Re: [R] Matrix to Vector
George Coyle wrote: Hi All, I am trying to turn a Matrix into a vector for analysis purposes. I need to select only certain columns from the entire matrix for the vector (intraday time intervals). Also I need to transpose the Matrix (so times are in rows) stack each successive new column on top of each other (latest at the top creating one long vector vs a matrix) then reassign the date to the left of each time (right now date is only shown once by row and will be in columns when transposed). Any thoughts? Yes, specify your problem with reproducible R code, so we can help you. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Matrix to Vector
How about: ?subset ?t ?as.vector I'm not sure transposing is really needed, but without a workable example as requested in the posting guide (hint, hint), it's hard to say for certain. Sarah On Tue, Jun 15, 2010 at 1:51 PM, George Coyle wrote: > Hi All, > > I am trying to turn a Matrix into a vector for analysis purposes. I need to > select only certain columns from the entire matrix for the vector (intraday > time intervals). Also I need to transpose the Matrix (so times are in rows) > stack each successive new column on top of each other (latest at the top > creating one long vector vs a matrix) then reassign the date to the left of > each time (right now date is only shown once by row and will be in columns > when transposed). Any thoughts? > -- Sarah Goslee http://www.functionaldiversity.org __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Matrix to Vector
Hi All, I am trying to turn a Matrix into a vector for analysis purposes. I need to select only certain columns from the entire matrix for the vector (intraday time intervals). Also I need to transpose the Matrix (so times are in rows) stack each successive new column on top of each other (latest at the top creating one long vector vs a matrix) then reassign the date to the left of each time (right now date is only shown once by row and will be in columns when transposed). Any thoughts? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Matrix to Vector
I bet that is what I did. On Sat, Jun 5, 2010 at 11:54 AM, John Kane wrote: > m<-matrix(seq(1,48),nrow=6,byrow=T) > as.vector(t(m)) > > gives me the correct result. > > Any chance you may have already transformed m ? > > --- On Sat, 6/5/10, steven mosher wrote: > > > From: steven mosher > > Subject: Re: [R] Matrix to Vector > > To: "Henrique Dallazuanna" > > Cc: r-help@r-project.org > > Received: Saturday, June 5, 2010, 2:44 PM > > as.vector(t(m)) > > [1] 1 9 17 25 33 41 2 10 18 26 34 > > 42 3 11 19 27 35 43 4 12 20 28 36 44 > > 5 13 21 29 37 45 6 14 22 30 38 46 7 15 23 31 > > 39 47 8 16 24 > > [46] 32 40 48 > > > > the result I want is this: > > > > [1] 1 2 3 4 5 6 > > 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 > > 24 > > 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 > > 45 > > [46] 46 47 48 > > > > > > > > On Sat, Jun 5, 2010 at 11:17 AM, Henrique Dallazuanna > > wrote: > > > > > Try this: > > > > > > as.vector(t(m)) > > > > > > On Sat, Jun 5, 2010 at 3:12 PM, steven mosher >wrote: > > > > > >> Given a matrix of m*n, I want to reorder it as a > > vector, using a row major > > >> transpose. > > >> > > >> so: > > >> > > >> > m<-matrix(seq(1,48),nrow=6,byrow=T) > > >> > m > > >> [,1] [,2] [,3] [,4] [,5] > > [,6] [,7] [,8] > > >> [1,]12 > > 3456 > > 78 > > >> [2,] > > 9 10 11 12 13 14 15 16 > > >> > > [3,] 17 18 19 20 21 22 23 24 > > >> > > [4,] 25 26 27 28 29 30 31 32 > > >> > > [5,] 33 34 35 36 37 38 39 40 > > >> > > [6,] 41 42 43 44 45 46 47 48 > > >> > > >> I want to reorder this as a vector copying by row, > > so that the final > > >> vector > > >> has elements ordered thusly: row 1, column 1:N > > (m[1,1:n]) maps to > > >> row 1-n, and m[2,1:n] maps to row[n+1:2n] ... > > >> > > >> this obviously is not a solution: as the inherent > > column major storage > > >> paradigm of a matrix > > >> defeats the approach. > > >> > dim(m)<-c(48,1) > > >> > m > > >> [,1] > > >> [1,]1 > > >> [2,]9 > > >> [3,] 17 > > >> [4,] 25 > > >> [5,] 33 > > >> [6,] 41 > > >> [7,]2 > > >> [8,] 10 > > >> [9,] 18 > > >> [10,] 26 > > >> [11,] 34 > > >> [12,] 42 > > >> [13,]3 > > >> [14,] 11 > > >> [15,] 19 > > >> [16,] 27 > > >> [17,] 35 > > >> [18,] 43 > > >> [19,]4 > > >> [20,] 12 > > >> [21,] 20 > > >> [22,] 28 > > >> [23,] 36 > > >> [24,] 44 > > >> [25,]5 > > >> [26,] 13 > > >> [27,] 21 > > >> [28,] 29 > > >> [29,] 37 > > >> [30,] 45 > > >> [31,]6 > > >> [32,] 14 > > >> [33,] 22 > > >> [34,] 30 > > >> [35,] 38 > > >> [36,] 46 > > >> [37,]7 > > >> [38,] 15 > > >> [39,] 23 > > >> [40,] 31 > > >> [41,] 39 > > >> [42,] 47 > > >> [43,]8 > > >> [44,] 16 > > >> [45,] 24 > > >> [46,] 32 > > >> [47,] 40 > > >> [48,] 48 > > >> > > >> > > >> I already have a version that loops through the > > data ( this is actually a > > >> portion of a data frame ) to reorder > > >> this into a vector, but I was hoping there was an > > elegant way > > >> > > >>[[alternative HTML > > version deleted]] > > >> > > >> __ > > >> R-help@r-project.org > > mailing list > > >> https://stat.ethz.ch/mailman/listinfo/r-help > > >> PLEASE do read the posting guide > > >> http://www.R-project.org/posting-guide.html > > >> and provide commented, minimal, self-contained, > > reproducible code. > > >> > > > > > > > > > > > > -- > > > Henrique Dallazuanna > > > Curitiba-Paraná-Brasil > > > 25° 25' 40" S 49° 16' 22" O > > > > > > > [[alternative HTML version deleted]] > > > > > > -Inline Attachment Follows- > > > > __ > > R-help@r-project.org > > mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, > > reproducible code. > > > > > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Matrix to Vector
m<-matrix(seq(1,48),nrow=6,byrow=T) as.vector(t(m)) gives me the correct result. Any chance you may have already transformed m ? --- On Sat, 6/5/10, steven mosher wrote: > From: steven mosher > Subject: Re: [R] Matrix to Vector > To: "Henrique Dallazuanna" > Cc: r-help@r-project.org > Received: Saturday, June 5, 2010, 2:44 PM > as.vector(t(m)) > [1] 1 9 17 25 33 41 2 10 18 26 34 > 42 3 11 19 27 35 43 4 12 20 28 36 44 > 5 13 21 29 37 45 6 14 22 30 38 46 7 15 23 31 > 39 47 8 16 24 > [46] 32 40 48 > > the result I want is this: > > [1] 1 2 3 4 5 6 > 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 > 24 > 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 > 45 > [46] 46 47 48 > > > > On Sat, Jun 5, 2010 at 11:17 AM, Henrique Dallazuanna > wrote: > > > Try this: > > > > as.vector(t(m)) > > > > On Sat, Jun 5, 2010 at 3:12 PM, steven mosher wrote: > > > >> Given a matrix of m*n, I want to reorder it as a > vector, using a row major > >> transpose. > >> > >> so: > >> > >> > m<-matrix(seq(1,48),nrow=6,byrow=T) > >> > m > >> [,1] [,2] [,3] [,4] [,5] > [,6] [,7] [,8] > >> [1,] 1 2 > 3 4 5 6 > 7 8 > >> [2,] > 9 10 11 12 13 14 15 16 > >> > [3,] 17 18 19 20 21 22 23 24 > >> > [4,] 25 26 27 28 29 30 31 32 > >> > [5,] 33 34 35 36 37 38 39 40 > >> > [6,] 41 42 43 44 45 46 47 48 > >> > >> I want to reorder this as a vector copying by row, > so that the final > >> vector > >> has elements ordered thusly: row 1, column 1:N > (m[1,1:n]) maps to > >> row 1-n, and m[2,1:n] maps to row[n+1:2n] ... > >> > >> this obviously is not a solution: as the inherent > column major storage > >> paradigm of a matrix > >> defeats the approach. > >> > dim(m)<-c(48,1) > >> > m > >> [,1] > >> [1,] 1 > >> [2,] 9 > >> [3,] 17 > >> [4,] 25 > >> [5,] 33 > >> [6,] 41 > >> [7,] 2 > >> [8,] 10 > >> [9,] 18 > >> [10,] 26 > >> [11,] 34 > >> [12,] 42 > >> [13,] 3 > >> [14,] 11 > >> [15,] 19 > >> [16,] 27 > >> [17,] 35 > >> [18,] 43 > >> [19,] 4 > >> [20,] 12 > >> [21,] 20 > >> [22,] 28 > >> [23,] 36 > >> [24,] 44 > >> [25,] 5 > >> [26,] 13 > >> [27,] 21 > >> [28,] 29 > >> [29,] 37 > >> [30,] 45 > >> [31,] 6 > >> [32,] 14 > >> [33,] 22 > >> [34,] 30 > >> [35,] 38 > >> [36,] 46 > >> [37,] 7 > >> [38,] 15 > >> [39,] 23 > >> [40,] 31 > >> [41,] 39 > >> [42,] 47 > >> [43,] 8 > >> [44,] 16 > >> [45,] 24 > >> [46,] 32 > >> [47,] 40 > >> [48,] 48 > >> > >> > >> I already have a version that loops through the > data ( this is actually a > >> portion of a data frame ) to reorder > >> this into a vector, but I was hoping there was an > elegant way > >> > >> [[alternative HTML > version deleted]] > >> > >> __ > >> R-help@r-project.org > mailing list > >> https://stat.ethz.ch/mailman/listinfo/r-help > >> PLEASE do read the posting guide > >> http://www.R-project.org/posting-guide.html > >> and provide commented, minimal, self-contained, > reproducible code. > >> > > > > > > > > -- > > Henrique Dallazuanna > > Curitiba-Paraná-Brasil > > 25° 25' 40" S 49° 16' 22" O > > > > [[alternative HTML version deleted]] > > > -Inline Attachment Follows- > > __ > R-help@r-project.org > mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. > __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Matrix to Vector
as.vector(t(m)) [1] 1 9 17 25 33 41 2 10 18 26 34 42 3 11 19 27 35 43 4 12 20 28 36 44 5 13 21 29 37 45 6 14 22 30 38 46 7 15 23 31 39 47 8 16 24 [46] 32 40 48 the result I want is this: [1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 [46] 46 47 48 On Sat, Jun 5, 2010 at 11:17 AM, Henrique Dallazuanna wrote: > Try this: > > as.vector(t(m)) > > On Sat, Jun 5, 2010 at 3:12 PM, steven mosher wrote: > >> Given a matrix of m*n, I want to reorder it as a vector, using a row major >> transpose. >> >> so: >> >> > m<-matrix(seq(1,48),nrow=6,byrow=T) >> > m >> [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] >> [1,]12345678 >> [2,]9 10 11 12 13 14 15 16 >> [3,] 17 18 19 20 21 22 23 24 >> [4,] 25 26 27 28 29 30 31 32 >> [5,] 33 34 35 36 37 38 39 40 >> [6,] 41 42 43 44 45 46 47 48 >> >> I want to reorder this as a vector