Re: [R] How to get names of a list into df:s?
Jim's solution showed me that mine should be simplified to: mapply(data.frame,value=g,nm=names(g),SIMPLIFY=FALSE) This has the slight advantage of automatically naming the list. Cheers, Bert Gunter -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of jim holtman Sent: Thursday, February 21, 2008 4:53 PM To: Lauri Nikkinen Cc: [EMAIL PROTECTED] Subject: Re: [R] How to get names of a list into df:s? Here is one way of doing it: > lapply(names(g), function(z)cbind(x=g[[z]], var1=z)) [[1]] x var1 1 1a 2 2a 3 3a [[2]] x var1 1 4b 2 5b 3 6b [[3]] x var1 1 7c 2 8c 3 9c On Thu, Feb 21, 2008 at 1:22 PM, Lauri Nikkinen <[EMAIL PROTECTED]> wrote: > R users, > > I have a simple lapply question. > > g <- list(a=1:3, b=4:6, c=7:9) > g <- lapply(g, function(x) as.data.frame(x)) > lapply(g, function(x) cbind(x, var1 = rep(names(g), each=nrow(x))[1:nrow(x)])) > > I get > > $a > x var1 > 1 1a > 2 2a > 3 3a > > $b > x var1 > 1 4a > 2 5a > 3 6a > > $c > x var1 > 1 7a > 2 8a > 3 9a > > And I would like to have > > $a > x var1 > 1 1a > 2 2a > 3 3a > > $b > x var1 > 1 4b > 2 5b > 3 6b > > $c > x var1 > 1 7c > 2 8c > 3 9c > > How should I modify my lapply clause to achieve this? > > Best regards, > Lauri > > > sessionInfo() > R version 2.6.1 (2007-11-26) > i386-apple-darwin8.10.1 > > locale: > C > > attached base packages: > [1] stats graphics grDevices utils datasets methods base > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem you are trying to solve? __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to get names of a list into df:s?
Here is one way of doing it: > lapply(names(g), function(z)cbind(x=g[[z]], var1=z)) [[1]] x var1 1 1a 2 2a 3 3a [[2]] x var1 1 4b 2 5b 3 6b [[3]] x var1 1 7c 2 8c 3 9c On Thu, Feb 21, 2008 at 1:22 PM, Lauri Nikkinen <[EMAIL PROTECTED]> wrote: > R users, > > I have a simple lapply question. > > g <- list(a=1:3, b=4:6, c=7:9) > g <- lapply(g, function(x) as.data.frame(x)) > lapply(g, function(x) cbind(x, var1 = rep(names(g), each=nrow(x))[1:nrow(x)])) > > I get > > $a > x var1 > 1 1a > 2 2a > 3 3a > > $b > x var1 > 1 4a > 2 5a > 3 6a > > $c > x var1 > 1 7a > 2 8a > 3 9a > > And I would like to have > > $a > x var1 > 1 1a > 2 2a > 3 3a > > $b > x var1 > 1 4b > 2 5b > 3 6b > > $c > x var1 > 1 7c > 2 8c > 3 9c > > How should I modify my lapply clause to achieve this? > > Best regards, > Lauri > > > sessionInfo() > R version 2.6.1 (2007-11-26) > i386-apple-darwin8.10.1 > > locale: > C > > attached base packages: > [1] stats graphics grDevices utils datasets methods base > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem you are trying to solve? __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to get names of a list into df:s?
mapply(data.frame,value=g,nm=lapply(names(g),rep,length(g)),SIMPLIFY=FALSE) Cheers, Bert Gunter Genentech -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of John Kane Sent: Thursday, February 21, 2008 2:05 PM To: Lauri Nikkinen; [EMAIL PROTECTED] Subject: Re: [R] How to get names of a list into df:s? I don't see any difference --- Lauri Nikkinen <[EMAIL PROTECTED]> wrote: > R users, > > I have a simple lapply question. > > g <- list(a=1:3, b=4:6, c=7:9) > g <- lapply(g, function(x) as.data.frame(x)) > lapply(g, function(x) cbind(x, var1 = rep(names(g), > each=nrow(x))[1:nrow(x)])) > > I get > > $a > x var1 > 1 1a > 2 2a > 3 3a > > $b > x var1 > 1 4a > 2 5a > 3 6a > > $c > x var1 > 1 7a > 2 8a > 3 9a > > And I would like to have > > $a > x var1 > 1 1a > 2 2a > 3 3a > > $b > x var1 > 1 4b > 2 5b > 3 6b > > $c > x var1 > 1 7c > 2 8c > 3 9c > > How should I modify my lapply clause to achieve > this? > > Best regards, > Lauri > > > sessionInfo() > R version 2.6.1 (2007-11-26) > i386-apple-darwin8.10.1 > > locale: > C > > attached base packages: > [1] stats graphics grDevices utils datasets > methods base > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. > __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to get names of a list into df:s?
