Re: [R] Adding a column into the file

2012-06-03 Thread John
On Fri, 1 Jun 2012 09:27:58 -0700 (PDT)
pigpigmeow gloryk...@hotmail.com wrote:

 Dear all,
 I have a lot of problems on R-programming.
 for example
 my csv. file is ..
 Date  wrfRH wrfsolar wrfwindspeed wrfrain wrftd wrfta
 21/10/2010 92.97 22.11 53.27 0 1546.337861 61.00852664
 22/10/2010 87.35 21.99 40.89 0 1300.408288 62.85352227
 23/10/2010 88.38 21.71 28.04 0.01 1381.768284 54.80594493
 24/10/2010 92.32 15.45 22.38 0.51 1113.90981 39.46573663
 25/10/2010 93.42 21.59 35.5 0.52 868.4895334 28.42952321
 26/10/2010 93.38 20.15 42.58 0.07 1404.722837 40.29300856 
 i calculate the ratio of wrfRH/wrfsolar for each day.
 
 that is  
 Date  wrfRH 
 wrfwindspeed wrfrain wrftd wrfta ratio 
 21/10/2010 92.97 22.11 53.27 0 1546.337861 61.00852664  
 22/10/2010 87.35 21.99 40.89 0 1300.408288 62.85352227  
 23/10/2010 88.38 21.71 28.04 0.01 1381.768284 54.80594493 
 24/10/2010 92.32 15.45 22.38 0.51 1113.90981 39.46573663 
 25/10/2010 93.42 21.59 35.5 0.52 868.4895334 28.42952321 
 26/10/2010 93.38 20.15 42.58 0.07 1404.722837 40.29300856  
 
 how to add new column in the original file ? Anyone can help me?!
 
First, that is not a csv file.  Your delimiter is a space.  Second, it
appears that the first and second records contain two spaces
between the wrtfa column and the ratio column.  Since you don't provide
an example how how you actually read the data table into R, there's no
way to say what else might be wrong.  If you specify an escaped space
as the delimiter, the read should fail at about the third line.  

Now, if you use R to calculate the ratio the story is different.  I
would guess you simply want to join the calulated field to your data
frame:

To move the new data to a data frame, calculate the new variable and
then assemble the new data frame:

ratio - dat$wrfRH/dat$wrfsolar

then

newdataframe - data.frame(dat, ratio)

which should yield what I believe you want.

That of course assumes that what you really want to do is simply add
the new column of calculated values to the original data.  There also
any number of very helpful books about R that can probably help.

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[R] Add a dim to an array

2012-06-03 Thread Patrick Hausmann

Dear list,

I'm trying to add a new dim to a multidimensional array. My array looks 
like this


a1 - array(1:8, c(2, 2, 2))
dimnames(a1) - list(A = c(A1, A2),
 B = c(B1, B2),
 D = c(D1, D2))

I would like to add a new dim 'group' with the value low. Right now 
I'm using this, but I think are better ways...


a2 - as.data.frame(as.table(a1))
a2$group - low
a2 - xtabs(Freq ~ A + B + D + group, data = a2)
a2

Thanks for any help!
Patrick

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Re: [R] Average curve in R

2012-06-03 Thread QAMAR MUHAMMAD UZAIR
Arun and Rui Barradas: thankyou very much for sorting out 
my issue. I got what I wanted.


Rainer Schuermann and Jeff Newmiller: thankyou very much 
for your suggestion. I will take care of it in future.


regards
-

On Fri, 1 Jun 2012 19:47:05 -0700 (PDT)
 arun smartpink...@yahoo.com wrote:

Hi Qamar,

I guess you are looking for row means vs. days plot.

If that is the case, try this:
datQ-cbind(c(6,5,6,7,4,3,5),c(2,4,35,32,4,6,6),c(2,4,2,3,423,4,5),c(2,3,13,5,3,5,3))

datQmean- apply(datQ,1,mean)
[1]   3.00   4.00  14.00  11.75 108.50   4.50   4.75
datQmean-data.frame(datQmean)
 days-c(1:7)

datQplot-data.frame(datQmean,days)
plot(datQmean~days,data=datQplot,type=l)

A.K.







- Original Message -
From: QAMAR MUHAMMAD UZAIR d029...@polito.it
To: r-help@r-project.org
Cc: 
Sent: Friday, June 1, 2012 5:31 PM

Subject: [R] Average curve in R

Dear R users,
l
I have weekly data in the following manner

[,1]    [,2]    [,3]    [,4]
6    2    2    2
5    4    4    3
6    35    2    13
7    32    3    5
4    4    423    3
3    6    4    5
5    6    5    3

I drew curve of each column against days 
(1,2,3,4,5,6,7). Now I want to draw an average curve (a 
representative curve) of the whole data. Is there a way 
in R to perform such operation? please reply ASAP as i 
have an assignment to submit on monday.

Thanks in Advance..
regards

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[R] Log-normal probability plot

2012-06-03 Thread eliza botto




Dear R users,

You can literally safe my
life my telling me the solution of my problem. I have created matrix of a data
frame with 3 columns, with each column representing data of different year. 

 


 
  
  2
  
  
  1
  
  
  5
  
 
 
  
  3
  
  
  4
  
  
  4
  
 
 
  
  4
  
  
  3
  
  
  32
  
 
 
  
  3
  
  
  4
  
  
  4
  
 
 
  
  4
  
  
  32
  
  
  5
  
 
 
  
  3
  
  
  4
  
  
  2
  
 
 
  
  1
  
  
  3
  
  
  4
  
 


 

I now want to plot “Lognormal
probability plot” of each column data against its respective “normal reduced
variante(z)”. 

How to do that?

If you don’t know the
answer, consider me dead.

  
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[R] Memory-random forest

2012-06-03 Thread MYRIAM TABASSO
Hi all,
I am working with random forest on the large data set( 39).
I have a warning message : In matrix(integer(nrnodes * nt), ncol = nt) :
Reached total allocation of 3766Mb: see help(memory.size).
Can you have any suggestions?
Thanks,
Myriam

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[R] Compare data between two groups/countries on 5-point Likert scale questionnare?

2012-06-03 Thread Frankfoot
Hi everyone, I'm stuck on my dissertation which is due next week. I'm a
business major student and my project is a comparative research on corporate
social responsibility (CSR) between Chinese and German firms. According to
my literature review, it's quite obvious that German firms have much better
CSR initiatives and strategies than the Chinese ones and I wanted to test
whether it was true by sending out Likert-scale questionnaires to Chinese
and German firms through bankers in my family. I have already got 24
responses from the Chinese and 27 from the Germans and it looked quite
evident that the hypothesis is correct. Now that I am writing my analysis
chapter, I am lost as I don't know which is the best way to analyse my data
after trying to find a solution for days. Basically, my questionnaire is
structured in this way:

Q1 - Q5: statements on environment-oriented CSR
Q6 - Q10: statements on workplace-oriented CSR
Q11 - Q15: statements on community-oriented CSR
Q16-Q20: statements on market-oriented CSR

All of the statements are 5-pt Likert questions. I initially planed to
compare the grouped mean values for each of the above section but I know
that it's not scientific. So can someone give me any advice on which kind of
tests is most suitable for my research? As you can see, my sample size is
quite small. I really appreciate your time!

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Re: [R] points() function will not plot

2012-06-03 Thread Sarah Goslee
Looks like you've swapped x and y.

Sarah

On Friday, June 1, 2012, David Winsemius wrote:


 On Jun 1, 2012, at 4:09 PM, jcrosbie wrote:

  I can not get the point function to work with in my code.

 The code:

  AggOfTempMatrix$**CumSumPercentSize-c(
 0.05265450, 0.05738490, 0.05865403, 0.05911553, 0.05957703, 0.06003854,
 0.06058368,
 0.06098750, 0.06147208, 0.06187589, 0.06291427, 0.06331808, 0.06354884,
 0.06408533,
 0.06489296, 0.07382014, 0.07397590, 0.08124456, 0.08228294, 0.0827,
 0.08283097,
 0.08306172, 0.08349438, 0.08372513, 0.08412894, 0.08435969, 0.08453276,
 0.08491350,
 0.08570382, 0.08599226, 0.08749791, 0.08831131, 0.08848437, 0.08954582,
 0.09058420,
 0.09069958, 0.09112358, 0.09123896, 0.11087010, 0.11410062, 0.15309754,
 0.20017364,
 1.)

 AggOfTempMatrix$Price-c(
 0.00,  71.35,  72.00,  74.00,  75.00,  76.00,  84.24,  87.00, 88.00,
  90.24,
 91.00,
 94.22,  96.00,  98.00, 100.25, 121.00, 246.12, 272.44, 273.00, 295.00,
 435.00, 455.14,
 460.00, 475.00, 586.00, 591.00, 609.00, 622.00, 656.00, 750.00, 789.16,
 798.00, 813.00,
 834.00, 850.00, 895.00, 904.00, 915.00, 916.00, 924.00, 950.00, 996.66,
 999.24)

 plot(AggOfTempMatrix$Price, AggOfTempMatrix$**CumSumPercentSize,
 type=l,
 main = mainTitle, xlab=xAxislable, ylab=yAxislable, lwd=5)
 points(x=0.5, y =300, col=darkred,pch=12) #this wont plot


 Your y range is from 0 to 1. Why would you expect to see that point?

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 View this message in context: http://r.789695.n4.nabble.com/**
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 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT

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-- 
Sarah Goslee
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http://www.sarahgoslee.com
http://www.functionaldiversity.org

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[R] igraph and igraph0

2012-06-03 Thread jalantho...@verizon.net
Could someone tell me the difference between igraph and igraph0?

I searched the CRAN web site, but cannot find an explantion of the differences.

Thanks, Alan


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Re: [R] R and igraph problems

2012-06-03 Thread jalantho...@verizon.net
Why is igraph 0.5.5 not on the igraph sourceforgwe home page?


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Re: [R] Help with this web scrape function

2012-06-03 Thread Sven D
Would like to see this at the top again, as I think it did not get pick up
when I posted it initially.

Apologies, last try.




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Re: [R] About Plot.new

2012-06-03 Thread czar
@mr.parashar4 - If this not resolved yet, here is what can help
plot.new is trying to create a new object out of the standard point plot. I
believe you have not created a standard point plot, i.e. in your case,
plot(xm,ym). This will show the graphical plot window. Keep that window open
and then run your given command.
If you have already defined plot(), then just keep that window open. That is
when R will find the object and go ahead with the further commands over the
plot you specify.
Hope this helps.

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Re: [R] Add a dim to an array

2012-06-03 Thread Rui Barradas

Hello,

Try

a3 - array(dim=c(2, 2, 2, 2))
dn - dimnames(a1)
dn$group - c(low, high)
dimnames(a3) - dn
a3[] - a1  # to use [] keeps the dimensions
a3  # it fills a3 recycling a1 (two copies)

dim(a2)
dim(a3)


As you can see, 'a2' is not of the right dimensions, and 'a3' has now 
two copies of 'a1' but it's dimensions are right.
There are ways of giving dimnames to 'a3' other than creating a new 
object, 'dn', but this one is a simple one.


Hope this helps,

Rui Barradas

Em 02-06-2012 16:17, Patrick Hausmann escreveu:

Dear list,

I'm trying to add a new dim to a multidimensional array. My array 
looks like this


a1 - array(1:8, c(2, 2, 2))
dimnames(a1) - list(A = c(A1, A2),
 B = c(B1, B2),
 D = c(D1, D2))

I would like to add a new dim 'group' with the value low. Right now 
I'm using this, but I think are better ways...


a2 - as.data.frame(as.table(a1))
a2$group - low
a2 - xtabs(Freq ~ A + B + D + group, data = a2)
a2

Thanks for any help!
Patrick

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[R] R 15.0 Warning message.

2012-06-03 Thread Jinyan Huang
Dear list,

I have install R15.0 on Ubuntu system using the source code. It is
install to my home directory. I have no root privilege.  When I start
R, I got this warning message:

During startup - Warning message:
Setting LC_CTYPE failed, using C

How can I fix this?

Thanks.

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Re: [R] Add a dim to an array

2012-06-03 Thread Petr Savicky
On Sat, Jun 02, 2012 at 05:17:36PM +0200, Patrick Hausmann wrote:
 Dear list,
 
 I'm trying to add a new dim to a multidimensional array. My array looks 
 like this
 
 a1 - array(1:8, c(2, 2, 2))
 dimnames(a1) - list(A = c(A1, A2),
  B = c(B1, B2),
  D = c(D1, D2))
 
 I would like to add a new dim 'group' with the value low. Right now 
 I'm using this, but I think are better ways...
 
 a2 - as.data.frame(as.table(a1))
 a2$group - low
 a2 - xtabs(Freq ~ A + B + D + group, data = a2)
 a2

Hi.

Try the following.

  a1 - array(1:8, c(2, 2, 2))
  dimnames(a1) - list(A = c(A1, A2),
   B = c(B1, B2),
   D = c(D1, D2))
  a2 - array(a1, c(2, 2, 2, 1))
  dimnames(a2) - c(dimnames(a1), list(group = low))
  a2

  , , D = D1, group = low
  
  B
  AB1 B2
A1  1  3
A2  2  4
  
  , , D = D2, group = low
  
  B
  AB1 B2
A1  5  7
A2  6  8

Hope this helps.

Petr Savicky.

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[R] Modify pdf file with Illustrator.

2012-06-03 Thread Jinyan Huang
Dear list,

Some times I want to modify the pdf file which produced by R with
illustrator. But when I use Illustrator open the pdf file, it often
makes the pdf some little changed. Anyone have some suggestions? Is it
better to use other file type, not pdf? Or when I produced the pdf, I
should set some other parameters?

Thank you

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Re: [R] R 2.15.0 and 2.14.2 crash on the same code that runs on 2.14.1

2012-06-03 Thread peter dalgaard

On Jun 3, 2012, at 07:40 , Ebrahim Jahanshiri wrote:

 Dear list,
 
 My code runs on 2.14.1 smoothly (with no error) but makes R crash on 2.14.2
 and 2.15.0 with the usual windows message about R for windows GUI
 front-end has stopped working... and as such I dont have any access to R
 to get any error or warning message (if any). It crashes on random parts of
 the code any time that I run it.
 The code consists of EDA and spatial regression and various loops
 and optimizations. The goal of the code is to perform a complete analysis
 on various datasets.
 Please take a look at the code here :
 https://sites.google.com/site/geosciej/Home/STAR_ter1.R?attredirects=0d=1

You are not likely to find people willing to debug 15553 lines of code for you, 
and they are certainly not going to do it by eye, without the datasets!

One thing that jumps out is that you start off by loading five external 
packages, either of which might be the true owner of the problem. Even if the 
actual crash hits in the stats.dll, the underlying issue could well be memory 
corruption occurring some time earlier. 

Things to try:

Run under Rterm in a command window instead of Rgui. That should at least tell 
you how far you got before the crash, maybe even a proper traceback.

Carefully try disabling parts of the code until the issue goes away. The last 
item removed might hold the clue. If you can cut it down to something 
small(-ish) and reproducible, people might be in a better position to help you.

Is it really a random crash, or does the crash point move every time you change 
the code slightly? If the former, you might have physical computer problems or 
you might be running close to your memory limit.

-Peter D.

 
 It seems that the results that comes out of 2.15.0 is more valid for my
 work.
 
 I cant think of anything that makes the code crash on the latest versions.
 
 Here is the error message from windows:
 
  Problem Event Name: APPCRASH
  Application Name: Rgui.exe
  Application Version: 2.150.58871.0
  Application Timestamp: 4f75a0ca
  Fault Module Name: stats.dll
  Fault Module Version: 2.150.58871.0
  Fault Module Timestamp: 4f75a1c9
  Exception Code: c005
  Exception Offset: 000237c5
  OS Version: 6.1.7601.2.1.0.256.48
  Locale ID: 1033
  Additional Information 1: 0a9e
  Additional Information 2: 0a9e372d3b4ad19135b953a78882e789
  Additional Information 3: 0a9e
  Additional Information 4: 0a9e372d3b4ad19135b953a78882e789
 
 
 
 I appreciate your help,
 
 Thank you
 Ebrahim Jahanshiri
 
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Re: [R] R and igraph problems

2012-06-03 Thread peter dalgaard

On Jun 2, 2012, at 15:43 , jalantho...@verizon.net wrote:

 Why is igraph 0.5.5 not on the igraph sourceforgwe home page?

You'll have to ask the igraph developers... Possibly, they just ran out of 
round tuits.

-- 
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Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk  Priv: pda...@gmail.com

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Re: [R] R 2.15.0 and 2.14.2 crash on the same code that runs on 2.14.1

2012-06-03 Thread Ebrahim Jahanshiri
Thank you very much.

Memory problem or heat (of CPU?) is the main suspect here for me. But how
is it that 2.14.1 can run it but others can not I dont know (maybe some
mechanisms that prevent memory problem in 2.14.1 are not working in the
latest versions. One thing for sure is that the speed of loops are really
higher in 2.15 and the results as I said are more valid for me).

I did use divide and conquer and it think the optimization part with
nlminb() is the main suspect here (the code does 28 nlminb() in each loop)
but again how is it that it does not work sometimes is really a mystery to
me.

I did try running the code on different machines (32 and 64 bit windows 7
with 4GB of RAM mainly CORE2DUO and CORE i5) but all of them had crashes at
random parts.

I will continue to post my observations to the group along with a smaller
reproducible code and the dataset.

Thank you

EJ


On Sun, Jun 3, 2012 at 3:17 PM, peter dalgaard pda...@gmail.com wrote:


 On Jun 3, 2012, at 07:40 , Ebrahim Jahanshiri wrote:

  Dear list,
 
  My code runs on 2.14.1 smoothly (with no error) but makes R crash on
 2.14.2
  and 2.15.0 with the usual windows message about R for windows GUI
  front-end has stopped working... and as such I dont have any access to R
  to get any error or warning message (if any). It crashes on random parts
 of
  the code any time that I run it.
  The code consists of EDA and spatial regression and various loops
  and optimizations. The goal of the code is to perform a complete analysis
  on various datasets.
  Please take a look at the code here :
 
 https://sites.google.com/site/geosciej/Home/STAR_ter1.R?attredirects=0d=1

 You are not likely to find people willing to debug 15553 lines of code for
 you, and they are certainly not going to do it by eye, without the
 datasets!

 One thing that jumps out is that you start off by loading five external
 packages, either of which might be the true owner of the problem. Even if
 the actual crash hits in the stats.dll, the underlying issue could well be
 memory corruption occurring some time earlier.

 Things to try:

 Run under Rterm in a command window instead of Rgui. That should at least
 tell you how far you got before the crash, maybe even a proper traceback.

 Carefully try disabling parts of the code until the issue goes away. The
 last item removed might hold the clue. If you can cut it down to something
 small(-ish) and reproducible, people might be in a better position to help
 you.

 Is it really a random crash, or does the crash point move every time you
 change the code slightly? If the former, you might have physical computer
 problems or you might be running close to your memory limit.

 -Peter D.

 
  It seems that the results that comes out of 2.15.0 is more valid for my
  work.
 
