
numbers[j],=, letters [i+j+k]) 
  dev.off()
 }
   }
   }

We get the following errors: 
Error: unexpected symbol in:
  text(0.5,0.5, text = paste(letters[i], +,
numbers[j],=, letters [i+j+k]) 
  dev.off
  }
Error: unexpected '}' in  }
}
Error: unexpected '}' in}
}
Error: unexpected '}' in}
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[R] Problems with code

2009-10-09 Thread Anne Buunk

The following code isn't working and we can't figure out why.. 

letters = c(A,B,C,D,E,F,G,H,I,J) 
numbers = 1:3 
  
for(i in 1:6){   #6 letters 
for (j in 1:3) {   #3 numbers 
for (k in -1:1) { #answer -1,right or +1
 
  fn = paste (i,j,k,.bmp,sep=) 
  bmp(file = fn) 
  plot(x = 10, y = 10, ylim=c(0,1), xlim=c(0,1), 
axes=FALSE, ylab=, xlab=) 
  text(0.5,0.5, text = paste(letters[i], +, 
numbers[j],=, letters [i+j+k]) 
  dev.off() 
 } 
   } 
   } 

We get the following errors: 
Error: unexpected symbol in: 
  text(0.5,0.5, text = paste(letters[i], +, 
numbers[j],=, letters [i+j+k]) 
  dev.off 
  } 
Error: unexpected '}' in  } 
} 
Error: unexpected '}' in} 
} 
Error: unexpected '}' in}
 
I hope you can figure out how to fix this..
Greetings
  
_


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[R] For loop isn't working correctly

2009-10-09 Thread Anne Buunk

Hi. With your help, I've fixed the errors in my for loops.

But now, the for loop isn't working correctly. There should be a plot,

but there's no plot when I run the for loop..

 

This is the code:

 

letters = c(A,B,C,D,E,F,G,H,I,J) 
numbers = 1:3 
 
for(i in 1:6){   #6 letters
for (j in 1:3) {   #3 numbers 
for (k in -1:1) { #answer -1,right or +1
 
  fn = paste (i,j,k,.bmp,sep=)
  bmp(file = fn)
  plot(x = 10, y = 10, ylim=c(0,1), xlim=c(0,1), 
axes=FALSE, ylab=, xlab=) 
  text(0.5,0.5, labels = paste(letters[i], +, 
numbers[j],=, letters [i+j+k])) 
  dev.off()
 }
   }
   }


Can somebody see why this isn't running correctly?

 

Thanks for the help untill now! Greetings
  
_


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[R] different time series in one plot

2009-10-09 Thread Tomas Lanczos
Hello,

I need to put 2 or more different time series to one plot for comparison
each other. The problem is that the time series are irregular, moreover
the time lenghts and periods are not the same. Is there a way to manage
it in R?

Many thanks for any hint and advice in advance

Tomas

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Re: [R] Problems with code

2009-10-09 Thread Barry Rowlingson
On Fri, Oct 9, 2009 at 4:54 PM, Anne Buunk ann3bu...@hotmail.com wrote:
                          text(0.5,0.5, text = paste(letters[i], +, 
 numbers[j],=, letters [i+j+k])

Missing ) on the end there. You have one ( for text( and one for
paste( but only one ).

 Use an editor that matches parentheses, and read error messages to
figure out where things are going wrong.

Barry

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Re: [R] For loop isn't working correctly

2009-10-09 Thread jim holtman
It plots on my system just fine.  You might want to check what
directory (getwd()) that you are plotting in.

On Fri, Oct 9, 2009 at 12:17 PM, Anne Buunk ann3bu...@hotmail.com wrote:

 Hi. With your help, I've fixed the errors in my for loops.

 But now, the for loop isn't working correctly. There should be a plot,

 but there's no plot when I run the for loop..



 This is the code:



 letters = c(A,B,C,D,E,F,G,H,I,J)
 numbers = 1:3

 for(i in 1:6){                       #6 letters
                for (j in 1:3) {                   #3 numbers
                    for (k in -1:1) {             #answer -1,right or +1
                          fn = paste (i,j,k,.bmp,sep=)
                          bmp(file = fn)
                          plot(x = 10, y = 10, ylim=c(0,1), xlim=c(0,1), 
 axes=FALSE, ylab=, xlab=)
                          text(0.5,0.5, labels = paste(letters[i], +, 
 numbers[j],=, letters [i+j+k]))
                          dev.off()
                                     }
                               }
                           }


 Can somebody see why this isn't running correctly?



 Thanks for the help untill now! Greetings

 _


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 and provide commented, minimal, self-contained, reproducible code.




-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?

__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] wrong plot with fda or lda?

2009-10-09 Thread Alejo C.S.
Hi,
I have a strange behavior of plot function when trying to plot a
discriminant analysis obtained by fda.
I'd attached the data for reproduction. I made the same analysis (linear
discriminant analysis) but using lda and fda (default args, using
polyreg). The resulting coefficients and trace proportions for the two
analysis are the same, that's good, but if you plot the two analysis the
graphs are very different. Plotting the results of lda function gives much
more overlapping of points from different groups than using fda.


 If you make:

libray(MASS)
library(mda)

read.table(data, header=T) - data

data[,1] - grp
data[,2:24] - X

#Linear discriminant analysis using fda
fda(grp ~ ., data=X) - FDA
plot(FDA)

#Linear discriminant analysis using lda
lda(grp ~ ., data=X) - LDA
plot(LDA, col=palette()[grp])# Very different results

#Same coefficients
coef(FDA)
coef(LDA)

Regards,
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Re: [R] Any reference to Tukeyline algorithm?

2009-10-09 Thread Bert Gunter
Google is your friend! (search on Tukey median line fit); e.g. 

http://www.amstat.org/publications/jse/v14n2/morrell.html

Bert Gunter
Genentech Noclinical Statistics

-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of shanmukha patel
Sent: Friday, October 09, 2009 6:26 AM
To: r-help@r-project.org
Subject: [R] Any reference to Tukeyline algorithm?

Hi,
I am using line function to plot the line. And I would like to understand
Tukeyline algorithm. Since, the line function is calling the Tukeyline
algorithm(which is compiled code) using foreign function interface, I am not
able to look into the source code of this algorithm. Can somebody help me
out, so that I can refer the same.

Thanks in advance!!!

Thanks,
Shanmukh.




  Try the new Yahoo! India Homepage. Click here.
http://in.yahoo.com/trynew
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Re: [R] row selection

2009-10-09 Thread Ashta
 Hi all,

Thank you for your help. Now I am able to select every 5th row of the data
from the main data set (x)
using

sub1- x[seq(1, nrow(x), by=5), ]


So sub1 contains one fith of the data set  X.  I want also create another
data set that will contain the remaining  data set from X (ie., four fifth
of the data set).

Any help is highly appreciated.








I have a matrix  named x with N by  C
I want to select every 5 th rrow from matrix x I used the following
code
 n- nrow(x)
 for(i in 1: n){
 + b - a[i+5,]
 b
 }



sc  x[seq(1, nrow(x), by=5), ]


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
 On Behalf Of David Winsemius
 Sent: Thursday, October 08, 2009 4:19 PM
 To: Ashta
 Cc: R help
 Subject: Re: [R] row selection


 On Oct 8, 2009, at 4:14 PM, Ashta wrote:

  Hi all,
  I have a matrix  named x with N by  C
  I want to select every 5 th rrow from matrix x I used the following
  code
  n- nrow(x)
  for(i in 1: n){
  + b - a[i+5,]
  b
  }
  Error: subscript out of bounds

 What did you expect when i in your loop counter became one greater
 than the number of rows?

 


 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT

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Re: [R] distr package

2009-10-09 Thread Peter Ruckdeschel
Thanks David,

for answering this question.

 On Oct 8, 2009, at 4:33 AM, msig...@yahoo.com wrote:
 
 Dear all
 when I try to install distr, the following error appears, I am using
 R in windows. can u suggest me?

 
 I'm not a Windows user, but the obvious questions would be How?. What
 commands or method? and Which? (version of Windows and the ever
 present question for Vista users ... what is your level of admin
 privileges), and Is that everything? (was that the entire output?)
 
 And the second obvious question: Why have you not included output from:
 
  sessionInfo()
 
 Perhaps a not so obvious question that you should answer:  what is the
 output from:
 
  .libPaths()
 
 
 Error in normalizePath(path) :
  path[1]=C:\Program Files\R\R-2.9.1\library/distr: The system cannot
 find the file specified

I can assist David's comments.

@ the original poster:

It might be a backslash thing (and does not seem to be
connected to package distr in any respect):

Within R, even on Windows, you can use the forward slash as folder
separator, so your trailing /distr seems to be oK.

