[R] Variable Length Differ
This is my code BSUPred-(forecast(BSU,h=h)[[2]]) PressurePred-(forecast(Pressure,h=h)[[2]]) Placer-(rep(1,h)) test-as.data.frame(cbind(BSUPred,PressurePred)) test$Placer-rep(1:2,h/12) test$Placer-i test-as.data.frame((test[c(Placer,BSUPred,PressurePred)])) resp-predict(fit,newdata=test,type=response) Pred-ifelse((predict(fit,newdata=test,type=response)0.5),1,0) But I get this error message Error in model.frame.default(Terms, newdata, na.action = na.action, xlev = object$xlevels) : variable lengths differ (found for 'Placer') Can anyone help? Thanks Tjun Kiat [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Variable Length Differ
This is not reproducible (see for example [1]), so it is very difficult to know exactly what the problem is. Also, you need to post on this list using the plain text format option in your email software, since the HTML format you used can mess up your code. I can say that using [ indexing on a data frame will give you back a data frame as long as you have multiple result columns, and cbind converts that to a matrix. Since data frames typically have columns of a variety of types (storage modes) while matrices do not, you are likely damaging your data frames every time you use cbind. I recommend that you interactively execute (e.g. using copy/paste) one line at a time in your script and use the str() function after each line to learn the structure of the the objects you are creating and modifying. The best way to make a data frame from vector is: test - data.frame( BSUPred, PressurePred ) or test - data.frame( BSUPred=BSUPred, PressurePred=PressurePred ) A couple of ways to add columns to data frames that don't damage the data frame are: test$Placer - i or (an example where specifying only one column identifies a vector rather than the usual data frame result) test[ , Placer ] - i or even (not recommended for efficiency reasons): test - data.frame( test, Placer=i ) If this is not enough help, make your example reproducible using the advice in [1] and try posting again. [1] http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On November 2, 2014 3:19:45 AM PST, TJUN KIAT TEO teotj...@hotmail.com wrote: This is my code BSUPred-(forecast(BSU,h=h)[[2]]) PressurePred-(forecast(Pressure,h=h)[[2]]) Placer-(rep(1,h)) test-as.data.frame(cbind(BSUPred,PressurePred)) test$Placer-rep(1:2,h/12) test$Placer-i test-as.data.frame((test[c(Placer,BSUPred,PressurePred)])) resp-predict(fit,newdata=test,type=response) Pred-ifelse((predict(fit,newdata=test,type=response)0.5),1,0) But I get this error message Error in model.frame.default(Terms, newdata, na.action = na.action, xlev = object$xlevels) : variable lengths differ (found for 'Placer') Can anyone help? Thanks Tjun Kiat [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Finding MLE
Hi all,
I am trying to use the mle function in R to find the maximum likelihood
estimator. The ll function below is the negative of the log likelihood.
Suppose x0 is the observed values, I want to find the maximum likelihood
for a and b. After running the code below, I get the error message Error
in eval(expr, envir, enclos) : argument is missing, with no default.
Could anyone familiar with this function give some suggetion? Thanks very
much!
Hanna
n - 8
x0 - c(2,3)
ll- function(a,b,x=x0,size=n){
+
-sum(log(gamma((n-1)/2+a-1)/(gamma((n-1)/2)*gamma(a))*1/(2*b^a)*(x/2)^((n-1)/2-1)*(1/b+x/2)^(-((n-1)/2+a-1}
fit - mle(ll, nobs = length(x0))
[[alternative HTML version deleted]]
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] Finding MLE
You do not appear to provide initial values for a and b , i.e. the
start argument for mle.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
Clifford Stoll
On Sun, Nov 2, 2014 at 10:36 AM, li li hannah@gmail.com wrote:
Hi all,
I am trying to use the mle function in R to find the maximum likelihood
estimator. The ll function below is the negative of the log likelihood.
Suppose x0 is the observed values, I want to find the maximum likelihood
for a and b. After running the code below, I get the error message Error
in eval(expr, envir, enclos) : argument is missing, with no default.
Could anyone familiar with this function give some suggetion? Thanks very
much!
