[R] start values for random effects in nlme

2018-01-03 Thread Jos Lommerse
Hi Lindsey,

Yeah, I do realize that this answer gets to you 12 years too late, however, it 
may be helpful to others in future.
I have been struggling with the same issue. When analysing the source code 
(https://svn.r-project.org/R-packages/trunk/nlme/R/nlme.R)
I found out that the E matrix needs rownames referring to the random effect of 
each group in the dataset, something like:
rownames(E) <- c("subjectname1","subjectname2","subjectname3",.).
Then your code should run perfectly OK.

Example:
--
library(nlme)

data <- data.frame(a=c(1,2,3,4,5,1,2,3,4,5,1,2,3,4,5),
   b=c(2,3,4,5,7,3,4,5,7,8,3,5,6,8,9),
   ID=c(rep('X',5),rep('Y',5),rep('Z',5)))

# Random effect matrix E:
E <- as.matrix(c(-0.1,0.2,0.3))
rownames(E) <- c('X','Y','Z')
fm1 <- nlme(b ~ par1*a + par2*exp(IIV),
data = data,
fixed = list(par1 ~ 1, par2 ~ 1),
random = IIV ~ 1 | ID,
start = list(fixed = c(1,1), random= E))
summary(fm1)
-

Kind regards,
Jos Lommerse, Certara


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[R] raster package: OpenStreetMap broken on Ubuntu, works on Mac

2013-09-21 Thread jos
Hi,
I'm a novice in R and I was trying to play with OpenStreetMap package as in a 
few examples on the web. And the examples worked on my Mac but on Ubuntu 
(12.04) they fail to work. The simplest one is:

library(OpenStreetMap)
library(rgdal)
map - openmap(c(70,-179), c(-70,179))
plot(map)

(OpenStreetMap, rgdal, rJava etc..) packages have to be installed first.

On the Mac - it worked without any problems from the first try (shows a picture 
of world map). On Ubuntu, I get:

'merge' is not an exported object from 'namespace:raster'

when I execute the openmap function.

Now, at first I thought that the problem was in different library versions and 
it was quite a pain to make ubuntu install everything I wanted (rgdal being the 
biggest - unless one knows exactly what to look for on the internet, 
instructions are vague and there is a lot of outdated versions out there). But 
even after that, when version numbers matched on both OSes in R console, it 
still failed to work on Ubuntu. So the versions are:



library(rgdal)
Loading required package: sp
rgdal: version: 0.8-11, (SVN revision 479M)
Geospatial Data Abstraction Library extensions to R successfully loaded
Loaded GDAL runtime: GDAL 1.9.2, released 2012/10/08
Path to GDAL shared files: /usr/local/share/gdal
Loaded PROJ.4 runtime: Rel. 4.8.0, 6 March 2012, [PJ_VERSION: 480]
Path to PROJ.4 shared files: (autodetected)



Still didn't work with identical output on both machines. Then I thought that 
the problem must be in raster library, but both have the same version number:


packageVersion(raster)
[1] ‘2.1.49’

but after showing all the functions in raster package, although both have 235 
elements:


basevals - ls(pos=package:raster)
basevals


the Mac one has merge listed and Ubuntu - doesn't. Also on Mac, the array 
begins with %in% and on Ubuntu with addLayer... so there is more than one 
inconsistency and merge is actually breaking openmap().

My questions are:
*is this a bug?
*is there a workaround (eg. can I export merge from raster namespace myself 
by copying potentially the code from Mac)?


Thanks in advance,

J

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[R] r help: source-function is very slow

2012-01-19 Thread Jos van Nijnatten
Hello everybody,
I noticed a performance problem when using the source-function in R. 
When I try to source an r script that is located in the same directory 
as the script I execute via command line ('R -f file.r' contents 
'source(someOtherScript.r)') it's very fast. But if I put 
'someOtherScript.r' in another directory (say ../../R) R takes moments, 
if not minutes to locate and load the script. Is there another way to do 
this that is not slow?
Thanks, Jos

-- 
Jos van Nijnatten, BSc Candidate
Erasmus MC, Rotterdam, NL
Department of Bioinformatics
(ph) +31 1 07 04 45 51
(mob) +31 6 14 92 14 01
(e) j.vannijnat...@erasmusmc.nl

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Re: [R] r help: source-function is very slow

2012-01-19 Thread Jos van Nijnatten

Hello Uwe, Duncan and the rest of the community,
It indeed seemed to be a file system problem and I'm lucky to figure 
that out before it crashed. New computer's great and everything is 
working fine again.

