Re: [R] Can R read Word fonts and comments?
Thanks, Bob. Regarding other functionalities I would request: Extract all text with (1) a specific color or (2) a specific font (3) underlines. For example, if one highlights in red, then she would like to extract all texts in red. Occasionally she might use more than one colors, and each color bears its own implication. Thanks! John 2016-07-05 10:03 GMT-07:00 boB Rudis: > I'll dig into that (was hoping the small feature addition wld cause > enhanced feature requests :-) > > On Tue, Jul 5, 2016 at 1:02 PM, John wrote: > > Thank you, David and Bert, for the info. > > Thank you, Bob, for this excellent function. Allow me to request a > feature: > > You highlighted the following text, and comment "This is the first > comment". > > > > "Lorem ipsum dolor sit amet, cu sit modus voluptua accommodare, meis > > disputando voluptatibus eu nec, qui te modo solum delicata. Eam scripta > > maluisset urbanitas et, numquam disputationi in pri, vis tibique deserunt > > accusamus ut. Vis movet admodum probatus cu, ex pri ludus possit. > Molestiae > > efficiendi at vix, eu labore elaboraret deterruisset mei, et eos persius > > nominati." > > > > Could you let the function output the above text (with the comments, of > > course), which you highlighted for comment? > > > > Thanks, > > > > John > > > > > > > > 2016-07-02 14:12 GMT-07:00 boB Rudis : > >> > >> I just added `docx_extract_all_cmnts()` (and a cpl other > >> comments-related things) to the dev version of `docxtractr` > >> (https://github.com/hrbrmstr/docxtractr). You can use > >> `devtools::install_github("hrbrmstr/docxtractr")` to install it. > >> There's an example in the help for that function. > >> > >> Give it a go and file detailed issues for other functionality you need. > >> > >> On Fri, Jul 1, 2016 at 11:14 PM, David Winsemius < > dwinsem...@comcast.net> > >> wrote: > >> > It’s my understanding that docx and xlsx files are zipped containers > >> > that have their data in XML files. You should try unzipping one and > >> > examining it with a viewer. You may then be able to use pkg:XML. > >> > > >> > — > >> > David. > >> > > >> >> On Jul 1, 2016, at 3:13 PM, Bert Gunter > wrote: > >> >> > >> >> No, sorry -- all I would do is search. > >> >> > >> >> -- Bert > >> >> > >> >> > >> >> Bert Gunter > >> >> > >> >> "The trouble with having an open mind is that people keep coming > along > >> >> and sticking things into it." > >> >> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > >> >> > >> >> > >> >> On Fri, Jul 1, 2016 at 2:33 PM, John wrote: > >> >>> Yes, I have done some search (e.g., tm, markdown, etc), but I can't > >> >>> find > >> >>> this function. > >> >>> If you know any package that works for this purpose, that would be > >> >>> quite > >> >>> helpful. > >> >>> Thanks, > >> >>> > >> >>> John > >> >>> > >> >>> 2016-06-28 16:50 GMT-07:00 Bert Gunter : > >> > >> Did you try searching before posting here? -- e.g. a web search or > on > >> rseek.org ? > >> > >> Cheers, > >> Bert > >> > >> > >> Bert Gunter > >> > >> "The trouble with having an open mind is that people keep coming > >> along > >> and sticking things into it." > >> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > >> > >> > >> On Tue, Jun 28, 2016 at 3:53 PM, John wrote: > >> > Hi, > >> > > >> > From time to time I highlight the word documents with red/blue > >> > color > >> > or > >> > italic/bold fonts, and I also add comments to a file. Is there a > >> > package/function to let R extract the italic/bold blue/red words > and > >> > comments from a docx/doc file? > >> > > >> > I am aware that there are a few packages reading Word, but don't > >> > know > >> > which one is able to do it. > >> > > >> > Thanks, > >> > > >> > John > >> > > >> >[[alternative HTML version deleted]] > >> > > >> > __ > >> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> > https://stat.ethz.ch/mailman/listinfo/r-help > >> > PLEASE do read the posting guide > >> > http://www.R-project.org/posting-guide.html > >> > and provide commented, minimal, self-contained, reproducible code. > >> >>> > >> >>> > >> >> > >> >> __ > >> >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> >> https://stat.ethz.ch/mailman/listinfo/r-help > >> >> PLEASE do read the posting guide > >> >> http://www.R-project.org/posting-guide.html > >> >> and provide commented, minimal, self-contained, reproducible code. > >> > > >> > __ > >> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more,
Re: [R] BCa Bootstrapped regression coefficients from lmrob function not working
It would help to show your error message, n'est-ce pas? Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Tue, Jul 5, 2016 at 2:51 PM, varin sacha via R-helpwrote: > Dear Professor Dalgaard, > > I really thank you lots for your response. I have solved my problem. Now, I > have tried to do the same (calculate the BCa bootstrapped CIs) for the MARS > regression, and I get an error message. If somebody has a hint to solve my > problem, would be highly appreciated. > > Reproducible example : > > > Dataset = > data.frame(PIBparHab=c(43931,67524,48348,44827,52409,15245,24453,57636,28992,17102,51495,47243,40908,22494,12784,48391,44221,32514,35132,46679,106022,9817,99635,38678,49128,12876,20732,17151,19670,41053,22488,57134,83295,10660), > > QUALITESANSREDONDANCE=c(1082.5,1066.6,1079.3,1079.9,1074.9,1008.6,1007.5,.3,1108.2,1109.7,1059.6,1165.1,1026.7,1035.1,997.8,1044.8,1073.6,1085.7,1083.8,1021.6,1036.2,1075.3,1069.3,1101.4,1086.9,1072.1,1166.7,983.9,1004.5,1082.5,1123.5,1094.9,1105.1,1010.8), > > competitivite=c(89,83,78,73,90,71,77,85,61,67,98,82,70,43,57,78,72,79,61,71,86,63,90,75,87,64,60,56,66,80,53,91,97,62), > > innovation=c(56,52,53,54,57,43,54,60,47,55,58,62,52,35,47,59,56,56,45,52,58,33,57,57,61,40,45,41,50,61,50,65,68,34)) > > install.packages("earth") > > library(earth) > > newdata=na.omit(Dataset) > > model=earth(PIBparHab ~ QUALITESANSREDONDANCE + competitivite + > innovation,data=newdata) > > summary(model) > > plot(model) > > plotmo(model) > > > boot.MARS=function(formula,data,indices) { > > d=data[indices,] > > fit=earth(formula,data=d) > > return(coef(fit)) > > } > > library(boot) > > results=boot(data=newdata, statistic=boot.MARS, R=1000,formula=PIBparHab ~ > QUALITESANSREDONDANCE + competitivite + innovation) > > boot.ci(results, type= "bca",index=2) > > > Best, > S > > > De : peter dalgaard > > Cc : R-help Mailing List > Envoyé le : Dimanche 3 juillet 2016 18h19 > Objet : Re: [R] BCa Bootstrapped regression coefficients from lmrob function > not working > > > >> On 03 Jul 2016, at 13:47 , varin sacha via R-help >> wrote: >> >> Dear R-experts, >> >> I am trying to calculate the bootstrapped (BCa) regression coefficients for >> a robust regression using MM-type estimator (lmrob function from robustbase >> package). >> >> My R code here below is showing a warning message ([1] "All values of t are >> equal to >> 22.2073014256803\n Can not calculate confidence intervals" NULL), I was >> wondering if it was because I am trying to fit a robust regression with >> lmrob function rather than a simple lm ? I mean maybe the boot.ci function >> does not work with lmrob function ? If not, I was wondering what was going >> on ? > > You need to review your code. You calculate a,b,c,d in the global environment > and create newdata as a subset of Dataset, then use a,b,c,d in the formula, > but no such variables are in newdata. AFAICT, all your bootstrap fits use the > _same_ global values for a,b,c,d hence give the same result 1000 times... > > -pd > > > >> >> Here is the reproducible example >> >> >> Dataset = >> data.frame(PIBparHab=c(43931,67524,48348,44827,52409,15245,24453,57636,28992,17102,51495,47243,40908,22494,12784,48391,44221,32514,35132,46679,106022,9817,99635,38678,49128,12876,20732,17151,19670,41053,22488,57134,83295,10660), >> >> QUALITESANSREDONDANCE=c(1082.5,1066.6,1079.3,1079.9,1074.9,1008.6,1007.5,.3,1108.2,1109.7,1059.6,1165.1,1026.7,1035.1,997.8,1044.8,1073.6,1085.7,1083.8,1021.6,1036.2,1075.3,1069.3,1101.4,1086.9,1072.1,1166.7,983.9,1004.5,1082.5,1123.5,1094.9,1105.1,1010.8), >> >> competitivite=c(89,83,78,73,90,71,77,85,61,67,98,82,70,43,57,78,72,79,61,71,86,63,90,75,87,64,60,56,66,80,53,91,97,62), >> >> innovation=c(56,52,53,54,57,43,54,60,47,55,58,62,52,35,47,59,56,56,45,52,58,33,57,57,61,40,45,41,50,61,50,65,68,34)) >> >> library("robustbase") >> newdata=na.omit(Dataset) >> a=Dataset$PIBparHab >> b=Dataset$QUALITESANSREDONDANCE >> c=Dataset$competitivite >> d=Dataset$innovation >> >> fm.lmrob=lmrob(a~b+c+d,data=newdata) >> fm.lmrob >> >> boot.Lmrob=function(formula,data,indices) { >> d=data[indices,] >> fit=lmrob(formula,data=d) >> return(coef(fit)) >> } >> >> library(boot) >> results=boot(data=newdata, statistic=boot.Lmrob, R=1000,formula=a~b+c+d) >> boot.ci(results, type= "bca",index=2) >> >> >> Any help would be highly appreciated, >> S >> >> __ >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. > > -- > Peter Dalgaard,
Re: [R] BCa Bootstrapped regression coefficients from lmrob function not working
Dear Professor Dalgaard, I really thank you lots for your response. I have solved my problem. Now, I have tried to do the same (calculate the BCa bootstrapped CIs) for the MARS regression, and I get an error message. If somebody has a hint to solve my problem, would be highly appreciated. Reproducible example : Dataset = data.frame(PIBparHab=c(43931,67524,48348,44827,52409,15245,24453,57636,28992,17102,51495,47243,40908,22494,12784,48391,44221,32514,35132,46679,106022,9817,99635,38678,49128,12876,20732,17151,19670,41053,22488,57134,83295,10660), QUALITESANSREDONDANCE=c(1082.5,1066.6,1079.3,1079.9,1074.9,1008.6,1007.5,.3,1108.2,1109.7,1059.6,1165.1,1026.7,1035.1,997.8,1044.8,1073.6,1085.7,1083.8,1021.6,1036.2,1075.3,1069.3,1101.4,1086.9,1072.1,1166.7,983.9,1004.5,1082.5,1123.5,1094.9,1105.1,1010.8), competitivite=c(89,83,78,73,90,71,77,85,61,67,98,82,70,43,57,78,72,79,61,71,86,63,90,75,87,64,60,56,66,80,53,91,97,62), innovation=c(56,52,53,54,57,43,54,60,47,55,58,62,52,35,47,59,56,56,45,52,58,33,57,57,61,40,45,41,50,61,50,65,68,34)) install.packages("earth") library(earth) newdata=na.omit(Dataset) model=earth(PIBparHab ~ QUALITESANSREDONDANCE + competitivite + innovation,data=newdata) summary(model) plot(model) plotmo(model) boot.MARS=function(formula,data,indices) { d=data[indices,] fit=earth(formula,data=d) return(coef(fit)) } library(boot) results=boot(data=newdata, statistic=boot.MARS, R=1000,formula=PIBparHab ~ QUALITESANSREDONDANCE + competitivite + innovation) boot.ci(results, type= "bca",index=2) Best, S De : peter dalgaardCc : R-help Mailing List Envoyé le : Dimanche 3 juillet 2016 18h19 Objet : Re: [R] BCa Bootstrapped regression coefficients from lmrob function not working > On 03 Jul 2016, at 13:47 , varin sacha via R-help > wrote: > > Dear R-experts, > > I am trying to calculate the bootstrapped (BCa) regression coefficients for a > robust regression using MM-type estimator (lmrob function from robustbase > package). > > My R code here below is showing a warning message ([1] "All values of t are > equal to > 22.2073014256803\n Can not calculate confidence intervals" NULL), I was > wondering if it was because I am trying to fit a robust regression with lmrob > function rather than a simple lm ? I mean maybe the boot.ci function does not > work with lmrob function ? If not, I was wondering what was going on ? You need to review your code. You calculate a,b,c,d in the global environment and create newdata as a subset of Dataset, then use a,b,c,d in the formula, but no such variables are in newdata. AFAICT, all your bootstrap fits use the _same_ global values for a,b,c,d hence give the same result 1000 times... -pd > > Here is the reproducible example > > > Dataset = > data.frame(PIBparHab=c(43931,67524,48348,44827,52409,15245,24453,57636,28992,17102,51495,47243,40908,22494,12784,48391,44221,32514,35132,46679,106022,9817,99635,38678,49128,12876,20732,17151,19670,41053,22488,57134,83295,10660), > > QUALITESANSREDONDANCE=c(1082.5,1066.6,1079.3,1079.9,1074.9,1008.6,1007.5,.3,1108.2,1109.7,1059.6,1165.1,1026.7,1035.1,997.8,1044.8,1073.6,1085.7,1083.8,1021.6,1036.2,1075.3,1069.3,1101.4,1086.9,1072.1,1166.7,983.9,1004.5,1082.5,1123.5,1094.9,1105.1,1010.8), > > competitivite=c(89,83,78,73,90,71,77,85,61,67,98,82,70,43,57,78,72,79,61,71,86,63,90,75,87,64,60,56,66,80,53,91,97,62), > > innovation=c(56,52,53,54,57,43,54,60,47,55,58,62,52,35,47,59,56,56,45,52,58,33,57,57,61,40,45,41,50,61,50,65,68,34)) > > library("robustbase") > newdata=na.omit(Dataset) > a=Dataset$PIBparHab > b=Dataset$QUALITESANSREDONDANCE > c=Dataset$competitivite > d=Dataset$innovation > > fm.lmrob=lmrob(a~b+c+d,data=newdata) > fm.lmrob > > boot.Lmrob=function(formula,data,indices) { > d=data[indices,] > fit=lmrob(formula,data=d) > return(coef(fit)) > } > > library(boot) > results=boot(data=newdata, statistic=boot.Lmrob, R=1000,formula=a~b+c+d) > boot.ci(results, type= "bca",index=2) > > > Any help would be highly appreciated, > S > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Peter Dalgaard, Professor, Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Office: A 4.23 Email: pd@cbs.dk Priv: pda...@gmail.com __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R-es] ayuda frecuencia asistencia clase
Estimado Sebastián Kruk La respuesta es sí, pero su mensaje sale difícil de interpretar en mi computadora. No comprendo correctamente su pregunta, creo que todos los libros deben tener un ejemplo de R y frecuencias, su problema no entra en mi cabeza. Javier Rubén Marcuzzi De: Sebastian Kruk [[alternative HTML version deleted]] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es
Re: [R] How to extract "specific"/"last" intercept value from segmented package.
You should use only plain text emails, provide sample data, and indicate any relevant packages that you had to load. First let's load the necessary package and create some data: > library(segmented) > set.seed(42) > x <- sort(runif(60, 10, 60)) > int <- c(rep(0, 20), rep(60, 20), rep(-80, 20)) > slp <- c(rep(2, 20), rep(0, 20), rep(3, 20)) > y <- int + slp*x + rnorm(60, 0, 2) > plot(x, y) You should have a plot showing 2 break points. Using psi=mean(x) puts a single breakpoint in the middle of the distribtution so we have to be more specific: > lin.mod <- lm(y~x) > segmented.mod <- segmented(lin.mod, seg.Z = ~x, psi= c(25, 55)) > plot(segmented.mod, add=T) > sl <- slope(segmented.mod) > inter <- intercept(segmented.mod) Now your plot shows the segmented model. You need to know what intercept() is returning so you should look at the manual page: ?intercept. It returns a list of matrices (one matrix for each independent variable). You have only one, x, so you get a list with one element. > str(inter) List of 1 $ x: num [1:3, 1] -0.179 60.25 -86.77 ..- attr(*, "dimnames")=List of 2 .. ..$ : chr [1:3] "intercept1" "intercept2" "intercept3" .. ..$ : chr "Est." To get the first matrix without knowing its name and the last row: > tail(inter[[1]], 1) Est. intercept3 -86.77 If you want to strip off the labels: > as.vector(tail(inter[[1]], 1)) [1] -86.77 - David L. Carlson Department of Anthropology Texas A University -Original Message- From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Narendra Modi Sent: Tuesday, July 5, 2016 1:42 PM To: R-help@r-project.org Subject: [R] How to extract "specific"/"last" intercept value from segmented package. I am able to perform regression on a dataset as below: plot(x,y) lin.mod <- lm(y~x) m <- mean(x) m segmented.mod <- segmented(lin.mod, seg.Z = ~x, psi= m) plot(segmented.mod, add=T) sl <- slope(segmented.mod) inter <- intercept(segmented.mod) summary(segmented.mod)# Show Summary sl# show all the slopes inter # show all the intercepts In my dataset, the above method correctly identifies the breakpoints and hence I get two intercepts. > inter $x Est. intercept1 -3.269 intercept2 -19.980 What I am interested is the "intercept2" value. How can I obtain this? The method needs to be dynamic as in if the next dataset has 3 intercepts, I would like to get "intercept3 value. PD [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to extract "specific"/"last" intercept value from segmented package.
