Re: [R] simple main effect.
Try going through this: http://www.personality-project.org/r/r.anova.html http://www.personality-project.org/r/r.anova.html Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sat, Dec 19, 2009 at 7:27 PM, Or Duek ord...@gmail.com wrote: Hi, I'm a bit new to R and I would like to know how can I compare simple main effects when using the aov function. I'm doing a mixed model ANOVA with two between subjects variables and one within. When I get an interaction of two of the variables I don't know how to check for simple main effect of that interaction (A at B1 and A at B2 for example). The aov function is very simple but for some reason I can't find how to do this. Thank you very much. Or Duek. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] read.table: mysterious line omissions
Jonathan wrote: Tried deleting several line above and below line 362; did that and changed the extension. Still finds the same number of rows (362). Strange! Jonathan The reason is quite apparent if you try page(temp) Ovine lentivirus, Peanut chlorotic streak virus, Pelargonium vein banding virus, Petunia vein clearing virus, Porcine endogenous retrovirus, RD114 retrovirus, Reticuloendotheliosis virus, Rice tungro bacilliform virus, Rosss goose hepatitis B virus\tNC_005888\nSnow goose hepatitis B virus\tNC_005950\nRous sarcoma virus\tNC_001407\nRudbeckia flower distortion virus\tNC_011920\nSheldgoose hepatitis B virus\tNC_005890\nSimian T-cell lymphotropic virus 6\tNC_011546\nSimian T-lymphotropic . The single quote in Ross's is doing you in. Try adding quote=. -- O__ Peter Dalgaard Øster Farimagsgade 5, Entr.B c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~ - (p.dalga...@biostat.ku.dk) FAX: (+45) 35327907 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] utf8 postscript cyrillic
Dear R users, I am running R version 2.10.0 (2009-10-26). I need to prepare an eps graphic with a legend with cyrillic words. I tried setting the encoding parameter of the postscript command, but in vain, nothing seems to work. I tried with CP1251, KOI8-R, UTF-8 and Cyrillic (UTF-8 turned out to not be available under /usr/lib/R/library/grDevices/enc). All I get is in the final inscription. Has someone been successful in producing postscript legends with cyrillic words and how? Is the encoding the only thing to be tweaked? I would be glad if you share your experience. Regards, Martin __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] utf8 postscript cyrillic
'Nothing seems to work' is not at all helpful, and you seem under the misconception that PostScript supports UTF-8 (sic): life would be much easier for device writers if it did. The postscript() help page says More details of font families and encodings and especially handling text in a non-Latin-1 encoding and embedding fonts can be found in Paul Murrell and Brian Ripley (2006) Non-standard fonts in PostScript and PDF graphics. _R News_, 6(2):41-47. URL: http://cran.r-project.org/doc/Rnews/Rnews_2006-2.pdf. which shows Cyrillic examples. We can write documentation for you, but you have to read it for yourself On Sun, 20 Dec 2009, Martin Ivanov wrote: Dear R users, I am running R version 2.10.0 (2009-10-26). I need to prepare an eps graphic with a legend with cyrillic words. I tried setting the encoding parameter of the postscript command, but in vain, nothing seems to work. I tried with CP1251, KOI8-R, UTF-8 and Cyrillic (UTF-8 turned out to not be available under /usr/lib/R/library/grDevices/enc). All I get is in the final inscription. Has someone been successful in producing postscript legends with cyrillic words and how? Is the encoding the only thing to be tweaked? I would be glad if you share your experience. Regards, Martin -- Brian D. Ripley, rip...@stats.ox.ac.uk Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UKFax: +44 1865 272595 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] how to create three new variables? Thanks a lot!
Dear R experts: I have following data structure: student id, exam time and score. I want to create three new columes: 1 st before, 2nd before and 3rd before. For example, for student 1's 4th exam score is assumed to be influenced by his previous three cloest scores, which are 6, 9, and 10 in that order. For student 2's 5th exam score is assumed to be inflenced by her previous cloest three scores, which are 10, 10 and 8 in that order. Note that for student 1, his first time score 10 can not be influenced by other scores, thus has three empties in the three new columes. for student 1, his second score 9 is only influenced by his first score thus has two empties in the columes of 2nd before and 3rd before. Now I only have 3 columes: id, time and score, and I want to create three new columes: 1st before, 2nd before and 3rd before. How can I do that? Thanks a lot. Best Jay id timescore 1st before 2nd before 3rd before 1 1 10 1 2 9 10 1 3 6 9 10 1 4 10 6 9 10 1 5 5 10 6 9 2 1 7 2 2 8 7 2 3 10 8 7 2 4 10 10 8 7 2 5 5 10 10 8 2 6 9 5 10 10 [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
Thanks. But there is no simple main effect there. On Sun, Dec 20, 2009 at 10:00 AM, Tal Galili tal.gal...@gmail.com wrote: Try going through this: http://www.personality-project.org/r/r.anova.html http://www.personality-project.org/r/r.anova.html Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sat, Dec 19, 2009 at 7:27 PM, Or Duek ord...@gmail.com wrote: Hi, I'm a bit new to R and I would like to know how can I compare simple main effects when using the aov function. I'm doing a mixed model ANOVA with two between subjects variables and one within. When I get an interaction of two of the variables I don't know how to check for simple main effect of that interaction (A at B1 and A at B2 for example). The aov function is very simple but for some reason I can't find how to do this. Thank you very much. Or Duek. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to count the total number of (INCLUDING overlapping) occurrences of a substring within a string?
Use a zero lookaround expression. It will not consume its match. See ?regexp
gregexpr(a(?=a), aaa, perl = TRUE)
[[1]]
[1] 1 2
attr(,match.length)
[1] 1 1
On Sun, Dec 20, 2009 at 1:43 AM, Jonathan jonsle...@gmail.com wrote:
Last one for you guys:
The command:
length(gregexpr('cus','hocus pocus')[[1]])
[1] 2
returns the number of times the substring 'cus' appears in 'hocus pocus'
(which is two)
It's returning the number of **disjoint** matches. So:
length(gregexpr('aa','aaa')[[1]])
[1] 1
returns 1.
**What I want to do:**
I'm looking for a way to count all occurrences of the substring, including
overlapping sets (so 'aa' would be found in 'aaa' two times, because the
middle 'a' gets counted twice).
Any ideas would be much appreciated!!
Signing off and thanks for all the great assistance,
Jonathan
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to count the total number of (INCLUDING overlapping) occurrences of a substring within a string?
On Sun, Dec 20, 2009 at 5:33 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
Use a zero lookaround expression. It will not consume its match. See ?regexp
That should be lookahead, not lookaround.
gregexpr(a(?=a), aaa, perl = TRUE)
[[1]]
[1] 1 2
attr(,match.length)
[1] 1 1
On Sun, Dec 20, 2009 at 1:43 AM, Jonathan jonsle...@gmail.com wrote:
Last one for you guys:
The command:
length(gregexpr('cus','hocus pocus')[[1]])
[1] 2
returns the number of times the substring 'cus' appears in 'hocus pocus'
(which is two)
It's returning the number of **disjoint** matches. So:
length(gregexpr('aa','aaa')[[1]])
[1] 1
returns 1.
**What I want to do:**
I'm looking for a way to count all occurrences of the substring, including
overlapping sets (so 'aa' would be found in 'aaa' two times, because the
middle 'a' gets counted twice).
Any ideas would be much appreciated!!
Signing off and thanks for all the great assistance,
Jonathan
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Res: how to create three new variables? Thanks a lot!
Hello! Here is a way: mydata - data.frame(third_before=c(6,10), second_before=c(9,10), first_before=c(10,8)) mydata third_before second_before first_before 1 6 9 10 2 10 10 8 And if you already have a dataset and wants only to create three more columns, create the 3 variables independently and use cbind: third_before=c(6,10) second_before=c(9,10) first_before=c(10,8) cbind(your.dataset, third_before, second_before, first_before) Hope this helps, All the best! Rafael De: jie feng jiefeng...@gmail.com Para: R-help@r-project.org Enviadas: Domingo, 20 de Dezembro de 2009 6:34:20 [[elided Yahoo spam]] Dear R experts: I have following data structure: student id, exam time and score. I want to create three new columes: 1 st before, 2nd before and 3rd before. For example, for student 1's 4th exam score is assumed to be influenced by his previous three cloest scores, which are 6, 9, and 10 in that order. For student 2's 5th exam score is assumed to be inflenced by her previous cloest three scores, which are 10, 10 and 8 in that order. Note that for student 1, his first time score 10 can not be influenced by other scores, thus has three empties in the three new columes. for student 1, his second score 9 is only influenced by his first score thus has two empties in the columes of 2nd before and 3rd before. Now I only have 3 columes: id, time and score, and I want to create three new columes: 1st before, 2nd before and 3rd before. How can I do that? Thanks a lot. Best Jay id time score 1st before 2nd before 3rd before 1 1 10 1 2 9 10 1 3 6 9 10 1 4 10 6 9 10 1 5 5 10 6 9 2 1 7 2 2 8 7 2 3 10 8 7 2 4 10 10 8 7 2 5 5 10 10 8 2 6 9 5 10 10 [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[elided Yahoo spam]] [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to count the total number of (INCLUDING overl apping) occurrences of a substring within a string ?
Gabor Grothendieck ggrothendieck at gmail.com writes:
Use a zero lookaround expression. It will not consume its match. See ?regexp
gregexpr(a(?=a), aaa, perl = TRUE)
[[1]]
[1] 1 2
attr(,match.length)
[1] 1 1
I wonder how you would count the number of occurrences of, for example,
'aba' or 'a.a' (*) in the string ababacababab using simple lookahead?
In Perl, there is a modifier '/g' to do that, and in Python one could
apply the function 'findall'.
When I had this task, I wrote a small function findall(), see below, but
I would be glad to see a solution with lookahead only.
Regards
Hans Werner
(*) or anything more complex
findall - function(apat, atxt) {
stopifnot(length(apat) == 1, length(atxt) == 1)
pos - c() # positions of matches
i - 1; n - nchar(atxt)
found - regexpr(apat, substr(atxt, i, n), perl=TRUE)
while (found 0) {
pos - c(pos, i + found - 1)
i - i + found
found - regexpr(apat, substr(atxt, i, n), perl=TRUE)
}
return(pos)
}
On Sun, Dec 20, 2009 at 1:43 AM, Jonathan jonsleepy at gmail.com wrote:
Last one for you guys:
The command:
length(gregexpr('cus','hocus pocus')[[1]])
[1] 2
returns the number of times the substring 'cus' appears in 'hocus pocus'
(which is two)
It's returning the number of **disjoint** matches. So:
length(gregexpr('aa','aaa')[[1]])
[1] 1
returns 1.
**What I want to do:**
I'm looking for a way to count all occurrences of the substring, including
overlapping sets (so 'aa' would be found in 'aaa' two times, because the
middle 'a' gets counted twice).
Any ideas would be much appreciated!!
Signing off and thanks for all the great assistance,
Jonathan
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to count the total number of (INCLUDING overlapping) occurrences of a substring within a string?
Try this:
findall(aba, ababacababab)
[1] 1 3 7 9
gregexpr(a(?=ba), ababacababab, perl = TRUE)
[[1]]
[1] 1 3 7 9
attr(,match.length)
[1] 1 1 1 1
findall(a.a, ababacababab)
[1] 1 3 5 7 9
gregexpr(a(?=.a), ababacababab, perl = TRUE)
[[1]]
[1] 1 3 5 7 9
attr(,match.length)
[1] 1 1 1 1 1
On Sun, Dec 20, 2009 at 7:22 AM, Hans W Borchers
hwborch...@googlemail.com wrote:
Gabor Grothendieck ggrothendieck at gmail.com writes:
Use a zero lookaround expression. It will not consume its match. See
?regexp
gregexpr(a(?=a), aaa, perl = TRUE)
[[1]]
[1] 1 2
attr(,match.length)
[1] 1 1
I wonder how you would count the number of occurrences of, for example,
'aba' or 'a.a' (*) in the string ababacababab using simple lookahead?
In Perl, there is a modifier '/g' to do that, and in Python one could
apply the function 'findall'.
When I had this task, I wrote a small function findall(), see below, but
I would be glad to see a solution with lookahead only.
