[R] Scaling error
Hi useRs,
I ran into an inconsistent output problem again. Here is the simplify
illustration
I've got a matrix as follows
x
V1V2 V3
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
Associated with the matrix is a scaling factor, sca, derived from, say
the mean of the respective columns, V1-V3;
sca
V1V2 V3
2.5 1.7 3.6
The idea is that the scaling factor gets applied to each element in the
column matrix. So
out - x / sca
would give me
V1V2 V3
1 *2.5 2 *1.7 3 *3.6
4 *2.5 5 *1.7 6 *3.6
7 *2.5 8 *1.7 9 *3.6
But what actually happen is this,
V1V2 V3
1 *2.5 2 *2.5 3 *2.5
4 *1.7 5 *1.7 6 *1.7
7 *3.6 8 *3.6 9 *3.6
I can do the following;
x[,1] / sca[1]
x[,2] / sca[2]
which is OK for a set of test data but not for my actual dataset.
At the moment, I'm thinking of something in the lines of a for loop
function i.e.
for (i in ...){
statement...
}
Is there a syntax in the for loop that allows me to select the
column/row in the file?
Thanks.
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom
Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974
Email: muhammad.ra...@ouce.ox.ac.uk
__
R-help@r-project.org mailing list
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Re: [R] Scaling error
If out is what you want to achieve, why don't you multiply sca (called
m below) with the transpose of x and then transpose the resulting
matrix?
x=c(1,2,3,4,5,6,7,8,9)
dim(x)=c(3,3)
x=t(x)
x
m=c(2.5,1.7,3.6)
x*m #returns what you don't want
t(t(x)*m) #returns what you want
HTH
Daniel
-
cuncta stricte discussurus
-
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Muhammad Rahiz
Sent: Sunday, December 27, 2009 2:27 PM
To: r-help@r-project.org
Subject: [R] Scaling error
Hi useRs,
I ran into an inconsistent output problem again. Here is the simplify
illustration
I've got a matrix as follows
x
V1V2 V3
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
Associated with the matrix is a scaling factor, sca, derived from, say
the mean of the respective columns, V1-V3;
sca
V1V2 V3
2.5 1.7 3.6
The idea is that the scaling factor gets applied to each element in the
column matrix. So
out - x / sca
would give me
V1V2 V3
1 *2.5 2 *1.7 3 *3.6
4 *2.5 5 *1.7 6 *3.6
7 *2.5 8 *1.7 9 *3.6
But what actually happen is this,
V1V2 V3
1 *2.5 2 *2.5 3 *2.5
4 *1.7 5 *1.7 6 *1.7
7 *3.6 8 *3.6 9 *3.6
I can do the following;
x[,1] / sca[1]
x[,2] / sca[2]
which is OK for a set of test data but not for my actual dataset.
At the moment, I'm thinking of something in the lines of a for loop
function i.e.
for (i in ...){
statement...
}
Is there a syntax in the for loop that allows me to select the
column/row in the file?
Thanks.
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom
Tel: +44 (0)1865-285194 Mobile: +44 (0)7854-625974
Email: muhammad.ra...@ouce.ox.ac.uk
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Scaling error
Hi,
Try this,
x - matrix(1:9, ncol=3, byrow=T)
sca - c(2.5, 1.7, 3.6)
x %*% diag(1/sca)
HTH,
baptiste
2009/12/27 Muhammad Rahiz muhammad.ra...@ouce.ox.ac.uk:
Hi useRs,
I ran into an inconsistent output problem again. Here is the simplify
illustration
I've got a matrix as follows
x
V1 V2 V3
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
Associated with the matrix is a scaling factor, sca, derived from, say the
mean of the respective columns, V1-V3;
sca
V1 V2 V3
2.5 1.7 3.6
The idea is that the scaling factor gets applied to each element in the
column matrix. So
out - x / sca
would give me
V1 V2 V3
1 *2.5 2 *1.7 3 *3.6
4 *2.5 5 *1.7 6 *3.6
7 *2.5 8 *1.7 9 *3.6
But what actually happen is this,
V1 V2 V3
1 *2.5 2 *2.5 3 *2.5
4 *1.7 5 *1.7 6 *1.7
7 *3.6 8 *3.6 9 *3.6
I can do the following;
x[,1] / sca[1]
x[,2] / sca[2]
which is OK for a set of test data but not for my actual dataset.
At the moment, I'm thinking of something in the lines of a for loop function
i.e.
for (i in ...){
statement...
}
Is there a syntax in the for loop that allows me to select the column/row in
the file?
Thanks.
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194
Mobile: +44 (0)7854-625974
Email: muhammad.ra...@ouce.ox.ac.uk
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Scaling error
sweep(x, 2, m, FUN='/')
On Sun, Dec 27, 2009 at 2:26 PM, Muhammad Rahiz
muhammad.ra...@ouce.ox.ac.uk wrote:
Hi useRs,
I ran into an inconsistent output problem again. Here is the simplify
illustration
I've got a matrix as follows
x
V1V2 V3
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
Associated with the matrix is a scaling factor, sca, derived from, say the
mean of the respective columns, V1-V3;
sca
V1V2 V3
2.5 1.7 3.6
The idea is that the scaling factor gets applied to each element in the
column matrix. So
out - x / sca
would give me
V1V2 V3
1 *2.5 2 *1.7 3 *3.6
4 *2.5 5 *1.7 6 *3.6
7 *2.5 8 *1.7 9 *3.6
But what actually happen is this,
V1V2 V3
1 *2.5 2 *2.5 3 *2.5
4 *1.7 5 *1.7 6 *1.7
7 *3.6 8 *3.6 9 *3.6
I can do the following;
x[,1] / sca[1]
x[,2] / sca[2]
which is OK for a set of test data but not for my actual dataset.
At the moment, I'm thinking of something in the lines of a for loop
function i.e.
for (i in ...){
statement...
}
Is there a syntax in the for loop that allows me to select the column/row
in the file?
Thanks.
--
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom Tel: +44 (0)1865-285194
Mobile: +44 (0)7854-625974
Email: muhammad.ra...@ouce.ox.ac.uk
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem that you are trying to solve?
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