Sorry for wasting your time ;-)


On Thursday, January 19, 2012 15:16, Duncan Murdoch wrote:

On 12-01-19 8:25 AM, Jos van Nijnatten wrote:

Hello everybody,
I noticed a performance problem when using the source-function in R.
When I try to source an r script that is located in the same directory
as the script I execute via command line ('R -f file.r' contents
'source(someOtherScript.r)') it's very fast. But if I put
'someOtherScript.r' in another directory (say ../../R) R takes moments,
if not minutes to locate and load the script. Is there another way to do
this that is not slow?


R uses the same method in both instances. If there's a difference in 
timing, it's almost certainly because there's something going on with 
your OS or file system.


Duncan Murdoch




--
Jos van Nijnatten, BSc Candidate
Erasmus MC, Rotterdam, NL
Department of Bioinformatics
(ph) +31 1 07 04 45 51
(mob) +31 6 14 92 14 01
(e) j.vannijnat...@erasmusmc.nl

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[R] Rmpi installation problems

2011-12-02 Thread Jos Elkink
Hi all,

I am trying to install the Rmpi package in R and, while the installation
itself works, it breaks down when trying to load the library. I think it
has something to do with shared vs static loading of helper libraries,
or the order in which shared libraries are loaded, but I am not sure.

R version: 2.14.0
Linux version: Gentoo, i686-pc-linux-gnu (32-bit)
GCC version: 4.5.3 (Gentoo 4.5.3-r1 p1.0)
OpenMPI version: 1.5.4

Output from R CMD INSTALL . in Rmpi source directory:

* installing to library ‘/home/jos/R/i686-pc-linux-gnu-library/2.14’
* installing *source* package ‘Rmpi’ ...
checking for gcc... i686-pc-linux-gnu-gcc -std=gnu99
checking for C compiler default output file name... a.out
checking whether the C compiler works... yes
checking whether we are cross compiling... no
checking for suffix of executables... 
checking for suffix of object files... o
checking whether we are using the GNU C compiler... yes
checking whether i686-pc-linux-gnu-gcc -std=gnu99 accepts -g... yes
checking for i686-pc-linux-gnu-gcc -std=gnu99 option to accept ISO C89... none 
needed
I am here /usr and it is OpenMPI
Trying to find mpi.h ...
Found in /usr/include
Trying to find libmpi.so or libmpich.a ...
Found libmpi in /usr/lib
checking for openpty in -lutil... yes
checking for main in -lpthread... yes
configure: creating ./config.status
config.status: creating src/Makevars
** Creating default NAMESPACE file
** libs
make: Nothing to be done for `all'.
installing to /home/jos/R/i686-pc-linux-gnu-library/2.14/Rmpi/libs
** R
** demo
** inst
** preparing package for lazy loading
** help
*** installing help indices
** building package indices ...
** testing if installed package can be loaded
/usr/lib/R/bin/exec/R: symbol lookup error: 
/usr/lib/openmpi/mca_paffinity_hwloc.so: undefined symbol: 
mca_base_param_reg_int
ERROR: loading failed
* removing ‘/home/jos/R/i686-pc-linux-gnu-library/2.14/Rmpi’

Any help would be greatly appreciated!

Jos

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[R] (svy)glm and weights question

2010-05-11 Thread Jos Elkink
Hi all,

I am running a set of logistic regressions, where we want to use some
weights, and I am not sure whether what I am doing is reasonable or
not.

The dependent variable is turnout in an election - i.e. survey
respondents were asked whether or not they voted. The percentage of
those who say they voted is much higher than the actual turnout,
probably due both to non-response bias and social desirability issues.
So now the suggestion is to weigh the cases, to weigh down the
respondents who say they voted and weigh more heavily those who did
say they did not vote. So the questions that arise from this are:

1) Is it reasonable to use the distribution of the dependent variable
to calculate the weights used in a logistic regression? It feels
wrong, but I cannot find, so far, any sources on this.

2) How to implement this in R? I tried the weights option in glm(),
but I think that is meant for when you have one row in your data for
multiple observations, not for this kind of weight. Although I have
the McCullagh and Nelder book explaining in detail how glm() operates,
I cannot find a similar book for svyglm(). Is svyglm() better for this
type of weighting?

3) Where would I find a good source describing the estimation
procedure, including weighting, applied in svyglm()?

Thanks in advance for any help!

