Re: [R] cross-validation in plsr package

2010-02-22 Thread Bjørn-Helge Mevik
Peter Tillmann peter.tillm...@t-online.de writes:

 can anyone give an example how to use cross-validation in the plsr package.

There are examples in the references cited on
http://mevik.net/work/software/pls.html

 I miss to find the number of factors proposed by cross-validation as
 optimum.

The cross-validation in the pls package does not propose a number of
factors as optimum, you have to select this yourself.  (The reason for
this is that there is AFAIK no theoretically founded and widely accepted
way of doing this automatically.  I'd be happy to learn otherwise.)

-- 
Regards,
Bjørn-Helge Mevik

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[R] RExcel + RCOM + Linux

2010-02-22 Thread Philipp Rappold

Dear all,

does anyone know if it is possible to connect a Windows RExcel 
instance to a linux R instance?


Within Rexcel, I find the option Remote Server Address, but I 
wonder what the installation procedure on my linux (ubuntu) R looks 
like (if possible at all)?


Thanks
Philipp

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Re: [R] Error of Stepwise Regression with number of rows in use has changed: remove missing values?

2010-02-22 Thread Kum-Hoe Hwang
This solution such as  data-na.omit(original database) before you
run step() or stepAIC() has some limitations, I think. I reduced the
number of data lines, and it enhance R square value.

If you have some tips or advices for another solution, I welcome.

Kum

Urban and Regional Planning, GRI


On Sat, Feb 20, 2010 at 5:57 AM, Greg Snow greg.s...@imail.org wrote:
 Have you considered the implications of that solution?

 --
 Gregory (Greg) L. Snow Ph.D.
 Statistical Data Center
 Intermountain Healthcare
 greg.s...@imail.org
 801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Kum-Hoe Hwang
 Sent: Wednesday, February 17, 2010 1:41 AM
 To: r-help@r-project.org
 Subject: Re: [R] Error of Stepwise Regression with number of rows in
 use has changed: remove missing values?

 I thank those who helped to solve a error in stepwise regression with
 missing values.


 Kum

 *
 *

 A good solution that I have tried was Andreas's advice.

 =

 Try

 data-na.omit(original database) before you run step() or stepAIC()

 On Tue, Feb 16, 2010 at 8:09 PM, Peter Ehlers ehl...@ucalgary.ca
 wrote:

  On 2010-02-16 1:24, Kum-Hoe Hwang wrote:
 
  Howdy, R Grues
 
  I have enjoyed R, but I cannot solve one problem easily. Please help
 my
  problem.
  When I tried the R script, I got the following Error. This error
  results from input data file exported through a Excel spreadsheet
  software.
 
   Error in step(lm(pop.rate ~ as.numeric(year) + as.factor(policy) +
  as.numeric(nation.grant) +  :
    number of rows in use has changed: remove missing values?
 
  Could you direct me to solve the Error?
  Thanks in advance,
 
 
  This is a common situation when you use step() on data where
  the predictors have missing values.
 
  A case (row) is included in the model only if all the
  predictors for that model are non-missing for the case.
 
  As you vary which predictors are to be in the model, the
  included cases will vary, resulting in models based on
  different data. (Think of your cases as subjects; you want
  all your models to be based on the same set of subjects.)
 
  Finally: (Re-)read the help page and note the 'warning'.
 
   -Peter Ehlers
 
 
 
 
   ### outputs from R console ###
  pop- step(
 
  +             lm(pop.rate ~ as.numeric(year) + as.factor(policy) +
  as.numeric(nation.grant)
  +                + as.numeric(do.grant) + as.numeric(city.grant) +
  as.numeric(DMZ.dist) + as.numeric(Seoul.dist), data=borderI.data,
  na.action = na.omit)
  +             )
  Start:  AIC=494.27
  pop.rate ~ as.numeric(year) + as.factor(policy) +
 as.numeric(nation.grant)
  +
      as.numeric(do.grant) + as.numeric(city.grant) +
 as.numeric(DMZ.dist) +
      as.numeric(Seoul.dist)
                             Df Sum of Sq    RSS    AIC
  - as.numeric(do.grant)      1      0.71 6622.9 492.28
  - as.factor(policy)         1      1.21 6623.4 492.29
  - as.numeric(DMZ.dist)      1      1.91 6624.1 492.30
  - as.numeric(city.grant)    1      5.07 6627.3 492.36
  - as.numeric(nation.grant)  1     11.51 6633.7 492.47
  - as.numeric(year)          1     29.58 6651.8 492.80
  none                                    6622.2 494.27
  - as.numeric(Seoul.dist)    1    673.22 7295.4 503.79
  Step:  AIC=492.28
  pop.rate ~ as.numeric(year) + as.factor(policy) +
 as.numeric(nation.grant)
  +
      as.numeric(city.grant) + as.numeric(DMZ.dist) +
 as.numeric(Seoul.dist)
                             Df Sum of Sq    RSS    AIC
  - as.factor(policy)         1      1.99 6624.9 490.32
  - as.numeric(DMZ.dist)      1      2.09 6625.0 490.32
  - as.numeric(city.grant)    1      7.18 6630.1 490.41
  - as.numeric(nation.grant)  1     20.08 6643.0 490.64
  - as.numeric(year)          1     28.89 6651.8 490.80
  none                                    6622.9 492.28
  - as.numeric(Seoul.dist)    1    697.46 7320.4 502.20
  Step:  AIC=490.32
  pop.rate ~ as.numeric(year) + as.numeric(nation.grant) +
  as.numeric(city.grant) +
      as.numeric(DMZ.dist) + as.numeric(Seoul.dist)
                             Df Sum of Sq    RSS    AIC
  - as.numeric(DMZ.dist)      1      2.08 6627.0 488.35
  - as.numeric(city.grant)    1     10.65 6635.6 488.51
  - as.numeric(nation.grant)  1     31.30 6656.2 488.88
  - as.numeric(year)          1     31.44 6656.4 488.88
  none                                    6624.9 490.32
  - as.numeric(Seoul.dist)    1    732.88 7357.8 500.80
  Step:  AIC=488.35
  pop.rate ~ as.numeric(year) + as.numeric(nation.grant) +
  as.numeric(city.grant) +
      as.numeric(Seoul.dist)
                             Df Sum of Sq    RSS    AIC
  - as.numeric(city.grant)    1      9.86 6636.9 486.53
  - as.numeric(year)          1     31.42 6658.4 486.92
  - as.numeric(nation.grant)  1     33.33 6660.3 486.95
  none                                    6627.0 488.35
  - as.numeric(Seoul.dist)  

Re: [R] cross-validation in plsr package

2010-02-22 Thread Peter Tillmann

Kjaere Bjørn-Helge,
 
   can anyone give an example how to use cross-validation in the plsr 
 package.
 
 There are examples in the references cited on
 http://mevik.net/work/software/pls.html
 
   I miss to find the number of factors proposed by cross-validation as
   optimum.
 
 The cross-validation in the pls package does not propose a number of
 factors as optimum, you have to select this yourself.  (The reason for
 this is that there is AFAIK no theoretically founded and widely accepted
 way of doing this automatically.  I'd be happy to learn otherwise.)

tusend takk.

Vi i NIRS bruker CV for a bestemme antall faktorer i PLS, derfor lurer 
jeg paa en foreslag fra CV. Men klart vi er bare brukerer ikke 
statistiker i samenheng med PLS.


Hilsen

Peter
*
Espenauer Str. 28, D-34246 Vellmar, Deutschland


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[R] Odp: new to R Project

2010-02-22 Thread Petr PIKAL
Hi

r-help-boun...@r-project.org napsal dne 22.02.2010 08:49:01:

 
 hi everyone,
 i am new to R project can anyone please help me by providing 
documents

If you already succeeded to install R it has installed into some 
directory. Use means of your operating system (maybe Windows?) to find 
where it is. In a doc folder of R directory (maybe R-2.10.1) you find many 
documents and If you bother to read at least R Intro you will get answers 
to many of your questions.

I am not sure where you get R. If from CRAN there is also extensive set of 
various documents together with some books you can buy.

And last but not least when starting R you can use help provided with 
system simply by questioning required function

?plot

Regards
Petr



 
 my goal is using R i have to connect to the database and i have to 
generate
 reports.
 
 Thanks in advance
 chinna.
 -- 
 View this message in context: http://n4.nabble.com/new-to-R-Project-
 tp1564104p1564104.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
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 PLEASE do read the posting guide 
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 and provide commented, minimal, self-contained, reproducible code.

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Re: [R] how to generate graph from dataframe?

2010-02-22 Thread Paul Hiemstra

chinna wrote:

I connected to database  and i am accessing the tables  but i dont know how
to generate graphs from the database tables.

can anyone please help me
 i am new to R project
  

Hi,

Take a look at the plot() command. Or you can have a look at the lattice 
or ggplot2 packages. The book R graphics by Paul Murrel is a good book 
on R graphics.


cheers,
Paul

--
Drs. Paul Hiemstra
Department of Physical Geography
Faculty of Geosciences
University of Utrecht
Heidelberglaan 2
P.O. Box 80.115
3508 TC Utrecht
Phone:  +3130 274 3113 Mon-Tue
Phone:  +3130 253 5773 Wed-Fri
http://intamap.geo.uu.nl/~paul

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[R] plotrix 2.8-3

2010-02-22 Thread Jim Lemon

Hi all,
I'm announcing this version of plotrix because I have made a couple of 
changes that will affect users. Although the function that used to be 
known as hierobarp is fairly new, there may be some users who are 
surprised when they find that it has changed its name to barNest. I will 
probably rename the two functions hierobarp.svymean and 
hierobarp.svyprop in the next version to barNest.* as well.


The other major changes are to the pyramid.plot function. A recent 
exchange with a user led to new options to use different category labels 
for the left and right bars and to place the category labels and values 
outside the bars. So there are a couple of new arguments and options. 
The help page and examples should make these clear. If not, you all know 
my email address. Have fun.


Jim

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[R] Single character input without Enter

2010-02-22 Thread Dieter Menne
How do I wait for a single character input without terminating Enter?

Following Brian Ripley on 

http://markmail.org/message/ptmbkhdfnpnf5zcd

In general R does not have a character-by-character interface with a
keyboard.

Dieter

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[R] bug in R 2.10.1 html help

2010-02-22 Thread Tristan Allouis

I'm running R 2.10.1 on a GNU/Linux Debian Squeeze (testing)

I type :
 help.start()

I get :
starting httpd help server ... Terminé.
Si 'xdg-open' est déjà lancé, il ne sera pas relancé, et vous devez
   passer à sa fenêtre.
Sinon, soyez patient...
I think the translation is :

If '/usr/bin/xdg-open' is already running, it is *not* restarted, and
   you must switch to its window.
Otherwise, be patient ...


Iceweasel starts and I get the page 
http://127.0.0.1:28025/doc/html/index.html


Now I type :
 ?plot

It does not opens the help page in Iceweasel. It starts the R 
documentation in my terminal.


To fix the problem :
Create a .Rprofile file in your home/'user' directory containing the 
following command :

options(help_type=html)

I hope it will help.

Tristan

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[R] how do I calculate means or cov matrix for multivariate groups

2010-02-22 Thread mirauta

Hello,

Having the matrix d
 d
   value value2 class
1  1  1 x
2  2  2 x
3  3  3 x
4  4  2 x
5  5  1 y
6 11  3 y
7 12  4 z
8 13  5 z
9 14  6 z
1015  7 z

I want to calculate the means and cov matrix for groups x,y,z.
I know how to do it the long way.
I tried to use tapply and kmeans but no good results.
(tapply is a good solution for only 1 variable)


Thank you

Bogdan


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Re: [R] plotrix 2.8-3

2010-02-22 Thread Tal Galili
Hi Jim,
I just went thorough the demo(plotrix) , what amazing work you have done
there, thank you!

Tal


Contact
Details:---
Contact me: tal.gal...@gmail.com |  972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
--




On Mon, Feb 22, 2010 at 11:08 AM, Jim Lemon j...@bitwrit.com.au wrote:

 Hi all,
 I'm announcing this version of plotrix because I have made a couple of
 changes that will affect users. Although the function that used to be known
 as hierobarp is fairly new, there may be some users who are surprised when
 they find that it has changed its name to barNest. I will probably rename
 the two functions hierobarp.svymean and hierobarp.svyprop in the next
 version to barNest.* as well.

 The other major changes are to the pyramid.plot function. A recent exchange
 with a user led to new options to use different category labels for the left
 and right bars and to place the category labels and values outside the bars.
 So there are a couple of new arguments and options. The help page and
 examples should make these clear. If not, you all know my email address.
 Have fun.

