Re: [R] Data import export zipped files from URLs
cannot open: HTTP status was '404 Not Found' while running the following commands f - tempfile() download.file(http://nseindia.com/content/equities/scripvol/datafiles/01-01-2010-TO-23-01-2010RCOMXN.csv;, f) myData - read.csv(f) On 1/19/10, Henrique Dallazuanna www...@gmail.com wrote: Try this: f - tempfile() download.file(http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip;, f) myData - read.csv(unzip(f)) On Tue, Jan 19, 2010 at 2:56 PM, Velappan Periasamy veepsi...@gmail.com wrote: How to unzip this file?. mydata - unzip(http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip;) Warning message: In unzip(http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip;) : error 1 in extracting from zip file __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Quartiles and Inter-Quartile Range
Interestingly, Hmisc::describe() and summary() seem to be using one Type, and stats::fivenum() seems to be using another Type. fivenum(cbiomass) [1] 910.0 1039.0 1088.5 1156.5 1415.0 summary(cbiomass) Min. 1st Qu. MedianMean 3rd Qu.Max. 91010481088110411391415 describe(cbiomass)$counts n missing unique Mean .05 .10 .25 .50 .75 12 0 12 1104 920.5 938.3 1047.5 1088.5 1138.8 .90 .95 1248.7 1327.0 cheers, -Girish -- View this message in context: http://n4.nabble.com/Quartiles-and-Inter-Quartile-Range-tp1145817p1248728.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Optimizing C code
Duncan Murdoch a écrit :
On 22/01/2010 12:52 PM, Christophe Genolini wrote:
Thanks both of you.
Inf - Inf
[1] NaN
So isn't the line 9 useless ? If either x[i] or y[i] are NA, then dev
will be NA and !ISNAN(dev) will detect it...
Sothe loop cool be
8.for(i = 0 ; i taille ; i++) {
10.dev = (x[i] - y[i]);
11.if(!ISNAN(dev)) {
12. dist += dev * dev;
13. count++;
15. }
16. }
No ?
That would presumably give the same answer, but there are lots of
reasons it might not be useless:
- the author might find it clearer, or easier to generalize to integer
data (where your version wouldn't work).
- it might be faster, because it can abort sooner.
- it might be essentially equivalent in all important respects.
Duncan Murdoch
That's 3 good reasons to keep the other code. Thanks.
Christophe
Duncan Murdoch
Christophe
#define both_FINITE(a,b) (R_FINITE(a) R_FINITE(b))
#define both_non_NA(a,b) (!ISNAN(a) !ISNAN(b))
1. static double R_euclidean2(double *x, double *y, int taille)
2. {
3.double dev, dist;
4.int count, i;
5.
6.count= 0;
7.dist = 0;
8.for(i = 0 ; i taille ; i++) {
9.if(both_non_NA(x[i], y[i])) {
10.dev = (x[i] - y[i]);
11.if(!ISNAN(dev)) {
12.dist += dev * dev;
13.count++;
14.}
15.}
16.}
17.if(count == 0)return NA_REAL;
18.if(count != taille) dist /= ((double)count/taille);
19.return sqrt(dist);
20.}
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Re: [R] Quartiles and Inter-Quartile Range
and SAS give one a choice of 5 option, and i'm fairly sure that it used a different default than does R (although one of the 5 corresponds to the sas default) see pctldef on http://www.technion.ac.il/docs/sas/proc/z0146803.htm my simple brain thinks of thinks of the problem as 'how does one calculate the median of 4 values?' david freedman Girish A.R. [via R] wrote: Interestingly, Hmisc::describe() and summary() seem to be using one Type, and stats::fivenum() seems to be using another Type. fivenum(cbiomass) [1] 910.0 1039.0 1088.5 1156.5 1415.0 summary(cbiomass) Min. 1st Qu. MedianMean 3rd Qu.Max. 91010481088110411391415 describe(cbiomass)$counts n missing unique Mean .05 .10 .25 .50 .75 12 0 12 1104 920.5 938.3 1047.5 1088.5 1138.8 .90 .95 1248.7 1327.0 cheers, -Girish View message @ http://n4.nabble.com/Quartiles-and-Inter-Quartile-Range-tp1145817p1248728.html To unsubscribe from Re: Quartiles and Inter-Quartile Range, click here (link removed) =. -- View this message in context: http://n4.nabble.com/Quartiles-and-Inter-Quartile-Range-tp1145817p1264043.html Sent from the R help mailing list archive at Nabble.com. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] R and Limesurvey
Hello. I used Limesurvey to get answers to a survey. Now I need to process the data collected. I exported the R syntax file describing the survey structure, the file is a http://fdelente.free.fr/Surveydata_syntax.R It contains lines like attributes(data)$variable.labels[which(names(data)==V5)]=Quel âge avez-vous ? that are the clear text of my question. I'd like to be able to reference these values to display them. I tried print(attributes(data)$variable.labels[V5] but it gives NA whereas I'd like to get Quel âge avez-vous ?. How does this work? Thanks for any hint! -- Fabrice DELENTE __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] rda.cv cross validation
Dear R listmates, I am doing a cross validation with rda.cv to set alpha and delta parameters in a training set counting on 614 instances. The result of the process in R is: rda.cv(fit = z, x = Tt, y = TtL, nfold = 10) $nonzero      delta alpha 0 0.333 0.667 1 1.333 1.667 2 2.333 2.667 3  0     9    9    9 8    8    8 8    7    6 4  0.11 9    9    8 8    6    3 1    1    1 0  0.22 9    8    7 6    2    1 1    0    0 0  0.33 9    8    6 2    1    1 0    0    0 0  0.44 9    8    4 2    1    0 0    0    0 0  0.55 9    6    2 1    0    0 0    0    0 0  0.66 9    6    2 1    0    0 0    0    0 0  0.77 9    6    2 1    0    0 0    0    0 0  0.88 9    5    2 0    0    0 0    0    0 0  0.99 9    4    1 0    0    0 0    0    0 0 $cv.err      delta alpha  0 0.333 0.667  1 1.333 1.667  2 2.333 2.667  3  0     22   23   23 25   25   25 23    25    26 34  0.11 24   24   25 28   31    54 64    72   160 214  0.22 24   25   29 39   58    72 144   214  214 214  0.33 24   27   36 56   72   160 214   214  214 214  0.44 25   30   53 64  126   214 214  214  214 214  0.55 25   32   53 73  214   214 214  214  214 214  0.66 25   35   57 127  214  214 214  214  214 214  0.77 25   37   64 201  214  214 214  214  214 214  0.88 25   42   76 214  214  214 214  214  214 214  0.99 25   49   85 214  214  214 214  214  214 214 My doubt is: What do these numbers in the second table really represent? I am considerind that they are the averaged number of missclassifications for each set. Am I right? Thanks, Alexandre. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] rda.cv cross validation
Dear R listmates, I am doing a cross validation with rda.cv to set alpha and delta parameters in a training set counting on 614 instances. The result of the process in R is:      delta alpha 0 0.333 0.667 1 1.333 1.667 2 2.333 2.667 3  0   9    9    9 8    8    8 8    7    6 4  0.11 9    9    8 8    6    3 1    1    1 0  0.22 9    8    7 6    2    1 1    0    0 0  0.33 9    8    6 2    1    1 0    0    0 0  0.44 9    8    4 2    1    0 0    0    0 0  0.55 9    6    2 1    0    0 0    0    0 0  0.66 9    6    2 1    0    0 0    0    0 0  0.77 9    6    2 1    0    0 0    0    0 0  0.88 9    5    2 0    0    0 0    0    0 0  0.99 9    4    1 0    0    0 0    0    0 0 $cv.err      delta alpha  0 0.333 0.667  1 1.333 1.667  2 2.333 2.667  3  0   22   23   23 25   25   25 23   25   26 34  0.11 24   24   25 28   31   54 64   72  160 214  0.22 24   25   29 39   58   72 144  214  214 214  0.33 24   27   36 56   72  160 214  214  214 214  0.44 25   30   53 64  126  214 214  214  214 214  0.55 25   32   53 73  214  214 214  214  214 214  0.66 25   35   57 127  214  214 214  214  214 214  0.77 25   37   64 201  214  214 214  214  214 214  0.88 25   42   76 214  214  214 214  214  214 214  0.99 25   49   85 214  214  214 214  214  214 214 My doubt is: What do these numbers in the second table really represent? I am considerind that they are the averaged number of missclassifications for each set. Am I right? Thanks, Alexandre. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data import export zipped files from URLs
The same link works and dowloads data while copying and pasteing the link in firebox address box. the file is there and the server is active. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R and Limesurvey
Fabrice DELENTE wrote: Hello. I used Limesurvey to get answers to a survey. Now I need to process the data collected. I exported the R syntax file describing the survey structure, the file is a http://fdelente.free.fr/Surveydata_syntax.R It contains lines like attributes(data)$variable.labels[which(names(data)==V5)]=Quel âge avez-vous ? that are the clear text of my question. I'd like to be able to reference these values to display them. I tried print(attributes(data)$variable.labels[V5] but it gives NA whereas I'd like to get Quel âge avez-vous ?. How does this work? Hmm, does it help if you first set names(attributes(data)$variable.labels) - names(data) -- O__ Peter Dalgaard Øster Farimagsgade 5, Entr.B c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~ - (p.dalga...@biostat.ku.dk) FAX: (+45) 35327907 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] ltext, small lattice question
Dear friends - I have a dataset of 40 patients in two groups observed on
three occasions. I only want to plot a line
for each patient in the two groups. I use the ltext function to put the
patient number but fail to make lattice understand the numbers as
unique since apparently it starts all over with 1:20 for each panel
instead of respecting my desires to have 1:20 and then 21:40.
