[R] Joining elements of an array into a single element

2010-03-10 Thread vega_l
Dear forum:

I've been trying like for hours but I cannot solve this. I wonder if you could 
give me a hand.

I would like to combine the following elements of an array which I must 
generate in order to get the syntax I need for another software, lets say:

c-c(1:7)
zest-c(12,34,45,132,56,23,6)
p-[foresnat2]

for(i in 1:7){tre[i]-paste(con(,p, == ,c[i],, ,zest[i],, ,sep=)}

[1] con([foresnat2] == 1, 12, 
[1] con([foresnat2] == 2, 34, 
[1] con([foresnat2] == 3, 45, 
[1] con([foresnat2] == 4, 132, 
[1] con([foresnat2] == 5, 56, 
[1] con([foresnat2] == 6, 23, 
[1] con([foresnat2] == 7, 6, 

I would like the elements of the object tre to go one after another without 
space (or with a character I design like for example * or + )like this:

[1] con([foresnat2] == 1, 12, con([foresnat2] == 2, 34, con([foresnat2] == 3, 
45, con... etc

I understand it could be done with the function paste invoking each of the 
elements, but lets say they are not only 7 but 20 or 40 elements...

Is it possible? What can I do?

Thank you very much in advance.

Luis Vega

PD: Just in case:  For the other software language i was talking about, the 
usage of con is the same as ifelse in R, I'm trying to generate
 a large embed ifelse(..., ..., ifelse(...,...,ifelse(   entry. but with 
what I'm requiring lines above should be enough I think.





  


  
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Re: [R] Joining elements of an array into a single element

2010-03-10 Thread vega_l
Thank you very much Miguel ! I couldn't believe it was that easy.

Luis Vega.

--- On Wed, 3/10/10, Miguel Porto mpbert...@gmail.com wrote:

From: Miguel Porto mpbert...@gmail.com
Subject: Re: [R] Joining elements of an array into a single element
To: veg...@yahoo.com
Cc: r-help@r-project.org
Date: Wednesday, March 10, 2010, 8:57 PM

Hello,If you do this after the for loop, you'll get what you want:
paste(tre,collapse=)
(you can use whatever separator you want in the collapse argument)

But you don't even need the for loop, just do this instead of the for loop:
paste(con(,p, == ,c,, ,zest,, ,sep=,collapse=)

Best,Miguel



On Wed, Mar 10, 2010 at 11:44 AM,  veg...@yahoo.com wrote:

Dear forum:



I've been trying like for hours but I cannot solve this. I wonder if you could 
give me a hand.



I would like to combine the following elements of an array which I must 
generate in order to get the syntax I need for another software, lets say:



c-c(1:7)

zest-c(12,34,45,132,56,23,6)

p-[foresnat2]



for(i in 1:7){tre[i]-paste(con(,p, == ,c[i],, ,zest[i],, ,sep=)}



[1] con([foresnat2] == 1, 12, 

[1] con([foresnat2] == 2, 34, 

[1] con([foresnat2] == 3, 45, 

[1] con([foresnat2] == 4, 132, 

[1] con([foresnat2] == 5, 56, 

[1] con([foresnat2] == 6, 23, 

[1] con([foresnat2] == 7, 6, 



I would like the elements of the object tre to go one after another without 
space (or with a character I design like for example * or + )like this:



[1] con([foresnat2] == 1, 12, con([foresnat2] == 2, 34, con([foresnat2] == 3, 
45, con... etc



I understand it could be done with the function paste invoking each of the 
elements, but lets say they are not only 7 but 20 or 40 elements...



Is it possible? What can I do?



Thank you very much in advance.



Luis Vega



PD: Just in case:  For the other software language i was talking about, the 
usage of con is the same as ifelse in R, I'm trying to generate

 a large embed ifelse(..., ..., ifelse(...,...,ifelse(   entry. but with 
what I'm requiring lines above should be enough I think.



















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R-help@r-project.org mailing list

https://stat.ethz.ch/mailman/listinfo/r-help

PLEASE do read the posting guide http://www.R-project.org/posting-guide.html

and provide commented, minimal, self-contained, reproducible code.







  
[[alternative HTML version deleted]]

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.