Hello, Try dimnames(inter$x)[[1]] You could have seen this by inspecting 'inter': str(inter) Hope this helps, Rui Barradas Citando Narendra Modi: > I am able to perform regression on a dataset as below: > > plot(x,y) > lin.mod <- lm(y~x) > m <- mean(x) > m > > segmented.mod <- segmented(lin.mod, seg.Z = ~x, psi= m) > > plot(segmented.mod, add=T) > sl <- slope(segmented.mod) > inter <- intercept(segmented.mod) > > summary(segmented.mod) # Show Summary > sl # show all the slopes > inter # show all the intercepts > > In my dataset, the above method correctly identifies the breakpoints and > hence I get two intercepts. >> inter > > $x > Est. > intercept1 -3.269 > intercept2 -19.980 > > What I am interested is the "intercept2" value. How can I obtain this? > > The method needs to be dynamic as in if the next dataset has 3 intercepts, > I would like to get "intercept3 value. > > PD > > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.htmland provide commented, > minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to extract "specific"/"last" intercept value from segmented package.
I am able to perform regression on a dataset as below: plot(x,y) lin.mod <- lm(y~x) m <- mean(x) m segmented.mod <- segmented(lin.mod, seg.Z = ~x, psi= m) plot(segmented.mod, add=T) sl <- slope(segmented.mod) inter <- intercept(segmented.mod) summary(segmented.mod)# Show Summary sl# show all the slopes inter # show all the intercepts In my dataset, the above method correctly identifies the breakpoints and hence I get two intercepts. > inter $x Est. intercept1 -3.269 intercept2 -19.980 What I am interested is the "intercept2" value. How can I obtain this? The method needs to be dynamic as in if the next dataset has 3 intercepts, I would like to get "intercept3 value. PD [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R-es] ayuda frecuencia asistencia clase
Estimados usurios-R: Tengo una lista de alumnos. Hay alguna forma de sacar una tabla de frecuencias por la asistencia a clases mensual. Es decir cuantos días concurrió cada alumno en el mes. Supongamos que la lista está conformada por ocho alumnos, el curso duró 4 días y quiero saber cuantos días concurrió cada uno al curso poniendolo en la columna mes. Quisiera obtener un cuadro así: Alumnos Dia 1 Dia 2 Dia 3 Dia 4 Mes Pedro si 1 Juan si si si si 4 Carlos si si 2 Daniel si si 2 Florencia si si 2 Ana 0 Paula si 1 Ximena si si 2 Gracias de antemano. Saludos, Sebastián. [[alternative HTML version deleted]] ___ R-help-es mailing list R-help-es@r-project.org https://stat.ethz.ch/mailman/listinfo/r-help-es
Re: [R] Can R read Word fonts and comments?
I'll dig into that (was hoping the small feature addition wld cause enhanced feature requests :-) On Tue, Jul 5, 2016 at 1:02 PM, Johnwrote: > Thank you, David and Bert, for the info. > Thank you, Bob, for this excellent function. Allow me to request a feature: > You highlighted the following text, and comment "This is the first comment". > > "Lorem ipsum dolor sit amet, cu sit modus voluptua accommodare, meis > disputando voluptatibus eu nec, qui te modo solum delicata. Eam scripta > maluisset urbanitas et, numquam disputationi in pri, vis tibique deserunt > accusamus ut. Vis movet admodum probatus cu, ex pri ludus possit. Molestiae > efficiendi at vix, eu labore elaboraret deterruisset mei, et eos persius > nominati." > > Could you let the function output the above text (with the comments, of > course), which you highlighted for comment? > > Thanks, > > John > > > > 2016-07-02 14:12 GMT-07:00 boB Rudis : >> >> I just added `docx_extract_all_cmnts()` (and a cpl other >> comments-related things) to the dev version of `docxtractr` >> (https://github.com/hrbrmstr/docxtractr). You can use >> `devtools::install_github("hrbrmstr/docxtractr")` to install it. >> There's an example in the help for that function. >> >> Give it a go and file detailed issues for other functionality you need. >> >> On Fri, Jul 1, 2016 at 11:14 PM, David Winsemius >> wrote: >> > It’s my understanding that docx and xlsx files are zipped containers >> > that have their data in XML files. You should try unzipping one and >> > examining it with a viewer. You may then be able to use pkg:XML. >> > >> > — >> > David. >> > >> >> On Jul 1, 2016, at 3:13 PM, Bert Gunter wrote: >> >> >> >> No, sorry -- all I would do is search. >> >> >> >> -- Bert >> >> >> >> >> >> Bert Gunter >> >> >> >> "The trouble with having an open mind is that people keep coming along >> >> and sticking things into it." >> >> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) >> >> >> >> >> >> On Fri, Jul 1, 2016 at 2:33 PM, John wrote: >> >>> Yes, I have done some search (e.g., tm, markdown, etc), but I can't >> >>> find >> >>> this function. >> >>> If you know any package that works for this purpose, that would be >> >>> quite >> >>> helpful. >> >>> Thanks, >> >>> >> >>> John >> >>> >> >>> 2016-06-28 16:50 GMT-07:00 Bert Gunter : >> >> Did you try searching before posting here? -- e.g. a web search or on >> rseek.org ? >> >> Cheers, >> Bert >> >> >> Bert Gunter >> >> "The trouble with having an open mind is that people keep coming >> along >> and sticking things into it." >> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) >> >> >> On Tue, Jun 28, 2016 at 3:53 PM, John wrote: >> > Hi, >> > >> > From time to time I highlight the word documents with red/blue >> > color >> > or >> > italic/bold fonts, and I also add comments to a file. Is there a >> > package/function to let R extract the italic/bold blue/red words and >> > comments from a docx/doc file? >> > >> > I am aware that there are a few packages reading Word, but don't >> > know >> > which one is able to do it. >> > >> > Thanks, >> > >> > John >> > >> >[[alternative HTML version deleted]] >> > >> > __ >> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> > https://stat.ethz.ch/mailman/listinfo/r-help >> > PLEASE do read the posting guide >> > http://www.R-project.org/posting-guide.html >> > and provide commented, minimal, self-contained, reproducible code. >> >>> >> >>> >> >> >> >> __ >> >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> >> https://stat.ethz.ch/mailman/listinfo/r-help >> >> PLEASE do read the posting guide >> >> http://www.R-project.org/posting-guide.html >> >> and provide commented, minimal, self-contained, reproducible code. >> > >> > __ >> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> > https://stat.ethz.ch/mailman/listinfo/r-help >> > PLEASE do read the posting guide >> > http://www.R-project.org/posting-guide.html >> > and provide commented, minimal, self-contained, reproducible code. >> >> __ >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. > > __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
Re: [R] Can R read Word fonts and comments?