 Jim

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


[[alternative HTML version deleted]]

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Re: [R] how do I calculate means or cov matrix for multivariate groups

2010-02-22 Thread Dennis Murphy
Hi:

Here are three ways, but there are others:

# (1)
# package doBy:

library(doBy)
summaryBy(value + value2 ~ class, data = df)
  class value.mean value2.mean
1 x2.5 2.0
2 y8.0 2.0
3 z   13.5 5.5

# (2)  aggregate():

with(df, aggregate(list(val1 = value, val2 = value2), list(class), FUN =
mean))
  Group.1 val1 val2
1   x  2.5  2.0
2   y  8.0  2.0
3   z 13.5  5.5

# plyr solution
library(plyr)
ddply(df, .(class), summarise, val1 = mean(value), val2 = mean(value2))
  class val1 val2
1 x  2.5  2.0
2 y  8.0  2.0
3 z 13.5  5.5

HTH,
Dennis

On Mon, Feb 22, 2010 at 1:13 AM, mirauta bmira...@yahoo.com wrote:


 Hello,

 Having the matrix d
  d
   value value2 class
 1  1  1 x
 2  2  2 x
 3  3  3 x
 4  4  2 x
 5  5  1 y
 6 11  3 y
 7 12  4 z
 8 13  5 z
 9 14  6 z
 1015  7 z

 I want to calculate the means and cov matrix for groups x,y,z.
 I know how to do it the long way.
 I tried to use tapply and kmeans but no good results.
 (tapply is a good solution for only 1 variable)


 Thank you

 Bogdan


 --
 View this message in context:
 http://n4.nabble.com/how-do-I-calculate-means-or-cov-matrix-for-multivariate-groups-tp1564157p1564157.html
 Sent from the R help mailing list archive at Nabble.com.

 __
 R-help@r-project.org mailing list
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 http://www.R-project.org/posting-guide.html
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[[alternative HTML version deleted]]

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[R] rownames cannot allocate vector of size

2010-02-22 Thread Larson, TR

Hi,

On R 2.10.1 for Windows, when I do the following to duplicate the 
structure of a large numeric matrix called matrix1:


matrix2 - matrix(0,nrow=nrow(matrix1),ncol=ncol(matrix1))

and then

rownames(matrix2) - rownames(matrix1)

I get a cannot allocate vector of size xxMb error

but if I instead do:

rnames - list()
rnames - rownames(matrix1)
matrix2 - matrix(0,nrow=nrow(matrix1),ncol=ncol(matrix1),dimnames=rnames)

I get no error.

Of course both approaches work in R on Unix without memory limits.  But 
I'm intrigued about the apaprent difference in memory usage/allocation 
for the two above approaches. Is there any explanation for this 
difference in behaviour?


thanks
Tony

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Re: [R] rownames cannot allocate vector of size

2010-02-22 Thread Benilton Carvalho
assigning rownames (after the object is created) triggers a copy of
the object... if you assign the rownames at creation time, no extra
copies...

b

On Mon, Feb 22, 2010 at 9:46 AM, Larson, TR t...@york.ac.uk wrote:
 Hi,

 On R 2.10.1 for Windows, when I do the following to duplicate the structure
 of a large numeric matrix called matrix1:

 matrix2 - matrix(0,nrow=nrow(matrix1),ncol=ncol(matrix1))

 and then

 rownames(matrix2) - rownames(matrix1)

 I get a cannot allocate vector of size xxMb error

 but if I instead do:

 rnames - list()
 rnames - rownames(matrix1)
 matrix2 - matrix(0,nrow=nrow(matrix1),ncol=ncol(matrix1),dimnames=rnames)

 I get no error.

 Of course both approaches work in R on Unix without memory limits.  But I'm
 intrigued about the apaprent difference in memory usage/allocation for the
 two above approaches. Is there any explanation for this difference in
 behaviour?

 thanks
 Tony

 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] (Somewhat) broken EPS files produced

2010-02-22 Thread Paul Hiemstra

Hi Wartan,

Not really an answer to your specific problem, but you could try to use 
pdf instead of eps, in combination ofcourse with pdflatex. I've never 
had problems with pdf nad Sweave. If you need to use eps, than my reply 
is of no help to you :).


cheers,
Paul

Wartan Hachaturow wrote:

Hello.

I'm writing some simple text using sweave, and faced a strange problem
with eps files produced for my plots (one example attached).
Individual eps files are interpreted by ghostscript just fine, and
show up without errors. But once I try to include them into main
LaTeX/Sweave document (using regular \includegraphics, produced by
Sweave),
ghostscript gives me this error on those files:

Error: /undefinedresult in --stringwidth--
Operand stack:
   (600)   0.5
Execution stack:
   %interp_exit   .runexec2   --nostringval--   --nostringval--
--nostringval--   2   %stopped_push   --nostringval--
--nostringval--   --nostringval--   false   1   %stopped_push   1878
1   3   %oparray_pop   1877   1   3   %oparray_pop   1861   1   3
%oparray_pop   1755   1   3   %oparray_pop   --nostringval--
%errorexec_pop   .runexec2   --nostringval--   --nostringval--
--nostringval--   2   %stopped_push   --nostringval--
--nostringval--
Dictionary stack:
   --dict:1157/1684(ro)(G)--   --dict:0/20(G)--   --dict:82/200(L)--
--dict:178/300(L)--   --dict:91/200(L)--
Current allocation mode is local
Current file position is 207944
GPL Ghostscript 8.71: Unrecoverable error, exit code 1

What might be the problem?

P.S. I get exactly the same behavior on Debian/sid and OS X.

  



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--
Drs. Paul Hiemstra
Department of Physical Geography
Faculty of Geosciences
University of Utrecht
Heidelberglaan 2
P.O. Box 80.115
3508 TC Utrecht
Phone:  +3130 274 3113 Mon-Tue
Phone:  +3130 253 5773 Wed-Fri
http://intamap.geo.uu.nl/~paul

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Re: [R] how do I calculate means or cov matrix for multivariate groups

2010-02-22 Thread mirauta

Thanks,

These functions solve 1 problem ( the mean).
I tried to use them also for the cov matrix but I didn't succed.
Is there any way to calculate the cov matrix for groups?

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[R] Generating reports from database

2010-02-22 Thread chinna

MY REQUIREMENT:

I have a database and i want to connect to the database through R Project
and using the tables from the database i need to generate the reports.

can anyone plese tell me whether this is possible with  R project or not.

Thanks in advance
Chinna.
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Re: [R] Generating reports from database

2010-02-22 Thread Cedrick W. Johnson

List Requirements:

PLEASE do read the posting guide [1]http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


   With that said.. We need a *bit* more information What database are you
   connecting   to?   MySQL?   MSSQL?   Are   you   on   Windows?  Linux?
   [2]https://stat.ethz.ch/mailman/listinfo/r-sig-db  With  a  lil bit of
   Googling, I found: [3]http://www.statmethods.net/input/dbinterface.html
   which highlights RODBC and the other access methods for retrieving data from
   DBMS's for use in R. I personally use RODBC and RMySQL for working with
   data. Regards, -cedrick On 2/22/2010 5:38 AM, chinna wrote:

MY REQUIREMENT:

I have a database and i want to connect to the database through R Project
and using the tables from the database i need to generate the reports.

can anyone plese tell me whether this is possible with  R project or not.

Thanks in advance
Chinna.

References

   1. http://www.R-project.org/posting-guide.html
   2. https://stat.ethz.ch/mailman/listinfo/r-sig-db
   3. http://www.statmethods.net/input/dbinterface.html
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Re: [R] Generating reports from database

2010-02-22 Thread chinna

we r using teradata database and through R Project we have to access tables
from teradata database and we need to generate graphs using that
dataand also we need forecasted results of that data 

...can please tell me the possible ways.


Thanks in advance


Regards
Chinna
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[R] cmdscale error message - k' must be in {1, 2, .. n - 1}

2010-02-22 Thread Sigbert Klinke
Hi,

I got the error message:

Error in cmdscale(1 - similarity, k = 1) :
  'k' must be in {1, 2, ..  n - 1}

It turned out that similarity was just a scalar and therefore n-1 = 0 :(

Maybe the error message could be improved.

Bset Sigbert

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Re: [R] BMDP and SAS (was R in clinical trials)

2010-02-22 Thread Heinz Tuechler
Once I suggested to BMDP to introduce a module-statement that would 
direct the syntax to the specified module (1L, 2L, ...), so that all 
syntax could reside in one job, but they did not like that idea.


Heinz

At 14:55 19.02.2010, Terry Therneau wrote:

  I used both BMDP and SAS in my earlier years, side by side.  At that
time the BMDP statistical methods were much more mature and
comprehensive: we treated them as the standard when the two packages
disagreed.  (It was a BMDP manual that clearly explained to me what the
hypothesis of Yate's weighted mean test is, something SAS decided to
call type III and eternally obfuscate by defining it in terms of a
computational algorithm).
  The BMDP programs had reasonable facilities for data manipulation ---
not as strong as SAS but reasonable.  However each analysis program was
a separate run, so you had to cut and paste your block of setup code
onto the front of each program's instructions.  Cut and paste with a
keypunch machine is not quite as simple as with a mouse, if you needed a
listing, some frequencies, 2-3 regressions, ... it got rather tedious.

  Terry Therneau

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Re: [R] Post-Hoc tests for Friedman Test?

2010-02-22 Thread Tal Galili
Hello David,
I wanted to thank you for pointing to this code for performing posthoc
friedman test. I just used this example to create a function to perform this
test (and also added some illustrative flexible plots to the mix), here:
http://www.r-statistics.com/2010/02/post-hoc-analysis-for-friedmans-test-r-code/

Best,
Tal




Contact
Details:---
Contact me: tal.gal...@gmail.com |  972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
--




On Mon, Sep 21, 2009 at 3:35 AM, David Winsemius dwinsem...@comcast.netwrote:


 On Sep 20, 2009, at 9:05 PM, j...@terraspark.com wrote:

  Hi there all,

 This is my first post to the list and I'll first say a few things:
 - R is great!
 - The archives of this list have helped me solve all of my
 problems/questions so far
 - I only know enough statistics to be dangerous

 I'm looking for a way to do post-hoc tests for the Friedman test. I have a
 dataset from a within-subjects design with 5 conditions where some of the
 dependent variables are ordinal, resulting from (summed) likert-scaled
 questionnaire data.

 From what I've read, I could use a wilcox.test on pairs of conditions and
 adjust the p level, but is there something in R that does a better
 job/automates this.

 I've seen references to the npmc package but that doesn't seem to do what
 I'm looking for, because it only accepts a data frame with two columns -
 i.e. there's no way to specify grouping/subject identifiers.

 Thanks,


 There is a worked example in the coin package for using a permutation test
 to examine differences after a Friedman test. The authors, Hothorn , Hornik
 , van de Wiel, and Zeileis, call this method the
 Wilcoxon-Nemenyi-McDonald-Thompson test and cite: Hollander  Wolfe (1999),
 page 295


 http://finzi.psych.upenn.edu/R/library/coin/html/SymmetryTests.html

 --
 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT

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Re: [R] how do I calculate means or cov matrix for multivariate groups

2010-02-22 Thread Henrique Dallazuanna
Try this:

lapply(list(mean, cov), by, data = d[,1:2], INDICES = d[,'class'])

On Mon, Feb 22, 2010 at 6:13 AM, mirauta bmira...@yahoo.com wrote:

 Hello,

 Having the matrix d
 d
   value value2 class
 1      1      1     x
 2      2      2     x
 3      3      3     x
 4      4      2     x
 5      5      1     y
 6     11      3     y
 7     12      4     z
 8     13      5     z
 9     14      6     z
 10    15      7     z

 I want to calculate the means and cov matrix for groups x,y,z.
 I know how to do it the long way.
 I tried to use tapply and kmeans but no good results.
 (tapply is a good solution for only 1 variable)


 Thank you

 Bogdan


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-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O

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[R] change email subscription

2010-02-22 Thread Wendy Qiao
Dear R team,

 

As this is a university email address with very small inbox limit, can I
please change my R email subscription to another email address instead of
this  one? My new email address is wendy2.q...@gmail.com. I have change my
email in my profile, but seems that does not change my subscription.

 

Thank you. 