Backslashes, which in R on Windows may also serve for this purpose,
have to be escaped, so you might eigher try

C:/Program Files/R/R-2.9.1/library/distr

or

C:\\Program Files\\R\R-2.9.1\\library/distr

In fact you have not told us all you saw, I suppose:
Didn't you get this warning, too?

In addition: Warning messages:
1: '\P' is an unrecognized escape in a character string
2: '\R' is an unrecognized escape in a character string
3: '\R' is an unrecognized escape in a character string
4: unrecognized escapes removed from C:\Program Files\R\R-2.9.1/distr

which already told you the problem.

btw: it would be nice also if you could at least tell us your
name so that we can address you personally.

Peter Ruckdeschel,
maintainer of package distr

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Re: [R] variogram

2009-10-09 Thread jim holtman
It probably means that your data is not in the right format. PLEASE do
read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

If you show the data, it might help.  It sounds like something is
empty, but it is hard to tell what from the information provided.

On Thu, Oct 8, 2009 at 9:07 AM, JRE akun...@gmx.de wrote:

 Hello everybody,
 I want to run the following R-code, but it does'nt work.


 res.vgm = variogram(ertrag ~ rep, # !!!
 +                     loc = ~ xpos + ypos, # !!!
 +                     width = start.range / 10,
 +                     data = d)
 Error in vector(double, length) : element 2 is empty;
   the part of the args list of '.Internal' being evaluated was:
   (mode, length)

 What does the error message mean?

 Many thanks for your help!

 JRE


 --
 View this message in context: 
 http://www.nabble.com/variogram-tp25802976p25802976.html
 Sent from the R help mailing list archive at Nabble.com.

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+1 513 646 9390

What is the problem that you are trying to solve?

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Re: [R] row selection

2009-10-09 Thread Nutter, Benjamin
sub3 - x[-seq(1, nrow(x), by=5), ]
 
Notice the '-' in front of the seq() command.  This will select
everything but what is in the sequence.

 



From: Ashta [mailto:sewa...@gmail.com] 
Sent: Friday, October 09, 2009 12:42 PM
To: Nutter, Benjamin
Cc: r-help@r-project.org
Subject: Re: [R] row selection


Hi all,

Thank you for your help. Now I am able to select every 5th row of the
data from the main data set (x) 
using

sub1- x[seq(1, nrow(x), by=5), ]


So sub1 contains one fith of the data set  X.  I want also create
another data set that will contain the remaining  data set from X (ie.,
four fifth of the data set).

Any help is highly appreciated.








I have a matrix  named x with N by  C
I want to select every 5 th rrow from matrix x I used the following
code
 n- nrow(x)
 for(i in 1: n){
 + b - a[i+5,]
 b
 }



sc  x[seq(1, nrow(x), by=5), ]



-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org]
On Behalf Of David Winsemius
Sent: Thursday, October 08, 2009 4:19 PM
To: Ashta
Cc: R help
Subject: Re: [R] row selection


On Oct 8, 2009, at 4:14 PM, Ashta wrote:

 Hi all,
 I have a matrix  named x with N by  C
 I want to select every 5 th rrow from matrix x I used the
following
 code
 n- nrow(x)
 for(i in 1: n){
 + b - a[i+5,]
 b
 }
 Error: subscript out of bounds

What did you expect when i in your loop counter became one
greater
than the number of rows?




David Winsemius, MD
Heritage Laboratories
West Hartford, CT


__
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code.


===

P Please consider the environment before printing this e-mail

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Visit us online at http://www.clevelandclinic.org for
a complete listing of our services, staff and
locations.


Confidentiality Note:  This message is intended for
use\...{{dropped:13}}

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code.




===

P Please consider the environment before printing this e-mail

Cleveland Clinic is ranked one of the top hospitals
in America by U.S. News  World Report (2008).  
Visit us online at http://www.clevelandclinic.org for
a complete listing of our services, staff and
locations.


Confidentiality Note:  This message is intended for use\...{{dropped:16}}

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Re: [R] Trendline for a subset of data

2009-10-09 Thread David Winsemius
You are emitting weird hex-stuff from your mail client. And from what  
I can tell that is not a reproducible example even if hex-ation  
problem gets fixed. There is a worked example in segments.


On Oct 9, 2009, at 10:45 AM, Steve Murray wrote:



cb247343-29ec-495a-ba8e-d5a466bab...@comcast.net
Content-Type: text/plain; charset=iso-8859-1
Content-Transfer-Encoding: quoted-printable
MIME-Version: 1.0


Thanks for flagging up the 'segments' command. However=2C I'm having  
troubl=
e getting it to work - this is probably due to me misunderstanding  
the docu=

mentation for this command.

The plot section of my script appears as follows:

test3 - 36:45
plot(data_means=2C type=3Db=2C pch=3D4=2C ylab=3D=2C  
xlab=3D=2C xaxt=

=3Dn=2C yaxt=3Dn=2C col=3D3=2C ylim=3Dc(250=2C380))
abline(lm(data_means[36:45] ~ test3)=2C lty=3D2)


As you can see=2C


I cannot see anything. If you are under the impression that there  
should have been an attachment, then (re-?)read the Posting Guide on  
that topic.




I'm only plotting points 36 to 45 from the object 'data_m=
eans'. This intentionally results in much white space along the x- 
axis unti=
l point 36 is reached. However=2C when inserting the trendline=2C  
this runs=
along the entire length of the x-axis instead of just through points  
36 to=
45. Ideally=2C a line which slightly overshoots the data subset  
would look=
the best=2C but one constrained to the extents of the 36:45 would  
also do =

the job just fine.

So=2C my question is=2C how do I use 'segments' (or otherwise) to  
create a =
linear trendline which only extends through points 36:45? (and  
overshoots a=
t either end very slightly=2C if possible=2C rather than running  
along the =

entire length of the x-axis).


The basic strategy would be to calculate the x and y coordinates of  
the two points at the end of the desired segment and then say  
segments( x[1], y[1], x[2], y[2] )




Many thanks again=2C

Steve



CC: r-help@r-project.org
From: dwinsem...@comcast.net
To: smurray...@hotmail.com
Subject: Re: [R] Trendline for a subset of data
Date: Fri=2C 9 Oct 2009 09:27:43 -0400


On Oct 9=2C 2009=2C at 5:50 AM=2C Steve Murray wrote:



Dear all=2C

I am using abline(lm ...) to insert a linear trendline through a
portion of my data (e.g. dataset[=2C36:45]). However=2C I am finding
that whilst the trendline is correctly displayed and representative
of the data portion I've chosen=2C the line continues to run beyond
this data segment and continues until it intersects the vertical
axes at each side of the plot.

How do I display the line so that it only runs between point 36 and
45 (as shown in the example above) as doesn't continue to display a
line throughout the rest of the plot space?



?segments






  =0A=
_=0A=
View your other email accounts from your Hotmail inbox. Add them  
now.=0A=

http://clk.atdmt.com/UKM/go/167688463/direct/01/=


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] row selection

2009-10-09 Thread David Winsemius


On Oct 9, 2009, at 12:41 PM, Ashta wrote:


Hi all,

Thank you for your help. Now I am able to select every 5th row of  
the data

from the main data set (x)
using

sub1- x[seq(1, nrow(x), by=5), ]


So sub1 contains one fith of the data set  X.  I want also create  
another
data set that will contain the remaining  data set from X (ie., four  
fifth

of the data set).


sub1- x[-seq(1, nrow(x), by=5), ]




Any help is highly appreciated.

I have a matrix  named x with N by  C
I want to select every 5 th rrow from matrix x I used the following
code

n- nrow(x)

for(i in 1: n){

+ b - a[i+5,]

b

}




sc  x[seq(1, nrow(x), by=5), ]




-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org 
]

On Behalf Of David Winsemius
Sent: Thursday, October 08, 2009 4:19 PM
To: Ashta
Cc: R help
Subject: Re: [R] row selection


On Oct 8, 2009, at 4:14 PM, Ashta wrote:


Hi all,
I have a matrix  named x with N by  C
I want to select every 5 th rrow from matrix x I used the following
code
n- nrow(x)

for(i in 1: n){

+ b - a[i+5,]

b

}
Error: subscript out of bounds


What did you expect when i in your loop counter became one greater
than the number of rows?








David Winsemius, MD
Heritage Laboratories
West Hartford, CT

__
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and provide commented, minimal, self-contained, reproducible code.


Re: [R] different time series in one plot

2009-10-09 Thread Gabor Grothendieck
plot.zoo and xyplot.zoo in the zoo package can both do that:

library(zoo)
z - zoo(c(21, 34, 33, 41, 39, 38, 37, 28, 33, 40),
 as.Date(c(1992-01-10, 1992-01-17, 1992-01-24, 1992-01-31,
   1992-02-07, 1992-02-14, 1992-02-21, 1992-02-28, 1992-03-06,
   1992-03-13)))
# z and lag(z) have different spans and are irregular
zz - merge(z, lag(z))

# same screem
plot(zz, screen = 1)
# different screens
plot(zz)

# similar but using zoo's xyplot lattice method
library(lattice)
xyplot(zz, screen = 1)
xyplot(zz)

Read the three vignettes that come with zoo and the help files.

