[R] Loading List data into R with scan()
Hi All, I've been given a data file of the form: 1: 3,4,5,6 2:1,2,3 43: 5,7,8,9,5 and i want to read this data in as a list to create the form: (guessing final look) my.list [[1]] [1] 3 4 5 6 [[2]] [1] 1 2 3 [[43]] [1] 5 7 8 9 5 I can get to a stage using scan: scan(my.data, what = character(0), quiet = TRUE) to load [1] 1: 3,4,5,6 [2] 2:1,2,3 [3] 43: 5,7,8,9,5 but im not sure on how next to proceed to arrange this into a list form, can anyone offer some advise? Thanks in advance Mike [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Loading List data into R with scan()
On 23.06.2011 16:39, Michael Pearmain wrote:
Hi All,
I've been given a data file of the form:
1: 3,4,5,6
2:1,2,3
43: 5,7,8,9,5
and i want to read this data in as a list to create the form:
(guessing final look)
my.list
[[1]]
[1] 3 4 5 6
[[2]]
[1] 1 2 3
[[43]]
[1] 5 7 8 9 5
I can get to a stage using scan:
scan(my.data, what = character(0), quiet = TRUE)
to load
[1] 1: 3,4,5,6
[2] 2:1,2,3
[3] 43: 5,7,8,9,5
I don't understand why you want 40 empty list elements, but here is what
you asked for (not optimized, just hacked in few seconds):
temp - strsplit(d, :)
num - as.numeric(sapply(temp, [[, 1))
L - vector(mode = list, length = max(num))
for(i in seq_along(temp)){
L[[num[i]]] - as.numeric(unlist(strsplit(temp[[i]][2], ,)))
}
L
Uwe Ligges
but im not sure on how next to proceed to arrange this into a list form, can
anyone offer some advise?
Thanks in advance
Mike
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Loading List data into R with scan()
l - readLines(textConnection(1: 3,4,5,6 2:1,2,3 43: 5,7,8,9,5)) On Thu, Jun 23, 2011 at 12:28 PM, Henrique Dallazuanna www...@gmail.com wrote: Try this: sapply(lapply(strsplit(l, :), strsplit, ,), function(x)structure(lapply(x[2], as.numeric), .Names = x[1])) On Thu, Jun 23, 2011 at 11:39 AM, Michael Pearmain michael.pearm...@gmail.com wrote: Hi All, I've been given a data file of the form: 1: 3,4,5,6 2:1,2,3 43: 5,7,8,9,5 and i want to read this data in as a list to create the form: (guessing final look) my.list [[1]] [1] 3 4 5 6 [[2]] [1] 1 2 3 [[43]] [1] 5 7 8 9 5 I can get to a stage using scan: scan(my.data, what = character(0), quiet = TRUE) to load [1] 1: 3,4,5,6 [2] 2:1,2,3 [3] 43: 5,7,8,9,5 but im not sure on how next to proceed to arrange this into a list form, can anyone offer some advise? Thanks in advance Mike [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Loading List data into R with scan()
Thanks Uwe,
The list elements was a mistake on my part, i just wanted everything before
the : to be the name of the element.
Thanks for the help, i can play around with this to get what i want.
M
2011/6/23 Uwe Ligges lig...@statistik.tu-dortmund.de
On 23.06.2011 16:39, Michael Pearmain wrote:
Hi All,
I've been given a data file of the form:
1: 3,4,5,6
2:1,2,3
43: 5,7,8,9,5
and i want to read this data in as a list to create the form:
(guessing final look)
my.list
[[1]]
[1] 3 4 5 6
[[2]]
[1] 1 2 3
[[43]]
[1] 5 7 8 9 5
I can get to a stage using scan:
scan(my.data, what = character(0), quiet = TRUE)
to load
[1] 1: 3,4,5,6
[2] 2:1,2,3
[3] 43: 5,7,8,9,5
I don't understand why you want 40 empty list elements, but here is what
you asked for (not optimized, just hacked in few seconds):
temp - strsplit(d, :)
num - as.numeric(sapply(temp, [[, 1))
L - vector(mode = list, length = max(num))
for(i in seq_along(temp)){
L[[num[i]]] - as.numeric(unlist(strsplit(**temp[[i]][2], ,)))
}
L
Uwe Ligges
but im not sure on how next to proceed to arrange this into a list form,
can
anyone offer some advise?
