Re: [R] Data Frame to list?

2014-03-10 Thread Brian Diggs

On 3/7/2014 7:41 PM, Keith S Weintraub wrote:

Folks,

I have a data frame as follows:


foo<-structure(list(name = c("A", "B", "C"), num = c(3L, 2L, 1L)), .Names = 
c("name",

"num"), row.names = c(NA, -3L), class = "data.frame")


str(foo)

'data.frame':   3 obs. of  2 variables:
  $ name: chr  "A" "B" "C"
  $ num : int  3 2 1


foo

   name num
1A   3
2B   2
3C   1

I want to convert this to a list like so:


oof<-list(A = 3, B = 2, C = 1)


You can do it as a one-liner as well:

oof <- setNames(as.list(foo$num), foo$name)


str(oof)

List of 3
  $ A: num 3
  $ B: num 2
  $ C: num 1


oof

$A
[1] 3

$B
[1] 2

$C
[1] 1

Any Suggestions?

Thanks,
KW

--




--
Brian S. Diggs, PhD
Senior Research Associate, Department of Surgery
Oregon Health & Science University

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Re: [R] Data Frame to list?

2014-03-08 Thread Keith S Weintraub
Arun et al.

Thanks,
This is exactly what I need.

All the best,
KW

--

On Mar 7, 2014, at 10:59 PM, arun  wrote:

> Try:
> oof1 <- list()
>  oof1[foo$name] <- foo$num
> A.K.
> 
> 
> 
> 
> On Friday, March 7, 2014 10:43 PM, Keith S Weintraub  wrote:
> Folks,
> 
> I have a data frame as follows:
> 
>> foo<-structure(list(name = c("A", "B", "C"), num = c(3L, 2L, 1L)), .Names = 
>> c("name", 
> "num"), row.names = c(NA, -3L), class = "data.frame")
> 
>> str(foo)
> 'data.frame':   3 obs. of  2 variables:
> $ name: chr  "A" "B" "C"
> $ num : int  3 2 1
> 
>> foo
>   name num
> 1A   3
> 2B   2
> 3C   1
> 
> I want to convert this to a list like so:
> 
>> oof<-list(A = 3, B = 2, C = 1)
> 
>> str(oof)
> List of 3
> $ A: num 3
> $ B: num 2
> $ C: num 1
> 
>> oof
> $A
> [1] 3
> 
> $B
> [1] 2
> 
> $C
> [1] 1
> 
> Any Suggestions?
> 
> Thanks,
> KW
> 
> --
> 
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
> 

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Re: [R] Data Frame to list?

2014-03-07 Thread arun
Try:
oof1 <- list()
 oof1[foo$name] <- foo$num
A.K.




On Friday, March 7, 2014 10:43 PM, Keith S Weintraub  wrote:
Folks,

I have a data frame as follows:

> foo<-structure(list(name = c("A", "B", "C"), num = c(3L, 2L, 1L)), .Names = 
> c("name", 
"num"), row.names = c(NA, -3L), class = "data.frame")

> str(foo)
'data.frame':   3 obs. of  2 variables:
$ name: chr  "A" "B" "C"
$ num : int  3 2 1

> foo
  name num
1    A   3
2    B   2
3    C   1

I want to convert this to a list like so:

> oof<-list(A = 3, B = 2, C = 1)

> str(oof)
List of 3
$ A: num 3
$ B: num 2
$ C: num 1

> oof
$A
[1] 3

$B
[1] 2

$C
[1] 1

Any Suggestions?

Thanks,
KW

--

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Re: [R] Data Frame to list?

2014-03-07 Thread Richard M. Heiberger
> oof <- as.list(foo$num)
> names(oof) <- foo$name
> oof

On Fri, Mar 7, 2014 at 10:41 PM, Keith S Weintraub  wrote:
> Folks,
>
> I have a data frame as follows:
>
>> foo<-structure(list(name = c("A", "B", "C"), num = c(3L, 2L, 1L)), .Names = 
>> c("name",
> "num"), row.names = c(NA, -3L), class = "data.frame")
>
>> str(foo)
> 'data.frame':   3 obs. of  2 variables:
>  $ name: chr  "A" "B" "C"
>  $ num : int  3 2 1
>
>> foo
>   name num
> 1A   3
> 2B   2
> 3C   1
>
> I want to convert this to a list like so:
>
>> oof<-list(A = 3, B = 2, C = 1)
>
>> str(oof)
> List of 3
>  $ A: num 3
>  $ B: num 2
>  $ C: num 1
>
>> oof
> $A
> [1] 3
>
> $B
> [1] 2
>
> $C
> [1] 1
>
> Any Suggestions?
>
> Thanks,
> KW
>
> --
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

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and provide commented, minimal, self-contained, reproducible code.


[R] Data Frame to list?

