Re: [R] How to extract Friday data from daily data.
thornbird huachang...@gmail.com 05-Nov-10 20:10: Thank you very much. It worked great with the testdata. I have one more questionto to ask. As my data is incomplete, sometimes Thu is also missing, then I have no other options but to pick Sat instead, and if Sat is also missing, then my best possible option is to pick Wed, and etc. Bascially I have to pick a day as the data for that week starting from Friday following this order: Fri-- (if no Fri) Thu-- (if no Thu) Sat-- (if no Sat) Wed -- (if no Wed) Sun -- (if no Sun) Tue --(if no Tue) Mon. In this sense, I have to write a loop if command, right? Could you please help me with that? Again thanks a lot. I don't think you need a loop. Without knowing zoo, here's what I would try: If you look at Gabor's code, # extract all Thursdays and Fridays z45 - z[format(time(z), %w) %in% 4:5,] # keep last entry in each week # and show result on R console z45[!duplicated(format(time(z45), %U), fromLast = TRUE), ] It takes Thur and Fri data and takes the latest record that is there. You could work on a solution along the same lines except have the days ordered in the order of your top choice above (or inverse), then pick the first (or last) entry that exists for that week. Of course, since your choice order is not chronologlical you probably can't use fromLast. Marianne -- Marianne Promberger PhD, King's College London http://promberger.info R version 2.12.0 (2010-10-15) Ubuntu 9.04 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to extract Friday data from daily data.
Thanks for your suggestion. I received a few error messages. Can anyone help me figure out why I get the following error messages and how to solve them by revising my code? The data is shown in the post above. Thanks. library(zoo) colClasses - c(character, character, numeric, character, character, numeric) col.names - c(date, day, time, webpage, item, value) # z - read.zoo(myfile.dat, skip = 1, index = as.list(1:5), z - read.zoo(testdata[,1:5],as.Date(as.character(testdata[, 1])),skip = 1, index = as.list(1:6), + format = %d/%m/%Y, col.names = col.names, + aggregate = function(x) tail(x, 1), colClasses = colClasses) Error in `[.data.frame`(rval, , j) : undefined columns selected # extract all Thursdays and Fridays z45 - z[format(time(z), %w) %in% 4:5,] Error: object 'z' not found # keep last entry in each week # and show result on R console z45[!duplicated(format(time(z45), %U), fromLast = TRUE), ] Error: object 'z45' not found -- View this message in context: http://r.789695.n4.nabble.com/How-to-extract-Friday-data-from-daily-data-tp3029050p3034553.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to extract Friday data from daily data.
On Tue, Nov 9, 2010 at 11:23 AM, thornbird huachang...@gmail.com wrote: Thanks for your suggestion. I received a few error messages. Can anyone help me figure out why I get the following error messages and how to solve them by revising my code? The data is shown in the post above. Thanks. library(zoo) colClasses - c(character, character, numeric, character, character, numeric) col.names - c(date, day, time, webpage, item, value) # z - read.zoo(myfile.dat, skip = 1, index = as.list(1:5), z - read.zoo(testdata[,1:5],as.Date(as.character(testdata[, 1])),skip = 1, index = as.list(1:6), + format = %d/%m/%Y, col.names = col.names, + aggregate = function(x) tail(x, 1), colClasses = colClasses) Error in `[.data.frame`(rval, , j) : undefined columns selected # extract all Thursdays and Fridays z45 - z[format(time(z), %w) %in% 4:5,] Error: object 'z' not found # keep last entry in each week # and show result on R console z45[!duplicated(format(time(z45), %U), fromLast = TRUE), ] Error: object 'z45' not found Read ?read.zoo and the three zoo vignettes (pdf documents). Assuming we wish to read in the date and value column the following first writes out a test file and then uses read.zoo to read it back in. If there are multiple records at the same date we only keep the last (see aggregate= argument). Then we perform the extraction. # create some data and write out a file with it Lines - date day time webpage item value 1 10-Jun-09 Wed 9:40:53 MattDamon fans 613031 2 11-Jun-09 Thu 5:27:47 