Re: [R] Compressing code help in a loop
Hi
slightly more general if first number is quarter and last two are year
index - c(406, 107, 207, 307, 407, 108, 208, 308, 408, 109, 209, 309, 409,
+ 110, 210, 310, 410, 111, 211)
year-substr(as.character(index), 2,3)
qrt-substr(as.character(index), 1,1)
as.numeric(factor(paste(year, qrt, sep=-)))
[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
qyTOindex - function(x) {
year - substr(as.character(x), 2,3)
qrt - substr(as.character(x), 1,1)
result -as.numeric(factor(paste(year, qrt, sep=-)))
}
qyTOindex(p_int$p_made)
Regards
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Wush Wu
Sent: Monday, November 10, 2014 2:30 PM
To: Francesca
Cc: R help
Subject: Re: [R] Compressing code help in a loop
Dear Francesca,
Is this what you want?
```r
index - c(406, 107, 207, 307, 407, 108, 208, 308, 408, 109, 209, 309,
409,
110, 210, 310, 410, 111, 211)
p_m - match( p_int$p_made, index)
dim(p_m) - c(dim(p_int)[1],1)
```
Best,
Wush
PhD Student Graduate Institute of Electrical Engineering, National
Taiwan
University
2014-11-10 20:14 GMT+08:00 Francesca francesca.panco...@gmail.com:
Dear Contributors
I have a problem with a loop.
I needed to create a variable that takes values 1,2.. to 19
corresponding
to the value of a variable in a data.frame whose name is p_int$p_made
and
which takes values from 406 to 211.
The problem is that this values come ordered in the wrong way when I
try to
compress the loop as the system reads
107,111,207,211,311,406,407,408,409,410,411,
while they correspond to quarters-years so they should be ordered as
406-107-207-307-407…
the only solution I found was really silly. It is the following.
p_m-matrix(0,dim(p_int)[1],1)
for (i in 1:length(p_int$p_made)){
if (p_int$p_made[i]==406) p_m[i]-1 else
if (p_int$p_made[i]==107) p_m[i]-2 else
if (p_int$p_made[i]==207) p_m[i]-3 else
if (p_int$p_made[i]==307) p_m[i]-4 else
if (p_int$p_made[i]==407) p_m[i]-5 else
if (p_int$p_made[i]==108) p_m[i]-6 else
if (p_int$p_made[i]==208) p_m[i]-7 else
if (p_int$p_made[i]==308) p_m[i]-8 else
if (p_int$p_made[i]==408) p_m[i]-9 else
if (p_int$p_made[i]==109) p_m[i]-10 else
if (p_int$p_made[i]==209) p_m[i]-11 else
if (p_int$p_made[i]==309) p_m[i]-12 else
if (p_int$p_made[i]==409) p_m[i]-13 else
if (p_int$p_made[i]==110) p_m[i]-14 else
if (p_int$p_made[i]==210) p_m[i]-15
else
if (p_int$p_made[i]==310) p_m[i]-16
else
if (p_int$p_made[i]==410) p_m[i]-
17 else
if (p_int$p_made[i]==111)
p_m[i]-18
else
if (p_int$p_made[i]==211)
p_m[i]-19
}
Can anyone help to find something more efficient?
Thanks in advance.
Francesca
--
Francesca
--
Francesca Pancotto
Associate Professor
University of Modena and Reggio Emilia
Viale A. Allegri, 9
40121 Reggio Emilia
Office: +39 0522 523264
Web: https://sites.google.com/site/francescapancotto/
--
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[R] factor levels numeric values
Hi everybody, I have another question (to which I could not find an answer in my r-books. I am sure, it's not a great issue, but I simply lack of a good idea how to solve this: One of my variables gets imported as a factor instead of a numeric variable. Now I have a... Factor w/ 63 levels 0,0.02,0.03,..: 1 NA NA 1 NA NA 1 1 53 10 ... How can I transform these factor levels into actual values? Thank you very much for any help! David [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] factor levels numeric values
Hello, David, take a look at the beginning of the Warning section of ?factor. Hth -- Gerrit Hi everybody, I have another question (to which I could not find an answer in my r-books. I am sure, it's not a great issue, but I simply lack of a good idea how to solve this: One of my variables gets imported as a factor instead of a numeric variable. Now I have a... Factor w/ 63 levels 0,0.02,0.03,..: 1 NA NA 1 NA NA 1 1 53 10 ... How can I transform these factor levels into actual values? Thank you very much for any help! David [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Submodel selection using dredge and gam (mgcv)
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Re: [R] factor levels numeric values
Also look at the Frequently Asked Questions document that comes with your R installation: 7.10 How do I convert factors to numeric? It may happen that when reading numeric data into R (usually, when reading in a file), they come in as factors. If f is such a factor object, you can use as.numeric(as.character(f)) to get the numbers back. More efficient, but harder to remember, is as.numeric(levels(f))[as.integer(f)] In any case, do not call as.numeric() or their likes directly for the task at hand (as as.numeric() or unclass() give the internal codes). - David L Carlson Department of Anthropology Texas AM University College Station, TX 77840-4352 -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Gerrit Eichner Sent: Wednesday, November 12, 2014 8:06 AM To: David Studer Cc: r-help@r-project.org Subject: Re: [R] factor levels numeric values Hello, David, take a look at the beginning of the Warning section of ?factor. Hth -- Gerrit Hi everybody, I have another question (to which I could not find an answer in my r-books. I am sure, it's not a great issue, but I simply lack of a good idea how to solve this: One of my variables gets imported as a factor instead of a numeric variable. Now I have a... Factor w/ 63 levels 0,0.02,0.03,..: 1 NA NA 1 NA NA 1 1 53 10 ... How can I transform these factor levels into actual values? Thank you very much for any help! David [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R memory issues