Regards
Hans Werner
(*) or anything more complex
findall - function(apat, atxt) {
stopifnot(length(apat) == 1, length(atxt) == 1)
pos - c() # positions of matches
i - 1; n - nchar(atxt)
found - regexpr(apat, substr(atxt, i, n), perl=TRUE)
while (found 0) {
pos - c(pos, i + found - 1)
i - i + found
found - regexpr(apat, substr(atxt, i, n), perl=TRUE)
}
return(pos)
}
On Sun, Dec 20, 2009 at 1:43 AM, Jonathan jonsleepy at gmail.com wrote:
Last one for you guys:
The command:
length(gregexpr('cus','hocus pocus')[[1]])
[1] 2
returns the number of times the substring 'cus' appears in 'hocus pocus'
(which is two)
It's returning the number of **disjoint** matches. So:
length(gregexpr('aa','aaa')[[1]])
[1] 1
returns 1.
**What I want to do:**
I'm looking for a way to count all occurrences of the substring, including
overlapping sets (so 'aa' would be found in 'aaa' two times, because the
middle 'a' gets counted twice).
Any ideas would be much appreciated!!
Signing off and thanks for all the great assistance,
Jonathan
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] read.table: mysterious line omissions
Most likely an unbalanced quote. put the following option in the
read.table:
quote='', comment.char=''
On Sat, Dec 19, 2009 at 11:42 PM, Jonathan jonsle...@gmail.com wrote:
Hello again,
I am simply trying to import a rectangular table of strings. The
table's dimensions are 1990 x 2, yet my read.table() command can only find
362 of the rows (and they're not the first 362). I would've taken the time
to figure out how to use scan, readLines, or some other tool that can read
in character strings, and then parse and input to a table, but that seems
like overkill, and probably it would be good to understand what's wrong
with
my text file.
The file is here.
https://regtransfers-sth-se.diino.com/download/jonsleepy/_mydropbox_/finalInput.xls
The code is here:
temp - as.matrix(read.table('finalInput.xls', header=FALSE, sep = \t))
dim(temp) #expect 1990 x 2; but find 362 x 2
Sorry to require a download (this probably won't make people happy), but
since my problem is file-specific, the file is needed for troubleshooting.
I generated it with some grep, gawk commands using Cygwin in a Windows
environment (though subsequently converted it to Windows format - R loads
it
exactly the same way, regardless of whether it's in linux or windows
format)
Regards,
Jonathan
[[alternative HTML version deleted]]
__
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
[[alternative HTML version deleted]]
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
Hi Or, Maybe I didn't understand you. Are you asking how can I read the output of a fitted (complex within and between) model for finding the simple main effect ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 11:56 AM, Or Duek ord...@gmail.com wrote: Thanks. But there is no simple main effect there. On Sun, Dec 20, 2009 at 10:00 AM, Tal Galili tal.gal...@gmail.com wrote: Try going through this: http://www.personality-project.org/r/r.anova.html http://www.personality-project.org/r/r.anova.html Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sat, Dec 19, 2009 at 7:27 PM, Or Duek ord...@gmail.com wrote: Hi, I'm a bit new to R and I would like to know how can I compare simple main effects when using the aov function. I'm doing a mixed model ANOVA with two between subjects variables and one within. When I get an interaction of two of the variables I don't know how to check for simple main effect of that interaction (A at B1 and A at B2 for example). The aov function is very simple but for some reason I can't find how to do this. Thank you very much. Or Duek. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
I don't think so. I'm asking how can I see/analyse the simple main effect. I don't think it shows in the summary report of the aov() function. On Sun, Dec 20, 2009 at 3:35 PM, Tal Galili tal.gal...@gmail.com wrote: Hi Or, Maybe I didn't understand you. Are you asking how can I read the output of a fitted (complex within and between) model for finding the simple main effect ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 11:56 AM, Or Duek ord...@gmail.com wrote: Thanks. But there is no simple main effect there. On Sun, Dec 20, 2009 at 10:00 AM, Tal Galili tal.gal...@gmail.comwrote: Try going through this: http://www.personality-project.org/r/r.anova.html http://www.personality-project.org/r/r.anova.html Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sat, Dec 19, 2009 at 7:27 PM, Or Duek ord...@gmail.com wrote: Hi, I'm a bit new to R and I would like to know how can I compare simple main effects when using the aov function. I'm doing a mixed model ANOVA with two between subjects variables and one within. When I get an interaction of two of the variables I don't know how to check for simple main effect of that interaction (A at B1 and A at B2 for example). The aov function is very simple but for some reason I can't find how to do this. Thank you very much. Or Duek. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to create three new variables? Thanks a lot!
On Dec 20, 2009, at 4:34 AM, jie feng wrote: Dear R experts: I have following data structure: student id, exam time and score. I want to create three new columes: 1 st before, 2nd before and 3rd before. For example, for student 1's 4th exam score is assumed to be influenced by his previous three cloest scores, which are 6, 9, and 10 in that order. For student 2's 5th exam score is assumed to be inflenced by her previous cloest three scores, which are 10, 10 and 8 in that order. Note that for student 1, his first time score 10 can not be influenced by other scores, thus has three empties in the three new columes. for student 1, his second score 9 is only influenced by his first score thus has two empties in the columes of 2nd before and 3rd before. Now I only have 3 columes: id, time and score, and I want to create three new columes: 1st before, 2nd before and 3rd before. How can I do that? Thanks a lot. The combination of your choice of text editors and your use of HTML mail format (contrary to the Posting Guide ... please read it more carefully) has completely mangled your posting of the data. As a result it is not possible for ordinary humans to figure out what your starting point really is. It's possible that the answer lies in the help page for lag: ?lag Future postings on this matter ought to include the data in parse-able R format (also described in the Posting Guide.) Best Jay id timescore 1st before 2nd before 3rd before 1 1 10 1 2 9 10 1 3 6 9 10 1 4 10 6 9 10 1 5 5 10 6 9 2 1 7 2 2 8 7 2 3 10 8 7 2 4 10 10 8 7 2 5 5 10 10 8 2 6 9 5 10 10 http://www.R-project.org/posting-guide.html -- David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
Could you please write the aov formula you are using ? Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 3:36 PM, Or Duek ord...@gmail.com wrote: I don't think so. I'm asking how can I see/analyse the simple main effect. I don't think it shows in the summary report of the aov() function. On Sun, Dec 20, 2009 at 3:35 PM, Tal Galili tal.gal...@gmail.com wrote: Hi Or, Maybe I didn't understand you. Are you asking how can I read the output of a fitted (complex within and between) model for finding the simple main effect ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 11:56 AM, Or Duek ord...@gmail.com wrote: Thanks. But there is no simple main effect there. On Sun, Dec 20, 2009 at 10:00 AM, Tal Galili tal.gal...@gmail.comwrote: Try going through this: http://www.personality-project.org/r/r.anova.html http://www.personality-project.org/r/r.anova.html Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sat, Dec 19, 2009 at 7:27 PM, Or Duek ord...@gmail.com wrote: Hi, I'm a bit new to R and I would like to know how can I compare simple main effects when using the aov function. I'm doing a mixed model ANOVA with two between subjects variables and one within. When I get an interaction of two of the variables I don't know how to check for simple main effect of that interaction (A at B1 and A at B2 for example). The aov function is very simple but for some reason I can't find how to do this. Thank you very much. Or Duek. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
No problem. If I have a mixed model with A as within subject (A is exposure, has 2 levels) and drug(2 levels between subject) and strain(2 levels between subject). I reshape the data to fit the R aov() function. thus instead of looking like this: subjectdrug strain exposure_1 exposure2 1 1 1 34 25 22 1 26 22 etc. it looks like this: subject drug strain exposure dependent 1 1 1 1 34 1 1 1 2 25 etc. and the I do: aov(dependent~(exposure*strain*drug) + Error(subject/exposure) + (drug*strain), data) Thank you very much for your help. Or. On Sun, Dec 20, 2009 at 4:18 PM, Tal Galili tal.gal...@gmail.com wrote: Could you please write the aov formula you are using ? Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 3:36 PM, Or Duek ord...@gmail.com wrote: I don't think so. I'm asking how can I see/analyse the simple main effect. I don't think it shows in the summary report of the aov() function. On Sun, Dec 20, 2009 at 3:35 PM, Tal Galili tal.gal...@gmail.com wrote: Hi Or, Maybe I didn't understand you. Are you asking how can I read the output of a fitted (complex within and between) model for finding the simple main effect ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 11:56 AM, Or Duek ord...@gmail.com wrote: Thanks. But there is no simple main effect there. On Sun, Dec 20, 2009 at 10:00 AM, Tal Galili tal.gal...@gmail.comwrote: Try going through this: http://www.personality-project.org/r/r.anova.html http://www.personality-project.org/r/r.anova.html Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sat, Dec 19, 2009 at 7:27 PM, Or Duek ord...@gmail.com wrote: Hi, I'm a bit new to R and I would like to know how can I compare simple main effects when using the aov function. I'm doing a mixed model ANOVA with two between subjects variables and one within. When I get an interaction of two of the variables I don't know how to check for simple main effect of that interaction (A at B1 and A at B2 for example). The aov function is very simple but for some reason I can't find how to do this. Thank you very much. Or Duek. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to count the total number of (INCLUDING overl apping) occurrences of a substring within a string ?
Gabor Grothendieck ggrothendieck at gmail.com writes:
Try this:
findall(aba, ababacababab)
[1] 1 3 7 9
gregexpr(a(?=ba), ababacababab, perl = TRUE)
[[1]]
[1] 1 3 7 9
attr(,match.length)
[1] 1 1 1 1
findall(a.a, ababacababab)
[1] 1 3 5 7 9
gregexpr(a(?=.a), ababacababab, perl = TRUE)
[[1]]
[1] 1 3 5 7 9
attr(,match.length)
[1] 1 1 1 1 1
Thanks --- somehow I did not realize that the expression in ?=...
can also be regular.
My original problem was to find all three character matches where the
first and the last one are the same. With findall() it works like:
findall((.).\\1, ababacababab)
# [1] 1 2 3 5 7 8 9 10
I am still not able to reproduce this with lookahead. Attempts with
gregexpr((.)?=.\\1, ababacababab, perl = TRUE)
do not work as the lookahead expression apparently does not know about
the captured group from before.
Regards
Hans Werner
Correction: I meant the '\G' metacharacter in Perl, not a modifier.
On Sun, Dec 20, 2009 at 7:22 AM, Hans W Borchers
hwborchers at googlemail.com wrote:
Gabor Grothendieck ggrothendieck at gmail.com writes:
[Sorry; Gmane forces me to delete more quoted text.]
findall - function(apat, atxt) {
stopifnot(length(apat) == 1, length(atxt) == 1)
pos - c() # positions of matches
i - 1; n - nchar(atxt)
found - regexpr(apat, substr(atxt, i, n), perl=TRUE)
while (found 0) {
pos - c(pos, i + found - 1)
i - i + found
found - regexpr(apat, substr(atxt, i, n), perl=TRUE)
}
return(pos)
}
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to count the total number of (INCLUDING overlapping) occurrences of a substring within a string?
Try this:
findall((.).\\1, ababacababab)
[1] 1 2 3 5 7 8 9 10
gregexpr((.)(?=.\\1), ababacababab, perl = TRUE)
[[1]]
[1] 1 2 3 5 7 8 9 10
attr(,match.length)
[1] 1 1 1 1 1 1 1 1
On Sun, Dec 20, 2009 at 9:33 AM, Hans W Borchers
hwborch...@googlemail.com wrote:
Gabor Grothendieck ggrothendieck at gmail.com writes:
Try this:
findall(aba, ababacababab)
[1] 1 3 7 9
gregexpr(a(?=ba), ababacababab, perl = TRUE)
[[1]]
[1] 1 3 7 9
attr(,match.length)
[1] 1 1 1 1
findall(a.a, ababacababab)
[1] 1 3 5 7 9
gregexpr(a(?=.a), ababacababab, perl = TRUE)
[[1]]
[1] 1 3 5 7 9
attr(,match.length)
[1] 1 1 1 1 1
Thanks --- somehow I did not realize that the expression in ?=...
can also be regular.
My original problem was to find all three character matches where the
first and the last one are the same. With findall() it works like:
findall((.).\\1, ababacababab)
# [1] 1 2 3 5 7 8 9 10
I am still not able to reproduce this with lookahead. Attempts with
gregexpr((.)?=.\\1, ababacababab, perl = TRUE)
do not work as the lookahead expression apparently does not know about
the captured group from before.
