[R] match
Hi, I'm new about R. My problem is: I have 2 lists of proteins and I would compare them. I import the 2 lists like 2 different matrixs and I would that the first entry in the matrix 1 match with all entries of the matrix 2, then the second entry of the matrix 1 matchs with all entries of the matrix 2 and repeat this process with all entries of the matrix 1. Anybodies know can I do it? Thanks, Marco - Contatti *Mail: [EMAIL PROTECTED] [EMAIL PROTECTED] *Messanger: [EMAIL PROTECTED] *Skype: marpello *Sito: http://web.mac.com/marpello/iWeb/Sito/index.html __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] match
Hi, I would like to check which rows of 'types.prev' matrix pop up in 'types', following R in-built procedure. I tried 'match' function but it works in case of the one dimensional vectors. Will appreciate any suggestions. best, robert > types edateK [1,] 20060819 12.5 [2,] 20060819 17.5 [3,] 20060819 22.5 [4,] 20070217 12.5 [5,] 20060617 10.0 [6,] 20060617 15.0 [7,] 20060520 12.5 [8,] 20060520 15.0 [9,] 20060520 17.5 [10,] 20061118 10.0 [11,] 20061118 12.5 [12,] 20061118 15.0 [13,] 20061118 17.5 > types.prev edateK [1,] 20060819 10.0 [2,] 20060819 12.5 [3,] 20060819 17.5 [4,] 20070217 10.0 [5,] 20070217 12.5 [6,] 20070217 15.0 [7,] 20060617 10.0 [8,] 20060617 12.5 [9,] 20060617 15.0 [10,] 20060617 20.0 [11,] 20060520 10.0 [12,] 20060520 12.5 [13,] 20060520 17.5 [14,] 20061118 12.5 [15,] 20061118 15.0 [16,] 20061118 17.5 -- View this message in context: http://www.nabble.com/match-tp20799206p20799206.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] match
Can you provide an example of the input data and what you would like the output to be. When you say "first entry" is this a single cell, or the whole row? So an example would help to understand what you are after. On Nov 22, 2007 8:45 AM, Marco chiapello <[EMAIL PROTECTED]> wrote: > Hi, > I'm new about R. My problem is: > I have 2 lists of proteins and I would compare them. I import the 2 > lists like 2 different matrixs and I would that the first entry in the > matrix 1 match with all entries of the matrix 2, then the second entry > of the matrix 1 matchs with all entries of the matrix 2 and repeat > this process with all entries of the matrix 1. Anybodies know can I do > it? > Thanks, > Marco > - > Contatti > *Mail: > [EMAIL PROTECTED] > [EMAIL PROTECTED] > *Messanger: > [EMAIL PROTECTED] > *Skype: > marpello > *Sito: > http://web.mac.com/marpello/iWeb/Sito/index.html > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem you are trying to solve? __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] match
Tena koe Robert You could first apply paste apply(types, 1, paste, collapse=':') and then match. HTH Peter Alspach > -Original Message- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of threshold > Sent: Wednesday, 3 December 2008 8:32 a.m. > To: r-help@r-project.org > Subject: [R] match > > > Hi, I would like to check which rows of 'types.prev' matrix > pop up in 'types', following R in-built procedure. I tried > 'match' function but it works in case of the one dimensional vectors. > Will appreciate any suggestions. > best, robert > > > types > edateK > [1,] 20060819 12.5 > [2,] 20060819 17.5 > [3,] 20060819 22.5 > [4,] 20070217 12.5 > [5,] 20060617 10.0 > [6,] 20060617 15.0 > [7,] 20060520 12.5 > [8,] 20060520 15.0 > [9,] 20060520 17.5 > [10,] 20061118 10.0 > [11,] 20061118 12.5 > [12,] 20061118 15.0 > [13,] 20061118 17.5 > > > types.prev > edateK > [1,] 20060819 10.0 > [2,] 20060819 12.5 > [3,] 20060819 17.5 > [4,] 20070217 10.0 > [5,] 20070217 12.5 > [6,] 20070217 15.0 > [7,] 20060617 10.0 > [8,] 20060617 12.5 > [9,] 20060617 15.0 > [10,] 20060617 20.0 > [11,] 20060520 10.0 > [12,] 20060520 12.5 > [13,] 20060520 17.5 > [14,] 20061118 12.5 > [15,] 20061118 15.0 > [16,] 20061118 17.5 > > > -- > View this message in context: > http://www.nabble.com/match-tp20799206p20799206.html > Sent from the R help mailing list archive at Nabble.com. > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > The contents of this e-mail are confidential and may be subject to legal privilege. If you are not the intended recipient you must not use, disseminate, distribute or reproduce all or any part of this e-mail or attachments. If you have received this e-mail in error, please notify the sender and delete all material pertaining to this e-mail. Any opinion or views expressed in this e-mail are those of the individual sender and may not represent those of The New Zealand Institute for Plant and Food Research Limited. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] match() indexing