Thank you, David and Bert, for the info. Thank you, Bob, for this excellent function. Allow me to request a feature: You highlighted the following text, and comment "This is the first comment". "Lorem ipsum dolor sit amet, cu sit modus voluptua accommodare, meis disputando voluptatibus eu nec, qui te modo solum delicata. Eam scripta maluisset urbanitas et, numquam disputationi in pri, vis tibique deserunt accusamus ut. Vis movet admodum probatus cu, ex pri ludus possit. Molestiae efficiendi at vix, eu labore elaboraret deterruisset mei, et eos persius nominati." Could you let the function output the above text (with the comments, of course), which you highlighted for comment? Thanks, John 2016-07-02 14:12 GMT-07:00 boB Rudis: > I just added `docx_extract_all_cmnts()` (and a cpl other > comments-related things) to the dev version of `docxtractr` > (https://github.com/hrbrmstr/docxtractr). You can use > `devtools::install_github("hrbrmstr/docxtractr")` to install it. > There's an example in the help for that function. > > Give it a go and file detailed issues for other functionality you need. > > On Fri, Jul 1, 2016 at 11:14 PM, David Winsemius > wrote: > > It’s my understanding that docx and xlsx files are zipped containers > that have their data in XML files. You should try unzipping one and > examining it with a viewer. You may then be able to use pkg:XML. > > > > — > > David. > > > >> On Jul 1, 2016, at 3:13 PM, Bert Gunter wrote: > >> > >> No, sorry -- all I would do is search. > >> > >> -- Bert > >> > >> > >> Bert Gunter > >> > >> "The trouble with having an open mind is that people keep coming along > >> and sticking things into it." > >> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > >> > >> > >> On Fri, Jul 1, 2016 at 2:33 PM, John wrote: > >>> Yes, I have done some search (e.g., tm, markdown, etc), but I can't > find > >>> this function. > >>> If you know any package that works for this purpose, that would be > quite > >>> helpful. > >>> Thanks, > >>> > >>> John > >>> > >>> 2016-06-28 16:50 GMT-07:00 Bert Gunter : > > Did you try searching before posting here? -- e.g. a web search or on > rseek.org ? > > Cheers, > Bert > > > Bert Gunter > > "The trouble with having an open mind is that people keep coming along > and sticking things into it." > -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > > > On Tue, Jun 28, 2016 at 3:53 PM, John wrote: > > Hi, > > > > From time to time I highlight the word documents with red/blue > color > > or > > italic/bold fonts, and I also add comments to a file. Is there a > > package/function to let R extract the italic/bold blue/red words and > > comments from a docx/doc file? > > > > I am aware that there are a few packages reading Word, but don't > know > > which one is able to do it. > > > > Thanks, > > > > John > > > >[[alternative HTML version deleted]] > > > > __ > > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > >>> > >>> > >> > >> __ > >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > >> https://stat.ethz.ch/mailman/listinfo/r-help > >> PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > >> and provide commented, minimal, self-contained, reproducible code. > > > > __ > > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Antwort: Re: dplyr : row total for all groups in dplyr summarise
> On Jul 5, 2016, at 2:27 AM, g.maub...@weinwolf.de wrote: > > Hi guys, > > I checked out your example but I can't follow the results.: > >> mtcars %>% > + group_by (am, gear) %>% > + summarise (n=n()) %>% > + mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) %>% > + ungroup() %>% > + mutate(row.tot = sum(n)) > Source: local data frame [4 x 5] > > am gear n rel.freq row.tot > (dbl) (dbl) (int)(chr) (int) > 1 0 315 79% 32 > 2 0 4 4 21% 32 > 3 1 4 8 62% 32 > 4 1 5 5 38% 32 > > We have a total of 32 cases and 15 * 100 / 32 = 48,9 % instead of 79 %. > The same with the other columns. How is 79 % calculated? > It is apparently the number of items in the first “group determinant” > mtcars %>% +group_by (am, gear) %>% +summarise (n=n()) %>% +mutate(sum = sum(n)) %>% +ungroup() Source: local data frame [4 x 4] am gear n sum (dbl) (dbl) (int) (int) 1 0 31519 2 0 4 419 3 1 4 813 4 1 5 513 > ?n > with(mtcars,table(am,gear)) gear am 3 4 5 0 15 4 0 1 0 8 5 The documentation for the `n` functions is particularly unhelpful in letting one know what to expect from it: "Description This function is implemented special for each data source and can only be used from within summarise, mutate and filter" — David. > When searching the web I saw this example: > > -- cut -- > > #-- not run -- > url <- "http://www.lock5stat.com/datasets/HollywoodMovies2011.csv; > response <- GET(url) > Hollywoodmovies2011 <- content(x = GET(url), as = data.frame) > #-- end not run > > Hollywoodmovies2011 %>% > group_by(genre) %>% > summarize(count = n()) %>% > mutate(rf = count / sum(count)) > > -- cut -- > > which gives > > Source: local data frame [9 x 3] > > Genre count % > (fctr) (int) (dbl) > 1Action32 0.235294118 > 2 Adventure 1 0.007352941 > 3 Animation12 0.088235294 > 4Comedy27 0.198529412 > 5 Drama21 0.154411765 > 6 Fantasy 2 0.014705882 > 7Horror17 0.12500 > 8 Romance11 0.080882353 > 9 Thriller13 0.095588235 > > Here the % correspond to the count and the sum of count, e. g. sum = 136 > and 32 / 136 = 0,2352941. > > What is the difference when counting? What do the relative counts in the > first example mean? > > Kind regards > > Georg > > > > > > Von:Ulrik Stervbo> An: David Winsemius , > Kopie: r-help@r-project.org, mai...