I'm on windows vista, R2.9.2
Best wishes
Troels
score - runif(120,0,100)
pt - gl(40,3,120)
times - rep(c(0,3,6),40)
trt - gl(2,60,120)
ach - data.frame(score=score,pt=pt,times=times,trt=trt)
library(lattice)
myPanel - function(x,y,...){
panel.xyplot(x,y,...)
ltext(x-.1,y+1,paste(pt),cex=0.5) }
xyplot(score~times|trt,groups=pt,type=c(p,l),ach,
panel=myPanel)
--
Troels Ring
Department of nephrology
Aalborg Hospital
Mølleparkvej
phone: +4599326629
Heliosvej 12
9210 Aalborg SØ
98140582
30480176
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Re: [R] R and Limesurvey
Hmm, does it help if you first set names(attributes(data)$variable.labels) - names(data) Yes, it does, many thanks! I'll take some time later to work out what all these commands mean :^) -- Fabrice DELENTE __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data import export zipped files from URLs
Your url is wrong. is missing .zip in the end. See the code again. On Sat, Jan 23, 2010 at 6:37 AM, Velappan Periasamy veepsi...@gmail.com wrote: cannot open: HTTP status was '404 Not Found' while running the following commands f - tempfile() download.file(http://nseindia.com/content/equities/scripvol/datafiles/01-01-2010-TO-23-01-2010RCOMXN.csv;, f) myData - read.csv(f) On 1/19/10, Henrique Dallazuanna www...@gmail.com wrote: Try this: f - tempfile() download.file(http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip;, f) myData - read.csv(unzip(f)) On Tue, Jan 19, 2010 at 2:56 PM, Velappan Periasamy veepsi...@gmail.com wrote: How to unzip this file?. mydata - unzip(http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip;) Warning message: In unzip(http://nseindia.com/content/historical/EQUITIES/2010/JAN/cm15JAN2010bhav.csv.zip;) : error 1 in extracting from zip file __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] sorted reshaping?
thank you, dennis. your example was much better than my own, too. for everyone else's benefit who will be searching for the answers for this problem on r-help, let me extend this a little. the problem arises primarily in data sets that are sparse. in my case, the first (ordered) firm does not have data in the first (ordered) year. firm - c(0,rep(1:10, each = 5)) year - c(2004,rep(2002:2006, 10)) resp - c(1.0,rnorm(50)) dat.long - data.frame(firm = firm, year = year, resp = resp) dat.wide - reshape(dat.long, direction = 'wide', idvar = 'firm', timevar= 'year') head(dat.wide) yields firm resp.2004 resp.2002 resp.2003 resp.2005 resp.2006 1 01.NANANANA 2 1 -0.4483 -0.76231.06250.4654 -0.36041 7 2 -0.1373 -0.86480.72720.1637 -0.09235 1231.08350.45440.1577 -1.6991 -1.04559 1741.13902.1633 -1.22980.9460 -0.28682 225 -0.89061.0084 -0.1948 -0.6801 -0.47192 in contrast, the library(reshape) function did yield the desired order: library(reshape) Loading required package: plyr dat.cast - cast(dat.long, firm ~ year) Using resp as value column. Use the value argument to cast to override this choice head(dat.cast) firm2002200320042005 2006 10 NA NA 1. NA NA 21 -0.7623 1.0625 -0.4483 0.4654 -0.36041 32 -0.8648 0.7272 -0.1373 0.1637 -0.09235 43 0.4544 0.1577 1.0835 -1.6991 -1.04559 54 2.1633 -1.2298 1.1390 0.9460 -0.28682 65 1.0084 -0.1948 -0.8906 -0.6801 -0.47192 I think this example would make a nice addition to ?reshape. for see also, I would add library(reshape). finally, it would be nice if an email would be on each R help (in R documentation) to make suggestions for improvements. regards, /iaw Ivo Welch (ivo.we...@brown.edu, ivo.we...@gmail.com) __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] sorted reshaping?