you may try to increase virtual memory : http://windows.microsoft.com/en-us/windows/change-virtual-memory-size#1TC=windows-7 -Original Message- From: eliza botto [eliza_bo...@hotmail.com] Date: 11/11/2014 02:35 PM To: r-help@r-project.org r-help@r-project.org Subject: [R] R memory issues Dear useRs, I have this funny thing going on with me since morning. I am 32 bit window 7 system with 4 GB RAM(2.95 usable). I tried to run a code on it but when I tried to convert dataframe to matrix by using the following code mat-matrix(as.numeric(unlist(SFI)),nrow=nrow(SFI)) *where SFI is my dataframe. an error came up, Error: cannot allocate vector of size 237.3 Mb I tried to increase memory by using memory.limit(2500) but to no effect. Kindly help me out on it as you always do. Thanks, Eliza [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] factor levels numeric values
I have not completely followed the discussion, so excuse me if it was already pointed out. If numeric data are read as factors, this means that there are not only numeric data in the column. It could be an empty space somewhere, or some character that should be NA, or... I think it is worth spending some time searching for the typo so that the file will be read correctly in R. HTH, Ivan -- Ivan Calandra, ATER University of Reims Champagne-Ardenne GEGENA² - EA 3795 CREA - 2 esplanade Roland Garros 51100 Reims, France +33(0)3 26 77 36 89 ivan.calan...@univ-reims.fr https://www.researchgate.net/profile/Ivan_Calandra Le 12/11/14 15:56, David L Carlson a écrit : Also look at the Frequently Asked Questions document that comes with your R installation: 7.10 How do I convert factors to numeric? It may happen that when reading numeric data into R (usually, when reading in a file), they come in as factors. If f is such a factor object, you can use as.numeric(as.character(f)) to get the numbers back. More efficient, but harder to remember, is as.numeric(levels(f))[as.integer(f)] In any case, do not call as.numeric() or their likes directly for the task at hand (as as.numeric() or unclass() give the internal codes). - David L Carlson Department of Anthropology Texas AM University College Station, TX 77840-4352 -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Gerrit Eichner Sent: Wednesday, November 12, 2014 8:06 AM To: David Studer Cc: r-help@r-project.org Subject: Re: [R] factor levels numeric values Hello, David, take a look at the beginning of the Warning section of ?factor. Hth -- Gerrit Hi everybody, I have another question (to which I could not find an answer in my r-books. I am sure, it's not a great issue, but I simply lack of a good idea how to solve this: One of my variables gets imported as a factor instead of a numeric variable. Now I have a... Factor w/ 63 levels 0,0.02,0.03,..: 1 NA NA 1 NA NA 1 1 53 10 ... How can I transform these factor levels into actual values? Thank you very much for any help! David [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Compilation error: Rcpp and related packages - record-gcc-switches missing
Hello, I encountered problem with Linux machine (openSUSE, 3.1.1. version of R) while I tried to update the packages with update.packages(). Rcpp, RcppArmadillo and RcppEigen refused to compile because record-gcc-swtiches was missing. I don't know much about compiling and such so I didn't get any further with the problem. Enquiries to Rcpp and openSUSE experts have not solved my problem. What I learned was that -frecord-gcc-switches might be mispelled somewhere. That information did not help me to find solution. If anyone could help with this problem I would we very thankful. See the log and SessionInfo() below for more detail: Rcpp : Version 0.11.2 installed in /home/antti/R/x86_64-suse-linux-gnu-library/3.1 Version 0.11.3 available at http://ftp.eenet.ee/pub/cran Update (y/N/c)? y RcppArmadillo : Version 0.4.320.0 installed in /home/antti/R/x86_64-suse-linux-gnu-library/3.1 Version 0.4.450.1.0 available at http://ftp.eenet.ee/pub/cran Update (y/N/c)? y RcppEigen : Version 0.3.2.1.2 installed in /home/antti/R/x86_64-suse-linux-gnu-library/3.1 Version 0.3.2.2.0 available at http://ftp.eenet.ee/pub/cran Update (y/N/c)? y trying URL 'http://ftp.eenet.ee/pub/cran/src/con..._0.11.3.tar.gz http://ftp.eenet.ee/pub/cran/src/contrib/Rcpp_0.11.3.tar.gz' Content type 'application/x-tar' length 2169583 bytes (2.1 Mb) opened URL == downloaded 2.1 Mb trying URL 'http://ftp.eenet.ee/pub/cran/src/con...450.1.0.tar.gz http://ftp.eenet.ee/pub/cran/src/contrib/RcppArmadillo_0.4.450.1.0.tar.gz' Content type 'application/x-tar' length 931597 bytes (909 Kb) opened URL == downloaded 909 Kb trying URL 'http://ftp.eenet.ee/pub/cran/src/con...3.2.2.0.tar.gz http://ftp.eenet.ee/pub/cran/src/contrib/RcppEigen_0.3.2.2.0.tar.gz' Content type 'application/x-tar' length 1216536 bytes (1.2 Mb) opened URL == downloaded 1.2 Mb * installing *source* package ‘Rcpp’ ... ** package ‘Rcpp’ successfully unpacked and MD5 sums checked ** libs g++ -I/usr/lib64/R/include -I../inst/include/ -I/usr/local/include -fpic -fmessage-length=0 record-gcc-switches -fstack-protector -O3 -Wall -D_FORTIFY_SOURCE=2 -funwind-tables -fasynchronous-unwind-tables -c Date.cpp -o Date.o g++: error: record-gcc-switches: No such file or directory make: *** [Date.o] Error 1 ERROR: compilation failed for package ‘Rcpp’ * removing ‘/home/antti/R/x86_64-suse-linux-gnu-library/3.1/Rcpp’ * restoring previous ‘/home/antti/R/x86_64-suse-linux-gnu-library/3.1/Rcpp’ * installing *source* package ‘RcppArmadillo’ ... ** package ‘RcppArmadillo’ successfully unpacked and MD5 sums checked * checking LAPACK_LIBS: divide-and-conquer complex SVD available via R-supplied LAPACK ** libs g++ -I/usr/lib64/R/include -I/usr/local/include -I/home/antti/R/x86_64-suse-linux-gnu-library/3.1/Rcpp/include -I../inst/include -fpic -fmessage-length=0 record-gcc-switches -fstack-protector -O3 -Wall -D_FORTIFY_SOURCE=2 -funwind-tables -fasynchronous-unwind-tables -c RcppArmadillo.cpp -o RcppArmadillo.o g++: error: record-gcc-switches: No such file or directory make: *** [RcppArmadillo.o] Error 1 ERROR: compilation failed for package ‘RcppArmadillo’ * removing ‘/home/antti/R/x86_64-suse-linux-gnu-library/3.1/RcppArmadillo’ * restoring previous ‘/home/antti/R/x86_64-suse-linux-gnu-library/3.1/RcppArmadillo’ * installing *source* package ‘RcppEigen’ ... ** package ‘RcppEigen’ successfully unpacked and MD5 sums checked ** libs g++ -I/usr/lib64/R/include -I/usr/local/include -I/home/antti/R/x86_64-suse-linux-gnu-library/3.1/Rcpp/include -I../inst/include -fpic -fmessage-length=0 record-gcc-switches -fstack-protector -O3 -Wall -D_FORTIFY_SOURCE=2 -funwind-tables -fasynchronous-unwind-tables -c RcppEigen.cpp -o RcppEigen.o g++: error: record-gcc-switches: No such file or directory make: *** [RcppEigen.o] Error 1 ERROR: compilation failed for package ‘RcppEigen’ * removing ‘/home/antti/R/x86_64-suse-linux-gnu-library/3.1/RcppEigen’ * restoring previous ‘/home/antti/R/x86_64-suse-linux-gnu-library/3.1/RcppEigen’ The downloaded source packages are in ‘/tmp/Rtmpnx5dfE/downloaded_packages’ Warning messages: 1: In install.packages(update[instlib == l, Package], l, contriburl = contriburl, : installation of package ‘Rcpp’ had non-zero exit status 2: In install.packages(update[instlib == l, Package], l, contriburl = contriburl, : installation of package ‘RcppArmadillo’ had non-zero exit status 3: In install.packages(update[instlib == l, Package], l, contriburl = contriburl, : installation of package ‘RcppEigen’ had non-zero exit status sessionInfo() R version 3.1.1 (2014-07-10) Platform: x86_64-suse-linux-gnu (64-bit) locale: [1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C [3] LC_TIME=en_US.UTF-8 LC_COLLATE=en_US.UTF-8 [5] LC_MONETARY=en_US.UTF-8 LC_MESSAGES=en_US.UTF-8 [7] LC_PAPER=en_US.UTF-8 LC_NAME=C [9] LC_ADDRESS=C LC_TELEPHONE=C [11] LC_MEASUREMENT=en_US.UTF-8
Re: [R] factor levels numeric values
Another approach is to re-import your data using options that do not put the data into a factor in the first place. For example you can use the colClasses parameter in the read.table family of functions to specify numeric for that column. If you need to give special handling to that column anyway (using strong functions) then you can use the stringsAsFactors=FALSE or as.is=TRUE parameter settings and avoid the as.character() band-aid in your code. --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. On November 12, 2014 6:56:11 AM PST, David L Carlson dcarl...@tamu.edu wrote: Also look at the Frequently Asked Questions document that comes with your R installation: 7.10 How do I convert factors to numeric? It may happen that when reading numeric data into R (usually, when reading in a file), they come in as factors. If f is such a factor object, you can use as.numeric(as.character(f)) to get the numbers back. More efficient, but harder to remember, is as.numeric(levels(f))[as.integer(f)] In any case, do not call as.numeric() or their likes directly for the task at hand (as as.numeric() or unclass() give the internal codes). - David L Carlson Department of Anthropology Texas AM University College Station, TX 77840-4352 -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Gerrit Eichner Sent: Wednesday, November 12, 2014 8:06 AM To: David Studer Cc: r-help@r-project.org Subject: Re: [R] factor levels numeric values Hello, David, take a look at the beginning of the Warning section of ?factor. Hth -- Gerrit Hi everybody, I have another question (to which I could not find an answer in my r-books. I am sure, it's not a great issue, but I simply lack of a good idea how to solve this: One of my variables gets imported as a factor instead of a numeric variable. Now I have a... Factor w/ 63 levels 0,0.02,0.03,..: 1 NA NA 1 NA NA 1 1 53 10 ... How can I transform these factor levels into actual values? Thank you very much for any help! David [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R memory issues
On 12/11/2014 15:18, ce wrote: you may try to increase virtual memory : http://windows.microsoft.com/en-us/windows/change-virtual-memory-size#1TC=windows-7 That is a very low plausibility for the error. See the discussion in the FAQ: http://cran.r-project.org/bin/windows/base/rw-FAQ.html#There-seems-to-be-a-limit-on-the-memory-it-uses_0021 and the discussion of fragmentation in ?Memory-limits . As others have said: get a 64-bit OS -- the only 32-bit one I have seen for several years now is on an old Windows sub-notebook with an Atom CPU. -Original Message- From: eliza botto [eliza_bo...@hotmail.com] Date: 11/11/2014 02:35 PM To: r-help@r-project.org r-help@r-project.org Subject: [R] R memory issues Dear useRs, I have this funny thing going on with me since morning. I am 32 bit window 7 system with 4 GB RAM(2.95 usable). I tried to run a code on it but when I tried to convert dataframe to matrix by using the following code mat-matrix(as.numeric(unlist(SFI)),nrow=nrow(SFI)) *where SFI is my dataframe. an error came up, Error: cannot allocate vector of size 237.3 Mb I tried to increase memory by using memory.limit(2500) but to no effect. Kindly help me out on it as you always do. Thanks, Eliza [[alternative HTML version deleted]] -- Brian D. Ripley, rip...@stats.ox.ac.uk Emeritus Professor of Applied Statistics, University of Oxford 1 South Parks Road, Oxford OX1 3TG, UK __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] tapply error svyby function survey package
Hi.
I'm trying to calculate the weighted mean score of a quality of life
measure (ovt) in patients with irritable bowel syndrome by their
marital status (d7).