@infomed.sld.cu > Datum: 05.07.2016 06:06 > Betreff:Re: [R] dplyr : row total for all groups in dplyr > summarise > Gesendet von: "R-help" > > > > That will give you the wrong result when used on summarised data > > David Winsemius schrieb am Di., 5. Juli 2016 > 02:10: > >> I thought there was an nrow() function? >> >> Sent from my iPhone >> >> On Jul 4, 2016, at 9:59 AM, Ulrik Stervbo > wrote: >> >> If you want the total number of rows in the original data.frame after >> counting the rows in each group, you can ungroup and sum the row counts, >> like: >> >> library("dplyr") >> >> >> mtcars %>% >> group_by (am, gear) %>% >> summarise (n=n()) %>% >> mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) %>% >> ungroup() %>% >> mutate(row.tot = sum(n)) >> >> HTH >> Ulrik >> >> On Mon, 4 Jul 2016 at 18:23 David Winsemius >> wrote: >> >>> On Jul 4, 2016, at 6:56 AM, mai...@infomed.sld.cu wrote: Hello, How can I aggregate row total for all groups in dplyr summarise ? >>> >>> Row total … of what? Aggregate … how? What is the desired answer? >>> >>> >>> library(dplyr) mtcars %>% group_by (am, gear) %>% summarise (n=n()) %>% mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) best regard Maicel Monzon -- Este mensaje le ha llegado mediante el servicio de correo electronico >>> que ofrece Infomed para respaldar el cumplimiento de las misiones del >>> Sistema Nacional de Salud. La persona que envia este correo asume el >>> compromiso de usar el servicio a tales fines y cumplir con las > regulaciones >>> establecidas Infomed: http://www.sld.cu/ __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide >>> http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. >>> >>> __ >>> R-help@r-project.org mailing list --
Re: [R] dplyr : row total for all groups in dplyr summarise
mtcars %>% group_by (am, gear) %>% summarise (n=n()) %>% mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) %>% ungroup() %>% plyr::rbind.fill(data.frame( n=nrow(mtcars),rel.freq="100%”)) > On Jul 5, 2016, at 4:47 AM, mai...@infomed.sld.cu wrote: > > Sorry, what I wanted to do was to add a total row at the end of the summary. > The marginal totals by columns correspond to 100% and the sum of levels. > best reagard > Maicel Monzon > > > Ulrik Stervboescribió: > >> Yes. But in the sample code the data is summarised. In which case you get 4 >> rows and not the correct 32. >> >> On Tue, 5 Jul 2016, 07:48 David Winsemius, wrote: >> >>> nrow(mtcars) >>> >>> >>> Sent from my iPhone >>> >>> On Jul 4, 2016, at 9:03 PM, Ulrik Stervbo wrote: >>> >>> That will give you the wrong result when used on summarised data >>> >>> David Winsemius schrieb am Di., 5. Juli 2016 >>> 02:10: >>> I thought there was an nrow() function? Sent from my iPhone On Jul 4, 2016, at 9:59 AM, Ulrik Stervbo wrote: If you want the total number of rows in the original data.frame after counting the rows in each group, you can ungroup and sum the row counts, like: library("dplyr") mtcars %>% group_by (am, gear) %>% summarise (n=n()) %>% mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) %>% ungroup() %>% mutate(row.tot = sum(n)) HTH Ulrik On Mon, 4 Jul 2016 at 18:23 David Winsemius wrote: > > > On Jul 4, 2016, at 6:56 AM, mai...@infomed.sld.cu wrote: > > > > Hello, > > How can I aggregate row total for all groups in dplyr summarise ? > > Row total ? of what? Aggregate ? how? What is the desired answer? > > > > > library(dplyr) > > mtcars %>% > > group_by (am, gear) %>% > > summarise (n=n()) %>% > > mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) > > > > best regard > > Maicel Monzon > > > > > > > > > > > > > > > > > > -- > > Este mensaje le ha llegado mediante el servicio de correo electronico > que ofrece Infomed para respaldar el cumplimiento de las misiones del > Sistema Nacional de Salud. La persona que envia este correo asume el > compromiso de usar el servicio a tales fines y cumplir con las > regulaciones > establecidas > > > > Infomed: http://www.sld.cu/ > > > > __ > > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >> > > > > > This message was sent using IMP, the Internet Messaging Program. > > > > -- > Este mensaje le ha llegado mediante el servicio de correo electronico que > ofrece Infomed para respaldar el cumplimiento de las misiones del Sistema > Nacional de Salud. La persona que envia este correo asume el compromiso de > usar el servicio a tales fines y cumplir con las regulaciones establecidas > > Infomed: http://www.sld.cu/ > __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R-3.3.1 RPM release
Thanks a lot Mac for your kind answer. In the meanwhile I could successfully build the 3.3.1 on a CentOS 6.3 (VM) Anyway I will contact Tom as you suggest. Thanks and regards, Cristiano -Original Message- From: Marc Schwartz [mailto:marc_schwa...@me.com] Sent: Tuesday, July 05, 2016 1:30 PM To: Sangalli Cristiano Giovanni (Ext. - UniCredit Business Integrated Solutions) Cc: R-help Subject: Re: [R] R-3.3.1 RPM release > On Jul 4, 2016, at 9:37 AM, Sangalli Cristiano Giovanni (Ext. - UniCredit > Business Integrated Solutions)wrote: > > Dear CRAN, > > I have installed on a RHEL 5.7 server the recent R-3.3.0 rpm but I would like > to upgrade to the latest now available R-3.3.1 . I have not found so far the > rpm, I would like to know if and when it will be available? > > Thanks in advance, > Cris > Hi, The CRAN team does not build RPMs for RH and Fedora, that is done via RH maintainers and released via the EPEL: https://fedoraproject.org/wiki/EPEL As an FYI, there is a dedicated SIG list for R on RH/Fedora and the RH maintainers (e.g. Tom Callaway) read that list: https://stat.ethz.ch/mailman/listinfo/r-sig-fedora You should post there and Tom can provide a sense of when 3.3.1 will be made available. At present, there is no indication that 3.3.1 is in the R build queue, which can be viewed at: https://bodhi.fedoraproject.org/updates/?packages=R Regards, Marc Schwartz This e-mail is confidential and may also contain privileged information. If you are not the intended recipient you are not authorised to read, print, save, process or disclose this message. If you have received this message by mistake, please inform the sender immediately and delete this e-mail, its attachments and any copies. Any use, distribution, reproduction or disclosure by any person other than the intended recipient is strictly prohibited and the person responsible may incur penalties. Thank you! __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Problems with parallel processing using the foreach package