2014-03-07 Thread Keith S Weintraub
Folks,

I have a data frame as follows:

> foo<-structure(list(name = c("A", "B", "C"), num = c(3L, 2L, 1L)), .Names = 
> c("name", 
"num"), row.names = c(NA, -3L), class = "data.frame")

> str(foo)
'data.frame':   3 obs. of  2 variables:
 $ name: chr  "A" "B" "C"
 $ num : int  3 2 1

> foo
  name num
1A   3
2B   2
3C   1

I want to convert this to a list like so:

> oof<-list(A = 3, B = 2, C = 1)

> str(oof)
List of 3
 $ A: num 3
 $ B: num 2
 $ C: num 1

> oof
$A
[1] 3

$B
[1] 2

$C
[1] 1

Any Suggestions?

Thanks,
KW

--

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Re: [R] Data frame to list?

2011-08-11 Thread David Winsemius


On Aug 11, 2011, at 8:24 AM, Michael Karol wrote:


Perhaps the split() function would do.


Something like split(dfrm, 1:nrow(dfrm)) or split(dfrm, rownames(dfrm))

--  


Regards,
Michael

-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org 
] On Behalf Of Jonathan Greenberg

Sent: Wednesday, August 10, 2011 10:36 PM
To: r-help
Subject: [R] Data frame to list?

R-helpers:

Is there an easy way to transfer a data frame to a list, where each
list element is a dataframe containing a single row from the original
data frame?

--j


David Winsemius, MD
West Hartford, CT

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Re: [R] Data frame to list?

2011-08-11 Thread Michael Karol
Perhaps the split() function would do.

Regards, 
Michael

-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On 
Behalf Of Jonathan Greenberg
Sent: Wednesday, August 10, 2011 10:36 PM
To: r-help
Subject: [R] Data frame to list?

R-helpers:

Is there an easy way to transfer a data frame to a list, where each
list element is a dataframe containing a single row from the original
data frame?

--j

-- 
Jonathan A. Greenberg, PhD
Assistant Project Scientist
Center for Spatial Technologies and Remote Sensing (CSTARS)
Department of Land, Air and Water Resources
University of California, Davis
One Shields Avenue
Davis, CA 95616
Phone: 415-763-5476
AIM: jgrn307, MSN: jgrn...@hotmail.com, Gchat: jgrn307

__
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and provide commented, minimal, self-contained, reproducible code.

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[R] Data frame to list?

2011-08-10 Thread Jonathan Greenberg
R-helpers:

Is there an easy way to transfer a data frame to a list, where each
list element is a dataframe containing a single row from the original
data frame?

--j

-- 
Jonathan A. Greenberg, PhD
Assistant Project Scientist
Center for Spatial Technologies and Remote Sensing (CSTARS)
Department of Land, Air and Water Resources
University of California, Davis
One Shields Avenue
Davis, CA 95616
Phone: 415-763-5476
AIM: jgrn307, MSN: jgrn...@hotmail.com, Gchat: jgrn307

__
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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Data frame to list?

2011-08-10 Thread Jonathan Greenberg
Answered my own question.  ?split

Never mind!

--j

On Wed, Aug 10, 2011 at 7:35 PM, Jonathan Greenberg
 wrote:
> R-helpers:
>
> Is there an easy way to transfer a data frame to a list, where each
> list element is a dataframe containing a single row from the original
> data frame?
>
> --j
>
> --
> Jonathan A. Greenberg, PhD
> Assistant Project Scientist
> Center for Spatial Technologies and Remote Sensing (CSTARS)
> Department of Land, Air and Water Resources
> University of California, Davis
> One Shields Avenue
> Davis, CA 95616
> Phone: 415-763-5476
> AIM: jgrn307, MSN: jgrn...@hotmail.com, Gchat: jgrn307
>



-- 
Jonathan A. Greenberg, PhD
Assistant Project Scientist
Center for Spatial Technologies and Remote Sensing (CSTARS)
Department of Land, Air and Water Resources
University of California, Davis
One Shields Avenue
Davis, CA 95616
Phone: 415-763-5476
AIM: jgrn307, MSN: jgrn...@hotmail.com, Gchat: jgrn307

__
R-help@r-project.org mailing list
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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Data frame to list

2011-07-28 Thread David Winsemius


On Jul 28, 2011, at 4:14 PM, Jonathan Greenberg wrote:

I'm hoping this is an easy problem that I'm missing something  
obvious.  Given:


x=c(1,1,1,2,2,3,3,3)
y=c(1:length(x))
dataframe=data.frame(x,y)

I would like to convert this to a list for use with certain functions,
where each entry of the list is a subsetted dataframe based on
dataframe$x


?split
> split(dataframe, x)
$`1`
  x y
1 1 1
2 1 2
3 1 3

$`2`
  x y
4 2 4
5 2 5

$`3`
  x y
6 3 6
7 3 7
8 3 8



I can do this "brute force" by a for-next loop:

unique_x=unique(dataframe$x)
unique_x_N=length(unique_x)
dataframe_to_list=vector(mode="list",length=unique_x_N)
for(i in 1:unique_x_N)
{
dataframe_to_list[[i]]=subset(dataframe,x==unique_x[i])

}

My R-gut is telling me there's a much more efficient way of doing this
-- is it right?

--j

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and provide commented, minimal, self-contained, reproducible code.