Wendy 


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[R] Raster table: how separate lines with the same value (count 1)

2010-02-22 Thread Simone R. Freitas
Dear all,

I intend to do some statistics with my raster table, like correlations or
regression analysis. For that, I need that each pixel be in one line, that
is, there is no count  1. So, all columns should have the same number of
lines, when I compare (combine) rasters.

I'd like to know if there is a way to create lines and copy the values of
the lines, when count is  1. So, even though values were the same, and
count twice (or more), I need that those values be repeated in different
lines.

Example:

My raster table now:

COUNT_Forest KTOTAL500X FOREST_BUF
1 28006 50
1 27953 50
1 12726 150
2 12725 1
1 12722 50
1 76001
2 586  1000
10 5861

My new raster table (the ideal one):

COUNT_Forest KTOTAL500X FOREST_BUF
1 28006 50
1 27953 50
1 12726 150
1 12725 1
1 12725 1
1 12722 50
1 76001
1 586  1000
1 586  1000
1 5861
1 5861
1 5861
1 5861
1 5861
1 5861
1 5861
1 5861
1 5861
1 5861

 After that, I'd like to join tables using KTOTAL500X column. How can I do
that?

Thank you very much.

Best regards

Simone.
--
Simone R. Freitas
Universidade Federal do ABC (UFABC)
Centro de Ciências Naturais e Humanas (CCNH)
R. Catequese, 242
Bairro Jardim
09090-400 - Santo André - SP
Brasil
http://srfreitas.webs.com/

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Re: [R] tests for measures of influence in regression

2010-02-22 Thread Viechtbauer Wolfgang (STAT)
I don't think this information can be found in the documentation, but you can 
always just check the actual influence.measures() and print.infl() code to find 
out. Most importantly, influence.measures() incldues the following code:

function (model)
{
is.influential - function(infmat, n) {
k - ncol(infmat) - 4
if (n = k)
stop(too few cases, n  k)
absmat - abs(infmat)
result - cbind(absmat[, 1L:k]  1, absmat[, k + 1] 
3 * sqrt(k/(n - k)), abs(1 - infmat[, k + 2])  (3 *
k)/(n - k), pf(infmat[, k + 3], k, n - k)  0.5,
infmat[, k + 4]  (3 * k)/n)
dimnames(result) - dimnames(infmat)
result
}
...
infmat - cbind(dfbetas, dffit = dffits, cov.r = cov.ratio,
cook.d = cooks.d, hat = h)
...
is.inf - is.influential(infmat, sum(h  0))
...
}

So, a case is flagged if:

- any of its absolute dfbetas values are larger than 1, or
- its absolute dffits value is larger than 3*sqrt(k/(n-k)), or
- abs(1 - covratio) is larger than 3*k/(n-k), or
- its Cook's distance is larger than the 50% percentile of
  an F-distributio with k and n-k degrees of freedom, or
- its hatvalue is larger than 3*k/n,

where k denotes the number of model coefficients (e.g., k = 2 for simple 
regression with the intercept included in the model).

Best,

--
Wolfgang Viechtbauerhttp://www.wvbauer.com/
Department of Methodology and StatisticsTel: +31 (43) 388-2277
School for Public Health and Primary Care   Office Location:
Maastricht University, P.O. Box 616 Room B2.01 (second floor)
6200 MD Maastricht, The Netherlands Debyeplein 1 (Randwyck)


Original Message
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Frank Tamborello
Sent: Monday, February 22, 2010 00:39 To: r-help@r-project.org
Subject: [R] tests for measures of influence in regression

 influence.measures gives several measures of influence for each
 observation (Cook's Distance, etc) and actually flags observations
 that it determines are influential by any of the measures. Looks
 good! But how does it discriminate between the influential and non-
 influential observations by each of the measures? Like does it do a
 Bonferroni-corrected t on the residuals identified by the influence
 measures or some other test?

 Cheers,

 Frank Tamborello, PhD
 W. M. Keck Postdoctoral Fellow
 School of Health Information Sciences
 University of Texas Health Science Center, Houston


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Re: [R] new to R Project

2010-02-22 Thread Dr. David Kirkby

chinna wrote:

hi everyone,
i am new to R project can anyone please help me by providing documents

my goal is using R i have to connect to the database and i have to generate
reports.

Thanks in advance
chinna.


R is a complex program. If you can't work out how to find the documentation, I 
doubt you will be able to use R.


Dave

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Re: [R] (Somewhat) broken EPS files produced

2010-02-22 Thread Marc Schwartz
On Feb 21, 2010, at 10:48 PM, Wartan Hachaturow wrote:

 Hello.
 
 I'm writing some simple text using sweave, and faced a strange problem
 with eps files produced for my plots (one example attached).
 Individual eps files are interpreted by ghostscript just fine, and
 show up without errors. But once I try to include them into main
 LaTeX/Sweave document (using regular \includegraphics, produced by
 Sweave),
 ghostscript gives me this error on those files:
 
 Error: /undefinedresult in --stringwidth--
 Operand stack:
   (600)   0.5
 Execution stack:
   %interp_exit   .runexec2   --nostringval--   --nostringval--
 --nostringval--   2   %stopped_push   --nostringval--
 --nostringval--   --nostringval--   false   1   %stopped_push   1878
 1   3   %oparray_pop   1877   1   3   %oparray_pop   1861   1   3
 %oparray_pop   1755   1   3   %oparray_pop   --nostringval--
 %errorexec_pop   .runexec2   --nostringval--   --nostringval--
 --nostringval--   2   %stopped_push   --nostringval--
 --nostringval--
 Dictionary stack:
   --dict:1157/1684(ro)(G)--   --dict:0/20(G)--   --dict:82/200(L)--
 --dict:178/300(L)--   --dict:91/200(L)--
 Current allocation mode is local
 Current file position is 207944
 GPL Ghostscript 8.71: Unrecoverable error, exit code 1
 
 What might be the problem?
 
 P.S. I get exactly the same behavior on Debian/sid and OS X.

It would be helpful to attach the .Rnw SWeave file (if small) or post it 
someplace that we can look at it, along with any data to replicate your process.

I took the EPS file that you provided here, included it in a simple tex file 
(test.tex) which contains the following:

\documentclass{article}
\usepackage{graphicx}

\begin{document}

\begin{figure}
\centering
\includegraphics[width=0.8\textwidth]{Report-fig1}
\caption{Test Figure}
\end{figure}

\end{document}


I then processed the file using MacTeX (TeXLive on Snow Leopard) with:

latex test.tex
dvips test -o test.ps
ps2pdf test.ps test.pdf

The result is attached here and there were no problems.

I would say that perhaps your GS installation might be corrupted, but that 
seems less likely on two separate platforms, unless your installation process 
is common and faulty. Alternatively, there is a problem with your .Rnw file 
content, since that would be common on both.

That does not give you a specific resolution, but at least suggests that the 
EPS generation process via SWeave is not at fault.

Regards,

Marc Schwartz



test.pdf
Description: Adobe PDF document
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[R] R language syntax highlighting file of VIM

2010-02-22 Thread zhuojun chen
I sent an email to current maintainer Vaidotas Zemlys 2 weeks ago but
no response yet.
Here is a mod, it's an unfinished version. Please have a look, thanks.
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[R] Alternatives to linear regression with multiple variables

2010-02-22 Thread Guy Green

I wonder if someone can give some pointers on alternatives to linear
regression (e.g. Loess) when dealing with multiple variables.

Taking any simple table with three variables, you can very easily get the
intercept and coefficients with:
summary(lm(read_table))

For obvious reasons, the coefficients in a multiple regression are quite
different from what you get if you calculate regressions for the single
variables separately.  Alternative approaches such as Loess seem
straightforward when you have only one variable, and have the advantage that
they can cope even if the relationship is not linear.

My question is: how can you extend a flexible approach like Loess to a
multi-variable scenario?  I assume that any non-parametric calculation
becomes very resource-intensive very quickly.  Can anyone suggest
alternatives (preferably R-based) that cope with multiple variables, even
when the relationship (linear, etc) is not known in advance?

Thanks,

Guy
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Re: [R] new to R Project

2010-02-22 Thread Ivan Calandra

Hi!
You should first go to the home page of the R project and read the 
manuals available there (and there are a lot).
When you'll understand how R works, read the posting guide and ask 
specific questions.

I don't think you'll get answers if you have such imprecise questions.
Ivan

Le 2/22/2010 14:07, Dr. David Kirkby a écrit :

chinna wrote:

hi everyone,
i am new to R project can anyone please help me by providing 
documents


my goal is using R i have to connect to the database and i have to 
generate

reports.

Thanks in advance
chinna.


R is a complex program. If you can't work out how to find the 
documentation, I doubt you will be able to use R.


Dave

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http://www.R-project.org/posting-guide.html

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[R] Fortune candidate! Re: new to R Project

2010-02-22 Thread Detlef Steuer
One vote goes to Dave's answer!

You made (saved) my day
detlef


On Mon, 22 Feb 2010 13:07:23 +
Dr. David Kirkby david.kir...@onetel.net wrote:

 chinna wrote:
  hi everyone,
  i am new to R project can anyone please help me by providing documents
  
  my goal is using R i have to connect to the database and i have to generate
  reports.
  
  Thanks in advance
  chinna.
 
 R is a complex program. If you can't work out how to find the documentation, 
 I 
 doubt you will be able to use R.
 
 Dave
 
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Re: [R] odfWeave - merged table cells, and adding information like totals and p-values

2010-02-22 Thread Max Kuhn
The devel version of odfWeave has some multicolumn capabilities. these
were added by Patrick Lenon and Zekai Otles recently, but I have not
had a chance to test it out.

You can go to:

   https://r-forge.r-project.org/projects/odfweave/

and download the version there if you want to evaluate the new
arguments to odfTable.

Thanks,

Max

On Sun, Feb 21, 2010 at 11:35 AM, Polwart Calum (County Durham and
Darlington NHS Foundation Trust) calum.polw...@nhs.net wrote:
 I'm hoping I'm missing some (probably fundamental basic process) which might 
 make my life easier!

 Lets assume I have a 3 column table summarizing results from a trial from 
 three arms (Arm A, B and C).
 For each arm there will be a number of pieces of information to report.  The 
 simplest example might be to compare this to the demographic comparisons 
 often seen in clinical traisl where you are setting out to prove that your 
 randomization produced similar populations

 So I might have a table like this:

 ---
                 A             B               C
 ---

 Male            50              50              50
 Female  49              51              50

 Age  65        30              29              31
 Age 65+ 69              72              69
 ---

 I've got a matrix with that data in it which I'm passing to odfWeave's table 
 function.   I just want to check a few basic things.

 Here's some short code which will create the matrix:
 groups = c(A,B,C)
 factors = c(Male,Female, Age lt; 65, Age 65+)
 mydata = matrix (c(50,49,30,69,50,51,29,72,50,50,31,69), nrow=4, dimnames = 
 list(factors,groups))

 - Is there anyway to add a merged cell above ABC which would say Group?
 - If I want to total column I can do that using:
 total=as.numeric()
 for (fact in 1:length(factors)) {
        total[fact]=sum(mydata[fact,])
 }
 mydata = cbind(mydata,total)
 Is there an easier way?

 - Now lets say i want to do a chi-squ test between the ages differences in Gp 
 A and Gp B I run
 chisq.test(mydata[3:4,1:2])
 What I really want is the p-value and I'll want to repeat that for Gp A vs Gp 
 C.  If I was just using R I'd simply print those and then add them to my 
 table by hand.  But I'm trying to be smart and use odfWeave.  Now I know I 
 can put them in my caption but I'd probably have added them as an extra row 
 in my table or added it in brackets similar to the SDs/ORs and CIs shown in 
 this example http://www.bmj.com/cgi/content-nw/full/340/feb05_1/c199/TBL2 
 depending which was more appropriate.

 - Is there an easy way to do anything like this?  I'm thinking that we often 
 put crude numbers in and (%) in brackets, or CIs etc  - so my exported table 
 would not ideally be pure numbers.

 - As a p value usually links two columns I might have expected to use a 
 merged cell which again brings me back to my original question ;-)

 Thanks





 Calum Polwart BSc(Hons) MSc MRPharmS SP IP
 Network Pharmacist - North of England Cancer Network and
 Pharmacy Clinical Team Manager (Cancer  Aseptic Services) - County Durham  
 Darlington NHS Foundation Trust

 

 This message may contain confidential information. If ...{{dropped:16}}

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Re: [R] cross-validation in plsr package

2010-02-22 Thread Max Kuhn
 The cross-validation in the pls package does not propose a number of
 factors as optimum, you have to select this yourself.  (The reason for
 this is that there is AFAIK no theoretically founded and widely accepted
 way of doing this automatically.  I'd be happy to learn otherwise.)

