Is this what you want:
x - read.table(textConnection('read no length
+ 2 2 144
+ 7 7 47490
+ 9 9 310944
+ 11 11 10089
+ 14 14 13152
+ 17 17 27363 '), header=TRUE)
closeAllConnections()
result - lapply(1:nrow(x), function(.indx){
+ data.frame(read=paste(x$read[.indx], seq(x$length[.indx] %/% 100
+ 1), sep=_),
+ no=rep(x$no[.indx], x$length[.indx] %/% 100 + 1),
+ length=c(rep(100, x$length[.indx] %/% 100), x$length[.indx] %% 100))
+ })
result - do.call(rbind, result)
str(result)
'data.frame': 4094 obs. of 3 variables:
$ read : Factor w/ 4094 levels 2_1,2_2,7_1,..: 1 2 3 114 225
336 423 434 445 456 ...
$ no: int 2 2 7 7 7 7 7 7 7 7 ...
$ length: num 100 44 100 100 100 100 100 100 100 100 ...
head(result)
read no length
1 2_1 2100
2 2_2 2 44
3 7_1 7100
4 7_2 7100
5 7_3 7100
6 7_4 7100
On Thu, Nov 27, 2008 at 5:16 AM, mitras [EMAIL PROTECTED] wrote:
Dear all,
I have one problem to handle a large dataset...
It looks like:
read no length
2 2 144
7 7 47490
9 9 310944
11 11 10089
14 14 13152
17 17 27363 and so on
There are 13 rows
From this table I need to make a table like
2_1 2 100
2_2 2 44
7_1 7 100
7_2 7 100
...
...
7_474 7 100
7_475 7 90
9_1 9 100
9_2 9 100 and so on...
In words: I want to divide the 3rd column by 100 to keep the length 100 and
increasing no of rows needed, where no will be same for all increased rows,
but the read will be changed like 2_1,2_2 and so on..
Please let me know if any one can help.
Thanks a lot in advance.
Best,
Mitra.
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What is the problem that you are trying to solve?
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