This also works (giving a matrix so use as.data.frame if you want it as a data frame): tapply(dat.long[,3], dat.long[1:2], c) year firm20022003 2004 20052006 0 NA NA 1.000 NA NA 1 0.86456075 -1.06794272 1.1850129 -0.1385206 -0.41101249 2 0.04505626 0.24331227 -0.7902969 0.6833840 0.17823240 3 -2.07018155 0.32203467 -1.0867019 1.1990902 -0.86256005 4 -1.04872782 -0.90006314 1.0398810 -0.3545491 -0.93241925 5 -1.55728162 0.98297102 1.0280005 1.6397312 0.79278075 6 0.21446824 0.10913775 1.1284486 -0.4148321 0.95917517 7 -1.97895845 -0.05366712 0.9740745 0.8070221 1.33701029 8 -1.94635463 -1.03172741 1.5351331 -2.0643955 0.63561387 9 -0.08866245 0.42450753 -0.8108118 0.5155799 -1.54716628 10 0.11008895 0.18344337 0.3891310 0.9016668 0.04618046 On Sat, Jan 23, 2010 at 8:25 AM, ivo welch ivo...@gmail.com wrote: thank you, dennis. your example was much better than my own, too. for everyone else's benefit who will be searching for the answers for this problem on r-help, let me extend this a little. the problem arises primarily in data sets that are sparse. in my case, the first (ordered) firm does not have data in the first (ordered) year. firm - c(0,rep(1:10, each = 5)) year - c(2004,rep(2002:2006, 10)) resp - c(1.0,rnorm(50)) dat.long - data.frame(firm = firm, year = year, resp = resp) dat.wide - reshape(dat.long, direction = 'wide', idvar = 'firm', timevar= 'year') head(dat.wide) yields firm resp.2004 resp.2002 resp.2003 resp.2005 resp.2006 1 0 1. NA NA NA NA 2 1 -0.4483 -0.7623 1.0625 0.4654 -0.36041 7 2 -0.1373 -0.8648 0.7272 0.1637 -0.09235 12 3 1.0835 0.4544 0.1577 -1.6991 -1.04559 17 4 1.1390 2.1633 -1.2298 0.9460 -0.28682 22 5 -0.8906 1.0084 -0.1948 -0.6801 -0.47192 in contrast, the library(reshape) function did yield the desired order: library(reshape) Loading required package: plyr dat.cast - cast(dat.long, firm ~ year) Using resp as value column. Use the value argument to cast to override this choice head(dat.cast) firm 2002 2003 2004 2005 2006 1 0 NA NA 1. NA NA 2 1 -0.7623 1.0625 -0.4483 0.4654 -0.36041 3 2 -0.8648 0.7272 -0.1373 0.1637 -0.09235 4 3 0.4544 0.1577 1.0835 -1.6991 -1.04559 5 4 2.1633 -1.2298 1.1390 0.9460 -0.28682 6 5 1.0084 -0.1948 -0.8906 -0.6801 -0.47192 I think this example would make a nice addition to ?reshape. for see also, I would add library(reshape). finally, it would be nice if an email would be on each R help (in R documentation) to make suggestions for improvements. regards, /iaw Ivo Welch (ivo.we...@brown.edu, ivo.we...@gmail.com) __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] MAC R crashes
The typical reason for a crash on startup is a corrupted (or version
mismatched) .RData file.
http://cran.r-project.org/bin/macosx/RMacOSX-FAQ.html#R_002eapp-GUI-crashes-on-startup_0021
--
David.
On Jan 22, 2010, at 6:32 PM, Peter Rossi wrote:
Dear R-Help Group:
R will not start on my imac running 10.6.2. I installed both
R2.10.1 and
2.10.0 from pkg. It crashed on both. I tried both the R and R64 apps
and
both versions 2.10.1 and 2.10.0. I googled and found nothing on this.
Below is part of report:
Process: R [767]
Path:/Applications/R64.app/Contents/MacOS/R
Identifier: org.R-project.R
Version: R 2.10.0 GUI 1.30 Leopard build 64-bit (5511)
Code Type: X86-64 (Native)
Parent Process: launchd [182]
Date/Time: 2010-01-22 15:22:28.306 -0800
OS Version: Mac OS X 10.6.2 (10C2234)
Report Version: 6
Interval Since Last Report: 868605 sec
Crashes Since Last Report: 12
Per-App Crashes Since Last Report: 1
Anonymous UUID:
2711C8BB-9B34-4F6D-98AF-8753700C7B8F
Exception Type: EXC_CRASH (SIGABRT)
Exception Codes: 0x, 0x
Crashed Thread: 0 Dispatch queue: com.apple.main-thread
Application Specific Information:
abort() called
*** Terminating app due to uncaught exception
'NSInvalidArgumentException',
reason: '-[NSApplication _setup:]: unrecognized selector sent to
instance
0x1006088b0'
If I delete my Rprofile, R will sometimes run but hangs and goes
non-responsive when I type only one letter of a command.
cat .Rprofile
# Example of .Rprofile
.First - function() {
library(bayesm)
library(tcltk)
cat( tcltk,bayesm loaded \n\n)
}
source(my_R_functions.R)
cat( custom functions loaded \n)
.Last - function() cat(\n Goodbye!\n\n)
I have fully updated by mac os.
Any help would be most appreciated.
Peter Rossi
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David Winsemius, MD
Heritage Laboratories
West Hartford, CT
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] simulation of binary data
Check out the help page of the lrm function in the rms library. To show how lrm is used, the examples simulate data for logistic regression. This may give you some ideas. On Wed, Jan 20, 2010 at 10:41 AM, omar kairan omarkaira...@gmail.com wrote: Hi, could someone help me with dilemma on the simulation of logistic regressiondata with multicollinearity effect and high leverage point.. Thank you [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Rotating the axis labels in the basic graphic device ?
On 22.01.2010 21:26, Tal Galili wrote: Hello dear R help group, I learned recently that one can change the rotation of labels in the axis, when using a lattice plot, for example: library(lattice) barchart(yield ~ variety , data = barley, groups = year, ylab = Barley Yield (bushels/acre), scales = list(rot = 45)) My question is: Is there an application of rot in something like barplot ? The only solution I know of is using las = X (X is 1,2, or 3) Is there another solution/hack for this ? No, by design there is just the las way ... Uwe Ligges Thanks! Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Rotating the axis labels in the basic graphic device ?
Uwe and Marc, You two just made me smile in more then one way - thank you :) Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sat, Jan 23, 2010 at 6:07 PM, Marc Schwartz marc_schwa...@me.com wrote: On Jan 23, 2010, at 9:59 AM, Uwe Ligges wrote: On 23.01.2010 16:56, Marc Schwartz wrote: On Jan 23, 2010, at 9:51 AM, Uwe Ligges wrote: On 22.01.2010 21:26, Tal Galili wrote: Hello dear R help group, I learned recently that one can change the rotation of labels in the axis, when using a lattice plot, for example: library(lattice) barchart(yield ~ variety , data = barley, groups = year, ylab = Barley Yield (bushels/acre), scales = list(rot = 45)) My question is: Is there an application of rot in something like barplot ? The only solution I know of is using las = X (X is 1,2, or 3) Is there another solution/hack for this ? No, by design there is just the las way ... Uwe Ligges Actually, there is a method and it is in the R FAQs: http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-create-rotated-axis-labels_003f Yes you are right, Marc, thank you! I would not call this as by design and it sometimes need quite a lot fiddling if font sizes change. Best, Uwe Quite right Uwe, it is not by design, but is consistent with: library(fortunes) fortune(yoda) ;-) As you note, it took some understanding and tweaking of base graphics parameters and such to get that method to work. Cheers, Marc [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] matrix to a C function
Hi the list,
Is there a way to give a matrix to a C function, and then to use it as a
matrix ?
I write a function to print a matrix, but I use it as a vector :
1. void printMatrix(double *mTraj,int *nbCol, int *nbLigne){
2. int i=0,j=0;
3. for(i=0 ; i *nbLigne ; i++){
4. for(j=0 ; j *nbCol ; j++){
5. Rprintf( %f,mTraj[i * *nbCol + j]);
6. }
7. Rprintf(\n);
8.}
9. }
I would like to use it as a matrix (line 5 changes) :
1. void printMatrix(double *mTraj,int *nbCol, int *nbLigne){
2. int i=0,j=0;
3. for(i=0 ; i *nbLigne ; i++){
4. for(j=0 ; j *nbCol ; j++){
5. Rprintf( %f,mTraj[i,j]);
6. }
7. Rprintf(\n);
8.}
9. }
It does not work, but is there an solution close to this ?
Thanks.
Christophe
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Re: [R] Rotating the axis labels in the basic graphic device ?