Regards
Hans Werner
Correction: I meant the '\G' metacharacter in Perl, not a modifier.
On Sun, Dec 20, 2009 at 7:22 AM, Hans W Borchers
hwborchers at googlemail.com wrote:
Gabor Grothendieck ggrothendieck at gmail.com writes:
[Sorry; Gmane forces me to delete more quoted text.]
findall - function(apat, atxt) {
stopifnot(length(apat) == 1, length(atxt) == 1)
pos - c() # positions of matches
i - 1; n - nchar(atxt)
found - regexpr(apat, substr(atxt, i, n), perl=TRUE)
while (found 0) {
pos - c(pos, i + found - 1)
i - i + found
found - regexpr(apat, substr(atxt, i, n), perl=TRUE)
}
return(pos)
}
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Problem reading binaries created with fortran
Duncan Murdoch helped me sort it out last Friday. Thanks to all who responded. On Fri, Dec 18, 2009 at 11:20 AM, Don MacQueen m...@llnl.gov wrote: However, source code is available at http://water.usgs.gov/nrp/gwsoftware/modflow2005/modflow2005.html so it would seem that the details are available. -Don At 4:35 PM -0500 12/17/09, kapo coulibaly wrote: Duncan, I couldn't find clear details about the way fortran writes the binaries. I was hoping someone here has done it before. But the hexView package seems like a great idea i'll give it a shot. Thanks a bunch On Thu, Dec 17, 2009 at 4:02 PM, Duncan Murdoch murd...@stats.uwo.ca wrote: On 17/12/2009 3:48 PM, kapo coulibaly wrote: Is it possible to read fortran binaries with R? I tried unsucessfully and my understanding is that fortran write binaries with leading and trailing bytes. I get numbers but not the right ones. Thanks ps: the binary I'm interested in reading is a MODFLOW output with a mix of character, double and integers. One other thing: the hexView package does a very nice job of displaying the file, so you can work out what the structure is if the documentation is unclear (or nonexistent). Duncan Murdoch [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://*stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http:// *www.*R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- -- Don MacQueen Environmental Protection Department Lawrence Livermore National Laboratory Livermore, CA, USA 925-423-1062 -- [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
Thanks Or, So I am failing to understand, When you put that aov expression into the summary() Why isn't what you are getting what you need ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 4:30 PM, Or Duek ord...@gmail.com wrote: No problem. If I have a mixed model with A as within subject (A is exposure, has 2 levels) and drug(2 levels between subject) and strain(2 levels between subject). I reshape the data to fit the R aov() function. thus instead of looking like this: subjectdrug strain exposure_1 exposure2 1 1 1 34 25 22 1 26 22 etc. it looks like this: subject drug strain exposure dependent 1 1 1 1 34 1 1 1 2 25 etc. and the I do: aov(dependent~(exposure*strain*drug) + Error(subject/exposure) + (drug*strain), data) Thank you very much for your help. Or. On Sun, Dec 20, 2009 at 4:18 PM, Tal Galili tal.gal...@gmail.com wrote: Could you please write the aov formula you are using ? Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 3:36 PM, Or Duek ord...@gmail.com wrote: I don't think so. I'm asking how can I see/analyse the simple main effect. I don't think it shows in the summary report of the aov() function. On Sun, Dec 20, 2009 at 3:35 PM, Tal Galili tal.gal...@gmail.comwrote: Hi Or, Maybe I didn't understand you. Are you asking how can I read the output of a fitted (complex within and between) model for finding the simple main effect ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 11:56 AM, Or Duek ord...@gmail.com wrote: Thanks. But there is no simple main effect there. On Sun, Dec 20, 2009 at 10:00 AM, Tal Galili tal.gal...@gmail.comwrote: Try going through this: http://www.personality-project.org/r/r.anova.html http://www.personality-project.org/r/r.anova.html Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il(Hebrew) | www.r-statistics.com/ (English) -- On Sat, Dec 19, 2009 at 7:27 PM, Or Duek ord...@gmail.com wrote: Hi, I'm a bit new to R and I would like to know how can I compare simple main effects when using the aov function. I'm doing a mixed model ANOVA with two between subjects variables and one within. When I get an interaction of two of the variables I don't know how to check for simple main effect of that interaction (A at B1 and A at B2 for example). The aov function is very simple but for some reason I can't find how to do this. Thank you very much. Or Duek. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
Also, do you have any missing data ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 5:52 PM, Tal Galili tal.gal...@gmail.com wrote: Thanks Or, So I am failing to understand, When you put that aov expression into the summary() Why isn't what you are getting what you need ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 4:30 PM, Or Duek ord...@gmail.com wrote: No problem. If I have a mixed model with A as within subject (A is exposure, has 2 levels) and drug(2 levels between subject) and strain(2 levels between subject). I reshape the data to fit the R aov() function. thus instead of looking like this: subjectdrug strain exposure_1 exposure2 1 1 1 34 25 22 1 26 22 etc. it looks like this: subject drug strain exposure dependent 1 1 1 1 34 1 1 1 2 25 etc. and the I do: aov(dependent~(exposure*strain*drug) + Error(subject/exposure) + (drug*strain), data) Thank you very much for your help. Or. On Sun, Dec 20, 2009 at 4:18 PM, Tal Galili tal.gal...@gmail.com wrote: Could you please write the aov formula you are using ? Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 3:36 PM, Or Duek ord...@gmail.com wrote: I don't think so. I'm asking how can I see/analyse the simple main effect. I don't think it shows in the summary report of the aov() function. On Sun, Dec 20, 2009 at 3:35 PM, Tal Galili tal.gal...@gmail.comwrote: Hi Or, Maybe I didn't understand you. Are you asking how can I read the output of a fitted (complex within and between) model for finding the simple main effect ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 11:56 AM, Or Duek ord...@gmail.com wrote: Thanks. But there is no simple main effect there. On Sun, Dec 20, 2009 at 10:00 AM, Tal Galili tal.gal...@gmail.comwrote: Try going through this: http://www.personality-project.org/r/r.anova.html http://www.personality-project.org/r/r.anova.html Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il(Hebrew) | www.r-statistics.com/ (English) -- On Sat, Dec 19, 2009 at 7:27 PM, Or Duek ord...@gmail.com wrote: Hi, I'm a bit new to R and I would like to know how can I compare simple main effects when using the aov function. I'm doing a mixed model ANOVA with two between subjects variables and one within. When I get an interaction of two of the variables I don't know how to check for simple main effect of that interaction (A at B1 and A at B2 for example). The aov function is very simple but for some reason I can't find how to do this. Thank you very much. Or Duek. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
I don't have missing data. about what I need. Lets say the drug*strain interaction is significant - now I want to check for drug under the levels of strain - compare drug 1 and 2 only on strain 1 and then only on strain 2. Or I'd like to compare the strains under levels of exposure. This is the kind of data I fail to see in summary() but it is important to understand the interactions. thank you. On Sun, Dec 20, 2009 at 5:52 PM, Tal Galili tal.gal...@gmail.com wrote: Also, do you have any missing data ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 5:52 PM, Tal Galili tal.gal...@gmail.com wrote: Thanks Or, So I am failing to understand, When you put that aov expression into the summary() Why isn't what you are getting what you need ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 4:30 PM, Or Duek ord...@gmail.com wrote: No problem. If I have a mixed model with A as within subject (A is exposure, has 2 levels) and drug(2 levels between subject) and strain(2 levels between subject). I reshape the data to fit the R aov() function. thus instead of looking like this: subjectdrug strain exposure_1 exposure2 1 1 1 34 25 22 1 26 22 etc. it looks like this: subject drug strain exposure dependent 1 1 1 1 34 1 1 1 2 25 etc. and the I do: aov(dependent~(exposure*strain*drug) + Error(subject/exposure) + (drug*strain), data) Thank you very much for your help. Or. On Sun, Dec 20, 2009 at 4:18 PM, Tal Galili tal.gal...@gmail.comwrote: Could you please write the aov formula you are using ? Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 3:36 PM, Or Duek ord...@gmail.com wrote: I don't think so. I'm asking how can I see/analyse the simple main effect. I don't think it shows in the summary report of the aov() function. On Sun, Dec 20, 2009 at 3:35 PM, Tal Galili tal.gal...@gmail.comwrote: Hi Or, Maybe I didn't understand you. Are you asking how can I read the output of a fitted (complex within and between) model for finding the simple main effect ? Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il(Hebrew) | www.r-statistics.com/ (English) -- On Sun, Dec 20, 2009 at 11:56 AM, Or Duek ord...@gmail.com wrote: Thanks. But there is no simple main effect there. On Sun, Dec 20, 2009 at 10:00 AM, Tal Galili tal.gal...@gmail.comwrote: Try going through this: http://www.personality-project.org/r/r.anova.html http://www.personality-project.org/r/r.anova.html Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il(Hebrew) | www.r-statistics.com/ (English) -- On Sat, Dec 19, 2009 at 7:27 PM, Or Duek ord...@gmail.com wrote: Hi, I'm a bit new to R and I would like to know how can I compare simple main effects when using the aov function. I'm doing a mixed model ANOVA with two between subjects variables and one within. When I get an interaction of two of the variables I don't know how to check for simple main effect of that interaction (A at B1 and A at B2 for example). The aov function is very simple but for some reason I can't find how to do this. Thank you very much. Or Duek. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the
[R] expression()
Hi All, I'm wondering if its possible to write degree in symbol. I would like y-label as Temperature (degreeF). where degree should be in symbols. Thanks in advance, #R Code library(lattice) data(barley) barchart(yield ~ variety | site, data = barley, groups = year, layout = c(1,6), ylab = Temperature (degreeF), scales = list(x = list(abbreviate = TRUE, minlength = 5))) ~Kim Jung Hwa [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
On 12/20/2009 04:56 PM, Or Duek wrote: I don't have missing data. about what I need. Lets say the drug*strain interaction is significant - now I want to check for drug under the levels of strain - compare drug 1 and 2 only on strain 1 and then only on strain 2. Or I'd like to compare the strains under levels of exposure. This is the kind of data I fail to see in summary() but it is important to understand the interactions. thank you. Do you main pairwise multiple comparison tests like Tukey Honest Significant Difference tests? Then you could use TukeyHSD in the stats package or see the DTK package (Dunnett-Tukey-Kramer Pairwise Multiple Comparison Test Adjusted for Unequal Variances and Unequal Sample Sizes) Stephan __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] expression()
Hi, try this, ylab = expression(Temperature~(degree*F)) ?plotmath baptiste 2009/12/20 Kim Jung Hwa kimhwamaill...@gmail.com: Hi All, I'm wondering if its possible to write degree in symbol. I would like y-label as Temperature (degreeF). where degree should be in symbols. Thanks in advance, #R Code library(lattice) data(barley) barchart(yield ~ variety | site, data = barley, groups = year, layout = c(1,6), ylab = Temperature (degreeF), scales = list(x = list(abbreviate = TRUE, minlength = 5))) ~Kim Jung Hwa [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
For some reasion I wasn't able to use TukeyHSD - I think because I need to set the different levels under a second variable. Tukey only helps me when I have more than 2 levels of same variable. Thanl you. On Sun, Dec 20, 2009 at 6:32 PM, S Devriese sdmaill...@gmail.com wrote: On 12/20/2009 04:56 PM, Or Duek wrote: I don't have missing data. about what I need. Lets say the drug*strain interaction is significant - now I want to check for drug under the levels of strain - compare drug 1 and 2 only on strain 1 and then only on strain 2. Or I'd like to compare the strains under levels of exposure. This is the kind of data I fail to see in summary() but it is important to understand the interactions. thank you. Do you main pairwise multiple comparison tests like Tukey Honest Significant Difference tests? Then you could use TukeyHSD in the stats package or see the DTK package (Dunnett-Tukey-Kramer Pairwise Multiple Comparison Test Adjusted for Unequal Variances and Unequal Sample Sizes) Stephan [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] basic proto question
Dear list,
I made the following example of a proto object that contains some data
and a spline interpolation. I don't understand why test$predict()
fails with this error message:
Error: evaluation nested too deeply: infinite recursion / options(expressions=)?