MattDamon fans 630242 3 11-Jun-09 Thu 9:23:23 MattDamon fans 631966 4 11-Jun-09 Thu 22:11:33 MattDamon fans 642045 5 13-Jun-09 Sat 13:07:53 MattDamon fans 669791 6 15-Jun-09 Mon 5:07:06 MattDamon fans 700180 7 15-Jun-09 Mon 13:09:43 MattDamon fans 702949 8 16-Jun-09 Tue 22:45:27 MattDamon fans 726624 9 17-Jun-09 Wed 13:08:19 MattDamon fans 734412 10 19-Jun-09 Fri 12:37:09 MattDamon fans 765057 11 20-Jun-09 Sat 12:38:36 MattDamon fans 782741 12 21-Jun-09 Sun 12:36:25 MattDamon fans 796054 13 22-Jun-09 Mon 12:39:36 MattDamon fans 809816 14 23-Jun-09 Tue 12:40:25 MattDamon fans 833996 15 27-Jun-09 Sat 12:40:36 MattDamon fans 899900 16 28-Jun-09 Sun 12:38:07 MattDamon fans 910401 17 10-Jun-09 Wed 9:40:53 MattDamon views 613031 18 11-Jun-09 Thu 5:27:47 MattDamon views 630242 19 11-Jun-09 Thu 9:23:23 MattDamon views 631966 20 11-Jun-09 Thu 22:11:33 MattDamon views 642045 21 13-Jun-09 Sat 13:07:53 MattDamon views 669791 22 15-Jun-09 Mon 5:07:06 MattDamon views 700180 23 15-Jun-09 Mon 13:09:43 MattDamon views 702949 24 16-Jun-09 Tue 22:45:27 MattDamon views 726624 25 17-Jun-09 Wed 13:08:19 MattDamon views 734412 26 19-Jun-09 Fri 12:37:09 MattDamon views 765057 27 20-Jun-09 Sat 12:38:36 MattDamon views 782741 28 21-Jun-09 Sun 12:36:25 MattDamon views 796054 29 22-Jun-09 Mon 12:39:36 MattDamon views 809816 30 23-Jun-09 Tue 12:40:25 MattDamon views 833996 31 25-Jun-09 Thu 12:38:27 MattDamon views 871237 32 26-Jun-09 Fri 12:36:12 MattDamon views 887175 33 26-Jun-09 Fri 13:36:12 MattDamon views 887195 34 27-Jun-09 Sat 12:40:36 MattDamon views 899900 35 10-Jun-09 Wed 9:40:53 AngieeJolie fans 613031 36 11-Jun-09 Thu 5:27:47 AngieeJolie fans 630242 37 11-Jun-09 Thu 9:23:23 AngieeJolie fans 631966 38 11-Jun-09 Thu 22:11:33 AngieeJolie fans 642045 39 13-Jun-09 Sat 13:07:53 AngieeJolie fans 669791 40 15-Jun-09 Mon 5:07:06 AngieeJolie fans 700180 41 16-Jun-09 Tue 22:45:27 AngieeJolie fans 726624 42 17-Jun-09 Wed 13:08:19 AngieeJolie fans 734412 43 19-Jun-09 Fri 12:37:09 AngieeJolie fans 765057 44 20-Jun-09 Sat 12:38:36 AngieeJolie fans 782741 45 21-Jun-09 Sun 12:36:25 AngieeJolie fans 796054 46 22-Jun-09 Mon 12:39:36 AngieeJolie fans 809816 47 23-Jun-09 Tue 12:40:25 AngieeJolie fans 833996 48 25-Jun-09 Thu 12:38:27 AngieeJolie fans 871237 49 26-Jun-09 Fri 12:36:12 AngieeJolie fans 887175 50 26-Jun-09 Fri 13:36:12 AngieeJolie fans 887195 51 30-Jun-09 Tue 12:36:43 AngieeJolie fans 934280 52 10-Jun-09 Wed 9:40:53 AngieeJolie views 613031 53 11-Jun-09 Thu 5:27:47 AngieeJolie views 630242 54 11-Jun-09 Thu 9:23:23 AngieeJolie views 631966 55 11-Jun-09 Thu 22:11:33 AngieeJolie views 642045 56 13-Jun-09 Sat 13:07:53 AngieeJolie views 669791 57 15-Jun-09 Mon 5:07:06 AngieeJolie views 700180 58 15-Jun-09 Mon 13:09:43 AngieeJolie views 702949 59 16-Jun-09 Tue 22:45:27 AngieeJolie views 726624 60 17-Jun-09 Wed 13:08:19 AngieeJolie views 734412 61 19-Jun-09 Fri 12:37:09 AngieeJolie views 765057 62 20-Jun-09 Sat 12:38:36 AngieeJolie views 782741 63 21-Jun-09 Sun 12:36:25 AngieeJolie views 796054 64 22-Jun-09 Mon 12:39:36 AngieeJolie views 809816 65 23-Jun-09 Tue 12:40:25 AngieeJolie views 833996 66 25-Jun-09 Thu 12:38:27 AngieeJolie views 871237 67 26-Jun-09 Fri 12:36:12 AngieeJolie views 887175 68 26-Jun-09 Fri 13:36:12 AngieeJolie views 887195 69 27-Jun-09 Sat 12:40:36
Re: [R] How to extract Friday data from daily data.
I did the following but it shows a couple of error messages. Could you help me with that? Thanks in advance. testdata - read.csv(C:\\Users\\Kevin\\Desktop\\testdata.csv, header=TRUE) testdata date day time webpage item value 1 10-Jun-09 Wed 9:40:53 MattDamon fans 613031 2 11-Jun-09 Thu 5:27:47 MattDamon fans 630242 3 11-Jun-09 Thu 9:23:23 MattDamon fans 631966 4 11-Jun-09 Thu 22:11:33 MattDamon fans 642045 5 13-Jun-09 Sat 13:07:53 MattDamon fans 669791 6 15-Jun-09 Mon 5:07:06 MattDamon fans 700180 7 15-Jun-09 Mon 13:09:43 MattDamon fans 702949 8 16-Jun-09 Tue 22:45:27 MattDamon fans 726624 9 17-Jun-09 Wed 13:08:19 MattDamon fans 734412 10 19-Jun-09 Fri 12:37:09 MattDamon fans 765057 11 20-Jun-09 Sat 12:38:36 MattDamon fans 782741 12 21-Jun-09 Sun 12:36:25 MattDamon fans 796054 13 22-Jun-09 Mon 12:39:36 MattDamon fans 809816 14 23-Jun-09 Tue 12:40:25 MattDamon fans 833996 15 27-Jun-09 