On Fri, Oct 9, 2009 at 12:18 PM, Tomas Lanczos lanc...@fns.uniba.sk wrote:
 Hello,

 I need to put 2 or more different time series to one plot for comparison
 each other. The problem is that the time series are irregular, moreover
 the time lenghts and periods are not the same. Is there a way to manage
 it in R?

 Many thanks for any hint and advice in advance

 Tomas

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Re: [R] Trendline for a subset of data

2009-10-09 Thread Steve Murray

 b2a99330-1d1d-49cc-b287-81f37c16b...@comcast.net
Content-Type: text/plain; charset=iso-8859-1
Content-Transfer-Encoding: quoted-printable
MIME-Version: 1.0


Thanks Mark=2C the reg.line trick seemed to work really well.

David - hopefully the hex-text will have gone now - if not=2C please accept=
 my apologies as=2C this is=2C as far as I know=2C the first time this has =
happened. If it hasn't gone=2C then I'm afraid I'm a little clueless as to =
how to remove it!

Thanks again both of you=2C

Steve
  =0A=
_=0A=
Save time by using Hotmail to access your other email accounts.=0A=
http://clk.atdmt.com/UKM/go/167688463/direct/01/=

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Re: [R] Re place many rows in a table with new rows in one step

2009-10-09 Thread David Winsemius


On Oct 9, 2009, at 6:42 AM, Zhen Lin wrote:



I tried this:
(c is the column vector with indices of those rows I want to replace)

table[c,]-replace(table[c,],c,newRows)

but it does not work and the error is:
new columns would leave holes after existing columns


replace() is supposed to work on vectors, but if you have a table  
object then that might be better manipulated with indexing approaches.  
Try making up a small table object and they working on it.


 table1 - table(sample(LETTERS[1:5], 10, replace=T),  
sample(letters[1:5], 10, replace=T))

 table1

a b c d
  A 1 0 1 2
  B 0 1 0 0
  C 0 1 0 1
  D 0 0 0 1
  E 0 1 0 1
 table1[2,] - c(1,1,1,1)
 table1

a b c d
  A 1 0 1 2
  B 1 1 1 1
  C 0 1 0 1
  D 0 0 0 1
  E 0 1 0 1


--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] celebrating revision 50000

2009-10-09 Thread Romain Francois
Thanks to Dirk for pointing it out in my blog : thomas and tlumley 
are the same person. Also martyn and plummer, and paul and 
murrell ... updated number of commits per author below


 sort( table( simple$author ), decreasing=T )

 ripleymaechler  hornik  pd murdoch   iacus
  20523   10207674446551370 915
 leisch jmcluke   ihaka murrell   bates
743 643 618 481 427 350
tlumleyrgentlemurbaneks (no author)  duncan   r
337 299 274 203 172  96
plummer  lyndon   guidodeepayan  falconmike
 65  54  39  20  18   1


Not quite sure who r is (96 commits) and mike (1 commit). Also there 
are 203 commits that have (no author)


The other thing is that it does not include data from the pre-svn era.

Romain

On 10/09/2009 03:41 PM, Romain Francois wrote:


Hello,

Today, Brian Ripley commited the revision 5 of R's svn repository.

I took this as an opportunity to do some data analysis of the log and
posted some code and graphics on my blog:
http://romainfrancois.blog.free.fr/index.php?post/2009/10/09/celebrating-R-commit-5


The plots of the number of commits per day (and per month) indicates a
peak in 2002.

Here are the top 20 modified files :

  most.updated - head( sort( table( data$file ), decreasing=TRUE ), 20 )
  cat( sprintf( %40s : %6d, names(most.updated), most.updated ), sep
=\n )
/trunk/NEWS : 5449
/trunk/date-stamp : 2219
/trunk/BUGS : 1485
/trunk/src/gnuwin32/CHANGES : 994
/trunk/configure : 979
/trunk/doc/manual/R-FAQ.texi : 948
/trunk/doc/manual/R-exts.texi : 814
/trunk/doc/manual/R-admin.texi : 666
/trunk/src/main/names.c : 634
/trunk/tests/reg-tests-1.R : 621
/trunk/src/gnuwin32/Makefile : 542
/trunk/FAQ : 471
/trunk/doc/html/faq.html : 458
/trunk/src/include/Defn.h : 455
/trunk/configure.ac : 447
/trunk/src/scripts/check.in : 433
/trunk/src/library/tools/R/QC.R : 397
/branches/unlabeled-1.1139.4/date-stamp : 386
/trunk/src/main/connections.c : 349
/trunk/src/main/plot.c : 325


The most modified file extensions (the second element indicates files
without extensions) :

  head( sort( table( data$extension ), decreasing=T ) , 24 )

Rd c R po in mo h
36766 33999 29849 25221 10215 8806 6280 6147
texi gmo html save pot f win m4
5274 3705 1920 1668 1285 1148 1060 1041
pl ac afm pm mac y packages sh
910 527 482 461 402 384 311 215

Many thanks to the R core team for these 50 000 commits.

Romain




--
Romain Francois
Professional R Enthusiast
+33(0) 6 28 91 30 30
http://romainfrancois.blog.free.fr
|- http://tr.im/BcPw : celebrating R commit #5
|- http://tr.im/ztCu : RGG #158:161: examples of package IDPmisc
`- http://tr.im/yw8E : New R package : sos

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Re: [R] k-modes (Huang) in package klaR?

2009-10-09 Thread Uwe Ligges



Uwe Ligges wrote:



Uwe Ligges wrote:



Kim Vanselow wrote:

Dear R-Users and Developers,
I want to calculate something like k-means clustering, but with 
ordinal data (Braun-Blanquet) to combine this classification 
technique with a NMDS-Ordination.
I found an algorithm especially developed for categorical data: 
k-modes (Huang 1998). Is there a function implemented in R which can 
calculate with this algorithm. I found a hint on a poster-abstract 
from Gero Szepannek, Uwe Ligges and Claus Weihs. There it is stated 
that the algorithm is implemented in their package klaR. But I cannot 
find anything about k-modes in the klaR-Tutorial.

Could you please help me.


Dear Kim,

well, maybe you start writing a message to the authors of that 
poster-abstract at first who might be able to help?
Since I am one of those: Where can I find this abstract or poster (at 
least in order to remind Gero who does no longer work at the 
university to finally implement the feature, if it is not yet there)?


Some news on this:

Gero never presented it in his talk at the useR!2008 and we all forgot 
that he announced it in his abstract. He is working for a bank these 
days and is going to send his code within a few days. Will take a look 
if it is easy to add the existing code to klaR then.



FYI: I got the code now, will try to incorporate it soon.

Best,
Uwe



Best wishes,
Uwe Ligges



Best wishes,
Uwe Ligges




Thanks
Kim






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[R] Satellite ocean color palette?

2009-10-09 Thread Tim Clark
Dear List,

Is there a color palette avaliable similar to what is used in satellite ocean 
color imagery?  I.e. a gradient with blue on one end and red on the other, with 
yellow in the middle?  I have tried topo.colors(n) but that comes out more 
yellow on the end.  I am looking for something similar to what is found on the 
CoastWatch web page:

http://oceanwatch.pifsc.noaa.gov/imagery/GA2009281_2009282_sst_2D_eddy.jpg

Thanks!

Tim


Tim Clark
Department of Zoology 
University of Hawaii

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Re: [R] Satellite ocean color palette?

2009-10-09 Thread Henrique Dallazuanna
See ?colorRampPallete


On Fri, Oct 9, 2009 at 3:51 PM, Tim Clark mudiver1...@yahoo.com wrote:
 Dear List,

 Is there a color palette avaliable similar to what is used in satellite ocean 
 color imagery?  I.e. a gradient with blue on one end and red on the other, 
 with yellow in the middle?  I have tried topo.colors(n) but that comes out 
 more yellow on the end.  I am looking for something similar to what is found 
 on the CoastWatch web page:

 http://oceanwatch.pifsc.noaa.gov/imagery/GA2009281_2009282_sst_2D_eddy.jpg

 Thanks!

 Tim


 Tim Clark
 Department of Zoology
 University of Hawaii

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-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O

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Re: [R] Satellite ocean color palette?