Thanks in advance
Mike
[[alternative HTML version deleted]]
__**
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/**listinfo/r-helphttps://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/**
posting-guide.html http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Loading List data into R with scan()
Try this: sapply(lapply(strsplit(l, :), strsplit, ,), function(x)structure(lapply(x[2], as.numeric), .Names = x[1])) On Thu, Jun 23, 2011 at 11:39 AM, Michael Pearmain michael.pearm...@gmail.com wrote: Hi All, I've been given a data file of the form: 1: 3,4,5,6 2:1,2,3 43: 5,7,8,9,5 and i want to read this data in as a list to create the form: (guessing final look) my.list [[1]] [1] 3 4 5 6 [[2]] [1] 1 2 3 [[43]] [1] 5 7 8 9 5 I can get to a stage using scan: scan(my.data, what = character(0), quiet = TRUE) to load [1] 1: 3,4,5,6 [2] 2:1,2,3 [3] 43: 5,7,8,9,5 but im not sure on how next to proceed to arrange this into a list form, can anyone offer some advise? Thanks in advance Mike [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Loading List data into R with scan()
On Jun 23, 2011, at 11:19 AM, Uwe Ligges wrote:
On 23.06.2011 16:39, Michael Pearmain wrote:
Hi All,
I've been given a data file of the form:
1: 3,4,5,6
2:1,2,3
43: 5,7,8,9,5
and i want to read this data in as a list to create the form:
(guessing final look)
my.list
[[1]]
[1] 3 4 5 6
[[2]]
[1] 1 2 3
[[43]]
[1] 5 7 8 9 5
I can get to a stage using scan:
scan(my.data, what = character(0), quiet = TRUE)
to load
[1] 1: 3,4,5,6
[2] 2:1,2,3
[3] 43: 5,7,8,9,5
I don't understand why you want 40 empty list elements, but here is
what you asked for (not optimized, just hacked in few seconds):
temp - strsplit(d, :)
num - as.numeric(sapply(temp, [[, 1))
L - vector(mode = list, length = max(num))
for(i in seq_along(temp)){
L[[num[i]]] - as.numeric(unlist(strsplit(temp[[i]][2], ,)))
}
L
I wondered about that too. Perhaps he would be satisfied with alpha
indexing:
d - c( 1: 3,4,5,6, 2:1,2,3, 43: 5,7,8,9,5)
temp - strsplit(d, :)
num - sapply(temp, [[, 1)
L - vector(mode = list)
for(i in seq_along(temp)){
L[[num[i]]] - as.numeric(unlist(strsplit(temp[[i]][2], ,)))
}
L
$`1`
[1] 3 4 5 6
$`2`
[1] 1 2 3
$`43`
[1] 5 7 8 9 5
Uwe Ligges
but im not sure on how next to proceed to arrange this into a list
form, can
anyone offer some advise?
Thanks in advance
Mike
David Winsemius, MD
West Hartford, CT
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Loading List data into R with scan()
Thanks All,
Henrique, gave me the solution is was looking for, the indexing was a
mistake on my part.
Thanks again
On 23 June 2011 16:37, David Winsemius dwinsem...@comcast.net wrote:
On Jun 23, 2011, at 11:19 AM, Uwe Ligges wrote:
On 23.06.2011 16:39, Michael Pearmain wrote:
Hi All,
I've been given a data file of the form:
1: 3,4,5,6
2:1,2,3
43: 5,7,8,9,5
and i want to read this data in as a list to create the form:
(guessing final look)
my.list
[[1]]
[1] 3 4 5 6
[[2]]
[1] 1 2 3
[[43]]
[1] 5 7 8 9 5
I can get to a stage using scan:
scan(my.data, what = character(0), quiet = TRUE)
to load
[1] 1: 3,4,5,6
[2] 2:1,2,3
[3] 43: 5,7,8,9,5
I don't understand why you want 40 empty list elements, but here is what
you asked for (not optimized, just hacked in few seconds):
temp - strsplit(d, :)
num - as.numeric(sapply(temp, [[, 1))
L - vector(mode = list, length = max(num))
for(i in seq_along(temp)){
L[[num[i]]] - as.numeric(unlist(strsplit(**temp[[i]][2], ,)))
}
L
I wondered about that too. Perhaps he would be satisfied with alpha
indexing:
d - c( 1: 3,4,5,6, 2:1,2,3, 43: 5,7,8,9,5)
temp - strsplit(d, :)
num - sapply(temp, [[, 1)
L - vector(mode = list)
for(i in seq_along(temp)){
L[[num[i]]] - as.numeric(unlist(strsplit(**temp[[i]][2], ,)))
}
L
$`1`
[1] 3 4 5 6
$`2`
[1] 1 2 3
$`43`
[1] 5 7 8 9 5
Uwe Ligges
but im not sure on how next to proceed to arrange this into a list form,
can
anyone offer some advise?
Thanks in advance
Mike
David Winsemius, MD
West Hartford, CT
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