Jos

-- 
Johan A. Elkink
Lecturer in Social Science Research Methods
School of Politics and International Relations  CHS Graduate School
University College Dublin
Ph. +353 1 716 8150  |  Newman Building, Rm F304
http://jaeweb.cantr.net

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[R] sample unique pairs from a matrix

2009-05-28 Thread jos matejus
Dear R users,

I have a matrix of both negative and positive values that I would like
to randomly sample with the following 2 conditions:

1. only sample positive values
2. once a cell in the matrix has been sampled the row and column of
that cell cannot be sampled from again.

#some dummy data
set.seed(101)
dataf - matrix(rnorm(36,1,2), nrow=6)

I can do this quite simply if all the values are positive by using the
sample function without replacement on the column and row indices.

samrow - sample(6,replace=F)
samcol - sample(6,replace=F)
values - numeric(6)
for(i in 1:6){
values[i] - dataf[samrow[i], samcol[i]]
}

However, I am not sure how to include the logical condition to only
include postitive values
Any help would be gratefully received.
Jos

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Re: [R] sample unique pairs from a matrix

2009-05-28 Thread jos matejus
Dear Ritchie and David,

Thanks very much for your advice. I had thought of this potential
solution, however it doesn't really fullfill my second criteria which
is that once a particular cell has been sampled, the row and column of
that cell can't be sampled from subsequently. In other words, the next
sample would be taken from a 5x5 matrix, and then a 4x4 matrix and so
on until I have my 6 values.

I will keep thinking!
Cheers
Jos

2009/5/28 David Winsemius dwinsem...@comcast.net:

 On May 28, 2009, at 6:33 AM, jos matejus wrote:

 Dear R users,

 I have a matrix of both negative and positive values that I would like
 to randomly sample with the following 2 conditions:

 1. only sample positive values
 2. once a cell in the matrix has been sampled the row and column of
 that cell cannot be sampled from again.

 #some dummy data
 set.seed(101)
 dataf - matrix(rnorm(36,1,2), nrow=6)

 I can do this quite simply if all the values are positive by using the
 sample function without replacement on the column and row indices.

 samrow - sample(6,replace=F)
 samcol - sample(6,replace=F)
 values - numeric(6)
 for(i in 1:6){
        values[i] - dataf[samrow[i], samcol[i]]
 }

 However, I am not sure how to include the logical condition to only
 include postitive values
 Any help would be gratefully received.
 Jos

 M - matrix(rnorm(36),nrow=6)

 M[M[,]0]
  [1] 1.65619781 0.56182830 0.23812890 0.81493915 1.01279243 1.29188874
 0.64252343 0.53748655 0.31503112
 [10] 0.37245358 0.07942883 0.56834586 0.62200056 0.39478167 0.02374574
 0.04974857 0.56219171 0.52901658


 sample(M[M[,]0],6,replace=F)
 [1] 0.56834586 0.07942883 0.31503112 0.62200056 0.02374574 0.64252343

 --
 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT



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Re: [R] sample unique pairs from a matrix

2009-05-28 Thread jos matejus
Dear All,

Many thanks for all your useful suggestions. Much appreciated.

Jos

2009/5/28 David Winsemius dwinsem...@comcast.net:
 Your last step will either be a single number (not really a sampling
 operation) or a
 non-positive number. So at best you really only have an number that depends
 entirely on the prior sequence of draws.

 --
 David.

 On May 28, 2009, at 8:21 AM, jos matejus wrote:

 Dear Ritchie and David,

 Thanks very much for your advice. I had thought of this potential
 solution, however it doesn't really fullfill my second criteria which
 is that once a particular cell has been sampled, the row and column of
 that cell can't be sampled from subsequently. In other words, the next
 sample would be taken from a 5x5 matrix, and then a 4x4 matrix and so
 on until I have my 6 values.

 I will keep thinking!
 Cheers
 Jos

 2009/5/28 David Winsemius dwinsem...@comcast.net:

 On May 28, 2009, at 6:33 AM, jos matejus wrote:

 Dear R users,

 I have a matrix of both negative and positive values that I would like
 to randomly sample with the following 2 conditions:

 1. only sample positive values
 2. once a cell in the matrix has been sampled the row and column of
 that cell cannot be sampled from again.