Hanna
n - 8
x0 - c(2,3)
ll- function(a,b,x=x0,size=n){
+
-sum(log(gamma((n-1)/2+a-1)/(gamma((n-1)/2)*gamma(a))*1/(2*b^a)*(x/2)^((n-1)/2-1)*(1/b+x/2)^(-((n-1)/2+a-1}
fit - mle(ll, nobs = length(x0))
[[alternative HTML version deleted]]
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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[R] How to calculate correlation of a vector in R?
Hi list, I have trying to calculate the covariance/correlation of three elements. I have vector say, v - c(700, 800, 1000) I want to have a 3 by 3 correlation matrix, meaning cor(v1, c2), cor(v1, c3), cor(v2, v3), etc... So far I get, cor(v) Error in cor(v) : supply both 'x' and 'y' or a matrix-like 'x' vvv - cbind(v, v, v) cor(vvv) v v v v 1 1 1 v 1 1 1 v 1 1 1 I am calculating squared exponential kernel as seen here. http://mlg.eng.cam.ac.uk/duvenaud/cookbook/index.html Thanks a bunch, Mike [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] CRAN (and crantastic) updates this week
CRAN (and crantastic) updates this week New packages * addreg (1.2) Maintainer: Mark Donoghoe Author(s): Mark Donoghoe mark.donog...@mq.edu.au License: GPL (= 2) http://crantastic.org/packages/addreg Methods for fitting identity-link GLMs and GAMs to discrete data. The package uses EM-type algorithms with more stable convergence properties than standard methods. * CateSelection (1.0) Maintainer: Yi Xu Author(s): Yi Xu and Jixiang Wu License: GPL (= 2) http://crantastic.org/packages/CateSelection A multi-factor dimensionality reduction based forward selection method for genetic association mapping. * DAMOCLES (1.0) Maintainer: Rampal S. Etienne Author(s): Rampal S. Etienne Alex L. Pigot License: GPL-2 http://crantastic.org/packages/DAMOCLES Simulates and computes (maximum) likelihood of a dynamical model of community assembly that takes into account the phylogenetic history * exCon (0.1-0) Maintainer: Bryan A. Hanson Author(s): Bryan Hanson [aut, cre], Kristina Mulry [ctb] License: GPL-3 http://crantastic.org/packages/exCon exCon is an interactive tool to explore topographic-like data sets. Such data sets take the form of a matrix in which the rows and columns provide location/frequency information, and the matrix elements contain altitude/response information. Such data is found in cartography, 2D spectroscopy and chemometrics. exCon creates an interactive web page showing the contoured data set along with slices from the original matrix parallel to each dimension. The page is written in d3/javascript. * genpathmox (0.1) Maintainer: quot;Giuseppe Lambertiquot; Author(s): Giuseppe Lamberti [aut, cre] License: GPL-3 http://crantastic.org/packages/genpathmox genpathmox provides a very interesting solution for handling segmentation variables in complex statistical methodology. It contains en extended version of the PATHMOX algorithm in the context of partial least square path modeling (Sanchez, 2009) including the F-block test (to detect the responsible latent endogenous equations of the difference), the F-coefficient (to detect the path coefficients responsible of the difference) and the invariance test (to realize a comparison between the sub-models#39; latent variables). Furthermore, the package contains a generalized version of the PATHMOX algorithm to approach different methodologies: linear regression and least absolute regression models. * hermite (1.0) Maintainer: David Moriña Soler Author(s): David Moriña (Centre for Research in Environmental Epidemiology, CREAL), Manuel Higueras (Universitat Autònoma de Barcelona and Public Health England) and Pedro Puig (Universitat Autònoma de Barcelona) License: GPL (= 2) http://crantastic.org/packages/hermite Probability functions for the generalized Hermite distribution * MfUSampler (0.9) Maintainer: Alireza S. Mahani Author(s): Alireza S. Mahani, Mansour T.A. Sharabiani License: GPL (= 2) http://crantastic.org/packages/MfUSampler Convenience Functions for Multivariate MCMC Using Univariate Samplers, including Slice Sampler with Stepout and Shrinkage (Neal, 2003), and Adaptive Rejection Sampler (Gilks and Wild, 1992). * myTAI (0.0.1) Maintainer: Hajk-Georg Drost Author(s): Hajk-Georg Drost License: GPL-3 http://crantastic.org/packages/myTAI The present collection