One approach is:
sectors - 2
namSec - LETTERS[seq_len(sectors)]
nSec - round(3 / runif(sectors))
mapply(paste, namSec, sapply(nSec, seq_len),
MoreArgs = list(sep = ))
I hope it helps.
Best,
Dimitris
On 11/2/2011 2:56 PM, Christian Langkamp wrote:
Hi everyone
After the following setup
sector=2 # Define Number of Sectors
sectors=LETTERS[seq( from = 1, to = sector )] # Name sectors
No_ent=round(3/runif(sector)) # Number of entities per sector
#Tot_No_ent=sum(No_ent)
Goal is to get a List like
(A1, A2, A3, B1, B2, B3, B4) where A is denoting an industrial sector and
then a numbered sequence of companies within the sector.
The step I am missing is how to generate a sequence of vectors (one for each
sector) with individual length being determined by No_ent.
The goal is to generate a set of entities from different sectors. One simple
way out of it would be to set the number of entities equal per sector and
have a matrix, but I am quite sure it should also be possible for having a
different number of entities in each sector.
Once this is done, I can bind them together as vector with
as.vector(rbind(?)) (both as an (A,A,A,B,B,B,B) and (1,2,3,1,2,3,4) and
then concatenate)
Thanks, Christian
Trials included the following bits
A=for (i in 1:sector){
rep(i,No_ent[i])
}
paste(LETTERS[i], seq(from =1, to =No_ent[i]), sep = )
but I don't get the correct object definition right.
[[alternative HTML version deleted]]
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Dimitris Rizopoulos
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Erasmus University Medical Center
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