Hello, I'm trying to vectorize some assignment statements using match(), but can't seem to get it correct. I have 2 data frames each with a key column of unique values. I want to copy a column from one frame to another where the key values are the same. The data frames are not the same length, and the set of keys is non-overlapping (each frame has keys not in the other). Example: x <- data.frame(id=c(1,3,4,6,7,9,10), r=runif(7)) > x id r 1 1 0.4243219 2 3 0.2389127 3 4 0.7094532 4 6 0.2053836 5 7 0.9630027 6 9 0.1218458 7 10 0.9183175 > y <- data.frame(id=c(1,2,4,7,8,9,10,11,12)) > y id 1 1 2 2 3 4 4 7 5 8 6 9 7 10 8 11 9 12 I want to copy the x$r values to y to obtain >y idr 1 10.4243219 2 2NA 3 40.7094532 4 70.9630027 5 8NA 6 90.1218458 7 100.9183175 8 11NA 9 12NA xIdx <- match(x$id,y$id) yields a vector of length x, so it cannot be used directly to copy to y. Any help in vectorizing this assignment would be most welcome. Chris This e-mail, including attachments, may include confidential and/or proprietary information, and may be used only by the person or entity to which it is addressed. If the reader of this e-mail is not the intended recipient or his or her authorized agent, the reader is hereby notified that any dissemination, distribution or copying of this e-mail is prohibited. If you have received this e-mail in error, please notify the sender by replying to this message and delete this e-mail immediately. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] match and incomparables
Hello,
I was playing around with the newly implemented 'incomparables' argument
in 'match' and realized the argument does not behave anything like I
expected. Can someone explain what is going on here? Sorry if I'm
misreading the documentation.
> match(1:3, 1:3, incomparables=1)
[1] NA 2 3 # This seems right, the 1 in 'x' is 'incomparable'
> match(1:3, 1:3, incomparables=2)
[1] 1 2 3 # Shouldn't this be 1 NA 3? Why isn't the 2 incomparable?
> match(1:3, 1:3, incomparables=5)
[1] NA 2 3 # Why isn't the 5 ignored?
Note from ?match:
"incomparables: a vector of values that cannot be matched. Any value in
x matching a value in this vector is assigned the nomatch value. For
historical reasons, FALSE is equivalent to NULL."
Thanks in advance!
Robert
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status
major 2
minor 7.2
year 2008
month 08
day25
svn rev46428
language R
version.string R version 2.7.2 (2008-08-25)
Robert McGehee, CFA
Geode Capital Management, LLC
One Post Office Square, 28th Floor | Boston, MA | 02109
Tel: 617/392-8396Fax:617/476-6389
mailto:[EMAIL PROTECTED]
This e-mail, and any attachments hereto, are intended fo...{{dropped:12}}
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Re: [R] match() indexing
Dear Christopher, Try this: merge(x,y,all=TRUE) HTH, Jorge On Wed, Jul 1, 2009 at 2:51 PM, Hane, Christopher A < christopher.h...@ingenixconsulting.com> wrote: > > Hello, > > I'm trying to vectorize some assignment statements using match(), but > can't seem to get it correct. > > I have 2 data frames each with a key column of unique values. I want to > copy a column from one frame to another where the key values are the > same. The data frames are not the same length, and the set of keys is > non-overlapping (each frame has keys not in the other). > > Example: > x <- data.frame(id=c(1,3,4,6,7,9,10), r=runif(7)) > > x > id r > 1 1 0.4243219 > 2 3 0.2389127 > 3 4 0.7094532 > 4 6 0.2053836 > 5 7 0.9630027 > 6 9 0.1218458 > 7 10 0.9183175 > > y <- data.frame(id=c(1,2,4,7,8,9,10,11,12)) > > y > id > 1 1 > 2 2 > 3 4 > 4 7 > 5 8 > 6 9 > 7 10 > 8 11 > 9 12 > > I want to copy the x$r values to y to obtain > >y > idr > 1 10.4243219 > 2 2NA > 3 40.7094532 > 4 70.9630027 > 5 8NA > 6 90.1218458 > 7 100.9183175 > 8 11NA > 9 12NA > > xIdx <- match(x$id,y$id) yields a vector of length x, so it cannot be > used directly to copy to y. > > Any help in vectorizing this assignment would be most welcome. > > Chris > > This e-mail, including attachments, may include confidential and/or > proprietary information, and may be used only by the person or entity > to which it is addressed. If the reader of this e-mail is not the intended > recipient or his or her authorized agent, the reader is hereby notified > that any dissemination, distribution or copying of this e-mail is > prohibited. If you have received this e-mail in error, please notify the > sender by replying to this message and delete this e-mail immediately. > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] match and as.character truncation
I know the following is documented behaviour, in the sense that the help page for as.character mentions that it truncates at about 500 characters... but wouldn't it be better if there was a warning of some sort issued? Or am I misunderstanding what's happening here? > str <- sample(LETTERS,301, replace=TRUE) > search.list <- list(str[-301],str) > item <- list(str)# == search.list[2] > match(item, search.list) [1] 1 > item <- list(str[1:299]) > match(item, search.list) [1] 1 > item <- list(str[1:29]) > match(item, search.list) [1] NA > version$version.string [1] "R version 2.7.1 (2008-06-23)" Thanks. -Eric Weese PhD candidate, Economics MIT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] match problem by rownames
Hi all,
While dat['a1',] and dat['a10',] produce the same results in the
following example, I'd like dat['a1',] to return NAs.