2009-10-09 Thread Barry Rowlingson
On Fri, Oct 9, 2009 at 7:51 PM, Tim Clark mudiver1...@yahoo.com wrote:
 Dear List,

 Is there a color palette avaliable similar to what is used in satellite ocean 
 color imagery?  I.e. a gradient with blue on one end and red on the other, 
 with yellow in the middle?  I have tried topo.colors(n) but that comes out 
 more yellow on the end.  I am looking for something similar to what is found 
 on the CoastWatch web page:

 http://oceanwatch.pifsc.noaa.gov/imagery/GA2009281_2009282_sst_2D_eddy.jpg

 Thanks!

 You could build one yourself with the colorRamp function:

satRampP = 
colorRampPalette(c(black,blue,cyan,yellow,orange,red,black))

 that looks roughly like the one in the jpg, but I'm not sure about
the black at the far end...anyway, let's see:

image(matrix(seq(0,1,len=100),100,1),col=satRampP(100))

Or you could try my colour schemes package:

https://r-forge.r-project.org/projects/colourscheme/

Barry

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Re: [R] Satellite ocean color palette?

2009-10-09 Thread Bernardo Rangel Tura
On Fri, 2009-10-09 at 11:51 -0700, Tim Clark wrote:
 Dear List,
 
 Is there a color palette avaliable similar to what is used in satellite ocean 
 color imagery?  I.e. a gradient with blue on one end and red on the other, 
 with yellow in the middle?  I have tried topo.colors(n) but that comes out 
 more yellow on the end.  I am looking for something similar to what is found 
 on the CoastWatch web page:
 
 http://oceanwatch.pifsc.noaa.gov/imagery/GA2009281_2009282_sst_2D_eddy.jpg
 
 Thanks!
 
 Tim
 
 
 Tim Clark
 Department of Zoology 
 University of Hawaii

Tim,

You can make a palette in R, using colorRampPalette, look this example

Satelite.Pallete -
colorRampPalette(c(blue3,cyan,aquamarine,yellow,orange,red))
require(fields)
image.plot(volcano, col = Satelite.Pallete(500), legend.lab=Scale) 
contour(volcano, levels = seq(90, 200, by = 5), add = TRUE)

-- 
Bernardo Rangel Tura, M.D,MPH,Ph.D
National Institute of Cardiology
Brazil

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[R] Use R -- term and logo copyright?

2009-10-09 Thread Marianne Promberger
Dear list,

I would like to start some R workshops at King's College London, and
to do so, I would like to use the Use R! logo at
http://www.agrocampus-ouest.fr/math/useR-2009//useR%21%202008_fichiers/useR-middle.png

Since it seems to be difficult to get a shell account at KCL, I also went
ahead and registered use-r.org.uk and am starting to put together a
website at kcl.use-r.org.uk.

I really like the Use R! slogan, which seems to be used by the R
user conferences and Springer (the latter without the exclamation
mark).

Even more, I really *really* like Use R! logo.  I think it is very
elegant indeed! Kudos to whoever designed it.

However, I'm completely in the dark about copyright issues of the logo
and the slogan.

Can I use (a) the logo and/or (b) the slogan for the KCL R workshops?
I think it is quite clear from my website that this is neither about
the Springer book series nor about an R user conference.

I enquired with the agrocampus-ouest.fr website about the logo but was
pointed to r-project.org and the R development core team. I thought in
that case it might be best to ask here to have the answer publicly
available -- sorry if I overlooked the information online somewhere.

Marianne

-- 
Marianne Promberger PhD, King's College London
http://promberger.info
R version 2.9.2 (2009-08-24)
Ubuntu 9.04

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Re: [R] Satellite ocean color palette?

2009-10-09 Thread Tim Clark
Thanks!  The colorRampPalette() did just what I need.

Tim


Tim Clark
Department of Zoology 
University of Hawaii


--- On Fri, 10/9/09, Barry Rowlingson b.rowling...@lancaster.ac.uk wrote:

 From: Barry Rowlingson b.rowling...@lancaster.ac.uk
 Subject: Re: [R] Satellite ocean color palette?
 To: Tim Clark mudiver1...@yahoo.com
 Cc: r-help@r-project.org
 Date: Friday, October 9, 2009, 9:06 AM
 On Fri, Oct 9, 2009 at 7:51 PM, Tim
 Clark mudiver1...@yahoo.com
 wrote:
  Dear List,
 
  Is there a color palette avaliable similar to what is
 used in satellite ocean color imagery?  I.e. a gradient
 with blue on one end and red on the other, with yellow in
 the middle?  I have tried topo.colors(n) but that comes out
 more yellow on the end.  I am looking for something similar
 to what is found on the CoastWatch web page:
 
  http://oceanwatch.pifsc.noaa.gov/imagery/GA2009281_2009282_sst_2D_eddy.jpg
 
  Thanks!
 
  You could build one yourself with the colorRamp function:
 
 satRampP =
 colorRampPalette(c(black,blue,cyan,yellow,orange,red,black))
 
  that looks roughly like the one in the jpg, but I'm not
 sure about
 the black at the far end...anyway, let's see:
 
 image(matrix(seq(0,1,len=100),100,1),col=satRampP(100))
 
 Or you could try my colour schemes package:
 
 https://r-forge.r-project.org/projects/colourscheme/
 
 Barry
 




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[R] Placing text in a ggplot

2009-10-09 Thread John Kane
I am attempting to graph 12 months of temperatures, delineate the months with a 
vline and place the names of the months at the top of the graph.

So far I have gotten everything to work except the names, despite getting a 
similar graph to work yesterday the day before yesterday with Baptise A's help. 
 Can anyone suggest what I am doing wrong.  Data set is below code.

Thanks.

Code 
=
line.count - c(1,cumsum(as.vector((table(year$monthnum)
namposts - line.count[1:12]
temprange - range(year[,4], na.rm=TRUE)
mlabs - month.name[1:12]

p  - ggplot(year, aes(duration, temps, colour=month)) + geom_line() +
   ylab(Temperature (C)) + xlab(Mean Daily Temperatures)  +
   opts(legend.position = none, title=Ottawa, 2008,
   axis.text.x = theme_blank(), axis.ticks = theme_blank()) +
   geom_vline(xintercept= line.count) 

[[elided Yahoo spam]]
   
p +  geom_text(aes(x = namposts, y = temprange[2], label = mlabs),
 data = year, size = 2.5, colour='black', hjust = 0, vjust = 0)

==

year  - structure(list(monthnum = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 
2L, 2L, 2L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 
3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 
3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 
5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 
5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 6L, 
6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 
6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L, 7L, 7L, 7L, 
7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 
7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 7L, 8L, 8L, 8L, 8L, 
8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 
8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 9L, 9L, 9L, 9L, 9L, 
9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 
9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 10L, 10L, 10L, 10L, 10L, 
10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 
10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 10L, 
11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 
11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 11L, 
11L, 11L, 11L, 11L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 
12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 
12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L, 12L), days = c(1L, 2L, 
3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 
17L, 18L, 19L, 20L, 21L, 22L, 23L, 24L, 25L, 26L, 27L, 28L, 29L, 
30L, 31L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 
13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L, 21L, 22L, 23L, 24L, 25L, 
26L, 27L, 28L, 29L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 
11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L, 21L, 22L, 23L, 
24L, 25L, 26L, 27L, 28L, 29L, 30L, 31L, 1L, 2L, 3L, 4L, 5L, 6L, 
7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 
20L, 21L, 22L, 23L, 24L, 25L, 26L, 27L, 28L, 29L, 30L, 1L, 2L, 
3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 
17L, 18L, 19L, 20L, 21L, 22L, 23L, 24L, 25L, 26L, 27L, 28L, 29L, 
30L, 31L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 
13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L, 21L, 22L, 23L, 24L, 25L, 
26L, 27L, 28L, 29L, 30L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 
10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L, 21L, 22L, 
23L, 24L, 25L, 26L, 27L, 28L, 29L, 30L, 31L, 1L, 2L, 3L, 4L, 
5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 
19L, 20L, 21L, 22L, 23L, 24L, 25L, 26L, 27L, 28L, 29L, 30L, 31L, 
1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 
15L, 16L, 17L, 18L, 19L, 20L, 21L, 22L, 23L, 24L, 25L, 26L, 27L, 
28L, 29L, 30L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 
12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L, 21L, 22L, 23L, 24L, 
25L, 26L, 27L, 28L, 29L, 30L, 31L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 
8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 20L, 
21L, 22L, 23L, 24L, 25L, 26L, 27L, 28L, 29L, 30L, 1L, 2L, 3L, 
4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 
18L, 19L, 20L, 21L, 22L, 23L, 24L, 25L, 26L, 27L, 28L, 29L, 30L, 
31L), month = structure(c(5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 
5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 5L, 
5L, 5L, 5L, 5L, 5L, 5L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 
4L, 4L, 4L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 
8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 
8L, 8L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 

[R] R CMD --meetup=Chicago --when=Oct 29 --where=Jak'sTap

2009-10-09 Thread Jeff Ryan
Chicagoland R Users:

We are pleased to announce a Fall meetup for Chicagoland R users. This
is open to anyone with an interest in R: practioners, researchers,
casual users and other interested parties.