On Jan 23, 2010, at 10:25 AM, Tal Galili wrote: Marc, Following the R FAQ you linked to, I wonder how to ALWAYS have the text and the plot region fit. I know that if the text is too long, one can use the par(mar = c(big.number, 4, 4 ,4)) and get the text to fit. The question is: Is there a way to make the plot know what big.number should be so the text wouldn't go beyond plot regions ? (I suspect my question might get lost inside this topic, if so - I'll repeat it with a different header) Thanks again, Tal snip Tal, I suspect that you would to create an algorithm using functions such as strwidth() and strheight() to get the plot metrics for the sizes of the character labels to have a sense of how much room would be required given other parameters. I am guessing that if you were to look at the appropriate source code in the lattice package, something along these lines is implemented there, since lattice supports rotated labels 'out of the box' and would logically have to consider these plotting characteristics at some level. Otherwise, it is a manual tweaking process. HTH, Marc __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] About LU decomposition in R
Read the Matrix package documentation require(Matrix) help(lu, html=TRUE) Walmes. - ..oooO .. ..()... 0ooo... Walmes Zeviani ...\..(.(.)... Master in Statistics and Agricultural Experimentation \_). )../ walmeszevi...@hotmail.com, Lavras - MG, Brasil (_/ -- View this message in context: http://n4.nabble.com/About-LU-decomposition-in-R-tp1229137p1288264.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Error: could not find function
Hi. I'm trying to create an Agresti-Coull confidence interval without using the binom package. Despite many trials, I keep getting the same problem- see below. y=334 n=1160 alpha=.05 b=(y+.5*qnorm(1-alpha/2)**2)/(n+qnorm(1-alpha/2)**2) b [1] 0.288631 ac=b+qnorm(1-alpha/2)*sqrt(b(1-b)/(n+qnorm(1-alpha/2)**2)) Error: could not find function b What am I missing? What am I doing wrong? Thank you, Remus [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Rotating the axis labels in the basic graphic device ?
On 23.01.2010 17:42, Marc Schwartz wrote: On Jan 23, 2010, at 10:25 AM, Tal Galili wrote: Marc, Following the R FAQ you linked to, I wonder how to ALWAYS have the text and the plot region fit. I know that if the text is too long, one can use the par(mar = c(big.number, 4, 4 ,4)) and get the text to fit. The question is: Is there a way to make the plot know what big.number should be so the text wouldn't go beyond plot regions ? (I suspect my question might get lost inside this topic, if so - I'll repeat it with a different header) Thanks again, Tal snip Tal, I suspect that you would to create an algorithm using functions such as strwidth() and strheight() to get the plot metrics for the sizes of the character labels to have a sense of how much room would be required given other parameters. I am guessing that if you were to look at the appropriate source code in the lattice package, something along these lines is implemented there, since lattice supports rotated labels 'out of the box' and would logically have to consider these plotting characteristics at some level. Well, lattice relies on grid and grid can place arbitrary viewports with arbitrary rotations everywhere by design. Otherwise, it is a manual tweaking process. Indeed, that's the thing I meant with not by design. ;-) Best wishes, Uwe HTH, Marc __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Rotating the axis labels in the basic graphic device ?
Marc, Following the R FAQ you linked to, I wonder how to ALWAYS have the text and the plot region fit. I know that if the text is too long, one can use the par(mar = c(big.number, 4, 4 ,4)) and get the text to fit. The question is: Is there a way to make the plot know what big.number should be so the text wouldn't go beyond plot regions ? (I suspect my question might get lost inside this topic, if so - I'll repeat it with a different header) Thanks again, Tal Contact Details:--- Contact me: tal.gal...@gmail.com | 972-52-7275845 Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com/ (English) -- On Sat, Jan 23, 2010 at 5:56 PM, Marc Schwartz marc_schwa...@me.com wrote: On Jan 23, 2010, at 9:51 AM, Uwe Ligges wrote: On 22.01.2010 21:26, Tal Galili wrote: Hello dear R help group, I learned recently that one can change the rotation of labels in the axis, when using a lattice plot, for example: library(lattice) barchart(yield ~ variety , data = barley, groups = year, ylab = Barley Yield (bushels/acre), scales = list(rot = 45)) My question is: Is there an application of rot in something like barplot ? The only solution I know of is using las = X (X is 1,2, or 3) Is there another solution/hack for this ? No, by design there is just the las way ... Uwe Ligges Actually, there is a method and it is in the R FAQs: http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-create-rotated-axis-labels_003f HTH, Marc Schwartz [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Rotating the axis labels in the basic graphic device ?
On Jan 23, 2010, at 9:51 AM, Uwe Ligges wrote: On 22.01.2010 21:26, Tal Galili wrote: Hello dear R help group, I learned recently that one can change the rotation of labels in the axis, when using a lattice plot, for example: library(lattice) barchart(yield ~ variety , data = barley, groups = year, ylab = Barley Yield (bushels/acre), scales = list(rot = 45)) My question is: Is there an application of rot in something like barplot ? The only solution I know of is using las = X (X is 1,2, or 3) Is there another solution/hack for this ? No, by design there is just the las way ... Uwe Ligges Actually, there is a method and it is in the R FAQs: http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-create-rotated-axis-labels_003f HTH, Marc Schwartz __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Rotating the axis labels in the basic graphic device ?
On 23.01.2010 16:56, Marc Schwartz wrote: On Jan 23, 2010, at 9:51 AM, Uwe Ligges wrote: On 22.01.2010 21:26, Tal Galili wrote: Hello dear R help group, I learned recently that one can change the rotation of labels in the axis, when using a lattice plot, for example: library(lattice) barchart(yield ~ variety , data = barley, groups = year, ylab = Barley Yield (bushels/acre), scales = list(rot = 45)) My question is: Is there an application of rot in something like barplot ? The only solution I know of is using las = X (X is 1,2, or 3) Is there another solution/hack for this ? No, by design there is just the las way ... Uwe Ligges Actually, there is a method and it is in the R FAQs: http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-create-rotated-axis-labels_003f Yes you are right, Marc, thank you! I would not call this as by design and it sometimes need quite a lot fiddling if font sizes change. Best, Uwe HTH, Marc Schwartz __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Help on tcl/tk package installation
On 23.01.2010 01:35, 李道丰 wrote: Hi, how to compile with tcl/tk support ? command line options? thank you:) There is a manual called R Installation and Administration you are obviously not aware of (probably because you never read the posting guide of the mailing list). That manual contains a section (cuurently Appendix A.2.1) Tcl/Tk ... Best wishes, Uwe Ligges 2010/1/22 Uwe Liggeslig...@statistik.tu-dortmund.de You need to reinstall R and compile with tcl/tk support (best is to use R-2.10.1 nowadays since yours is already outdated). Best, Uwe Ligges On 22.01.2010 08:13, 李道丰 wrote: Hi, Dear all, i encounted a problem with tcl/tk installation actually i want to install q-value package i use the R CMD INSTALL command: [r...@bioinfo ~]# R CMD INSTALL qvalue_1.20.0.tar.gz * Installing to library â€?usr/local/lib64/R/libraryâ€? * Installing *source* package ‘qvalueâ€?... ** R ** data ** inst ** preparing package for lazy loading Error in firstlib(which.lib.loc, package) : Tcl/Tk support is not available on this system Error : package 'tcltk' could not be loaded ERROR: lazy loading failed for package ‘qvalueâ€? * Removing â€?usr/local/lib64/R/library/qvalueâ€? i do some search work with google, suggest i need to install tcl and tk at system level i download the source tcl and tk from sourceforge and installed them: [r...@bioinfo ~]# tclsh % info patchlevel 8.4.13 % i uninstall R package with make uninstall and make distclean,then reinstall R but the problem stills occurs i am using Redhat enterprise linux 5 x64 version packages metioned above are listed follow: R-2.9.2.tar.gz tcl8.5.8-src.tar.gz tk8.5.8-src.tar.gz qvalue_1.20.0.tar.gz any commments would be very appeciated:) thank you in advance:) __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Error: could not find function
On 23.01.2010 17:50, Remus Suciu wrote: Hi. I'm trying to create an Agresti-Coull confidence interval without using the binom package. Despite many trials, I keep getting the same problem- see below. y=334 n=1160 alpha=.05 b=(y+.5*qnorm(1-alpha/2)**2)/(n+qnorm(1-alpha/2)**2) b [1] 0.288631 ac=b+qnorm(1-alpha/2)*sqrt(b(1-b)/(n+qnorm(1-alpha/2)**2)) Error: could not find function b What am I missing? The * between b and (1-b), I guess. Uwe Ligges What am I doing wrong? Thank you, Remus [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Rotating the axis labels in the basic graphic device ?