This is a summary of the structure of the dataset:
str(sii.tesis)
'data.frame':1063 obs. of 75 variables:
$ id : int 51 52 53 54 55 56 57 58 59 60 ...
$ stratum: Factor w/ 6 levels MEst,MAcad,..: 1 4 NA 4 4 1 6 NA 4 4 ...
$ expfc : num 22.8 17.1 NA 17.1 17.1 ...
$ d6 : Factor w/ 3 levels Estudiante,Profesor,..: 1 1 NA
1 1 1 3 NA 1 1 ...
$ d7 : Factor w/ 6 levels Soltero,Casado,..: 1 1 NA 1 1 1
1 NA 1 1 ...
$ d7c: Factor w/ 2 levels No estable,Estable: 1 1 NA 1 1
1 1 NA 1 1 ...
$ s1cm : Factor w/ 2 levels No,Si: 1 2 NA 1 1 1 2 NA 1 1 ...
$ ovt: num NA 93.4 NA NA NA ...
I declared the sampling design:
sii.design - svydesign(
id = ~1,
strata = ~stratum,
weights = ~expfc,
data = subset(sii.tesis, !is.na(stratum)))
Then I tried to get the result:
svyby(~ovt, ~d7, sii.design, svymean, na.rm = TRUE, level = 0.95)
but i get the error:
Error in tapply(1:NROW(x), list(factor(strata)), function(index) { :
arguments must have same length
The length of both variables is the same. If the variable ovt exists,
there is a d7 match in the data frame.
I try the same thing using another variable instead - role (d6) -
and it works.
svyby(~ovt, ~d6, sii.design, svymean, na.rm = TRUE, level = 0.95)
d6 ovt se
Estudiante Estudiante 71.01805 1.370569
Profesor Profesor 72.30923 6.518378
Administrativo Administrativo 75.69102 3.715050
If I use the recategorized d7 variable (d7c, two levels only) it works too:
svyby(~ovt, ~d7c, sii.design, svymean, na.rm = TRUE, level = 0.95)
d7c ovt se
No estable No estable 70.92344 1.37460
Estable Estable 74.53719 4.16954
What could be the problem?
Regards.
Martin Canon
Colombia, South America
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] tapply error svyby function survey package
try resetting your levels? if that doesn't work, please dput() an example
data set that we can test with :) thanks!
sii.design - update( sii.design , d6 = factor( d6 ) )
On Wed, Nov 12, 2014 at 7:59 AM, Martin Canon martin.ca...@gmail.com
wrote:
Hi.
I'm trying to calculate the weighted mean score of a quality of life
measure (ovt) in patients with irritable bowel syndrome by their
marital status (d7).
This is a summary of the structure of the dataset:
str(sii.tesis)
'data.frame':1063 obs. of 75 variables:
$ id : int 51 52 53 54 55 56 57 58 59 60 ...
$ stratum: Factor w/ 6 levels MEst,MAcad,..: 1 4 NA 4 4 1 6 NA 4
4 ...
$ expfc : num 22.8 17.1 NA 17.1 17.1 ...
$ d6 : Factor w/ 3 levels Estudiante,Profesor,..: 1 1 NA
1 1 1 3 NA 1 1 ...
$ d7 : Factor w/ 6 levels Soltero,Casado,..: 1 1 NA 1 1 1
1 NA 1 1 ...
$ d7c: Factor w/ 2 levels No estable,Estable: 1 1 NA 1 1
1 1 NA 1 1 ...
$ s1cm : Factor w/ 2 levels No,Si: 1 2 NA 1 1 1 2 NA 1 1 ...
$ ovt: num NA 93.4 NA NA NA ...
I declared the sampling design:
sii.design - svydesign(
id = ~1,
strata = ~stratum,
weights = ~expfc,
data = subset(sii.tesis, !is.na(stratum)))
Then I tried to get the result:
svyby(~ovt, ~d7, sii.design, svymean, na.rm = TRUE, level = 0.95)
but i get the error:
Error in tapply(1:NROW(x), list(factor(strata)), function(index) { :
arguments must have same length
The length of both variables is the same. If the variable ovt exists,
there is a d7 match in the data frame.
I try the same thing using another variable instead - role (d6) -
and it works.
svyby(~ovt, ~d6, sii.design, svymean, na.rm = TRUE, level = 0.95)
d6 ovt se
Estudiante Estudiante 71.01805 1.370569
Profesor Profesor 72.30923 6.518378
Administrativo Administrativo 75.69102 3.715050
If I use the recategorized d7 variable (d7c, two levels only) it works
too:
svyby(~ovt, ~d7c, sii.design, svymean, na.rm = TRUE, level = 0.95)
d7c ovt se
No estable No estable 70.92344 1.37460
Estable Estable 74.53719 4.16954
What could be the problem?
Regards.
