Re: [R] backreferences in gregexpr
On Sat, Nov 3, 2012 at 4:08 PM, Alexander Shenkin wrote:
> On 11/2/2012 5:14 PM, Gabor Grothendieck wrote:
> > On Fri, Nov 2, 2012 at 6:02 PM, Alexander Shenkin
> wrote:
> >> Hi Folks,
> >>
> >> I'm trying to extract just the backreferences from a regex.
> >>
> >>> temp = "abcd1234abcd1234"
> >>> regmatches(temp, gregexpr("(?:abcd)(1234)", temp))
> >> [[1]]
> >> [1] "abcd1234" "abcd1234"
> >>
> >> What I would like is:
> >> [1] "1234" "1234"
> >>
> >> Note: I know I can just match 1234 here, but the actual example is
> >> complicated enough that I have to match a larger string, and just want
> >> to pass out the backreferenced portion.
> >>
> >> Any help greatly appreciated!
> >>
> >
> > Try this:
> >
> >> library(gsubfn)
> >> strapplyc(temp, "abcd(1234)")
> > [[1]]
> > [1] "1234" "1234"
> >
>
> Thanks Gabor. Didn't find strapplyc in package gsubfun, but did find
> strapply, and that worked well.
>
You must have an old version of the package. Time to upgrade.
--
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Re: [R] backreferences in gregexpr
On 11/2/2012 5:14 PM, Gabor Grothendieck wrote:
> On Fri, Nov 2, 2012 at 6:02 PM, Alexander Shenkin wrote:
>> Hi Folks,
>>
>> I'm trying to extract just the backreferences from a regex.
>>
>>> temp = "abcd1234abcd1234"
>>> regmatches(temp, gregexpr("(?:abcd)(1234)", temp))
>> [[1]]
>> [1] "abcd1234" "abcd1234"
>>
>> What I would like is:
>> [1] "1234" "1234"
>>
>> Note: I know I can just match 1234 here, but the actual example is
>> complicated enough that I have to match a larger string, and just want
>> to pass out the backreferenced portion.
>>
>> Any help greatly appreciated!
>>
>
> Try this:
>
>> library(gsubfn)
>> strapplyc(temp, "abcd(1234)")
> [[1]]
> [1] "1234" "1234"
>
Thanks Gabor. Didn't find strapplyc in package gsubfun, but did find
strapply, and that worked well.
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Re: [R] backreferences in gregexpr
HI,
I am not sure whether this helps:
temp1<-regmatches(temp, gregexpr("(?:abcd)(1234)", temp)) #your code
substr(unlist(temp1),5,8)
#[1] "1234" "1234"
A.K.
- Original Message -
From: Alexander Shenkin
To: r-help@r-project.org
Cc:
Sent: Friday, November 2, 2012 6:02 PM
Subject: [R] backreferences in gregexpr
Hi Folks,
I'm trying to extract just the backreferences from a regex.
> temp = "abcd1234abcd1234"
> regmatches(temp, gregexpr("(?:abcd)(1234)", temp))
[[1]]
[1] "abcd1234" "abcd1234"
What I would like is:
[1] "1234" "1234"
Note: I know I can just match 1234 here, but the actual example is
complicated enough that I have to match a larger string, and just want
to pass out the backreferenced portion.
Any help greatly appreciated!
Thanks,
Allie
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] backreferences in gregexpr
On Fri, Nov 2, 2012 at 6:02 PM, Alexander Shenkin wrote:
> Hi Folks,
>
> I'm trying to extract just the backreferences from a regex.
>
>> temp = "abcd1234abcd1234"
>> regmatches(temp, gregexpr("(?:abcd)(1234)", temp))
> [[1]]
> [1] "abcd1234" "abcd1234"
>
> What I would like is:
> [1] "1234" "1234"
>
> Note: I know I can just match 1234 here, but the actual example is
> complicated enough that I have to match a larger string, and just want
> to pass out the backreferenced portion.
>
> Any help greatly appreciated!
>
Try this:
> library(gsubfn)
> strapplyc(temp, "abcd(1234)")
[[1]]
[1] "1234" "1234"
--
Statistics & Software Consulting
GKX Group, GKX Associates Inc.
tel: 1-877-GKX-GROUP
email: ggrothendieck at gmail.com
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] backreferences in gregexpr
Hi Folks,
I'm trying to extract just the backreferences from a regex.
> temp = "abcd1234abcd1234"
> regmatches(temp, gregexpr("(?:abcd)(1234)", temp))
[[1]]
[1] "abcd1234" "abcd1234"
What I would like is:
[1] "1234" "1234"
Note: I know I can just match 1234 here, but the actual example is
complicated enough that I have to match a larger string, and just want
to pass out the backreferenced portion.
Any help greatly appreciated!
Thanks,
Allie
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