The caret package has a wrapper for pls and multiple resampling
methods (cv, bootstrap, repeated test/train splits etc).

There are a few modules that can be used for automatically determining
the optimal number of components. I agree that there is no uniformly
best technique. The only thing that I know of that is widely accepted
is the 1 stardard error rule in CART. In this case, that would mean
that you find the value of ncomp with the smallest error and choose
the final ncomp value based of the smallest value within one standard
error of the optimal. caret can do this or use any other rule that you
think is appropriate.

Thanks,

Max

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Re: [R] Fortune candidate! Re: new to R Project

2010-02-22 Thread Achim Zeileis

Thanks for the pointer, Detlef, added to the devel-version on R-Forge.
Z

On Mon, 22 Feb 2010, Detlef Steuer wrote:


One vote goes to Dave's answer!

You made (saved) my day
detlef


On Mon, 22 Feb 2010 13:07:23 +
Dr. David Kirkby david.kir...@onetel.net wrote:


chinna wrote:

hi everyone,
i am new to R project can anyone please help me by providing documents

my goal is using R i have to connect to the database and i have to generate
reports.

Thanks in advance
chinna.


R is a complex program. If you can't work out how to find the documentation, I
doubt you will be able to use R.

Dave

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Re: [R] Generating reports from database

2010-02-22 Thread Bart Joosen

Chinna,

I found that there are ODBC drivers for the teradatabase available, so with
the use of RODBC you should be able to connect to your database.
This will allow you to extract your data into an R dataframe, and make
reports of it.

But you noticed in another thread that you are an R beginner, so maybe you
should sit down and take the time to learn how to work with R, read the
manuals and docs!
R is very powerfull and flexible, but is known for it's rather steep
learning curve.
And connecting to a db, extracting the data you want, analyse this and put
in a report, with graphs isn't that hard, but if you are starting out, you
have to accept that you will have to learn the basics.

So go on, play with R and your data, and ask when you are stuck and can't
figure it out without reading the manuals, help lists, ...

Bart

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[R] Rounding like in finances

2010-02-22 Thread Oliver
Hello,

I need to have a kaufmaennisches Runden function.

Is there already something like that?

It means: rounding up the 5, instead of rounding it down.

So, 245.455 would give 245.46

I found no option for this.
Maybe there is a package for it?


Oliver

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Re: [R] Rounding like in finances

2010-02-22 Thread Henrique Dallazuanna
 round(245.455, 2) ?

On Mon, Feb 22, 2010 at 11:06 AM, Oliver oli...@first.in-berlin.de wrote:
 Hello,

 I need to have a kaufmaennisches Runden function.

 Is there already something like that?

 It means: rounding up the 5, instead of rounding it down.

 So, 245.455 would give 245.46

 I found no option for this.
 Maybe there is a package for it?


 Oliver

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25° 25' 40 S 49° 16' 22 O

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[R] Extract information from S4 object

2010-02-22 Thread Jay
The function prediction() returns this:

Formal class 'performance' [package ROCR] with 6 slots
  ..@ x.name  : chr Cutoff
  ..@ y.name  : chr Accuracy
  ..@ alpha.name  : chr none
  ..@ x.values:List of 1
  .. ..$ : Named num [1:89933] Inf 2.23 2.22 2.17 2.16 ...
  .. .. ..- attr(*, names)= chr [1:89933]  36477 56800
41667 ...
  ..@ y.values:List of 1
  .. ..$ : num [1:89933] 0.5 0.5 0.5 0.5 0.5 ...
  ..@ alpha.values: list()

Now, since I want to match each prediction with its original case, I
need to extract the names, i.e. the information in - attr(*,
names)= chr [1:89933]  36477 56800 41667 ... so I can use
it with a simple datafile[names,] query.

How do I get these names in plain number formats?

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Re: [R] Raster table: how separate lines with the same value (count 1)

2010-02-22 Thread David Winsemius


On Feb 22, 2010, at 6:40 AM, Simone R. Freitas wrote:


Dear all,

I intend to do some statistics with my raster table, like  
correlations or
regression analysis. For that, I need that each pixel be in one  
line, that
is, there is no count  1. So, all columns should have the same  
number of

lines, when I compare (combine) rasters.

I'd like to know if there is a way to create lines and copy the  
values of
the lines, when count is  1. So, even though values were the same,  
and
count twice (or more), I need that those values be repeated in  
different

lines.

Example:

My raster table now:

COUNT_Forest KTOTAL500X FOREST_BUF
1 28006 50
1 27953 50
1 12726 150
2 12725 1
1 12722 50
1 76001
2 586  1000
10 5861

My new raster table (the ideal one):

COUNT_Forest KTOTAL500X FOREST_BUF
1 28006 50
1 27953 50
1 12726 150
1 12725 1
1 12725 1
1 12722 50
1 76001
1 586  1000
1 586  1000
1 5861
1 5861
1 5861
1 5861
1 5861
1 5861
1 5861
1 5861
1 5861
1 5861


 dta[ rep(row(dta)[ ,1], dta$COUNT_Forest), ]
COUNT_Forest KTOTAL500X FOREST_BUF
1  1  28006 50
2  1  27953 50
3  1  12726150
4  2  12725  1
4.12  12725  1
5  1  12722 50
6  1   7600  1
7  2586   1000
7.12586   1000
8 10586  1
8.1   10586  1
8.2   10586  1
8.3   10586  1
8.4   10586  1
8.5   10586  1
8.6   10586  1
8.7   10586  1
8.8   10586  1
8.9   10586  1

 After that, I'd like to join tables using KTOTAL500X column. How  
can I do

that?



?merge



Thank you very much.

Best regards

Simone.
--
Simone R. Freitas
Universidade Federal do ABC (UFABC)
Centro de Ciências Naturais e Humanas (CCNH)
R. Catequese, 242
Bairro Jardim
09090-400 - Santo André - SP
Brasil
http://srfreitas.webs.com/

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Re: [R] machine precision problem

2010-02-22 Thread David Winsemius


On Feb 21, 2010, at 1:37 PM, wendy wrote:



Dear all,

I am analysising a set of gene expression data using multiplicative  
Gaussian
Kernel function. I calculated the kernels between two gene sets with  
2
genes for each set. The kernels are less than 1, therefore the  
product of
the kernels is out of the minimum precision in R. I wonder if there  
is a way
to lowering the minimum double precision in R. I am using R version  
2.10.1.




Have you considered other strategies, e.g. summing the logs and  
exponentiating?


Your proposed solution would involve rewriting R. There is no switch  
to throw that would increase the width of doubles.


--
David

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[R] Normality in split-plot design

2010-02-22 Thread Silvano

Hi,

I would like to test the normality of errors in an 
split-plot design using R.


I used the following program:

anava = aov(ganhos ~ Blocos + Trat*Supl + 
Error(Blocos/Trat))

summary(anava)

bartlett.test(ganhos, Trat)
bartlett.test(ganhos, Supl)

How can I test the normality of the errors?

Thanks,

--
Silvano Cesar da Costa
Departamento de Estatística
Universidade Estadual de Londrina
Fone: 3371-4346

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Re: [R] Extract information from S4 object

2010-02-22 Thread Henrique Dallazuanna
Try this:

 names(o...@x.values)

On Mon, Feb 22, 2010 at 11:05 AM, Jay josip.2...@gmail.com wrote:
 The function prediction() returns this:

 Formal class 'performance' [package ROCR] with 6 slots
  ..@ x.name      : chr Cutoff
  ..@ y.name      : chr Accuracy
  ..@ alpha.name  : chr none
  ..@ x.values    :List of 1
  .. ..$ : Named num [1:89933] Inf 2.23 2.22 2.17 2.16 ...
  .. .. ..- attr(*, names)= chr [1:89933]  36477 56800
 41667 ...
  ..@ y.values    :List of 1
  .. ..$ : num [1:89933] 0.5 0.5 0.5 0.5 0.5 ...
  ..@ alpha.values: list()

 Now, since I want to match each prediction with its original case, I
 need to extract the names, i.e. the information in - attr(*,
 names)= chr [1:89933]  36477 56800 41667 ... so I can use
 it with a simple datafile[names,] query.

 How do I get these names in plain number formats?

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25° 25' 40 S 49° 16' 22 O

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Re: [R] Rounding like in finances

2010-02-22 Thread Oliver
Oh strange...


 round(108.275 , 2)
[1] 108.28
 round(208.275 , 2)
[1] 208.28
 round(308.275 , 2)
[1] 308.27
 


looks not like what one should expect...


R version 2.9.2 (2009-08-24)



Ciao,
   Oliver

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Re: [R] Extract information from S4 object

2010-02-22 Thread David Winsemius


On Feb 22, 2010, at 8:05 AM, Jay wrote:


The function prediction() returns this:

Formal class 'performance' [package ROCR] with 6 slots
 ..@ x.name  : chr Cutoff
 ..@ y.name  : chr Accuracy
 ..@ alpha.name  : chr none
 ..@ x.values:List of 1
 .. ..$ : Named num [1:89933] Inf 2.23 2.22 2.17 2.16 ...
 .. .. ..- attr(*, names)= chr [1:89933]  36477 56800
41667 ...
 ..@ y.values:List of 1
 .. ..$ : num [1:89933] 0.5 0.5 0.5 0.5 0.5 ...
 ..@ alpha.values: list()

Now, since I want to match each prediction with its original case, I
need to extract the names, i.e. the information in - attr(*,
names)= chr [1:89933]  36477 56800 41667 ... so I can use
it with a simple datafile[names,] query.

How do I get these names in plain number formats?


Not sure what you mean by plain number formats but this should get  
you a vector of names assuming the prediction object is named  
predobject:


names( predobj...@x.values )

If you wanted them as.numeric, then that is the name of the  
appropriate function.


--
David



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Re: [R] Rounding like in finances

2010-02-22 Thread Duncan Murdoch

On 22/02/2010 9:06 AM, Oliver wrote:

Hello,

I need to have a kaufmaennisches Runden function.

Is there already something like that?

It means: rounding up the 5, instead of rounding it down.

So, 245.455 would give 245.46

I found no option for this.
Maybe there is a package for it?


This is a little tricky, because 245.455 is not a representable number 
in base R.  If x is represented as x+epsilon, it will tend to round up, 
if it is x-epsilon, it will tend to round down.  (I say tend to because 
R tries to do banker's rounding, and the math routines attempt to do 
exact calculations even when they are not really possible, so it is hard 
to predict exactly what will happen for a particular number.) There are 
packages for handling rational numbers that could handle it exactly; I 
don't know how flexible they are about rounding.


Duncan Murdoch

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Re: [R] Rounding like in finances

2010-02-22 Thread Ivan Calandra

same result with R2.10.1 on Windows...

Le 2/22/2010 15:34, Oliver a écrit :

Oh strange...


   

round(108.275 , 2)
 

[1] 108.28
   

round(208.275 , 2)
 

[1] 208.28
   

round(308.275 , 2)
 

[1] 308.27
   
 


looks not like what one should expect...


R version 2.9.2 (2009-08-24)



Ciao,
Oliver

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--
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University of Hamburg
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Martin-Luther-King-Platz 3
D-20146 Hamburg, GERMANY
+49(0)40 42838 6231
ivan.calan...@uni-hamburg.de

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Re: [R] change email subscription

2010-02-22 Thread Steve Lianoglou
Hi,

On Mon, Feb 22, 2010 at 7:27 AM, Wendy Qiao wendy.q...@utoronto.ca wrote:
 Dear R team,



 As this is a university email address with very small inbox limit, can I
 please change my R email subscription to another email address instead of
 this  one? My new email address is wendy2.q...@gmail.com. I have change my
 email in my profile, but seems that does not change my subscription.

I think you'll just have to unsubscribe from the list with your
current address, then resubscribe with your desired one.

-steve

-- 
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Graduate Student: Computational Systems Biology
 | Memorial Sloan-Kettering Cancer Center
 | Weill Medical College of Cornell University
Contact Info: http://cbio.mskcc.org/~lianos/contact

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Re: [R] Rounding like in finances

2010-02-22 Thread Oliver
Hello,


which packages are you talking about?

And... are thoise packages using integer-based calculations?

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Re: [R] svm

2010-02-22 Thread Steve Lianoglou
Hi Amy,

On Sat, Feb 20, 2010 at 9:29 PM, Amy Hessen amy_4_5...@hotmail.com wrote:
 Hi ,

 Could you please help me in this question:?