of functions can be used to perform phylotranscriptomics analyses to investigate phenomena within the field of Evolutionary Developmental Biology * PrevMap (1.0) Maintainer: Emanuele Giorgi Author(s): Emanuele Giorgi, Peter J. Diggle License: GPL (= 2) http://crantastic.org/packages/PrevMap The PrevMap package provides functions for both likelihood-based and Bayesian analysis of spatially referenced prevalence data. #39;PrevMap#39; is also an extension of the #39;geoR#39; package which should be installed first together with the #39;maxLik#39;, #39;raster#39; and #39;pdist#39; packages. * qdm (0.1-0) Maintainer: Nora Umbach Author(s): Nora Umbach [aut, cre], Florian Wickelmaier [aut] License: GPL (= 2) http://crantastic.org/packages/qdm This package provides different specifications of a Quadrilateral Dissimilarity Model which can be used to fit same-different judgments in order to get a predicted matrix that satisfies regular minimality [Colonius amp; Dzhafarov, 2006, Measurement and representations of sensations, Erlbaum]. From such a matrix, Fechnerian distances can be computed. * RealVAMS (0.3-1) Maintainer: Andrew Karl Author(s): Andrew Karl, Jennifer Broatch, and Jennifer Green License: GPL-2 http://crantastic.org/packages/RealVAMS The RealVAMs package fits a multivariate value-added model (VAM) (see Broatch and Lohr 2012) with normally distributed test scores and a binary outcome indicator. This material is based upon work supported
Re: [R] How to calculate correlation of a vector in R?
What is your question? The matrix form is probably what you are looking for, but you put the same vector in three times so if course it is all ones. I don't know what you expected to happen when you entered cor(v) since there is nothing to correlate if you only have one vector. Please post in plain text as the footer and Posting Guide request. --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On November 2, 2014 3:30:14 PM PST, C W tmrs...@gmail.com wrote: Hi list, I have trying to calculate the covariance/correlation of three elements. I have vector say, v - c(700, 800, 1000) I want to have a 3 by 3 correlation matrix, meaning cor(v1, c2), cor(v1, c3), cor(v2, v3), etc... So far I get, cor(v) Error in cor(v) : supply both 'x' and 'y' or a matrix-like 'x' vvv - cbind(v, v, v) cor(vvv) v v v v 1 1 1 v 1 1 1 v 1 1 1 I am calculating squared exponential kernel as seen here. http://mlg.eng.cam.ac.uk/duvenaud/cookbook/index.html Thanks a bunch, Mike [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to calculate correlation of a vector in R?
Thanks, Jeff. I had some misunderstanding. So, I want to calculate the squared exponential of vector v v = c(700, 800, 1029) formula is: k(x_i, x_j)=sigma^2 * exp(-1/(2*l^2) * (x_i - x_j) ^2) where, sigma=7, l=100 I used, v - c(700, 800, 1029) corr.matrix(cbind(v),scales=0.5) [,1] [,2] [,3] [1,]100 [2,]010 [3,]001 the output should be covariance matrix = [49, 29.7, 0.02; 29.7, 49, 3.6; 0.2, 3.6, 49] On Sun, Nov 2, 2014 at 7:04 PM, Jeff Newmiller jdnew...@dcn.davis.ca.us wrote: What is your question? The matrix form is probably what you are looking for, but you put the same vector in three times so if course it is all ones. I don't know what you expected to happen when you entered cor(v) since there is nothing to correlate if you only have one vector. Please post in plain text as the footer and Posting Guide request. --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On November 2, 2014 3:30:14 PM PST, C W tmrs...@gmail.com wrote: Hi list, I have trying to calculate the covariance/correlation of three elements. I have vector say, v - c(700, 800, 1000) I want to have a 3 by 3 correlation matrix, meaning cor(v1, c2), cor(v1, c3), cor(v2, v3), etc... So far I get, cor(v) Error in cor(v) : supply both 'x' and 'y' or a matrix-like 'x' vvv - cbind(v, v, v) cor(vvv) v v v v 1 1 1 v 1 1 1 v 1 1 1 I am calculating squared exponential kernel as seen here. http://mlg.eng.cam.ac.uk/duvenaud/cookbook/index.html Thanks a bunch, Mike [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to calculate correlation of a vector in R?
k - sigma^2 * exp( -1/(2*l^2) * outer( v,v,FUN=function(x,y){(x-y)^2}))
but perhaps you should look at the e1071 package instead?
