Re: [R] Delete rows from data.frame matching a certain criteria
Hi my favourite would be test$v[which(test$pattern==1)]-NA Regards Petr Hi, On Mar 1, 2012, at 12:38 PM, Sarah Goslee wrote: Hi, On Thu, Mar 1, 2012 at 11:11 AM, mails mails00...@gmail.com wrote: Hello, consider the following data.frame: test - data.frame(n = c(1,2,3,4,5), v = c(6,5,7,5,3), pattern = c(1,1,NA,1,NA)) snip So basically the result should look like this: test n v pattern 1 1 NA 1 2 2 NA 1 3 3 7 NA 4 4 NA 1 5 5 3 NA So far, I solved it by creating subsets and using merge but it turns out to be super slow. Is there a way to do that with the apply function? Far too much work. What about: test$v - ifelse(test$pattern == 1, NA, v) test n v pattern 1 1 NA 1 2 2 NA 1 3 3 NA NA 4 4 NA 1 5 5 NA NA Actually that doesn't work because of those pesky missing values. You need test - transform(test, v = ifelse(pattern == 1 !is.na(pattern), NA, v)) Best, Ista -- Sarah Goslee http://www.functionaldiversity.org __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Delete rows from data.frame matching a certain criteria
Hello, consider the following data.frame: test - data.frame(n = c(1,2,3,4,5), v = c(6,5,7,5,3), pattern = c(1,1,NA,1,NA)) test n v pattern 1 1 6 1 2 2 5 1 3 3 7 NA 4 4 5 1 5 5 3 NA I tried to use apply and the adply function to set v to NA where pattern = 1 and v to v where pattern = 1 So basically the result should look like this: test n v pattern 1 1 NA 1 2 2 NA 1 3 3 7 NA 4 4 NA 1 5 5 3 NA So far, I solved it by creating subsets and using merge but it turns out to be super slow. Is there a way to do that with the apply function? Any help/hint is appreciated Thanks -- View this message in context: http://r.789695.n4.nabble.com/Delete-rows-from-data-frame-matching-a-certain-criteria-tp4435414p4435414.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Delete rows from data.frame matching a certain criteria
Hi, On Thu, Mar 1, 2012 at 11:11 AM, mails mails00...@gmail.com wrote: Hello, consider the following data.frame: test - data.frame(n = c(1,2,3,4,5), v = c(6,5,7,5,3), pattern = c(1,1,NA,1,NA)) test n v pattern 1 1 6 1 2 2 5 1 3 3 7 NA 4 4 5 1 5 5 3 NA Thanks for the reproducible example. I tried to use apply and the adply function to set v to NA where pattern = 1 and v to v where pattern = 1 Presumably that should be set v to NA where pattern == 1 and v to v where pattern != 1 So basically the result should look like this: test n v pattern 1 1 NA 1 2 2 NA 1 3 3 7 NA 4 4 NA 1 5 5 3 NA So far, I solved it by creating subsets and using merge but it turns out to be super slow. Is there a way to do that with the apply function? Far too much work. What about: test$v - ifelse(test$pattern == 1, NA, v) test n v pattern 1 1 NA 1 2 2 NA 1 3 3 NA NA 4 4 NA 1 5 5 NA NA -- Sarah Goslee http://www.functionaldiversity.org __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Delete rows from data.frame matching a certain criteria
Your criteria did not make sense since in both cases pattern == 1, so I chose to set to NA if pattern == 1 test - data.frame(n = c(1,2,3,4,5), v = c(6,5,7,5,3), pattern = + c(1,1,NA,1,NA)) test n v pattern 1 1 6 1 2 2 5 1 3 3 7 NA 4 4 5 1 5 5 3 NA # set v to NA when pattern = 1 test$v[!is.na(test$pattern) (test$pattern == 1)] - NA test n v pattern 1 1 NA 1 2 2 NA 1 3 3 7 NA 4 4 NA 1 5 5 3 NA On Thu, Mar 1, 2012 at 11:11 AM, mails mails00...@gmail.com wrote: Hello, consider the following data.frame: test - data.frame(n = c(1,2,3,4,5), v = c(6,5,7,5,3), pattern = c(1,1,NA,1,NA)) test n v pattern 1 1 6 1 2 2 5 1 3 3 7 NA 4 4 5 1 5 5 3 NA I tried to use apply and the adply function to set v to NA where pattern = 1 and v to v where pattern = 1 So basically the result should look like this: test n v pattern 1 1 NA 1 2 2 NA 1 3 3 7 NA 4 4 NA 1 5 5 3 NA So far, I solved it by creating subsets and using merge but it turns out to be super slow. Is there a way to do that with the apply function? Any help/hint is appreciated Thanks -- View this message in context: http://r.789695.n4.nabble.com/Delete-rows-from-data-frame-matching-a-certain-criteria-tp4435414p4435414.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Delete rows from data.frame matching a certain criteria