 After trying this code:

 library(e1071)
  mydata - as.matrix(read.delim(iris.txt))
  train.x - mydata[,-1]
  train.y - mydata[,1]
  mymodel - svm(train.x, train.y, cross=3, type=C-classification)

 I receive this error:

 Error in colMeans(x, na.rm = TRUE) : 'x' must be numeric

 I put the class label in the first column.

I think you would be able to find out where many of your problems lie
if you try to provide a reproducible example we can use to test:
meaning, something I can just copy from your email and paste into my R
workspace that would reproduce your problem.

The error is telling you that something is expecting x to be
numeric, and it's not. So the question is, what isn't numeric? I
guess the answer must be in one of the two arguments you supply to the
svm function, so can you please check to see what type of arguments
you are passing into your function?

You can do that by running these R commands?

R is(mydata)
R is(train.x)
R is(train.y)

What do you get from that?

-steve

-- 
Steve Lianoglou
Graduate Student: Computational Systems Biology
 | Memorial Sloan-Kettering Cancer Center
 | Weill Medical College of Cornell University
Contact Info: http://cbio.mskcc.org/~lianos/contact

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[R] Count between interval

2010-02-22 Thread Bosken

Hi all,

I take a simple dataset like this:

-1.3
1
-1.5
-1
1.5
-2.5
3
-0.5

Now I want to count how many values there are between -2 and 2.

The answer here would be 6.

Can anyone do this with R?

Thank you in advance.

Gr. Bosken 
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Re: [R] Accessing values of a matrix

2010-02-22 Thread statquant

Hello Sarah, thanks for answering
For example if I have the following example 

 test - as.data.frame(matrix(c(1,2,3,4, 11,12,13,14, a,b,b,c), nrow
= 3, ncol=3,dimnames = list(c(r1,r2,r3,r4),NULL))

   V1 V2 V3
r1  1 11  a
r2  2 12  b
r3  3 13  b
r4  4 14  c

it is easy to select test - test[,mylist] with for example mylist -
c(V1,V3)

   V1 V3
r1  1  a
r2  2  b
r3  3  b
r4  4  c

But after how can I restrict test in selecting the rows where the result in
column V3 are in a list mylist2, with for example mylist2 -c(b,c,d) ?
which would give as an example 

   V1 V3
r2  2  b
r3  3  b
r4  4  c

Regards 
Colin
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[R] How to run the VECM BEKK model in R?

2010-02-22 Thread 曾振兴

Dear all,

I want to run the VECM BEKK model, but I cannot find the corresponding
package to run this model. Anybody can help?

Thanks a lot

Ted
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Re: [R] plot is not keeping the order of variable

2010-02-22 Thread Peter Dalgaard

Dieter Menne wrote:


Peter Dalgaard wrote:

d - data.frame(f=c(rare, medium,well-done))
#To get the cast in order of appearance, this can be used:

  d$f - factor(d$f, levels=unique(d$f))
  d$f
[1] rare  mediumwell-done
Levels: rare medium well-done




.. which caused some head-scratching from me, because it made me believe
there was some hidden Kopenhagen-factor conserving the original order.




To protect the innocent: for the more general case, unique() does not help.


Right. As I said, it gives cast in order of appearance. The default 
factor levels are sort(unique(x)) which is independent of data order, 
but not necessarily desirable. In the general case, you have to tell R 
about the order explicitly.



Dieter

levs = c(rare, medium,well-done) 
set.seed(4711)
d - data.frame(f=sample(levs,10,TRUE)) 
unique(d$f)
d$f =  factor(d$f, levels=unique(d$f)) 
levels(d$f)
d$f =  factor(d$f, levels = levs) 
levels(d$f)





--
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  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
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Re: [R] tests for measures of influence in regression

2010-02-22 Thread Frank Tamborello
Thank you, Wolfgang! Now that I know what the function does I can at  
least search some literature to learn about those criteria.


Thanks,
Frank Tamborello

On Feb 22, 2010, at 7:00 AM, Viechtbauer Wolfgang (STAT) wrote:

I don't think this information can be found in the documentation,  
but you can always just check the actual influence.measures() and  
print.infl() code to find out. Most importantly, influence.measures 
() incldues the following code:


function (model)
{
is.influential - function(infmat, n) {
k - ncol(infmat) - 4
if (n = k)
stop(too few cases, n  k)
absmat - abs(infmat)
result - cbind(absmat[, 1L:k]  1, absmat[, k + 1] 
3 * sqrt(k/(n - k)), abs(1 - infmat[, k + 2])  (3 *
k)/(n - k), pf(infmat[, k + 3], k, n - k)  0.5,
infmat[, k + 4]  (3 * k)/n)
dimnames(result) - dimnames(infmat)
result
}
...
infmat - cbind(dfbetas, dffit = dffits, cov.r = cov.ratio,
cook.d = cooks.d, hat = h)
...
is.inf - is.influential(infmat, sum(h  0))
...
}

So, a case is flagged if:

- any of its absolute dfbetas values are larger than 1, or
- its absolute dffits value is larger than 3*sqrt(k/(n-k)), or
- abs(1 - covratio) is larger than 3*k/(n-k), or
- its Cook's distance is larger than the 50% percentile of
  an F-distributio with k and n-k degrees of freedom, or
- its hatvalue is larger than 3*k/n,

where k denotes the number of model coefficients (e.g., k = 2 for  
simple regression with the intercept included in the model).


Best,

--
Wolfgang Viechtbauerhttp://www.wvbauer.com/
Department of Methodology and StatisticsTel: +31 (43) 388-2277
School for Public Health and Primary Care   Office Location:
Maastricht University, P.O. Box 616 Room B2.01 (second floor)
6200 MD Maastricht, The Netherlands Debyeplein 1 (Randwyck)


Original Message
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Frank Tamborello
Sent: Monday, February 22, 2010 00:39 To: r-help@r-project.org
Subject: [R] tests for measures of influence in regression


influence.measures gives several measures of influence for each
observation (Cook's Distance, etc) and actually flags observations
that it determines are influential by any of the measures. Looks
good! But how does it discriminate between the influential and non-
influential observations by each of the measures? Like does it do a
Bonferroni-corrected t on the residuals identified by the influence
measures or some other test?

Cheers,

Frank Tamborello, PhD
W. M. Keck Postdoctoral Fellow
School of Health Information Sciences
University of Texas Health Science Center, Houston


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Re: [R] Accessing values of a matrix

2010-02-22 Thread David Winsemius


On Feb 22, 2010, at 8:45 AM, statquant wrote:



Hello Sarah, thanks for answering
For example if I have the following example

test - as.data.frame(matrix(c(1,2,3,4, 11,12,13,14,  
a,b,b,c), nrow

= 3, ncol=3,dimnames = list(c(r1,r2,r3,r4),NULL))


This is a malformed example. Should be:
 test - as.data.frame(matrix(c(1,2,3,4, 11,12,13,14,  
a,b,b,c), nrow= 4, ncol=3,dimnames =  
list(c(r1,r2,r3,r4),NULL))  )

 test
   V1 V2 V3
r1  1 11  a
r2  2 12  b
r3  3 13  b
r4  4 14  c




  V1 V2 V3
r1  1 11  a
r2  2 12  b
r3  3 13  b
r4  4 14  c

it is easy to select test - test[,mylist] with for example mylist -
c(V1,V3)

  V1 V3
r1  1  a
r2  2  b
r3  3  b
r4  4  c

But after how can I restrict test in selecting the rows where the  
result in
column V3 are in a list mylist2, with for example mylist2 - 
c(b,c,d) ?

which would give as an example


?%in%
?[
?subset

 test[test$V3 %in% c(b,c,d), c(V1,V2)]
   V1 V2
r2  2 12
r3  3 13
r4  4 14

#Or:

 subset(test, V3 %in% c(b,c,d), select=c(V1, V3))
   V1 V3
r2  2  b
r3  3  b
r4  4  c



  V1 V3
r2  2  b
r3  3  b
r4  4  c

Regards
Colin
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Re: [R] R language syntax highlighting file of VIM

2010-02-22 Thread Gabor Grothendieck
Your attachment did not get though.  Here is what did:

https://stat.ethz.ch/pipermail/r-help/2010-February/229132.html

On Mon, Feb 22, 2010 at 8:11 AM, zhuojun chen uifid...@gmail.com wrote:
 I sent an email to current maintainer Vaidotas Zemlys 2 weeks ago but
 no response yet.
 Here is a mod, it's an unfinished version. Please have a look, thanks.

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Re: [R] Count between interval

2010-02-22 Thread Eik Vettorazzi

Hi,
ab-read.table(header=F,file=textConnection(-1.3
1
-1.5
-1
1.5
-2.5
3
-0.5))

length(which(ab =-2  ab=2))


Bosken schrieb:

Hi all,

I take a simple dataset like this:

-1.3
1
-1.5
-1
1.5
-2.5
3
-0.5

Now I want to count how many values there are between -2 and 2.

The answer here would be 6.

Can anyone do this with R?

Thank you in advance.

Gr. Bosken 
  


--
Eik Vettorazzi
Institut für Medizinische Biometrie und Epidemiologie
Universitätsklinikum Hamburg-Eppendorf

Martinistr. 52
20246 Hamburg

T ++49/40/7410-58243
F ++49/40/7410-57790

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Re: [R] Rounding like in finances

2010-02-22 Thread Duncan Murdoch

On 22/02/2010 9:57 AM, Oliver wrote:

Hello,


which packages are you talking about?

And... are thoise packages using integer-based calculations?

I don't use this, but the ones I'd look in would be:

MASS (function rational())
rcdd
Rmpfr

You can use

RSiteSearch(rational)

to look for more.

Duncan Murdoch

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Re: [R] how to make R plot under Linux

2010-02-22 Thread xin wei

thank you for reply. I just type: hist(x) from SSH terminal, expecting a
histogram to pop up like what i got under windows.instead I got the
following error msg:

Error in X11(d$display, d$width, d$height, d$pointsize, d$gamma,
d$colortype,  : 
  unable to start device X11cairo
In addition: Warning message:
In function (display = , width, height, pointsize, gamma, bg,  :
  unable to open connection to X11 display ''

Would you give some clues what is going on?

thanks


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Re: [R] how to make R plot under Linux

2010-02-22 Thread K. Elo
Hi!

22.02.2010 17:45, xin wei wrote:
 
 thank you for reply. I just type: hist(x) from SSH terminal, expecting a
 histogram to pop up like what i got under windows.instead I got the
 following error msg:
 
 Error in X11(d$display, d$width, d$height, d$pointsize, d$gamma,
 d$colortype,  : 
   unable to start device X11cairo
 In addition: Warning message:
 In function (display = , width, height, pointsize, gamma, bg,  :
   unable to open connection to X11 display ''
 
 Would you give some clues what is going on?

You wrote you are using R over an SSH connection. Have you enabled
X-window support for the connection (see 'man ssh')?

HTH,
-Kimmo

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Re: [R] how to make R plot under Linux

2010-02-22 Thread Kevin E. Thorpe

xin wei wrote:

thank you for reply. I just type: hist(x) from SSH terminal, expecting a
histogram to pop up like what i got under windows.instead I got the
following error msg:

Error in X11(d$display, d$width, d$height, d$pointsize, d$gamma,
d$colortype,  : 
  unable to start device X11cairo

In addition: Warning message:
In function (display = , width, height, pointsize, gamma, bg,  :
  unable to open connection to X11 display ''

Would you give some clues what is going on?

thanks




Did you start ssh with the -X switch?

--
Kevin E. Thorpe
Biostatistician/Trialist, Knowledge Translation Program
Assistant Professor, Dalla Lana School of Public Health
University of Toronto
email: kevin.tho...@utoronto.ca  Tel: 416.864.5776  Fax: 416.864.3016

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Re: [R] tiff() and antialias option

2010-02-22 Thread Andrew Yee
Uwe, you're right, it turns out that cairo hadn't been previously installed
on the system.

Andrew

2010/2/19 Uwe Ligges lig...@statistik.tu-dortmund.de



 On 19.02.2010 17:44, Andrew Yee wrote:

 I was wondering if someone could help with the antialias option in tiff().
  I'm running R 2.9.2 on a Linux machine.

 I'm working on creating a tiff file and have tried different antialias
 parameters, e.g. default, none, gray, and subpixel, but don't seem to be
 seeing a difference in the output.  Or perhaps I'm missing something
 obvious?


 Perhaps you are not using type=cairo ?