WHEN: October 29, 2009 @5:30
WHERE: Jak's Tap www.jakstap.com

A short series of so-called lightning talks from some noted R
contributors and users is on the agenda. Speakers include:

Gib Basset (UIC)
Bryan Lewis (Revolution Computing)
JD Long (Cerebral Mastication)
David St. John (UIC, ttrTests package)

Casual conversation and food will follow, courtesy of the
International Center for Futures and Derivatives at the University of
Illinois at Chicago and the organizers of the R/Finance conferences:
http://www.RinFinance.com


Best,
Jeffrey Ryan
(on behalf of the organizing committee)

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Re: [R] gregmisc library (Mandriva)

2009-10-09 Thread Paul Bivand
Hi

You may find that you need to use the compilation tools. I gave up on
using R from Mandriva repositories as the R base is usually out of
date and the selection of packages available depends on the interests
of those who produced them. If I knew how rpm spec files worked I
might do something about it for my interests.

Of course if the package is simply R code with no C, C++, Fortran
needing compiling, then unpacking the source in your library location
will do, though you may need to check dependencies.

I do like Mandriva, but for programs like R using install.packages()
and having the relevant devel-packages enables you to keep up to date.

Paul Bivand

2009/10/3 chi ball c...@hotmail.it:



 Hi, I'm not able to find a rpm of gregmisc library (2.0.0)  for Linux 
 Mandriva 2008 Spring.
 Any suggestion?
 Thanks

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Re: [R] different time series in one plot

2009-10-09 Thread Giovanni Petris

 Date: Fri, 09 Oct 2009 18:18:05 +0200
 From: Tomas Lanczos lanc...@fns.uniba.sk
 Sender: r-help-boun...@r-project.org
 Precedence: list
 
 Hello,
 
 I need to put 2 or more different time series to one plot for comparison
 each other. The problem is that the time series are irregular, moreover
 the time lenghts and periods are not the same. Is there a way to manage
 it in R?

The function plot(), maybe...?

You need to have both series in a single mts object. Look also at the
argument plot.type...

HTH,
Giovanni

 
 Many thanks for any hint and advice in advance
 
 Tomas
 
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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
 
 

-- 

Giovanni Petris  gpet...@uark.edu
Associate Professor
Department of Mathematical Sciences
University of Arkansas - Fayetteville, AR 72701
Ph: (479) 575-6324, 575-8630 (fax)
http://definetti.uark.edu/~gpetris/

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[R] How to get last status change, ctime on Windows?

2009-10-09 Thread johannes rara
Hi,

file.info is producing data.frame with ctime variable. Help file says
that on Unix this is 'last status change' and on Windows 'creation
time'. Is there a way to get 'last status change' on Windows using
some R function?

Thanks,
Johannes

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[R] plot the same types of graphics on the same R graphic device

2009-10-09 Thread carol white
Hi,
How to plot the same types of graphics on the same R graphic device? Suppose 
that we want to plot a vector y against x (using plot for instance). How is it 
possible to plot y against x for different values of these two vectors on the 
same device so that the plots could be compared?

Cheers,

Carol



  
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[R] lm output

2009-10-09 Thread Brecknock, Peter
Hi All

I am running a linear regression using the lm object.

In the event that my independent variable is the same across all
observations the regression slope is returned as an NA.

For example, if I have the following 

y=c(10,12,17)
x=c(5,5,5)

lm = lm(y~x)
produces the following 

Coefficients:
(Intercept)x  
  13   NA  

Other than post-processing the results, is there a way to output the
slope as 0 rather than NA?

Thanks

Pete 


This e-mail may contain confidential or proprietary information
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Re: [R] lm output

2009-10-09 Thread Daniel Malter
That comes out as an NA because X'X is not invertible because it is not full
rank (one row/column is a linear combination of the other(s)). And that
means there is no unique solution to the system.

y=c(10,12,17)
x=c(5,5,5)
X=cbind(1,x)

X
t(X)%*%X
solve(t(X)%*%X)

Therefore, nope, there is now way to make this come out as a zero, because
it fails the very assumptions of regression analysis.

HTH,
Daniel

-
cuncta stricte discussurus
-

-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von Brecknock, Peter
Gesendet: Friday, October 09, 2009 5:12 PM
An: r-help@r-project.org
Betreff: [R] lm output

Hi All

I am running a linear regression using the lm object.

In the event that my independent variable is the same across all
observations the regression slope is returned as an NA.

For example, if I have the following 

y=c(10,12,17)
x=c(5,5,5)

lm = lm(y~x)
produces the following 

Coefficients:
(Intercept)x  
  13   NA  

Other than post-processing the results, is there a way to output the slope
as 0 rather than NA?

Thanks

Pete 


This e-mail may contain confidential or proprietary information belonging to
the BP group and is intended only for the use of the recipients named above.
If you are not the intended recipient, please immediately notify the sender
and either delete this email or return to the sender immediately.  You may
not review, copy or distribute this email.  Within the bounds of law, this
part of BP retains all emails and IMs and may monitor them to ensure
compliance with BP's internal policies and for other legitimate business
purposes.


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Re: [R] lm output

2009-10-09 Thread Ted Harding
On 09-Oct-09 21:12:18, Brecknock, Peter wrote:
 Hi All
 I am running a linear regression using the lm object.
 
 In the event that my independent variable is the same across all
 observations the regression slope is returned as an NA.
 
 For example, if I have the following 
 
 y=c(10,12,17)
 x=c(5,5,5)
 
 lm = lm(y~x)
 produces the following 
 
 Coefficients:
 (Intercept)x  
   13   NA  
 
 Other than post-processing the results, is there a way to output the
 slope as 0 rather than NA?
 
 Thanks
 Pete

You should post-process! To incorporate such a thing into the
function lm() itself would be an arbitrary resolution of an
indeterminate situation, and would not be appropriate for a
general-purpose function. Your situation is, graphically,


17 +*
   |
15 +
   |
   |
12 +*
   |
10 +*
   |
   |
   |
   |
 5 +++
   0510

Any line whatever through the point (5,13) will fit the three
points as well as any other, so the slope is indeterminate.[*]
You have decided that you would like it to be zero, but that
is an arbitrary decision!

[*] Note that a vertical line (with slope +/- Inf) does not
resolve the indeterminacy, since, although it goes through all
three points, you do not know which point[s] on the line to
use in evaluating the error -- the difference between a point
on the line with given value of x and the y-value on the line
corresponding to x -- because all points on the line qualify
as potential y values, since they all have the same value of x.

Since the slope is indeterminate, it is NA (that is what NA means).
It arises numerically because the calculation of the slope is

  (N*sum(x*y) - sum(x)*sum(y))/(N*sum(x^2) - sum(x)^2)

which is 0/0 -- likewise NA.

Hoping this helps,
Ted.


E-Mail: (Ted Harding) ted.hard...@manchester.ac.uk
Fax-to-email: +44 (0)870 094 0861
Date: 09-Oct-09   Time: 22:41:37
-- XFMail --

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Re: [R] lm output

2009-10-09 Thread Brecknock, Peter
Daniel

Thanks very much for the reply. 

If the data fails the underlying assumptions of regression wouldn't it make 
sense to suppress all the output and not just the slope coefficient?

Incidently, if I run this simple example in Excel it returns the slope as 0. 
Intuitively, this makes sense to me ... the best estimate of y would be its 
mean for any value of x.

Kind regards

Pete


-Original Message-
From: Daniel Malter [mailto:dan...@umd.edu] 
Sent: Friday, October 09, 2009 4:24 PM
To: Brecknock, Peter; r-help@r-project.org
Subject: AW: [R] lm output

That comes out as an NA because X'X is not invertible because it is not full
rank (one row/column is a linear combination of the other(s)). And that
means there is no unique solution to the system.

y=c(10,12,17)
x=c(5,5,5)
X=cbind(1,x)

X
t(X)%*%X
solve(t(X)%*%X)

Therefore, nope, there is now way to make this come out as a zero, because
it fails the very assumptions of regression analysis.

HTH,
Daniel

-
cuncta stricte discussurus
-

-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von Brecknock, Peter
Gesendet: Friday, October 09, 2009 5:12 PM
An: r-help@r-project.org
Betreff: [R] lm output

Hi All

I am running a linear regression using the lm object.

In the event that my independent variable is the same across all
observations the regression slope is returned as an NA.

For example, if I have the following 

y=c(10,12,17)
x=c(5,5,5)

lm = lm(y~x)
produces the following 

Coefficients:
(Intercept)x  
  13   NA  

Other than post-processing the results, is there a way to output the slope
as 0 rather than NA?