  I cant think of anything that makes the code crash on the latest
 versions.
 
  Here is the error message from windows:
 
   Problem Event Name: APPCRASH
   Application Name: Rgui.exe
   Application Version: 2.150.58871.0
   Application Timestamp: 4f75a0ca
   Fault Module Name: stats.dll
   Fault Module Version: 2.150.58871.0
   Fault Module Timestamp: 4f75a1c9
   Exception Code: c005
   Exception Offset: 000237c5
   OS Version: 6.1.7601.2.1.0.256.48
   Locale ID: 1033
   Additional Information 1: 0a9e
   Additional Information 2: 0a9e372d3b4ad19135b953a78882e789
   Additional Information 3: 0a9e
   Additional Information 4: 0a9e372d3b4ad19135b953a78882e789
 
 
 
  I appreciate your help,
 
  Thank you
  Ebrahim Jahanshiri
 
[[alternative HTML version deleted]]
 
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 http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.

 --
 Peter Dalgaard, Professor,
 Center for Statistics, Copenhagen Business School
 Solbjerg Plads 3, 2000 Frederiksberg, Denmark
 Phone: (+45)38153501
 Email: pd@cbs.dk  Priv: pda...@gmail.com










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Re: [R] R 15.0 Warning message.

2012-06-03 Thread Prof Brian Ripley

On 03/06/2012 07:34, Jinyan Huang wrote:

Dear list,

I have install R15.0 on Ubuntu system using the source code. It is
install to my home directory. I have no root privilege.  When I start
R, I got this warning message:

During startup - Warning message:
Setting LC_CTYPE failed, using C

How can I fix this?


You will need to ask once R 15.0 is released (sometime next century?).

But in a released version of R, the problem would be your locale 
settings, so study the manual at e.g. 
http://cran.r-project.org/doc/manuals/R-admin.html#Internationalization


Since you managed to install it, something is different in your 
environment now from when you installed R.  Check your environment 
variables such as LC_ALL or LANG.  A guess is that you have .utf8 where 
.UTF-8 is required, or v.v.




Thanks.

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PLEASE do, and note what it says about R versions.

--
Brian D. Ripley,  rip...@stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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[R] fine control of plots after use of layout(matrix ...

2012-06-03 Thread Matthew Johnson
Sir,

I would like to create a combined line-bar plot, with the line up top and
bar plot below, but with the x-axes suppressed on the topmost plot, the
line and bar plot areas joined by a common line, and the x-axes (of dates)
joined to the bottom part of the bar plot.

i have been able to format the area using the layout(matrix( ... commands,
but cannot figure out the final step.

here's the code so far:


layout(matrix(c(1,2), 2, 1, byrow=TRUE), widths=c(3,3), heights=c(2,1))
plot(saDwlPx[,1])
barplot(saDwlMoM[,1])

thanks + best regards

matt johnson

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Re: [R] Add a dim to an array

2012-06-03 Thread Rui Barradas

Hello again,

Sorry, I've misread your post and thought that you wanted the new dim to 
have 'low' and 'high' values.
It's just 'low'. So dim=c(2, 2, 2, 1) and set dn$group to the first 
value only.

And forget the final comments.

Rui Barradas

Em 03-06-2012 07:31, Rui Barradas escreveu:

Hello,

Try

a3 - array(dim=c(2, 2, 2, 2))
dn - dimnames(a1)
dn$group - c(low, high)
dimnames(a3) - dn
a3[] - a1  # to use [] keeps the dimensions
a3  # it fills a3 recycling a1 (two copies)

dim(a2)
dim(a3)


As you can see, 'a2' is not of the right dimensions, and 'a3' has now 
two copies of 'a1' but it's dimensions are right.
There are ways of giving dimnames to 'a3' other than creating a new 
object, 'dn', but this one is a simple one.


Hope this helps,

Rui Barradas

Em 02-06-2012 16:17, Patrick Hausmann escreveu:

Dear list,

I'm trying to add a new dim to a multidimensional array. My array 
looks like this


a1 - array(1:8, c(2, 2, 2))
dimnames(a1) - list(A = c(A1, A2),
 B = c(B1, B2),
 D = c(D1, D2))

I would like to add a new dim 'group' with the value low. Right now 
I'm using this, but I think are better ways...


a2 - as.data.frame(as.table(a1))
a2$group - low
a2 - xtabs(Freq ~ A + B + D + group, data = a2)
a2

Thanks for any help!
Patrick

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Re: [R] R 15.0 Warning message.

2012-06-03 Thread Jinyan Huang
Yes. I think it is my environment variables problem. But I donot know
how to fix.

echo $LC_ALL

echo $LANG
en_US.UTF-8


On Sun, Jun 3, 2012 at 4:07 PM, Prof Brian Ripley rip...@stats.ox.ac.uk wrote:
 LANG

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Re: [R] R 15.0 Warning message.

2012-06-03 Thread Prof Brian Ripley

On 03/06/2012 09:27, Jinyan Huang wrote:

Yes. I think it is my environment variables problem. But I donot know
how to fix.


That is described in the same manual.


echo $LC_ALL

echo $LANG
en_US.UTF-8


On Sun, Jun 3, 2012 at 4:07 PM, Prof Brian Ripleyrip...@stats.ox.ac.uk  wrote:

LANG


No, that's not what I wrote.  The posting guide required you to quote 
the context, and excising it is a breach of the conditions under which 
you are allowed to copy the work of others.



--
Brian D. Ripley,  rip...@stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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Re: [R] mtext bug

2012-06-03 Thread Duncan Murdoch

On 12-06-02 8:42 PM, Matthew Johnson wrote:

Sir,

I am now having a similar problem with the barplot: i cannot get the
margin text to 'stick'.

png(paste(drive, MoMUnit.png, sep=))
par(mar=c(10, 3, 2, 2), opar=(1,0,0,0))


I think opar is a typo.

Duncan Murdoch


mainnameUnit = expression(paste(MoM %, Delta,  Apptmnt Prices, sep=))
ymin - min(percentDiff[,c(6, 9, 33, 36, seq(15,30,3), 3)]) -1
ymax - max(percentDiff[,c(6, 9, 33, 36, seq(15,30,3), 3)]) +1
barplot(percentDiff[,c(6, 9, 33, 36, seq(15,30,3), 3)], las=2, beside=T,
ylim=c(ymin, ymax), legend.text=c(prior2m, prior1m, ee),
 main=mainnameUnit)
mtext(stamp, cex=0.75, line=0, side=1, adj=1, outer=T)
mtext(Source: ASX, cex=0.75, side=1, adj=0, outer=T)
dev.off()

i also have a few assorted issues that i cannot figure out -- i would
like to remove the box around the bar plot, and add some intro text
above the key, as i have done in the line plot case.

thanks and best regards

matt johnson

On 3 June 2012 08:38, Matthew Johnson mcoog...@gmail.com
mailto:mcoog...@gmail.com wrote:

thanks very much - fixed.


On 3 June 2012 08:26, Duncan Murdoch murdoch.dun...@gmail.com
mailto:murdoch.dun...@gmail.com wrote:

On 12-06-02 6:21 PM, Matthew Johnson wrote:

Sir,

I have hit a the limits of my understanding of text / par /
opar etc...

I have a few related xts data frames which have multiple
columns, and have
written a for-loop to make a set of charts - however i do
not get any
margin text when i run the loop.

when i test the code outside of the loop the margin text
appears - however
when i run the loop the margin text does not appear ... what
gives?


You're calling par() before png().  Your par() settings will
apply to the device that was active before you open the png()
device, not to it.

Duncan Murdoch


here is the code

for (col in 1:ncol(xdf)){
   par(mar=c(3.5, 4.5, 2, 1), oma=c(2,0,0,0))
   ymin = min(xdf[,col]) - 20
   ymax = max(xdf[,col]) + 20
   png(paste(drive, names(xdf)[col], '.png', sep=))
   plot(coredata(yr09_10[,col]), type='l', ylim=c(ymin,
ymax), col=1, lwd=2,
las=1, xlab=, ylab=,
xaxt='n', main=names(xdf)[col])
   lines(coredata(yr10_11[,col]), col=2, lwd=2)
   lines(coredata(yr11_12[,col]), col=3, lwd=2)
   axis(1, at=c(1:365), labels=format(index(yr09_10),
%d-%b), tck=0.01,
las=1)
   legend(bottom, inset=0.02, title=Financial Years,
c(09/10, 10/11,
11/12), col=c(1,2,3), lwd=3, horiz=TRUE, bty='n')
   mtext(stamp, cex=0.75, line=0, side=1, adj=1, outer=T)
   mtext(Source: ABS, cex=0.75, side=1, adj=0, outer=T)
   dev.off()
}

the charts are certainly re-made each time (i've checked
this!) and they
appear as desired, excepting the absence of the margin text.

could anyone please help?

tips on any other aspects of the above code are also very
welcome.

thanks and best regards

matt johnson

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Re: [R] R 15.0 Warning message.

2012-06-03 Thread peter dalgaard

On Jun 3, 2012, at 10:27 , Jinyan Huang wrote:

 Yes. I think it is my environment variables problem. But I donot know
 how to fix.
 
 echo $LC_ALL
 
 echo $LANG
 en_US.UTF-8
 
 
 On Sun, Jun 3, 2012 at 4:07 PM, Prof Brian Ripley rip...@stats.ox.ac.uk 
 wrote:
 LANG

First, use locale to check that the above is the full story.

For finding the right locale, try starting R with, e.g.

LANG=en_US.utf8 R

or, for a more scientific approach, find your system locale database, usually 
/usr/share/locale, and look for a suitable name:

pd$ ls -ld /usr/share/locale/en_US*
drwxr-xr-x  8 root  wheel  272 Sep 25  2010 /usr/share/locale/en_US
drwxr-xr-x  8 root  wheel  272 Sep 25  2010 /usr/share/locale/en_US.ISO8859-1
drwxr-xr-x  8 root  wheel  272 Sep 25  2010 /usr/share/locale/en_US.ISO8859-15
drwxr-xr-x  8 root  wheel  272 Sep 25  2010 /usr/share/locale/en_US.US-ASCII
drwxr-xr-x  8 root  wheel  272 Sep 25  2010 /usr/share/locale/en_US.UTF-8

so on a Mac like mine, en_US.UTF-8 should do just fine, but if you see .utf8, 
.UTF8, .utf-8, you'll have to adjust LANG accordingly. 

For a permanent fix, edit the appropriate startup file for your shell, probably 
.profile, cor maybe .bash_profile or .bashrc.

-- 
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk  Priv: pda...@gmail.com

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Re: [R] R 15.0 Warning message.

2012-06-03 Thread Jinyan Huang
locale
locale: Cannot set LC_CTYPE to default locale: No such file or directory
locale: Cannot set LC_ALL to default locale: No such file or directory
LANG=en_US.UTF-8
LANGUAGE=
LC_CTYPE=UTF-8
LC_NUMERIC=en_US.UTF-8
LC_TIME=en_US.UTF-8
LC_COLLATE=en_US.UTF-8
LC_MONETARY=en_US.UTF-8
LC_MESSAGES=en_US.UTF-8
LC_PAPER=en_US.UTF-8
LC_NAME=en_US.UTF-8
LC_ADDRESS=en_US.UTF-8
LC_TELEPHONE=en_US.UTF-8
LC_MEASUREMENT=en_US.UTF-8
LC_IDENTIFICATION=en_US.UTF-8
LC_ALL=


ls -ld /usr/share/locale/en_US*
drwxr-xr-x 2 root root 4096 Dec 15 15:19 /usr/share/locale/en_US

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Re: [R] R 15.0 Warning message.

2012-06-03 Thread Prof Brian Ripley

On 03/06/2012 10:31, Jinyan Huang wrote:

locale
locale: Cannot set LC_CTYPE to default locale: No such file or directory
locale: Cannot set LC_ALL to default locale: No such file or directory
LANG=en_US.UTF-8
LANGUAGE=
LC_CTYPE=UTF-8


That's wrong: see the manual I pointed you to!


LC_NUMERIC=en_US.UTF-8
LC_TIME=en_US.UTF-8
LC_COLLATE=en_US.UTF-8
LC_MONETARY=en_US.UTF-8
LC_MESSAGES=en_US.UTF-8
LC_PAPER=en_US.UTF-8
LC_NAME=en_US.UTF-8
LC_ADDRESS=en_US.UTF-8
LC_TELEPHONE=en_US.UTF-8
LC_MEASUREMENT=en_US.UTF-8
LC_IDENTIFICATION=en_US.UTF-8
LC_ALL=


ls -ld /usr/share/locale/en_US*
drwxr-xr-x 2 root root 4096 Dec 15 15:19 /usr/share/locale/en_US


This is clearly not an R issue: so ask your IT support for help.

--
Brian D. Ripley,  rip...@stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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Re: [R] R 15.0 Warning message.

2012-06-03 Thread peter dalgaard

On Jun 3, 2012, at 11:36 , Prof Brian Ripley wrote:

 
 ls -ld /usr/share/locale/en_US*
 drwxr-xr-x 2 root root 4096 Dec 15 15:19 /usr/share/locale/en_US
 
 This is clearly not an R issue: so ask your IT support for help.

Or check out the Ubuntu docs/forums for information on which package of 
configuration trick you might be missing to get UTF-8 locales properly 
installed. (Googling utf-8 ubuntu seem to come up with relevant stuff.)

-- 
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk  Priv: pda...@gmail.com

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Re: [R] R 2.15.0 and 2.14.2 crash on the same code that runs on 2.14.1

2012-06-03 Thread Rainer Hurling

On 03.06.2012 09:17 (UTC+2), peter dalgaard wrote:


On Jun 3, 2012, at 07:40 , Ebrahim Jahanshiri wrote:


Dear list,

My code runs on 2.14.1 smoothly (with no error) but makes R crash on 2.14.2
and 2.15.0 with the usual windows message about R for windows GUI
front-end has stopped working... and as such I dont have any access to R
to get any error or warning message (if any). It crashes on random parts of
the code any time that I run it.
The code consists of EDA and spatial regression and various loops
and optimizations. The goal of the code is to perform a complete analysis
on various datasets.
Please take a look at the code here :
https://sites.google.com/site/geosciej/Home/STAR_ter1.R?attredirects=0d=1


You are not likely to find people willing to debug 15553 lines of code for you, and they 
are certainly not going to do it by eye, without the datasets!

One thing that jumps out is that you start off by loading five external 
packages, either of which might be the true owner of the problem. Even if the 
actual crash hits in the stats.dll, the underlying issue could well be memory 
corruption occurring some time earlier.

Things to try:

Run under Rterm in a command window instead of Rgui. That should at least tell 
you how far you got before the crash, maybe even a proper traceback.

Carefully try disabling parts of the code until the issue goes away. The last 
item removed might hold the clue. If you can cut it down to something 
small(-ish) and reproducible, people might be in a better position to help you.

Is it really a random crash, or does the crash point move every time you change 
the code slightly? If the former, you might have physical computer problems or 
you might be running close to your memory limit.


Just a guess:
One more thing you could try is to rebuild your packages under 2.15.0. 
One often forgets to update them after a version change of R:


update.packages(checkBuilt=TRUE, dependencies=TRUE, ask='graphics')

Rainer Hurling


-Peter D.



It seems that the results that comes out of 2.15.0 is more valid for my
work.

I cant think of anything that makes the code crash on the latest versions.

Here is the error message from windows:

  Problem Event Name: APPCRASH
  Application Name: Rgui.exe
  Application Version: 2.150.58871.0
  Application Timestamp: 4f75a0ca
  Fault Module Name: stats.dll
  Fault Module Version: 2.150.58871.0
  Fault Module Timestamp: 4f75a1c9
  Exception Code: c005
  Exception Offset: 000237c5
  OS Version: 6.1.7601.2.1.0.256.48
  Locale ID: 1033
  Additional Information 1: 0a9e
  Additional Information 2: 0a9e372d3b4ad19135b953a78882e789
  Additional Information 3: 0a9e
  Additional Information 4: 0a9e372d3b4ad19135b953a78882e789



I appreciate your help,

Thank you
Ebrahim Jahanshiri


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Re: [R] community finding in a graph and heatplot

2012-06-03 Thread Gábor Csárdi
The problem is that your graph is unconnected, it has two components
and the as.dendrogram() function in igraph cannot handle that.
fastgreedy.community() returns a matrix of merges that is not a
complete dendrogram, the final top level merge of the components is
missing.

A workaround is to modify the result of fastgreedy.community and add
the missing row to the merges matrix, before calling as.dendrogram().

G.

On Thu, May 31, 2012 at 7:42 PM, Aziz, Muhammad Fayez
az...@illinois.edu wrote:

 Thank you so much Gabor for taking this on. Please find attached a sample 
 scenario with the problem of malfunctioning dendogram by fgc. I hope this 
 helps you narrow down to the solution.

 Best,
 Fayez

 
 From: csardi.ga...@gmail.com [csardi.ga...@gmail.com] on behalf of Gábor 
 Csárdi [csa...@rmki.kfki.hu]
 Sent: Thursday, May 31, 2012 4:23 PM
 To: Aziz, Muhammad Fayez
 Cc: r-help@r-project.org
 Subject: Re: [R] community finding in a graph and heatplot

 On Thu, May 31, 2012 at 12:08 PM, Aziz, Muhammad Fayez
 az...@illinois.edu wrote:

 Thank you so much Gabor for your reply. I had spotted your post earlier and 
 it worked like a charm. Interestingly I have just ran into a trouble with 
 the stament dend - igraph:::as.dendrogram.igraph.walktrap(fc). Apparently 
 the members are empty as when I print(dend) it says 'dendrogram' with 2 
 branches and  members total, at height 93 while the error with using dend 
 with dendrapply remians to be

 Error in `[[.dendrogram`(X, 2L) : attempt to set an attribute on NULL

 Any ideas?

 I would need to see fgc for this. Can you send it to me in private? Or
 send some self-contained example that generates the same error?

 Gabor

 My code looks like this

                File2Open = paste(FilePath, NetworkFiles\\net\\, NetPrefix, 
  , TPPostfix, .net, sep = )
                g - read.graph(File2Open, format=pajek)

                g - delete.isolates(g)
                g - simplify(g)

                fgc - fastgreedy.community(g, modularity=TRUE, weights = 
 E(g)$weight)
                ModularityIndexfgc - max(fgc$modularity) # fgc modularity
                ModularityIndexng - modularity(g, membership, weights = 
 E(g)$weight) # newman-girvan modularity
                dend - igraph:::as.dendrogram.igraph.walktrap(fgc)

                png(filename = paste(FilePath, 
 Analysis\\Graphs\\EColiStressModuleHeatMap, NetPrefixAbbr, TPPostfix, 
 .png, sep = ), width = 800, height = 800) # heat map is square

                adjMatrix = get.adjacency(g, attr=weight)
                DendNodeCounter - 0 # counter for ColorGroupsOrdered
                ColorGroupsOrdered - rep(red, vcount(g))
                dendrapply(dend, colLab) # modifies ColorGroupsOrdered
 
 From: csardi.ga...@gmail.com [csardi.ga...@gmail.com] on behalf of Gábor 
 Csárdi [csa...@rmki.kfki.hu]
 Sent: Thursday, May 31, 2012 10:45 AM
 To: Aziz, Muhammad Fayez
 Cc: r-help@r-project.org
 Subject: Re: [R] community finding in a graph and heatplot

 On Tue, May 29, 2012 at 1:16 AM, Aziz, Muhammad Fayez
 az...@illinois.edu wrote:

 Hi everyone,

 I am using the fastgreedy.community function to get the $merges matrix and 
 the $modularity vector. This serves my purpose of testing modularity of my 
 graph. But I am greedy to plot the heat map and dendrrogram based on the 
 $merges dendogram matrix. I know that heatplot does the graphics part but I 
 am not sure if the dendogram generated by the heatplot will match the one 
 given by fastgreedy.community in all cases and that the heat map will 
 represent the same clustering.