 Uwe Ligges


 Thanks,
 Andrew

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Re: [R] SEM error

2010-02-22 Thread Uwe Ligges



On 20.02.2010 08:51, Dan Edgcumbe wrote:

I'm trying to do some confirmatory factor analysis on some data. My SEM
model solves in 22 iterations, but when I try to look at the modification
indices, using mod.indices, I get the following error message:

Error in solve.default(hessian) :
   system is computationally singular: reciprocal condition number =
4.40283e-18

What does this mean?


That the method you apply tries to invert some object called hessian 
(maybe a hessian? ;-)) but fails since a singular matrix cannot be 
inverted. Perhaps (as I often found for people doing sem analyses) you 
have less observations than parameters to estimate or only certain 
combinations for some factors?


Uwe Ligges







Many thanks,

Dan

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Re: [R] Rounding like in finances

2010-02-22 Thread Oliver

Duncan Murdoch murdoch at stats.uwo.ca writes:
[...]
 MASS (function rational())
 rcdd
 Rmpfr
[...]



OK, I will look for those packages.
Maybe they will help.

Thank you.

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Re: [R] Count between interval

2010-02-22 Thread Jorge Ivan Velez
Hi,

Here is a suggeston:


 x - c(-1.3, 1, -1.5, -1, 1.5, -2.5, 3, -0.5)
 sum(x =-2  x=2)
[1] 6

HTH,
Jorge


On Mon, Feb 22, 2010 at 9:49 AM, Bosken  wrote:


 Hi all,

 I take a simple dataset like this:

 -1.3
 1
 -1.5
 -1
 1.5
 -2.5
 3
 -0.5

 Now I want to count how many values there are between -2 and 2.

 The answer here would be 6.

 Can anyone do this with R?

 Thank you in advance.

 Gr. Bosken
 --
 View this message in context:
 http://n4.nabble.com/Count-between-interval-tp1564537p1564537.html
 Sent from the R help mailing list archive at Nabble.com.

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
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Re: [R] change email subscription

2010-02-22 Thread Uwe Ligges

See the footer of your message.

Uwe Ligges

On 22.02.2010 13:27, Wendy Qiao wrote:

Dear R team,



As this is a university email address with very small inbox limit, can I
please change my R email subscription to another email address instead of
this  one? My new email address is wendy2.q...@gmail.com. I have change my
email in my profile, but seems that does not change my subscription.



Thank you.

Wendy


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Re: [R] Error with KNN

2010-02-22 Thread Uwe Ligges



On 20.02.2010 19:10, Nancy Adam wrote:




Hi all

I receive this error message:  “Error in mymodel$MSE : $ operator is invalid 
for atomic vectors”
When I use KNN.
This is the code:

library(e1071)
train- rbind(iris3[,,1], iris3[,,2], iris3[,,3])
cl- factor(c(rep(s,50), rep(c,50), rep(v,50)))
knn.cv(train, cl, k = 3, prob = TRUE)
sqrt(mymodel$MSE)
#error message : “Error in mymodel$MSE : $ operator is invalid for atomic 
vectors”



There is no component MSE in mymodel. Hence you cannot extract it.

Uwe Ligges






thanks,
Nancy

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[R] gsub patterns from vector elements w/out loop?

2010-02-22 Thread Marianne Promberger
Dear list,

I have two vectors:

x - c(one,two)
y - paste(rep(x,2),blah)

I want to replace all occurrences of each element of x in y with
something else, so that y looks like this:

y
[1] something else blah something else blah something else blah
[4] something else blah

I can do this using a loop:

for ( i in 1:length(x) ) {
  y - gsub(x[i],something else,y)
}

Surely, there must be a less kludgy way? 

I tried looking at the different apply()s but am not getting anywhere,
partly because I lack the mental flexibility to combine the fact that
I am applying gsub() to y but now want to apply that to x ...  erm. :/

Marianne

-- 
Marianne Promberger PhD, King's College London
http://promberger.info
R version 2.10.1 (2009-12-14)
Ubuntu 9.10

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Re: [R] replicate matrix

2010-02-22 Thread William Dunlap
 -Original Message-
 From: r-help-boun...@r-project.org 
 [mailto:r-help-boun...@r-project.org] On Behalf Of wendy
 Sent: Saturday, February 20, 2010 6:58 PM
 To: r-help@r-project.org
 Subject: [R] replicate matrix
 
 
 Hi all,
 
 I have a matrix, for example
  [,1] [,2]
 [1,]  13
 [2,]  46
 
 I want to replicate the matrix twice and add an extra column 
 at the end,
 which is
  [,1] [,2] [,3] [,4] [,5] [,6] [,7]
 [1,]  13 13 132
 [2,]  46 46 465
 
 I found 'rep' only works for vector. Does anyone know how to 
 replicate a
 matrix, and append the matrix?

You want to replicate the columns of the matrix
so use rep() in a column subscripting expression:
x - matrix(c(1,4,3,6),nrow=2,ncol=2) # setup
xRepped - x[ , rep(seq_len(ncol(x)), 3)]
then append the new column with
xReppedAppended - cbind(xRepped, c(2,5)) 

I avoid the solutions that convert the original
matrix to a vector and back to a matrix, like
xxx - matrix(rep(as.vector(x),3), nrow=2)
as they make me assume more than I want to assume
about how matrices are represented internally.
Those solutions also lose any column or row names
that my matrix may have had.

Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com 
 
 Thank you in advance,
 Wendy  
 
 
 -- 
 View this message in context: 
 http://n4.nabble.com/replicate-matrix-tp1563337p1563337.html
 Sent from the R help mailing list archive at Nabble.com.
 
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Re: [R] gsub patterns from vector elements w/out loop?

2010-02-22 Thread Benilton Carvalho
gsub(one|two, something else, y)

?

On Mon, Feb 22, 2010 at 4:25 PM, Marianne Promberger
marianne.promber...@kcl.ac.uk wrote:
 Dear list,

 I have two vectors:

 x - c(one,two)
 y - paste(rep(x,2),blah)

 I want to replace all occurrences of each element of x in y with
 something else, so that y looks like this:

 y
 [1] something else blah something else blah something else blah
 [4] something else blah

 I can do this using a loop:

 for ( i in 1:length(x) ) {
  y - gsub(x[i],something else,y)
 }

 Surely, there must be a less kludgy way?

 I tried looking at the different apply()s but am not getting anywhere,
 partly because I lack the mental flexibility to combine the fact that
 I am applying gsub() to y but now want to apply that to x ...  erm. :/

 Marianne

 --
 Marianne Promberger PhD, King's College London
 http://promberger.info
 R version 2.10.1 (2009-12-14)
 Ubuntu 9.10

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Re: [R] gsub patterns from vector elements w/out loop?

2010-02-22 Thread Marc Schwartz

On Feb 22, 2010, at 10:25 AM, Marianne Promberger wrote:

 Dear list,
 
 I have two vectors:
 
 x - c(one,two)
 y - paste(rep(x,2),blah)
 
 I want to replace all occurrences of each element of x in y with
 something else, so that y looks like this:
 
 y
 [1] something else blah something else blah something else blah
 [4] something else blah
 
 I can do this using a loop:
 
 for ( i in 1:length(x) ) {
  y - gsub(x[i],something else,y)
 }
 
 Surely, there must be a less kludgy way? 
 
 I tried looking at the different apply()s but am not getting anywhere,
 partly because I lack the mental flexibility to combine the fact that
 I am applying gsub() to y but now want to apply that to x ...  erm. :/
 
 Marianne

You can use | to specify a logical or in the search regex:

 gsub(one|two, something else, y)
[1] something else blah something else blah something else blah
[4] something else blah


Thus:

 paste(x, collapse = |)
[1] one|two


and finally:

 gsub(paste(x, collapse = |), something else, y)
[1] something else blah something else blah something else blah
[4] something else blah


See ?regex and ?paste

HTH,

Marc Schwartz

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Re: [R] Count between interval

2010-02-22 Thread Peter Ehlers

And as long as the interval is symmetric about zero:

sum(abs(x) = 2)
[1] 6

 -Peter Ehlers

On 2010-02-22 9:18, Jorge Ivan Velez wrote:

Hi,

Here is a suggeston:



x- c(-1.3, 1, -1.5, -1, 1.5, -2.5, 3, -0.5)
sum(x=-2  x=2)

[1] 6

HTH,
Jorge


On Mon, Feb 22, 2010 at 9:49 AM, Bosken  wrote:



Hi all,

I take a simple dataset like this:

-1.3
1
-1.5
-1
1.5
-2.5
3
-0.5

Now I want to count how many values there are between -2 and 2.

The answer here would be 6.

Can anyone do this with R?

Thank you in advance.

Gr. Bosken
--
View this message in context:
http://n4.nabble.com/Count-between-interval-tp1564537p1564537.html
Sent from the R help mailing list archive at Nabble.com.

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Re: [R] gsub patterns from vector elements w/out loop?

2010-02-22 Thread Marianne Promberger
 
  gsub(paste(x, collapse = |), something else, y)
 [1] something else blah something else blah something else blah
 [4] something else blah

Many thanks! I didn't know about collapse. Should have thought about
reading up in ?paste ...

Thanks

Marianne

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http://promberger.info
R version 2.10.1 (2009-12-14)
Ubuntu 9.10

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Re: [R] SEM error

2010-02-22 Thread Jarrett Byrnes
I have often found this to happen if the scale of one variable is  
orders of magnitude different than the scale of other variables.  Have  
you tried inspecting the covariance matrix and log transforming any  
such variables?


On Feb 22, 2010, at 8:14 AM, Uwe Ligges wrote:




On 20.02.2010 08:51, Dan Edgcumbe wrote:
I'm trying to do some confirmatory factor analysis on some data. My  
SEM
model solves in 22 iterations, but when I try to look at the  
modification

indices, using mod.indices, I get the following error message:

Error in solve.default(hessian) :
  system is computationally singular: reciprocal condition number =
4.40283e-18

What does this mean?


That the method you apply tries to invert some object called  
hessian (maybe a hessian? ;-)) but fails since a singular matrix  
cannot be inverted. Perhaps (as I often found for people doing sem  
analyses) you have less observations than parameters to estimate or  
only certain combinations for some factors?


Uwe Ligges







Many thanks,

Dan

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[R] adding infrequent date labels to x-axis

2010-02-22 Thread emorway

I'm sure there is a clever way to do the following, but I've been unable to
find it on this forum or by writing my own functions.  I have 8 years worth
of weekly data but would like to restrict the labels on the x-axis to months
only.  I've included the first year's worth of data below. 

My line of thought has been along these lines

x-seq(as.Date(1999-04-01),as.Date(2007-10-25),by=1 month)
y-as.POSIXlt(x)$mon+1
months-month.name
month.names-months[as.numeric(y)]
month.names-substr(month.names,1,3)

plot(cropped.cast1$date,cropped.cast1$Frac_ET_Satsfd_mean,xaxt='n')
mtext(text=month.names,side=1,at=???

I'm not sure how to tie month.names back to their true location on the
x-axis?

I appreciate any insights, Eric
Also,

class(cropped.cast1$date)
[1] POSIXt  POSIXct

cropped.cast1
  date Frac_ET_Satsfd_mean Frac_ET_Satsfd_sd
1999-04-08   0.83448850.13545515
1999-04-15   0.83554660.12810387
1999-04-22   0.85955790.11259251
1999-04-29   0.89972250.09611060
1999-05-06   0.87143640.09527164
1999-05-13   0.85302030.11088544
1999-05-20   0.84378660.12689882
1999-05-27   0.83100030.13985307
1999-06-03   0.80312030.15851422
1999-06-10   0.82885050.12827027
1999-06-17   0.82511300.13051783
1999-06-24   0.82276390.14227501
1999-07-01   0.79146890.15892716
1999-07-08   0.80509290.14465413
1999-07-15   0.83701410.11843615
1999-07-22   0.84486970.10823010
1999-07-29   0.85619250.10694348
1999-08-05   0.85207900.09953065
1999-08-12   0.84299250.10545427
1999-08-19   0.83979660.11629002
1999-08-26   0.83679530.12363411
1999-09-02   0.82194790.13870596
1999-09-09   0.82181930.13617427
1999-09-16   0.82175840.13346997
1999-09-23   0.82168340.13304117
1999-09-30   0.81110050.14367143
1999-10-07   0.80908130.14967750
1999-10-14   0.82651880.13484263
1999-10-21   0.83913330.11873929
1999-10-28   0.84261020.11215439
1999-11-04   0.84318130.11007485
1999-11-11   0.83941400.11206864
1999-11-18   0.83506500.11042384
1999-11-25   0.83600820.11011926
1999-12-02   0.83621290.10834491
1999-12-09   0.83775120.10519698
1999-12-16   0.83673390.10176535
1999-12-23   0.83386210.10273662
1999-12-30   0.83170940.10470654
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[R] Re : how to plot select points in preexisting persp plot

2010-02-22 Thread Preeti Iyer

Hello,
I am trying to plot selected data points to a preexisting persp plot 
that satisfies a condition. I used the following statement -


text(coords[,1], coords[,2], names(act[which(act  8.75)]), cex=0.7)
But I get all the points labeled, instead of the points that satisfy 
the condition specified. Is there any way to plot only the points I 
want? Also can this be done using trans3d function. I found no topics 
pertaining to this issue.