Sat 12:40:36 MattDamon fans 899900 16 28-Jun-09 Sun 12:38:07 MattDamon fans 910401 17 10-Jun-09 Wed 9:40:53 MattDamon views 613031 18 11-Jun-09 Thu 5:27:47 MattDamon views 630242 19 11-Jun-09 Thu 9:23:23 MattDamon views 631966 20 11-Jun-09 Thu 22:11:33 MattDamon views 642045 21 13-Jun-09 Sat 13:07:53 MattDamon views 669791 22 15-Jun-09 Mon 5:07:06 MattDamon views 700180 23 15-Jun-09 Mon 13:09:43 MattDamon views 702949 24 16-Jun-09 Tue 22:45:27 MattDamon views 726624 25 17-Jun-09 Wed 13:08:19 MattDamon views 734412 26 19-Jun-09 Fri 12:37:09 MattDamon views 765057 27 20-Jun-09 Sat 12:38:36 MattDamon views 782741 28 21-Jun-09 Sun 12:36:25 MattDamon views 796054 29 22-Jun-09 Mon 12:39:36 MattDamon views 809816 30 23-Jun-09 Tue 12:40:25 MattDamon views 833996 31 25-Jun-09 Thu 12:38:27 MattDamon views 871237 32 26-Jun-09 Fri 12:36:12 MattDamon views 887175 33 26-Jun-09 Fri 13:36:12 MattDamon views 887195 34 27-Jun-09 Sat 12:40:36 MattDamon views 899900 35 10-Jun-09 Wed 9:40:53 AngieeJolie fans 613031 36 11-Jun-09 Thu 5:27:47 AngieeJolie fans 630242 37 11-Jun-09 Thu 9:23:23 AngieeJolie fans 631966 38 11-Jun-09 Thu 22:11:33 AngieeJolie fans 642045 39 13-Jun-09 Sat 13:07:53 AngieeJolie fans 669791 40 15-Jun-09 Mon 5:07:06 AngieeJolie fans 700180 41 16-Jun-09 Tue 22:45:27 AngieeJolie fans 726624 42 17-Jun-09 Wed 13:08:19 AngieeJolie fans 734412 43 19-Jun-09 Fri 12:37:09 AngieeJolie fans 765057 44 20-Jun-09 Sat 12:38:36 AngieeJolie fans 782741 45 21-Jun-09 Sun 12:36:25 AngieeJolie fans 796054 46 22-Jun-09 Mon 12:39:36 AngieeJolie fans 809816 47 23-Jun-09 Tue 12:40:25 AngieeJolie fans 833996 48 25-Jun-09 Thu 12:38:27 AngieeJolie fans 871237 49 26-Jun-09 Fri 12:36:12 AngieeJolie fans 887175 50 26-Jun-09 Fri 13:36:12 AngieeJolie fans 887195 51 30-Jun-09 Tue 12:36:43 AngieeJolie fans 934280 52 10-Jun-09 Wed 9:40:53 AngieeJolie views 613031 53 11-Jun-09 Thu 5:27:47 AngieeJolie views 630242 54 11-Jun-09 Thu 9:23:23 AngieeJolie views 631966 55 11-Jun-09 Thu 22:11:33 AngieeJolie views 642045 56 13-Jun-09 Sat 13:07:53 AngieeJolie views 669791 57 15-Jun-09 Mon 5:07:06 AngieeJolie views 700180 58 15-Jun-09 Mon 13:09:43 AngieeJolie views 702949 59 16-Jun-09 Tue 22:45:27 AngieeJolie views 726624 60 17-Jun-09 Wed 13:08:19 AngieeJolie views 734412 61 19-Jun-09 Fri 12:37:09 AngieeJolie views 765057 62 20-Jun-09 Sat 12:38:36 AngieeJolie views 782741 63 21-Jun-09 Sun 12:36:25 AngieeJolie views 796054 64 22-Jun-09 Mon 12:39:36 AngieeJolie views 809816 65 23-Jun-09 Tue 12:40:25 AngieeJolie views 833996 66 25-Jun-09 Thu 12:38:27 AngieeJolie views 871237 67 26-Jun-09 Fri 12:36:12 AngieeJolie views 887175 68 26-Jun-09 Fri 13:36:12 AngieeJolie views 887195 69 27-Jun-09 Sat 12:40:36 AngieeJolie views 899900 library(zoo) colClasses - c(character, character, numeric, character, character, numeric) col.names - c(date, day, time, webpage, item, value) # z - read.zoo(myfile.dat, skip = 1, index = as.list(1:5), z - read.zoo(testdata[,1:5],as.Date(as.character(testdata[, 1])),skip = 1, index = as.list(1:6), + format = %d/%m/%Y, col.names = col.names, + aggregate = function(x) tail(x, 1), colClasses = colClasses) Error in `[.data.frame`(rval, , j) : undefined columns selected ## Now that we have read it in lets process it ## 1. # extract all Thursdays and Fridays z45 - z[format(time(z), %w) %in% 4:5,] Error: object 'z' not found # keep last entry in each week # and show result on R console z45[!duplicated(format(time(z45), %U), fromLast = TRUE), ] Error: object 'z45' not found -- View this message in context: http://r.789695.n4.nabble.com/How-to-extract-Friday-data-from-daily-data-tp3029050p3032947.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide
Re: [R] How to extract Friday data from daily data.