 No, they are different. To plot fast-greedy results as a dendrogram,
 see this and the follow-ups:
 http://lists.gnu.org/archive/html/igraph-help/2010-11/msg00059.html

 Gabor

 Tell me if my apprehension is incorrect. Otherwise please let me know of 
 any alternatives. Here is the code I am testing so far:

 # http://igraph.sourceforge.net/doc/R/modularity.html
 # http://igraph.sourceforge.net/doc/R/fastgreedy.community.html
 # http://igraph.sourceforge.net/doc/R/graph.constructors.html

 library(igraph)
 library(made4)

 g - graph(c(1,2, 2,3, 3,1, 4,5)-1, , FALSE)
 print(g)
 ModuleInfo - fastgreedy.community(g)
 print(ModuleInfo)
 heatplot(c(1,2, 2,3, 3,1, 4,5))


 Thanks
 Fayez
 Grad student UIUC
 IL, USA

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Re: [R] R 2.15.0 and 2.14.2 crash on the same code that runs on 2.14.1

2012-06-03 Thread Prof Brian Ripley
Since this appears to be Windows (not explicitly said), the likely 
change is the compilers used for R = 2.14.2 differ from those used for 
2.14.1.  The posting guide does ask for 'at a minimum' information with 
good reason.  How big the change was depends on whether this was 32- or 
64-bit Windows.


Unfortunately there are a lot of badly written packages out there which 
write in memory they should not.  As time goes on compilers get better 
at optimizing, and that means they are better at keeping things in 
places in memory close to hand that are more liable to get clobbered.


The only really effective way to find such things is to use valgrind, 
and that means to use Linux (or perhaps Mac OS X, but that's flaky and 
with a lot more overhead than on Linux).  See R CMD check --use-valgrind.


And of course a new compiler may have a new set of bugs: but so far 
we've uncovered about 50 errors in packages and none in the compiler.


On 03/06/2012 14:46, Rainer Hurling wrote:

On 03.06.2012 09:17 (UTC+2), peter dalgaard wrote:


On Jun 3, 2012, at 07:40 , Ebrahim Jahanshiri wrote:


Dear list,

My code runs on 2.14.1 smoothly (with no error) but makes R crash on
2.14.2
and 2.15.0 with the usual windows message about R for windows GUI
front-end has stopped working... and as such I dont have any access
to R
to get any error or warning message (if any). It crashes on random
parts of
the code any time that I run it.
The code consists of EDA and spatial regression and various loops
and optimizations. The goal of the code is to perform a complete
analysis
on various datasets.
Please take a look at the code here :
https://sites.google.com/site/geosciej/Home/STAR_ter1.R?attredirects=0d=1



You are not likely to find people willing to debug 15553 lines of code
for you, and they are certainly not going to do it by eye, without
the datasets!

One thing that jumps out is that you start off by loading five
external packages, either of which might be the true owner of the
problem. Even if the actual crash hits in the stats.dll, the
underlying issue could well be memory corruption occurring some time
earlier.

Things to try:

Run under Rterm in a command window instead of Rgui. That should at
least tell you how far you got before the crash, maybe even a proper
traceback.

Carefully try disabling parts of the code until the issue goes away.
The last item removed might hold the clue. If you can cut it down to
something small(-ish) and reproducible, people might be in a better
position to help you.

Is it really a random crash, or does the crash point move every time
you change the code slightly? If the former, you might have physical
computer problems or you might be running close to your memory limit.


Just a guess:
One more thing you could try is to rebuild your packages under 2.15.0.
One often forgets to update them after a version change of R:

update.packages(checkBuilt=TRUE, dependencies=TRUE, ask='graphics')

Rainer Hurling


-Peter D.



It seems that the results that comes out of 2.15.0 is more valid for my
work.

I cant think of anything that makes the code crash on the latest
versions.

Here is the error message from windows:

Problem Event Name: APPCRASH
Application Name: Rgui.exe
Application Version: 2.150.58871.0
Application Timestamp: 4f75a0ca
Fault Module Name: stats.dll
Fault Module Version: 2.150.58871.0
Fault Module Timestamp: 4f75a1c9
Exception Code: c005
Exception Offset: 000237c5
OS Version: 6.1.7601.2.1.0.256.48
Locale ID: 1033
Additional Information 1: 0a9e
Additional Information 2: 0a9e372d3b4ad19135b953a78882e789
Additional Information 3: 0a9e
Additional Information 4: 0a9e372d3b4ad19135b953a78882e789



I appreciate your help,

Thank you
Ebrahim Jahanshiri


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Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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Re: [R] About Plot.new

2012-06-03 Thread Uwe Ligges
Perhaps not at all, since you are posting to the R-help list rather than 
to the original poster of the question. You also forgot to quote the 
original question as the posting guide asks you to do.


Uwe Ligges



On 03.06.2012 08:12, czar wrote:

@mr.parashar4 - If this not resolved yet, here is what can help
plot.new is trying to create a new object out of the standard point plot. I
believe you have not created a standard point plot, i.e. in your case,
plot(xm,ym). This will show the graphical plot window. Keep that window open
and then run your given command.
If you have already defined plot(), then just keep that window open. That is
when R will find the object and go ahead with the further commands over the
plot you specify.
Hope this helps.

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Re: [R] Modify pdf file with Illustrator.

2012-06-03 Thread Uwe Ligges



On 03.06.2012 08:42, Jinyan Huang wrote:

Dear list,

Some times I want to modify the pdf file which produced by R with
illustrator. But when I use Illustrator open the pdf file, it often
makes the pdf some little changed. Anyone have some suggestions? Is it
better to use other file type, not pdf? Or when I produced the pdf, I
should set some other parameters?


Questions are:

1. Why do you need to modify it, perhaps you don't.
2. What dio you want to do with the file in later steps? Perhaps a 
format with a representation in a more human readable form helps...


Best,
Uwe Ligges





Thank you

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Re: [R] Partial R-square in multiple linear regression

2012-06-03 Thread Uwe Ligges



On 01.06.2012 21:05, Jin Choi wrote:

Hello,

I am trying to obtain the partial r-square values (r^2 or R2) for
individual predictors of an outcome variable in multiple linear
regression. I am using the 'lm' function to calculate the beta
coefficients, however, I would like to know the individual %
contributions of several indepenent variables. I tried searching for
this function in many R packages, but it has proven elusive to me. I
am an R beginner, and I am hoping that I will find a solution!



summary(lm(...)) calculates the R^2. See ?summary.lm

Uwe Ligges


Thank you very much.

Sincerely,

Jin Choi
MSc Epidemiology student
McGill University, Montreal, Quebec, CANADA

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Re: [R] Modify pdf file with Illustrator.

2012-06-03 Thread Jinyan Huang
Thank you.

1, I want to put some text and title. Then put several figures into one.


On Sun, Jun 3, 2012 at 10:59 PM, Uwe Ligges
lig...@statistik.tu-dortmund.de wrote:


 On 03.06.2012 08:42, Jinyan Huang wrote:

 Dear list,

 Some times I want to modify the pdf file which produced by R with
 illustrator. But when I use Illustrator open the pdf file, it often
 makes the pdf some little changed. Anyone have some suggestions? Is it
 better to use other file type, not pdf? Or when I produced the pdf, I
 should set some other parameters?


 Questions are:

 1. Why do you need to modify it, perhaps you don't.
 2. What dio you want to do with the file in later steps? Perhaps a format
 with a representation in a more human readable form helps...

 Best,
 Uwe Ligges




 Thank you

 __
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 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
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Re: [R] Compare data between two groups/countries on 5-point Likert scale questionnare?

2012-06-03 Thread Uwe Ligges
This is the R-help mailing list. It is not a statistical consulting list 
nor the others write my thesis list.



On 02.06.2012 14:56, Frankfoot wrote:

Hi everyone, I'm stuck on my dissertation which is due next week.


Interesting. The question given below should arise two years before the 
dissertation is due (actually, at the time when you planned the 
questionnaire). Otherwise I'm interested to hear which university 
accepts theses where the analysis chapters can be written within a week 
and the evaluation and analysis of questionnaires is not planned in advance.


Uwe Ligges



 I'm a

business major student and my project is a comparative research on corporate
social responsibility (CSR) between Chinese and German firms. According to
my literature review, it's quite obvious that German firms have much better
CSR initiatives and strategies than the Chinese ones and I wanted to test
whether it was true by sending out Likert-scale questionnaires to Chinese
and German firms through bankers in my family. I have already got 24
responses from the Chinese and 27 from the Germans and it looked quite
evident that the hypothesis is correct. Now that I am writing my analysis
chapter, I am lost as I don't know which is the best way to analyse my data
after trying to find a solution for days. Basically, my questionnaire is
structured in this way:

Q1 - Q5: statements on environment-oriented CSR
Q6 - Q10: statements on workplace-oriented CSR
Q11 - Q15: statements on community-oriented CSR
Q16-Q20: statements on market-oriented CSR

All of the statements are 5-pt Likert questions. I initially planed to
compare the grouped mean values for each of the above section but I know
that it's not scientific. So can someone give me any advice on which kind of
tests is most suitable for my research? As you can see, my sample size is
quite small. I really appreciate your time!

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Re: [R] Modify pdf file with Illustrator.

2012-06-03 Thread Uwe Ligges



On 03.06.2012 17:03, Jinyan Huang wrote:

Thank you.

1, I want to put some text and title. Then put several figures into one.


So  just do it within R and use title() within R and use par() and its 
argument mfrow to arrange several figures in rows and columns.


Uwe Ligges



On Sun, Jun 3, 2012 at 10:59 PM, Uwe Ligges
lig...@statistik.tu-dortmund.de  wrote:



On 03.06.2012 08:42, Jinyan Huang wrote:


Dear list,

Some times I want to modify the pdf file which produced by R with
illustrator. But when I use Illustrator open the pdf file, it often
makes the pdf some little changed. Anyone have some suggestions? Is it
better to use other file type, not pdf? Or when I produced the pdf, I
should set some other parameters?



Questions are:

1. Why do you need to modify it, perhaps you don't.
2. What dio you want to do with the file in later steps? Perhaps a format
with a representation in a more human readable form helps...

Best,
Uwe Ligges





Thank you

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Re: [R] Memory-random forest

2012-06-03 Thread Uwe Ligges



On 02.06.2012 16:11, MYRIAM TABASSO wrote:

Hi all,
I am working with random forest on the large data set( 39).
I have a warning message : In matrix(integer(nrnodes * nt), ncol = nt) :
Reached total allocation of 3766Mb: see help(memory.size).
Can you have any suggestions?


Use anther methods that can deal with such huge amounts of data.


Uwe Ligges



Thanks,
Myriam

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Re: [R] How to make a transaction class data?

2012-06-03 Thread Uwe Ligges



On 01.06.2012 20:08, jasminedawn wrote:

Hi,

I have encounter a problem that my data a_data.frame  is of data.frame class
with columns: sequenceID, eventID, items.

when I convert it to transaction class:

as(a_data.frame, transactions)

All columns are grouped together under items, which is like this:
{sequenceID, eventID, items}
instead of the right form: sequenceID, eventID, {items}

Also when i read_baskets, there is always an error:  Error in readLines(con)
: 'con' is not a connection

Can anyone help me with the problem? Thanks very much!



Read the posting guide and provide reproducible examples so that people 
can help.


Uwe Ligges




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Re: [R] Partial R-square in multiple linear regression

2012-06-03 Thread peter dalgaard

On Jun 3, 2012, at 17:00 , Uwe Ligges wrote:

 
 
 On 01.06.2012 21:05, Jin Choi wrote:
 Hello,
 
 I am trying to obtain the partial r-square values (r^2 or R2) for
 individual predictors of an outcome variable in multiple linear
 regression. I am using the 'lm' function to calculate the beta
 coefficients, however, I would like to know the individual %
 contributions of several indepenent variables. I tried searching for
 this function in many R packages, but it has proven elusive to me. I
 am an R beginner, and I am hoping that I will find a solution!
 
 
 summary(lm(...)) calculates the R^2. See ?summary.lm

The question was about _partial_ R^2. There is such a thing and it would be 
calculated as

SS_term/(SS_term+SS_error) 

where SS_term is the sum of squares of the kind you'd get from drop1(). For 
single quantitative terms, as far as I can tell this is the square of the 
partial correlation obtained by regression of y-residuals on x-residuals, 
removing effects of all other terms in the model.

However, that is not a partitioning of the full R^2. The partial R-squares do 
not sum or otherwise combine to give that number. Rather, it is just a 
transformation of the F-statistic for the relevant term. 

 
 Uwe Ligges
 
 Thank you very much.
 
 Sincerely,
 
 Jin Choi
 MSc Epidemiology student
 McGill University, Montreal, Quebec, CANADA
 
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Solbjerg Plads 3, 2000 Frederiksberg, Denmark
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[R] Regions of significance plots with ggplot2

2012-06-03 Thread Dominic Comtois
I'd like to create a plot similar to this one from Kochanska et al.
(Development and Psychopathology, 2011):

 

 http://pages.videotron.com/do999/r-help/Kochanska_graph_ros.jpg
http://pages.videotron.com/do999/r-help/Kochanska_graph_ros.jpg

 

I am new to ggplot2 and can't see any obvious way to create distinct
coloured regions for the background, nor can I find any relevant examples. 

 

Any guidance appreciated. 

 

DC

 

PS: The context is practically the same as the one from the image (Gene x
Environment interaction study). I used the following tool to find the
regions of significance, if this is of interest to anyone:
http://www.quantpsy.org/interact/mlr2
http://www.quantpsy.org/interact/mlr2

 


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[R] Problems installing Packages

2012-06-03 Thread Sven D
Hello, 

I am going through Zhao's RDataMining PDF, and to redo all the graphics on
my computer, I need several packages, 'coin' and 'party' to name two.

I get the following error:

 install.packages(coin)
Installing package(s) into ‘/home/sven/R/i686-pc-linux-gnu-library/2.15’
(as ‘lib’ is unspecified)
trying URL 'http://cran.ma.imperial.ac.uk/src/contrib/coin_1.0-21.tar.gz'
Content type 'application/x-gzip' length 903944 bytes (882 Kb)
opened URL
==
downloaded 882 Kb

* installing *source* package ‘coin’ ...
** package ‘coin’ successfully unpacked and MD5 sums checked
** libs
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG  -fpic  -O3 -pipe  -g  -c
Classes.c -o Classes.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG  -fpic  -O3 -pipe  -g  -c
Helpers.c -o Helpers.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG  -fpic  -O3 -pipe  -g  -c
LinearStatistic.c -o LinearStatistic.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG  -fpic  -O3 -pipe  -g  -c
StreitbergRoehmel.c -o StreitbergRoehmel.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG  -fpic  -O3 -pipe  -g  -c
vandeWiel.c -o vandeWiel.o
gcc -std=gnu99 -shared -o coin.so Classes.o Helpers.o LinearStatistic.o
StreitbergRoehmel.o vandeWiel.o -lblas -lgfortran -lm -L/usr/lib/R/lib -lR
/usr/bin/ld: cannot find -lblas
collect2: ld returned 1 exit status
make: *** [coin.so] Error 1
ERROR: compilation failed for package ‘coin’
* removing ‘/home/sven/R/i686-pc-linux-gnu-library/2.15/coin’
Warning in install.packages :
  installation of package ‘coin’ had non-zero exit status

The downloaded source packages are in
‘/tmp/RtmpYPqZgS/downloaded_packages’

My system session info is as follows:

R version 2.15.0 (2012-03-30)
Platform: i686-pc-linux-gnu (32-bit)

locale:
 [1] LC_CTYPE=en_GB.UTF-8   LC_NUMERIC=C  
 [3] LC_TIME=en_GB.UTF-8LC_COLLATE=en_GB.UTF-8
 [5] LC_MONETARY=en_GB.UTF-8LC_MESSAGES=en_GB.UTF-8   
 [7] LC_PAPER=C LC_NAME=C 
 [9] LC_ADDRESS=C   LC_TELEPHONE=C
[11] LC_MEASUREMENT=en_GB.UTF-8 LC_IDENTIFICATION=C   

attached base packages:
[1] stats graphics  grDevices utils datasets  methods  
[7] base 

loaded via a namespace (and not attached):
[1] tools_2.15.0


I do not have a problem loading it on my windows PC. Anyone having similar
experience, and perhaps know the solution? Furthermore, package 'RHTMLForms'
from Omegahat I could only install on the ubuntu computer and not on the
windows computer. Anyone know the reason why? Perhaps this is not even an R
question, but any hint would be great.

Thanks



Sven


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Re: [R] How can I export a paired t-test output table to an excel file?

2012-06-03 Thread Kay Cichini
If you wish to use the table in a write-up or something like this, there is a
package for exporting to MS Word - see  
http://cran.r-project.org/web/packages/R2wd/index.html
http://cran.r-project.org/web/packages/R2wd/index.html  and these examples 
http://thebiobucket.blogspot.co.at/2012/04/reproducible-research-export-regression.html
http://thebiobucket.blogspot.co.at/2012/04/reproducible-research-export-regression.html
. You could also copy-paste it to excel from there..

Yours,
Kay

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[R] pre-clinical results analysis in R using the function 'aov'

2012-06-03 Thread Amit Novik
Hi.

I hope someone could help me with my question.

I have clinical scores of a longitudinal study:
4 treatments.
In each treatment j there are nj different subjects that were measured few 
times (of course for each subject the measurements are dependent during time).
I want to check it with ANOVA for repeated measurements and then go PostHoc 
tests.

Should I use the R function 'aov'?
What should be its parameters and especially the model grammar?
What format should I use for the data file (Groups(=Treatments), Subjects, 
TimePoints, Scores).

Thank you very much,
Amit.





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Re: [R] Bug in truncgof package?

2012-06-03 Thread Andreea Picu
Dear Carlos, Duncan and everyone

You may have already sorted the matter by now, but since I have not seen
anything posted since Duncan's reply, here I go. I apologize in advance
for the spam, if it turns out I've missed some post.

I think the test and the implementation of the truncgof package are just
fine. I've done Carlos' experiment (repeatedly generating samples and
testing them with AD) and the test never rejected the null hypothesis.