Regards,
Preeti

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Re: [R] Accessing values of a matrix

2010-02-22 Thread statquant

OKKK

Thanks a lot for letting me know the subset function
Cheers
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Re: [R] Extract information from S4 object

2010-02-22 Thread Jay
Tahnk you. But, when I try the command you both suggested I get a NULL
as the results.

 names(object1 @ x.values)
NULL

Where did I go wrong?


On Feb 22, 4:34 pm, David Winsemius dwinsem...@comcast.net wrote:
 On Feb 22, 2010, at 8:05 AM, Jay wrote:



  The function prediction() returns this:

  Formal class 'performance' [package ROCR] with 6 slots
   ..@ x.name      : chr Cutoff
   ..@ y.name      : chr Accuracy
   ..@ alpha.name  : chr none
   ..@ x.values    :List of 1
   .. ..$ : Named num [1:89933] Inf 2.23 2.22 2.17 2.16 ...
   .. .. ..- attr(*, names)= chr [1:89933]  36477 56800
  41667 ...
   ..@ y.values    :List of 1
   .. ..$ : num [1:89933] 0.5 0.5 0.5 0.5 0.5 ...
   ..@ alpha.values: list()

  Now, since I want to match each prediction with its original case, I
  need to extract the names, i.e. the information in - attr(*,
  names)= chr [1:89933]  36477 56800 41667 ... so I can use
  it with a simple datafile[names,] query.

  How do I get these names in plain number formats?

 Not sure what you mean by plain number formats but this should get  
 you a vector of names assuming the prediction object is named  
 predobject:

 names( predobj...@x.values )

 If you wanted them as.numeric, then that is the name of the  
 appropriate function.

 --
 David



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[R] counting repeating sequence lengths in a vector

2010-02-22 Thread Larson, TR

Hello,
I have a very long (~50,000) sequence of repeating numbers.  The first 
100 are:


[1] 0 0 0 0 0 0 0 0 0 0 0   429
 [13]   429   429   429   429   429   429   429   858   858   858   858 
  858
 [25]   858  1287  1287  1287  1287  1287  1716  2145  2145  2574  2574 
 3003
 [37]  3003  3432  3432  3861  4290  4719  5148  5577  5577  6006  6006 
 6006
 [49]  6435  6435  6435  6864  6864  7293  7293  7293  7722  7722  7722 
 7722
 [61]  8151  8151  8151  8580  8580  8580  9009  9009  9009  9009  9438 
 9438
 [73]  9438  9438  9867  9867  9867 10296 10296 10296 10725 10725 10725 
10725
 [85] 11154 11154 11154 11154 11154 11583 11583 11583 11583 12012 12012 
12012

 [97] 12012 12441 12441 12441


What I want is to produce a vector of lengths for each contiguous run of 
numbers . i.e. for the above example, the first three items of the 
vector returned would be:


11 8 6

...to represent the counts of 0, 429, and 585, respectively.  I could do 
this with unique() and a for loop, but this would be very inefficient. 
Any advice on how to do this efficiently would be most appreciated.


thanks
Tony

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Re: [R] counting repeating sequence lengths in a vector

2010-02-22 Thread Henrique Dallazuanna
Try this:

rle(x)$length


On Mon, Feb 22, 2010 at 2:27 PM, Larson, TR t...@york.ac.uk wrote:
 Hello,
 I have a very long (~50,000) sequence of repeating numbers.  The first 100
 are:

 [1]     0     0     0     0     0     0     0     0     0     0     0   429
  [13]   429   429   429   429   429   429   429   858   858   858   858  858
  [25]   858  1287  1287  1287  1287  1287  1716  2145  2145  2574  2574
  3003
  [37]  3003  3432  3432  3861  4290  4719  5148  5577  5577  6006  6006
  6006
  [49]  6435  6435  6435  6864  6864  7293  7293  7293  7722  7722  7722
  7722
  [61]  8151  8151  8151  8580  8580  8580  9009  9009  9009  9009  9438
  9438
  [73]  9438  9438  9867  9867  9867 10296 10296 10296 10725 10725 10725
 10725
  [85] 11154 11154 11154 11154 11154 11583 11583 11583 11583 12012 12012
 12012
  [97] 12012 12441 12441 12441


 What I want is to produce a vector of lengths for each contiguous run of
 numbers . i.e. for the above example, the first three items of the vector
 returned would be:

 11 8 6

 ...to represent the counts of 0, 429, and 585, respectively.  I could do
 this with unique() and a for loop, but this would be very inefficient. Any
 advice on how to do this efficiently would be most appreciated.

 thanks
 Tony

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Re: [R] [BioC] Empirical Pvalue

2010-02-22 Thread Hervé Pagès

Hi Mohamed,

Please read the posting guides for both, the R-help and BioC mailing
lists, so you learn the basics of how to ask questions on these
lists (and software related mailing lists in general). Following
those guides will greatly increase the chance that someone will
actually be willing (and able) to help you.

Cheers,
H.


Mohamed Lajnef wrote:

Dear R users,

Can someone explain me the interpretation of  empirical p-value ( 
max(t))  used to test the genetic association with PLINK?


Any help will be appreciated
Regards

M




--
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Program in Computational Biology
Division of Public Health Sciences
Fred Hutchinson Cancer Research Center
1100 Fairview Ave. N, M2-B876
P.O. Box 19024
Seattle, WA 98109-1024

E-mail: hpa...@fhcrc.org
Phone:  (206) 667-5791
Fax:(206) 667-1319

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Re: [R] Re : how to plot select points in preexisting persp plot

2010-02-22 Thread Hrishi Mittal

Preeti,

Could you please post a sample of your data and all the code? It is hard to
answer your question without knowing what coords and act are


-
Try  http://prettygraph.com Pretty Graph , the easiest way to make R-powered
graphs on the web.
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[R] Bootstrap Multivariate Times Series Forecast

2010-02-22 Thread Ricardo Gonçalves Silva
Dear Users,

Consider a multivariate time series model:
a_1*y(t)-...-a_k*y(t-k)=b+[c_1*z(t)-...-c_j*z(t-j)]

i.e., a simple multivariate time series model with one exogenous variable.
I would like to know what package can I use to do the following, using R:

1) Select k and j jointly;
2) Estimate the model;
2) Forecast h=4 steps ahead the estimated model;
4) Bootstrap the forecast, since my sample is small.

For univariate time series, I already used the BootBC package, but
I don't know how to perform the analysis in the case here.

Thanks in advance,

Rick
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Re: [R] adding infrequent date labels to x-axis

2010-02-22 Thread emorway

Hello Hrishi, 

The command you suggested plotted the years on the x-axis only.  It was the
same exact plot as the one I included in the original post.

Respectfully,
Eric
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Re: [R] adding infrequent date labels to x-axis

2010-02-22 Thread Hrishi Mittal

Hi emorway,

It seems to me that all you need is one command:

plot(as.Date(cropped.cast1$date,%Y-%m-%d),cropped.cast1$Frac_ET_Satsfd_mean)

-
Try  http://prettygraph.com Pretty Graph , the easiest way to make R-powered
graphs on the web.
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Re: [R] how to make R plot under Linux

2010-02-22 Thread xin wei

hi, Kevin and K.Elo:
thank you for the suggestion. Can you be more specific on these? (like how
exactly get into x-switch or man ssh). I am totally ignorant about linux and
SSH:( Memory limitation forces me to switch from windows to Linux
cluster.

Xin
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Re: [R] SEM error

2010-02-22 Thread John Fox
Dear Jarret, Uwe, and Dan,

Sorry -- I missed the initial question. What's a bit odd here is that the 
singularity occurs only in the computation of the modification indices. It 
might help to look at the conditioning of the covariance matrix of the 
parameter estimates (i.e., the eigenvalues or singular values), which must have 
been invertible.

Regards,
 John

On Mon, 22 Feb 2010 09:00:08 -0800
 Jarrett Byrnes byr...@msi.ucsb.edu wrote:
 I have often found this to happen if the scale of one variable is  orders of 
 magnitude different than the scale of other variables.  Have  you tried 
 inspecting the covariance matrix and log transforming any  such variables?
 
 On Feb 22, 2010, at 8:14 AM, Uwe Ligges wrote:
 
 
 
  On 20.02.2010 08:51, Dan Edgcumbe wrote:
  I'm trying to do some confirmatory factor analysis on some data. My  
  SEM
  model solves in 22 iterations, but when I try to look at the  
  modification
  indices, using mod.indices, I get the following error message:
 
  Error in solve.default(hessian) :
system is computationally singular: reciprocal condition number =
  4.40283e-18
 
  What does this mean?
 
  That the method you apply tries to invert some object called  
  hessian (maybe a hessian? ;-)) but fails since a singular matrix  
  cannot be inverted. Perhaps (as I often found for people doing sem  
  analyses) you have less observations than parameters to estimate or  
  only certain combinations for some factors?
 
  Uwe Ligges
 
 
 
 
 
 
  Many thanks,
 
  Dan
 
 [[alternative HTML version deleted]]
 
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John Fox
Sen. William McMaster Prof. of Social Statistics
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
http://socserv.mcmaster.ca/jfox/

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Re: [R] gsub patterns from vector elements w/out loop?

2010-02-22 Thread Christian Raschke

Marianne,

The function substring2 from the Hmisc packages works nicely for me to 
do this (without explicit gsub, though):


x- c(one,two)
y- paste(rep(x,2),blah)

y
[1] one blah two blah one blah two blah

substring2(y,x)- something else

y
[1] something else blah something else blah something else blah something 
else blah


Christian





On 02/22/2010 10:25 AM, Marianne Promberger wrote:

Dear list,

I have two vectors:

x- c(one,two)
y- paste(rep(x,2),blah)

I want to replace all occurrences of each element of x in y with
something else, so that y looks like this:

y
[1] something else blah something else blah something else blah
[4] something else blah

I can do this using a loop:

for ( i in 1:length(x) ) {
   y- gsub(x[i],something else,y)
}

Surely, there must be a less kludgy way?

I tried looking at the different apply()s but am not getting anywhere,
partly because I lack the mental flexibility to combine the fact that
I am applying gsub() to y but now want to apply that to x ...  erm. :/

Marianne

   



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and
ISDS Research Lab (HSRG)
Louisiana State University
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Re: [R] how to make R plot under Linux

2010-02-22 Thread Vojtěch Zeisek
Dne Po 22. února 2010 18:53:55 xin wei napsal(a):
 hi, Kevin and K.Elo:
 thank you for the suggestion. Can you be more specific on these? (like how
 exactly get into x-switch or man ssh). I am totally ignorant about linux

Hello,
in Linux You can plot as in Windows, for example using hist(x). But not over 
remote connection using SSH. Connect with command similar to
ssh -X your_usern...@remote.server.com
Then You can launch applications making windows. Normally, over SSH You can 
use only text-based applications. But there is one big but: the remote 
server has to support the -X switch. If it is not permitted in configuration 
of server's SSH daemon, You can not use it and You will not have windows with 
Your graphs. Then You would have to ask admin of the server or run R on Your 
own computer. For more information type man ssh.
Best regards,
Vojtěch Zeisek

  and SSH:( Memory limitation forces me to switch from windows to
  Linux cluster.
 
 Xin
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Komunita openSUSE GNU/Linuxu /
Community of the openSUSE GNU/Linux

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Re: [R] how to make R plot under Linux

2010-02-22 Thread K. Elo
Hi!

22.02.2010 19:53, xin wei wrote:
 
 hi, Kevin and K.Elo:
 thank you for the suggestion. Can you be more specific on these? (like how
 exactly get into x-switch or man ssh). I am totally ignorant about linux and
 SSH:( Memory limitation forces me to switch from windows to Linux
 cluster.