Martin Canon
Colombia, South America
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Submodel selection using dredge and gam (mgcv)
Hi Arnaud, please read ?dredge - Details - Subsetting, where this is explained. On 2014-11-12 15:19, Arnaud Mosnier wrote: Hi Kamil, Thanks for your answer. In fact, I already tried something with operators in such a way you advise, but it seems more complicated due to the use of the s() and ti() operators. Can you provide a solution for the following example ? library(mgcv) set.seed(2) dat - gamSim(1,n=400,dist=normal,scale=2) bt - gam(y~s(x0)+s(x1)+ti(x0,x1), data=dat,method=ML) library(MuMIn) # this does not work dredge(bt, subset = (!(x0,x1) | (x0 x1))) dredge(bt, subset = (!ti(x0,x1) | (s(x0) s(x1 Cheers, Arnaud 2014-11-11 4:11 GMT-05:00 Kamil Bartoń kamil.bar...@o2.pl mailto:kamil.bar...@o2.pl: Hi Arnaud, your question has in fact nothing to do with gam or model selection. What you are asking is: what is the logical expression that yields True when AB is False or both A and B are True. Now replace the words with operators (!AB | (A B)) and voilà. See also: help(Logic, base) fortunes::fortune(350) best, kamil On 2014-11-10 21:26, Arnaud Mosnier wrote: Hi, I want to use dredge to test several gam submodels including interactions. I tried to find a way in order to keep models with interaction only if the single variables occurring in the interaction are also included. i.e.: for y~s(x0)+s(x1)+ti(x0, x1) I want to keep y ~ s(x0) y ~ s(x1) y ~ s(x0) + s(x1) y ~ s(x0) + s(x1) + ti(x0,x1) and I want to remove y ~ s(x0) + ti(x0,x1) y ~ s(x1) + ti(x0,x1) y ~ ti(x0,x1) I know that I should use the subset option of the dredge function. However, I can not find the correct matrix / expression to obtain what I need ! Here a small example. # Create some data (use mgcv example) library(mgcv) set.seed(2) dat - gamSim(1,n=400,dist=normal,__scale=2) # Create the global gam model # Here a model with interaction. Note the use of ti() bt - gam(y~s(x0)+s(x1)+s(x2)+s(x3)+__ti(x1,x2), data=dat,method=ML) # Use dredge to test sub-models library(MuMIn) print(modstab - dredge(bt)) # Here the 11th model include the interaction but do not include the single variables x1 and x2 # ... I want to avoid that kind of model. get.models(modstab, subset = 11) Any help would be appreciated ! Arnaud __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] tapply error svyby function survey package
hi martin, sending the first 25 rows does not help if it does not re-create the problem.. when i run the data you have provided, i do not encounter your problem (see below). someone else may be able to guess the issue, but this would be a lot easier to solve if you can create a minimal reproducible example http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example sii.tesis - structure(list(id = c(51L, 52L, 53L, 54L, 55L, 56L, 57L, 58L, 59L, 60L, 61L, 62L, 63L, 64L, 65L, 66L, 67L, 68L, 69L, 70L, 71L, 73L, 74L, 75L, 76L), stratum = structure(c(1L, 4L, NA, 4L, 4L, 1L, 6L, NA, 4L, 4L, 1L, 1L, 1L, 6L, 6L, 3L, 3L, 6L, NA, 1L, 1L, 6L, 4L, 3L, 6L), .Label = c(MEst, MAcad, MAdm, FEst, FAcad, FAdm), class = factor), expfc = c(22.8195266723633, 17.0644626617432, NA, 17.0644626617432, 17.0644626617432, 22.8195266723633, 5.1702127456665, NA, 17.0644626617432, 17.0644626617432, 22.8195266723633, 22.8195266723633, 22.8195266723633, 5.1702127456665, 5.1702127456665, 6.24137926101685, 6.24137926101685, 5.1702127456665, NA, 22.8195266723633, 22.8195266723633, 5.1702127456665, 17.0644626617432, 6.24137926101685, 5.1702127456665), d7 = structure(c(1L, 1L, NA, 1L, 1L, 1L, 1L, NA, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, NA, 1L, 1L, 6L, 1L, 6L, 6L), .Label = c(Soltero, Casado, Separado, Divorciado, Viudo, Union libre), class = factor), ovt = c(NA, 93.3823547363281, NA, NA, NA, NA, 83.8235321044922, NA, NA, NA, NA, NA, NA, NA, 79.4117660522461, NA, NA, 19.1176471710205, NA, NA, NA, 85.2941207885742, NA, NA, NA)), .Names = c(id, stratum, expfc, d7, ovt ), row.names = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25), class = data.frame) sii.design - svydesign( id = ~1, strata = ~stratum, weights = ~expfc, data = subset(sii.tesis, !is.na(stratum))) svyby(~ovt, ~d7, sii.design, svymean, na.rm = TRUE, level = 0.95) # works fine--- svyby(~ovt, ~d7, sii.design, svymean, na.rm = TRUE, level = 0.95) d7 ovt se Soltero Soltero 88.94329 3.333485 Casado Casado 19.11765 0.00 Union libre Union libre 85.29412 0.00 On Wed, Nov 12, 2014 at 5:25 PM, Martin Canon martin.ca...@gmail.com wrote: Anthony, thanks for your reply. Resetting the levels didn't work. These are the first 25 rows of the dataset: structure(list(id = c(51L, 52L, 53L, 54L, 55L, 56L, 57L, 58L, 59L, 60L, 61L, 62L, 63L, 64L, 65L, 66L, 67L, 68L, 69L, 70L, 71L, 73L, 74L, 75L, 76L), stratum = structure(c(1L, 4L, NA, 4L, 4L, 1L, 6L, NA, 4L, 4L, 1L, 1L, 1L, 6L, 6L, 3L, 3L, 6L, NA, 1L, 1L, 6L, 4L, 3L, 6L), .Label = c(MEst, MAcad, MAdm, FEst, FAcad, FAdm), class = factor), expfc = c(22.8195266723633, 17.0644626617432, NA, 17.0644626617432, 17.0644626617432, 22.8195266723633, 5.1702127456665, NA, 17.0644626617432, 17.0644626617432, 22.8195266723633, 22.8195266723633, 22.8195266723633, 5.1702127456665, 5.1702127456665, 6.24137926101685, 6.24137926101685, 5.1702127456665, NA, 22.8195266723633, 22.8195266723633, 5.1702127456665, 17.0644626617432, 6.24137926101685, 5.1702127456665), d7 = structure(c(1L, 1L, NA, 1L, 1L, 1L, 1L, NA, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, NA, 1L, 1L, 6L, 1L, 6L, 6L), .Label = c(Soltero, Casado, Separado, Divorciado, Viudo, Union libre), class = factor), ovt = c(NA, 93.3823547363281, NA, NA, NA, NA, 83.8235321044922, NA, NA, NA, NA, NA, NA, NA, 79.4117660522461, NA, NA, 19.1176471710205, NA, NA, NA, 85.2941207885742, NA, NA, NA)), .Names = c(id, stratum, expfc, d7, ovt ), row.names = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25), class = data.frame) Regards. Martin On Wed, Nov 12, 2014 at 1:39 PM, Anthony Damico ajdam...