Re: [R] How to improve accuracy of output?
Hello, I cannot reproduce this print behavior, with digits=14, there are 14 digits printed. x <- c(98.718527356108, 103.10265923704) x #> [1] 98.71853 103.10266 old_dig <- options(digits = 14) x #> [1] 98.718527356108 103.102659237040 options(old_dig) Maybe there's something else going on? Hope this helps, Rui Barradas Às 15:00 de 24/05/2022, maithili_shiva--- via R-help escreveu: Dear Forum In my code, I am trying to compute Value at risk. I have an issue as mentioned below: I have defined options(digits = 14) But my output is something like df$price [1] 98.7185273 103.10265923 However, if use Excel, I get values as 98.718527356108 103.10265923704 and so on. Is there any way I can improve on R output accuracy. Problem is If I use options(digits = 20) I still get same prices as when I was using options(digits = 14) and on the other hand my confidence level value, which should be equal to 0.99, gets distorted to 0.9899 impacting Value at Risk value. Please guide Regards Maithreyi [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to improve accuracy of output?
I think you have to use print(df$price, digits = 14) On Tue, May 24, 2022, 10:01 maithili_shiva--- via R-help < r-help@r-project.org> wrote: > Dear Forum > In my code, I am trying to compute Value at risk. > I have an issue as mentioned below: > I have defined > > > options(digits = 14) > But my output is something like > > df$price > [1] 98.7185273 103.10265923 > However, if use Excel, I get values as > 98.718527356108 103.10265923704 > and so on. > Is there any way I can improve on R output accuracy. > Problem is If I use > options(digits = 20) > I still get same prices as when I was using options(digits = 14) and on > the other hand my confidence level value, which should be equal to 0.99, > gets distorted to 0.9899 impacting Value at Risk value. > Please guide > Regards > Maithreyi > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] How to improve accuracy of output?
Dear Forum In my code, I am trying to compute Value at risk. I have an issue as mentioned below: I have defined options(digits = 14) But my output is something like > df$price [1] 98.7185273 103.10265923 However, if use Excel, I get values as 98.718527356108 103.10265923704 and so on. Is there any way I can improve on R output accuracy. Problem is If I use options(digits = 20) I still get same prices as when I was using options(digits = 14) and on the other hand my confidence level value, which should be equal to 0.99, gets distorted to 0.9899 impacting Value at Risk value. Please guide Regards Maithreyi [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