Thanks

Pete 


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the BP group and is intended only for the use of the recipients named above.
If you are not the intended recipient, please immediately notify the sender
and either delete this email or return to the sender immediately.  You may
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Re: [R] lm output

2009-10-09 Thread Ted Harding
On 09-Oct-09 21:45:04, Brecknock, Peter wrote:
 Daniel
 Thanks very much for the reply. 
 
 If the data fails the underlying assumptions of regression wouldn't it
 make sense to suppress all the output and not just the slope
 coefficient?
 
 Incidently, if I run this simple example in Excel it returns the slope
 as 0.

So much the worse for Excel -- not the first time Excel has been
found to produce nonsense!

 Intuitively, this makes sense to me ... the best estimate of y
 would be its mean for any value of x.

On the contrary -- your data give you no information whatever
about the value of y at any value of x other than x=5. So, given
your data, if you want to predict the value of y for some other
value of x, you can choose whatever value you like -- hence the
indeterminate slope. And this is where the statement made by Excel
is grossly misleading: telling you that the slope is 0 would make
you adopt the same value (mean(y) = 13) for any value of x, and
you have no basis whatever for doing so.

Ted.

 
 Kind regards
 Pete



 -Original Message-
 From: Daniel Malter [mailto:dan...@umd.edu] 
 Sent: Friday, October 09, 2009 4:24 PM
 To: Brecknock, Peter; r-help@r-project.org
 Subject: AW: [R] lm output
 
 That comes out as an NA because X'X is not invertible because it is not
 full
 rank (one row/column is a linear combination of the other(s)). And that
 means there is no unique solution to the system.
 
 y=c(10,12,17)
 x=c(5,5,5)
 X=cbind(1,x)
 
 X
 t(X)%*%X
 solve(t(X)%*%X)
 
 Therefore, nope, there is now way to make this come out as a zero,
 because it fails the very assumptions of regression analysis.
 
 HTH,
 Daniel
 
 -
 cuncta stricte discussurus
 -
 
 -Ursprüngliche Nachricht-
 Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
 Im
 Auftrag von Brecknock, Peter
 Gesendet: Friday, October 09, 2009 5:12 PM
 An: r-help@r-project.org
 Betreff: [R] lm output
 
 Hi All
 
 I am running a linear regression using the lm object.
 
 In the event that my independent variable is the same across all
 observations the regression slope is returned as an NA.
 
 For example, if I have the following 
 
 y=c(10,12,17)
 x=c(5,5,5)
 
 lm = lm(y~x)
 produces the following 
 
 Coefficients:
 (Intercept)x  
   13   NA  
 
 Other than post-processing the results, is there a way to output the
 slope
 as 0 rather than NA?
 
 Thanks
 
 Pete 
 
 
 This e-mail may contain confidential or proprietary information
 belonging to
 the BP group and is intended only for the use of the recipients named
 above.
 If you are not the intended recipient, please immediately notify the
 sender
 and either delete this email or return to the sender immediately.  You
 may
 not review, copy or distribute this email.  Within the bounds of law,
 this
 part of BP retains all emails and IMs and may monitor them to ensure
 compliance with BP's internal policies and for other legitimate
 business
 purposes.
 
 
   [[alternative HTML version deleted]]
 
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E-Mail: (Ted Harding) ted.hard...@manchester.ac.uk
Fax-to-email: +44 (0)870 094 0861
Date: 09-Oct-09   Time: 23:00:09
-- XFMail --

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Re: [R] plot the same types of graphics on the same R graphic device

2009-10-09 Thread John Kane
?lines
?points

Something like :

x - 1:10
y1 - rnorm(10, 4, 3)
y2 - rnorm(5,5,2)

ymax - max(c(y1,y2))
ymin - min(c(y1,y2))


plot(x, y1, col='red',ylim = c(ymin,ymax))
lines(y2, col='green')



--- On Fri, 10/9/09, carol white wht_...@yahoo.com wrote:

 From: carol white wht_...@yahoo.com
 Subject: [R] plot the same types of graphics on the same R graphic device
 To: r-h...@stat.math.ethz.ch
 Received: Friday, October 9, 2009, 5:10 PM
 Hi,
 How to plot the same types of graphics on the same R
 graphic device? Suppose that we want to plot a vector y
 against x (using plot for instance). How is it possible to
 plot y against x for different values of these two vectors
 on the same device so that the plots could be compared?
 
 Cheers,
 
 Carol
 
 
 
       
     [[alternative HTML version deleted]]
 
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 mailing list
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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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 reproducible code.
 


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Re: [R] lm output

2009-10-09 Thread David Winsemius


On Oct 9, 2009, at 5:45 PM, Brecknock, Peter wrote:


Daniel

Thanks very much for the reply.

If the data fails the underlying assumptions of regression wouldn't  
it make sense to suppress all the output and not just the slope  
coefficient?


Incidently, if I run this simple example in Excel it returns the  
slope as 0. Intuitively, this makes sense to me ... the best  
estimate of y would be its mean for any value of x.


R gave you the best estimate for y. It was Excel that gave you an  
estimate for something for which it had no basis. There is no mean of  
dy/dx because dx=0.


--
David.


Kind regards

Pete


-Original Message-
From: Daniel Malter [mailto:dan...@umd.edu]
Sent: Friday, October 09, 2009 4:24 PM
To: Brecknock, Peter; r-help@r-project.org
Subject: AW: [R] lm output

That comes out as an NA because X'X is not invertible because it is  
not full
rank (one row/column is a linear combination of the other(s)). And  
that

means there is no unique solution to the system.

y=c(10,12,17)
x=c(5,5,5)
X=cbind(1,x)

X
t(X)%*%X
solve(t(X)%*%X)

Therefore, nope, there is now way to make this come out as a zero,  
because

it fails the very assumptions of regression analysis.

HTH,
Daniel

-
cuncta stricte discussurus
-

-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r- 
project.org] Im

Auftrag von Brecknock, Peter
Gesendet: Friday, October 09, 2009 5:12 PM
An: r-help@r-project.org
Betreff: [R] lm output

Hi All

I am running a linear regression using the lm object.

In the event that my independent variable is the same across all
observations the regression slope is returned as an NA.

For example, if I have the following

y=c(10,12,17)
x=c(5,5,5)

lm = lm(y~x)
produces the following

Coefficients:
(Intercept)x
 13   NA

Other than post-processing the results, is there a way to output the  
slope

as 0 rather than NA?

Thanks

Pete


This e-mail may contain confidential or proprietary information  
belonging to
the BP group and is intended only for the use of the recipients  
named above.
If you are not the intended recipient, please immediately notify the  
sender
and either delete this email or return to the sender immediately.   
You may
not review, copy or distribute this email.  Within the bounds of  
law, this

part of BP retains all emails and IMs and may monitor them to ensure
compliance with BP's internal policies and for other legitimate  
business

purposes.


[[alternative HTML version deleted]]

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David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] lm output

2009-10-09 Thread Brecknock, Peter
Fair point. 

Thanks.

-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net] 
Sent: Friday, October 09, 2009 5:02 PM
To: Brecknock, Peter
Cc: Daniel Malter; r-help@r-project.org
Subject: Re: [R] lm output


On Oct 9, 2009, at 5:45 PM, Brecknock, Peter wrote:

 Daniel

 Thanks very much for the reply.

 If the data fails the underlying assumptions of regression wouldn't  
 it make sense to suppress all the output and not just the slope  
 coefficient?

 Incidently, if I run this simple example in Excel it returns the  
 slope as 0. Intuitively, this makes sense to me ... the best  
 estimate of y would be its mean for any value of x.

R gave you the best estimate for y. It was Excel that gave you an  
estimate for something for which it had no basis. There is no mean of  
dy/dx because dx=0.

-- 
David.

 Kind regards

 Pete


 -Original Message-
 From: Daniel Malter [mailto:dan...@umd.edu]
 Sent: Friday, October 09, 2009 4:24 PM
 To: Brecknock, Peter; r-help@r-project.org
 Subject: AW: [R] lm output

 That comes out as an NA because X'X is not invertible because it is  
 not full
 rank (one row/column is a linear combination of the other(s)). And  
 that
 means there is no unique solution to the system.

 y=c(10,12,17)
 x=c(5,5,5)
 X=cbind(1,x)

 X
 t(X)%*%X
 solve(t(X)%*%X)

 Therefore, nope, there is now way to make this come out as a zero,  
 because
 it fails the very assumptions of regression analysis.

 HTH,
 Daniel

 -
 cuncta stricte discussurus
 -

 -Ursprüngliche Nachricht-
 Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r- 
 project.org] Im
 Auftrag von Brecknock, Peter
 Gesendet: Friday, October 09, 2009 5:12 PM
 An: r-help@r-project.org
 Betreff: [R] lm output

 Hi All

 I am running a linear regression using the lm object.