-Original Message- From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- project.org] On Behalf Of mails Sent: Thursday, March 01, 2012 8:11 AM To: r-help@r-project.org Subject: [R] Delete rows from data.frame matching a certain criteria Hello, consider the following data.frame: test - data.frame(n = c(1,2,3,4,5), v = c(6,5,7,5,3), pattern = c(1,1,NA,1,NA)) test n v pattern 1 1 6 1 2 2 5 1 3 3 7 NA 4 4 5 1 5 5 3 NA I tried to use apply and the adply function to set v to NA where pattern = 1 and v to v where pattern = 1 So basically the result should look like this: test n v pattern 1 1 NA 1 2 2 NA 1 3 3 7 NA 4 4 NA 1 5 5 3 NA So far, I solved it by creating subsets and using merge but it turns out to be super slow. Is there a way to do that with the apply function? Any help/hint is appreciated Thanks There is no need for apply here, this is a simple indexing problem. Something like this should work test$v - ifelse(is.na(test$pattern), test$v, NA) Hope this is helpful, Dan Daniel J. Nordlund Washington State Department of Social and Health Services Planning, Performance, and Accountability Research and Data Analysis Division Olympia, WA 98504-5204 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Delete rows from data.frame matching a certain criteria
Hi, On Mar 1, 2012, at 12:38 PM, Sarah Goslee wrote: Hi, On Thu, Mar 1, 2012 at 11:11 AM, mails mails00...@gmail.com wrote: Hello, consider the following data.frame: test - data.frame(n = c(1,2,3,4,5), v = c(6,5,7,5,3), pattern = c(1,1,NA,1,NA)) snip So basically the result should look like this: test n v pattern 1 1 NA 1 2 2 NA 1 3 3 7 NA 4 4 NA 1 5 5 3 NA So far, I solved it by creating subsets and using merge but it turns out to be super slow. Is there a way to do that with the apply function? Far too much work. What about: test$v - ifelse(test$pattern == 1, NA, v) test n v pattern 1 1 NA 1 2 2 NA 1 3 3 NA NA 4 4 NA 1 5 5 NA NA Actually that doesn't work because of those pesky missing values. You need test - transform(test, v = ifelse(pattern == 1 !is.na(pattern), NA, v)) Best, Ista -- Sarah Goslee http://www.functionaldiversity.org __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Delete rows from data.frame matching a certain criteria
You're all correct: I copied in the wrong thing. My apologies! On Thu, Mar 1, 2012 at 1:00 PM, Ista Zahn istaz...@gmail.com wrote: Hi, On Mar 1, 2012, at 12:38 PM, Sarah Goslee wrote: Hi, On Thu, Mar 1, 2012 at 11:11 AM, mails mails00...@gmail.com wrote: Hello, consider the following data.frame: test - data.frame(n = c(1,2,3,4,5), v = c(6,5,7,5,3), pattern = c(1,1,NA,1,NA)) snip So basically the result should look like this: test n v pattern 1 1 NA 1 2 2 NA 1 3 3 7 NA 4 4 NA 1 5 5 3 NA So far, I solved it by creating subsets and using merge but it turns out to be super slow. Is there a way to do that with the apply function? Far too much work. What about: test$v - ifelse(test$pattern == 1, NA, v) test n v pattern 1 1 NA 1 2 2 NA 1 3 3 NA NA 4 4 NA 1 5 5 NA NA Actually that doesn't work because of those pesky missing values. You need test - transform(test, v = ifelse(pattern == 1 !is.na(pattern), NA, v)) Best, Ista __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Delete rows from data.frame matching a certain criteria
On Mar 1, 2012, at 1:02 PM, Sarah Goslee wrote: You're all correct: I copied in the wrong thing. My apologies! On Thu, Mar 1, 2012 at 1:00 PM, Ista Zahn istaz...@gmail.com wrote: Hi, On Mar 1, 2012, at 12:38 PM, Sarah Goslee wrote: Hi, On Thu, Mar 1, 2012 at 11:11 AM, mails mails00...@gmail.com wrote: Hello, consider the following data.frame: test - data.frame(n = c(1,2,3,4,5), v = c(6,5,7,5,3), pattern = c(1,1,NA,1,NA)) snip So basically the result should look like this: test n v pattern 1 1 NA 1 2 2 NA 1 3 3 7 NA 4 4 NA 1 5 5 3 NA So far, I solved it by creating subsets and using merge but it turns out to be super slow. Is there a way to do that with the apply function? Far too much work. What about: test$v - ifelse(test$pattern == 1, NA, v) test n v pattern 1 1 NA 1 2 2 NA 1 3 3 NA NA 4 4 NA 1 5 5 NA NA Actually that doesn't work because of those pesky missing values. You need test - transform(test, v = ifelse(pattern == 1 !is.na(pattern), NA, v)) What about just using `is.na-`: is.na(test$v) - test$pattern==1 -- David Winsemius, MD West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