Best regards,
baptiste
test - proto(source = data.frame(x=1:10, y=rnorm(10)),
raw = function(.){
data.frame(xx=.$source$x, yy=.$source$y)
},
spline = function(.){
with(.$raw(), smooth.spline(xx, yy))
},
predict = function(., range=NULL, n=100){
if(is.null(range))
range - range(.$raw()$xx)
x.fine - seq(from=range[1], to=range[2], length=n)
predict(.$spline(), x.fine)
}
)
test$source
test$raw()
test$spline() # OK so far
test$predict() # fails
sessionInfo()
R version 2.10.1 RC (2009-12-06 r50690)
i386-apple-darwin9.8.0
locale:
[1] en_GB.UTF-8/en_GB.UTF-8/C/C/en_GB.UTF-8/en_GB.UTF-8
attached base packages:
[1] grid tools stats graphics grDevices utils datasets
[8] methods base
other attached packages:
[1] lattice_0.17-26 ggplot2_0.8.5 digest_0.4.1reshape_0.8.3
[5] plyr_0.1.9 proto_0.3-8 constants_1.0 gtools_2.6.1
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] basic proto question
The free variables in a proto method are looked up in the object that
the method was defined in so by referencing predict within
test$predict you are referring back to test$predict whereas you mean
to refer to stats::predict. Change the line that calls predict to:
stats::predict(.$spline(), x.fine)
On Sun, Dec 20, 2009 at 11:49 AM, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Dear list,
I made the following example of a proto object that contains some data
and a spline interpolation. I don't understand why test$predict()
fails with this error message:
Error: evaluation nested too deeply: infinite recursion /
options(expressions=)?
Best regards,
baptiste
test - proto(source = data.frame(x=1:10, y=rnorm(10)),
raw = function(.){
data.frame(xx=.$source$x, yy=.$source$y)
},
spline = function(.){
with(.$raw(), smooth.spline(xx, yy))
},
predict = function(., range=NULL, n=100){
if(is.null(range))
range - range(.$raw()$xx)
x.fine - seq(from=range[1], to=range[2], length=n)
predict(.$spline(), x.fine)
}
)
test$source
test$raw()
test$spline() # OK so far
test$predict() # fails
sessionInfo()
R version 2.10.1 RC (2009-12-06 r50690)
i386-apple-darwin9.8.0
locale:
[1] en_GB.UTF-8/en_GB.UTF-8/C/C/en_GB.UTF-8/en_GB.UTF-8
attached base packages:
[1] grid tools stats graphics grDevices utils datasets
[8] methods base
other attached packages:
[1] lattice_0.17-26 ggplot2_0.8.5 digest_0.4.1 reshape_0.8.3
[5] plyr_0.1.9 proto_0.3-8 constants_1.0 gtools_2.6.1
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] as.Date question
All! This piece of code: zzz1 - as.POSIXct(1999-03-18, tz=CET) zzz2 - as.POSIXlt(1999-03-18, tz=CET) zzz1 == zzz2 as.Date(zzz1) as.Date(zzz2) yields TRUE for zzz1==zzz2, but the two dates returned by as.Date are different: as.Date(zzz1) [1] 1999-03-17 as.Date(zzz2) [1] 1999-03-18 I'm using R 2.10.0. Would be glad for any clarifications. Thanks! [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
Hi Or, I understand your question (and am not sure what the confusion is about actually). Just like you said, you want to know the effect of A at B=1, and the effect of A at B=2. In this case, you want to know if drug has a significant effect for those with strain one, and whether drug has a significant effect for those with strain two. So the good part is, I understand the question. The bad part is that unfortunately I don't know how to do it with aov(). Also, I'm not a stats guru and could easily be wrong about the following advice. You've been warned! If you didn't have a mixed model, I would tell you to run the model using lm() twice, setting drug = 1 as the reference group the first time, and drug = 2 as the reference group the second time, but this won't work in your case. The best I can offer is a suggestion to run the model separately for each level of drug. Note that you can and should use the error term from the overall model though -- you will have to do this by hand (just divide MS_effect from the subset model by MS_error from the full model, and evaluate using df_error from the overall model). So basically, I'm suggesting that you do Data.drug1 - subset(Data, drug == 1) aov.model.drug.1 - aov(dependent~(exposure*strain) + Error(subject/exposure) + (strain), data=Data.drug1) summary(aov.model.drug.1) Data.drug2 - subset(Data, drug == 2) aov.model.drug.2 - aov(dependent~(exposure*strain) + Error(subject/exposure) + (strain), data=Data.drug2) summary(aov.model.drug.2) Good luck! -Ista On Sun, Dec 20, 2009 at 11:35 AM, Or Duek ord...@gmail.com wrote: For some reasion I wasn't able to use TukeyHSD - I think because I need to set the different levels under a second variable. Tukey only helps me when I have more than 2 levels of same variable. Thanl you. On Sun, Dec 20, 2009 at 6:32 PM, S Devriese sdmaill...@gmail.com wrote: On 12/20/2009 04:56 PM, Or Duek wrote: I don't have missing data. about what I need. Lets say the drug*strain interaction is significant - now I want to check for drug under the levels of strain - compare drug 1 and 2 only on strain 1 and then only on strain 2. Or I'd like to compare the strains under levels of exposure. This is the kind of data I fail to see in summary() but it is important to understand the interactions. thank you. Do you main pairwise multiple comparison tests like Tukey Honest Significant Difference tests? Then you could use TukeyHSD in the stats package or see the DTK package (Dunnett-Tukey-Kramer Pairwise Multiple Comparison Test Adjusted for Unequal Variances and Unequal Sample Sizes) Stephan [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Ista Zahn Graduate student University of Rochester Department of Clinical and Social Psychology http://yourpsyche.org __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Problem with sequence in loop
Hi all,
I've got a list of files from 1914 to 2000. For each file, I can call the
read.table function as follows.
file - read.table(1914.txt)
But I want to make a script so that at the end of the loop, the script selects
the file 1915.txt, 1916.txt and so on.
I've used seq() to create the increment
seq - paste(seq(1914, 2006, by=1), *.txt.h, sep=.)
But it didn't work.
Below is the script;
seq - paste(seq(1914, 2006, by=1), *.txt, sep=.)
for (i in 1:93){
list - list.files(~/ukcp09/txt/x.djf, seq)
file - lapply(list, read.table)
mean - (Reduce(+, file))/3
}
When I call
objects()
list
[1] 2006.01.txt.h 2006.02.txt.h 2006.12.txt.h
The listed files are the last files in the sequence.
Am I doing the loop correctly?
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom
Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974
Email: muhammad.ra...@ouce.ox.ac.uk
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] basic proto question
Thanks, it seems so obvious now!
baptiste
2009/12/20 Gabor Grothendieck ggrothendi...@gmail.com:
The free variables in a proto method are looked up in the object that
the method was defined in so by referencing predict within
test$predict you are referring back to test$predict whereas you mean
to refer to stats::predict. Change the line that calls predict to:
stats::predict(.$spline(), x.fine)
On Sun, Dec 20, 2009 at 11:49 AM, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Dear list,
I made the following example of a proto object that contains some data
and a spline interpolation. I don't understand why test$predict()
fails with this error message:
Error: evaluation nested too deeply: infinite recursion /
options(expressions=)?
Best regards,
baptiste
test - proto(source = data.frame(x=1:10, y=rnorm(10)),
raw = function(.){
data.frame(xx=.$source$x, yy=.$source$y)
},
spline = function(.){
with(.$raw(), smooth.spline(xx, yy))
},
predict = function(., range=NULL, n=100){
if(is.null(range))
range - range(.$raw()$xx)
x.fine - seq(from=range[1], to=range[2], length=n)
predict(.$spline(), x.fine)
}
)
test$source
test$raw()
test$spline() # OK so far
test$predict() # fails
sessionInfo()
R version 2.10.1 RC (2009-12-06 r50690)
i386-apple-darwin9.8.0
locale:
[1] en_GB.UTF-8/en_GB.UTF-8/C/C/en_GB.UTF-8/en_GB.UTF-8
attached base packages:
[1] grid tools stats graphics grDevices utils datasets
[8] methods base
other attached packages:
[1] lattice_0.17-26 ggplot2_0.8.5 digest_0.4.1 reshape_0.8.3
[5] plyr_0.1.9 proto_0.3-8 constants_1.0 gtools_2.6.1
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] as.Date question
Hello, On 2009.12.20 18:06:17, MAL wrote: All! This piece of code: zzz1 - as.POSIXct(1999-03-18, tz=CET) zzz2 - as.POSIXlt(1999-03-18, tz=CET) zzz1 == zzz2 as.Date(zzz1) as.Date(zzz2) yields TRUE for zzz1==zzz2, but the two dates returned by as.Date are different: as.Date(zzz1) [1] 1999-03-17 as.Date(zzz2) [1] 1999-03-18 I'm using R 2.10.0. Would be glad for any clarifications. Thanks! I don't know why as.Date() is giving different results, but if look at the value of the variables, they are equal: zzz1 - as.POSIXct(1999-03-18, tz=CET) zzz2 - as.POSIXlt(1999-03-18, tz=CET) zzz1 == zzz2 [1] TRUE as.Date(zzz1) [1] 1999-03-17 as.Date(zzz2) [1] 1999-03-18 zzz1 [1] 1999-03-18 CET zzz2 [1] 1999-03-18 CET Maybe someone here can explain the behavior of as.Date(). Cheers, ~Jason -- Jason W. Morgan Graduate Student Department of Political Science *The Ohio State University* 154 North Oval Mall Columbus, Ohio 43210 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] as.Date question
All! This piece of code: zzz1 - as.POSIXct(1999-03-18, tz=CET) zzz2 - as.POSIXlt(1999-03-18, tz=CET) zzz1 == zzz2 as.Date(zzz1) as.Date(zzz2) yields TRUE for zzz1==zzz2, but the two dates returned by as.Date are different: as.Date(zzz1) [1] 1999-03-17 as.Date(zzz2) [1] 1999-03-18 I'm using R 2.10.0. Would be glad for any clarifications. Thanks! __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
Thank you very much Ista. Can you please be a bit more specific as to using the overall error. I don't know how to actually do it in R. thank you, Or. On Sun, Dec 20, 2009 at 7:09 PM, Ista Zahn istaz...@gmail.com wrote: Hi Or, I understand your question (and am not sure what the confusion is about actually). Just like you said, you want to know the effect of A at B=1, and the effect of A at B=2. In this case, you want to know if drug has a significant effect for those with strain one, and whether drug has a significant effect for those with strain two. So the good part is, I understand the question. The bad part is that unfortunately I don't know how to do it with aov(). Also, I'm not a stats guru and could easily be wrong about the following advice. You've been warned! If you didn't have a mixed model, I would tell you to run the model using lm() twice, setting drug = 1 as the reference group the first time, and drug = 2 as the reference group the second time, but this won't work in your case. The best I can offer is a suggestion to run the model separately for each level of drug. Note that you can and should use the error term from the overall model though -- you will have to do this by hand (just divide MS_effect from the subset model by MS_error from the full model, and evaluate using df_error from the overall model). So basically, I'm suggesting that you do Data.drug1 - subset(Data, drug == 1) aov.model.drug.1 - aov(dependent~(exposure*strain) + Error(subject/exposure) + (strain), data=Data.drug1) summary(aov.model.drug.1) Data.drug2 - subset(Data, drug == 2) aov.model.drug.2 - aov(dependent~(exposure*strain) + Error(subject/exposure) + (strain), data=Data.drug2) summary(aov.model.drug.2) Good luck! -Ista On Sun, Dec 20, 2009 at 11:35 AM, Or Duek ord...@gmail.com wrote: For some reasion I wasn't able to use TukeyHSD - I think because I need to set the different levels under a second variable. Tukey only helps me when I have more than 2 levels of same variable. Thanl you. On Sun, Dec 20, 2009 at 6:32 PM, S Devriese sdmaill...@gmail.com wrote: On 12/20/2009 04:56 PM, Or Duek wrote: I don't have missing data. about what I need. Lets say the drug*strain interaction is significant - now I want to check for drug under the levels of strain - compare drug 1 and 2 only on strain 1 and then only on strain 2. Or I'd like to compare the strains under levels of exposure. This is the kind of data I fail to see in summary() but it is important to understand the interactions. thank you. Do you main pairwise multiple comparison tests like Tukey Honest Significant Difference tests? Then you could use TukeyHSD in the stats package or see the DTK package (Dunnett-Tukey-Kramer Pairwise Multiple Comparison Test Adjusted for Unequal Variances and Unequal Sample Sizes) Stephan [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Ista Zahn Graduate student University of Rochester Department of Clinical and Social Psychology http://yourpsyche.org [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Recall: Problem with sequence in loop
I recall the above problem. It works. Just error on my part in the file
output.