On Jan 23, 2010, at 9:59 AM, Uwe Ligges wrote: On 23.01.2010 16:56, Marc Schwartz wrote: On Jan 23, 2010, at 9:51 AM, Uwe Ligges wrote: On 22.01.2010 21:26, Tal Galili wrote: Hello dear R help group, I learned recently that one can change the rotation of labels in the axis, when using a lattice plot, for example: library(lattice) barchart(yield ~ variety , data = barley, groups = year, ylab = Barley Yield (bushels/acre), scales = list(rot = 45)) My question is: Is there an application of rot in something like barplot ? The only solution I know of is using las = X (X is 1,2, or 3) Is there another solution/hack for this ? No, by design there is just the las way ... Uwe Ligges Actually, there is a method and it is in the R FAQs: http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-create-rotated-axis-labels_003f Yes you are right, Marc, thank you! I would not call this as by design and it sometimes need quite a lot fiddling if font sizes change. Best, Uwe Quite right Uwe, it is not by design, but is consistent with: library(fortunes) fortune(yoda) ;-) As you note, it took some understanding and tweaking of base graphics parameters and such to get that method to work. Cheers, Marc __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] lm on group
You can guess by looking at class(g). It is a factor. It is NOT regressing on the mean of g (i.e. 2.5 and 7.5) and you could have changed g from (0,5] and (5,10] to A and B with the same results. Read some books or help(lm) to get an idea of what the outputs mean. Regards, Adai newbieR wrote: Hi all, I have a quick question about lm on group, say I have: x - 1:10 y - x*3 buckets - seq(0, 10, by=5) g - cut(x, buckets) summary(lm(y ~ g - 1)) Coefficients: Estimate Std. Error t value Pr(|t|) g(0,5] 9.000 2.121 4.243 0.00283 ** g(5,10] 24.000 2.121 11.314 3.35e-06 *** What is it doing exactly? I guess the estimate is the mean of the y's in each group. How about other stats.. what do they exactly mean when we do lm on groups? Thanks a lot! __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] fatal error unable to restore saved data in .rdata
Dear R help team, I am trying to open R to continue my analysis but it doesn't want to open and I get this message fatal error unable to restore saved data in .rdata. I don't know what went wrong ( iam using Windows). Could you please help me on this? Thanks a lot Best Regards Saad [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Failure to produce italics in jpeg
Colleagues, Using R 2.10.1 in OS X (Snow Leopard), I created JPEG documents that were intended to include italicized text. In the JPEG versions, the italics appear in bold-face. The identical code (except for the call to the device) yields italics in PDF. A minimal example is: PDF version: pdf(plot.pdf) plot(1,1) mtext(bquote(italic(P) .(0.005))) dev.off() JPEG version: jpeg(file=plot.jpeg, pointsize=12, bg=white, res=150, quality=100) plot(1,1) mtext(bquote(italic(P) .(0.005))) dev.off() I can't find any info in the help pages for either jpeg or bquote that explain this. Any ideas? Dennis Dennis Fisher MD P (The P Less Than Company) Phone: 1-866-PLessThan (1-866-753-7784) Fax: 1-866-PLessThan (1-866-753-7784) www.PLessThan.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] fatal error unable to restore saved data in .rdata
On 23/01/2010 10:56 AM, Badaoui, Saad wrote: Dear R help team, I am trying to open R to continue my analysis but it doesn't want to open and I get this message fatal error unable to restore saved data in .rdata. I don't know what went wrong ( iam using Windows). Could you please help me on this? Thanks a lot Rename the .rdata file to something else, and R won't try to open it. It looks as though somehow it has been corrupted. If it was the only place you stored your intermediate results, you're going to have to start over. But next time, don't do that. Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] first and second derivative calculation
How about?
eval( D( expression( t^3-6*t^2+5*t+30 ), t ) )
David Winsemius wrote:
On Jan 22, 2010, at 6:49 PM, Marlin Keith Cox wrote:
I can plot this just fine:
t-seq(0,4, by=.1)
y- t^3-6*t^2+5*t+30
plot(t,y ,xlab=t-values, ylab=f(t), type=l)
This is the first derivative, how I I make a similar plot?
t-seq(0,4, by=.1)
y- t^3-6*t^2+5*t+30
y1-D(expression(t^3-6*t^2+5*t+30), 't')
There might be some sort of deparse() operation that one could do on
y1, but what follows sidesteps that level of programming.
y1fn - function(t) {3 * t^2 - 6 * (2 * t) + 5}
par(new=TRUE)
plot(t, y1fn(t), ylab=, xlab=, axes=FALSE)
axis(side=4, at=seq(-7,5,by=1) )
--
David.
Thanks ahead of time.
kc
On Fri, Jan 22, 2010 at 12:41 PM, Doran, Harold hdo...@air.org
wrote:
D(expression(t^3-6*t^2+5*t + 30), 't')
3 * t^2 - 6 * (2 * t) + 5
D(D(expression(t^3-6*t^2+5*t + 30), 't'), 't')
3 * (2 * t) - 6 * 2
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org
]
On Behalf Of Marlin Keith Cox
Sent: Friday, January 22, 2010 4:37 PM
To: r-help@r-project.org
Subject: [R] first and second derivative calculation
I would like to calculate a first and second derivative and am having
problems finding a simple solution. My syntax may be off as I am
not a
mathematician, so pardon ahead of time.
data:
t-seq(0,4, by=.1)
The function is:
H(t) = t^3-6*t^2+5*t + 30
from here I plot the curve:
plot(x,y ,xlab=x-values, ylab=f(x), type=l)
But would like to similarly plot the curve for both the first and
second
derivatives.
I can calculate the derivatives by hand but would like to get R to
do this
for me.
by hand:
H'(t) = 3*t^2 - 12*t + 5
H''(t) = 6*t-12
Keith
--
M. Keith Cox, Ph.D.
Alaska NOAA Fisheries, National Marine Fisheries Service
Auke Bay Laboratories
17109 Pt. Lena Loop Rd.
Juneau, AK 99801
keith@noaa.gov
marlink...@gmail.com
U.S. (907) 789-6603
[[alternative HTML version deleted]]
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http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
M. Keith Cox, Ph.D.
Alaska NOAA Fisheries, National Marine Fisheries Service
Auke Bay Laboratories
17109 Pt. Lena Loop Rd.
Juneau, AK 99801
keith@noaa.gov
marlink...@gmail.com
U.S. (907) 789-6603
[[alternative HTML version deleted]]
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and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
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Re: [R] fatal error unable to restore saved data in .rdata
And once you've renamed the file and started R, it might be worth a try to see if you can 'attach' the file. On 23/01/2010 17:22, Duncan Murdoch wrote: On 23/01/2010 10:56 AM, Badaoui, Saad wrote: Dear R help team, I am trying to open R to continue my analysis but it doesn't want to open and I get this message fatal error unable to restore saved data in .rdata. I don't know what went wrong ( iam using Windows). Could you please help me on this? Thanks a lot Rename the .rdata file to something else, and R won't try to open it. It looks as though somehow it has been corrupted. If it was the only place you stored your intermediate results, you're going to have to start over. But next time, don't do that. Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Patrick Burns pbu...@pburns.seanet.com http://www.burns-stat.com (home of 'The R Inferno' and 'A Guide for the Unwilling S User') __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] matrix to a C function
Christophe,
That's another question for the R-devel mailing list.