@Carlos: in the first piece of code you are using ad.test ( ad.test(xt,
plnorm, list(meanlog = 2, sdlog = 2), H = 10)), but in the function
that you are later defining for iteration purposes, you are use the KS
test (   ks.test(xt, plnorm, list(meanlog = 2, sdlog = 2), H =
10)$p.value)... This may have something to do with the contradictory
results that you thought you were getting.

Cheers
Andreea

Carlos J. Gil Bellosta wrote:
 Dear R-helpers,

 I was testing the truncgof CRAN package, found something that looked
 like a bug, and did my job: contacted the maintainer. But he did not
 reply, so I am resending my query here.

 I installed package truncgof and run the example for function ad.test. I
 got the following output:

 set.seed(123)
 treshold - 10
 xc  - rlnorm(100, 2, 2)# complete sample
 xt - xc[xc = treshold]# left truncated sample
 ad.test(xt, plnorm, list(meanlog = 2, sdlog = 2), H = 10)


 Supremum Class Anderson-Darling Test

 data:  xt
 AD = 3.124, p-value = 0.12
 alternative hypothesis: two.sided

 treshold = 10, simulations: 100


 So I cannot reject the hipothesis (at a standard confidence level) that
 the original sample comes from a lognormal distribution (as it is the
 case).

 But let us try to iterate on this example:

 set.seed( 123 )
 treshold - 10

 foo - function(){
   xc  - rlnorm(100, 2, 2) # complete sample
   xt - xc[xc = treshold] # left truncated sample
   ks.test(xt, plnorm, list(meanlog = 2, sdlog = 2), H =
 10)$p.value
 }

 results - replicate( 100, foo() )


 Then:

  
 table( results )

 results
0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09  0.1 0.11 0.16 0.18
 0.19  0.2
   257931234112211
 32
 0.21 0.22 0.26 0.27 0.28  0.3 0.31 0.32 0.33 0.36 0.38  0.4 0.44 0.49
 0.54 0.55
22131211121211
 21
 0.56 0.57 0.62  0.7 0.76 0.78 0.96 0.98
12111111


 This is, in a 45% of the cases, you would reject the H_0 hypothesis,
 which happens to be true, at the 5% standard confidence level.
  

That looks to me that the test as implemented is not very good.  This
could be an implementation bug, but it could also be a limitation of the
test itself.  I don't know the theory underlying this particular test,
but a way to determine it is in implementation bug is to carefully
implement the test and see if you got the same answer.

Duncan Murdoch

 Do you think this behaviour is buggy? If so, given that the maintainer
 does not seem to be contactable, what would be the next step to take?

 Best regards,

 Carlos J. Gil Bellosta
 http://www.datanalytics.com

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-- 
--
Andreea Picu
Communication Systems Research Group, ETH Zurich
Web: http://www.csg.ethz.ch/people/apicu
Office: ETZ G 96, Gloriastrasse 35, 8092 Zurich
Phone: +41 44 632 6894  Fax: +41 44 632 1035

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[R] a question about subsetting

2012-06-03 Thread jacaranda tree
Hi all,
I started using R about 3 weeks ago, and now I've pretty much figured out how 
to do the types of statistical modeling, graphs, tables etc. that I frequently  
use (with zero background in computer languages or other statistical packages 
that are similar to R like S or SAS!). So it's been a  quite  rewarding process 
so far, and I thank you all R gurus for all your generous help!
That being said, my question is about applying a model or an analysis to 
different groups based on a grouping variable. Below is the first six rows of 
my data:

   ID Group1 Group2 Mem   Gen Chance MSELGM MSELVR MSELFM MSELRL MSELEL ADOS Age
1  1      1           1        75     50.0     50         53               52   
         62             57            56        3        25
2  2      1           1        75     12.5     50         46               48   
         47             52            55        2        30
3  3      1           1        25     37.5     50         48               43   
         52             63            63        3        24
4  4      1           1        25     37.5     50         51               62   
         52             59            54        0        31
5  5      1           1        50     87.5     50         45               58   
         42             46            43        6        31
6  6      1           1       100    100.0   50         45               80     
       49             69            63        1        31

Group1: First grouping variable
Group2: Second grouping variable
Mem: Memory trial
Gen: Generalization trial
MSEL: Mullen Scales of Early Learning (a scale measuring various skills in 
little children). GM: Gross Motor Scale, VR: Visual Reception, FM: Fine Motor, 
RL: receptive Language, EL: Expressive Language. 
ADOS: An autism-specific measure.

First I wanted to do correlations between Generalization (variable Gen) and 
expressive language (MSELEL) for each group of Group1. For this, I used lapply 
or by functions which work just fine. Here is the code with 
lapply: lapply(split(mydata, mydata$Group1), function(x){cor.test(x[,5],
x[,11], method = pearson)})

Then I did regression. My DV is the variable Gen, and the IV is MSELEL. And 
again I wanted to do this for each group. Here is the code I came up with for 
each group:
fit1-lm(Gen~ MSELEL, data=mydata, subset=mydata$Group1==1)

fit2-lm(Gen~MSELEL, data=mydata, subset=mydata$Group1==2)

This works fine for regression, but when I used the subset function with the 
correlation (e.g.   cor.test (mydata$Gen, mydata$MSELEL, method=pearson, 
subset=mydata$Group1==1) , it did not work. It just did the correlation for the 
entire group and then used this for both groups. I was just curious as to why 
subset function works with regression, but not with correlation. Any thoughts? 
Thanks,
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[R] plotting evolution of dates

2012-06-03 Thread stef salvez
Dear R users,

I have the following problem

I have a panel data across countries and individuals. For each country
I have a sequence of dates
For France for example
22/02/09
22/03/09
19/04/09
17/05/09
12/07/09
09/08/09
06/09/09
04/10/09
01/11/09
29/11/09
27/12/09
31/01/10

For Italy
14/06/09
12/07/09
09/08/09
06/09/09
04/10/09
01/11/09
29/11/09
27/12/09
31/01/10
28/02/10
28/03/10


The structure of the MS  excel file is the following
France  Italy..
22/02/09   14/06/09
 22/03/09 12/7/2009
19/04/09  9/8/2009
17/05/096/9/2009
12/7/2009 4/10/2009
 09/08/09 01/11/09
6/9/200929/11/09
4/10/2009 27/12/09
 01/11/09 31/01/10
29/11/09  28/02/10
27/12/09  28/03/10
31/01/10



I want to plot (in one graph) these sequences of dates in the
sense that I want to have a visual contact of  the behaviour
of each of  these 2 sequences because as you can see I do not have the same
start date and   end date for each country and each next date is not
always every other 28 days. So the difference between  2 successive
dates is not always 28 days but 35 is some cases or otherwise.  Put
differently, I have jumps.
 I would like to visualize these
characteristics of the  series of  dates by
making a plot similar to

http://i46.tinypic.com/2h7gpvn.png

But this is not enough.
I want to measure the distance between 2 successive knots (the
difference between 2 successive dates) and note  on the plot the
number of weeks that separate apart the successive knots-dates
Something like

http://www.survey-design.com.au/stripplot3.png

where as you can see between the knots there are some red lines. In my
case these red lines would inform the reader about the number of weeks
between successive knots-dates




I need a specific code for this because a simple hint will not help me
as I am a new R user.

Thank you all

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[R] Multiple imputation, multinomial response random effects

2012-06-03 Thread Davina Hill
Dear R-group,

Could somebody recommend a package that can deal with a multinomial response 
variable (choice of breeding tactic in mice, which has four unordered levels), 
multiply-imputed data (generated using the Amelia package) and two non-nested 
random effects: individual identity (133 individuals made up to four choices 
each) and year (for which there are six levels and sample size varies between 
years)?

I've tried sabreR, drm, mixcat and mlogit but none of them seem able to 
accommodate multiply-imputed datasets.  The most promising package I’ve found 
so far is Zelig, which can handle multiply-imputed data and either multinomial 
responses OR random effects (but seemingly not both).  I could randomly select 
one case per individual and run the following model (with year as a fixed 
rather than random effect):

z.out - zelig(as.factor(tactic) ~ mass+age+year, model = mlogit, data = 
a.out$imputations)

but it probably isn't the most elegant solution.  Does anybody have any 
suggestions?

Thanks in advance,
Davina

--
Animal, Plant and Environmental Sciences
University of the Witwatersrand
South Africa

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[R] reduced variate in R

2012-06-03 Thread eliza botto

Dear  R users,
is there a way in R to calculate normal reduced variate??

eliza
  
[[alternative HTML version deleted]]

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Re: [R] Adding a column into the file

2012-06-03 Thread David Winsemius


On Jun 1, 2012, at 4:08 PM, David Winsemius wrote:



On Jun 1, 2012, at 12:27 PM, pigpigmeow wrote:


Dear all,
I have a lot of problems on R-programming.
for example my csv. file is ..


That certainly does not look like any csv file I have ever seen.


Date  wrfRH wrfsolar wrfwindspeed wrfrain wrftd wrfta
21/10/2010 92.97 22.11 53.27 0 1546.337861 61.00852664




i calculate the ratio of wrfRH/wrfsolar for each day.



If you are confused in your terminology, and you really have a  
data.frame created by read.table, then adding a column to an  
existing data.frame , say the ratio of wrftd divided by wrfta,  is  
really simple:


dfrm$ratio - with dfrm, wrftd/wrfta)


And that of course should have been :

dfrm$ratio - with( dfrm, wrftd/wrfta)

--

David Winsemius, MD
West Hartford, CT

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Re: [R] a question about subsetting

2012-06-03 Thread Jorge I Velez
Hi jacaranda,

Try

with(subset(mydata, Group1 == 1), cor.test(Gen, MSELEL, method = pearson))

HTH,
Jorge.-


On Sun, Jun 3, 2012 at 11:51 AM, jacaranda tree  wrote:

 Hi all,
 I started using R about 3 weeks ago, and now I've pretty much figured out
 how to do the types of statistical modeling, graphs, tables etc. that I
 frequently  use (with zero background in computer languages or other
 statistical packages that are similar to R like S or SAS!). So it's been a
  quite  rewarding process so far, and I thank you all R gurus for all your
 generous help!
 That being said, my question is about applying a model or an analysis to
 different groups based on a grouping variable. Below is the first six rows
 of my data:

ID Group1 Group2 Mem   Gen Chance MSELGM MSELVR MSELFM MSELRL MSELEL
 ADOS Age
 1  1  1   175 50.0 50 53
 5262 5756325
 2  2  1   175 12.5 50 46
 4847 5255230
 3  3  1   125 37.5 50 48
 4352 6363324
 4  4  1   125 37.5 50 51
 6252 5954031
 5  5  1   150 87.5 50 45
 5842 4643631
 6  6  1   1   100100.0   50 45
 8049 6963131

 Group1: First grouping variable
 Group2: Second grouping variable
 Mem: Memory trial
 Gen: Generalization trial
 MSEL: Mullen Scales of Early Learning (a scale measuring various skills in
 little children). GM: Gross Motor Scale, VR: Visual Reception, FM: Fine
 Motor, RL: receptive Language, EL: Expressive Language.
 ADOS: An autism-specific measure.

 First I wanted to do correlations between Generalization (variable Gen)
 and expressive language (MSELEL) for each group of Group1. For this, I used
 lapply or by functions which work just fine. Here is the code with
 lapply: lapply(split(mydata, mydata$Group1), function(x){cor.test(x[,5],
 x[,11], method = pearson)})

 Then I did regression. My DV is the variable Gen, and the IV is MSELEL.
 And again I wanted to do this for each group. Here is the code I came up
 with for each group:
 fit1-lm(Gen~ MSELEL, data=mydata, subset=mydata$Group1==1)

 fit2-lm(Gen~MSELEL, data=mydata, subset=mydata$Group1==2)

 This works fine for regression, but when I used the subset function with
 the correlation (e.g.   cor.test (mydata$Gen, mydata$MSELEL,
 method=pearson, subset=mydata$Group1==1) , it did not work. It just did
 the correlation for the entire group and then used this for both groups. I
 was just curious as to why subset function works with regression, but not
 with correlation. Any thoughts?
 Thanks,
[[alternative HTML version deleted]]


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[[alternative HTML version deleted]]

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Re: [R] Log-normal probability plot

2012-06-03 Thread David Winsemius


On Jun 2, 2012, at 9:38 PM, eliza botto wrote:

You might consider the strategy of reading the Posting Guide, followed  
by posting an intelligible message.




Dear R users,

You can literally safe my
life my telling me the solution of my problem. I have created matrix  
of a data
frame with 3 columns, with each column representing data of  
different year.


 2
...snipped useless srting of numbers mangled by mailer processing of  
HTML.



4





I now want to plot “Lognormal
probability plot” of each column data against its respective “normal  
reduced

variante(z)”.


Normal reduced variate? What is that? Is it a set of numbers that  
have been centered and scaled, also known as a z-transform? If so, I  
do not think it should affect the results of a probability plot since  
it is just a linear transformation and the theoretical quantiles will  
be unaffected.


You might look at qqplot()



How to do that?




If you don’t know the
answer, consider me dead.


What greater lifesaving project are you trying to accomplish,    
other than getting homework done?


[[alternative HTML version deleted]]



--
David Winsemius, MD
West Hartford, CT

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Re: [R] reduced variate in R

2012-06-03 Thread peter dalgaard

On Jun 3, 2012, at 17:57 , eliza botto wrote:

 
 Dear  R users,
 is there a way in R to calculate normal reduced variate??

Yes. It depends on what you mean, though. AFAICT reduced is just what others 
call standard normal (mean 0, variance 1), so rnorm(n, 0, 1) is one answer; z 
- (X - mu)/s is another.


-- 
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk  Priv: pda...@gmail.com

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] reduced variate in R

2012-06-03 Thread eliza botto


thankyou very much for answer. i want to calculate normal reduced variate of a 
matix consisting of 366 rows and 92 columns. how can i do that??
please reply if you know the answer..
eliza


 Subject: Re: [R] reduced variate in R
 From: pda...@gmail.com
 Date: Sun, 3 Jun 2012 19:11:55 +0200
 CC: r-help@r-project.org
 To: eliza_bo...@hotmail.com
 
 
 On Jun 3, 2012, at 17:57 , eliza botto wrote:
 
  
  Dear  R users,
  is there a way in R to calculate normal reduced variate??
 
 Yes. It depends on what you mean, though. AFAICT reduced is just what 
 others call standard normal (mean 0, variance 1), so rnorm(n, 0, 1) is one 
 answer; z - (X - mu)/s is another.
 
 
 -- 
 Peter Dalgaard, Professor,
 Center for Statistics, Copenhagen Business School
 Solbjerg Plads 3, 2000 Frederiksberg, Denmark
 Phone: (+45)38153501
 Email: pd@cbs.dk  Priv: pda...@gmail.com
 
 
 
 
 
 
 
 
  
[[alternative HTML version deleted]]

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Re: [R] reduced variate in R

2012-06-03 Thread Rui Barradas

Hello,

Try

scale(x)

Half of homework done.
The other half is to have a quick look at R-intro.pdf, it comes with 
every installation of R. Chapters 8 and 12.


Hope this helps,

Rui Barradas

Em 03-06-2012 18:15, eliza botto escreveu:


thankyou very much for answer. i want to calculate normal reduced variate of a 
matix consisting of 366 rows and 92 columns. how can i do that??
please reply if you know the answer..
eliza



Subject: Re: [R] reduced variate in R
From: pda...@gmail.com
Date: Sun, 3 Jun 2012 19:11:55 +0200
CC: r-help@r-project.org
To: eliza_bo...@hotmail.com


On Jun 3, 2012, at 17:57 , eliza botto wrote:


Dear  R users,
is there a way in R to calculate normal reduced variate??

Yes. It depends on what you mean, though. AFAICT reduced is just what others call 
standard normal (mean 0, variance 1), so rnorm(n, 0, 1) is one answer; z- (X - mu)/s 
is another.


--
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk  Priv: pda...@gmail.com










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and provide commented, minimal, self-contained, reproducible code.


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and provide commented, minimal, self-contained, reproducible code.


Re: [R] mgcv (bam) very large standard error difference between versions 1.7-11 and 1.7-17, bug?

2012-06-03 Thread Martijn Wieling
Dear useRs,

I've ran some additional analyses (see below), which strongly suggest
the standard errors of the bam (and gam) function are much too low in
mgcv version 1.7-17, at least when including an s(X,bs=re) term.
Until this issue has been clarified, it's perhaps best to use an older
version of mgcv (unfortunately, however, in earlier versions the
p-value calculation of s(X,bs=re) is not correct). All analyses were
conducted in R 2.15.0.

My approach was the following: I created a mixed-effects regression
model with a single random intercept and only linear predictors. In my
view, the results using lmer (lme4) should be comparable to those of
bam and gam (mgcv). This was the case when using an older version of
mgcv (version 1.7-13), but this is not the case anymore in version
1.7-17. In version 1.7-17, the standard errors and p-values are much
lower and very similar to those of a linear model (which does not take
the random-effects structure into account). The R-code and results are
shown below. (The results using gam are not shown, but show the same
pattern.)

Furthermore, note that the differences in standard errors become less
severe (but still noticeable) when less data is involved (e.g., using
only 500 rows as opposed to 100.000). Finally, when not including an
s(X,bs=re) term, but another non-random-effect smooth, the standard
errors do not appear to be structurally lower (only for some
variables, but not by a great deal - see also below).