Here is the script that works.
-
seq - paste(seq(1914, 1916, by=1), *.y, sep=.)
for (i in 1:3){
list - list.files(~/ukcp09/txt/x.djf, seq[[i]])
file - lapply(list, read.table)
mean - (Reduce(+, file))
myfile1 - paste(strsplit(seq[[i]], \\.)[[1]][1], sum.txt, sep=.)
write.table(mean, file=myfile1, row.names=FALSE, col.names=FALSE)
}
-
Muhammad Rahiz wrote:
Hi all,
I've got a list of files from 1914 to 2000. For each file, I can call the
read.table function as follows.
file - read.table(1914.txt)
But I want to make a script so that at the end of the loop, the script selects
the file 1915.txt, 1916.txt and so on.
I've used seq() to create the increment
seq - paste(seq(1914, 2006, by=1), *.txt.h, sep=.)
But it didn't work.
Below is the script;
seq - paste(seq(1914, 2006, by=1), *.txt, sep=.)
for (i in 1:93){
list - list.files(~/ukcp09/txt/x.djf, seq)
file - lapply(list, read.table)
mean - (Reduce(+, file))/3
}
When I call
objects()
list
[1] 2006.01.txt.h 2006.02.txt.h 2006.12.txt.h
The listed files are the last files in the sequence.
Am I doing the loop correctly?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
Well, the F value is just MS_effect/MS_error. So you run the original model, run the subset models, but disregard the F values. To calculate the correct F values, divide MS_effect from the subset model by the MS_error term from the original (full) model. It's not really a matter of learning how to do it in R -- you're just doing simple division. -Ista On Sun, Dec 20, 2009 at 12:28 PM, Or Duek ord...@gmail.com wrote: Thank you very much Ista. Can you please be a bit more specific as to using the overall error. I don't know how to actually do it in R. thank you, Or. On Sun, Dec 20, 2009 at 7:09 PM, Ista Zahn istaz...@gmail.com wrote: Hi Or, I understand your question (and am not sure what the confusion is about actually). Just like you said, you want to know the effect of A at B=1, and the effect of A at B=2. In this case, you want to know if drug has a significant effect for those with strain one, and whether drug has a significant effect for those with strain two. So the good part is, I understand the question. The bad part is that unfortunately I don't know how to do it with aov(). Also, I'm not a stats guru and could easily be wrong about the following advice. You've been warned! If you didn't have a mixed model, I would tell you to run the model using lm() twice, setting drug = 1 as the reference group the first time, and drug = 2 as the reference group the second time, but this won't work in your case. The best I can offer is a suggestion to run the model separately for each level of drug. Note that you can and should use the error term from the overall model though -- you will have to do this by hand (just divide MS_effect from the subset model by MS_error from the full model, and evaluate using df_error from the overall model). So basically, I'm suggesting that you do Data.drug1 - subset(Data, drug == 1) aov.model.drug.1 - aov(dependent~(exposure*strain) + Error(subject/exposure) + (strain), data=Data.drug1) summary(aov.model.drug.1) Data.drug2 - subset(Data, drug == 2) aov.model.drug.2 - aov(dependent~(exposure*strain) + Error(subject/exposure) + (strain), data=Data.drug2) summary(aov.model.drug.2) Good luck! -Ista On Sun, Dec 20, 2009 at 11:35 AM, Or Duek ord...@gmail.com wrote: For some reasion I wasn't able to use TukeyHSD - I think because I need to set the different levels under a second variable. Tukey only helps me when I have more than 2 levels of same variable. Thanl you. On Sun, Dec 20, 2009 at 6:32 PM, S Devriese sdmaill...@gmail.com wrote: On 12/20/2009 04:56 PM, Or Duek wrote: I don't have missing data. about what I need. Lets say the drug*strain interaction is significant - now I want to check for drug under the levels of strain - compare drug 1 and 2 only on strain 1 and then only on strain 2. Or I'd like to compare the strains under levels of exposure. This is the kind of data I fail to see in summary() but it is important to understand the interactions. thank you. Do you main pairwise multiple comparison tests like Tukey Honest Significant Difference tests? Then you could use TukeyHSD in the stats package or see the DTK package (Dunnett-Tukey-Kramer Pairwise Multiple Comparison Test Adjusted for Unequal Variances and Unequal Sample Sizes) Stephan [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Ista Zahn Graduate student University of Rochester Department of Clinical and Social Psychology http://yourpsyche.org -- Ista Zahn Graduate student University of Rochester Department of Clinical and Social Psychology http://yourpsyche.org __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to rotate an axis?
Hi everybody, I'm trying to build a trilineare coordinate system with R. For that, I need to rotate an axis. Does anybody know, if it is possible to rotate an axis, created with the command axis(), about for instance 60 degrees? I'm looking foward to any ideas and hints and want to wish everybody a merry merry christmas. Thanks in advance. Etienne Stockhausen __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] plotting polynomial regression line
Dear All, I am trying to plot polynomial regression line to a scatterplot. I did following so far: x=c(1:9335) y=read.table(gp.txt,header=T,sep=\t) length(y$PCC) # y$PCC has values between 1 to 0 in decreasing order [1] 9335 plot(x,y$PCC,col=red) #scatterplot between x and y$PCC reg=lm(y$PCC~poly(x,6)) # calculating polynomial fit with degree 6 abline(reg,col=blue) Warning message: In abline(reg, col = blue) : only using the first two of 7regression coefficients After the above warning a line is drawn in the graph parallel to the y-axis. But I was expecting a curve line through the scatterplot. Am I doing something wrong? Please help! Best Amit __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to rotate an axis?
On 20.12.2009 19:06, Etienne Stockhausen wrote: Hi everybody, I'm trying to build a trilineare coordinate system with R. For that, I need to rotate an axis. Does anybody know, if it is possible to rotate an axis, created with the command axis(), about for instance 60 degrees? You cannot with base graphics. You could switch to the grid framework which allows such things. Best wishes, Uwe Ligges I'm looking foward to any ideas and hints and want to wish everybody a merry merry christmas. Thanks in advance. Etienne Stockhausen __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to rotate an axis?
On Dec 20, 2009, at 1:06 PM, Etienne Stockhausen wrote: Hi everybody, I'm trying to build a trilineare coordinate system with R. For that, I need to rotate an axis. Does anybody know, if it is possible to rotate an axis, created with the command axis(), about for instance 60 degrees? I'm looking foward to any ideas and hints and want to wish everybody a merry merry christmas. I think that answer about rotating what gets plotted by axis() is no, but perhaps you are unaware of the persp() or wireframe() functions in package:lattice or the facilities offer by package:rgl? Thanks in advance. Etienne Stockhausen David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] plotting polynomial regression line
On 20.12.2009 19:35, Amit wrote: Dear All, I am trying to plot polynomial regression line to a scatterplot. I did following so far: x=c(1:9335) y=read.table(gp.txt,header=T,sep=\t) length(y$PCC) # y$PCC has values between 1 to 0 in decreasing order [1] 9335 plot(x,y$PCC,col=red) #scatterplot between x and y$PCC reg=lm(y$PCC~poly(x,6)) # calculating polynomial fit with degree 6 abline(reg,col=blue) Warning message: In abline(reg, col = blue) : only using the first two of 7regression coefficients abline() draws straight lines. After the above warning a line is drawn in the graph parallel to the y-axis. But I was expecting a curve line through the scatterplot. Am I doing something wrong? Please help! You can predict() some points along your x values and connect them via lines(). Best wishes, Uwe Ligges Best Amit __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] plotting polynomial regression line
Hello Amit, On 2009.12.20 19:35:09, Amit wrote: Dear All, I am trying to plot polynomial regression line to a scatterplot. I did following so far: x=c(1:9335) y=read.table(gp.txt,header=T,sep=\t) length(y$PCC) # y$PCC has values between 1 to 0 in decreasing order [1] 9335 plot(x,y$PCC,col=red) #scatterplot between x and y$PCC reg=lm(y$PCC~poly(x,6)) # calculating polynomial fit with degree 6 abline(reg,col=blue) Warning message: In abline(reg, col = blue) : only using the first two of 7regression coefficients After the above warning a line is drawn in the graph parallel to the y-axis. But I was expecting a curve line through the scatterplot. Am I doing something wrong? Please help! Take a look at ?predict. Briefly, I think this will give you what you want: reg - lm(y$PCC ~ poly(x,6)) plot(x, y$PCC, col=red) lines(x, predict(reg), col=blue) Cheers, Jason -- Jason W. Morgan Graduate Student Department of Political Science *The Ohio State University* 154 North Oval Mall Columbus, Ohio 43210 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] birats example with R2WinBugs
On 18.12.2009 17:29, M JH wrote:
Hello,
I am trying, and failing, to do the birats example from the WinBugs manual
with R2Winbugs.
I can manage the rats example OK. Also, I can manage birats in WinBugs.
Here is the code I am running, the .bug program, and the error message. Any
help would be gratefully received.
Thank you,
Mike
library(R2WinBUGS)
data = list(x = c(8.0, 15.0, 22.0, 29.0, 36.0), N = 30, T = 5,
Omega = structure(.Data = c(200, 0, 0, 0.2), .Dim = c(2, 2)),
mean = c(0,0),
prec = structure(.Data = c(1.0E-6, 0, 0, 1.0E-6), .Dim = c(2,
2)),
Y = structure(
.Data = c(151, 199, 246, 283, 320,
145, 199, 249, 293,
354,
147, 214, 263, 312,
328,
155, 200, 237, 272,
297,
135, 188, 230, 280,
323,
159, 210, 252, 298,
331,
141, 189, 231, 275,
305,
159, 201, 248, 297,
338,
177, 236, 285, 350,
376,
134, 182, 220, 260,
296,
160, 208, 261, 313,
352,
143, 188, 220, 273,
314,
154, 200, 244, 289,
325,
171, 221, 270, 326,
358,
163, 216, 242, 281,
312,
160, 207, 248, 288,
324,
142, 187, 234, 280,
316,
156, 203, 243, 283,
317,
157, 212, 259, 307,
336,
152, 203, 246, 286,
321,
154, 205, 253, 298,
334,
139, 190, 225, 267,
302,
146, 191, 229, 272,
302,
157, 211, 250, 285,
323,
132, 185, 237, 286,
331,
160, 207, 257, 303,
345,
169, 216, 261, 295,
333,
157, 205, 248, 289,
316,
137, 180, 219, 258,
291,
153, 200, 244, 286,
324),
.Dim = c(30,5)))
inits- list(mu.beta = c(0,0), tauC = 1,
beta = structure(
.Data = c(100,6,100,6,100,6,100,6,100,6,
100,6,100,6,100,6,100,6,100,6,
100,6,100,6,100,6,100,6,100,6,
100,6,100,6,100,6,100,6,100,6,
100,6,100,6,100,6,100,6,100,6,
100,6,100,6,100,6,100,6,100,6),
.Dim = c(30, 2)),
R = structure(.Data = c(1,0,0,1), .Dim = c(2, 2)))
Although I do not know why you specify the inits in such an R-unlike
way, I know what is going wrong here. You could do as well after reading
?bugs:
inits must be a list of list(s), one list for each chain. You do not
have a list of lists but a list of the values, i.e. wrap the whole thing
in another list() and you are fine. That one will contain one list for
your one chain.