Thank you very much. I learned a lot through your help. It worked great for the sample data. But when I try to apply the command to my dataset, I ran into two more problems. First, the dataset is huge, it has thousands of lines. I can read it in R. Using Lines - data may not work such a huge dataset. Is there a way to use data name in the commands. Second, I have two more variables, webpage and item. Using your command, I can extract data for one item (say fans) with no problem. But under item, there is also views, they may have same time and date as fans, how can I sort it out without replacing the same date? Also, under webpage, I have two actors/actresses, it has the similar issue. How can I sort it out without replacing the same date? Thanks for the time and help. Below is the sample: testdata - read.csv(C:\\Users\\Kevin\\Desktop\\testdata.csv, header=TRUE) testdata webpage item value day date time 1 MattDamon fans 613031 Wed 10-Jun-09 9:40:53 2 MattDamon fans 630242 Thu 11-Jun-09 5:27:47 3 MattDamon fans 631966 Thu 11-Jun-09 9:23:23 4 MattDamon fans 642045 Thu 11-Jun-09 22:11:33 5 MattDamon fans 669791 Sat 13-Jun-09 13:07:53 6 MattDamon fans 700180 Mon 15-Jun-09 5:07:06 7 MattDamon fans 702949 Mon 15-Jun-09 13:09:43 8 MattDamon fans 726624 Tue 16-Jun-09 22:45:27 9 MattDamon fans 734412 Wed 17-Jun-09 13:08:19 10 MattDamon fans 765057 Fri 19-Jun-09 12:37:09 11 MattDamon fans 782741 Sat 20-Jun-09 12:38:36 12 MattDamon fans 796054 Sun 21-Jun-09 12:36:25 13 MattDamon fans 809816 Mon 22-Jun-09 12:39:36 14 MattDamon fans 833996 Tue 23-Jun-09 12:40:25 15 MattDamon fans 871237 Thu 25-Jun-09 12:38:27 16 MattDamon fans 887175 Fri 26-Jun-09 12:36:12 17 MattDamon fans 887195 Fri 26-Jun-09 13:36:12 18 MattDamon fans 899900 Sat 27-Jun-09 12:40:36 19 MattDamon fans 910401 Sun 28-Jun-09 12:38:07 20 MattDamon fans 921537 Mon 29-Jun-09 12:35:17 21 MattDamon fans 934280 Tue 30-Jun-09 12:36:43 22 MattDamon fans 986463 Mon 6-Jul-09 13:58:19 23 MattDamon views 613031 Wed 10-Jun-09 9:40:53 24 MattDamon views 630242 Thu 11-Jun-09 5:27:47 25 MattDamon views 631966 Thu 11-Jun-09 9:23:23 26 MattDamon views 642045 Thu 11-Jun-09 22:11:33 27 MattDamon views 669791 Sat 13-Jun-09 13:07:53 28 MattDamon views 700180 Mon 15-Jun-09 5:07:06 29 MattDamon views 702949 Mon 15-Jun-09 13:09:43 30 MattDamon views 726624 Tue 16-Jun-09 22:45:27 31 MattDamon views 734412 Wed 17-Jun-09 13:08:19 32 MattDamon views 765057 Fri 19-Jun-09 12:37:09 33 MattDamon views 782741 Sat 20-Jun-09 12:38:36 34 MattDamon views 796054 Sun 21-Jun-09 12:36:25 35 MattDamon views 809816 Mon 22-Jun-09 12:39:36 36 MattDamon views 833996 Tue 23-Jun-09 12:40:25 37 MattDamon views 871237 Thu 25-Jun-09 12:38:27 38 MattDamon views 887175 Fri 26-Jun-09 12:36:12 39 MattDamon views 887195 Fri 26-Jun-09 13:36:12 40 MattDamon views 899900 Sat 27-Jun-09 12:40:36 41 MattDamon views 910401 Sun 28-Jun-09 12:38:07 42 MattDamon views 921537 Mon 29-Jun-09 12:35:17 43 MattDamon views 934280 Tue 30-Jun-09 12:36:43 44 MattDamon views 986463 Mon 6-Jul-09 13:58:19 45 AngelinaJolie fans 613031 Wed 10-Jun-09 9:40:53 46 AngelinaJolie fans 630242 Thu 11-Jun-09 5:27:47 47 AngelinaJolie fans 631966 Thu 11-Jun-09 9:23:23 48 AngelinaJolie fans 642045 Thu 11-Jun-09 22:11:33 49 AngelinaJolie fans 669791 Sat 13-Jun-09 13:07:53 50 AngelinaJolie fans 700180 Mon 15-Jun-09 5:07:06 51 AngelinaJolie fans 702949 Mon 15-Jun-09 13:09:43 52 AngelinaJolie fans 726624 Tue 16-Jun-09 22:45:27 53 AngelinaJolie fans 734412 Wed 17-Jun-09 13:08:19 54 AngelinaJolie fans 765057 Fri 19-Jun-09 12:37:09 55 AngelinaJolie fans 782741 Sat 20-Jun-09 12:38:36 56 AngelinaJolie fans 796054 Sun 21-Jun-09 12:36:25 57 AngelinaJolie fans 809816 Mon 22-Jun-09 12:39:36 58 AngelinaJolie fans 833996 Tue 23-Jun-09 12:40:25 59 AngelinaJolie fans 871237 Thu 25-Jun-09 12:38:27 60 AngelinaJolie fans 887175 Fri 26-Jun-09 12:36:12 61 AngelinaJolie fans 887195 Fri 26-Jun-09 13:36:12 62 AngelinaJolie fans 899900 Sat 27-Jun-09 12:40:36 63 AngelinaJolie fans 910401 Sun 28-Jun-09 12:38:07 64 AngelinaJolie fans 921537 Mon 29-Jun-09 12:35:17 65 AngelinaJolie fans 934280 Tue 30-Jun-09 12:36:43 66 AngelinaJolie fans 986463 Mon 6-Jul-09 13:58:19 67 AngelinaJolie views 613031 Wed 10-Jun-09 9:40:53 68 AngelinaJolie views 630242 Thu 11-Jun-09 5:27:47 69 AngelinaJolie views 631966 Thu 11-Jun-09 9:23:23 70 AngelinaJolie views 642045 Thu 11-Jun-09 22:11:33 71 AngelinaJolie views 669791 Sat 13-Jun-09 13:07:53 72 AngelinaJolie views 700180 Mon 15-Jun-09 5:07:06 73 AngelinaJolie views 702949 Mon 15-Jun-09 13:09:43 74 AngelinaJolie views 726624 Tue 16-Jun-09 22:45:27 75 AngelinaJolie views 734412 Wed 17-Jun-09 13:08:19 76 AngelinaJolie views 765057 Fri 19-Jun-09 12:37:09 77 AngelinaJolie
Re: [R] How to extract Friday data from daily data.