With kind regards,
Martijn Wieling
University of Groningen

 lme4 model (most recent version of lme4)
modelLMER - lmer(RefPMIdistMeanLog.c ~ SpYearBirth.z*IsAragon +
SpIsMale + (1|Key), data=wrddst)
#Estimate Std. Error t value
#SpYearBirth.z  -0.012084   0.004577  -2.640
#IsAragon0.138959   0.010040  13.840
#SpIsMale   -0.003087   0.008290  -0.372
#SpYearBirth.z:IsAragon  0.015429   0.010159   1.519


 mgcv 1.7-13, default (method = REML) - almost identical to modelLMER
modelBAMold - bam(RefPMIdistMeanLog.c ~ SpYearBirth.z*IsAragon +
SpIsMale + s(Key,bs=re), data=wrddst)
#Estimate Std. Error t value Pr(|t|)
#SpYearBirth.z  -0.012084   0.004578  -2.640  0.00829 **
#IsAragon0.138959   0.010042  13.838   2e-16 ***
#SpIsMale   -0.003087   0.008292  -0.372  0.70968
#SpYearBirth.z:IsAragon  0.015429   0.010160   1.519  0.12886


 mgcv 1.7-17, method = REML - standard errors greatly reduced
# (comparable to standard errors of LM without random intercept)
modelBAMnew - bam(RefPMIdistMeanLog.c ~ SpYearBirth.z*IsAragon +
SpIsMale + s(Key,bs=re), data=wrddst); print(testje,cor=F)
#Estimate Std. Error t value Pr(|t|)
#SpYearBirth.z  -0.012084   0.001159 -10.428   2e-16 ***
#IsAragon0.138959   0.002551  54.472   2e-16 ***
#SpIsMale   -0.003087   0.002098  -1.4710.141
#SpYearBirth.z:IsAragon  0.015429   0.002587   5.965 2.45e-09 ***

 lm results, standard errors comparable to mgcv 1.7-17
modelLM - lm(RefPMIdistMeanLog.c ~ SpYearBirth.z*IsAragon + SpIsMale,
data=wrddst)
#Estimate Std. Error t value Pr(|t|)
#(Intercept)-0.025779   0.001653 -15.595   2e-16 ***
#SpYearBirth.z  -0.011906   0.001182 -10.070   2e-16 ***
#IsAragon0.139323   0.002603  53.531   2e-16 ***
#SpIsMale   -0.003076   0.002140  -1.4370.151
#SpYearBirth.z:IsAragon  0.015252   0.002639   5.780 7.49e-09 ***


 mgcv 1.7-17, default (method = fREML) - completely different
from previous models
modelBAMfREML - bam(RefPMIdistMeanLog.c ~ SpYearBirth.z*IsAragon +
SpIsMale + s(Key,bs=re), data=wrddst); print(testje,cor=F)
#Estimate Std. Error t value Pr(|t|)
#(Intercept)-0.025391   0.106897  -0.2380.812
#SpYearBirth.z  -0.012084   0.076300  -0.1580.874
#IsAragon0.138959   0.166697   0.8340.405
#SpIsMale   -0.003087   0.138291  -0.0220.982
#SpYearBirth.z:IsAragon  0.015429   0.168260   0.0920.927
#
#Approximate significance of smooth terms:
#  edf Ref.df F p-value
#s(Key) -38.95310 15.67  2e-16 ***


 differences w.r.t. standard smooths
 mgcv version 1.7-13
m2old - bam(RefPMIdistMeanLog.c ~ s(GeoX,GeoY) +
SpYearBirth.z*IsAragon + SpIsMale, data=wrddst, method=REML)
## RESULTS
#Family: gaussian
#Link function: identity
#
#Formula:
#RefPMIdistMeanLog.c ~ s(GeoX, GeoY) + SpYearBirth.z * IsAragon +
#SpIsMale
#
#Parametric coefficients:
#Estimate Std. Error t value Pr(|t|)
#(Intercept)-0.001386   0.004982  -0.278   0.7809
#SpYearBirth.z  -0.012950   0.001167 -11.097   2e-16 ***
#IsAragon0.020532   0.023608   0.870   0.3845
#SpIsMale   -0.004788   0.002219  -2.158   0.0309 *
#SpYearBirth.z:IsAragon  0.015611   0.002600   6.005 1.92e-09 ***
#---
#Signif. codes: 

Re: [R] Problems installing Packages

2012-06-03 Thread Jeff Newmiller
The error says you are missing the BLAS library... so install it?
---
Jeff NewmillerThe .   .  Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#.   ##.#.  Live Go...
  Live:   OO#.. Dead: OO#..  Playing
Research Engineer (Solar/BatteriesO.O#.   #.O#.  with
/Software/Embedded Controllers)   .OO#.   .OO#.  rocks...1k
--- 
Sent from my phone. Please excuse my brevity.

Sven D sd...@hotmail.com wrote:

Hello, 

I am going through Zhao's RDataMining PDF, and to redo all the graphics
on
my computer, I need several packages, 'coin' and 'party' to name two.

I get the following error:

 install.packages(coin)
Installing package(s) into
‘/home/sven/R/i686-pc-linux-gnu-library/2.15’
(as ‘lib’ is unspecified)
trying URL
'http://cran.ma.imperial.ac.uk/src/contrib/coin_1.0-21.tar.gz'
Content type 'application/x-gzip' length 903944 bytes (882 Kb)
opened URL
==
downloaded 882 Kb

* installing *source* package ‘coin’ ...
** package ‘coin’ successfully unpacked and MD5 sums checked
** libs
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG  -fpic  -O3 -pipe 
-g  -c
Classes.c -o Classes.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG  -fpic  -O3 -pipe 
-g  -c
Helpers.c -o Helpers.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG  -fpic  -O3 -pipe 
-g  -c
LinearStatistic.c -o LinearStatistic.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG  -fpic  -O3 -pipe 
-g  -c
StreitbergRoehmel.c -o StreitbergRoehmel.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG  -fpic  -O3 -pipe 
-g  -c
vandeWiel.c -o vandeWiel.o
gcc -std=gnu99 -shared -o coin.so Classes.o Helpers.o LinearStatistic.o
StreitbergRoehmel.o vandeWiel.o -lblas -lgfortran -lm -L/usr/lib/R/lib
-lR
/usr/bin/ld: cannot find -lblas
collect2: ld returned 1 exit status
make: *** [coin.so] Error 1
ERROR: compilation failed for package ‘coin’
* removing ‘/home/sven/R/i686-pc-linux-gnu-library/2.15/coin’
Warning in install.packages :
  installation of package ‘coin’ had non-zero exit status

The downloaded source packages are in
   ‘/tmp/RtmpYPqZgS/downloaded_packages’

My system session info is as follows:

R version 2.15.0 (2012-03-30)
Platform: i686-pc-linux-gnu (32-bit)

locale:
 [1] LC_CTYPE=en_GB.UTF-8   LC_NUMERIC=C  
 [3] LC_TIME=en_GB.UTF-8LC_COLLATE=en_GB.UTF-8
 [5] LC_MONETARY=en_GB.UTF-8LC_MESSAGES=en_GB.UTF-8   
 [7] LC_PAPER=C LC_NAME=C 
 [9] LC_ADDRESS=C   LC_TELEPHONE=C
[11] LC_MEASUREMENT=en_GB.UTF-8 LC_IDENTIFICATION=C   

attached base packages:
[1] stats graphics  grDevices utils datasets  methods  
[7] base 

loaded via a namespace (and not attached):
[1] tools_2.15.0


I do not have a problem loading it on my windows PC. Anyone having
similar
experience, and perhaps know the solution? Furthermore, package
'RHTMLForms'
from Omegahat I could only install on the ubuntu computer and not on
the
windows computer. Anyone know the reason why? Perhaps this is not even
an R
question, but any hint would be great.

Thanks



Sven


--
View this message in context:
http://r.789695.n4.nabble.com/Problems-installing-Packages-tp4632217.html
Sent from the R help mailing list archive at Nabble.com.

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[R] memory usage benefit from anonymous variable constructions.

2012-06-03 Thread Paul Johnson
This is an I was just wondering question.

When the package dataframe was announced, the author claimed to
reduce the number of times a data frame was copied, I started to
wonder if I should care about this in my projects.  Has anybody
written a general guide for how to write R code that doesn't
needlessly exhaust RAM?

In Objective-C, we used to gain some considerable advantages by
avoiding declaring objects separately, using anonymous variable
instead. The storage was allocated on the stack, I think, and I think
there was talk that the numbers might stay 'closer' to the CPU
(register?) for immediate usage.

Does this benefit in R as well?  For example, instead of the way I
would usually do this:

 mf - model.frame(model)
  y - model.response(mf)

Here is the anonymous alternative, mf is never declared

y - model.response(model.frame(model))

On the face of it, I can imagine this might be better because no
permanent thing mf is created, the garbage collector wouldn't be
called into play if all the data is local and disappears immediately.
But, then again, R is doing lots of stuff under the hood that I've
never bothered to learn about.


pj
-- 
Paul E. Johnson
Professor, Political Science    Assoc. Director
1541 Lilac Lane, Room 504     Center for Research Methods
University of Kansas               University of Kansas
http://pj.freefaculty.org            http://quant.ku.edu

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Partial R-square in multiple linear regression

2012-06-03 Thread Paul Johnson
On Fri, Jun 1, 2012 at 2:05 PM, Jin Choi oohps...@gmail.com wrote:
 Hello,

 I am trying to obtain the partial r-square values (r^2 or R2) for
 individual predictors of an outcome variable in multiple linear
 regression. I am using the 'lm' function to calculate the beta
 coefficients, however, I would like to know the individual %
 contributions of several indepenent variables. I tried searching for
 this function in many R packages, but it has proven elusive to me. I
 am an R beginner, and I am hoping that I will find a solution!

 Thank you very much.

 Sincerely,

This is the kind of practical user request I've been trying to answer
in the rockchalk package. I have a function called getDeltaRsquare.
It takes a fitted regression and calculates the change in Rsquare when
each variable is removed.

It does not achieve the Partition idea for Rsquare that you might
want because there is no logically meaningful way to partition Rsquare
among predictors if there is any multicollinearity.  I could point you
at some stat books that try to achieve that partition, mostly they
seem to be by psychologists (who like that kind of thing.)  You will
go down a rabbit hole of semi-partial correlation coefficients and
so forth.

But if you just want the how much does R-square drop if I leave out
this variable, I got that for you :)  Whether that is meaningful to
you, well, that's a bigger methodological question.

pj


 Jin Choi
 MSc Epidemiology student
 McGill University, Montreal, Quebec, CANADA

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 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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-- 
Paul E. Johnson
Professor, Political Science    Assoc. Director
1541 Lilac Lane, Room 504     Center for Research Methods
University of Kansas               University of Kansas
http://pj.freefaculty.org            http://quant.ku.edu

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and provide commented, minimal, self-contained, reproducible code.


[R] merging single column from different dataframe

2012-06-03 Thread Kai Mx
Hi all,
probably really simple to solve, but having no background in programming I
haven't been able to figure this out: I have two dataframes like

df1 - data.frame(names1=c('aa','ab', 'ac', 'ad'), var1=c(1,5,7,12))
df2 - data.frame(names2=c('aa', 'ab', 'ac', 'ad', 'ae'),
var2=c(3,6,9,12,15))

Now I want merge var1 to df2 by matching the dataframes by the 'names'
columns, i.e. something like

df3 - merge (df2, df1, by.x='names2', by.y='names1', all.x=T)

However, the original dataframes have quite a lot of columns and I thought
that I should be able to address the var1 column by something like
df1$var[[df2$name2]]. Could somebody please enlighten me and/or maybe
suggest a short tutorial for the extraction operator?
Thanks!


Best,

Kai

[[alternative HTML version deleted]]

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Re: [R] plotting evolution of dates

2012-06-03 Thread David Winsemius


On Jun 3, 2012, at 9:27 AM, stef salvez wrote:


Dear R users,

I have the following problem

I have a panel data across countries and individuals. For each country
I have a sequence of dates
For France for example
22/02/09
22/03/09
19/04/09
17/05/09
12/07/09
09/08/09
06/09/09
04/10/09
01/11/09
29/11/09
27/12/09
31/01/10

For Italy
14/06/09
12/07/09
09/08/09
06/09/09
04/10/09
01/11/09
29/11/09
27/12/09
31/01/10
28/02/10
28/03/10


The structure of the MS  excel file is the following
France  Italy..
22/02/09   14/06/09
22/03/09 12/7/2009
19/04/09  9/8/2009
17/05/096/9/2009
12/7/2009 4/10/2009
09/08/09 01/11/09
6/9/200929/11/09
4/10/2009 27/12/09
01/11/09 31/01/10
29/11/09  28/02/10
27/12/09  28/03/10
31/01/10



I want to plot (in one graph) these sequences of dates in the
sense that I want to have a visual contact of  the behaviour
of each of  these 2 sequences because as you can see I do not have  
the same

start date and   end date for each country and each next date is not
always every other 28 days. So the difference between  2 successive
dates is not always 28 days but 35 is some cases or otherwise.  Put
differently, I have jumps.
I would like to visualize these
characteristics of the  series of  dates by
making a plot similar to

http://i46.tinypic.com/2h7gpvn.png


That looks like an ordinary R plot and the fact that you might want  
jumps suggests you might want to use the s line type. Or you might  
be talking about gaps. Hard to tell without specific examples. Look  
at ?plot.default  and ?par for information on the 'lty' parameter. You  
should be converting your dates to 'Date' class vectors so that they  
have the proper numeric distance. You would also get Date formating  
with the axis calls.


 Italy - scan(what=character)
1: 14/06/09
2: 12/07/09
3: 09/08/09
4: 06/09/09
5: 04/10/09
6: 01/11/09
7: 29/11/09
8: 27/12/09
9: 31/01/10
10: 28/02/10
11: 28/03/10
12:
Read 11 items
 Italy.Dt - as.Date(Italy, format=%d/%m/%y)
 Italy.Dt
 [1] 2009-06-14 2009-07-12 2009-08-09 2009-09-06 2009-10-04  
2009-11-01 2009-11-29

 [8] 2009-12-27 2010-01-31 2010-02-28 2010-03-28





But this is not enough.


Well, in many ways you are already asking too much, since you have  
provided no sample dataset in a form that can be readily pasted into a  
console session. There are Wiki entries on importing Excel data that  
you should be able to find without too much difficulty. You are  
expected to do quite a bit of self-study and to post your coding  
efforts. A lot of people have spent a lot of time over the years in  
putting material in the R-wiki, their own blogs and of course the  
Contributed materials at CRAN.



I want to measure the distance between 2 successive knots (the
difference between 2 successive dates) and note  on the plot the
number of weeks that separate apart the successive knots-dates
Something like

http://www.survey-design.com.au/stripplot3.png


That reminds me a bit of a type of plot called something like  
beehive plot. There have been implementations in R and searching he  
archives would be the way to go. It's still not exactly clear how the  
stacking of interim observations should be specified. Again, with no  
data object (and please, please, do not offer console-print()ed  
output) , not much more coding can be suggested.




where as you can see between the knots there are some red lines. In my
case these red lines would inform the reader about the number of weeks
between successive knots-dates


Whatever that actually means ...



I need a specific code for this because a simple hint will not help me
as I am a new R user.


That's _not_ the implicit agreement that you committed to when you  
posted to Rhelp. Please read the Posting Guide.. again? This is not a  
tutorial website.


--

David Winsemius, MD
West Hartford, CT

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Re: [R] merging single column from different dataframe

2012-06-03 Thread Rui Barradas

Hello,

One way, with limited applicability, would be

df4 - cbind(df2, var1=NA)
df4$var1[ df2$names2 %in% df1$names1 ] - df1$var1
df4


Limited because it doesn't resist to duplicate key values (the columns 
names1/2).
But with unique keys it should be much more efficient, speed- and 
memory-wise. Much, much more.

There is also package data.table, designed for this type of problem.

As for the extraction operator, there is An Introduction to R, 
R-intro.pdf, in the doc directory of your R installation.

And several others on-line, on CRAN, for instance.
(Your example wouldn't work, df2$names2 are the values of that variable, 
not row indexes. See df2[[ names2 ]].)


Hope this helps,

Rui Barradas

Em 03-06-2012 20:22, Kai Mx escreveu:

Hi all,
probably really simple to solve, but having no background in programming I
haven't been able to figure this out: I have two dataframes like

df1- data.frame(names1=c('aa','ab', 'ac', 'ad'), var1=c(1,5,7,12))
df2- data.frame(names2=c('aa', 'ab', 'ac', 'ad', 'ae'),
var2=c(3,6,9,12,15))

Now I want merge var1 to df2 by matching the dataframes by the 'names'
columns, i.e. something like

df3- merge (df2, df1, by.x='names2', by.y='names1', all.x=T)

However, the original dataframes have quite a lot of columns and I thought
that I should be able to address the var1 column by something like
df1$var[[df2$name2]]. Could somebody please enlighten me and/or maybe
suggest a short tutorial for the extraction operator?
Thanks!


Best,

Kai

[[alternative HTML version deleted]]

__
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and provide commented, minimal, self-contained, reproducible code.


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and provide commented, minimal, self-contained, reproducible code.


Re: [R] community finding in a graph and heatplot

2012-06-03 Thread Aziz, Muhammad Fayez

Hmm interesting. To come to think of it there could be many disconnected 
components in the graph and thus there should be a generic way to either 
mitigate the disconnectedness in the dendrogram or in the original graph. I had 
no luck in finding such a trick though google search. I then ran the script on 
minute-scale graphs and have following results:

1) disconnected graph with three modules:

*Vertices 9
*Edges
1 2 1
2 3 1
3 1 1
4 5 1
5 6 1
6 4 1
7 8 1
8 9 1
9 7 1

corresponding fgc$merges matrix:

 [,1] [,2]
[1,]10
[2,]29
[3,]76
[4,]8   11
[5,]43
[6,]5   13

2) connected graph by adding links 1-2 and 4-7 in graph 1):

*Vertices 9
*Edges
1 2 1
2 3 1
3 1 1
4 5 1
5 6 1
6 4 1
7 8 1
8 9 1
9 7 1
1 4 1
4 7 1

corresponding fgc$merges matrix:

 [,1] [,2]
[1,]21
[2,]09
[3,]87
[4,]6   11
[5,]54
[6,]3   13
[7,]   14   12
[8,]   15   10

There needs to be a generic way to get fgc$merges of the form 2) from 1). Hints 
please.

Thank you so much Gabor for your help so far and marvelous job in identifying 
the problem.

Best,
Fayez





From: csardi.ga...@gmail.com [csardi.ga...@gmail.com] on behalf of Gábor Csárdi 
[csa...@rmki.kfki.hu]
Sent: Sunday, June 03, 2012 8:56 AM
To: Aziz, Muhammad Fayez
Cc: r-help@r-project.org; Caetano-Anolles, Gustavo
Subject: Re: [R] community finding in a graph and heatplot

The problem is that your graph is unconnected, it has two components
and the as.dendrogram() function in igraph cannot handle that.
fastgreedy.community() returns a matrix of merges that is not a
complete dendrogram, the final top level merge of the components is
missing.

A workaround is to modify the result of fastgreedy.community and add
the missing row to the merges matrix, before calling as.dendrogram().

G.

On Thu, May 31, 2012 at 7:42 PM, Aziz, Muhammad Fayez
az...@illinois.edu wrote:

 Thank you so much Gabor for taking this on. Please find attached a sample 
 scenario with the problem of malfunctioning dendogram by fgc. I hope this 
 helps you narrow down to the solution.

 Best,
 Fayez

 
 From: csardi.ga...@gmail.com [csardi.ga...@gmail.com] on behalf of Gábor 
 Csárdi [csa...@rmki.kfki.hu]
 Sent: Thursday, May 31, 2012 4:23 PM
 To: Aziz, Muhammad Fayez
 Cc: r-help@r-project.org
 Subject: Re: [R] community finding in a graph and heatplot

 On Thu, May 31, 2012 at 12:08 PM, Aziz, Muhammad Fayez
 az...@illinois.edu wrote:

 Thank you so much Gabor for your reply. I had spotted your post earlier and 
 it worked like a charm. Interestingly I have just ran into a trouble with 
 the stament dend - igraph:::as.dendrogram.igraph.walktrap(fc). Apparently 
 the members are empty as when I print(dend) it says 'dendrogram' with 2 
 branches and  members total, at height 93 while the error with using dend 
 with dendrapply remians to be

 Error in `[[.dendrogram`(X, 2L) : attempt to set an attribute on NULL

 Any ideas?

 I would need to see fgc for this. Can you send it to me in private? Or
 send some self-contained example that generates the same error?