I don't see any difference --- Lauri Nikkinen <[EMAIL PROTECTED]> wrote: > R users, > > I have a simple lapply question. > > g <- list(a=1:3, b=4:6, c=7:9) > g <- lapply(g, function(x) as.data.frame(x)) > lapply(g, function(x) cbind(x, var1 = rep(names(g), > each=nrow(x))[1:nrow(x)])) > > I get > > $a > x var1 > 1 1a > 2 2a > 3 3a > > $b > x var1 > 1 4a > 2 5a > 3 6a > > $c > x var1 > 1 7a > 2 8a > 3 9a > > And I would like to have > > $a > x var1 > 1 1a > 2 2a > 3 3a > > $b > x var1 > 1 4b > 2 5b > 3 6b > > $c > x var1 > 1 7c > 2 8c > 3 9c > > How should I modify my lapply clause to achieve > this? > > Best regards, > Lauri > > > sessionInfo() > R version 2.6.1 (2007-11-26) > i386-apple-darwin8.10.1 > > locale: > C > > attached base packages: > [1] stats graphics grDevices utils datasets > methods base > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. > __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to get names of a list into df:s?
On Thursday 21 February 2008 (19:22:40), Lauri Nikkinen wrote: > R users, > > I have a simple lapply question. > > g <- list(a=1:3, b=4:6, c=7:9) > g <- lapply(g, function(x) as.data.frame(x)) > And I would like to have > > $a > x var1 > 1 1 a > 2 2 a > 3 3 a > > $b > x var1 > 1 4 b > 2 5 b > 3 6 b > > $c > x var1 > 1 7 c > 2 8 c > 3 9 c The following seems to work: sapply(names(g), function(n) cbind( g[[n]], var1 = rep(n,each=nrow(g[[n]])) ), simplify=FALSE) Best, Martin __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to get names of a list into df:s?
Try this: g <- list(a=1:3, b=4:6, c=7:9) with(stack(g), split(stack(g), ind)) On 21/02/2008, Lauri Nikkinen <[EMAIL PROTECTED]> wrote: > R users, > > I have a simple lapply question. > > g <- list(a=1:3, b=4:6, c=7:9) > g <- lapply(g, function(x) as.data.frame(x)) > lapply(g, function(x) cbind(x, var1 = rep(names(g), > each=nrow(x))[1:nrow(x)])) > > I get > > $a > x var1 > 1 1a > 2 2a > 3 3a > > $b > x var1 > 1 4a > 2 5a > 3 6a > > $c > x var1 > 1 7a > 2 8a > 3 9a > > And I would like to have > > $a > x var1 > 1 1a > 2 2a > 3 3a > > $b > x var1 > 1 4b > 2 5b > 3 6b > > $c > x var1 > 1 7c > 2 8c > 3 9c > > How should I modify my lapply clause to achieve this? > > Best regards, > Lauri > > > sessionInfo() > R version 2.6.1 (2007-11-26) > i386-apple-darwin8.10.1 > > locale: > C > > attached base packages: > [1] stats graphics grDevices utils datasets methods base > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to get names of a list into df:s?
R users, I have a simple lapply question. g <- list(a=1:3, b=4:6, c=7:9) g <- lapply(g, function(x) as.data.frame(x)) lapply(g, function(x) cbind(x, var1 = rep(names(g), each=nrow(x))[1:nrow(x)])) I get $a x var1 1 1a 2 2a 3 3a $b x var1 1 4a 2 5a 3 6a $c x var1 1 7a 2 8a 3 9a And I would like to have $a x var1 1 1a 2 2a 3 3a $b x var1 1 4b 2 5b 3 6b $c x var1 1 7c 2 8c 3 9c How should I modify my lapply clause to achieve this? Best regards, Lauri > sessionInfo() R version 2.6.1 (2007-11-26) i386-apple-darwin8.10.1 locale: C attached base packages: [1] stats graphics grDevices utils datasets methods base __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