On Sat, Nov 6, 2010 at 11:05 PM, thornbird huachang...@gmail.com wrote: Thank you very much. I learned a lot through your help. It worked great for the sample data. But when I try to apply the command to my dataset, I ran into two more problems. First, the dataset is huge, it has thousands of lines. I can read it in R. Using Lines - data may not work such a huge dataset. Is there a way to use data name in the commands. That was just to keep the example self contained. The commented out line before the read.zoo line shows how it would be done with a file. Second, I have two more variables, webpage and item. Using your command, I can extract data for one item (say fans) with no problem. But under item, there is also views, they may have same time and date as fans, how can I sort it out without replacing the same date? Also, under webpage, I have two actors/actresses, it has the similar issue. How can I sort it out without replacing the same date? Please provide a reproducible example illustrating what is to be produced and include code to do as much of it as you can. Thanks for the time and help. Below is the sample: testdata - read.csv(C:\\Users\\Kevin\\Desktop\\testdata.csv, header=TRUE) testdata webpage item value day date time 1 MattDamon fans 613031 Wed 10-Jun-09 9:40:53 2 MattDamon fans 630242 Thu 11-Jun-09 5:27:47 3 MattDamon fans 631966 Thu 11-Jun-09 9:23:23 4 MattDamon fans 642045 Thu 11-Jun-09 22:11:33 5 MattDamon fans 669791 Sat 13-Jun-09 13:07:53 6 MattDamon fans 700180 Mon 15-Jun-09 5:07:06 7 MattDamon fans 702949 Mon 15-Jun-09 13:09:43 8 MattDamon fans 726624 Tue 16-Jun-09 22:45:27 9 MattDamon fans 734412 Wed 17-Jun-09 13:08:19 10 MattDamon fans 765057 Fri 19-Jun-09 12:37:09 11 MattDamon fans 782741 Sat 20-Jun-09 12:38:36 12 MattDamon fans 796054 Sun 21-Jun-09 12:36:25 13 MattDamon fans 809816 Mon 22-Jun-09 12:39:36 14 MattDamon fans 833996 Tue 23-Jun-09 12:40:25 15 MattDamon fans 871237 Thu 25-Jun-09 12:38:27 16 MattDamon fans 887175 Fri 26-Jun-09 12:36:12 17 MattDamon fans 887195 Fri 26-Jun-09 13:36:12 18 MattDamon fans 899900 Sat 27-Jun-09 12:40:36 19 MattDamon fans 910401 Sun 28-Jun-09 12:38:07 20 MattDamon fans 921537 Mon 29-Jun-09 12:35:17 21 MattDamon fans 934280 Tue 30-Jun-09 12:36:43 22 MattDamon fans 986463 Mon 6-Jul-09 13:58:19 23 MattDamon views 613031 Wed 10-Jun-09 9:40:53 24 MattDamon views 630242 Thu 11-Jun-09 5:27:47 25 MattDamon views 631966 Thu 11-Jun-09 9:23:23 26 MattDamon views 642045 Thu 11-Jun-09 22:11:33 27 MattDamon views 669791 Sat 13-Jun-09 13:07:53 28 MattDamon views 700180 Mon 15-Jun-09 5:07:06 29 MattDamon views 702949 Mon 15-Jun-09 13:09:43 30 MattDamon views 726624 Tue 16-Jun-09 22:45:27 31 MattDamon views 734412 Wed 17-Jun-09 13:08:19 32 MattDamon views 765057 Fri 19-Jun-09 12:37:09 33 MattDamon views 782741 Sat 20-Jun-09 12:38:36 34 MattDamon views 796054 Sun 21-Jun-09 12:36:25 35 MattDamon views 809816 Mon 22-Jun-09 12:39:36 36 MattDamon views 833996 Tue 23-Jun-09 12:40:25 37 MattDamon views 871237 Thu 25-Jun-09 12:38:27 38 MattDamon views 887175 Fri 26-Jun-09 12:36:12 39 MattDamon views 887195 Fri 26-Jun-09 13:36:12 40 MattDamon views 899900 Sat 27-Jun-09 12:40:36 41 MattDamon views 910401 Sun 28-Jun-09 12:38:07 42 MattDamon views 921537 Mon 29-Jun-09 12:35:17 43 MattDamon views 934280 Tue 30-Jun-09 12:36:43 44 MattDamon views 986463 Mon 6-Jul-09 13:58:19 45 AngelinaJolie fans 613031 Wed 10-Jun-09 9:40:53 46 AngelinaJolie fans 630242 Thu 11-Jun-09 5:27:47 47 AngelinaJolie fans 631966 Thu 11-Jun-09 9:23:23 48 AngelinaJolie fans 642045 Thu 11-Jun-09 22:11:33 49 AngelinaJolie fans 669791 Sat 13-Jun-09 13:07:53 50 AngelinaJolie fans 700180 Mon 15-Jun-09 5:07:06 51 AngelinaJolie fans 702949 Mon 15-Jun-09 13:09:43 52 AngelinaJolie fans 726624 Tue 16-Jun-09 22:45:27 53 AngelinaJolie fans 734412 Wed 17-Jun-09 13:08:19 54 AngelinaJolie fans 765057 Fri 19-Jun-09 12:37:09 55 AngelinaJolie fans 782741 Sat 20-Jun-09 12:38:36 56 AngelinaJolie fans 796054 Sun 21-Jun-09 12:36:25 57 AngelinaJolie fans 809816 Mon 22-Jun-09 12:39:36 58 AngelinaJolie fans 833996 Tue 23-Jun-09 12:40:25 59 AngelinaJolie fans 871237 Thu 25-Jun-09 12:38:27 60 AngelinaJolie fans 887175 Fri 26-Jun-09 12:36:12 61 AngelinaJolie fans 887195 Fri 26-Jun-09 13:36:12 62 AngelinaJolie fans 899900 Sat 27-Jun-09 12:40:36 63 AngelinaJolie fans 910401 Sun 28-Jun-09 12:38:07 64 AngelinaJolie fans 921537 Mon 29-Jun-09 12:35:17 65 AngelinaJolie fans 934280 Tue 30-Jun-09 12:36:43 66 AngelinaJolie fans 986463 Mon 6-Jul-09 13:58:19 67 AngelinaJolie views 613031 Wed 10-Jun-09 9:40:53 68 AngelinaJolie views 630242 Thu 11-Jun-09 5:27:47 69 AngelinaJolie
Re: [R] How to extract Friday data from daily data.