dat <- data.frame(x1 = paste(letters[1:5],10, sep=''), x2=rnorm(5))
rownames(dat) <- dat$x1
dat['a1',]
dat['a10',]
> sessionInfo()
R version 2.7.2 (2008-08-25)
i386-pc-mingw32
locale:
LC_COLLATE=English_Australia.1252;LC_CTYPE=English_Australia.1252;LC_MON
ETARY=English_Australia.1252;LC_NUMERIC=C;LC_TIME=English_Australia.1252
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] lattice_0.17-13
loaded via a namespace (and not attached):
[1] grid_2.7.2
>
Regards,
Xianming
DISCLAIMER:\ For details of our e-mail disclaimer, pleas...{{dropped:15}}
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] match and incomparables
I can replicate this and also do not understand it.
match(1:3,1:3,incomparables=5)
[1] NA 2 3
match(1:3,1:3,incomparables=4)
[1] 1 2 3
match(1:3,1:3,incomparables=3)
[1] 1 2 3
match(1:3,1:3,incomparables=2)
[1] 1 2 3
match(1:3,1:3,incomparables=1)
[1] NA 2 3
...every other integer value for incomparables produces 1 2 and 3 for
output. I'm using R 2.7.2, self-compiled, under linux.
--Adam
On Fri, 12 Sep 2008, McGehee, Robert wrote:
Hello,
I was playing around with the newly implemented 'incomparables' argument
in 'match' and realized the argument does not behave anything like I
expected. Can someone explain what is going on here? Sorry if I'm
misreading the documentation.
match(1:3, 1:3, incomparables=1)
[1] NA 2 3 # This seems right, the 1 in 'x' is 'incomparable'
match(1:3, 1:3, incomparables=2)
[1] 1 2 3 # Shouldn't this be 1 NA 3? Why isn't the 2 incomparable?
match(1:3, 1:3, incomparables=5)
[1] NA 2 3 # Why isn't the 5 ignored?
Note from ?match:
"incomparables: a vector of values that cannot be matched. Any value in
x matching a value in this vector is assigned the nomatch value. For
historical reasons, FALSE is equivalent to NULL."
Thanks in advance!
Robert
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status
major 2
minor 7.2
year 2008
month 08
day25
svn rev46428
language R
version.string R version 2.7.2 (2008-08-25)
Robert McGehee, CFA
Geode Capital Management, LLC
One Post Office Square, 28th Floor | Boston, MA | 02109
Tel: 617/392-8396Fax:617/476-6389
mailto:[EMAIL PROTECTED]
This e-mail, and any attachments hereto, are intended fo...{{dropped:12}}
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] match and incomparables
Looks like a bug to me. Compare:
> match (1:3,1:3,incom=3)
[1] 1 2 3
> match (1:3,1:3,incom=2:3)
[1] 1 2 3
> match (1:3,1:3,incom=1:2)
[1] NA NA 3
> match (1:3,1:3,incom=1)
[1] NA 2 3
Cheers,
Bert
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of Adam D. I. Kramer
Sent: Friday, September 12, 2008 3:06 PM
To: McGehee, Robert
Cc: r-help
Subject: Re: [R] match and incomparables
I can replicate this and also do not understand it.