A few things however.
Short answer : no it is not possible. I don't think x[i,j] is even
syntactically valid in C or C++.
I'd suggest you to give a go at the .Call interface that lets you
manipulate R objects directly. So in your example with the .Call
interface you'd only have to pass one argument and figure out the matrix
dimensions internally with the C api of R. Something like this perhaps:
SEXP pr( SEXP x ){
/* extract the dim attribute */
SEXP dim = getAttrib( x, R_DimSymbol ) ;
int nrow = INTEGER(dim)[0];
int ncol = INTEGER(dim)[1];
/* extracting the pointer just once */
double * p = REAL(x) ;
int i,j;
for( i=0; inrow; i++){
for( j=0; jncol; j++){
Rprintf( %f , p[i+nrow*j] ) ;
}
Rprintf( \\n ) ;
};
return R_NilValue ; /* NULL */
}
You can use the regular print function (called PrintValue internally),
which will nicely take care of aligning the columns properly, etc ...
SEXP pr( SEXP x ){
PrintValue( x ) ;
return( R_NilValue ) ;
}
Finally, you can use C++ through the Rcpp package and write something
like this :
SEXP pr( SEXP x){
RcppMatrixViewdouble m(x) ;
int i,j;
int nrow = m.rows() ;
int ncol = m.cols() ;
for( i=0; inrow; i++){
for( j=0; jncol; j++){
Rprintf( %f, m(i,j) ) ;
}
Rprintf( \\n ) ;
}
return R_NilValue ;
}
The indexing here is done with the round brackets here because it is
just not valid to have more than one parameters passed to operator[] in
C or C++.
Romain
On 01/23/2010 05:04 PM, Christophe Genolini wrote:
Hi the list,
Is there a way to give a matrix to a C function, and then to use it as a
matrix ?
I write a function to print a matrix, but I use it as a vector :
1. void printMatrix(double *mTraj,int *nbCol, int *nbLigne){
2. int i=0,j=0;
3. for(i=0 ; i *nbLigne ; i++){
4. for(j=0 ; j *nbCol ; j++){
5. Rprintf( %f,mTraj[i * *nbCol + j]);
6. }
7. Rprintf(\n);
8. }
9. }
I would like to use it as a matrix (line 5 changes) :
1. void printMatrix(double *mTraj,int *nbCol, int *nbLigne){
2. int i=0,j=0;
3. for(i=0 ; i *nbLigne ; i++){
4. for(j=0 ; j *nbCol ; j++){
5. Rprintf( %f,mTraj[i,j]);
6. }
7. Rprintf(\n);
8. }
9. }
It does not work, but is there an solution close to this ?
Thanks.
Christophe
--
Romain Francois
Professional R Enthusiast
+33(0) 6 28 91 30 30
http://romainfrancois.blog.free.fr
|- http://tr.im/KfKn : Rcpp 0.7.2
|- http://tr.im/JOlc : External pointers with Rcpp
`- http://tr.im/JFqa : R Journal, Volume 1/2, December 2009
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[R] ff package: ff objects don't reload completely on NFS drives from a different machine
Hi ff users and Jens, I am using the ff package and it has been working great. Recently I noticed an unexpected behavior in the ff package -- when I save an ff matrix on one machine to an NFS drive and load it on another machine from the save NFS drive, I got quote a lot of zeros in the matrix. The following code reproduces the error mat = matrix(1:25, 5) matFF = ff(mat, dim=dim(mat), dimnames = dimnames(mat), dimorder = c(2,1), filename= ~/m.ff, overwrite=TRUE) save(matFF, file = ~/mat.ff.rda) load(file = ~/mat.ff.rda) open(matFF) matFF If I execute all the six lines at one machine. Everything works fine. However, when I only execute the last three line at another machine, I got matFF ff (open) integer length=25 (25) dim=c(5,5) dimorder=c(2,1) [,1] [,2] [,3] [,4] [,5] [1,]00000 [2,]00000 [3,]00000 [4,]00000 [5,]00000 If the matrix is larger, say mat = matrix(1:2, 5), I would get the following -- dozens of zeros at the end. ff (open) integer length=2 (2) dim=c(5,4000) dimorder=c(2,1) [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,3993] [,3994] [,3995] [,3996] [,3997] [,3998] [,3999] [,4000] [1,] 1 6111621263136 : 19961 19966 19971 19976 19981 19986 19991 19996 [2,] 2 7121722273237 : 19962 19967 19972 19977 19982 19987 19992 19997 [3,] 3 8131823283338 : 19963 19968 19973 19978 19983 19988 19993 19998 [4,] 4 9141924293439 : 19964 19969 19974 19979 19984 19989 19994 1 [5,] 510152025303540 : 0 0 0 0 0 0 0 0 I tried set caching = mmeachflush in the ff function but it doesn't help. My computing enrionment is linux 64 bit, R 2.10, ff 2.1. If you know what causes the issue or how to solve it, please let me know. I highly appreciate. Jeff __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to apply a function on each column of a matrix
Hello everyone, I get for each date a measure for n elements in the form of a matrix. I am converting it to a ts object using ts(). I want to apply a function on each column. I started using the apply function ( set to 2) but what it returns is a matrix with the same columns representing the function applied on the last column of the initial matrix. I have been trying to use the sapply function or an apply in an apply but didn't get it to work the way I wanted. Have anyone any idea about it? -- View this message in context: http://n4.nabble.com/How-to-apply-a-function-on-each-column-of-a-matrix-tp1288436p1288436.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to implement a select distinct x, count(distinct y) ... group by x for a data frame
... Being an R newbie, I can only think of extracting distinct x values with unique, looping over them, extracting matching rows from the original data frame, applying table, and recording the size of table's output alongside the x value being checked. Is there a more elegant way? Thank you. -- View this message in context: http://n4.nabble.com/How-to-implement-a-select-distinct-x-count-distinct-y-group-by-x-for-a-data-frame-tp1288418p1288418.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] lattice ltext
Dear friends - please give me a hand.
I have a dataset of 40 patients in two groups observed on three
occasions. I only want to plot a line
for each patient in the two groups. I use the ltext function to put the
patient number but fail to make lattice understand the numbers as
unique since apparently it starts all over with 1:20 for each panel
instead of respecting my desires to have 1:20 and then 21:40.