 In the event that my independent variable is the same across all
 observations the regression slope is returned as an NA.

 For example, if I have the following

 y=c(10,12,17)
 x=c(5,5,5)

 lm = lm(y~x)
 produces the following

 Coefficients:
 (Intercept)x
  13   NA

 Other than post-processing the results, is there a way to output the  
 slope
 as 0 rather than NA?

 Thanks

 Pete


 This e-mail may contain confidential or proprietary information  
 belonging to
 the BP group and is intended only for the use of the recipients  
 named above.
 If you are not the intended recipient, please immediately notify the  
 sender
 and either delete this email or return to the sender immediately.   
 You may
 not review, copy or distribute this email.  Within the bounds of  
 law, this
 part of BP retains all emails and IMs and may monitor them to ensure
 compliance with BP's internal policies and for other legitimate  
 business
 purposes.


   [[alternative HTML version deleted]]

 __
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 and provide commented, minimal, self-contained, reproducible code.

 __
 R-help@r-project.org mailing list
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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] plot the same types of graphics on the same R graphic device

2009-10-09 Thread Sarah Goslee
Hi Carol,

It isn't at all clear exactly what you are trying to do, but you might want to
read the help for either points() and lines() [to put more than one data pair
on a single plot], or for par, specifically mfrow and mfcol, or for layout [to
put more than one plot on a single device window].

If none of those do it, then try again with a more detailed description of what
you are looking for.

Sarah

On Fri, Oct 9, 2009 at 5:10 PM, carol white wht_...@yahoo.com wrote:
 Hi,
 How to plot the same types of graphics on the same R graphic device? Suppose 
 that we want to plot a vector y against x (using plot for instance). How is 
 it possible to plot y against x for different values of these two vectors on 
 the same device so that the plots could be compared?

 Cheers,

 Carol




-- 
Sarah Goslee
http://www.functionaldiversity.org

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Re: [R] How to get last status change, ctime on Windows?

2009-10-09 Thread Duncan Murdoch

On 09/10/2009 5:05 PM, johannes rara wrote:

Hi,

file.info is producing data.frame with ctime variable. Help file says
that on Unix this is 'last status change' and on Windows 'creation
time'. Is there a way to get 'last status change' on Windows using
some R function?


What does last status change mean on Windows?  mtime is the last 
modification time; is that good enough?  If mtime isn't what you want, 
describe some other way in Windows to get what you do want.  You can't 
get something that the OS doesn't maintain.


Duncan Murdoch

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[R] user input in R

2009-10-09 Thread Sharon Beckett
 I'm just learning R (I don't know any other programming languages),
   and I have a question. I am trying to figure out how to ask for user
   input (say, a set of 3 numbers) then put those numbers into an array.
   I've looked around, but I haven't been able to find any answers that I
   understand.
   Thanks!

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[R] regressions on large dataframe: speed?

2009-10-09 Thread Georg Ehret
Dear R Helpers,
   I have a pretty large dataframe (150,000 variables, 10,000 entries for
each) and have to run a regression on each of the variables. Recorded are
the pvals.
 I wrote a function and use sapply. The function looks something like this:
calcpval-function(x){
modela - lm(apples~age,data=m)
modelb - lm(apples~age+ageSquared,data=m)
modelc - lm(apples~age+ageSquared+bmi,data=m)
p_main - anova(modela,modelb)$P[2]
p_main_i - anova(modela,modelc)$P[2]
p_i - anova(modelb,modelc)$P[2]
return(c(p_main,p_main_i,p_i))
}

This whole thing is terribly slow... I observed that it's faster when
breaking down the file. But other suggestions could you please make to make
it run faster (say days instead of weeks).
Thank you and best regards, Georg.
*
Georg Ehret, Johns Hopkins Medicine

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Re: [R] user input in R

2009-10-09 Thread David Winsemius


On Oct 9, 2009, at 6:36 PM, Sharon Beckett wrote:


I'm just learning R (I don't know any other programming languages),
  and I have a question. I am trying to figure out how to ask for user
  input (say, a set of 3 numbers) then put those numbers into an  
array.
  I've looked around, but I haven't been able to find any answers  
that I

  understand.
  Thanks!

I am guessing that your version of looking around did not include  
going to r-search and typing in user input because when you do, you  
quite a bit:


http://search.r-project.org/cgi-bin/namazu.cgi?query=%22user+input%22max=100result=normalsort=scoreidxname=functionsidxname=Rhelp08idxname=views

You could also try this at the console:

??input

Or even

??user input

Althought the last one does not give you very much, it still has a  
link to readline in the first offered hit on my system.


Also possible would be to install package sos and then try:

???user input

... which in this case gives you way too many hits.


--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] odfWeave XML error in post-processing

2009-10-09 Thread Rob James

Just so we complete (partially) the web-record...

Some further hunting determined that  the apos  was an  apostrophe - 
obvious only in retrospect!  Removal of this character has resolved the 
Entity errors, but not the xmlParseStartTag: invalid element name errors.


I had assumed that the two errors were dependent, but they are not.

odfWeave does have some ability with its translate command to address 
some XML/OO special characters, but I have not explored this facet of 
odfWeave yet, and I was a bit surprised that the use of this common 
grammatical mark generated an error, but..


Now, in search of a cause for the invalid element name error(s).

Thanks to Duncan for his help.



Duncan Temple Lang wrote:

Hi Rob.

Without the file content_1.xml or any information
from the R call stack (e.g. options(error = recover)
and then run the command and dynamically explore the
state of affairs when the error occurs), there is
no way for us to know what the problem might be.

Somehow, the XML parser appears to be seeing a
 token
and token is not a legitimate XML element name. It may also be
seeing apos; which would identify an XML entity.

Assuming that this is what the XML parser is seeing,
the question is how they got into the document.

So we need more to start diagnosing the problem.

  D.

Rob James wrote:
  

I've been happily building a file with odfWeave, and just as the hour
draws nigh for it to be sent off, odfWeave or XML throws  the following
catastrophic error:


...this is the tail of entirely uneventful processing of input file.

31 : term xml(label=LR_Fall_Model_Results)
 32 : term verbatim(label=LR_Model_Fall_graph)
 33 : term xml(label=LR_OMC_tab)

'content_1.xml' has been Sweaved

Removing content.xml

Post-processing the contents
xmlParseStartTag: invalid element name
Entity 'apos' not defined
Entity 'apos' not defined


This triplet of errors XMLParse, and duplicate Entity lines is
reported several times, then XML or odfWeave  packs up its toys, and
goes home without an output file.

I'd (desperately) love any insights anyone might have.

Thanks,

Rob

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Re: [R] Satellite ocean color palette?

2009-10-09 Thread Pedro Mardones
tim.colors() in library fields

On Fri, Oct 9, 2009 at 2:51 PM, Tim Clark mudiver1...@yahoo.com wrote:
 Dear List,

 Is there a color palette avaliable similar to what is used in satellite ocean 
 color imagery?  I.e. a gradient with blue on one end and red on the other, 
 with yellow in the middle?  I have tried topo.colors(n) but that comes out 
 more yellow on the end.  I am looking for something similar to what is found 
 on the CoastWatch web page:

 http://oceanwatch.pifsc.noaa.gov/imagery/GA2009281_2009282_sst_2D_eddy.jpg

 Thanks!

 Tim


 Tim Clark
 Department of Zoology
 University of Hawaii

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Re: [R] Creating a Clustered-Stacked Column Chart

2009-10-09 Thread zhijie zhang
Thanks a lot. Maybe someone else has the method to solve that.


2009/10/9 John Kane jrkrid...@yahoo.ca

 I don't think I've seen an R version, probably because the technique is not
 very good for displaying data.

 Have a look at http://chartsgraphs.wordpress.com/tag/r-and-excel/ for an
 alternative method of displaying the data using lattice.

 --- On Fri, 10/9/09, zhijie zhang rusers...@gmail.com wrote:

  From: zhijie zhang rusers...@gmail.com
  Subject: [R] Creating a Clustered-Stacked Column Chart
  To: r-h...@stat.math.ethz.ch
  Received: Friday, October 9, 2009, 5:31 AM
Hi all,
 In R, is there some functions or ways to
  create a Clustered-Stacked
  Column Chart as the example in the following page
  http://peltiertech.com/Excel/ChartsHowTo/ClusterStack.html?
I have browsed the R Graph Gallery (
 http://addictedtor.free.fr/graphiques/)
  and searched the R site, and didnot find an appropriate
  method to do it.
Anybody has met this problem before?
Thanks a lot.
 