> match(1:3,1:3,incomparables=5)
[1] NA 2 3
> match(1:3,1:3,incomparables=4)
[1] 1 2 3
> match(1:3,1:3,incomparables=3)
[1] 1 2 3
> match(1:3,1:3,incomparables=2)
[1] 1 2 3
> match(1:3,1:3,incomparables=1)
[1] NA 2 3
...every other integer value for incomparables produces 1 2 and 3 for
output. I'm using R 2.7.2, self-compiled, under linux.
--Adam
On Fri, 12 Sep 2008, McGehee, Robert wrote:
> Hello,
> I was playing around with the newly implemented 'incomparables' argument
> in 'match' and realized the argument does not behave anything like I
> expected. Can someone explain what is going on here? Sorry if I'm
> misreading the documentation.
>
>> match(1:3, 1:3, incomparables=1)
> [1] NA 2 3 # This seems right, the 1 in 'x' is 'incomparable'
>
>> match(1:3, 1:3, incomparables=2)
> [1] 1 2 3 # Shouldn't this be 1 NA 3? Why isn't the 2 incomparable?
>
>> match(1:3, 1:3, incomparables=5)
> [1] NA 2 3 # Why isn't the 5 ignored?
>
> Note from ?match:
> "incomparables: a vector of values that cannot be matched. Any value in
> x matching a value in this vector is assigned the nomatch value. For
> historical reasons, FALSE is equivalent to NULL."
>
> Thanks in advance!
> Robert
>
> platform i386-pc-mingw32
> arch i386
> os mingw32
> system i386, mingw32
> status
> major 2
> minor 7.2
> year 2008
> month 08
> day25
> svn rev46428
> language R
> version.string R version 2.7.2 (2008-08-25)
>
> Robert McGehee, CFA
> Geode Capital Management, LLC
> One Post Office Square, 28th Floor | Boston, MA | 02109
> Tel: 617/392-8396Fax:617/476-6389
> mailto:[EMAIL PROTECTED]
>
>
>
> This e-mail, and any attachments hereto, are intended fo...{{dropped:12}}
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] match and incomparables
On Fri, 12 Sep 2008, Bert Gunter wrote:
Looks like a bug to me. Compare:
A bug fixed in the R-devel version of R (because of a related problem with
duplicated).
match (1:3,1:3,incom=3)
[1] 1 2 3
match (1:3,1:3,incom=2:3)
[1] 1 2 3
match (1:3,1:3,incom=1:2)
[1] NA NA 3
match (1:3,1:3,incom=1)
[1] NA 2 3
Cheers,
Bert
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of Adam D. I. Kramer
Sent: Friday, September 12, 2008 3:06 PM
To: McGehee, Robert
Cc: r-help
Subject: Re: [R] match and incomparables
I can replicate this and also do not understand it.
match(1:3,1:3,incomparables=5)
[1] NA 2 3
match(1:3,1:3,incomparables=4)
[1] 1 2 3
match(1:3,1:3,incomparables=3)
[1] 1 2 3
match(1:3,1:3,incomparables=2)
[1] 1 2 3
match(1:3,1:3,incomparables=1)
[1] NA 2 3
...every other integer value for incomparables produces 1 2 and 3 for
output. I'm using R 2.7.2, self-compiled, under linux.
--Adam
On Fri, 12 Sep 2008, McGehee, Robert wrote:
Hello,
I was playing around with the newly implemented 'incomparables' argument
in 'match' and realized the argument does not behave anything like I
expected. Can someone explain what is going on here? Sorry if I'm
misreading the documentation.
match(1:3, 1:3, incomparables=1)
[1] NA 2 3 # This seems right, the 1 in 'x' is 'incomparable'
match(1:3, 1:3, incomparables=2)
[1] 1 2 3 # Shouldn't this be 1 NA 3? Why isn't the 2 incomparable?
match(1:3, 1:3, incomparables=5)
[1] NA 2 3 # Why isn't the 5 ignored?
Note from ?match:
"incomparables: a vector of values that cannot be matched. Any value in
x matching a value in this vector is assigned the nomatch value. For
historical reasons, FALSE is equivalent to NULL."
Thanks in advance!