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/BatteriesO.O#. #.O#. with
/Software/Embedded Controllers) .OO#. .OO#. rocks...1k
---
Sent from my phone. Please excuse my brevity.
On November 2, 2014 4:19:56 PM PST, C W tmrs...@gmail.com wrote:
Thanks, Jeff. I had some misunderstanding.
So, I want to calculate the squared exponential of vector v
v = c(700, 800, 1029)
formula is:
k(x_i, x_j)=sigma^2 * exp(-1/(2*l^2) * (x_i - x_j) ^2)
where,
sigma=7, l=100
I used,
v - c(700, 800, 1029)
corr.matrix(cbind(v),scales=0.5)
[,1] [,2] [,3]
[1,]100
[2,]010
[3,]001
the output should be covariance matrix = [49, 29.7, 0.02; 29.7, 49,
3.6;
0.2, 3.6, 49]
On Sun, Nov 2, 2014 at 7:04 PM, Jeff Newmiller
jdnew...@dcn.davis.ca.us
wrote:
What is your question? The matrix form is probably what you are
looking
for, but you put the same vector in three times so if course it is
all
ones. I don't know what you expected to happen when you entered
cor(v)
since there is nothing to correlate if you only have one vector.
Please post in plain text as the footer and Posting Guide request.
---
Jeff NewmillerThe . . Go
Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live
Go...
Live: OO#.. Dead: OO#..
Playing
Research Engineer (Solar/BatteriesO.O#. #.O#. with
/Software/Embedded Controllers) .OO#. .OO#.
rocks...1k
---
Sent from my phone. Please excuse my brevity.
On November 2, 2014 3:30:14 PM PST, C W tmrs...@gmail.com wrote:
Hi list,
I have trying to calculate the covariance/correlation of three
elements. I
have vector say,
v - c(700, 800, 1000)
I want to have a 3 by 3 correlation matrix, meaning cor(v1, c2),
cor(v1,
c3), cor(v2, v3), etc...
So far I get,
cor(v)
Error in cor(v) : supply both 'x' and 'y' or a matrix-like 'x'
vvv - cbind(v, v, v)
cor(vvv)
v v v
v 1 1 1
v 1 1 1
v 1 1 1
I am calculating squared exponential kernel as seen here.
http://mlg.eng.cam.ac.uk/duvenaud/cookbook/index.html
Thanks a bunch,
Mike
[[alternative HTML version deleted]]
__
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Finding MLE
Thanks Bert for the reply. I still get a message when adding the start
argument.
n - 8
x0 - c(2,3)
ll- function(a,b,x=x0,size=n){
+
-sum(log(gamma((n-1)/2+a-1)/(gamma((n-1)/2)*gamma(a))*1/(2*b^a)*(x/2)^((n-1)/2-1)*(1/b+x/2)^(-((n-1)/2+a-1}
fit - mle(ll, start=list(a=3, b=1), nobs = length(x0))
Error in validObject(.Object) :
invalid class “mle” object: invalid object for slot fullcoef in class
mle: got class list, should be or extend class numeric
2014-11-02 14:57 GMT-05:00 Bert Gunter gunter.ber...@gene.com:
You do not appear to provide initial values for a and b , i.e. the
start argument for mle.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
Clifford Stoll
On Sun, Nov 2, 2014 at 10:36 AM, li li hannah@gmail.com wrote:
Hi all,
I am trying to use the mle function in R to find the maximum likelihood
estimator. The ll function below is the negative of the log likelihood.