Uwe Ligges
names(inits)
inits$R
is.matrix(inits$beta)
is.matrix(inits$R)
mhbirats = bugs(data, inits, model.file = birats.bug,
parameters.to.save = c(beta, R, tauC, mu.beta),
n.chains = 1, n.iter=1, n.burnin=1000, n.thin=1,
bugs.directory = c:/Program Files/WinBUGS14/, debug = TRUE)
### birats example from winbugs
model
{
for( i in 1 : N ) {
beta[i , 1:2] ~ dmnorm(mu.beta[], R[ , ])
for( j in 1 : T ) {
Y[i , j] ~ dnorm(mu[i , j], tauC)
mu[i , j]- beta[i , 1] + beta[i , 2] * x[j]
Re: [R] plotting polynomial regression line
Amit, please provide gp.txt file. On Sun, Dec 20, 2009 at 1:47 PM, Jason Morgan jwm-r-h...@skepsi.net wrote: Hello Amit, On 2009.12.20 19:35:09, Amit wrote: Dear All, I am trying to plot polynomial regression line to a scatterplot. I did following so far: x=c(1:9335) y=read.table(gp.txt,header=T,sep=\t) length(y$PCC) # y$PCC has values between 1 to 0 in decreasing order [1] 9335 plot(x,y$PCC,col=red) #scatterplot between x and y$PCC reg=lm(y$PCC~poly(x,6)) # calculating polynomial fit with degree 6 abline(reg,col=blue) Warning message: In abline(reg, col = blue) : only using the first two of 7regression coefficients After the above warning a line is drawn in the graph parallel to the y-axis. But I was expecting a curve line through the scatterplot. Am I doing something wrong? Please help! Take a look at ?predict. Briefly, I think this will give you what you want: reg - lm(y$PCC ~ poly(x,6)) plot(x, y$PCC, col=red) lines(x, predict(reg), col=blue) Cheers, Jason -- Jason W. Morgan Graduate Student Department of Political Science *The Ohio State University* 154 North Oval Mall Columbus, Ohio 43210 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] plotting polynomial regression line
On Dec 20, 2009, at 1:35 PM, Amit wrote: Dear All, I am trying to plot polynomial regression line to a scatterplot. I did following so far: x=c(1:9335) y=read.table(gp.txt,header=T,sep=\t) length(y$PCC) # y$PCC has values between 1 to 0 in decreasing order [1] 9335 plot(x,y$PCC,col=red) #scatterplot between x and y$PCC reg=lm(y$PCC~poly(x,6)) # calculating polynomial fit with degree 6 abline(reg,col=blue) Warning message: In abline(reg, col = blue) : only using the first two of 7regression coefficients After the above warning a line is drawn in the graph parallel to the y-axis. But I was expecting a curve line through the scatterplot. Am I doing something wrong? Please help! abline is designed to draw lines of the form y=a+bx, ... hence the name. (And as documented on its help page for regression objects). An effective method would be with lines and predict: plot(cars, main=Stopping Distance versus Speed) lines(cars$speed, predict(lm(dist~poly(speed, 6) ,data=cars) ), col=red) Best Amit ___ David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] read.table: mysterious line omissions
Thanks everyone! The problem was definitely with the apostrophe being
interpreted as a single quote.
Jonathan
On Sun, Dec 20, 2009 at 7:49 AM, jim holtman jholt...@gmail.com wrote:
Most likely an unbalanced quote. put the following option in the
read.table:
quote='', comment.char=''
On Sat, Dec 19, 2009 at 11:42 PM, Jonathan jonsle...@gmail.com wrote:
Hello again,
I am simply trying to import a rectangular table of strings. The
table's dimensions are 1990 x 2, yet my read.table() command can only find
362 of the rows (and they're not the first 362). I would've taken the
time
to figure out how to use scan, readLines, or some other tool that can read
in character strings, and then parse and input to a table, but that seems
like overkill, and probably it would be good to understand what's wrong
with
my text file.
The file is here.
https://regtransfers-sth-se.diino.com/download/jonsleepy/_mydropbox_/finalInput.xls
The code is here:
temp - as.matrix(read.table('finalInput.xls', header=FALSE, sep = \t))
dim(temp) #expect 1990 x 2; but find 362 x 2
Sorry to require a download (this probably won't make people happy), but
since my problem is file-specific, the file is needed for troubleshooting.
I generated it with some grep, gawk commands using Cygwin in a Windows
environment (though subsequently converted it to Windows format - R loads
it
exactly the same way, regardless of whether it's in linux or windows
format)
Regards,
Jonathan
[[alternative HTML version deleted]]
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
[[alternative HTML version deleted]]
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[R] How to put text outside an xyplot?
Dear R-users,
I have a plot created with the code below. I tried to put some text to the
right of the color key. I worked with grid.text and also viewport(), but
couldn't achieve this. I know this should be simple, but I just couldn't figure
out how to do it. How does this work?
Cheers,
Marius
library(lattice)
library(grid)
myvec=1:10
data=data.frame(x=myvec,y=myvec)
mygray=function(l) gray(seq(0.2,0.8,length=l))
colors=level.colors(data[1:10,2],at=do.breaks(c(1,10),10),col.regions=mygray)
colorvec=colors[1:10]
#trellis.device(postscript,color=F,horizontal=F,onefile=F)
xyplot(data[,2]~data[,1],aspect=1,
panel=function(...){
panel.xyplot(...,type=n)
lpoints(data[,1],data[,2],pch=1,col=colorvec)
grid.text(text to the right of the color
key,1.2,0.5,rot=90)#does not work.
},
xlab=x,ylab=y,
legend=list(right=list(fun=draw.colorkey,args=list(key=list(col=mygray(10),at=1:10
)
#dev.off()
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to rotate an axis?
Hi, Do you want a ternary plot? http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=34 It's easy to rotate an axis with Grid graphics, library(grid) pushViewport(viewport(0.5,0.5, width=0.5, height=unit(3, lines))) grid.xaxis(at=seq(-0.5,0.5,by=0.1), vp=viewport(x=1, angle=-60)) HTH, baptiste 2009/12/20 Etienne Stockhausen einohr2...@web.de: Hi everybody, I'm trying to build a trilineare coordinate system with R. For that, I need to rotate an axis. Does anybody know, if it is possible to rotate an axis, created with the command axis(), about for instance 60 degrees? I'm looking foward to any ideas and hints and want to wish everybody a merry merry christmas. Thanks in advance. Etienne Stockhausen __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Object of type 'closure' not subsettable
Hi all,
How can I overcome the error object of type 'closure' not subsettable
I ran the following script
seq - paste(seq(1914, 1916, by=1), *.y, sep=.) # make sequence
c - 3 # total number of files
d2 - file # creates dummy file
# Input sequence in loop
for (i in 1:3){
list - list.files(~/ukcp09/txt/x.djf, seq[[i]])
file - lapply(list, read.table)
# Calculations
mean - (Reduce(+, file))/c
d2[[i]] - file[[i]] - mean
Apparently, the following command is the source of the error.
d2[[i]] - file[[i]] - mean
It works OK when I typed into the terminal the following after running
the script.
for (j in 1:3) print (file[[j]]-mean)
Thanks.
Muhammad
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom
Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974
Email: muhammad.ra...@ouce.ox.ac.uk
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Re: [R] Object of type 'closure' not subsettable
On Sun, Dec 20, 2009 at 7:40 PM, Muhammad Rahiz muhammad.ra...@ouce.ox.ac.uk wrote: Hi all, How can I overcome the error object of type 'closure' not subsettable I ran the following script seq - paste(seq(1914, 1916, by=1), *.y, sep=.) # make sequence c - 3 # total number of files d2 - file # creates dummy file No it doesn't. It copies the object called 'file' into an object called 'd2'. What's the object called 'file'? If you've not created one already, its the 'file' function that R uses to read stuff from files. So when you do: d2[[i]] - file[[i]] - mean you are trying to subset from d2 (and from 'file'). If I do this: file[[2]] I get your error message: Error in file[[2]] : object of type 'closure' is not subsettable So clearly you aren't doing what you think you're doing. Some hints: 1. Read a good introduction to R. You are making a number of fundamental mistakes here. 2. Run each line separately and check what value you get back by printing it. 3. Don't give your objects the same name as R functions (you're using 'seq', 'file', and 'mean'). Although this may work, it will confuse people later... Barry __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Object of type 'closure' not subsettable
On Dec 20, 2009, at 2:40 PM, Muhammad Rahiz wrote:
Hi all,
How can I overcome the error object of type 'closure' not
subsettable
I ran the following script
seq - paste(seq(1914, 1916, by=1), *.y, sep=.) # make sequence
c - 3 # total number of files
d2 - file # creates dummy file
# Input sequence in loop
for (i in 1:3){
list - list.files(~/ukcp09/txt/x.djf, seq[[i]])
file - lapply(list, read.table)
# Calculations
mean - (Reduce(+, file))/c
d2[[i]] - file[[i]] - mean
Apparently, the following command is the source of the error.
d2[[i]] - file[[i]] - mean
It works OK when I typed into the terminal the following after
running the script.
for (j in 1:3) print (file[[j]]-mean)
Generally R is able to keep straight what is a vector and what is a
function but you are using quite a few names for vectors and lists
which should be reserved (at least in your head) for functions. Here
is a list of function names to avoid as object names:
c
file
list
seq
mean
Why not try being so ambiguous? ObF: Would you call your dog dog?
--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
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Re: [R] Run time error when executing sqlQuery using the 64-bit version of R with 64-bit RODBC package in a Solaris 10 Sparc machine.
On Dec 19, 2009, at 11:39 AM, Alex Chelminsky wrote: I have compiled and linked a 64 bit version of R (R 2.9.2) and the corresponding unix ODBC 64 bit package The red highlighted text below is the error I'm getting trying to when invoking a sqlQuery library(RODBC) channel - odbcConnect(OraLSH, user, password) sqlQuery(channel,select sysdate from dual) Error in .Call(C_RODBCFetchRows, attr(channel, handle_ptr), max, buffsize, : negative length vectors are not allowed close(channel) q() Any suggestions are greatly appreciated. Given that you were able to connect to your server successfully, it tends to narrow the possible issues. Try using: sqlQuery(channel, select sysdate from dual, rows_at_time = 1) If you are using RODBC version 1.3-0 or newer, the default for rows_at_time is now 100, which has caused some problems with query results. Setting it to 1 (the former default value) seems to help. Also, if you are using Oracle (presumption based upon using OraLSH), you might try using 'case = toupper' in the sqlQuery() call as well. If the above does not help and you are using Oracle and have the InstantClient installed, try your queries using that from the CLI. If that works, then the underlying Oracle system configuration has been set correctly and helps to further isolate the problem to the R/RODBC combination. If not, then you have some underlying configuration issue to resolve. BTW, we won't see the 'red highlighted text' here, as the list is plain text only, not HTML or RTF. Last, but not least, R version 2.10.1 is the currently supported stable release of R. HTH, Marc Schwartz __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Problems in installing MCMCglmm package
Dear R-Helpers, I am having troubles with installing with MCMCglmm package and I get the following error with a package Matrix Warning in library(pkg, character.only = TRUE, logical.return = TRUE, lib.loc = lib.loc) : there is no package called 'Matrix' Error: package 'Matrix' could not be loaded Execution halted ERROR: lazy loading failed for package 'MCMCglmm' I tried installing the package Matrix - but it was unavailable. I am not able to understand why am I encountering this error - Any help is appreciated Thx, S. R version 2.8.1 (2008-12-22) x86_64-pc-linux-gnu locale: LC_CTYPE=en_US.UTF-8;LC_NUMERIC=C;LC_TIME=en_US.UTF-8;LC_COLLATE=en_US.UTF-8;LC_MONETARY=C;LC_MESSAGES=en_US.UTF-8;LC_PAPER=en_US.UTF-8;LC_NAME=C;LC_ADDRESS=C;LC_TELEPHONE=C;LC_MEASUREMENT=en_US.UTF-8;LC_IDENTIFICATION=C attached base packages: [1] stats graphics grDevices utils datasets methods [7] base other attached packages: [1] lattice_0.17-26 MASS_7.2-45 loaded via a namespace (and not attached): [1] grid_2.8.1 tools_2.8.1 [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] insert a dot to the numbers
Hi, Anybody can give me some hints on the following problem? s-c(110,112321) I want to insert a dot . after the third number and get the following results. 110. 112.321 Thanks a lot. -- - Jane Chang Queen's [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] insert a dot to the numbers
On Dec 20, 2009, at 3:50 PM, rusers.sh wrote: Hi, Anybody can give me some hints on the following problem? s-c(110,112321) I want to insert a dot . after the third number and get the following results. 110. 112.321 Thanks a lot. s - c(110, 112321) s / (10 ^ (nchar(s) - 3)) [1] 110. 112.3210 See ?nchar nchar(s) [1] 7 6 HTH, Marc Schwartz __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple main effect.