Hi thanks for quick reply. I am new to using R and still tried to figure out how to use Zoo package. Here is the code I have so far: library(zoo) colClasses - c(NULL, character, character, numeric, character, character, NULL) col.names - c(NA, webpage, item, value, day, date, NA) # z - read.zoo(myfile.dat, skip = 1, index = as.list(1:6), z - read.zoo(C:\\Users\\Kevin\\Desktop\\testdata.csv, sep = ,, skip = 1, index = as.list(1:6), format = %d/%m/%Y, col.names = col.names, aggregate = function(x) tail(x, 1), colClasses = colClasses) # extract all Thursdays and Fridays z45 - z[format(time(z), %w) %in% 4:5,] # keep last entry in each week # and show result on R console z45[!duplicated(format(time(z45), %U), fromLast = TRUE), ] I attached a reproducible dataset in excel and I hope to get the results as follows. It would be great if I can get all days in Friday format as you suggested in the second approach the first time. Again your time and help is appreciated! http://r.789695.n4.nabble.com/file/n3031420/testdata.csv testdata.csv webpage itemvalue day date time MattDamon fans642045 Thu 11-Jun-09 22:11:33 MattDamon fans765057 Fri 19-Jun-09 12:37:09 MattDamon fans899900 Sat 27-Jun-09 12:40:36 (no Fri or Thu, so I chose Sat) MattDamon views 642045 Thu 11-Jun-09 22:11:33 MattDamon views 765057 Fri 19-Jun-09 12:37:09 MattDamon views 887195 Fri 26-Jun-09 13:36:12 AngieeJolie fans642045 Thu 11-Jun-09 22:11:33 AngieeJolie fans765057 Fri 19-Jun-09 12:37:09 AngieeJolie fans887195 Fri 26-Jun-09 13:36:12 AngieeJolie views 642045 Thu 11-Jun-09 22:11:33 AngieeJolie views 765057 Fri 19-Jun-09 12:37:09 AngieeJolie views 887195 Fri 26-Jun-09 13:36:12 -- View this message in context: http://r.789695.n4.nabble.com/How-to-extract-Friday-data-from-daily-data-tp3029050p3031420.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to extract Friday data from daily data.
Hi thanks for quick reply. I am new to using R and still tried to figure out how to use Zoo package. Here is the code I have so far: library(zoo) colClasses - c(NULL, character, character, numeric, character, character, NULL) col.names - c(NA, webpage, item, value, day, date, NA) # z - read.zoo(myfile.dat, skip = 1, index = as.list(1:6), z - read.zoo(C:\\Users\\Kevin\\Desktop\\testdata.csv, sep = ,, skip = 1, index = as.list(1:6), format = %d/%m/%Y, col.names = col.names, aggregate = function(x) tail(x, 1), colClasses = colClasses) # extract all Thursdays and Fridays z45 - z[format(time(z), %w) %in% 4:5,] # keep last entry in each week # and show result on R console z45[!duplicated(format(time(z45), %U), fromLast = TRUE), ] I attached a reproducible dataset in excel http://r.789695.n4.nabble.com/file/n3031422/testdata.csv testdata.csv and I hope to get the results as follows. It would be great if I can get all days in Friday format as you suggested in the second approach the first time. Again your time and help is appreciated! webpage item valueday date time MattDamon fans 642045 Thu 11-Jun-09 22:11:33 MattDamon fans 765057 Fri 19-Jun-09 12:37:09 MattDamon fans 899900 Sat 27-Jun-09 12:40:36 (no Fri or Thu, so I chose Sat) MattDamon views 642045 Thu 11-Jun-09 22:11:33 MattDamon views 765057 Fri 19-Jun-09 12:37:09 MattDamon views 887195 Fri 26-Jun-09 13:36:12 AngieeJolie fans 642045 Thu 11-Jun-09 22:11:33 AngieeJolie fans 765057 Fri 19-Jun-09 12:37:09 AngieeJolie fans 887195 Fri 26-Jun-09 13:36:12 AngieeJolie views 642045 Thu 11-Jun-09 22:11:33 AngieeJolie views 765057 Fri 19-Jun-09 12:37:09 AngieeJolie views 887195 Fri 26-Jun-09 13:36:12 -- View this message in context: http://r.789695.n4.nabble.com/How-to-extract-Friday-data-from-daily-data-tp3029050p3031422.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to extract Friday data from daily data.
I am new to Using R for data analysis. I have an incomplete time series dataset that is in daily format. I want to extract only Friday data from it. However, there are two problems with it. First, if Friday data is missing in that week, I need to extract the data of the day prior to that Friday (e.g. Thursday). Second, sometimes there are duplicate Friday data (say Friday morning and afternoon), but I only need the latest one (Friday afternoon). My question is how I can only extract the Friday data and make it a new dataset so that I have data for every single week for the convenience of data analysis. Your help and time will be appreciated. Thanks. Kevin Below is what my dataset looks like: views number timestamp daytime 1 views 910401 1246192687 Sun 6/28/2009 12:38 2 views 921537 1246278917 Mon 6/29/2009 12:35 3 views 934280 1246365403 Tue 6/30/2009 12:36 4 views 986463 1246888699 Mon 7/6/2009 13:58 5 views 995002 1246970243 Tue 7/7/2009 12:37 6 views 1005211 1247079398 Wed 7/8/2009 18:56 7 views 1011144 1247135553 Thu 7/9/2009 10:32 8 views 1026765 1247308591 Sat 7/11/2009 10:36 9 views 1036856 1247436951 Sun 7/12/2009 22:15 10 views 1040909 1247481564 Mon 7/13/2009 10:39 11 views 1057337 1247568387 Tue 7/14/2009 10:46 12 views 1066999 1247665787 Wed 7/15/2009 13:49 13 views 1077726 1247778752 Thu 7/16/2009 21:12 14 views 1083059 1247845413 Fri 7/17/2009 15:43 15 views 1083059 1247845824 Fri 7/17/2009 18:45 16 views 1089529 1247914194 Sat 7/18/2009 10:49 -- View this message in context: http://r.789695.n4.nabble.com/How-to-extract-Friday-data-from-daily-data-tp3029050p3029050.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to extract Friday data from daily data.