Could you provide us with more information about the software you use
for establishing the ssh connection (i.e. your ssh client). I suppose
you are connecting a linux server (having R on it) from a windows
system, aren't you? And you use a ssh client software, right? There
should be an enable X11 forwarding (or something similar) option in
your ssh client application. You should look e.g. in connection settings.

Kind regards,
Kimmo

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Re: [R] Alternatives to linear regression with multiple variables

2010-02-22 Thread Liaw, Andy
You can try the locfit package, which I believe can handle up to 5
variables.  E.g.,

R library(locfit)
Loading required package: akima
Loading required package: lattice
locfit 1.5-6 2010-01-20 
R x - matrix(runif(1000 * 3), 1000, 3)
R y - rnorm(1000)
R mydata - data.frame(x, y)
R str(mydata)
'data.frame':   1000 obs. of  4 variables:
 $ X1: num  0.21 0.769 0.661 0.978 0.15 ...
 $ X2: num  0.426 0.132 0.214 0.774 0.472 ...
 $ X3: num  0.971 0.659 0.474 0.867 0.479 ...
 $ y : num  -0.496 -0.636 1.778 -0.876 0.657 ...
R fit - locfit(y ~ lf(X1, X2, X3), data=mydata)
R plot(fit)

Andy


 -Original Message-
 From: r-help-boun...@r-project.org 
 [mailto:r-help-boun...@r-project.org] On Behalf Of Guy Green
 Sent: Monday, February 22, 2010 7:47 AM
 To: r-help@r-project.org
 Subject: [R] Alternatives to linear regression with multiple variables
 
 
 I wonder if someone can give some pointers on alternatives to linear
 regression (e.g. Loess) when dealing with multiple variables.
 
 Taking any simple table with three variables, you can very 
 easily get the
 intercept and coefficients with:
   summary(lm(read_table))
 
 For obvious reasons, the coefficients in a multiple 
 regression are quite
 different from what you get if you calculate regressions for 
 the single
 variables separately.  Alternative approaches such as Loess seem
 straightforward when you have only one variable, and have the 
 advantage that
 they can cope even if the relationship is not linear.
 
 My question is: how can you extend a flexible approach like Loess to a
 multi-variable scenario?  I assume that any non-parametric calculation
 becomes very resource-intensive very quickly.  Can anyone suggest
 alternatives (preferably R-based) that cope with multiple 
 variables, even
 when the relationship (linear, etc) is not known in advance?
 
 Thanks,
 
 Guy
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Re: [R] how to make R plot under Linux

2010-02-22 Thread Kevin E. Thorpe

K. Elo wrote:

Hi!

22.02.2010 19:53, xin wei wrote:

hi, Kevin and K.Elo:
thank you for the suggestion. Can you be more specific on these? (like how
exactly get into x-switch or man ssh). I am totally ignorant about linux and
SSH:( Memory limitation forces me to switch from windows to Linux
cluster.


Could you provide us with more information about the software you use
for establishing the ssh connection (i.e. your ssh client). I suppose
you are connecting a linux server (having R on it) from a windows
system, aren't you? And you use a ssh client software, right? There
should be an enable X11 forwarding (or something similar) option in
your ssh client application. You should look e.g. in connection settings.

Kind regards,
Kimmo


Agree.  Sounds like you are using a client on Windows.  Also, Vojtech 
Zeisek's reply is pertinent too.


--
Kevin E. Thorpe
Biostatistician/Trialist, Knowledge Translation Program
Assistant Professor, Dalla Lana School of Public Health
University of Toronto
email: kevin.tho...@utoronto.ca  Tel: 416.864.5776  Fax: 416.864.3016

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Re: [R] adding infrequent date labels to x-axis

2010-02-22 Thread Hrishi Mittal

Hi emorway,

You are right. I tried the command only with one year's data, in which case
it plots month names as labels. But for multiple years, the labels become
years. I found this old post useful -
http://n4.nabble.com/Month-tick-marks-on-a-plot-td879121.html#a879121.
Picking the code from the comment by Gavin Simson, I think this should work:


plot(as.Date(cropped.cast1$date,%Y-%m-%d),cropped.cast1$Frac_ET_Satsfd_mean,xaxt=n)
 

x-as.Date(cropped.cast1$date,%Y-%m-%d)

ticks.at - seq(min(x), max(x), by = months)
## format the labels as abbreviated month names
ticks.lab - format(ticks.at, format = %b)
## indicator variable; is month January?
m1 - ticks.lab == Jan
## plot small ticks and labels for months not Jan
Axis(x, at = ticks.at[!m1], side = 1,
 labels = ticks.lab[!m1], las = 2, cex.axis = 0.7)
## plot the default tick locations for years
Axis(x, side = 1, las = 2)
## add the box 
box()



-
Try  http://prettygraph.com Pretty Graph , the easiest way to make R-powered
graphs on the web.
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Re: [R] adding infrequent date labels to x-axis

2010-02-22 Thread emorway

Hello Hrishi,

That worked great, and in the process I learned some new ways of going about
writing R code.  Thank you very much for helping me out!

Eric
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Re: [R] gsub patterns from vector elements w/out loop?

2010-02-22 Thread Gabor Grothendieck
Here are a few possibilities using gsubfn in the gsubfn package

x - c(one,two)
y - paste(rep(x,2),blah)

library(gsubfn)
# 1
gsubfn(\\w+, w ~ if (w %in% x) something else else w, y)

# 2
gsubfn(\\w+, list(one = something else, two = something else), y)

# 3
L - sapply(x, function(...) something else, simplify = FALSE)
gsubfn(\\w+, L, y)

gsubfn is the same as gsub except the second argument can be a
function, list or certain other objects.

The regular expression \\w+ matches each word in y and in the first
solution that is replaced with phrase or just returned according to
the function which is specified in formula notation.

The second solution uses the fact that gsubfn allows lists such that
the names of the list components are matched and replaced with the
corresponding contents.

The third is the same as the second except that it uses sapply to
create the list from x.


On Mon, Feb 22, 2010 at 11:55 AM, Marianne Promberger
marianne.promber...@kcl.ac.uk wrote:

  gsub(paste(x, collapse = |), something else, y)
 [1] something else blah something else blah something else blah
 [4] something else blah

 Many thanks! I didn't know about collapse. Should have thought about
 reading up in ?paste ...

 Thanks

 Marianne

 --
 Marianne Promberger PhD, King's College London
 http://promberger.info
 R version 2.10.1 (2009-12-14)
 Ubuntu 9.10

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Re: [R] how to make R plot under Linux

2010-02-22 Thread Zhuanshi He
Hi,

You just need to install X11 windows software on windows, such as
xming, and start xming before ssh -X use...@remotehost

Hope this helps.


On 2/22/10, xin wei xin...@stat.psu.edu wrote:


  thank you for reply. I just type: hist(x) from SSH terminal, expecting a
  histogram to pop up like what i got under windows.instead I got the
  following error msg:

  Error in X11(d$display, d$width, d$height, d$pointsize, d$gamma,
  d$colortype,  :
   unable to start device X11cairo
  In addition: Warning message:
  In function (display = , width, height, pointsize, gamma, bg,  :
   unable to open connection to X11 display ''

  Would you give some clues what is going on?

  thanks



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-- 
Zhuanshi He / Z. He (PhD)
Waterloo Centre for Atmospheric Sciences (WCAS)
Department of Earth and Environmental Sciences
Phy Bldg, Rm 2022
University of Waterloo,
Waterloo, ON N2L 3G1
Canada
Tel: +1-519-888-4567 ext 36667

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[R] First Appearance of value in splitted matrix

2010-02-22 Thread jorgusch

Hello,

I have a large matrix (foo), I have to split by weeks and in which measures
start at different points of time.

Now I am looking for the number of the week, in which a specific value
appears. I do not need the date or any other information from a row, but
(due to structure of result table) the indicator i.

One example:
foo has two columns: Date, ID


foo.all- split(foo, cut(foo$Date, weeks)
l_foo-length(foo.all)
for (i in 1:l_foo){
foo.i-foo.all[[i]]
}

Question:
Given I search for ID=4. How do I find the i, in which 4 appears?


Thanks in advance!
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[R] Goodness of fit test for count data

2010-02-22 Thread pinusan

Dear  all, 

I am trying to test goodness of fit. I assume that a data follow Poisson or
Negative binomial distribution. I can test the goodness of fit in case of no
truncated data. However, I could not find any good function or packages when
a data is truncated.  

For example, a frequency table for the number of visiting emergency room in
one hundred one observations past one year is as follow: 
N freq 
1 30 
2 35 
3 26 
4 8 
5 0 
6 2 
7 0 

 I expect the frequency table to satisfy a Poisson distribution or Negative
binomial distribution. However, the distribution is different from the usual
Poisson or Negative binomial distribution because one value, zero, is
excluded. I expect that the distribution is zero truncated distribution. 

In case of SAS, I used NLMIXED procedure to calculate the expected
probability when y=1 … y=n under the assumption that a data follows Poisson
or Negative binomial distribution. And then I run Chi-square test. If you
need the SAS code, I will send E-mail.
I want to run this test in R.
Could you suggest any idea that can I perform this test in R.

Have a nice day.

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[R] useR! 2010, Submission/early registration deadline: March 1

2010-02-22 Thread Katharine Mullen
Dear R-help members,

This message is to remind you that the submission deadline for abstracts
for the R User Conference, useR! 2010, is one week away:

Submission deadline:  Monday, March 1, 2010

The deadline for early registration is also Monday, March 1, 2010.

I encourage you all to submit abstracts (to give a presentation, or to
present a poster).  More information regarding the conference is pasted
below.

best regards,
Kate Mullen, for the useR! 2010 organizing committee

--
We are happy to announce that the R User Conference

   useR! 2010
   http://www.R-project.org/useR-2010

is scheduled for July 21-23, 2010, and will take place at the headquarters
of the National Institute of Standards and Technology (NIST) in
Gaithersburg, Maryland, USA.

Following the successful useR! 2004, useR! 2006, useR! 2007, useR! 2008,
and useR! 2009, conferences, the conference is focused on:

   1. R as the `lingua franca' of data analysis and statistical computing,
   2. providing a platform for R users to discuss and exchange ideas on
  how R can be used to do statistical computations, data analysis,
  visualization and exciting applications in various fields,
   3. giving an overview of the new features of the rapidly evolving R
  project.

As for the predecessor conferences, the program will consist of two parts:
invited lectures and user-contributed sessions.  Prior to the conference,
there will be tutorials on R, descriptions of which are available at
   http://www.R-project.org/useR-2010/tutorials

All R users are invited to submit abstracts on exciting applications of R
as specified in the call at
   http://www.R-project.org/useR-2010/#Call

The deadline for abstract submission (and early registration) is
   March 1, 2010.

INVITED LECTURES

Invited speakers will include

Mark Handcock, Frank Harrell Jr, Friedrich Leisch, Michael Meyer,
Richard Stallman, Luke Tierney, Diethelm Wuertz.

USER-CONTRIBUTED SESSIONS

The sessions will be a platform to bring together R users, contributors,
package maintainers and developers in the S spirit that `users are
developers'. People from different fields will show us how they solve
problems with R in fascinating applications.  The sessions are organized
by members of the program committee, including

 Dirk Eddelbuettel, John Fox, Virgilio Gomez-Rubio,
 Richard Heiberger, Torsten Hothorn, Aaron King, Jan de Leeuw,
 Nicholas Lewin-Koh, Andy Liaw, Uwe Ligges, Martin Maechler,
 Katharine Mullen, Heather Turner, Ravi Varadhan, H. D. Vinod,
 John Verzani, Alan Zaslavsky, Achim Zeileis.

The program will cover topics such as

 * Applied Statistics  Biostatistics
 * Bayesian Statistics
 * Bioinformatics
 * Chemometrics and Computational Physics
 * Data Mining
 * Econometrics  Finance
 * Environmetrics  Ecological Modeling
 * High Performance Computing
 * Machine Learning
 * Marketing  Business Analytics
 * Psychometrics
 * Robust Statistics
 * Social network analysis
 * Spatial Statistics
 * Statistics in the Social and Political Sciences
 * Teaching
 * Visualization  Graphics
 * and many more.

IMPORTANT DATES

   2009-10-01   open submission of abstracts
   2009-10-01   open registration
   2009-11-01   tutorial submission deadline

** 2010-03-01   early registration deadline
** 2010-03-01   submission deadline for abstracts

   Before 2010-03-15notification of acceptance
   2010-06-20   registration deadline
(later registration NOT possible on site)
   2010-07-20   tutorials
   2010-07-21   conference start
   2010-07-23   conference end

We hope to meet you in Gaithersburg!

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