Re: [R] Newbie Question on making subsets for every element of a table column
On Mon, Apr 23, 2012 at 02:33:22PM -0700, cyclondude wrote:
Yes. That is what I was looking for. Is there a simple way to (in this
scenario)
out[[1]]
v1 v2
1 a 1
4 a 2
7 a 3
a - out[[1]]
for each one?
Hi.
If you want to generate variable names by a script, then try
dat - expand.grid(v1=letters[1:3], v2=1:3)
for (var in unique(as.character(dat$v1))) {
assign(var, subset(dat, v1 == var))
}
ls() # [1] a b c dat var
a
v1 v2
1 a 1
4 a 2
7 a 3
b
v1 v2
2 b 1
5 b 2
8 b 3
Hope this helps.
Petr Savicky.
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[R] Newbie Question on making subsets for every element of a table column
Hello, very new to R, playing with tables, and I am trying to do x - subset(data, columnlabel == x) for every element in my column that I could find by using table (data [,columnlabel]) I'd appreciate any useful help and I'm sorry if I didn't get the terminology perfect. Thanks. -- View this message in context: http://r.789695.n4.nabble.com/Newbie-Question-on-making-subsets-for-every-element-of-a-table-column-tp4581228p4581228.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Newbie Question on making subsets for every element of a table column
On Mon, Apr 23, 2012 at 10:58:26AM -0700, cyclondude wrote: Hello, very new to R, playing with tables, and I am trying to do x - subset(data, columnlabel == x) for every element in my column that I could find by using table (data [,columnlabel]) Hi. The following may be close to what you require. #prepare some data dat - expand.grid(v1=letters[1:3], v2=1:3) dat v1 v2 1 a 1 2 b 1 3 c 1 4 a 2 5 b 2 6 c 2 7 a 3 8 b 3 9 c 3 out - split(dat, dat$v1) #the first two groups are out[[1]] v1 v2 1 a 1 4 a 2 7 a 3 out[[2]] v1 v2 2 b 1 5 b 2 8 b 3 Hope this helps. Petr Savicky. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Newbie Question on making subsets for every element of a table column
Yes. That is what I was looking for. Is there a simple way to (in this scenario) out[[1]] v1 v2 1 a 1 4 a 2 7 a 3 a - out[[1]] for each one? Thanks! -- View this message in context: http://r.789695.n4.nabble.com/Newbie-Question-on-making-subsets-for-every-element-of-a-table-column-tp4581228p4581775.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Newbie Question on making subsets for every element of a table column
There are, but it's generally considered better style to keep them all in a single list and use lapply() if you want to do things to each element. Michael On Mon, Apr 23, 2012 at 5:33 PM, cyclondude hans.thomps...@gmail.com wrote: Yes. That is what I was looking for. Is there a simple way to (in this scenario) out[[1]] v1 v2 1 a 1 4 a 2 7 a 3 a - out[[1]] for each one? Thanks! -- View this message in context: http://r.789695.n4.nabble.com/Newbie-Question-on-making-subsets-for-every-element-of-a-table-column-tp4581228p4581775.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