 #some dummy data
 set.seed(101)
 dataf - matrix(rnorm(36,1,2), nrow=6)

 I can do this quite simply if all the values are positive by using the
 sample function without replacement on the column and row indices.

 samrow - sample(6,replace=F)
 samcol - sample(6,replace=F)
 values - numeric(6)
 for(i in 1:6){
   values[i] - dataf[samrow[i], samcol[i]]
 }

 However, I am not sure how to include the logical condition to only
 include postitive values
 Any help would be gratefully received.
 Jos

 M - matrix(rnorm(36),nrow=6)

 M[M[,]0]

  [1] 1.65619781 0.56182830 0.23812890 0.81493915 1.01279243 1.29188874
 0.64252343 0.53748655 0.31503112
 [10] 0.37245358 0.07942883 0.56834586 0.62200056 0.39478167 0.02374574
 0.04974857 0.56219171 0.52901658


 sample(M[M[,]0],6,replace=F)

 [1] 0.56834586 0.07942883 0.31503112 0.62200056 0.02374574 0.64252343

 --
 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT



 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT



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[R] reference category for factor in regression

2009-01-19 Thread Jos Elkink
Hi all,

I am struggling with a strange issue in R that I have not encountered
before and I am not sure how to resolve this.

The model looks like this, with all irrelevant variables left out:

LABOUR - a dummy variable
NONLABOUR = 1 - LABOUR
AGE - a categorical variable / factor
VOTE - a dummy variable

glm(VOTE ~ 0 + LABOUR + NONLABOUR + LABOUR : AGE + NONLABOUR : AGE,
family=binomial(link=logit))

In other words, a standard interaction model, but I want to know the
intercepts and coefficients for each of the two cases (LABOUR and
NONLABOUR), instead of getting coefficients for the differences as in
a normal interaction model.

But the strange thing is, for the two occurances of the AGE variable,
it makes a different choice as to which AGE category to leave out of
the regression. The cross-table of AGE with LABOUR does not have empty
cells.

Anyone any idea what might be going wrong? Or what I could do about this?

Thanks in advance for any help!

Regards,

Jos

-- 
Johan A. Elkink
Lecturer
School of Politics and International Relations  CHS Graduate School
University College Dublin
Ph. +353 1 716 7026  |  Library Building, Rm 512
http://jaeweb.cantr.net

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Re: [R] reference category for factor in regression

2009-01-19 Thread Jos Elkink
Hi Thierry,

Thanks for your quick answer. The problem is not so much the LABOUR
variable, however, but the AGE variable, which consists of about 5
categories for which I do indeed not create separate dummy variables.
But R does not behave as expected when deciding on which dummy to use
as reference category ...

Jos

On Mon, Jan 19, 2009 at 2:37 PM, ONKELINX, Thierry
thierry.onkel...@inbo.be wrote:
 Dear Jos,

 In R you don't need to create you own dummy variables. Just create a
 factor variable LABOUR (with two levels) and rerun your model. Then you
 should be able to calculate all coefficients.

 HTH,

 Thierry

 
 
 ir. Thierry Onkelinx
 Instituut voor natuur- en bosonderzoek / Research Institute for Nature
 and Forest
 Cel biometrie, methodologie en kwaliteitszorg / Section biometrics,
 methodology and quality assurance
 Gaverstraat 4
 9500 Geraardsbergen
 Belgium
 tel. + 32 54/436 185
 thierry.onkel...@inbo.be
 www.inbo.be

 To call in the statistician after the experiment is done may be no more
 than asking him to perform a post-mortem examination: he may be able to
 say what the experiment died of.
 ~ Sir Ronald Aylmer Fisher

 The plural of anecdote is not data.
 ~ Roger Brinner

 The combination of some data and an aching desire for an answer does not
 ensure that a reasonable answer can be extracted from a given body of
 data.
 ~ John Tukey

 -Oorspronkelijk bericht-
 Van: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
 Namens Jos Elkink
 Verzonden: maandag 19 januari 2009 15:16
 Aan: r-help@r-project.org
 Onderwerp: [R] reference category for factor in regression

 Hi all,

 I am struggling with a strange issue in R that I have not encountered
 before and I am not sure how to resolve this.

 The model looks like this, with all irrelevant variables left out:

 LABOUR - a dummy variable
 NONLABOUR = 1 - LABOUR
 AGE - a categorical variable / factor
 VOTE - a dummy variable

 glm(VOTE ~ 0 + LABOUR + NONLABOUR + LABOUR : AGE + NONLABOUR : AGE,
 family=binomial(link=logit))

 In other words, a standard interaction model, but I want to know the
 intercepts and coefficients for each of the two cases (LABOUR and
 NONLABOUR), instead of getting coefficients for the differences as in
 a normal interaction model.

 But the strange thing is, for the two occurances of the AGE variable,
 it makes a different choice as to which AGE category to leave out of
 the regression. The cross-table of AGE with LABOUR does not have empty
 cells.