I'm on windows vista, R2.9.2
Best wishes
Troels
score - runif(120,0,100)
pt - gl(40,3,120)
times - rep(c(0,3,6),40)
trt - gl(2,60,120)
ach - data.frame(score=score,pt=pt,times=times,trt=trt)
myPanel - function(x,y,...){
panel.xyplot(x,y,...)
ltext(x-.1,y+1,paste(pt),cex=0.5) }
xyplot(score~times|trt,groups=pt,type=c(p,l),ach,
panel=myPanel)
--
Troels Ring
Department of nephrology
Aalborg Hospital
Mølleparkvej
phone: +4599326629
Heliosvej 12
9210 Aalborg SØ
98140582
30480176
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Re: [R] How to apply a function on each column of a matrix
Here is the last code that I wrote but it would give me the same problem: I have the matrix mat with n columns mat.1, mat.2 ...mat.n #To be able to use lapply I convert it to a data.frame: mat - data.frame(mat) lapply(mat, function, argument of function) It works but I still get for all elements the function applied for the last element. The elements of my results are all the same I don't understand I did exactly as shown on this website: http://www.ats.ucla.edu/stat/r/library/advanced_function_r.htm#lapply -- View this message in context: http://n4.nabble.com/How-to-apply-a-function-on-each-column-of-a-matrix-tp1288436p1288471.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Rotating the axis labels in the basic graphic device ?
On 01/24/2010 03:25 AM, Tal Galili wrote: Marc, Following the R FAQ you linked to, I wonder how to ALWAYS have the text and the plot region fit. I know that if the text is too long, one can use the par(mar = c(big.number, 4, 4 ,4)) and get the text to fit. The question is: Is there a way to make the plot know what big.number should be so the text wouldn't go beyond plot regions ? Hi Tal, I've been working on this, as it often appears on the help list. The function getMarginWidth in the plotrix package tries to solve the common problem of fitting text or legends in the margins of the plot. I would like to improve this function and perhaps extend it so that the user can specify an area in which something must fit and get the appropriate par argument to use. All suggestions are welcome. Jim __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to implement a select distinct x, count(distinct y) ... group by x for a data frame
Yes. ?sqldf ?split ?lapply But unless you provide commented, minimal, self-contained, reproducible code, it is hard to say how to proceed to a solution. On Sat, Jan 23, 2010 at 5:46 PM, Dimitri Shvorob dimitri.shvo...@gmail.com wrote: ... Being an R newbie, I can only think of extracting distinct x values with unique, looping over them, extracting matching rows from the original data frame, applying table, and recording the size of table's output alongside the x value being checked. Is there a more elegant way? Thank you. -- View this message in context: http://n4.nabble.com/How-to-implement-a-select-distinct-x-count-distinct-y-group-by-x-for-a-data-frame-tp1288418p1288418.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to apply a function on each column of a matrix
On 01/24/2010 11:11 AM, anna wrote: Here is the last code that I wrote but it would give me the same problem: I have the matrix mat with n columns mat.1, mat.2 ...mat.n #To be able to use lapply I convert it to a data.frame: mat- data.frame(mat) lapply(mat, function, argument of function) It works but I still get for all elements the function applied for the last element. The elements of my results are all the same I don't understand I did exactly as shown on this website: http://www.ats.ucla.edu/stat/r/library/advanced_function_r.htm#lapply Hi anna, If you could post your matrix mat (or something else that produces the problem you describe if mat is private or too big) and the commands you used, someone will probably figure out what is going wrong. Jim __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] ff package: ff objects don't reload completely on NFS drives from a different machine
Hi, this could be due to how NFS works. Note that there can be up to a 30 second delay before other hosts on the same file system see the updates that was flushed by one machine. You basically cannot treat files on an shared NFS file system as if you are working on a single machine. You have to add some higher protection if your data sources should be shared ...and that is not an easy problem if you want it to be bullet proof. You need to use a semaphore/mutex or other ways to communicate when files are updated/flushed/read etc. I'm still looking for a such a mechanism done over a file system that is bullet proof (without having to relying on a central server). My $.02 /Henrik On Sat, Jan 23, 2010 at 12:02 PM, Hao Cen h...@andrew.cmu.edu wrote: Hi ff users and Jens, I am using the ff package and it has been working great. Recently I noticed an unexpected behavior in the ff package -- when I save an ff matrix on one machine to an NFS drive and load it on another machine from the save NFS drive, I got quote a lot of zeros in the matrix. The following code reproduces the error mat = matrix(1:25, 5) matFF = ff(mat, dim=dim(mat), dimnames = dimnames(mat), dimorder = c(2,1), filename= ~/m.ff, overwrite=TRUE) save(matFF, file = ~/mat.ff.rda) load(file = ~/mat.ff.rda) open(matFF) matFF If I execute all the six lines at one machine. Everything works fine. However, when I only execute the last three line at another machine, I got matFF ff (open) integer length=25 (25) dim=c(5,5) dimorder=c(2,1) [,1] [,2] [,3] [,4] [,5] [1,] 0 0 0 0 0 [2,] 0 0 0 0 0 [3,] 0 0 0 0 0 [4,] 0 0 0 0 0 [5,] 0 0 0 0 0 If the matrix is larger, say mat = matrix(1:2, 5), I would get the following -- dozens of zeros at the end. ff (open) integer length=2 (2) dim=c(5,4000) dimorder=c(2,1) [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,3993] [,3994] [,3995] [,3996] [,3997] [,3998] [,3999] [,4000] [1,] 1 6 11 16 21 26 31 36 : 19961 19966 19971 19976 19981 19986 19991 19996 [2,] 2 7 12 17 22 27 32 37 : 19962 19967 19972 19977 19982 19987 19992 19997 [3,] 3 8 13 18 23 28 33 38 : 19963 19968 19973 19978 19983 19988 19993 19998 [4,] 4 9 14 19 24 29 34 39 : 19964 19969 19974 19979 19984 19989 19994 1 [5,] 5 10 15 20 25 30 35 40 : 0 0 0 0 0 0 0 0 I tried set caching = mmeachflush in the ff function but it doesn't help. My computing enrionment is linux 64 bit, R 2.10, ff 2.1. If you know what causes the issue or how to solve it, please let me know. I highly appreciate. Jeff __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to implement a select distinct x, count(distinct y) ... group by x for a data frame
Regarding your subject, the sqldf package on CRAN allows you to apply SQL statements directly to R data frames. http://sqldf.googlecode.com On Sat, Jan 23, 2010 at 5:46 PM, Dimitri Shvorob dimitri.shvo...@gmail.com wrote: ... Being an R newbie, I can only think of extracting distinct x values with unique, looping over them, extracting matching rows from the original data frame, applying table, and recording the size of table's output alongside the x value being checked. Is there a more elegant way? Thank you. -- View this message in context: http://n4.nabble.com/How-to-implement-a-select-distinct-x-count-distinct-y-group-by-x-for-a-data-frame-tp1288418p1288418.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data import export zipped files from URLs
http://nseindia.com/content/equities/scripvol/datafiles/01-01-2010-TO-23-01-2010RCOMXN.csv the url is correct. it is not zipped file. copy the url in the browser window you will get the this .. Symbol,Series,Date, Prev Close,Open Price,High Price,Low Price,Last Price,Close Price,Average Price,Total Traded Quantity,Turnover in Lacs, RCOM,EQ,04-Jan-2010,172.35,173,175.8,172.55,175.25,175.2,174.17,2418999,4213.1160435, RCOM,EQ,05-Jan-2010,175.2,176,182,175.8,181.45,181.35,178.64,6033757,10778.7459905, RCOM,EQ,06-Jan-2010,181.35,182.5,184.4,180.8,181.5,181.8,182.76,4680776,8554.525768, RCOM,EQ,07-Jan-2010,181.8,183.7,185.3,182.5,183.8,183.9,184.05,4255338,7831.773937, RCOM,EQ,08-Jan-2010,183.9,184.5,185.15,180.2,181.1,180.85,182.14,3775898,6877.5970215, RCOM,EQ,11-Jan-2010,180.85,184,184,180.2,181.85,182.1,182.04,3601269,6555.8894695, RCOM,EQ,12-Jan-2010,182.1,182.1,182.85,175.05,175.3,175.45,179.06,4834928,8657.6031315, RCOM,EQ,13-Jan-2010,175.45,174,176.6,173.05,175.7,175.55,175.01,3276310,5733.8242525, RCOM,EQ,14-Jan-2010,175.55,177.2,184.2,175.65,182.85,183,180.8,7227593,13067.2365775, RCOM,EQ,15-Jan-2010,183,183,193.4,183,191.3,191.6,191.03,15459863,29533.7056915, RCOM,EQ,18-Jan-2010,191.6,189.9,193.8,188.35,190.05,190.45,191.27,4710277,9009.3851875, RCOM,EQ,19-Jan-2010,190.45,190,192.9,185.2,186.5,186.35,188.67,4458474,8411.945425, RCOM,EQ,20-Jan-2010,186.35,187,190.6,185.3,186.6,186.9,188.05,3581194,6734.2921825, RCOM,EQ,21-Jan-2010,186.9,186.85,189.75,184.15,185.3,185.15,186.85,3673061,6863.2499155, RCOM,EQ,22-Jan-2010,185.15,183.7,184.7,176.45,181.6,181.55,181.5,4194634,7613.198626, __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to apply a function on each column of a matrix
On 24-Jan-10 00:27:37, Jim Lemon wrote:
On 01/24/2010 11:11 AM, anna wrote:
Here is the last code that I wrote but it would give me the
same problem:
I have the matrix mat with n columns mat.1, mat.2 ...mat.n
#To be able to use lapply I convert it to a data.frame:
mat- data.frame(mat)
lapply(mat, function, argument of function)
It works but I still get for all elements the function applied
for the last element. The elements of my results are all the
same I don't understand I did exactly as shown on this website:
http://www.ats.ucla.edu/stat/r/library/advanced_function_r.htm#lapply
Hi anna,
If you could post your matrix mat (or something else that
produces the problem you describe if mat is private or too big)
and the commands you used, someone will probably figure out what
is going wrong.