@gmail.com wrote: try resetting your levels? if that doesn't work, please dput() an example data set that we can test with :) thanks! sii.design - update( sii.design , d6 = factor( d6 ) ) On Wed, Nov 12, 2014 at 7:59 AM, Martin Canon martin.ca...@gmail.com wrote: Hi. I'm trying to calculate the weighted mean score of a quality of life measure (ovt) in patients with irritable bowel syndrome by their marital status (d7). This is a summary of the structure of the dataset: str(sii.tesis) 'data.frame':1063 obs. of 75 variables: $ id : int 51 52 53 54 55 56 57 58 59 60 ... $ stratum: Factor w/ 6 levels MEst,MAcad,..: 1 4 NA 4 4 1 6 NA 4 4 ... $ expfc : num 22.8 17.1 NA 17.1 17.1 ... $ d6 : Factor w/ 3 levels Estudiante,Profesor,..: 1 1 NA 1 1 1 3 NA 1 1 ... $ d7 : Factor w/ 6 levels Soltero,Casado,..: 1 1 NA 1 1 1 1 NA 1 1 ... $ d7c: Factor w/ 2 levels No estable,Estable: 1 1 NA 1 1 1 1 NA 1 1 ... $ s1cm : Factor w/ 2 levels No,Si: 1 2 NA 1 1 1 2 NA 1 1 ... $ ovt: num NA 93.4 NA NA NA ... I declared the sampling design: sii.design - svydesign( id = ~1, strata =
Re: [R] Is it possible to define another kind of NA
Along the lines of what Bert Gunter said, the ideal way to represent LDL results depends on the functions used later to analyze them. I deal with such data on a daily basis and have never found it necessary to incorporate that information in the same variable as the results. What would you do if data were censored at both ends, both low and high? Anyway, the functions I use mostly incorporate that information in a second variable, a ³detection indicator² variable, and that¹s what I do. -Don -- Don MacQueen Lawrence Livermore National Laboratory 7000 East Ave., L-627 Livermore, CA 94550 925-423-1062 On 11/9/14, 10:07 AM, Marc Girondot marc_...@yahoo.fr wrote: Dear member list, In many experimental sciences, there is a lower detection limit (LDL) when a dosage of a product is done. Then some samples are evaluated to be below this limit. I search for the best way to indicate in a data.frame that some values are such LDL. Ideally, an equivalent of NA would be the best. Until now I manage by indicating all the column in characters. So the question is: is it possible to define a value that could be named LDL and that could take place in vectors or data.frame such as: v - c(0.2, 0.28, LDL, 0.9) is the same way that NA can be used. with of course a function is.ldl(v) that would return F F T F Thanks a lot for any direction to solve this Marc __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Synthestic Control Methods for Causal Inference
I am interested in conducting causal inference using synthetic control method using R where there are multiple treated units/regions. The current synth package allows only one treated unit to be compared to other (several) synthetic units. In my case, I have 5 treated units and 35 untreated units. Is there any package I have missed? I am currently doing a sequential analysis comparing each treated unit to the 35 untreated units. I would like to get a composite result. Any help will be appreciated. Sincerely, Peter Maclean Department of Economics UDSM __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Submodel selection using dredge and gam (mgcv)
Argh ! Ok ... my fault ... the use of back-ticks was the solution !!! Thanks, Arnaud 2014-11-12 14:19 GMT-05:00 Kamil Bartoń kamil.bar...@o2.pl: Hi Arnaud, please read ?dredge - Details - Subsetting, where this is explained. On 2014-11-12 15:19, Arnaud Mosnier wrote: Hi Kamil, Thanks for your answer. In fact, I already tried something with operators in such a way you advise, but it seems more complicated due to the use of the s() and ti() operators. Can you provide a solution for the following example ? library(mgcv) set.seed(2) dat - gamSim(1,n=400,dist=normal,scale=2) bt - gam(y~s(x0)+s(x1)+ti(x0,x1), data=dat,method=ML) library(MuMIn) # this does not work dredge(bt, subset = (!(x0,x1) | (x0 x1))) dredge(bt, subset = (!ti(x0,x1) | (s(x0) s(x1 Cheers, Arnaud 2014-11-11 4:11 GMT-05:00 Kamil Bartoń kamil.bar...@o2.pl mailto:kamil.bar...@o2.pl: Hi Arnaud, your question has in fact nothing to do with gam or model selection. What you are asking is: what is the logical expression that yields True when AB is False or both A and B are True. Now replace the words with operators (!AB | (A B)) and voilà. See also: help(Logic, base) fortunes::fortune(350) best, kamil On 2014-11-10 21:26, Arnaud Mosnier wrote: Hi, I want to use dredge to test several gam submodels including interactions. I tried to find a way in order to keep models with interaction only if the single variables occurring in the interaction are also included. i.e.: for y~s(x0)+s(x1)+ti(x0, x1) I want to keep y ~ s(x0) y ~ s(x1) y ~ s(x0) + s(x1) y ~ s(x0) + s(x1) + ti(x0,x1) and I want to remove y ~ s(x0) + ti(x0,x1) y ~ s(x1) + ti(x0,x1) y ~ ti(x0,x1) I know that I should use the subset option of the dredge function. However, I can not find the correct matrix / expression to obtain what I need ! Here a small example. # Create some data (use mgcv example) library(mgcv) set.seed(2) dat - gamSim(1,n=400,dist=normal,__scale=2) # Create the global gam model # Here a model with interaction. Note the use of ti() bt - gam(y~s(x0)+s(x1)+s(x2)+s(x3)+__ti(x1,x2), data=dat,method=ML) # Use dredge to test sub-models library(MuMIn) print(modstab - dredge(bt)) # Here the 11th model include the interaction but do not include the single variables x1 and x2 # ... I want to avoid that kind of model. get.models(modstab, subset = 11) Any help would be appreciated ! Arnaud [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] tapply error svyby function survey package
Anthony, thanks for your reply.
Resetting the levels didn't work.