  [[alternative HTML version deleted]]
 
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[R] Fwd: Creating a Clustered-Stacked Column Chart

2009-10-09 Thread Khanh Nguyen
-- Forwarded message --
From: Khanh Nguyen kngu...@cs.umb.edu
Date: Fri, Oct 9, 2009 at 10:10 PM
Subject: Re: [R] Creating a Clustered-Stacked Column Chart
To: zhijie zhang rusers...@gmail.com


May be you can try to look into ggplot2

http://had.co.nz/ggplot2/position_fill.html

-k


On Fri, Oct 9, 2009 at 9:57 PM, zhijie zhang rusers...@gmail.com wrote:

 Thanks a lot. Maybe someone else has the method to solve that.


 2009/10/9 John Kane jrkrid...@yahoo.ca

  I don't think I've seen an R version, probably because the technique is
 not
  very good for displaying data.
 
  Have a look at http://chartsgraphs.wordpress.com/tag/r-and-excel/ for an
  alternative method of displaying the data using lattice.
 
  --- On Fri, 10/9/09, zhijie zhang rusers...@gmail.com wrote:
 
   From: zhijie zhang rusers...@gmail.com
   Subject: [R] Creating a Clustered-Stacked Column Chart
   To: r-h...@stat.math.ethz.ch
   Received: Friday, October 9, 2009, 5:31 AM
 Hi all,
  In R, is there some functions or ways to
   create a Clustered-Stacked
   Column Chart as the example in the following page
   http://peltiertech.com/Excel/ChartsHowTo/ClusterStack.html?
 I have browsed the R Graph Gallery (
  http://addictedtor.free.fr/graphiques/)
   and searched the R site, and didnot find an appropriate
   method to do it.
 Anybody has met this problem before?
 Thanks a lot.
  
   [[alternative HTML version deleted]]
  
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 http://www.r-project.org/posting-guide.html
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Re: [R] Creating a Clustered-Stacked Column Chart

2009-10-09 Thread David Winsemius

library(lattice)
barchart(Titanic, scales = list(x = free),
  auto.key = list(title = Survived))

Or if you prefer vertical:

barchart(Titanic, scales = list(x = free),
 auto.key = list(title = Survived), horizontal=FALSE)

There are adjustments available to the space between bars.

barchart(Titanic, scales = list(x = free),
 auto.key = list(title = Survived), horizontal=FALSE,  
box.ratio=100)



On Oct 9, 2009, at 9:57 PM, zhijie zhang wrote:


Thanks a lot. Maybe someone else has the method to solve that.


2009/10/9 John Kane jrkrid...@yahoo.ca

I don't think I've seen an R version, probably because the  
technique is not

very good for displaying data.

Have a look at http://chartsgraphs.wordpress.com/tag/r-and-excel/  
for an

alternative method of displaying the data using lattice.

--- On Fri, 10/9/09, zhijie zhang rusers...@gmail.com wrote:


From: zhijie zhang rusers...@gmail.com
Subject: [R] Creating a Clustered-Stacked Column Chart
To: r-h...@stat.math.ethz.ch
Received: Friday, October 9, 2009, 5:31 AM
Hi all,
  In R, is there some functions or ways to
create a Clustered-Stacked
Column Chart as the example in the following page
http://peltiertech.com/Excel/ChartsHowTo/ClusterStack.html?
 I have browsed the R Graph Gallery (

http://addictedtor.free.fr/graphiques/)

and searched the R site, and didnot find an appropriate
method to do it.
 Anybody has met this problem before?
 Thanks a lot.

   [[alternative HTML version deleted]]

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and provide commented, minimal, self-contained,
reproducible code.




 
__
Get the name you've always wanted @ymail.com or @rocketmail.com! Go  
to

http://ca.promos.yahoo.com/jacko/



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David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] Help with printing fixed width

2009-10-09 Thread Jim Lemon

On 10/09/2009 11:36 PM, sahil seth wrote:

Hello R users,
I am writing a summary() for a custom class, and am to display the integers
right justified,
Say where x is the vector with integers, I am using the following:
cat(\t,format(x),\t...other columns)

this way I am trying to pass the format(x), to the cat function to display
it,
but still I am getting a kink(b/w the 9th and 10th row).
6  81  170  251  1.998026e-08
7  26  93  119  4.937587e-10
8  96  209  305  8.750939e-11
9  94  211  305  1.758285e-11
  10  88  205  293  6.47853e-12
  11  82  244  326  7.943691e-20
  12  57  145  202  4.964509e-10
Thanks,
   

HI Sahil,
The kink is due to the fact that each row is being formatted 
separately. You may notice that there is a kink in row 7 as well, due to 
the same problem. What you may want to do is use formatC instead of 
format like this:


cat(formatC(x,width=10),...,rep( ,6),last number,\n,sep=)

Jim

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Re: [R] lm output

2009-10-09 Thread Daniel Malter
No, actually it does better to not suppress all output, because it tells you
where the trouble comes from by just showing the NA for the slope. The
intercept the regression gives you is the mean of y in this case. As for the
slope, Ted's graphic is illustrative as to why no slope can be estimated.
Overall, I would say the output makes sense.

Daniel

-
cuncta stricte discussurus
-

-Ursprüngliche Nachricht-
Von: Brecknock, Peter [mailto:peter.breckn...@bp.com] 
Gesendet: Friday, October 09, 2009 5:45 PM
An: Daniel Malter; r-help@r-project.org
Betreff: RE: [R] lm output

Daniel

Thanks very much for the reply. 

If the data fails the underlying assumptions of regression wouldn't it make
sense to suppress all the output and not just the slope coefficient?

Incidently, if I run this simple example in Excel it returns the slope as 0.
Intuitively, this makes sense to me ... the best estimate of y would be its
mean for any value of x.

Kind regards

Pete


-Original Message-
From: Daniel Malter [mailto:dan...@umd.edu]
Sent: Friday, October 09, 2009 4:24 PM
To: Brecknock, Peter; r-help@r-project.org
Subject: AW: [R] lm output

That comes out as an NA because X'X is not invertible because it is not full
rank (one row/column is a linear combination of the other(s)). And that
means there is no unique solution to the system.

y=c(10,12,17)
x=c(5,5,5)
X=cbind(1,x)

X
t(X)%*%X
solve(t(X)%*%X)

Therefore, nope, there is now way to make this come out as a zero, because
it fails the very assumptions of regression analysis.

HTH,
Daniel

-
cuncta stricte discussurus
-

-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von Brecknock, Peter
Gesendet: Friday, October 09, 2009 5:12 PM
An: r-help@r-project.org
Betreff: [R] lm output

Hi All

I am running a linear regression using the lm object.

In the event that my independent variable is the same across all
observations the regression slope is returned as an NA.

For example, if I have the following 

y=c(10,12,17)
x=c(5,5,5)

lm = lm(y~x)
produces the following 

Coefficients:
(Intercept)x  
  13   NA  

Other than post-processing the results, is there a way to output the slope
as 0 rather than NA?

Thanks

Pete 


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[R] Running R scripts from a GUI interface

2009-10-09 Thread Jason Rupert
It appears several that of my scripts are beginning to reaching maturity, so I 
am curious if it is possible to add an external GUI to run the scripts from 
this simplified GUI interface.  

The scripts are fairly rudimentary so the GUI only needs a few radial buttons 
and a could of numeric fields.  

I am curious if there is a typical approach for developing a GUI to run R 
scripts or to export R scripts in a DLL or other format so that they can be run 
from such a GUI. 

I also have not settled on a GUI development language so any suggestions there 
are also very much appreciated.  

Thank you again for any feedback and insights, especially if there is a blog or 
book that covers these topics.

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Re: [R] How to get last status change, ctime on Windows?

2009-10-09 Thread Prof Brian Ripley

On Fri, 9 Oct 2009, Duncan Murdoch wrote:


On 09/10/2009 5:05 PM, johannes rara wrote:

Hi,

file.info is producing data.frame with ctime variable. Help file says
that on Unix this is 'last status change' and on Windows 'creation
time'.


No, that is not what it says.  It actually says

 What is meant by the three file times depends on the OS and file
 system.  On Windows 'ctime' is the creation time.

The POSIX standard 1003 uses these terms, and its definitions are at
http://www.opengroup.org/onlinepubs/009695399/basedefs/xbd_chap04.html#tag_04_07
but of course Windows does not claim to be POSIX-compliant.

So the help page is answering Duncan's question


What does last status change mean on Windows?


by saying that on Windows 'last status change' means 'creation time'.

Unix-alikes differ in what they say about ctime, but for example Linux says

   The field st_ctime is changed by writing or by setting inode
   information (i.e., owner, group, link count, mode, etc.).

Windows does not have inodes nor most of those concepts ... so we need 
to look at what its system documentation (MSDN) says it returns in the 
field st_ctime of its 'stat' system call.  Other sources suggest that 
MSDN is wrong and st_ctime returns 'creation time' only on Windows' 
native file systems: but that possibility is covered by the two 
sentences quoted.


--
Brian D. Ripley,  rip...@stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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