Jim
I agree with Jim's comments. It may help to formulate your reply
to considet the following simple case of applying a function on
each column of a matrix:
X2 - function(x){ x^2 }
M - matrix(c(1,2,3,4,5,6,7,8,9),nrow=3)
M
# [,1] [,2] [,3]
# [1,]147
# [2,]258
# [3,]369
X2 - function(x){ x^2 }
apply(M,2,X2)
# [,1] [,2] [,3]
# [1,]1 16 49
# [2,]4 25 64
# [3,]9 36 81
SX2 - function(x){ sum(x^2) }
apply(M,2,SX2)
# [1] 14 77 194
Not ythe use of apply(), not lapply(); also that the result is
not a matrix (with 1 row) but a vector (dimensionless):
dim(apply(M,2,SX2))
# NULL
If you want the result to be a 1-row vector, then you need to
force this explicitly:
N - apply(M,2,SX2)
# dim(N)-c(1,3)
N
# [,1] [,2] [,3]
# [1,] 14 77 194
or (in this case) more simply:
rbind(NULL,apply(M,2,SX2))
# [,1] [,2] [,3]
# [1,] 14 77 194
If that approach does not work with your matrix and your function,
then there must be something special about one or the other!
Ted.
E-Mail: (Ted Harding) ted.hard...@manchester.ac.uk
Fax-to-email: +44 (0)870 094 0861
Date: 24-Jan-10 Time: 00:49:12
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[R] End of File for binary files
Hello, I'm new to R and I'm writing a function to read binary tables (the binary version of read.table essentially). I'm having trouble figuring out how to determine when I reach end-of-file. Can anybody please help? thanks! -- View this message in context: http://n4.nabble.com/End-of-File-for-binary-files-tp1288509p1288509.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] End of File for binary files
If you are reading a 'binary' file, then the end of file is when you read the last byte; the system will tell you. Exactly what are you trying do to? When you do a read, you typically request the number of bytes to read and then the system returns the number of bytes read. But since you did not give an indication of what/how you are trying to do this, it is hard to make an exact suggestion. Did you have some experience that you think you did not get an end of file indication? More information is required. On Sat, Jan 23, 2010 at 9:40 PM, rn00b forzat...@gmail.com wrote: Hello, I'm new to R and I'm writing a function to read binary tables (the binary version of read.table essentially). I'm having trouble figuring out how to determine when I reach end-of-file. Can anybody please help? thanks! -- View this message in context: http://n4.nabble.com/End-of-File-for-binary-files-tp1288509p1288509.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] header files for R packages
I have 6 or 7 nice constants (for example 1852 meters per nautical mile) I would like to have available to 4 or 5 functions in an R package. In C this would just be a header .h file and I would just include I am stuck trying to figure out how to create something like a C header file for an R package. Any ideas? __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] End of File for binary files
I am using readBin to continuously read characters from the binary file. I'm
trying to figure out how many characters are in the file. What I would like
to do is something like
(while! EOF)
{
charRead -.Internal(readBin(con,character,1L,NA,TRUE,swap))
i++
}
I'm not clear on how to determine the EOF condition in this case.
--
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Re: [R] End of File for binary files
Are you really trying to read in binary? You are asking for
characters which would be a null terminated string. If you are trying
to read in binary zeroes, this will not work. What you need to do is
to use 'raw'. Actually you should create a R script to test out the
various conditions you want. If you use 'raw', this will read in the
actual bytes in the file. You can check to see if the length of the
vector is what you requested. If it is not, then you have reached an
end of file. It is easy enough to try out the various options to see
what happens. So if you are trying to read binary, then use 'raw'.
If you are reading null terminated strings, then 'character' will
work. If your file consists of binary integers, then use 'integer'
and make sure you know if the 'endian' of the data. There are lots of
other cases/conditions depending on what you are trying to do.
On Sat, Jan 23, 2010 at 10:40 PM, rn00b forzat...@gmail.com wrote:
I am using readBin to continuously read characters from the binary file. I'm
trying to figure out how many characters are in the file. What I would like
to do is something like
(while! EOF)
{
charRead -.Internal(readBin(con,character,1L,NA,TRUE,swap))
i++
}
I'm not clear on how to determine the EOF condition in this case.
--
View this message in context:
http://n4.nabble.com/End-of-File-for-binary-files-tp1288509p1288525.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Feature selection
Hi, Could you please tell me whether there are feature selection algorithms in R or not such as genetic algorithms? If so, could you please tell me in which package? Cheers, Amy _ View photos of singles in your area! Browse profiles for FREE [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] tree()...binary reponse giving only one split
Hi, I'm new to CART. I have a data set with a binary reponse (0/1) and several predictors. I chose 2 continuous predictors to start and used the following code. testdata.ltr-tree(nondev85dev06~dist_rampm_wa + dis_prim_wa,testdata) The two predictors should be quite explanatory based upon previous work. After running this code, I am getting only one split using the first predictor listed. I've tried this with other sets of 2 and 3 predictors and it is always the same case, only one is used for a single split. I thought perhaps it was the binary nature of my data set. So, I constructed another where the response was 0,1, or 2. I got the same result. I've also tried the same experiment with predictors that are binary and got the same results. I've searched the help but can't find any answers. Thanks. Seth -- View this message in context: http://n4.nabble.com/tree-binary-reponse-giving-only-one-split-tp1288546p1288546.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