 Anyone any idea what might be going wrong? Or what I could do about
 this?

 Thanks in advance for any help!

 Regards,

 Jos

 --
 Johan A. Elkink
 Lecturer
 School of Politics and International Relations  CHS Graduate School
 University College Dublin
 Ph. +353 1 716 7026  |  Library Building, Rm 512
 http://jaeweb.cantr.net

 __
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 en binden het INBO onder geen enkel beding, zolang dit bericht niet bevestigd 
 is
 door een geldig ondertekend document. The views expressed in  this message
 and any annex are purely those of the writer and may not be regarded as 
 stating
 an official position of INBO, as long as the message is not confirmed by a 
 duly
 signed document.




-- 
Johan A. Elkink
Lecturer
School of Politics and International Relations  CHS Graduate School
University College Dublin
Ph. +353 1 716 7026  |  Library Building, Rm 512
http://jaeweb.cantr.net

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Re: [R] reference category for factor in regression

2009-01-19 Thread Jos Elkink
Hi all,

Thanks for the advice.

 See ?relevel for information on how to reorder the levels of a factor,
 while being able to specify the reference level.
 Basically, the first level of the factor is taken as the reference.

Yes, that is how I always used it. But the problem is, in this
particular regression R does *not* take the first level as reference.
In fact, AGE appears twice in the same regression (two different
interactions) and in one case it selects the 1st category and in
another case a different one.

 BTW, you might want to review Frank Harrell's page on why categorizing a
 continuous variable is not a good idea:

I most certainly agree, but the categorisation has been imposed in the
survey itself, so it is all the data I have. I did not design the
questions :-) ... Thanks for this reference, though, as it is
certainly interesting to inform my teaching.

 str(AGE)
 Factor w/ 5 levels 65+,18-24,..: 5 5 1 4 5 5 2 4 1 3 ...

So I expect 65+ to be the reference category, but it is not.

Here is a little bit more R code to show the problem:

 str(AGE)
 Factor w/ 5 levels 65+,18-24,..: 5 5 1 4 5 5 2 4 1 3 ...
 table(LABOUR)
LABOUR
   01
 692 1409
 NONLABOUR - 1 - LABOUR
 m - glm(NOVOTE ~ 0 + LABOUR + NONLABOUR + AGE : LABOUR + AGE : NONLABOUR, 
 family=binomial)
 m

Call:  glm(formula = NOVOTE ~ 0 + LABOUR + NONLABOUR + AGE:LABOUR +
  AGE:NONLABOUR, family = binomial)

Coefficients:
LABOUR   NONLABOUR   LABOUR:AGE65+ LABOUR:AGE18-24
  -0.35110-0.30486-0.11890-0.66444
   LABOUR:AGE25-34 LABOUR:AGE35-49 LABOUR:AGE50-64  NONLABOUR:AGE18-24
  -0.23893-0.15860  NA-0.65655
NONLABOUR:AGE25-34  NONLABOUR:AGE35-49  NONLABOUR:AGE50-64
  -0.72815 0.04951 0.17481

As you can see, 65+ is taken as reference category in the interaction
with NONLABOUR, but not in the interaction with LABOUR.

I know glm(NOVOTE ~ LABOUR * AGE, family=binomial) would be a more
conventional specification, but the above should be equivalent and
should give me the coefficients and standard errors for the two groups
(LABOUR and NONLABOUR) separately, rather than for the difference /
interaction term).

Perhaps the NA in the above output (which I only notice now) is a hint
at the problem, but I am not sure why that occurs.

 table(m$model$AGE, m$model$LABOUR, m$model$NOVOTE)
, ,  = 0


  0   1
  65+   137  24
  18-24  68 127
  25-34  59 267
  35-49  71 298
  50-64  82 179

, ,  = 1


  0   1
  65+   101  15
  18-24  26  46
  25-34  21 148
  35-49  55 179
  50-64  72 126

Anyone any idea? So there must be a reason R decides *not* to use 65+
as reference in that particular scenario, and I am missing why.

Jos

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[R] Port package

2008-07-09 Thread Jos Kaefer
Hi

When I type:
 ?nls

I come across this section:

algorithm: character string specifying the algorithm to use. The
  default algorithm is a Gauss-Newton algorithm.  Other
  possible values are 'plinear' for the Golub-Pereyra
  algorithm for partially linear least-squares models and
  'port' for the 'nl2sol' algorithm from the Port package.

The simple question is: where's the Port package?
I can't find it on cran.

Thanks,
Jos

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