Re: [R] Judging if a matrix contains any NA
On 27 Jul 2015, at 03:18 , LiuNing liuning.1...@qq.com wrote: all(is.na(a)) [1] FALSE Bzzt! Try !all(is.finite(a)) -pd -- Original -- From: Steven Yen;sye...@gmail.com; Date: Mon, Jul 27, 2015 09:10 AM To: r-help mailing listr-help@r-project.org; Subject: [R] Judging if a matrix contains any NA How do I judge if a matrix contain any NA or otherwise non-missing, non-numerical? In the following, I would like to deliver ONE logical of TRUE or FALSE, rather than a 4 x 4 matrix containing TRUE or FALSE. Thank you. a-matrix(1:16,nrow=4) diag(a)-NA a [,1] [,2] [,3] [,4] [1,] NA59 13 [2,]2 NA 10 14 [3,]37 NA 15 [4,]48 12 NA is.na(a) [,1] [,2] [,3] [,4] [1,] TRUE FALSE FALSE FALSE [2,] FALSE TRUE FALSE FALSE [3,] FALSE FALSE TRUE FALSE [4,] FALSE FALSE FALSE TRUE __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Peter Dalgaard, Professor, Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Email: pd@cbs.dk Priv: pda...@gmail.com __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Judging if a matrix contains any NA
How do I judge if a matrix contain any NA or otherwise non-missing, non-numerical? In the following, I would like to deliver ONE logical of TRUE or FALSE, rather than a 4 x 4 matrix containing TRUE or FALSE. Thank you. a-matrix(1:16,nrow=4) diag(a)-NA a [,1] [,2] [,3] [,4] [1,] NA59 13 [2,]2 NA 10 14 [3,]37 NA 15 [4,]48 12 NA is.na(a) [,1] [,2] [,3] [,4] [1,] TRUE FALSE FALSE FALSE [2,] FALSE TRUE FALSE FALSE [3,] FALSE FALSE TRUE FALSE [4,] FALSE FALSE FALSE TRUE __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Judging if a matrix contains any NA
On Jul 26, 2015, at 6:10 PM, Steven Yen wrote: How do I judge if a matrix contain any NA or otherwise non-missing, non-numerical? In the following, I would like to deliver ONE logical of TRUE or FALSE, rather than a 4 x 4 matrix containing TRUE or FALSE. Thank you. a-matrix(1:16,nrow=4) diag(a)-NA a [,1] [,2] [,3] [,4] [1,] NA59 13 [2,]2 NA 10 14 [3,]37 NA 15 [4,]48 12 NA any(is.na( a)) [1] TRUE is.na(a) [,1] [,2] [,3] [,4] [1,] TRUE FALSE FALSE FALSE [2,] FALSE TRUE FALSE FALSE [3,] FALSE FALSE TRUE FALSE [4,] FALSE FALSE FALSE TRUE __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. David Winsemius Alameda, CA, USA __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Judging if a matrix contains any NA
all(is.na(a)) [1] FALSE -- Original -- From: Steven Yen;sye...@gmail.com; Date: Mon, Jul 27, 2015 09:10 AM To: r-help mailing listr-help@r-project.org; Subject: [R] Judging if a matrix contains any NA How do I judge if a matrix contain any NA or otherwise non-missing, non-numerical? In the following, I would like to deliver ONE logical of TRUE or FALSE, rather than a 4 x 4 matrix containing TRUE or FALSE. Thank you. a-matrix(1:16,nrow=4) diag(a)-NA a [,1] [,2] [,3] [,4] [1,] NA59 13 [2,]2 NA 10 14 [3,]37 NA 15 [4,]48 12 NA is.na(a) [,1] [,2] [,3] [,4] [1,] TRUE FALSE FALSE FALSE [2,] FALSE TRUE FALSE FALSE [3,] FALSE FALSE TRUE FALSE [4,] FALSE FALSE FALSE TRUE __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Judging if a matrix contains any NA
On 26/07/2015 9:10 PM, Steven Yen wrote: How do I judge if a matrix contain any NA or otherwise non-missing, non-numerical? David told you about any(). You may also want to use !is.finite() instead of is.na(). Duncan Murdoch In the following, I would like to deliver ONE logical of TRUE or FALSE, rather than a 4 x 4 matrix containing TRUE or FALSE. Thank you. a-matrix(1:16,nrow=4) diag(a)-NA a [,1] [,2] [,3] [,4] [1,] NA59 13 [2,]2 NA 10 14 [3,]37 NA 15 [4,]48 12 NA is.na(a) [,1] [,2] [,3] [,4] [1,] TRUE FALSE FALSE FALSE [2,] FALSE TRUE FALSE FALSE [3,] FALSE FALSE TRUE FALSE [4,] FALSE FALSE FALSE TRUE __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