 Gabor

 My code looks like this

File2Open = paste(FilePath, NetworkFiles\\net\\, NetPrefix, 
  , TPPostfix, .net, sep = )
g - read.graph(File2Open, format=pajek)

g - delete.isolates(g)
g - simplify(g)

fgc - fastgreedy.community(g, modularity=TRUE, weights = 
 E(g)$weight)
ModularityIndexfgc - max(fgc$modularity) # fgc modularity
ModularityIndexng - modularity(g, membership, weights = 
 E(g)$weight) # newman-girvan modularity
dend - igraph:::as.dendrogram.igraph.walktrap(fgc)

png(filename = paste(FilePath, 
 Analysis\\Graphs\\EColiStressModuleHeatMap, NetPrefixAbbr, TPPostfix, 
 .png, sep = ), width = 800, height = 800) # heat map is square

adjMatrix = get.adjacency(g, attr=weight)
DendNodeCounter - 0 # counter for ColorGroupsOrdered
ColorGroupsOrdered - rep(red, vcount(g))
dendrapply(dend, colLab) # modifies ColorGroupsOrdered
 
 From: csardi.ga...@gmail.com [csardi.ga...@gmail.com] on behalf of Gábor 
 Csárdi [csa...@rmki.kfki.hu]
 Sent: Thursday, May 31, 2012 10:45 AM
 To: Aziz, Muhammad Fayez
 Cc: r-help@r-project.org
 Subject: Re: [R] community finding in a graph and heatplot

 On Tue, May 29, 2012 at 1:16 AM, Aziz, Muhammad Fayez
 az...@illinois.edu wrote:

 Hi everyone,

 I am using the fastgreedy.community function to get the $merges matrix and 
 the $modularity vector. This serves my purpose of testing modularity of my 
 graph. But I am greedy to plot the heat map and dendrrogram based on the 
 $merges dendogram matrix. I know that heatplot does the graphics part but I 
 am not sure if the dendogram generated by the heatplot will match 

Re: [R] fine control of plots after use of layout(matrix ...

2012-06-03 Thread Sarah Goslee
On Sun, Jun 3, 2012 at 4:05 PM, Matthew Johnson mcoog...@gmail.com wrote:
 Thanks. So i can call par after the layout command? I did not realise.

Some par options are set by calling par() directly, while others must
be included in the plot command itself.

Sarah

 Sent from my iPad

 On 03/06/2012, at 9:42 PM, Sarah Goslee sarah.gos...@gmail.com wrote:



 On Sunday, June 3, 2012, Matthew Johnson wrote:

 Sir,


 I'm no sir, but you need to spend some quality time reading ?par to lean
 abot axes and margins.

 Sarah


 I would like to create a combined line-bar plot, with the line up top and
 bar plot below, but with the x-axes suppressed on the topmost plot, the
 line and bar plot areas joined by a common line, and the x-axes (of dates)
 joined to the bottom part of the bar plot.

 i have been able to format the area using the layout(matrix( ... commands,
 but cannot figure out the final step.

 here's the code so far:


 layout(matrix(c(1,2), 2, 1, byrow=TRUE), widths=c(3,3), heights=c(2,1))
 plot(saDwlPx[,1])
 barplot(saDwlMoM[,1])

 thanks + best regards

 matt johnson


 --
 Sarah Goslee
 http://www.stringpage.com
 http://www.sarahgoslee.com
 http://www.functionaldiversity.org



-- 
Sarah Goslee
http://www.functionaldiversity.org

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] package grid: mirror grob objects along an axis

2012-06-03 Thread Thomas Zumbrunn
My question was answered off list by Paul Murrell, author of 'grid'. Here's am 
excerpt of our email exchange for the records of R-help.

 Paul Murrell 

In some special cases, you would be able to flip shapes.  If the 
coordinates of the shapes are given in native coordinates, then you 
could reverse the scales on the viewport that you are drawing in.

However, there is no general flip operation in 'grid'.  Especially not 
with respect to text.  Text is always left-to-right and sized using 
absolute units (points [modulo cex multipliers]).

If you really desperately needed to do something like this, a last 
resort might be to draw the required scene in hi-res raster format. 
You could then easily flip the raster and draw that.

 Thomas Zumbrunn 

I was actually asking the question primarily because I wanted to flip text 
grobs...

 If you really desperately needed to do something like this, a last
 resort might be to draw the required scene in hi-res raster format.
 You could then easily flip the raster and draw that.

That's exactly what I did as a workaround, but I was hoping that there is a 
more elegant solution - especially since reading in and drawing hi-res raster 
format images slows down the execution time of my code quite considerably.

What about converting text into paths? Could one do this in R? Then one could 
use your suggested solution of reversing the scales of the viewport.

 Paul Murrell 

Interesting idea.  You could do that using the 'grImport'.  Something 
like ...

library(grid)
postscript(test.ps)
grid.text(test)
dev.off()

library(grImport)
PostScriptTrace(test.ps, test.xml)
test - readPicture(test.xml)
# To check the scales on the picture
# test@summary
grid.picture(test,
  yscale=c(4400, 4000),
  xscale=c(2936.84, 3019.76))




On Tuesday 22 May 2012, Thomas Zumbrunn wrote:
 Hi everyone
 
 I'd like to flip grobs (grid graphical objects) along an axis, e.g. flip
 grobs horizontally or vertically. I couldn't find any hints, neither in
 the documentation nor by searching the web. Does anybody know how to
 achieve this?
 
 Cheers
 /thomas

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] merging single column from different dataframe

2012-06-03 Thread David Winsemius


On Jun 3, 2012, at 3:22 PM, Kai Mx wrote:


Hi all,
probably really simple to solve, but having no background in  
programming I

haven't been able to figure this out: I have two dataframes like

df1 - data.frame(names1=c('aa','ab', 'ac', 'ad'), var1=c(1,5,7,12))
df2 - data.frame(names2=c('aa', 'ab', 'ac', 'ad', 'ae'),
var2=c(3,6,9,12,15))

Now I want merge var1 to df2 by matching the dataframes by the 'names'
columns, i.e. something like

df3 - merge (df2, df1, by.x='names2', by.y='names1', all.x=T)

However, the original dataframes have quite a lot of columns and I  
thought

that I should be able to address the var1 column by something like
df1$var[[df2$name2]].


Well there is no df1$var object or even a column with that reference.  
Even if you meant to type `var1`,  the object df1$var[[df2$name2]]  
would not make much sense, since that would still be a failed attempt  
to access an named vector and df1$var1 is not named.


 names( df1$var1)
NULL

The [[ operation is different than the [ operation. [[ returns  
only one item. [ returns multiple items. In the case of dataframes  
(of which df1$var1 is _not_ an example) , [[ returns one entire  
column as a vector. If you had been trying to access a named vector  
using the 'names' in the character vector df1$names1 and there were  
any matches then you might have had some success with '['.


Even then there are gators in the swamp.

vec1 - c(aa=3, gx =10,  ac=4, cc = 12)
vec1[df1$names1]
aa gx ac cc
 3 10  4 12

WTF?

Well, by default R's dataframes construct factor variables for  
character arguments and have an underlying numeric representation, so  
by the time df1$names got coerced it ended up as 1,2,3,4 and  
referenced all of vec1. These other methods would return something  
appropriate:


vec1[as.character(df1$names1)]
  aa NA   ac NA
   3   NA4   NA


vec1[which(names(vec1) %in% df1$names1)]
aa ac
 3  4

I happen to think that returning NA is unfortunate in the first  
inatance, but I did not construct the language and there must have  
been some good reason to make it that way.



Could somebody please enlighten me and/or maybe
suggest a short tutorial for the extraction operator?


Arguments to [ can be numeric, character, or logical. If numeric, it  
will return values at the sequence locations along the referenced  
object.  If character, it will return the matched items with those  
names. if logical, the call will return those items for which the  
index is TRUE (and there will be argument recycling, so this will  
return every second item in df1$var1


 df1$var1[c(FALSE, TRUE)]
[1]  5 12


Spend some time working through the examples on ?Extract and then re- 
reading that help page at least three times, although I probably took  
me ten or twenty times to get a pretty good grasp of it.  The material  
there is accurate and precise, but the subtleties are numerous.


--

David Winsemius, MD
West Hartford, CT

__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] Dummies guide to getting HPC working on R

2012-06-03 Thread Jonathan Greenberg
R-folks:  Sorry for the cross-posting, but I wanted to share a link to
a (fairly long) blog post I created which tries to take the mystery
out of getting R setup for doing high performance/parallel computing
if you have to compile R from scratch:

http://lostingeospace.blogspot.com/2012/06/r-and-hpc-blas-mpi-in-linux-environment.html

Let me know if you have any comments/corrections on it.  Cheers!

--j

-- 
Jonathan A. Greenberg, PhD
Assistant Professor
Department of Geography and Geographic Information Science
University of Illinois at Urbana-Champaign
607 South Mathews Avenue, MC 150
Urbana, IL 61801
Phone: 415-763-5476
AIM: jgrn307, MSN: jgrn...@hotmail.com, Gchat: jgrn307, Skype: jgrn3007
http://www.geog.illinois.edu/people/JonathanGreenberg.html

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] fine control of plots after use of layout(matrix ...

2012-06-03 Thread Matthew Johnson
Thanks. The solution i have been persuing is reading Murrell - and
trying to figure out grid / Viewport commands. Is it best to stay in
the base graphics package if possible?

Sent from my iPad

On 04/06/2012, at 6:20 AM, Sarah Goslee sarah.gos...@gmail.com wrote:

 On Sun, Jun 3, 2012 at 4:05 PM, Matthew Johnson mcoog...@gmail.com wrote:
 Thanks. So i can call par after the layout command? I did not realise.

 Some par options are set by calling par() directly, while others must
 be included in the plot command itself.

 Sarah

 Sent from my iPad

 On 03/06/2012, at 9:42 PM, Sarah Goslee sarah.gos...@gmail.com wrote:



 On Sunday, June 3, 2012, Matthew Johnson wrote:

 Sir,


 I'm no sir, but you need to spend some quality time reading ?par to lean
 abot axes and margins.

 Sarah


 I would like to create a combined line-bar plot, with the line up top and
 bar plot below, but with the x-axes suppressed on the topmost plot, the
 line and bar plot areas joined by a common line, and the x-axes (of dates)
 joined to the bottom part of the bar plot.

 i have been able to format the area using the layout(matrix( ... commands,
 but cannot figure out the final step.

 here's the code so far:


 layout(matrix(c(1,2), 2, 1, byrow=TRUE), widths=c(3,3), heights=c(2,1))
 plot(saDwlPx[,1])
 barplot(saDwlMoM[,1])

 thanks + best regards

 matt johnson


 --
 Sarah Goslee
 http://www.stringpage.com
 http://www.sarahgoslee.com
 http://www.functionaldiversity.org



 --
 Sarah Goslee
 http://www.functionaldiversity.org

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] fine control of plots after use of layout(matrix ...

2012-06-03 Thread Sarah Goslee
On Sun, Jun 3, 2012 at 5:02 PM, Matthew Johnson mcoog...@gmail.com wrote:
 Thanks. The solution i have been persuing is reading Murrell - and
 trying to figure out grid / Viewport commands. Is it best to stay in
 the base graphics package if possible?

It really depends on what you need to do. Your original example used
plot, so I went with par.

Murrell's explanation of par() options is also very good.

Sarah

 On 04/06/2012, at 6:20 AM, Sarah Goslee sarah.gos...@gmail.com wrote:

 On Sun, Jun 3, 2012 at 4:05 PM, Matthew Johnson mcoog...@gmail.com wrote:
 Thanks. So i can call par after the layout command? I did not realise.

 Some par options are set by calling par() directly, while others must
 be included in the plot command itself.

 Sarah

 Sent from my iPad

 On 03/06/2012, at 9:42 PM, Sarah Goslee sarah.gos...@gmail.com wrote:



 On Sunday, June 3, 2012, Matthew Johnson wrote:

 Sir,


 I'm no sir, but you need to spend some quality time reading ?par to lean
 abot axes and margins.

 Sarah


 I would like to create a combined line-bar plot, with the line up top and
 bar plot below, but with the x-axes suppressed on the topmost plot, the
 line and bar plot areas joined by a common line, and the x-axes (of dates)
 joined to the bottom part of the bar plot.

 i have been able to format the area using the layout(matrix( ... commands,
 but cannot figure out the final step.

 here's the code so far:


 layout(matrix(c(1,2), 2, 1, byrow=TRUE), widths=c(3,3), heights=c(2,1))
 plot(saDwlPx[,1])
 barplot(saDwlMoM[,1])

 thanks + best regards

 matt johnson


-- 
Sarah Goslee
http://www.sarahgoslee.com

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] package grid: mirror grob objects along an axis

2012-06-03 Thread baptiste auguie
Hi,

Another option that you might want to try is the tikzDevice package;
tikz has functions to flip and rotate objects and could it from R with
tikzAnnotate / tikzAnnotateGrob. Of course these objects would not
really be grobs but tikz code, though for text the end result would
probably be the same.

Cheers,

baptiste


On 4 June 2012 08:22, Thomas Zumbrunn t.zumbr...@unibas.ch wrote:
 My question was answered off list by Paul Murrell, author of 'grid'. Here's am
 excerpt of our email exchange for the records of R-help.

  Paul Murrell 

 In some special cases, you would be able to flip shapes.  If the
 coordinates of the shapes are given in native coordinates, then you
 could reverse the scales on the viewport that you are drawing in.

 However, there is no general flip operation in 'grid'.  Especially not
 with respect to text.  Text is always left-to-right and sized using
 absolute units (points [modulo cex multipliers]).

 If you really desperately needed to do something like this, a last
 resort might be to draw the required scene in hi-res raster format.
 You could then easily flip the raster and draw that.

  Thomas Zumbrunn 

 I was actually asking the question primarily because I wanted to flip text
 grobs...

 If you really desperately needed to do something like this, a last
 resort might be to draw the required scene in hi-res raster format.
 You could then easily flip the raster and draw that.

 That's exactly what I did as a workaround, but I was hoping that there is a
 more elegant solution - especially since reading in and drawing hi-res raster
 format images slows down the execution time of my code quite considerably.

 What about converting text into paths? Could one do this in R? Then one could
 use your suggested solution of reversing the scales of the viewport.

  Paul Murrell 

 Interesting idea.  You could do that using the 'grImport'.  Something
 like ...

 library(grid)
 postscript(test.ps)
 grid.text(test)
 dev.off()

 library(grImport)
 PostScriptTrace(test.ps, test.xml)
 test - readPicture(test.xml)
 # To check the scales on the picture
 # test@summary
 grid.picture(test,
              yscale=c(4400, 4000),
              xscale=c(2936.84, 3019.76))




 On Tuesday 22 May 2012, Thomas Zumbrunn wrote:
 Hi everyone

 I'd like to flip grobs (grid graphical objects) along an axis, e.g. flip
 grobs horizontally or vertically. I couldn't find any hints, neither in
 the documentation nor by searching the web. Does anybody know how to
 achieve this?

 Cheers
 /thomas

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] fine control of plots after use of layout(matrix ...

2012-06-03 Thread Matthew Johnson
Thank you.

Sent from my iPad

On 04/06/2012, at 7:12 AM, Sarah Goslee sarah.gos...@gmail.com wrote:

 On Sun, Jun 3, 2012 at 5:02 PM, Matthew Johnson mcoog...@gmail.com wrote:
 Thanks. The solution i have been persuing is reading Murrell - and
 trying to figure out grid / Viewport commands. Is it best to stay in
 the base graphics package if possible?

 It really depends on what you need to do. Your original example used
 plot, so I went with par.

 Murrell's explanation of par() options is also very good.

 Sarah

 On 04/06/2012, at 6:20 AM, Sarah Goslee sarah.gos...@gmail.com wrote:

 On Sun, Jun 3, 2012 at 4:05 PM, Matthew Johnson mcoog...@gmail.com wrote:
 Thanks. So i can call par after the layout command? I did not realise.

 Some par options are set by calling par() directly, while others must
 be included in the plot command itself.

 Sarah

 Sent from my iPad

 On 03/06/2012, at 9:42 PM, Sarah Goslee sarah.gos...@gmail.com wrote:



 On Sunday, June 3, 2012, Matthew Johnson wrote:

 Sir,


 I'm no sir, but you need to spend some quality time reading ?par to lean
 abot axes and margins.

 Sarah


 I would like to create a combined line-bar plot, with the line up top and
 bar plot below, but with the x-axes suppressed on the topmost plot, the
 line and bar plot areas joined by a common line, and the x-axes (of dates)
 joined to the bottom part of the bar plot.

 i have been able to format the area using the layout(matrix( ... commands,
 but cannot figure out the final step.

 here's the code so far:


 layout(matrix(c(1,2), 2, 1, byrow=TRUE), widths=c(3,3), heights=c(2,1))
 plot(saDwlPx[,1])
 barplot(saDwlMoM[,1])

 thanks + best regards

 matt johnson


 --
 Sarah Goslee
 http://www.sarahgoslee.com

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Problems installing Packages

2012-06-03 Thread R. Michael Weylandt
I'm not really an expert on BLAS-y things, but wouldn't there be more
problems upstream with R if it weren't able to find the local BLAS? I
was under the impression that R shipped it's own BLAS but could also
be directed to one at compile time -- either way, I would guess that
many other would break if the whole BLAS went missing for whatever
reason.

to Sven: Did you use a repository build or compile it yourself? And
did you touch the BLAS or R's linker flags?

Best,
Michael

On Sun, Jun 3, 2012 at 1:46 PM, Jeff Newmiller jdnew...@dcn.davis.ca.us wrote:
 The error says you are missing the BLAS library... so install it?
 ---
 Jeff Newmiller                        The     .       .  Go Live...
 DCN:jdnew...@dcn.davis.ca.us        Basics: ##.#.       ##.#.  Live Go...
                                      Live:   OO#.. Dead: OO#..  Playing
 Research Engineer (Solar/Batteries            O.O#.       #.O#.  with
 /Software/Embedded Controllers)               .OO#.       .OO#.  rocks...1k
 ---
 Sent from my phone. Please excuse my brevity.

 Sven D sd...@hotmail.com wrote:

Hello,

I am going through Zhao's RDataMining PDF, and to redo all the graphics
on
my computer, I need several packages, 'coin' and 'party' to name two.

