Re: [R] Time series example in Koop
> Date: Tue, 5 Apr 2011 07:35:04 -0500 > From: ravi.k...@gmail.com > To: r-help@r-project.org > Subject: [R] Time series example in Koop > > I am trying to reproduce the output of a time series example in Koop's book > "Analysis of Financial Data". Koop does the example in Excel and I used the > ts function followed by the lm function. > I am unable to get the exact coefficients that Koop gives - my coefficients > are slightly different. > After loading the data file and attaching the frame, my code reads: > > > y = ts(m.cap) > > x = ts(oil.price) > > d = ts.union(y,x,x1=lag(x,-1),x2=lag(x,-2),x3=lag(x,-3),x4=lag(x,-4)) > > mod1 = lm(y~x+x1+x2+x3+x4, data=d) > > summary(mod1) > > Koop gives an intercept of 92001.51, while the code above gives 91173.32. > The other coefficients are also slightly off. The differences here seem to be of order 1 percent. You could suspect a number of things, including the published data file being published to less precision than that used in the book numbers(also look at number of points and see if any were added or dropped etc ). However, you may want to judge these based on what they do to your error which they presumably are both supposed to minimize but the calculation of which could be subject to various roundoff errors etc. Unless minimization is done analytically, it is of course subject to limitations of convergence or iteration count. Plotting both fits over the data and looking at residuals may help too. Depending on what you are really trying to do, you may want to change your error calculation etc. Details of numerical results often depend on details of implementation. This is why stats packages that are not open source have limitations in applicability. With "real models" of course things get even more confusing. ( take a look at credit rating agencies results for example LOL). > > This is the example in Table 8.3 of Koop. I also attach a plain text version > of the tab separated file "badnews.txt". > http://r.789695.n4.nabble.com/file/n3427897/badnews.txt badnews.txt > > Any light on why I do not get Koop's coefficients is most welcome... > > Ravi __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Time series example in Koop
On Tue, Apr 5, 2011 at 8:35 AM, Ravi Kulkarni wrote: > I am trying to reproduce the output of a time series example in Koop's book > "Analysis of Financial Data". Koop does the example in Excel and I used the > ts function followed by the lm function. > I am unable to get the exact coefficients that Koop gives - my coefficients > are slightly different. > After loading the data file and attaching the frame, my code reads: > >> y = ts(m.cap) >> x = ts(oil.price) >> d = ts.union(y,x,x1=lag(x,-1),x2=lag(x,-2),x3=lag(x,-3),x4=lag(x,-4)) >> mod1 = lm(y~x+x1+x2+x3+x4, data=d) >> summary(mod1) > > Koop gives an intercept of 92001.51, while the code above gives 91173.32. > The other coefficients are also slightly off. > > This is the example in Table 8.3 of Koop. I also attach a plain text version > of the tab separated file "badnews.txt". > http://r.789695.n4.nabble.com/file/n3427897/badnews.txt badnews.txt > > Any light on why I do not get Koop's coefficients is most welcome... > It looks like he erroneously left out the first point. > URL <- "http://r.789695.n4.nabble.com/file/n3427897/badnews.txt"; > BAD <- read.table(URL, header = TRUE) > library(dyn) > dyn$lm(m.cap ~ lag(oil.price, -(0:4)), as.zoo(BAD)) Call: lm(formula = dyn(m.cap ~ lag(oil.price, -(0:4))), data = as.zoo(BAD)) Coefficients: (Intercept) lag(oil.price, -(0:4))1 lag(oil.price, -(0:4))2 91173.32 -131.99 -449.86 lag(oil.price, -(0:4))3 lag(oil.price, -(0:4))4 lag(oil.price, -(0:4))5 -422.52 -187.10 -27.77 > > # without first point > dyn$lm(m.cap ~ lag(oil.price, -(0:4)), tail(as.zoo(BAD), -1)) Call: lm(formula = dyn(m.cap ~ lag(oil.price, -(0:4))), data = tail(as.zoo(BAD), -1)) Coefficients: (Intercept) lag(oil.price, -(0:4))1 lag(oil.price, -(0:4))2 92001.5 -145.0 -462.1 lag(oil.price, -(0:4))3 lag(oil.price, -(0:4))4 lag(oil.price, -(0:4))5 -424.5 -199.5-36.9 > -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Time series example in Koop
I am trying to reproduce the output of a time series example in Koop's book "Analysis of Financial Data". Koop does the example in Excel and I used the ts function followed by the lm function. I am unable to get the exact coefficients that Koop gives - my coefficients are slightly different. After loading the data file and attaching the frame, my code reads: > y = ts(m.cap) > x = ts(oil.price) > d = ts.union(y,x,x1=lag(x,-1),x2=lag(x,-2),x3=lag(x,-3),x4=lag(x,-4)) > mod1 = lm(y~x+x1+x2+x3+x4, data=d) > summary(mod1) Koop gives an intercept of 92001.51, while the code above gives 91173.32. The other coefficients are also slightly off. This is the example in Table 8.3 of Koop. I also attach a plain text version of the tab separated file "badnews.txt". http://r.789695.n4.nabble.com/file/n3427897/badnews.txt badnews.txt Any light on why I do not get Koop's coefficients is most welcome... Ravi -- View this message in context: http://r.789695.n4.nabble.com/Time-series-example-in-Koop-tp3427897p3427897.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