For simple effects in the presence of interaction there are several options included in the HH package. If you don't already have the HH package, you can get it with install.packages(HH) Graphically, you can plot them with the function interaction2wt(..., simple=TRUE) See the examples in ?HH::interaction2wt For tests on the simple effect of A conditional on a level of B, you can use the model formula B/A and look at the partition of the sums of squares using the split= argument summary(mymodel.aov, split=put your details here) For multiple comparisons from designs with Error() terms, you need to specify the same sums of squares with an equivalent formula that doesn't use the Error() function. See the maiz example in ?HH::MMC Read the example all the way to the end of the help file. Rich __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] forecasting
Very good patrick, lol. does anyone have any useful ideas Patrick Burns wrote: DispersionMap wrote: What about validating forecasting results. I have 5 years of data and have been forecasting the following three years i.e. 2010 to 2012. How can i check my forecast. Why types of tests are out there that can be implemented in R?? isbn 9780553213515 Sorry, couldn't resist, Pat __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://n4.nabble.com/forecasting-tp974326p975920.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] insert a dot to the numbers
On 20-Dec-09 21:50:58, rusers.sh wrote:
Hi,
Anybody can give me some hints on the following problem?
s-c(110,112321)
I want to insert a dot . after the third number and get the
following
results.
110.
112.321
Thanks a lot.
-
Jane Chang
Queen's
s-c(110,112321)
# [A]
s/(10^(floor(log10(s))-2))
# [1] 110. 112.3210
# [B]
sub(([0-9]{3}),\\1.,as.character(s))
[1] 110. 112.321
# [C]
as.double(sub(([0-9]{3}),\\1.,as.character(s)))
# [1] 110. 112.3210
Not sure exactly what you are asking; but these should give some ideas.
Ted.
E-Mail: (Ted Harding) ted.hard...@manchester.ac.uk
Fax-to-email: +44 (0)870 094 0861
Date: 20-Dec-09 Time: 22:23:26
-- XFMail --
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[R] Object is not a matrix Error
I'm trying to follow this guide here: http://www.ats.ucla.edu/stat/r/modules/dummy_vars.htm In which I'm creating categorical variables using the factor function. I am able to go through the example listed above and have everything work, however, when I try to input my own numbers, I get an error. I input the following: hits = read.csv(file.choose()) attach(hits) day.f - factor(day) lm(write ~ (day.f)) lm(write ~ (day.f)) Error in model.frame.default(formula = write ~ (day.f), drop.unused.levels = TRUE) : object is not a matrix So I import hits = read.csv(file.choose()) a .csv file, which has the columns visits and day where visits is the number of hits to a website, and day is a number 1-7, for example 1 corresponds to Sunday and 7 corresponds to Saturday. I understand that the day variable needs to be a categorical variable, and I'm trying to use the factor function to do this. I would like to be able to run a regression that will correlate the day with the number of hits. Any help would be much appreciated. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Object is not a matrix Error
Where is the object 'write'? SHouldn't you be using: lm(visits ~ (day.f)) On Sun, Dec 20, 2009 at 5:59 PM, John Paul Telthorst jpteltho...@gmail.comwrote: I'm trying to follow this guide here: http://www.ats.ucla.edu/stat/r/modules/dummy_vars.htm In which I'm creating categorical variables using the factor function. I am able to go through the example listed above and have everything work, however, when I try to input my own numbers, I get an error. I input the following: hits = read.csv(file.choose()) attach(hits) day.f - factor(day) lm(write ~ (day.f)) lm(write ~ (day.f)) Error in model.frame.default(formula = write ~ (day.f), drop.unused.levels = TRUE) : object is not a matrix So I import hits = read.csv(file.choose()) a .csv file, which has the columns visits and day where visits is the number of hits to a website, and day is a number 1-7, for example 1 corresponds to Sunday and 7 corresponds to Saturday. I understand that the day variable needs to be a categorical variable, and I'm trying to use the factor function to do this. I would like to be able to run a regression that will correlate the day with the number of hits. Any help would be much appreciated. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Object is not a matrix Error
When you imported did you not import the headers? Joe King 206-913-2912 j...@joepking.com Never throughout history has a man who lived a life of ease left a name worth remembering. --Theodore Roosevelt -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of jim holtman Sent: Sunday, December 20, 2009 3:11 PM To: John Paul Telthorst Cc: r-help@r-project.org Subject: Re: [R] Object is not a matrix Error Where is the object 'write'? SHouldn't you be using: lm(visits ~ (day.f)) On Sun, Dec 20, 2009 at 5:59 PM, John Paul Telthorst jpteltho...@gmail.comwrote: I'm trying to follow this guide here: http://www.ats.ucla.edu/stat/r/modules/dummy_vars.htm In which I'm creating categorical variables using the factor function. I am able to go through the example listed above and have everything work, however, when I try to input my own numbers, I get an error. I input the following: hits = read.csv(file.choose()) attach(hits) day.f - factor(day) lm(write ~ (day.f)) lm(write ~ (day.f)) Error in model.frame.default(formula = write ~ (day.f), drop.unused.levels = TRUE) : object is not a matrix So I import hits = read.csv(file.choose()) a .csv file, which has the columns visits and day where visits is the number of hits to a website, and day is a number 1-7, for example 1 corresponds to Sunday and 7 corresponds to Saturday. I understand that the day variable needs to be a categorical variable, and I'm trying to use the factor function to do this. I would like to be able to run a regression that will correlate the day with the number of hits. Any help would be much appreciated. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting -guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] CRAN (and crantastic) updates this week
CRAN (and crantastic) updates this week New packages Updated packages New reviews --- * deal, by newfuntek http://crantastic.org/reviews/45 * bnlearn, by newfuntek http://crantastic.org/reviews/44 * gRain, by newfuntek http://crantastic.org/reviews/43 This email provided as a service for the R community by http://crantastic.org. Like it? Hate it? Please let us know: crana...@gmail.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] insert a dot to the numbers
Try this also: sapply(s, function(x)format(x, big.interval = nchar(x) - 3, big.mark = .)) On Sun, Dec 20, 2009 at 7:50 PM, rusers.sh rusers...@gmail.com wrote: Hi, Anybody can give me some hints on the following problem? s-c(110,112321) I want to insert a dot . after the third number and get the following results. 110. 112.321 Thanks a lot. -- - Jane Chang Queen's [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Limit on number of times Realloc can be called?
Hello,
I've been writing a program in C that will be called by R. I seem to have
stumbled upon an odd error that seems to suggest there is a limit on the
number of times Realloc (the R version as defined in the manual
R-extenstions not the C version realloc) when I try to use the
following program:
#include R.h
#include Rinternals.h
SEXP test_mem_alloc(SEXP z) {
double *t = Calloc(sizeof(double), double);
*t = 2;
SEXP end_product;
int i = 0;
for(i=1; i 20; i++) {
t = Realloc(t, sizeof(t) + sizeof(double), double);
t[i] = i;
}
PROTECT(end_product = allocVector(REALSXP,6));
for(i = 0; i 20; i++) {
REAL(end_product)[i] = t[i];
}
UNPROTECT(1);
Free(t);
return end_product;
}
I call it from R using the following script:
z - 1
test_mem_alloc - function(z) {
if(!(is.loaded(test_mem_alloc_v6))) dyn.load(test_mem_alloc_v6.dll)
out - .Call(test_mem_alloc,
as.double(z))
return(out)
dyn.unload(test_mem_alloc_v6.dll)
}
Basically I get the following error messages:
First:
Runtime Error!
Program: C:\Program Files\R\R-2.10.0\bin\Rgui.exe
This application has requested the Runtime to terminate it in an unusual
way. Please contact the application's support team for more information.
The second error message is:
The instruction at 0x002c. The memory could not be read.
Now, if change the number of times the program goes through the for loop
from 20 to say 6, and hence calls Realloc fewer times, then the program
runs without any problems. It does not seem to have anything to do with
the size of the memory being allocated as I changed the size of the total
memory being allocated with a for loop with only 6 iterations to
something that is substantially larger than the memory being allocated in
the for loop when calling Realloc twenty times and the program ran
successfully. Has anyone else come across this problem or knows about some
sort of limitation on using Realloc that is not specified in the R
documentation?
Any help would be greatly appreciated.
Yours sincerely
Adam Kowalewski
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Limit on number of times Realloc can be called?
Adam Waldemar Kowalewski wrote:
Hello,
I've been writing a program in C that will be called by R. I seem to have
stumbled upon an odd error that seems to suggest there is a limit on the
number of times Realloc (the R version as defined in the manual
R-extenstions not the C version realloc) when I try to use the
following program:
#include R.h
#include Rinternals.h
SEXP test_mem_alloc(SEXP z) {
double *t = Calloc(sizeof(double), double);
*t = 2;
SEXP end_product;
int i = 0;
for(i=1; i 20; i++) {
t = Realloc(t, sizeof(t) + sizeof(double), double);
The second argument to Realloc is supposed to be the number of elements
to allocate. sizeof(t) is 4 or 8 (32 bit or 64 bit), sizeof double is
8, so you always allocate 12 or 16 elements. Then in the next line you
write out of bounds.
Duncan Murdoch
t[i] = i;
}
PROTECT(end_product = allocVector(REALSXP,6));
for(i = 0; i 20; i++) {
REAL(end_product)[i] = t[i];
}
UNPROTECT(1);
Free(t);
return end_product;
}
I call it from R using the following script:
z - 1
test_mem_alloc - function(z) {
if(!(is.loaded(test_mem_alloc_v6))) dyn.load(test_mem_alloc_v6.dll)
out - .Call(test_mem_alloc,
as.double(z))
return(out)
dyn.unload(test_mem_alloc_v6.dll)
}
Basically I get the following error messages:
First:
Runtime Error!
Program: C:\Program Files\R\R-2.10.0\bin\Rgui.exe
This application has requested the Runtime to terminate it in an unusual
way. Please contact the application's support team for more information.
The second error message is:
The instruction at 0x002c. The memory could not be read.
Now, if change the number of times the program goes through the for loop
from 20 to say 6, and hence calls Realloc fewer times, then the program
runs without any problems. It does not seem to have anything to do with
the size of the memory being allocated as I changed the size of the total
memory being allocated with a for loop with only 6 iterations to
something that is substantially larger than the memory being allocated in
the for loop when calling Realloc twenty times and the program ran
successfully. Has anyone else come across this problem or knows about some
sort of limitation on using Realloc that is not specified in the R
documentation?
Any help would be greatly appreciated.
Yours sincerely
Adam Kowalewski
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Can you delete me from the list I don't want to receive the emails from the forum anymore, thank you!
Date: Mon, 21 Dec 2009 12:33:26 +1100
From: a.kowalew...@ugrad.unimelb.edu.au
To: r-help@r-project.org
Subject: [R] Limit on number of times Realloc can be called?
Hello,
I've been writing a program in C that will be called by R. I seem to have
stumbled upon an odd error that seems to suggest there is a limit on the
number of times Realloc (the R version as defined in the manual
R-extenstions not the C version realloc) when I try to use the
following program:
#include R.h
#include Rinternals.h
SEXP test_mem_alloc(SEXP z) {
double *t = Calloc(sizeof(double), double);
*t = 2;
SEXP end_product;
int i = 0;
for(i=1; i 20; i++) {
t = Realloc(t, sizeof(t) + sizeof(double), double);
t[i] = i;
}
PROTECT(end_product = allocVector(REALSXP,6));
for(i = 0; i 20; i++) {
REAL(end_product)[i] = t[i];
}
UNPROTECT(1);
Free(t);
return end_product;
}
I call it from R using the following script:
z - 1
test_mem_alloc - function(z) {
if(!(is.loaded(test_mem_alloc_v6))) dyn.load(test_mem_alloc_v6.dll)
out - .Call(test_mem_alloc,
as.double(z))
return(out)
dyn.unload(test_mem_alloc_v6.dll)
}
Basically I get the following error messages:
First:
Runtime Error!
Program: C:\Program Files\R\R-2.10.0\bin\Rgui.exe
This application has requested the Runtime to terminate it in an unusual
way. Please contact the application's support team for more information.
The second error message is:
The instruction at 0x002c. The memory could not be read.
Now, if change the number of times the program goes through the for loop
from 20 to say 6, and hence calls Realloc fewer times, then the program
runs without any problems. It does not seem to have anything to do with
the size of the memory being allocated as I changed the size of the total
memory being allocated with a for loop with only 6 iterations to
something that is substantially larger than the memory being allocated in
the for loop when calling Realloc twenty times and the program ran
successfully. Has anyone else come across this problem or knows about some
sort of limitation on using Realloc that is not specified in the R
documentation?