I get the following error:

 install.packages(coin)
Installing package(s) into
‘/home/sven/R/i686-pc-linux-gnu-library/2.15’
(as ‘lib’ is unspecified)
trying URL
'http://cran.ma.imperial.ac.uk/src/contrib/coin_1.0-21.tar.gz'
Content type 'application/x-gzip' length 903944 bytes (882 Kb)
opened URL
==
downloaded 882 Kb

* installing *source* package ‘coin’ ...
** package ‘coin’ successfully unpacked and MD5 sums checked
** libs
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG      -fpic  -O3 -pipe
-g  -c
Classes.c -o Classes.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG      -fpic  -O3 -pipe
-g  -c
Helpers.c -o Helpers.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG      -fpic  -O3 -pipe
-g  -c
LinearStatistic.c -o LinearStatistic.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG      -fpic  -O3 -pipe
-g  -c
StreitbergRoehmel.c -o StreitbergRoehmel.o
gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG      -fpic  -O3 -pipe
-g  -c
vandeWiel.c -o vandeWiel.o
gcc -std=gnu99 -shared -o coin.so Classes.o Helpers.o LinearStatistic.o
StreitbergRoehmel.o vandeWiel.o -lblas -lgfortran -lm -L/usr/lib/R/lib
-lR
/usr/bin/ld: cannot find -lblas
collect2: ld returned 1 exit status
make: *** [coin.so] Error 1
ERROR: compilation failed for package ‘coin’
* removing ‘/home/sven/R/i686-pc-linux-gnu-library/2.15/coin’
Warning in install.packages :
  installation of package ‘coin’ had non-zero exit status

The downloaded source packages are in
       ‘/tmp/RtmpYPqZgS/downloaded_packages’

My system session info is as follows:

R version 2.15.0 (2012-03-30)
Platform: i686-pc-linux-gnu (32-bit)

locale:
 [1] LC_CTYPE=en_GB.UTF-8       LC_NUMERIC=C
 [3] LC_TIME=en_GB.UTF-8        LC_COLLATE=en_GB.UTF-8
 [5] LC_MONETARY=en_GB.UTF-8    LC_MESSAGES=en_GB.UTF-8
 [7] LC_PAPER=C                 LC_NAME=C
 [9] LC_ADDRESS=C               LC_TELEPHONE=C
[11] LC_MEASUREMENT=en_GB.UTF-8 LC_IDENTIFICATION=C

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods
[7] base

loaded via a namespace (and not attached):
[1] tools_2.15.0


I do not have a problem loading it on my windows PC. Anyone having
similar
experience, and perhaps know the solution? Furthermore, package
'RHTMLForms'
from Omegahat I could only install on the ubuntu computer and not on
the
windows computer. Anyone know the reason why? Perhaps this is not even
an R
question, but any hint would be great.

Thanks



Sven


--
View this message in context:
http://r.789695.n4.nabble.com/Problems-installing-Packages-tp4632217.html
Sent from the R help mailing list archive at Nabble.com.

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] CRAN (and crantastic) updates this week

2012-06-03 Thread Crantastic
CRAN (and crantastic) updates this week

New packages


* anametrix (0.1)
  Maintainer: Roman Jugai
  Author(s): Roman Jugai
  License: LGPL
  http://crantastic.org/packages/anametrix

  Connects to Anametrix API and extracts data into R data structure

* assertive (0.1-4)
  Maintainer: Richard Cotton
  Author(s): Richard Cotton [aut, cre]
  License: Unlimited
  http://crantastic.org/packages/assertive

  assertive contains lots of is_* functions to check the state of your
  variables, and assert_* functions to throw errors if they aren't in
  the right form.

* crblocks (0.5-0)
  Maintainer: David Allingham
  Author(s): David Allingham, D.J. Best
  License: GPL (= 2)
  http://crantastic.org/packages/crblocks

  Implements a statistical test for comparing bar plots or histograms of
  categorical data derived from a randomized block repeated measures
  layout.

* deltaPlotR (1.0)
  Maintainer: David Magis
  Author(s): David Magis (U Liege), Bruno Facon (Univ Lille-Nord de France)
  License: GPL (= 2)
  http://crantastic.org/packages/deltaPlotR

  The deltaPlot package proposes an implementation of Angoff's elta Plot
  method to detect dichotomous DIF. Several detection thresholds are
  included, either from multivariate normality asumption, random
  simulation, or by prior determination. Item purification is
  supported.

* disp2D (1.0)
  Maintainer: Guillermo Ayala
  Author(s): Guillermo Ayala
  License: GPL-2
  http://crantastic.org/packages/disp2D

  An implementation of two exact algorithms for testing the Hausdorff
  and simplex dispersion orderings

* foodweb (1-0)
  Maintainer: Giselle Perdomo
  Author(s): Giselle Perdomo
  License: GPL (= 2)
  http://crantastic.org/packages/foodweb

  Calculates twelve commonly-used, basic measures of food web network
  structure from binary, predator-prey matrices: species richness,
  connectance, total number of links, link density, number of trophic
  positions, predator:prey ratio, and fraction of carnivores,
  herbivores, top species and intermediate species.  Employs food web
  language in the code and output, translates between a couple of
  common food web formats, can handle food webs consisting of multiple
  levels, and can automate the analysis for a large number of webs.
  The program produces 3-dimensional graphs of high quality that can
  be customized by the user.

* genomicper (1.3)
  Maintainer: Claudia Cabrera
  Author(s): Claudia P.Cabrera-Cardenas,Pau Navarro,Chris S.Haley
  License: GPL-2
  http://crantastic.org/packages/genomicper

  Circular genomic permutation approach uses GWAS results to establish
  the significance of pathway/gene-set associations whilst accounting
  for genomic structure. All SNPs in the GWAS are placed in a
  'circular genome' according to their location. Then the complete set
  of SNP association p-values are permuted by rotation with respect to
  the SNPs' genomic locations

* hiPOD (1.0)
  Maintainer: Wei E. Liang
  Author(s): Wei E. Liang
  License: GPL-3
  http://crantastic.org/packages/hiPOD

  Based on hierarchical modeling, this package provides a few practical
  functions to find and present the optimal designs for a pooled NGS
  design.

* intpoint (1.0)
  Maintainer: Alejandro Quintela del Rio
  Author(s): Alejandro Quintela del Rio
  License: GPL-2
  http://crantastic.org/packages/intpoint

  Solves linear programming problems by the interior point method, and
  plots the graphical solution of a linear programming problem of two
  dimensions.

* jmec (1.0-3)
  Maintainer: Willem M. van der Wal
  Author(s): Willem M. van der Wal w.m.vd@umcutrecht.nl
  License: GPL (= 2)
  http://crantastic.org/packages/jmec

  Fit joint model for event and censoring, with cluster-level frailties,
  according to Huang amp; Wolfe (2002).

* knnGarden (1.0)
  Maintainer: Boxian Wei
  Author(s): Boxian Wei  Fan Yang  Xinmiao Wang  Yanni Ge
  License: GPL (= 2)
  http://crantastic.org/packages/knnGarden

  Muti-distance based k-Nearest Neighbors Classification with K
  Threshold Value Check and Same K_i Problem Dealing, Missing
  Observations Filling

* longclust (1.1)
  Maintainer: K. Raju Jampani
  Author(s): P. D. McNicholas, K. Raju Jampani and Sanjeena Subedi
  License: GPL-2
  http://crantastic.org/packages/longclust

  Clustering or classification of longitudinal data based on a mixture
  of multivariate t or Gaussian distributions with a
  Cholesky-decomposed covariance structure.

* OIdata (1.0)
  Maintainer: Andrew P Bray
  Author(s): Andrew P Bray and David M Diez
  License: GPL-2 | GPL-3
  http://crantastic.org/packages/OIdata

  A collection of data sets from several sources that may be useful for
  teaching, practice, or other purposes. Functions have also been
  included to assist in the retrieval of table data from websites or
  in visualizing sample data.

* ParamHelpers (1.0-55)
  Maintainer: Bernd Bischl
  Author(s): Bernd Bischl bernd_bis...@gmx.net, Patrick Koch
 

Re: [R] regsubsets (Leaps)

2012-06-03 Thread Thomas Lumley
On Sat, Jun 2, 2012 at 3:19 AM, farmedgirl ksteinm...@cdpr.ca.gov wrote:
 Hi
 i need to create a model from 250 + variables with high collinearity, and
 only 17 data points (p = 250, n = 750). I would prefer to use Cp, AIC,
 and/or BIC to narrow down the number of variables, and then use VIF to
 choose a model without collinearity (if possible).  I realize that having a
 huge p and small n is going to give me extreme linear dependency problems,
 but I *think* these model selection criteria should still be useful?

 I have currently been running regsubsets for over a week with no results. I
 have no idea if R is still working, or if the computer is hung. I ran
 regsubsets on a smaller portion of the data, also with linear dependency
 problems, and got results. However, the hourglass continues its endless
 spiraling with the full dataset.

 I am running the following on Windows 7
 library(leaps)
 m_250-regsubsets(Y~., data=model2, nbest=1, really.big=TRUE)

 (NOTE: The ~ is a tilda, not a dash, in the regression statement above: Y~.)

 Does anyone have any opinions on:
 1) is R likely to still be running, even after a week, or should i just shut
 it down?

It's likely to be running for years.  2^250 is a large number, even
with the branch-and-bound algorithm to cut it down.

 2) am i doing something wrong with regsubsets?

Yes.  At the very least, set nvmax to something reasonable.  You
certainly don't want to find a model with 243 variables, so don't
waste time looking for one.


 3) is there a better option than regsubsets,

Almost certainly.  regsubsets() is pretty much useless as a way of
selecting a single model, unless perhaps when p is very small.  It was
produced as a way of viewing a large collection of best models, as in
the example for the plot() method, by setting nbest fairly large


  -thomas

-- 
Thomas Lumley
Professor of Biostatistics
University of Auckland

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[R] Variate

2012-06-03 Thread eliza botto



Dear
R users,

We
are working on a project called,”Environmental Impact Assessment”. We are 
stationed
at alpine regions of Ireland to see the impact of rainfall on localities. We 
have
divided our study area into 92 stations. We have also collected 1 year data
from each station. Afterwards we placed data into a matrix in such a way that
we got 366*92 matrix. 366 stands for number of days. 

What
we want is a lognormal probability plot, of each station(which is individual
column of matrix) with normal reduced variant on x-axis. In this way, we should
be getting, at the end, 92 curves, one for each station, on same coordinate
axis.

Kindly
help us on that. We are all very new to R. 

 

Eliza
botto 

Waters
Inn



 CC: r-help@r-project.org
 From: dwinsem...@comcast.net
 To: eliza_bo...@hotmail.com
 Subject: Re: [R] Log-normal probability plot
 Date: Sun, 3 Jun 2012 13:11:35 -0400
 
 
 On Jun 2, 2012, at 9:38 PM, eliza botto wrote:
 
 You might consider the strategy of reading the Posting Guide, followed  
 by posting an intelligible message.
 
 
  Dear R users,
 
  You can literally safe my
  life my telling me the solution of my problem. I have created matrix  
  of a data
  frame with 3 columns, with each column representing data of  
  different year.
 
   2
 ...snipped useless srting of numbers mangled by mailer processing of  
 HTML.
 
  4
 
 
 
  I now want to plot “Lognormal
  probability plot” of each column data against its respective “normal  
  reduced
  variante(z)”.
 
 Normal reduced variate? What is that? Is it a set of numbers that  
 have been centered and scaled, also known as a z-transform? If so, I  
 do not think it should affect the results of a probability plot since  
 it is just a linear transformation and the theoretical quantiles will  
 be unaffected.
 
 You might look at qqplot()
 
 
  How to do that?
 
 
  If you don’t know the
  answer, consider me dead.
 
 What greater lifesaving project are you trying to accomplish,    
 other than getting homework done?
  
  [[alternative HTML version deleted]]
 
 
 -- 
 David Winsemius, MD
 West Hartford, CT
 
  
[[alternative HTML version deleted]]

__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Variate

2012-06-03 Thread Duncan Mackay

Hi Eliza

You  will not want 1 panel with 96 lines - too confusing after about 20
Instead 1 per panel or with groups using useOuterStrips  and 
combineLimits from latticeExtra  package


Try this -- a minimal example with an 12 row 8 col grid done on the fly

setseed(12)
Sites - 1:92
dat -
data.frame(y = rep(rnorm(5),92), x = rep(1:5,92), site = rep(Sites,each = 5))

xyplot(y ~ x|site,dat,
   as.table=T,
   strip = F,
   layout = c(8,12),
   scales = list(x = list(alternating = 2),y=list(alternating=1)),
   type = b,
   panel = function(x,y,...){
pnl=panel.number()
panel.xyplot(x,y,...)
panel.text(4,-1.5,Sites[pnl], cex = 0.6)
  }
)

or with groupings for Site something like (untested)

xyplot(y ~ x|groupings,dat,
   as.table=T,
   strip = F,
   strip.left = T,
   groups = site,
   scales = list(x = list(alternating = 2),y=list(alternating=1)),
   type = b,
   panel = function(x,y,...){
pnl=panel.number()
panel.xyplot(x,y,...)
panel.text(4,-1.5,Sites[pnl], cex = 0.6)
  }
)
You will need an extra column for groupings

This can also be done with the base plot function but lattice gives 
more flexibility, see  ?xyplot  and particularly par.settings into 
get things right size


Regards

Duncan


Duncan Mackay
Department of Agronomy and Soil Science
University of New England
Armidale NSW 2351
Email: home: mac...@northnet.com.au


At 11:01 4/06/2012, you wrote:

Content-Type: text/plain
Content-Disposition: inline
Content-length: 2431




Dear
R users,

We
are working on a project called,Environmental Impact Assessment. 
We are stationed
at alpine regions of Ireland to see the impact of rainfall on 
localities. We have

divided our study area into 92 stations. We have also collected 1 year data
from each station. Afterwards we placed data into a matrix in such a way that
we got 366*92 matrix. 366 stands for number of days.

What
we want is a lognormal probability plot, of each station(which is individual
column of matrix) with normal reduced variant on x-axis. In this 
way, we should

be getting, at the end, 92 curves, one for each station, on same coordinate
axis.

Kindly
help us on that. We are all very new to R.



Eliza
botto

Waters
Inn



 CC: r-help@r-project.org
 From: dwinsem...@comcast.net
 To: eliza_bo...@hotmail.com
 Subject: Re: [R] Log-normal probability plot
 Date: Sun, 3 Jun 2012 13:11:35 -0400


 On Jun 2, 2012, at 9:38 PM, eliza botto wrote:

 You might consider the strategy of reading the Posting Guide, followed
 by posting an intelligible message.

 
  Dear R users,
 
  You can literally safe my
  life my telling me the solution of my problem. I have created matrix
  of a data
  frame with 3 columns, with each column representing data of
  different year.
 
   2
 ...snipped useless srting of numbers mangled by mailer processing of
 HTML.

  4
 
 

  I now want to plot Lognormal
  probability plot of each column data against its respective normal
  reduced
  variante(z).

 Normal reduced variate? What is that? Is it a set of numbers that
 have been centered and scaled, also known as a z-transform? If so, I
 do not think it should affect the results of a probability plot since
 it is just a linear transformation and the theoretical quantiles will
 be unaffected.

 You might look at qqplot()

 
  How to do that?

 
  If you don't know the
  answer, consider me dead.

 What greater lifesaving project are you trying to accomplish, 
 other than getting homework done?
 
  [[alternative HTML version deleted]]


 --
 David Winsemius, MD
 West Hartford, CT


[[alternative HTML version deleted]]


__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Modify pdf file with Illustrator.

2012-06-03 Thread Jinyan Huang
Thank you for your suggestion.

Do you have some example codes using  ggplot2 or grid.arrange() and
arrangeGrob to composite figures?



On Mon, Jun 4, 2012 at 7:36 AM, Neil Collier neilander...@gmail.com wrote:
 ggplot2 handles all of these requirements. I highly recommend using it for
 composite figures. Try the grid.arrange() and arrangeGrob in the 'gridExtra'
 package in addition to ggplot2.



 On Mon, Jun 4, 2012 at 1:08 AM, Uwe Ligges lig...@statistik.tu-dortmund.de
 wrote:



 On 03.06.2012 17:03, Jinyan Huang wrote:

 Thank you.

 1, I want to put some text and title. Then put several figures into one.


 So  just do it within R and use title() within R and use par() and its
 argument mfrow to arrange several figures in rows and columns.

 Uwe Ligges



 On Sun, Jun 3, 2012 at 10:59 PM, Uwe Ligges
 lig...@statistik.tu-dortmund.de  wrote:



 On 03.06.2012 08:42, Jinyan Huang wrote:


 Dear list,

 Some times I want to modify the pdf file which produced by R with
 illustrator. But when I use Illustrator open the pdf file, it often
 makes the pdf some little changed. Anyone have some suggestions? Is it
 better to use other file type, not pdf? Or when I produced the pdf, I
 should set some other parameters?



 Questions are:

 1. Why do you need to modify it, perhaps you don't.
 2. What dio you want to do with the file in later steps? Perhaps a
 format
 with a representation in a more human readable form helps...

 Best,
 Uwe Ligges




 Thank you

 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
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 https://stat.ethz.ch/mailman/listinfo/r-help
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 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.



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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] Legend colors not matching with Intxplot line colors

2012-06-03 Thread arun
Dear R help,

I am using intxplot() from the library(HH).  I have a dataset with 12 treatment 
groups.  At first, I tried intxplot with no color settings.  Then, the legend 
color was matching with the plot line colors, but some of the colors were 
repeated.  So, I set the colors using par.settings.  Now, I have the plot lines 
with different colors, but it seemed to be not matching with legend color.  
Legend colors are repeated.  I am pasting below sample dataset with codes.

set.seed(1)
dat1-rnorm(120,0.5,0.2)
dat2-data.frame(time=rep(c(1:20),rep(12,20)),trt=rep(LETTERS[1:12],each=1))
dat3-data.frame(dat2,dat1)
colnames(dat3)-c(names(dat2),Response)
dat3-transform(dat3,trt=ordered(trt,levels=LETTERS[1:12]))    
dat3$time-factor(dat3$time)
position(dat3$time)-as.numeric(levels(dat3$time))

library(HH)
par.settings-simpleTheme(col=c(8,12,28,36,41,47,81,92,98,113,125,155))
intxplot(Response ~ time, data = dat3, groups = trt, ylim=c(0,1), 
par.settings=par.settings, main= Response)

Any help will be appreciated.

Thanks,
A.K.

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[R] Separate Array Variable Content

2012-06-03 Thread arun



Hi Antony,

I am sending this message again as it was not yet posted by the rhelp.
 
One more solution:

dat2-read.table(text=
 ABC PQR XYZ
 42  29  22
 65  22  78      
 10  20  30
 40  50  60
 70  80  90
 61  15  24  
 ,sep=,header=T)


exprv - expression(c( ABC10  XYZ 30  PQR 90,ABC 9  XYZ 25  PQR 
60,ABC 60  XYZ 79  PQR 100))
dat3-list(ABC=dat2[,1],PQR=dat2[,2],XYZ=dat2[,3])


res1-sapply(exprv,function(x) with(dat3,eval(x)))
res2-data.frame(ABC_CHECK=res1[1:6,],XYZ_CHECK=res1[7:12,],PQR_CHECK=res1[13:18,])

resultA-data.frame(dat2,res2)
resultA
  ABC PQR XYZ ABC_CHECK XYZ_CHECK PQR_CHECK
1  42  29  22  TRUE  TRUE FALSE
2  65  22  78 FALSE FALSE  TRUE
3  10  20  30 FALSE FALSE FALSE
4  40  50  60 FALSE FALSE FALSE
5  70  80  90 FALSE FALSE FALSE
6  61  15  24  TRUE  TRUE  TRUE

# which is the same as the one below.

A.K.





- Original Message -
From: arun smartpink...@yahoo.com
To: Akkara, Antony (GE Energy, Non-GE) antony.akk...@ge.com
Cc: R help r-help@r-project.org
Sent: Friday, June 1, 2012 7:21 PM
Subject: Re: [R] Separate Array Variable Content

Hi Antony,

I guess I understood the format you needed.  I assume that there are only few 
conditions in the second matrix.