Suppose x0 is the observed values, I want to find the maximum likelihood
for a and b. After running the code below, I get the error message Error
in eval(expr, envir, enclos) : argument is missing, with no default.
Could anyone familiar with this function give some suggetion? Thanks
very
much!
Hanna
n - 8
x0 - c(2,3)
ll- function(a,b,x=x0,size=n){
+
-sum(log(gamma((n-1)/2+a-1)/(gamma((n-1)/2)*gamma(a))*1/(2*b^a)*(x/2)^((n-1)/2-1)*(1/b+x/2)^(-((n-1)/2+a-1}
fit - mle(ll, nobs = length(x0))
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
http://www.r-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
__
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] Finding MLE
I think I made an error in my funciton. Now it works.
library(stats4)
n - 8
ll- function(a,b,x){
-sum(log(gamma((n-1)/2+a-1)/(gamma((n-1)/2)*gamma(a))*1/(2*b^a)*(x/2)^((n-1)/2-1)*(1/b+x/2)^(-((n-1)/2+a-1}
fit - mle(ll, start=list(a=3, b=1), fixed=list(x=c(2,3)))
2014-11-02 22:04 GMT-05:00 li li hannah@gmail.com:
Thanks Bert for the reply. I still get a message when adding the start
argument.
n - 8
x0 - c(2,3)
ll- function(a,b,x=x0,size=n){
+
-sum(log(gamma((n-1)/2+a-1)/(gamma((n-1)/2)*gamma(a))*1/(2*b^a)*(x/2)^((n-1)/2-1)*(1/b+x/2)^(-((n-1)/2+a-1}
fit - mle(ll, start=list(a=3, b=1), nobs = length(x0))
Error in validObject(.Object) :
invalid class “mle” object: invalid object for slot fullcoef in class
mle: got class list, should be or extend class numeric
2014-11-02 14:57 GMT-05:00 Bert Gunter gunter.ber...@gene.com:
You do not appear to provide initial values for a and b , i.e. the
start argument for mle.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
Clifford Stoll
On Sun, Nov 2, 2014 at 10:36 AM, li li hannah@gmail.com wrote:
Hi all,
I am trying to use the mle function in R to find the maximum
likelihood
estimator. The ll function below is the negative of the log likelihood.
Suppose x0 is the observed values, I want to find the maximum likelihood
for a and b. After running the code below, I get the error message
Error
in eval(expr, envir, enclos) : argument is missing, with no default.
Could anyone familiar with this function give some suggetion? Thanks
very
much!
Hanna
n - 8
x0 - c(2,3)
ll- function(a,b,x=x0,size=n){
+
-sum(log(gamma((n-1)/2+a-1)/(gamma((n-1)/2)*gamma(a))*1/(2*b^a)*(x/2)^((n-1)/2-1)*(1/b+x/2)^(-((n-1)/2+a-1}
fit - mle(ll, nobs = length(x0))
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
http://www.r-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] treating missing values in timeSeries package
On Nov 1, 2014, at 2:58 AM, Upananda Pani wrote: Dear All, I am getting the following error when i am using interpNA function from timeSeries package # Missing Value Treatment (Linear Interpolation) spt = interpNA(spt, method = c(linear)) Error in interpNA(spt, method = c(linear)) : spt is not a tis object It puzzles me why you have not investigated an error message that seems quite informative. When I looked at the code of timeSeries::interpNA I was puzzled that the package seems to use timeSeries as the class name. This error reports a different class name, but it does seem that the function is designed to take only a particular set of intputs and yours fails that test. fut = interpNA(fut, method = c(linear)) Error in interpNA(fut, method = c(linear)) : fut is not a tis object spt = ts(spt, start=c(2006,4), frequency=305) fut = ts(fut, start=c(2006,4), frequency=305) spt = interpNA(spt, method = c(linear)) So the lack of an error here suggests that a ts-object might be acceptable to the same function that you were asking about. -- David. Would you please help me in this regard. With sincere regards, Upananda -- You may delay, but time will not. Research Scholar alternative mail id: up...@iitkgp.ac.in Department of HSS, IIT KGP KGP __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