Any help would be greatly appreciated.
Yours sincerely
Adam Kowalewski
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
_
ail you.
cial-network-basics.aspx?ocid=PID23461::T:WLMTAGL:ON:WL:en-xm:SI_SB_3:092
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Can you delete me from the list I don't want to receive the emails from the forum anymore, thank you!
A couple of week back someone posted this. It applies to you too:
None of the people reading this at the moment can do this for you. Read the
information on the page where you subscribed.:
https://stat.ethz.ch/mailman/listinfo/r-help
Q: How many psychiatrists does it take to unscrew a light bulb?
A: Only one, but the lightbulb must truly want to become unscrewed.
On Sun, Dec 20, 2009 at 9:00 PM, lippel anna lippelann...@hotmail.comwrote:
Date: Mon, 21 Dec 2009 12:33:26 +1100
From: a.kowalew...@ugrad.unimelb.edu.au
To: r-help@r-project.org
Subject: [R] Limit on number of times Realloc can be called?
Hello,
I've been writing a program in C that will be called by R. I seem to have
stumbled upon an odd error that seems to suggest there is a limit on the
number of times Realloc (the R version as defined in the manual
R-extenstions not the C version realloc) when I try to use the
following program:
#include R.h
#include Rinternals.h
SEXP test_mem_alloc(SEXP z) {
double *t = Calloc(sizeof(double), double);
*t = 2;
SEXP end_product;
int i = 0;
for(i=1; i 20; i++) {
t = Realloc(t, sizeof(t) + sizeof(double), double);
t[i] = i;
}
PROTECT(end_product = allocVector(REALSXP,6));
for(i = 0; i 20; i++) {
REAL(end_product)[i] = t[i];
}
UNPROTECT(1);
Free(t);
return end_product;
}
I call it from R using the following script:
z - 1
test_mem_alloc - function(z) {
if(!(is.loaded(test_mem_alloc_v6)))
dyn.load(test_mem_alloc_v6.dll)
out - .Call(test_mem_alloc,
as.double(z))
return(out)
dyn.unload(test_mem_alloc_v6.dll)
}
Basically I get the following error messages:
First:
Runtime Error!
Program: C:\Program Files\R\R-2.10.0\bin\Rgui.exe
This application has requested the Runtime to terminate it in an unusual
way. Please contact the application's support team for more information.
The second error message is:
The instruction at 0x002c. The memory could not be read.
Now, if change the number of times the program goes through the for loop
from 20 to say 6, and hence calls Realloc fewer times, then the program
runs without any problems. It does not seem to have anything to do with
the size of the memory being allocated as I changed the size of the total
memory being allocated with a for loop with only 6 iterations to
something that is substantially larger than the memory being allocated in
the for loop when calling Realloc twenty times and the program ran
successfully. Has anyone else come across this problem or knows about
some
sort of limitation on using Realloc that is not specified in the R
documentation?
Any help would be greatly appreciated.
Yours sincerely
Adam Kowalewski
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
_
ail you.
cial-network-basics.aspx?ocid=PID23461::T:WLMTAGL:ON:WL:en-xm:SI_SB_3:092
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Signif. codes
My question is about the Signif. codes and the p-value, specifically, the output when I run summary(nameofregression.lm) So you get this little key: Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1 And on a regression I ran, next to the intercept data, I get '***' Coefficients: Estimate Std. Error t value Pr(|t|) (Intercept) 7.956520.59993 13.262 2e-16 *** day.f2 -0.043480.84843 -0.0510.959 day.f3 -0.130430.84843 -0.1540.878 day.f4 -0.217390.84843 -0.2560.798 day.f5 0.021740.84843 0.0260.980 day.f6 -0.152170.84843 -0.1790.858 day.f7 0.149860.84390 0.1780.859 Does this mean that these numbers have a 0% chance of being wrong? Is there a way to change this to the .05 level of significance? Thanks, John [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Reading multiple Input Files
Dear R helpers,
Suppose I am dealing with no of interest rates at a time and the no of interest
rates I am selecting for my analysis is random i.e. it can be 2, can be 10 or
even higher. The R-code I had written (with the guidance of R helpers obviously
and I am really grateful to all of you) as of now is sort of hard coding when
it comes to reading interest rates as an input e.g.
## INPUT
rate_1 = read.csv('rate1_range.csv')
rate_2 = read.csv('rate2_range.csv')
rate_3 = read.csv('rate3_range.csv')
rate_4 = read.csv('rate4_range.csv')
prob_1 = read.csv('rate1_probs.csv')
prob_2 = read.csv('rate2_probs.csv')
prob_3 = read.csv('rate3_probs.csv')
prob_4 = read.csv('rate4_probs.csv')
However, since I am not sure how many interest rates I will be dealing with to
begin with, I have tried to call these inputs using a loop as follows.
In my R working directory, following files are there which are to be read as
input..
rate1_range.csv
rate2_range.csv
rate3_range.csv
rate4_range.csv
rate1_probs.csv
rate2_probs.csv
rate3_probs.csv
rate4_probs.csv
My R Code
# ___
n = no_of_Interest_Rates # This 'n' will be suppllied separately can be
anything.
n= 4 # As mentioned, this input will be added seperately.
for (i in 1:n)
{
rate_[i] = read.csv('rate[i]_range.csv')
prob_[i] = read.csv('rate[i]_probs.csv')
}
# End of code.
However when I excute this code (here, n = 4), I get following error.
Error in file(file, r) : cannot open the connection
In addition: Warning message:
In file(file, r) :
cannot open file 'rate[i]_range.csv': No such file or directory
Obviously as usual I have written some stupid code.
Please guide
Regards
Maithili
The INTERNET now has a personality. YOURS! See your Yahoo! Homepage.
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] Signif. codes
There will always be uncertainty in your estimates so you don't have 0 percent chance of being wrong, but remember that's your intercept, your regressors are not significant. Although you can say it is less than ..05, I mean if its significant at .001 (or something like that), that's less than .05, so its not unethical to say p .05, but it sounds like you need to understand the regression model a little better. Joe King 206-913-2912 j...@joepking.com Never throughout history has a man who lived a life of ease left a name worth remembering. --Theodore Roosevelt -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of John Paul Telthorst Sent: Sunday, December 20, 2009 10:13 PM To: r-help@r-project.org Subject: [R] Signif. codes My question is about the Signif. codes and the p-value, specifically, the output when I run summary(nameofregression.lm) So you get this little key: Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1 And on a regression I ran, next to the intercept data, I get '***' Coefficients: Estimate Std. Error t value Pr(|t|) (Intercept) 7.956520.59993 13.262 2e-16 *** day.f2 -0.043480.84843 -0.0510.959 day.f3 -0.130430.84843 -0.1540.878 day.f4 -0.217390.84843 -0.2560.798 day.f5 0.021740.84843 0.0260.980 day.f6 -0.152170.84843 -0.1790.858 day.f7 0.149860.84390 0.1780.859 Does this mean that these numbers have a 0% chance of being wrong? Is there a way to change this to the .05 level of significance? Thanks, John [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Signif. codes
No, so the probability means that's the probability of getting that data by chance, so a p-value of .9997 means there is a .9997 probability that the data could be acquired by chance. This is a very simplistic view and you should study the regression model better. Joe King 206-913-2912 j...@joepking.com Never throughout history has a man who lived a life of ease left a name worth remembering. --Theodore Roosevelt From: John Paul Telthorst [mailto:jpteltho...@gmail.com] Sent: Sunday, December 20, 2009 10:36 PM To: Joe King Subject: Re: [R] Signif. codes Thanks for the reply, I definitely do need to understand the regression model better. I got a p-value of .9997, so that would be .05? I guess I'm confused about the significance part you talked about. John On Mon, Dec 21, 2009 at 12:27 AM, Joe King j...@joepking.com wrote: There will always be uncertainty in your estimates so you don't have 0 percent chance of being wrong, but remember that's your intercept, your regressors are not significant. Although you can say it is less than ..05, I mean if its significant at .001 (or something like that), that's less than .05, so its not unethical to say p .05, but it sounds like you need to understand the regression model a little better. Joe King 206-913-2912 j...@joepking.com Never throughout history has a man who lived a life of ease left a name worth remembering. --Theodore Roosevelt -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of John Paul Telthorst Sent: Sunday, December 20, 2009 10:13 PM To: r-help@r-project.org Subject: [R] Signif. codes My question is about the Signif. codes and the p-value, specifically, the output when I run summary(nameofregression.lm) So you get this little key: Signif. codes: 0 0.001 0.01 0.05 0.1 And on a regression I ran, next to the intercept data, I get '***' Coefficients: Estimate Std. Error t value Pr(|t|) (Intercept) 7.956520.59993 13.262 2e-16 *** day.f2 -0.043480.84843 -0.0510.959 day.f3 -0.130430.84843 -0.1540.878 day.f4 -0.21739 0.84843 -0.2560.798 day.f5 0.021740.84843 0.0260.980 day.f6 -0.152170.84843 -0.1790.858 day.f7 0.14986 0.84390 0.1780.859 Does this mean that these numbers have a 0% chance of being wrong? Is there a way to change this to the .05 level of significance? Thanks, John [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- John Telthorst, MHRIR University of Illinois Alumnus [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Hello all, How can I get corss-validation MSE of SVM in e1071?
Hello, Max The caret package is so good, I am learning it, but one problem is that nearZeroVar function can be used to identify near zeroâvariance variables and it only identify, how can I remove those variables that were identify, because I have many zero- or near zero- ones, it is not realistic to removel it by hand, can this function can identify and removel those ones automatically? looking for your reply. kevin å¨2009-12-19ï¼Max Kuhn [via R] ml-node+975038-1351220...@n4.nabble.com åéï¼ -åå§é®ä»¶- å件人:Max Kuhn [via R] ml-node+975038-1351220...@n4.nabble.com åéæ¶é´:2009å¹´12æ19æ¥ ææå æ¶ä»¶äºº:bbslover dlu...@yeah.net 主é¢:Re: [R] Hello all, How can I get corss-validation MSE of SVM in e1071? You can get this using the caret package. There are a few package vignettes that come with the package and a JSS article http://www.jstatsoft.org/v28/i05/paper about the package. Max On Fri, Dec 18, 2009 at 12:26 PM, bbslover [hidden email] wrote: as known, svm need tune some parameters like cost,gamma and epsilon to get better performance,but one question appear, how can i monitor the performance . generally speaking ,we chose the cross-validation MSE in the training set, but It seems svm can not return the cross-validation MSE value, we just get it from summary model.svm, if I write a loop, have no idear call the cros-validate MSE, and no way to monitor this performance ,how can I do? -- View this message in context:http://n4.nabble.com/Hello-all-How-can-I-get-corss-validation-MSE-of-SVM-in-e1071-tp974942p974942.html Sent from the R help mailing list archive at Nabble.com. __ [hidden email]mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guidehttp://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Max __ [hidden email]mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guidehttp://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. View message @http://n4.nabble.com/Hello-all-How-can-I-get-corss-validation-MSE-of-SVM-in-e1071-tp974942p975038.html To unsubscribe from Hello all, How can I get corss-validation MSE of SVM in e1071?,click here. -- View this message in context: http://n4.nabble.com/Hello-all-How-can-I-get-corss-validation-MSE-of-SVM-in-e1071-tp974942p975955.html Sent from the R help mailing list archive at Nabble.com. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] what is criterion of removing independence?
Hello, all I have a lot of independents and one dependent, finally, I want to build one model using them, and predict the new samples value, that is regression. before it, I must remove some independents according to some criterion: 1. constant values independent. 2. variant near zero. 3. percentage of zero values what?? 4. have other critorion? for 3. and 4. 3. I have no idea, generally sepeaking, the corresponding independent with what is percentage of zero values should be removed (20% or 50% or others, have paper support?). 4. statistical, have any critorions that are used to removed independent? give me a hand. Actually, my questions is about feature selections, it is so complex, I hope any friends can give me a guidance. how can I leave those independent which is good to correlate to dependent.(i.e. high correlation coefficent R and small predictive error etc.). And removel bad independents. thank you! -- View this message in context: http://n4.nabble.com/what-is-criterion-of-removing-independence-tp975987p975987.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