Based on the information given, I would do:

dat1-read.table(text=
 ABC PQR XYZ
 42  29  22
 65  22  78      
 10  20  30
 40  50  60
 70  80  90
 61  15  24  
 ,sep=,header=T)


#I added some more datapoints

dat1[dat1$ABC  10  dat1$XYZ  30  dat1$PQR  90,ABC_CHECK]-TRUE
dat1[dat1$ABC  9  dat1$XYZ  25  dat1$PQR  60,XYZ_CHECK]-TRUE
dat1[dat1$ABC  60  dat1$XYZ  79  dat1$PQR  100,PQR_CHECK]-TRUE


dat1[is.na(dat1)]-FALSE
 
 dat1
  ABC PQR XYZ ABC_CHECK XYZ_CHECK PQR_CHECK
1  42  29  22  TRUE  TRUE FALSE
2  65  22  78 FALSE FALSE  TRUE
3  10  20  30 FALSE FALSE FALSE
4  40  50  60 FALSE FALSE FALSE
5  70  80  90 FALSE FALSE FALSE
6  61  15  24  TRUE  TRUE  TRUE


#if your data is in matrix format, convert it to dataframe.
dat1-as.matrix(dat1)
dat1-data.frame(dat1)


I hope this helps.

A.K.




- Original Message -
From: Akkara, Antony (GE Energy, Non-GE) antony.akk...@ge.com
To: arun smartpink...@yahoo.com
Cc: 
Sent: Friday, June 1, 2012 2:15 AM
Subject: RE: [R] Separate Array Variable Content

Hi Arun,

What you showed, same like I am also expecting.

There is two matrix,
    1) 1st - matrix contain values like this,

        ABC       XYZ     PQR       ABC_CHECK       XYZ_CHECK       PQR_CHECK
                               --       
-            
                                 10      20         30
     40    50         60
     70    80         90

    2)2nd matrix have some conditions, need to check with  1st matrix columns. 
Like this,
        
        CHECK FOR            CONDITION
        --            -
        ABC_CHECK            ABC  10  XYZ  30  PQR 90
        XYZ_CHECK            ABC  9  XYZ  25  PQR 60
        PQR_CHECK            ABC  60  XYZ  79  PQR 100


So, 
    Finally the result should get like this,

        ABC       XYZ     PQR       ABC_CHECK       XYZ_CHECK       PQR_CHECK
                               --       
-            
                                 10      20         30    FALSE        TRUE     
   FALSE
     40    50         60    FALSE        FALSE        FALSE
     70    80         90    FALSE        FALSE        TRUE

And can please tell me which is the best way to do this ?, Can we do this 
with-out loop ?

- Thanks 
Antony.



-Original Message-
From: arun [mailto:smartpink...@yahoo.com] 
Sent: Wednesday, May 30, 2012 10:43 PM
To: Akkara, Antony (GE Energy, Non-GE)
Cc: R help
Subject: Re: [R] Separate Array Variable Content

HI Antony,

I am not sure how you want the result.

Is it something like this?  Also, do you have lots of conditions in the array?


 Mydat2
  ABC PQR XYZ ELIGIBLE_ABC ELIGIBLE_PQR ELIGIBLE_ABC_XYZ
1  10  20  
30   TRUE
2  40  50  60
3  70  80  90 TRUE TRUE 



A.K.



- Original Message -
From: Rantony antony.akk...@ge.com
To: r-help@r-project.org
Cc: 
Sent: Wednesday, May 30, 2012 2:44 AM
Subject: [R] Separate Array Variable Content

Hi,

I am new in R,

i have a matrix like this

MyMatrix -
*ABC   PQR    XYZ*
10       20        30
40       50        60
70       80        90

And, i have an array containing some conditions like this, MyArray -  
c(*ABC*50,*PQR*50,*ABC*30 * XYZ*40)

ABC50 
PQR50
ABC30  XYZ40

My purpose what is, i need to check this conditions in *MyArray* with
*MyMatrix* value for particular column

How it is possible ? 

- Thanks
Antony.

--
View this message in context: 

Re: [R] a question about subsetting

2012-06-03 Thread arun
HI,

I am not sure about whether your subset function is correct.  If you look into 
this link (http://stat.ethz.ch/R-manual/R-devel/library/base/html/subset.html), 
it says about how to use subset (subset(data, condition) instead of 
(subset=data==condition).  Also, the one I am describing about use a different 
format.  For eg, in your data, both Group1 and Group2 are separate columns with 
each having the same values for the independent variables.  Normally, for 
different groups (or factors with multiple levels), it will be in the same 
column like this:
 dat2
   ID Group Mem   Gen Chance MSELGM MSELVR MSELFM MSELRL MSELEL ADOS Age
1   1 1  75  50.0 50 53 52 62 57 56    3  25
2   2 1  75  12.5 50 46 48 47 52 55    2  30
3   3 1  25  37.5 50 48 43 52 63 63    3  24
4   4 1  25  37.5 50 51 62 52 59 54    0  31
5   5 1  50  87.5 50 45 58 42 46 43    6  31
6   6 1 100 100.0 50 45 80 49 69 63    1  31
7   7 2  75  50.0 50 53 52 62 57 56    3  25
8   8 2  75  12.5 50 46 48 47 52 55    2  30
9   9 2  25  37.5 50 48 43 52 63 63    3  24
10 10 2  25  37.5 50 51 62 52 59 54    0  31
11 11 2  50  87.5 50 45 58 42 46 43    6  31
12 12 2 100 100.0 50 45 80 49 69 63    1  31


dat3-subset(dat2,Group==1)
dat4-subset(dat2,Group==2)
 dat4
   ID Group Mem   Gen Chance MSELGM MSELVR MSELFM MSELRL MSELEL ADOS Age
7   7 2  75  50.0 50 53 52 62 57 56    3  25
8   8 2  75  12.5 50 46 48 47 52 55    2  30
9   9 2  25  37.5 50 48 43 52 63 63    3  24
10 10 2  25  37.5 50 51 62 52 59 54    0  31
11 11 2  50  87.5 50 45 58 42 46 43    6  31
12 12 2 100 100.0 50 45 80 49 69 63    1  31


 fit1-lm(Gen~MSELEL,data=dat3)
 fit2-lm(Gen~MSELEL,data=dat4)

cor.test (dat3$Gen, dat3$MSELEL, method=pearson)

In the sample dataset that you showed here, you will get the same correlation 
results and regression results for both groups as there was no change in the 
values of the dependent or independent variables.

I guess this helps.



A.K.

  



- Original Message -
From: jacaranda tree myjacara...@yahoo.com
To: R-help@r-project.org R-help@r-project.org
Cc: 
Sent: Sunday, June 3, 2012 11:51 AM
Subject: [R] a question about subsetting

Hi all,
I started using R about 3 weeks ago, and now I've pretty much figured out how 
to do the types of statistical modeling, graphs, tables etc. that I frequently  
use (with zero background in computer languages or other statistical packages 
that are similar to R like S or SAS!). So it's been a  quite  rewarding process 
so far, and I thank you all R gurus for all your generous help!
That being said, my question is about applying a model or an analysis to 
different groups based on a grouping variable. Below is the first six rows of 
my data:

   ID Group1 Group2 Mem   Gen Chance MSELGM MSELVR MSELFM MSELRL MSELEL ADOS Age
1  1      1           1        75     50.0     50         53               52   
         62             57            56        3        25
2  2      1           1        75     12.5     50         46               48   
         47             52            55        2        30
3  3      1           1        25     37.5     50         48               43   
         52             63            63        3        24
4  4      1           1        25     37.5     50         51               62   
         52             59            54        0        31
5  5      1           1        50     87.5     50         45               58   
         42             46            43        6        31
6  6      1           1       100    100.0   50         45               80     
       49             69            63        1        31

Group1: First grouping variable
Group2: Second grouping variable
Mem: Memory trial
Gen: Generalization trial
MSEL: Mullen Scales of Early Learning (a scale measuring various skills in 
little children). GM: Gross Motor Scale, VR: Visual Reception, FM: Fine Motor, 
RL: receptive Language, EL: Expressive Language. 
ADOS: An autism-specific measure.

First I wanted to do correlations between Generalization (variable Gen) and 
expressive language (MSELEL) for each group of Group1. For this, I used lapply 
or by functions which work just fine. Here is the code with 
lapply: lapply(split(mydata, mydata$Group1), function(x){cor.test(x[,5],
x[,11], method = pearson)})

Then I did regression. My DV is the variable Gen, and the IV is MSELEL. And 
again I wanted to do this for each group. Here is the code I came up with for 
each group:
fit1-lm(Gen~ MSELEL, 

[R] Dummies guide to getting HPC working on R

2012-06-03 Thread Jonathan Greenberg
R-folks.  Sorry for the cross-posting, but I wanted to share a link to
a (fairly long) blog post I created which tries to take the mystery
out of getting R setup for doing high performance/parallel computing
if you have to compile R from scratch:

http://lostingeospace.blogspot.com/2012/06/r-and-hpc-blas-mpi-in-linux-environment.html

Let me know if you have any comments/corrections on it.  Cheers!

--j

-- 
Jonathan A. Greenberg, PhD
Assistant Professor
Department of Geography and Geographic Information Science
University of Illinois at Urbana-Champaign
607 South Mathews Avenue, MC 150
Urbana, IL 61801
Phone: 415-763-5476
AIM: jgrn307, MSN: jgrn...@hotmail.com, Gchat: jgrn307, Skype: jgrn3007
http://www.geog.illinois.edu/people/JonathanGreenberg.html

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[R] Rexcel question

2012-06-03 Thread blue honour
I am using the worksheet functions of RExcel. I am trying to pass a datatable 
to a function in the following call:

=RApply(O14:O18,D6)


Cells O14:O18 contain the definition of the function. This is a function that 
takes one argument which is a data.table. Cell D6 has the name of the 
data.table object. When I call the function this way, D6 is passed to the 
function as a string, not as a data.table. So I get an error. How can I fix 
this? I know that there is a data.table in R workspace with this name... I just 
can't seem to pass it to the function...
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Re: [R] Modify pdf file with Illustrator.

2012-06-03 Thread Neil Collier
ggplot2 handles all of these requirements. I highly recommend using it for
composite figures. Try the grid.arrange() and arrangeGrob in the
'gridExtra' package in addition to ggplot2.


On Mon, Jun 4, 2012 at 1:08 AM, Uwe Ligges
lig...@statistik.tu-dortmund.dewrote:



 On 03.06.2012 17:03, Jinyan Huang wrote:

 Thank you.

 1, I want to put some text and title. Then put several figures into one.


 So  just do it within R and use title() within R and use par() and its
 argument mfrow to arrange several figures in rows and columns.

 Uwe Ligges



 On Sun, Jun 3, 2012 at 10:59 PM, Uwe Ligges
 lig...@statistik.tu-dortmund.**de lig...@statistik.tu-dortmund.de
  wrote:



 On 03.06.2012 08:42, Jinyan Huang wrote:


 Dear list,

 Some times I want to modify the pdf file which produced by R with
 illustrator. But when I use Illustrator open the pdf file, it often
 makes the pdf some little changed. Anyone have some suggestions? Is it
 better to use other file type, not pdf? Or when I produced the pdf, I
 should set some other parameters?



 Questions are:

 1. Why do you need to modify it, perhaps you don't.
 2. What dio you want to do with the file in later steps? Perhaps a format
 with a representation in a more human readable form helps...

 Best,
 Uwe Ligges




 Thank you

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Re: [R] Fwd: Rgraphviz installation problem

2012-06-03 Thread slipkid90515
Martin -- I know this is about a year late, but I have to thank you for
taking the time to answer Ram's question in this thread.  It helped me get
Rgraphviz up and running.  I've been struggling with this for about 90
minutes, so thank you so much!  

And to anyone else who may run upon this thread with the same issues, I
found this link helpful: 
https://wiki.duke.edu/display/DUKER/Install+RGraphviz+under+Windows

Thanks,
Jess

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[R] Plotting with Rgraphviz

2012-06-03 Thread slipkid90515
Hi All,

After a lengthy battle just to get the package installed, I am not able to
actually use Rgraphviz to generate any plots.  I tried just using the sample
code in the documentation
(http://www2.warwick.ac.uk/fac/sci/moac/people/students/peter_cock/r/rgraphviz/)
and I get the following:

*  library(Rgraphviz)
 test.matrix-matrix(rep(c(0,1,0,0), 9), ncol=6, nrow=6)
 rownames(test.matrix)-c(a, b, c, d, e, f)
 colnames(test.matrix)-c(a, b, c, d, e, f)
 test.matrix
  a b c d e f
a 0 0 0 0 0 0
b 1 0 1 0 1 0
c 0 0 0 0 0 0
d 0 1 0 1 0 1
e 0 0 0 0 0 0
f 1 0 1 0 1 0
 am.graph-new(graphAM, adjMat=test.matrix, edgemode=directed)
 am.graph
A graphAM graph with directed edges
Number of Nodes = 6 
Number of Edges = 9 
 plot(am.graph, attrs = list(node = list(fillcolor = lightblue),
+ edge = list(arrowsize=0.5)))
There were 18 warnings (use warnings() to see them)
 warnings()
Warning messages:
1: In plot.xy(xy.coords(x, y), type = type, ...) :
  len is not a graphical parameter
2: In plot.xy(xy.coords(x, y), type = type, ...) :
  edgemode is not a graphical parameter
3: In plot.xy(xy.coords(x, y), type = type, ...) :
  len is not a graphical parameter
4: In plot.xy(xy.coords(x, y), type = type, ...) :
  edgemode is not a graphical parameter
5: In plot.xy(xy.coords(x, y), type = type, ...) :
  len is not a graphical parameter
6: In plot.xy(xy.coords(x, y), type = type, ...) :
  edgemode is not a graphical parameter
7: In plot.xy(xy.coords(x, y), type = type, ...) :
  len is not a graphical parameter
8: In plot.xy(xy.coords(x, y), type = type, ...) :
  edgemode is not a graphical parameter
9: In plot.xy(xy.coords(x, y), type = type, ...) :
  len is not a graphical parameter
10: In plot.xy(xy.coords(x, y), type = type, ...) :
  edgemode is not a graphical parameter
11: In plot.xy(xy.coords(x, y), type = type, ...) :
  len is not a graphical parameter
12: In plot.xy(xy.coords(x, y), type = type, ...) :
  edgemode is not a graphical parameter
13: In plot.xy(xy.coords(x, y), type = type, ...) :
  len is not a graphical parameter
14: In plot.xy(xy.coords(x, y), type = type, ...) :
  edgemode is not a graphical parameter
15: In plot.xy(xy.coords(x, y), type = type, ...) :
  len is not a graphical parameter
16: In plot.xy(xy.coords(x, y), type = type, ...) :
  edgemode is not a graphical parameter
17: In plot.xy(xy.coords(x, y), type = type, ...) :
  len is not a graphical parameter
18: In plot.xy(xy.coords(x, y), type = type, ...) :
  edgemode is not a graphical parameter*


Anyone with the same problem?  Any ideas on how to fix?

Thanks,
Jess

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Re: [R] R 15.0 Warning message.

2012-06-03 Thread Jinyan Huang
At last, the administrator provide me this command to fix this problem.

echo setenv LC_ALL en_US.UTF8  ~/.cshrc.aliases



On Sun, Jun 3, 2012 at 5:47 PM, peter dalgaard pda...@gmail.com wrote:

 On Jun 3, 2012, at 11:36 , Prof Brian Ripley wrote:


 ls -ld /usr/share/locale/en_US*
 drwxr-xr-x 2 root root 4096 Dec 15 15:19 /usr/share/locale/en_US

 This is clearly not an R issue: so ask your IT support for help.

 Or check out the Ubuntu docs/forums for information on which package of 
 configuration trick you might be missing to get UTF-8 locales properly 
 installed. (Googling utf-8 ubuntu seem to come up with relevant stuff.)

 --
 Peter Dalgaard, Professor,
 Center for Statistics, Copenhagen Business School
 Solbjerg Plads 3, 2000 Frederiksberg, Denmark
 Phone: (+45)38153501
 Email: pd@cbs.dk  Priv: pda...@gmail.com









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[R] Error while trying to install RPostgreSQL.

2012-06-03 Thread Prakash Thomas
Hi,
I am getting the following error while trying to install RPostgreSQL.
I tried all three methods(install.packages(RPostgreSQL, type =
source),install.packages(RPostgreSQL)  R CMD INSTALL
RPostgreSQL_0.3-1.tar.gz ) , but none of them is working.

++ Error

gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG -I -fpic  -O3 -pipe  -g
-c RS-PQescape.c -o RS-PQescape.o
In file included from RS-PQescape.c:7:0:
RS-PostgreSQL.h:23:26: fatal error: libpq-fe.h: No such file or directory
compilation terminated.
make: *** [RS-PQescape.o] Error 1
ERROR: compilation failed for package ‘RPostgreSQL’
* removing ‘/home/intel/R/x86_64-pc-linux-gnu-library/2.15/RPostgreSQL’

The downloaded source packages are in
‘/tmp/Rtmpz4zF04/downloaded_packages’
Warning message:
In install.packages(RPostgreSQL, type = source) :
  installation of package ‘RPostgreSQL’ had non-zero exit status
++

Thanks  Regards,
Thomas

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[R] Re : Error while trying to install RPostgreSQL.

2012-06-03 Thread Pascal Oettli
Hello,

You got the detail of the error:
RS-PostgreSQL.h:23:26: fatal error: libpq-fe.h: No such file or directory
compilation terminated.

Please searc on Internet libpq-fe.h. You will get answer to your problem.

Regards




- Mail original -
De : Prakash Thomas pthomas2...@gmail.com
À : r-help@r-project.org
Cc : 
Envoyé le : Lundi 4 juin 2012 14h14
Objet : [R]  Error while trying to install RPostgreSQL.

Hi,
    I am getting the following error while trying to install RPostgreSQL.
I tried all three methods(install.packages(RPostgreSQL, type =
source),install.packages(RPostgreSQL)  R CMD INSTALL
RPostgreSQL_0.3-1.tar.gz ) , but none of them is working.

++ Error

gcc -std=gnu99 -I/usr/share/R/include -DNDEBUG -I     -fpic  -O3 -pipe  -g
-c RS-PQescape.c -o RS-PQescape.o
In file included from RS-PQescape.c:7:0:
RS-PostgreSQL.h:23:26: fatal error: libpq-fe.h: No such file or directory
compilation terminated.
make: *** [RS-PQescape.o] Error 1
ERROR: compilation failed for package ‘RPostgreSQL’
* removing ‘/home/intel/R/x86_64-pc-linux-gnu-library/2.15/RPostgreSQL’

The downloaded source packages are in
    ‘/tmp/Rtmpz4zF04/downloaded_packages’
Warning message:
In install.packages(RPostgreSQL, type = source) :
  installation of package ‘RPostgreSQL’ had non-zero exit status
++

Thanks  Regards,
Thomas

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