These are the first 25 rows of the dataset:
structure(list(id = c(51L, 52L, 53L, 54L, 55L, 56L, 57L, 58L,
59L, 60L, 61L, 62L, 63L, 64L, 65L, 66L, 67L, 68L, 69L, 70L, 71L,
73L, 74L, 75L, 76L), stratum = structure(c(1L, 4L, NA, 4L, 4L,
1L, 6L, NA, 4L, 4L, 1L, 1L, 1L, 6L, 6L, 3L, 3L, 6L, NA, 1L, 1L,
6L, 4L, 3L, 6L), .Label = c(MEst, MAcad, MAdm, FEst,
FAcad, FAdm), class = factor), expfc = c(22.8195266723633,
17.0644626617432, NA, 17.0644626617432, 17.0644626617432, 22.8195266723633,
5.1702127456665, NA, 17.0644626617432, 17.0644626617432, 22.8195266723633,
22.8195266723633, 22.8195266723633, 5.1702127456665, 5.1702127456665,
6.24137926101685, 6.24137926101685, 5.1702127456665, NA, 22.8195266723633,
22.8195266723633, 5.1702127456665, 17.0644626617432, 6.24137926101685,
5.1702127456665), d7 = structure(c(1L, 1L, NA, 1L, 1L, 1L, 1L,
NA, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, NA, 1L, 1L, 6L, 1L,
6L, 6L), .Label = c(Soltero, Casado, Separado, Divorciado,
Viudo, Union libre), class = factor), ovt = c(NA, 93.3823547363281,
NA, NA, NA, NA, 83.8235321044922, NA, NA, NA, NA, NA, NA, NA,
79.4117660522461, NA, NA, 19.1176471710205, NA, NA, NA, 85.2941207885742,
NA, NA, NA)), .Names = c(id, stratum, expfc, d7, ovt
), row.names = c(1, 2, 3, 4, 5, 6, 7, 8, 9,
10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20,
21, 22, 23, 24, 25), class = data.frame)
Regards.
Martin
On Wed, Nov 12, 2014 at 1:39 PM, Anthony Damico ajdam...@gmail.com wrote:
try resetting your levels? if that doesn't work, please dput() an example
data set that we can test with :) thanks!
sii.design - update( sii.design , d6 = factor( d6 ) )
On Wed, Nov 12, 2014 at 7:59 AM, Martin Canon martin.ca...@gmail.com
wrote:
Hi.
I'm trying to calculate the weighted mean score of a quality of life
measure (ovt) in patients with irritable bowel syndrome by their
marital status (d7).
This is a summary of the structure of the dataset:
str(sii.tesis)
'data.frame':1063 obs. of 75 variables:
$ id : int 51 52 53 54 55 56 57 58 59 60 ...
$ stratum: Factor w/ 6 levels MEst,MAcad,..: 1 4 NA 4 4 1 6 NA 4
4 ...
$ expfc : num 22.8 17.1 NA 17.1 17.1 ...
$ d6 : Factor w/ 3 levels Estudiante,Profesor,..: 1 1 NA
1 1 1 3 NA 1 1 ...
$ d7 : Factor w/ 6 levels Soltero,Casado,..: 1 1 NA 1 1 1
1 NA 1 1 ...
$ d7c: Factor w/ 2 levels No estable,Estable: 1 1 NA 1 1
1 1 NA 1 1 ...
$ s1cm : Factor w/ 2 levels No,Si: 1 2 NA 1 1 1 2 NA 1 1 ...
$ ovt: num NA 93.4 NA NA NA ...
I declared the sampling design:
sii.design - svydesign(
id = ~1,
strata = ~stratum,
weights = ~expfc,
data = subset(sii.tesis, !is.na(stratum)))
Then I tried to get the result:
svyby(~ovt, ~d7, sii.design, svymean, na.rm = TRUE, level = 0.95)
but i get the error:
Error in tapply(1:NROW(x), list(factor(strata)), function(index) { :
arguments must have same length
The length of both variables is the same. If the variable ovt exists,
there is a d7 match in the data frame.
I try the same thing using another variable instead - role (d6) -
and it works.
svyby(~ovt, ~d6, sii.design, svymean, na.rm = TRUE, level = 0.95)
d6 ovt se
Estudiante Estudiante 71.01805 1.370569
Profesor Profesor 72.30923 6.518378
Administrativo Administrativo 75.69102 3.715050
If I use the recategorized d7 variable (d7c, two levels only) it works
too:
svyby(~ovt, ~d7c, sii.design, svymean, na.rm = TRUE, level = 0.95)
d7c ovt se
No estable No estable 70.92344 1.37460
Estable Estable 74.53719 4.16954
What could be the problem?
Regards.
Martin Canon
Colombia, South America
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] subset drops S3 classes?
Hi all --- I've stumbled upon some pretty annoying behavior, and I'm curious how others may have gotten around it. When using subset(...) on a data frame that contains a custom S3 field, the class is dropped in the result: MyClass - function(x) structure(x, class = MyClass) df - data.frame(x = 1:10, y = 10:1) df$x - MyClass(df$x) str(df) 'data.frame': 10 obs. of 2 variables: $ x:Class 'MyClass' int [1:10] 1 2 3 4 5 6 7 8 9 10 $ y: int 10 9 8 7 6 5 4 3 2 1 str(subset(df, x %% 2 == 0)) 'data.frame': 5 obs. of 2 variables: $ x: int 2 4 6 8 10 $ y: int 9 7 5 3 1 And so, any generic functions hooked to MyClass suddenly don't work on the subset results, but do work on the original data frame. I think I could write a custom as.data.frame.MyClass for all such classes, but this is annoying, indeed (and I don't know for sure if that's a robust solution) Wrapping in I(...) doesn't work, either: df - data.frame(x = 1:10, y = 10:1) df$x - I(MyClass(df$x)) str(df) 'data.frame': 10 obs. of 2 variables: $ x:Classes 'AsIs', 'MyClass' int [1:10] 1 2 3 4 5 6 7 8 9 10 $ y: int 10 9 8 7 6 5 4 3 2 1 str(subset(df, x %% 2 == 0)) 'data.frame': 5 obs. of 2 variables: $ x:Class 'AsIs' int [1:5] 2 4 6 8 10 $ y: int 9 7 5 3 1 (note that while 'AsIs' is kept, 'MyClass' has been removed in $x) Cheers! -Murat __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] subset drops S3 classes?
