[R] Major difference in multivariate analyses SPSS and R

2008-08-04 Thread Draga, R.
Dear colleagues,

 

I know SPSS can not compute linear mixed models. I used 'R' before for
computing multivariate analyses. But, I never encountered such a major
difference in outcome between SPSS and 'R':

 

In SPSS the Pearson correlation between variable 1 and variable 2 is 31%
p0.001.

 

In SPSS binary logistic regression gives us an Odds Ratio (OR)=4.9 (95%
CI 2.7-9.0), p0.001, n=338.

OR  lower   upper

gender  1,120   0,565   2,221

age   0,985   0,956   1,015

variable 2 4,937   2,698   9,032

 

In R multilevel logistic regression using statistical package 'lmer'
gives us an Odds Ratio=10.2 (95% CI 6.3-14), p=0.24, n=338, groups:
group 1, 98; group 2 84.

   OR   lower   upper

gender 2,295-2,840 7,430

age  0,003-70,047   70,054

variable 2 10,176 6,295   14,056

 

The crosstabs gives us:

 variable A

Var B  0   1

0 156 108

1  17  57

 

Would somebody know how it is possible that in SPSS we get p0.001 and
in R we get p=0.24?

And, in 'R' the 95% CI of the Odds Ratio is 6.2-14.1. Why is the
p-value=0.24?

 

Thanks, 

 

Ronald


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[R] Major difference in the outcome between SPSS and R statistical programs

2008-08-01 Thread Draga, R.
Dear collegues,
 
I have used R statistical program, package 'lmer', several times
already.
I never encountered major differences in the outcome between SPSS and R.
...untill my last analyses.
 
Would some know were the huge differences come from.
 
Thanks in advance, Ronald
 
In SPSS the Pearson correlation between variable 1 and variable 2 is 31%
p0.001.

 

In SPSS binary logistic regression gives us an OR=4.9 (95% CI 2.7-9.0),
p0.001, n=338.

OR  lower   upper

gender  1,120   0,565   2,221

age   0,985   0,956   1,015

variable 2 4,937   2,698   9,032

 

In R multilevel logistic regression using statistical package 'lmer'
gives us an OR=10.2 (95% CI 6.3-14), p=0.24, n=338, groups: group 1, 98;
group 2 84.

   OR   lower   upper

gender 2,295-2,840 7,430

age  0,003-70,047   70,054

variable 2 10,176 6,295   14,056

 

The crosstabs gives us:

 variable A

Var B  0   1

0 156 108

1  17  57

 

Would somebody know how it is possible that in SPSS we get p0.001 and
in R we get p=0.24?


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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.