Robert
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status
major 2
minor 7.2
year 2008
month 08
day25
svn rev46428
language R
version.string R version 2.7.2 (2008-08-25)
Robert McGehee, CFA
Geode Capital Management, LLC
One Post Office Square, 28th Floor | Boston, MA | 02109
Tel: 617/392-8396Fax:617/476-6389
mailto:[EMAIL PROTECTED]
This e-mail, and any attachments hereto, are intended fo...{{dropped:12}}
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
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--
Brian D. Ripley, [EMAIL PROTECTED]
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax: +44 1865 272595
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Re: [R] match problem by rownames
As suggested in ?"[.data.frame", try:
dat[match('a1', rownames(dat)),]
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
On Sep 9, 2008, at 2:41 AM, Xianming Wei wrote:
Hi all,
While dat['a1',] and dat['a10',] produce the same results in the
following example, I'd like dat['a1',] to return NAs.
dat <- data.frame(x1 = paste(letters[1:5],10, sep=''), x2=rnorm(5))
rownames(dat) <- dat$x1
dat['a1',]
dat['a10',]
sessionInfo()
R version 2.7.2 (2008-08-25)
i386-pc-mingw32
locale:
LC_COLLATE=English_Australia.1252;LC_CTYPE=English_Australia.
1252;LC_MON
ETARY=English_Australia.1252;LC_NUMERIC=C;LC_TIME=English_Australia.
1252
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] lattice_0.17-13
loaded via a namespace (and not attached):
[1] grid_2.7.2
Regards,
Xianming
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] match problem by rownames
try this:
dat <- data.frame(x1 = paste(letters[1:5],10, sep=''), x2=rnorm(5))
row.names(dat) <- dat$x1
dat['a1' %in% row.names(dat), ]
dat['a10' %in% row.names(dat), ]
I hope it helps.
Best,
Dimitris
> Hi all,
>
> While dat['a1',] and dat['a10',] produce the same results in the
> following example, I'd like dat['a1',] to return NAs.
>
> dat <- data.frame(x1 = paste(letters[1:5],10, sep=''), x2=rnorm(5))
> rownames(dat) <- dat$x1
> dat['a1',]
> dat['a10',]
>
>> sessionInfo()
> R version 2.7.2 (2008-08-25)
> i386-pc-mingw32
>
> locale:
> LC_COLLATE=English_Australia.1252;LC_CTYPE=English_Australia.1252;LC_MON
> ETARY=English_Australia.1252;LC_NUMERIC=C;LC_TIME=English_Australia.1252
>
> attached base packages:
> [1] stats graphics grDevices utils datasets methods base
>
>
> other attached packages:
> [1] lattice_0.17-13
>
> loaded via a namespace (and not attached):
> [1] grid_2.7.2
>>
>
> Regards,
> Xianming
>
>
>
> DISCLAIMER:\ For details of our e-mail disclaimer, pleas...{{dropped:15}}
>
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Department of Biostatistics
Erasmus University Medical Center
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[R] Match and replace between two data.frames
Hi folks,
I have two dataframes like these:
DF <- data.frame(ID=c("AA1234","AB3233","AC4353","AD2345","AE7453"),
CK32344=c(1,3,2,4,1), CK32664=c(2,1,1,2,3), CK33422=c(2,2,1,3,2))
VAL <- data.frame(num=rep(6,3), type=c("CK32344", "CK32664",
"CK33422"), number=c("32","452","234"))
I want to replace the values in DF$CK32344, DF$CK32664 DF$CK33422 with
the corresponding number in the VAL$number.
The results should look like this:
RES <- data.frame(ID=c("AA1234","AB3233","AC4353","AD2345","AE7453"),
CK32344=rep(32, 5), CK32664=rep(425, 5), CK33422=rep(234, 5))
How do I do that?
Regards,
Lauri
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Re: [R] Match and replace between two data.frames
HI,
Perhaps:
cbind(ID=DF$ID,as.data.frame(sapply(levels(VAL$type),
function(x){DF[,x]=VAL$number[VAL$type==x];DF[,x]})))
On 25/10/2007, Lauri Nikkinen <[EMAIL PROTECTED]> wrote:
>
> Hi folks,
>
> I have two dataframes like these:
>
> DF <- data.frame(ID=c("AA1234","AB3233","AC4353","AD2345","AE7453"),
> CK32344=c(1,3,2,4,1), CK32664=c(2,1,1,2,3), CK33422=c(2,2,1,3,2))
> VAL <- data.frame(num=rep(6,3), type=c("CK32344", "CK32664",
> "CK33422"), number=c("32","452","234"))
>
> I want to replace the values in DF$CK32344, DF$CK32664 DF$CK33422 with
> the corresponding number in the VAL$number.
>
> The results should look like this:
>
> RES <- data.frame(ID=c("AA1234","AB3233","AC4353","AD2345","AE7453"),
> CK32344=rep(32, 5), CK32664=rep(425, 5), CK33422=rep(234, 5))
>
> How do I do that?
>
> Regards,
> Lauri
>
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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