And as a follow-up, I implemented a barebones as.data.frame.MyClass(...). It works when dealing with non-subsetted data frames, but fails upon a subset(...) call: as.data.frame.MyClass - function(x, ...) as.data.frame.vector(x, ...) This works for a single column, e.g.: str(data.frame(MyClass(1:10))) 'data.frame': 10 obs. of 1 variable: $ MyClass.1.10.:Class 'MyClass' int [1:10] 1 2 3 4 5 6 7 8 9 10 But not during a subset: str(subset(data.frame(x = MyClass(1:10)), x %% 2 == 0)) 'data.frame': 5 obs. of 1 variable: $ x: int 2 4 6 8 10 -Murat On Wed, Nov 12, 2014 at 10:02 PM, Murat Tasan mmu...@gmail.com wrote: Hi all --- I've stumbled upon some pretty annoying behavior, and I'm curious how others may have gotten around it. When using subset(...) on a data frame that contains a custom S3 field, the class is dropped in the result: MyClass - function(x) structure(x, class = MyClass) df - data.frame(x = 1:10, y = 10:1) df$x - MyClass(df$x) str(df) 'data.frame': 10 obs. of 2 variables: $ x:Class 'MyClass' int [1:10] 1 2 3 4 5 6 7 8 9 10 $ y: int 10 9 8 7 6 5 4 3 2 1 str(subset(df, x %% 2 == 0)) 'data.frame': 5 obs. of 2 variables: $ x: int 2 4 6 8 10 $ y: int 9 7 5 3 1 And so, any generic functions hooked to MyClass suddenly don't work on the subset results, but do work on the original data frame. I think I could write a custom as.data.frame.MyClass for all such classes, but this is annoying, indeed (and I don't know for sure if that's a robust solution) Wrapping in I(...) doesn't work, either: df - data.frame(x = 1:10, y = 10:1) df$x - I(MyClass(df$x)) str(df) 'data.frame': 10 obs. of 2 variables: $ x:Classes 'AsIs', 'MyClass' int [1:10] 1 2 3 4 5 6 7 8 9 10 $ y: int 10 9 8 7 6 5 4 3 2 1 str(subset(df, x %% 2 == 0)) 'data.frame': 5 obs. of 2 variables: $ x:Class 'AsIs' int [1:5] 2 4 6 8 10 $ y: int 9 7 5 3 1 (note that while 'AsIs' is kept, 'MyClass' has been removed in $x) Cheers! -Murat __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] subset drops S3 classes?
... nd nevermind, figured it out (from the final example on the
Extract.data.frame page):
`[.MyClass` - function(x, i, ...) {
NextMethod([)
mostattributes(RV) - attribute(x)
RV
}
cheers,
-m
On Wed, Nov 12, 2014 at 11:02 PM, Murat Tasan mmu...@gmail.com wrote:
And as a follow-up, I implemented a barebones as.data.frame.MyClass(...).
It works when dealing with non-subsetted data frames, but fails upon a
subset(...) call:
as.data.frame.MyClass - function(x, ...) as.data.frame.vector(x, ...)
This works for a single column, e.g.:
str(data.frame(MyClass(1:10)))
'data.frame': 10 obs. of 1 variable:
$ MyClass.1.10.:Class 'MyClass' int [1:10] 1 2 3 4 5 6 7 8 9 10
But not during a subset:
str(subset(data.frame(x = MyClass(1:10)), x %% 2 == 0))
'data.frame': 5 obs. of 1 variable:
$ x: int 2 4 6 8 10
-Murat
On Wed, Nov 12, 2014 at 10:02 PM, Murat Tasan mmu...@gmail.com wrote:
Hi all --- I've stumbled upon some pretty annoying behavior, and I'm
curious how others may have gotten around it.
When using subset(...) on a data frame that contains a custom S3
field, the class is dropped in the result:
MyClass - function(x) structure(x, class = MyClass)
df - data.frame(x = 1:10, y = 10:1)
df$x - MyClass(df$x)
str(df)
'data.frame': 10 obs. of 2 variables:
$ x:Class 'MyClass' int [1:10] 1 2 3 4 5 6 7 8 9 10
$ y: int 10 9 8 7 6 5 4 3 2 1
str(subset(df, x %% 2 == 0))
'data.frame': 5 obs. of 2 variables:
$ x: int 2 4 6 8 10
$ y: int 9 7 5 3 1
And so, any generic functions hooked to MyClass suddenly don't work on
the subset results, but do work on the original data frame.
I think I could write a custom as.data.frame.MyClass for all such
classes, but this is annoying, indeed (and I don't know for sure if
that's a robust solution)
Wrapping in I(...) doesn't work, either:
df - data.frame(x = 1:10, y = 10:1)
df$x - I(MyClass(df$x))
str(df)
'data.frame': 10 obs. of 2 variables:
$ x:Classes 'AsIs', 'MyClass' int [1:10] 1 2 3 4 5 6 7 8 9 10
$ y: int 10 9 8 7 6 5 4 3 2 1
str(subset(df, x %% 2 == 0))
'data.frame': 5 obs. of 2 variables:
$ x:Class 'AsIs' int [1:5] 2 4 6 8 10
$ y: int 9 7 5 3 1
(note that while 'AsIs' is kept, 'MyClass' has been removed in $x)
Cheers!
-Murat
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] problem when using gmailr
Dear expeRts, Hi, when i using gmailr through Rscript got the following error : oauth_listener() needs an interactive environment But when i using the Rstudio it worked. Does the function gmail_auth(filepath,full) support the Rscript way ?? I need run it in a windows schdual task. TKS -- PO SU mail: desolato...@163.com Majored in Statistics from SJTU __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