copying by row, so that the final >> vector >> has elements ordered thusly: row 1, column 1:N (m[1,1:n]) maps to >> row 1-n, and m[2,1:n] maps to row[n+1:2n] ... >> >> this obviously is not a solution: as the inherent column major storage >> paradigm of a matrix >> defeats the approach. >> > dim(m)<-c(48,1) >> > m >> [,1] >> [1,]1 >> [2,]9 >> [3,] 17 >> [4,] 25 >> [5,] 33 >> [6,] 41 >> [7,]2 >> [8,] 10 >> [9,] 18 >> [10,] 26 >> [11,] 34 >> [12,] 42 >> [13,]3 >> [14,] 11 >> [15,] 19 >> [16,] 27 >> [17,] 35 >> [18,] 43 >> [19,]4 >> [20,] 12 >> [21,] 20 >> [22,] 28 >> [23,] 36 >> [24,] 44 >> [25,]5 >> [26,] 13 >> [27,] 21 >> [28,] 29 >> [29,] 37 >> [30,] 45 >> [31,]6 >> [32,] 14 >> [33,] 22 >> [34,] 30 >> [35,] 38 >> [36,] 46 >> [37,]7 >> [38,] 15 >> [39,] 23 >> [40,] 31 >> [41,] 39 >> [42,] 47 >> [43,]8 >> [44,] 16 >> [45,] 24 >> [46,] 32 >> [47,] 40 >> [48,] 48 >> >> >> I already have a version that loops through the data ( this is actually a >> portion of a data frame ) to reorder >> this into a vector, but I was hoping there was an elegant way >> >>[[alternative HTML version deleted]] >> >> __ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > > > > -- > Henrique Dallazuanna > Curitiba-Paraná-Brasil > 25° 25' 40" S 49° 16' 22" O > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Matrix to Vector
Hi Steven, If I understood correctly, this might do what you want: c(t(m)) HTH, Jorge On Sat, Jun 5, 2010 at 2:12 PM, steven mosher wrote: > Given a matrix of m*n, I want to reorder it as a vector, using a row major > transpose. > > so: > > > m<-matrix(seq(1,48),nrow=6,byrow=T) > > m > [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] > [1,]12345678 > [2,]9 10 11 12 13 14 15 16 > [3,] 17 18 19 20 21 22 23 24 > [4,] 25 26 27 28 29 30 31 32 > [5,] 33 34 35 36 37 38 39 40 > [6,] 41 42 43 44 45 46 47 48 > > I want to reorder this as a vector copying by row, so that the final vector > has elements ordered thusly: row 1, column 1:N (m[1,1:n]) maps to > row 1-n, and m[2,1:n] maps to row[n+1:2n] ... > > this obviously is not a solution: as the inherent column major storage > paradigm of a matrix > defeats the approach. > > dim(m)<-c(48,1) > > m > [,1] > [1,]1 > [2,]9 > [3,] 17 > [4,] 25 > [5,] 33 > [6,] 41 > [7,]2 > [8,] 10 > [9,] 18 > [10,] 26 > [11,] 34 > [12,] 42 > [13,]3 > [14,] 11 > [15,] 19 > [16,] 27 > [17,] 35 > [18,] 43 > [19,]4 > [20,] 12 > [21,] 20 > [22,] 28 > [23,] 36 > [24,] 44 > [25,]5 > [26,] 13 > [27,] 21 > [28,] 29 > [29,] 37 > [30,] 45 > [31,]6 > [32,] 14 > [33,] 22 > [34,] 30 > [35,] 38 > [36,] 46 > [37,]7 > [38,] 15 > [39,] 23 > [40,] 31 > [41,] 39 > [42,] 47 > [43,]8 > [44,] 16 > [45,] 24 > [46,] 32 > [47,] 40 > [48,] 48 > > > I already have a version that loops through the data ( this is actually a > portion of a data frame ) to reorder > this into a vector, but I was hoping there was an elegant way > >[[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Matrix to Vector