Dear R-users, I am trying my hand at parallel processing in R using the foreach package but it is not working as I want it to. I am using a function I created myself (Xenopus_Walk) which returns a vector. Now I would like to run this function for every number that is saved in a vector (newly_populated_vec) and obtain a list that stores a every vector that has been created as one element of said list. The command I am currently using is the following (I guess you can ignore most of it since that's mostly only exported packages and parameters my function relies on): no_cores <- detectCores()-1 cl <- makeCluster(no_cores) registerDoParallel(cl) Xenopus_Data <- foreach(b=1:length(newly_populated_vec),.combine=list,.multicombine=TRUE,.packages = c("raster", "gdistance", "rgdal","sp")) %dopar% { Xenopus_Walk(altdata=altdata,water=water,habitat_suitability=habitat_suitability,max_range_without_water=max_range_without_water,max_range=max_range,slope=slope,Start_Pt=newly_populated_vec[b]) } The problem I have now is that the length of the returned list (Xenopus_Data) si different from the length of the vector I retrieve the iterator from (newly_populated_vec): > length(Xenopus_Data) [1] 47 > length(newly_populated_vec) [1] 2027 While trying to figure out what is wrong I have read that one has to split up the workload into equal chunks and pass each of them to a core but as you probably can tell my understanding of all this is pretty low. I am have a total of 32 cores at my disposition. Does anyone know why I have this problem and maybe also a way to solve it ? I know that reproducible examples are desired, but the function I use is pretty long and I doubt anyone is going to work through it. Still, if I can help make things clearer by providing additional information I will be glad to do so! Any type of help is greatly appreciated. Thanks in advance! EDIT: I forgot to add that when I look at the list it is nested, so I don't get one element for every number in the vector but I get one element with multiple sub-elements. Just in case that helps. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] BesselK dll file use in VBA
Hi Team, I want to use R's Bessel dll file in VBA. Can anyone help with the commands? Have you used it? Regards, Gaurang Mehta This email is intended for the person or company named and access by anyone else is unauthorised. If you are not the person or company named, please delete this email and notify the sender. The information in this email, including any attachments, may be confidential or legally privileged (meaning that its disclosure is protected in law). Its unauthorised disclosure, copying, distribution or use is prohibited and may be unlawful. Email communications sent over the internet are not guaranteed to be secure or virus-free and such messages are potentially at risk. The Royal London Group accepts no liability for any claims arising from use of the internet to transmit messages by or to any company within the Royal London Group. The Royal London Group consists of The Royal London Mutual Insurance Society Limited and its subsidiaries. The Royal London Mutual Insurance Society Limited is authorised by the Prudential Regulation Authority and regulated by the Financial Conduct Authority and the Prudential Regulation Authority and provides life assurance and pensions. Registered in England and Wales number 99064. Registered office: 55 Gracechurch Street, London, EC3V 0RL. In the Republic of Ireland: The Royal London Mutual Insurance Society Limited is authorised by the Prudential Regulation Authority in the UK and is regulated by the Central Bank of Ireland for conduct of business rules. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] dplyr : row total for all groups in dplyr summarise
Sorry, what I wanted to do was to add a total row at the end of the summary. The marginal totals by columns correspond to 100% and the sum of levels. best reagard Maicel Monzon Ulrik Stervboescribió: Yes. But in the sample code the data is summarised. In which case you get 4 rows and not the correct 32. On Tue, 5 Jul 2016, 07:48 David Winsemius, wrote: nrow(mtcars) Sent from my iPhone On Jul 4, 2016, at 9:03 PM, Ulrik Stervbo wrote: That will give you the wrong result when used on summarised data David Winsemius schrieb am Di., 5. Juli 2016 02:10: I thought there was an nrow() function? Sent from my iPhone On Jul 4, 2016, at 9:59 AM, Ulrik Stervbo wrote: If you want the total number of rows in the original data.frame after counting the rows in each group, you can ungroup and sum the row counts, like: library("dplyr") mtcars %>% group_by (am, gear) %>% summarise (n=n()) %>% mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) %>% ungroup() %>% mutate(row.tot = sum(n)) HTH Ulrik On Mon, 4 Jul 2016 at 18:23 David Winsemius wrote: > On Jul 4, 2016, at 6:56 AM, mai...