Hey,
This should work, but after you read in your data make sure that your day,
date and time are separate, this should work just fine, or something like
it.
testdata
views number timestamp day date time
1 views 910401 1246192687 Sun 6/28/2009 12:38
2 views 921537 1246278917 Mon 6/29/2009 12:35
3 views 934280 1246365403 Tue 6/30/2009 12:36
4 views 986463 1246888699 Mon 7/6/2009 13:58
5 views 995002 1246970243 Tue 7/7/2009 12:37
6 views 1005211 1247079398 Wed 7/8/2009 18:56
7 views 1011144 1247135553 Thu 7/9/2009 10:32
8 views 1026765 1247308591 Sat 7/11/2009 10:36
9 views 1036856 1247436951 Sun 7/12/2009 22:15
10 views 1040909 1247481564 Mon 7/13/2009 10:39
11 views 1057337 1247568387 Tue 7/14/2009 10:46
12 views 1066999 1247665787 Wed 7/15/2009 13:49
13 views 1077726 1247778752 Thu 7/16/2009 21:12
14 views 1083059 1247845413 Fri 7/17/2009 15:43
15 views 1083059 1247845824 Fri 7/17/2009 18:45
16 views 1089529 1247914194 Sat 7/18/2009 10:49
testdata$date = as.Date(testdata$date,%m/%d/%Y)
Thudat = subset(testdata,day==Thu)
Fridat = subset(testdata,day==Fri)
Friday_dates = Thudat$date+1
Friday_info = NULL
for(i in 1:length(Friday_dates)){
temp = subset(Fridat,date==Friday_dates[i]) # select the Friday dates from
Fridat
if(nrow(temp)0){ # if that Friday date value exists in Friday
Friday_info = rbind(Friday_info,temp[nrow(temp),]) # by saying nrow(temp)
with the data organized chronologically already, you don't have to add an
additional if statement for multiple measurements in the same day.
} else { # if that Friday date value doesn't exist in Fridat
Friday_info = rbind(Friday_info,Thudat[i,]) # choosing the date from Thudat
instead.
}
}
Friday_info
views number timestamp day date time
7 views 1011144 1247135553 Thu 2009-07-09 10:32
15 views 1083059 1247845824 Fri 2009-07-17 18:45
Also, for other things involving getting data out to monthly or weekly, you
might want to try working with some functions from the chron package.
Things like seq.dates can allow you to get the appropriate dates for a
specific day of the week for every week that you want. something like this
for instance:
as.Date(seq.dates(7/3/2009,7/24/2009,by=weeks),%m/%d/%Y)
for all the Fridays in July 2009.
Hope this helps!
A
--
Adrienne Wootten
Graduate Research Assistant
State Climate Office of North Carolina
Department of Marine, Earth and Atmospheric Sciences
North Carolina State University
On Fri, Nov 5, 2010 at 1:22 PM, thornbird huachang...@gmail.com wrote:
I am new to Using R for data analysis. I have an incomplete time series
dataset that is in daily format. I want to extract only Friday data from
it.
However, there are two problems with it.
First, if Friday data is missing in that week, I need to extract the data
of
the day prior to that Friday (e.g. Thursday).
Second, sometimes there are duplicate Friday data (say Friday morning and
afternoon), but I only need the latest one (Friday afternoon).
My question is how I can only extract the Friday data and make it a new
dataset so that I have data for every single week for the convenience of
data analysis.
Your help and time will be appreciated. Thanks. Kevin
Below is what my dataset looks like:
views number timestamp daytime
1 views 910401 1246192687 Sun 6/28/2009 12:38
2 views 921537 1246278917 Mon 6/29/2009 12:35
3 views 934280 1246365403 Tue 6/30/2009 12:36
4 views 986463 1246888699 Mon 7/6/2009 13:58
5 views 995002 1246970243 Tue 7/7/2009 12:37
6 views 1005211 1247079398 Wed 7/8/2009 18:56
7 views 1011144 1247135553 Thu 7/9/2009 10:32
8 views 1026765 1247308591 Sat 7/11/2009 10:36
9 views 1036856 1247436951 Sun 7/12/2009 22:15
10 views 1040909 1247481564 Mon 7/13/2009 10:39
11 views 1057337 1247568387 Tue 7/14/2009 10:46
12 views 1066999 1247665787 Wed 7/15/2009 13:49
13 views 1077726 1247778752 Thu 7/16/2009 21:12
14 views 1083059 1247845413 Fri 7/17/2009 15:43
15 views 1083059 1247845824 Fri 7/17/2009 18:45
16 views 1089529 1247914194 Sat 7/18/2009 10:49
--
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http://r.789695.n4.nabble.com/How-to-extract-Friday-data-from-daily-data-tp3029050p3029050.html
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Re: [R] How to extract Friday data from daily data.
Thank you very much. It worked great with the testdata. I have one more
questionto to ask. As my data is incomplete, sometimes Thu is also missing,
then I have no other options but to pick Sat instead, and if Sat is also
missing, then my best possible option is to pick Wed, and etc. Bascially I
have to pick a day as the data for that week starting from Friday following
this order:
Fri-- (if no Fri) Thu-- (if no Thu) Sat-- (if no Sat) Wed -- (if no Wed)
Sun -- (if no Sun) Tue --(if no Tue) Mon.
In this sense, I have to write a loop if command, right? Could you please
help me with that? Again thanks a lot.
testdata$date = as.Date(testdata$date,%m/%d/%Y)
Thudat = subset(testdata,day==Thu)
Fridat = subset(testdata,day==Fri)
Friday_dates = Thudat$date+1
Friday_info = NULL
for(i in 1:length(Friday_dates)){
temp = subset(Fridat,date==Friday_dates[i]) # select the Friday dates from
Fridat
if(nrow(temp)0){ # if that Friday date value exists in Friday
Friday_info = rbind(Friday_info,temp[nrow(temp),]) # by saying nrow(temp)
with the data organized chronologically already, you don't have to add an
additional if statement for multiple measurements in the same day.
} else { # if that Friday date value doesn't exist in Fridat
Friday_info = rbind(Friday_info,Thudat[i,]) # choosing the date from Thudat
instead.
}
}
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-extract-Friday-data-from-daily-data-tp3029050p3029328.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to extract Friday data from daily data.