David Winsemius, MD
West Hartford, CT

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Re: [R] Data frame to list

2011-07-28 Thread Jonathan Greenberg
Yep, my R-gut was right!  Thanks Jean and Greg!

--j

On Thu, Jul 28, 2011 at 1:29 PM, Jean V Adams  wrote:

>
> Try this:
>
> split(dataframe, dataframe$x)
>
> Jean
>
>
> `·.,,  ><(((º>   `·.,,  ><(((º>   `·.,,  ><(((º>
>
> Jean V. Adams
> Statistician
> U.S. Geological Survey
> Great Lakes Science Center
> 223 East Steinfest Road
> Antigo, WI 54409  USA
>
>
>  From: Jonathan Greenberg  To: r-help <
> r-help@r-project.org> Date: 07/28/2011 03:22 PM Subject:
> [R] Data frame to list
> Sent by: r-help-boun...@r-project.org
> --
>
>
>
> I'm hoping this is an easy problem that I'm missing something obvious.
>  Given:
>
> x=c(1,1,1,2,2,3,3,3)
> y=c(1:length(x))
> dataframe=data.frame(x,y)
>
> I would like to convert this to a list for use with certain functions,
> where each entry of the list is a subsetted dataframe based on
> dataframe$x
>
> I can do this "brute force" by a for-next loop:
>
> unique_x=unique(dataframe$x)
> unique_x_N=length(unique_x)
> dataframe_to_list=vector(mode="list",length=unique_x_N)
> for(i in 1:unique_x_N)
> {
> dataframe_to_list[[i]]=subset(dataframe,x==unique_x[i])
>
> }
>
> My R-gut is telling me there's a much more efficient way of doing this
> -- is it right?
>
> --j
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html>
> and provide commented, minimal, self-contained, reproducible code.
>
>
>

[[alternative HTML version deleted]]

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Re: [R] Data frame to list

2011-07-28 Thread Jean V Adams
Try this:

split(dataframe, dataframe$x)

Jean


`·.,,  ><(((º>   `·.,,  ><(((º>   `·.,,  ><(((º>

Jean V. Adams
Statistician
U.S. Geological Survey
Great Lakes Science Center
223 East Steinfest Road
Antigo, WI 54409  USA



From:
Jonathan Greenberg 
To:
r-help 
Date:
07/28/2011 03:22 PM
Subject:
[R] Data frame to list
Sent by:
r-help-boun...@r-project.org



I'm hoping this is an easy problem that I'm missing something obvious. 
Given:

x=c(1,1,1,2,2,3,3,3)
y=c(1:length(x))
dataframe=data.frame(x,y)

I would like to convert this to a list for use with certain functions,
where each entry of the list is a subsetted dataframe based on
dataframe$x

I can do this "brute force" by a for-next loop:

unique_x=unique(dataframe$x)
unique_x_N=length(unique_x)
dataframe_to_list=vector(mode="list",length=unique_x_N)
for(i in 1:unique_x_N)
{
 dataframe_to_list[[i]]=subset(dataframe,x==unique_x[i])
 
}

My R-gut is telling me there's a much more efficient way of doing this
-- is it right?

--j

__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide 
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.



[[alternative HTML version deleted]]

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Re: [R] Data frame to list

2011-07-28 Thread Greg Snow
?split

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Jonathan Greenberg
> Sent: Thursday, July 28, 2011 2:14 PM
> To: r-help
> Subject: [R] Data frame to list
> 
> I'm hoping this is an easy problem that I'm missing something obvious.
> Given:
> 
> x=c(1,1,1,2,2,3,3,3)
> y=c(1:length(x))
> dataframe=data.frame(x,y)
> 
> I would like to convert this to a list for use with certain functions,
> where each entry of the list is a subsetted dataframe based on
> dataframe$x
> 
> I can do this "brute force" by a for-next loop:
> 
> unique_x=unique(dataframe$x)
> unique_x_N=length(unique_x)
> dataframe_to_list=vector(mode="list",length=unique_x_N)
> for(i in 1:unique_x_N)
> {
>   dataframe_to_list[[i]]=subset(dataframe,x==unique_x[i])
> 
> }
> 
> My R-gut is telling me there's a much more efficient way of doing this
> -- is it right?
> 
> --j
> 
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] Data frame to list

2011-07-28 Thread Jonathan Greenberg
I'm hoping this is an easy problem that I'm missing something obvious.  Given:

x=c(1,1,1,2,2,3,3,3)
y=c(1:length(x))
dataframe=data.frame(x,y)

I would like to convert this to a list for use with certain functions,
where each entry of the list is a subsetted dataframe based on
dataframe$x

I can do this "brute force" by a for-next loop:

unique_x=unique(dataframe$x)
unique_x_N=length(unique_x)
dataframe_to_list=vector(mode="list",length=unique_x_N)
for(i in 1:unique_x_N)
{
dataframe_to_list[[i]]=subset(dataframe,x==unique_x[i])

}

My R-gut is telling me there's a much more efficient way of doing this
-- is it right?

--j

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.