Try this: as.vector(t(m)) On Sat, Jun 5, 2010 at 3:12 PM, steven mosher wrote: > Given a matrix of m*n, I want to reorder it as a vector, using a row major > transpose. > > so: > > > m<-matrix(seq(1,48),nrow=6,byrow=T) > > m > [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] > [1,]12345678 > [2,]9 10 11 12 13 14 15 16 > [3,] 17 18 19 20 21 22 23 24 > [4,] 25 26 27 28 29 30 31 32 > [5,] 33 34 35 36 37 38 39 40 > [6,] 41 42 43 44 45 46 47 48 > > I want to reorder this as a vector copying by row, so that the final vector > has elements ordered thusly: row 1, column 1:N (m[1,1:n]) maps to > row 1-n, and m[2,1:n] maps to row[n+1:2n] ... > > this obviously is not a solution: as the inherent column major storage > paradigm of a matrix > defeats the approach. > > dim(m)<-c(48,1) > > m > [,1] > [1,]1 > [2,]9 > [3,] 17 > [4,] 25 > [5,] 33 > [6,] 41 > [7,]2 > [8,] 10 > [9,] 18 > [10,] 26 > [11,] 34 > [12,] 42 > [13,]3 > [14,] 11 > [15,] 19 > [16,] 27 > [17,] 35 > [18,] 43 > [19,]4 > [20,] 12 > [21,] 20 > [22,] 28 > [23,] 36 > [24,] 44 > [25,]5 > [26,] 13 > [27,] 21 > [28,] 29 > [29,] 37 > [30,] 45 > [31,]6 > [32,] 14 > [33,] 22 > [34,] 30 > [35,] 38 > [36,] 46 > [37,]7 > [38,] 15 > [39,] 23 > [40,] 31 > [41,] 39 > [42,] 47 > [43,]8 > [44,] 16 > [45,] 24 > [46,] 32 > [47,] 40 > [48,] 48 > > > I already have a version that loops through the data ( this is actually a > portion of a data frame ) to reorder > this into a vector, but I was hoping there was an elegant way > >[[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Matrix to Vector
Given a matrix of m*n, I want to reorder it as a vector, using a row major transpose. so: > m<-matrix(seq(1,48),nrow=6,byrow=T) > m [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,]12345678 [2,]9 10 11 12 13 14 15 16 [3,] 17 18 19 20 21 22 23 24 [4,] 25 26 27 28 29 30 31 32 [5,] 33 34 35 36 37 38 39 40 [6,] 41 42 43 44 45 46 47 48 I want to reorder this as a vector copying by row, so that the final vector has elements ordered thusly: row 1, column 1:N (m[1,1:n]) maps to row 1-n, and m[2,1:n] maps to row[n+1:2n] ... this obviously is not a solution: as the inherent column major storage paradigm of a matrix defeats the approach. > dim(m)<-c(48,1) > m [,1] [1,]1 [2,]9 [3,] 17 [4,] 25 [5,] 33 [6,] 41 [7,]2 [8,] 10 [9,] 18 [10,] 26 [11,] 34 [12,] 42 [13,]3 [14,] 11 [15,] 19 [16,] 27 [17,] 35 [18,] 43 [19,]4 [20,] 12 [21,] 20 [22,] 28 [23,] 36 [24,] 44 [25,]5 [26,] 13 [27,] 21 [28,] 29 [29,] 37 [30,] 45 [31,]6 [32,] 14 [33,] 22 [34,] 30 [35,] 38 [36,] 46 [37,]7 [38,] 15 [39,] 23 [40,] 31 [41,] 39 [42,] 47 [43,]8 [44,] 16 [45,] 24 [46,] 32 [47,] 40 [48,] 48 I already have a version that loops through the data ( this is actually a portion of a data frame ) to reorder this into a vector, but I was hoping there was an elegant way [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] matrix to vector
Not sure it is really "matrix to vector" but here are a few of attempts: > abM<-matrix(1:9, nrow=3) > rownames(abM) <- letters[1:3] > colnames(abM) <- letters[4:6] > data.frame( cols=colnames(abM)[col(abM)[1:9]], rows= rownames(abM) [row(abM)[1:9]], vals=abM[1:9]) cols rows vals 1da1 2db2 3dc3 4ea4 5eb5 6ec6 7fa7 8fb8 9fc9 > matrix( c(colnames(abM)[col(abM)[1:9]], rownames(abM)[row(abM) [1:9]], abM[1:9]) ,ncol=3) # all text values since matrices in R need to be of homogenous type [,1] [,2] [,3] [1,] "d" "a" "1" [2,] "d" "b" "2" [3,] "d" "c" "3" [4,] "e" "a" "4" [5,] "e" "b" "5" [6,] "e" "c" "6" [7,] "f" "a" "7" [8,] "f" "b" "8" [9,] "f" "c" "9" But the most compact would be: >library(reshape) > melt(abM) X1 X2 value 1 a d 1 2 b d 2 3 c d 3 4 a e 4 5 b e 5 6 c e 6 7 a f 7 8 b f 8 9 c f 9 On May 29, 2009, at 2:43 PM, Ian Coe wrote: Hi, Is there a way to convert a matrix into a vector representing all permutations of values and column/row headings with native R functions? I did this with 2 nested for loops and it took about 25 minutes to run on a ~700x700 matrix. I'm assuming there must be a smarter way to do this with R's vector commands, but being new to R, I'm having trouble making it work. Thanks, Ian [a] [b] [c] [d]147 [e]258 [f]369 a d 1 a e 2 a f 3 b d 4 b e 5 b f 6 c d 7 c e 8 c f 9 -- Ian Coe Connective Capital Management, LLC 385 Homer Ave. Palo Alto, CA 94301 (650) 321-4826 ext. 03 -- David Winsemius, MD Heritage Laboratories West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] matrix to vector
Ian Coe wrote:
Hi,
Is there a way to convert a matrix into a vector representing all
permutations of values and column/row headings with native R functions?
I did this with 2 nested for loops and it took about 25 minutes to run
on a ~700x700 matrix. I'm assuming there must be a smarter way to do
this with R's vector commands, but being new to R, I'm having trouble
making it work.
> cbind(expand.grid(rownames(x),colnames(x)),as.vector(x))
Var1 Var2 as.vector(x)
1da1
2ea2
3fa3
4db4
5eb5
6fb6
7dc7
8ec8
9fc9
> x <- matrix(rnorm(700*700),700)
> rownames(x) <- paste("R",1:700)
> colnames(x) <- paste("C",1:700)
> system.time(foo <-
cbind(expand.grid(rownames(x),colnames(x)),as.vector(x)))
user system elapsed
1.082 0.107 1.193
Thanks,
Ian
[a] [b] [c]
[d]147
[e]258
[f]369
a d 1
a e 2
a f 3
b d 4
b e 5
b f 6
c d 7
c e 8
c f 9
Ian Coe
Connective Capital Management, LLC
385 Homer Ave.
Palo Alto, CA 94301
(650) 321-4826 ext. 03
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[R] matrix to vector
Hi,
Is there a way to convert a matrix into a vector representing all
permutations of values and column/row headings with native R functions?
I did this with 2 nested for loops and it took about 25 minutes to run
on a ~700x700 matrix. I'm assuming there must be a smarter way to do
this with R's vector commands, but being new to R, I'm having trouble
making it work.
Thanks,
Ian
[a] [b] [c]
[d]147
[e]258
[f]369
a d 1
a e 2
a f 3
b d 4
b e 5
b f 6
c d 7
c e 8
c f 9
Ian Coe
Connective Capital Management, LLC
385 Homer Ave.
Palo Alto, CA 94301
(650) 321-4826 ext. 03
CONFIDENTIALITY NOTICE: This e-mail communication (inclu...{{dropped:23}}
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] matrix to vector
Hi,
Is there a way to convert a matrix into a vector representing all
permutations of values and column/row headings with native R functions?
I did this with 2 nested for loops and it took about 25 minutes to run
on a ~700x700 matrix. I'm assuming there must be a smarter way to do
this with R's vector commands, but being new to R, I'm having trouble
making it work.
Thanks,
Ian
[a] [b] [c]
[d]147
[e]258
[f]369
a d 1
a e 2
a f 3
b d 4
b e 5
b f 6
c d 7
c e 8
c f 9
Ian Coe
Connective Capital Management, LLC
385 Homer Ave.
Palo Alto, CA 94301
(650) 321-4826 ext. 03
CONFIDENTIALITY NOTICE: This e-mail communication (inclu...{{dropped:23}}
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