@infomed.sld.cu wrote: > > Hello, > How can I aggregate row total for all groups in dplyr summarise ? Row total ? of what? Aggregate ? how? What is the desired answer? > library(dplyr) > mtcars %>% > group_by (am, gear) %>% > summarise (n=n()) %>% > mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) > > best regard > Maicel Monzon > > > > > > > > > -- > Este mensaje le ha llegado mediante el servicio de correo electronico que ofrece Infomed para respaldar el cumplimiento de las misiones del Sistema Nacional de Salud. La persona que envia este correo asume el compromiso de usar el servicio a tales fines y cumplir con las regulaciones establecidas > > Infomed: http://www.sld.cu/ > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Este mensaje le ha llegado mediante el servicio de correo electronico que ofrece Infomed para respaldar el cumplimiento de las misiones del Sistema Nacional de Salud. La persona que envia este correo asume el compromiso de usar el servicio a tales fines y cumplir con las regulaciones establecidas Infomed: http://www.sld.cu/ __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R-3.3.1 RPM release
> On Jul 4, 2016, at 9:37 AM, Sangalli Cristiano Giovanni (Ext. - UniCredit > Business Integrated Solutions)wrote: > > Dear CRAN, > > I have installed on a RHEL 5.7 server the recent R-3.3.0 rpm but I would like > to upgrade to the latest now available R-3.3.1 . I have not found so far the > rpm, I would like to know if and when it will be available? > > Thanks in advance, > Cris > Hi, The CRAN team does not build RPMs for RH and Fedora, that is done via RH maintainers and released via the EPEL: https://fedoraproject.org/wiki/EPEL As an FYI, there is a dedicated SIG list for R on RH/Fedora and the RH maintainers (e.g. Tom Callaway) read that list: https://stat.ethz.ch/mailman/listinfo/r-sig-fedora You should post there and Tom can provide a sense of when 3.3.1 will be made available. At present, there is no indication that 3.3.1 is in the R build queue, which can be viewed at: https://bodhi.fedoraproject.org/updates/?packages=R Regards, Marc Schwartz __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Antwort: Re: dplyr : row total for all groups in dplyr summarise
Hi guys, I checked out your example but I can't follow the results.: > mtcars %>% + group_by (am, gear) %>% + summarise (n=n()) %>% + mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) %>% + ungroup() %>% + mutate(row.tot = sum(n)) Source: local data frame [4 x 5] am gear n rel.freq row.tot (dbl) (dbl) (int)(chr) (int) 1 0 315 79% 32 2 0 4 4 21% 32 3 1 4 8 62% 32 4 1 5 5 38% 32 We have a total of 32 cases and 15 * 100 / 32 = 48,9 % instead of 79 %. The same with the other columns. How is 79 % calculated? When searching the web I saw this example: -- cut -- #-- not run -- url <- "http://www.lock5stat.com/datasets/HollywoodMovies2011.csv; response <- GET(url) Hollywoodmovies2011 <- content(x = GET(url), as = data.frame) #-- end not run Hollywoodmovies2011 %>% group_by(genre) %>% summarize(count = n()) %>% mutate(rf = count / sum(count)) -- cut -- which gives Source: local data frame [9 x 3] Genre count % (fctr) (int) (dbl) 1Action32 0.235294118 2 Adventure 1 0.007352941 3 Animation12 0.088235294 4Comedy27 0.198529412 5 Drama21 0.154411765 6 Fantasy 2 0.014705882 7Horror17 0.12500 8 Romance11 0.080882353 9 Thriller13 0.095588235 Here the % correspond to the count and the sum of count, e. g. sum = 136 and 32 / 136 = 0,2352941. What is the difference when counting? What do the relative counts in the first example mean? Kind regards Georg Von:Ulrik StervboAn: David Winsemius , Kopie: r-help@r-project.org, mai...@infomed.sld.cu Datum: 05.07.2016 06:06 Betreff:Re: [R] dplyr : row total for all groups in dplyr summarise Gesendet von: "R-help" That will give you the wrong result when used on summarised data David Winsemius schrieb am Di., 5. Juli 2016 02:10: > I thought there was an nrow() function? > > Sent from my iPhone > > On Jul 4, 2016, at 9:59 AM, Ulrik Stervbo wrote: > > If you want the total number of rows in the original data.frame after > counting the rows in each group, you can ungroup and sum the row counts, > like: > > library("dplyr") > > > mtcars %>% >group_by (am, gear) %>% >summarise (n=n()) %>% >mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) %>% >ungroup() %>% >mutate(row.tot = sum(n)) > > HTH > Ulrik > > On Mon, 4 Jul 2016 at 18:23 David Winsemius > wrote: > >> >> > On Jul 4, 2016, at 6:56 AM, mai...@infomed.sld.cu wrote: >> > >> > Hello, >> > How can I aggregate row total for all groups in dplyr summarise ? >> >> Row total … of what? Aggregate … how? What is the desired answer? >> >> >> >> > library(dplyr) >> > mtcars %>% >> > group_by (am, gear) %>% >> > summarise (n=n()) %>% >> > mutate(rel.freq = paste0(round(100 * n/sum(n), 0), "%")) >> > >> > best regard >> > Maicel Monzon >> > >> > >> > >> > >> > >> > >> > >> > >> > -- >> > Este mensaje le ha llegado mediante el servicio de correo electronico >> que ofrece Infomed para respaldar el cumplimiento de las misiones del >> Sistema Nacional de Salud. La persona que envia este correo asume el >> compromiso de usar el servicio a tales fines y cumplir con las regulaciones >> establecidas >> > >> > Infomed: http://www.sld.cu/ >> > >> > __ >> > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> > https://stat.ethz.ch/mailman/listinfo/r-help >> > PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> > and provide commented, minimal, self-contained, reproducible code. >> >> __ >> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. > > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.