On Fri, Nov 5, 2010 at 1:22 PM, thornbird huachang...@gmail.com wrote: I am new to Using R for data analysis. I have an incomplete time series dataset that is in daily format. I want to extract only Friday data from it. However, there are two problems with it. First, if Friday data is missing in that week, I need to extract the data of the day prior to that Friday (e.g. Thursday). Second, sometimes there are duplicate Friday data (say Friday morning and afternoon), but I only need the latest one (Friday afternoon). My question is how I can only extract the Friday data and make it a new dataset so that I have data for every single week for the convenience of data analysis. There are several approaches depending on exactly what is to be produced. We show two of them here using zoo. # read in data Lines - views number timestamp daytime 1 views 910401 1246192687 Sun 6/28/2009 12:38 2 views 921537 1246278917 Mon 6/29/2009 12:35 3 views 934280 1246365403 Tue 6/30/2009 12:36 4 views 986463 1246888699 Mon 7/6/2009 13:58 5 views 995002 1246970243 Tue 7/7/2009 12:37 6 views 1005211 1247079398 Wed 7/8/2009 18:56 7 views 1011144 1247135553 Thu 7/9/2009 10:32 8 views 1026765 1247308591 Sat 7/11/2009 10:36 9 views 1036856 1247436951 Sun 7/12/2009 22:15 10 views 1040909 1247481564 Mon 7/13/2009 10:39 11 views 1057337 1247568387 Tue 7/14/2009 10:46 12 views 1066999 1247665787 Wed 7/15/2009 13:49 13 views 1077726 1247778752 Thu 7/16/2009 21:12 14 views 1083059 1247845413 Fri 7/17/2009 15:43 15 views 1083059 1247845824 Fri 7/17/2009 18:45 16 views 1089529 1247914194 Sat 7/18/2009 10:49 library(zoo) # read in and create a zoo series # - skip= over the header # - index=. the time index is third non-removed column. # - format=. convert the index to Date class using indicated format # - col.names= as specified # - aggregate= over duplicate dates keeping last # - colClasses= specifies NULL for columns we want to remove colClasses - c(NULL, NULL, numeric, numeric, NULL, character, NULL) col.names - c(NA, NA, views, number, NA, NA, NA) # z - read.zoo(myfile.dat, skip = 1, index = 3, z - read.zoo(textConnection(Lines), skip = 1, index = 3, format = %m/%d/%Y, col.names = col.names, aggregate = function(x) tail(x, 1), colClasses = colClasses) ## Now that we have read it in lets process it ## 1. # extract all Thursdays and Fridays z45 - z[format(time(z), %w) %in% 4:5,] # keep last entry in each week # and show result on R console z45[!duplicated(format(time(z45), %U), fromLast = TRUE), ] # 2. alternative approach # above approach labels each point as it was originally labelled # so if Thursday is used it gets the date of that Thursday # Another approach is to always label the resulting point as Friday # and also use the last available value even if its not Thursday # create daily grid g - seq(start(z), end(z), by = day) # fill in daily grid so Friday is filled in with prior value # if Friday is NA z.filled - na.locf(z, xout = g) # extract Fridays (including those filled in from previous) # and show result on R console z.filled[format(time(z.filled), %w) == 5, ] -- Statistics Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to extract Friday data from daily data.
On Fri, Nov 5, 2010 at 8:24 PM, Gabor Grothendieck ggrothendi...@gmail.com wrote: On Fri, Nov 5, 2010 at 1:22 PM, thornbird huachang...@gmail.com wrote: I am new to Using R for data analysis. I have an incomplete time series dataset that is in daily format. I want to extract only Friday data from it. However, there are two problems with it. First, if Friday data is missing in that week, I need to extract the data of the day prior to that Friday (e.g. Thursday). Second, sometimes there are duplicate Friday data (say Friday morning and afternoon), but I only need the latest one (Friday afternoon). My question is how I can only extract the Friday data and make it a new dataset so that I have data for every single week for the convenience of data analysis. There are several approaches depending on exactly what is to be produced. We show two of them here using zoo. # read in data Lines - views number timestamp day time 1 views 910401 1246192687 Sun 6/28/2009 12:38 2 views 921537 1246278917 Mon 6/29/2009 12:35 3 views 934280 1246365403 Tue 6/30/2009 12:36 4 views 986463 1246888699 Mon 7/6/2009 13:58 5 views 995002 1246970243 Tue 7/7/2009 12:37 6 views 1005211 1247079398 Wed 7/8/2009 18:56 7 views 1011144 1247135553 Thu 7/9/2009 10:32 8 views 1026765 1247308591 Sat 7/11/2009 10:36 9 views 1036856 1247436951 Sun 7/12/2009 22:15 10 views 1040909 1247481564 Mon 7/13/2009 10:39 11 views 1057337 1247568387 Tue 7/14/2009 10:46 12 views 1066999 1247665787 Wed 7/15/2009 13:49 13 views 1077726 1247778752 Thu 7/16/2009 21:12 14 views 1083059 1247845413 Fri 7/17/2009 15:43 15 views 1083059 1247845824 Fri 7/17/2009 18:45 16 views 1089529 1247914194 Sat 7/18/2009 10:49 library(zoo) # read in and create a zoo series # - skip= over the header # - index=. the time index is third non-removed column. # - format=. convert the index to Date class using indicated format # - col.names= as specified # - aggregate= over duplicate dates keeping last # - colClasses= specifies NULL for columns we want to remove colClasses - c(NULL, NULL, numeric, numeric, NULL, character, NULL) col.names - c(NA, NA, views, number, NA, NA, NA) # z - read.zoo(myfile.dat, skip = 1, index = 3, z - read.zoo(textConnection(Lines), skip = 1, index = 3, format = %m/%d/%Y, col.names = col.names, aggregate = function(x) tail(x, 1), colClasses = colClasses) ## Now that we have read it in lets process it ## 1. # extract all Thursdays and Fridays z45 - z[format(time(z), %w) %in% 4:5,] # keep last entry in each week # and show result on R console z45[!duplicated(format(time(z45), %U), fromLast = TRUE), ] # 2. alternative approach # above approach labels each point as it was originally labelled # so if Thursday is used it gets the date of that Thursday # Another approach is to always label the resulting point as Friday # and also use the last available value even if its not Thursday # create daily grid g - seq(start(z), end(z), by = day) # fill in daily grid so Friday is filled in with prior value # if Friday is NA z.filled - na.locf(z, xout = g) # extract Fridays (including those filled in from previous) # and show result on R console z.filled[format(time(z.filled), %w) == 5, ] Note that if the data can span more than one year then %U above should be replaced with %Y-%U so that weeks in one year are not lumped with weeks in other years. -- Statistics Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
