Re: [R] data manipulation between vector and matrix
HI, The option z5 takes care of it. z5<-t(x-t(mat)) #still faster than ?sweep() dim(z5) [1] 20 2 identical(sweep(-mat,2,x,"+"),z5) #[1] TRUE A.K. From: C W To: arun Sent: Wednesday, December 5, 2012 5:09 PM Subject: Re: [R] data manipulation between vector and matrix Hi Arun, Sorry, I might be a little unclear with my words. The dimensions are different. This is what I got: > x-t(mat) [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14] [1,] 0 -1 -2 -3 -4 -5 -6 -7 -8 -9 -10 -11 -12 -13 [2,] -19 -20 -21 -22 -23 -24 -25 -26 -27 -28 -29 -30 -31 -32 [,15] [,16] [,17] [,18] [,19] [,20] [1,] -14 -15 -16 -17 -18 -19 [2,] -33 -34 -35 -36 -37 -38 > sweep(-mat, 2, x, "+") [,1] [,2] [1,] 0 -19 [2,] -1 -20 [3,] -2 -21 [4,] -3 -22 [5,] -4 -23 [6,] -5 -24 [7,] -6 -25 [8,] -7 -26 [9,] -8 -27 [10,] -9 -28 [11,] -10 -29 [12,] -11 -30 [13,] -12 -31 [14,] -13 -32 [15,] -14 -33 [16,] -15 -34 [17,] -16 -35 [18,] -17 -36 [19,] -18 -37 [20,] -19 -38 > dim(x-t(mat)) [1] 2 20 > dim(sweep(-mat, 2, x, "+")) [1] 20 2 On Wed, Dec 5, 2012 at 4:55 PM, arun wrote: HI Mike, >I didn't understand "except the x-t(mat) output is very different than the >others". Are you saying that it needs to be transposed? BTW, that was z5. > >A.K. > > > > > > > > >From: C W >To: arun >Cc: R help ; Sarah Goslee >Sent: Wednesday, December 5, 2012 4:47 PM > >Subject: Re: [R] data manipulation between vector and matrix > > >Thanks for the benchmark. I actually wanted to go with the winner, except the >x-t(mat) output is very different than the others. >Mike > > >On Wed, Dec 5, 2012 at 4:40 PM, arun wrote: > >Hi, >> >>By comparing the different methods: >>set.seed(5) >> mat1<-matrix(sample(1:1e6,1e6,replace=TRUE),ncol=1) >> set.seed(25) >> x<-sample(1:1e6,1,replace=TRUE) >> system.time(z1<-sweep(-mat1,2,x,"+")) >># user system elapsed >> # 0.076 0.000 0.069 >> system.time(z2<-apply(-mat1,1,`+`,x)) >> # user system elapsed >> # 0.036 0.000 0.031 >> system.time(z3<-aaply(-mat1,1,`+`,x)) >># user system elapsed >># 1.880 0.000 1.704 >> system.time(z4<- x-t(mat1)) #winner >># user system elapsed >> # 0.004 0.000 0.007 >> system.time(z5<- t(x-t(mat1))) >># user system elapsed >># 0.008 0.000 0.009 >> >> >>A.K. >> >> >> >> >> >> >> >>From: C W >>To: arun >>Cc: R help ; Sarah Goslee >>Sent: Wednesday, December 5, 2012 4:11 PM >> >>Subject: Re: [R] data manipulation between vector and matrix >> >> >>thanks, I knew about apply, but did not you you can put plus signs with >>quotes. That's a cool tricky, >>Mike >> >> >>On Wed, Dec 5, 2012 at 4:05 PM, arun wrote: >> >>HI, >>>In addition to ?sweep(), you can use >>> >>>apply(-mat,1,`+`,x) >>> >>>#or >>>library(plyr) >>>aaply(-mat,1,"+",x) >>> >>> >>>A.K. >>> >>> >>> >>> >>> >>> >>> >>>- Original Message - >>>From: C W >>>To: Sarah Goslee >>>Cc: r-help >>>Sent: Wednesday, December 5, 2012 1:51 PM >>>Subject: Re: [R] data manipulation between vector and matrix >>> >>>Thanks, Sarah. First time heard about sweep(), it worked just the way I >>>wanted. >>>Mike >>> >>>On Wed, Dec 5, 2012 at 1:42 PM, Sarah Goslee wrote: >>> >>>> Hi, >>>> >>>> On Wed, Dec 5, 2012 at 1:30 PM, C W wrote: >>>> > Dear list, >>>> > I was curious how to subtract a vector from matrix? >>>> > >>>> > Say, I have >>>> > >>>> > mat <- matrix(1:40, nrow=20, ncol=2) >>>> > >>>> > x <-c(1,2) >>>> >>>> Thanks for the actual reproducible example. >>>> >>>> > I want, >>>> > >>>> > x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements >>>> > of x against column elements in mat. >>>> > >>>> > But x-mat won't do it. >>>> >>>> This will (note the modification to get x - mat): >>>> > sweep(-mat, 2, x, "+") >>>> [,1] [,2] >>>> [1,] 0 -19 >>>> [2,] -1 -20 >>>> [3,] -2 -21 >>>> [4,] -3 -22 >>>> [5,] -4 -23 >>>> etc. >>>> >>>> -- >>>> Sarah Goslee >>>> http://www.functionaldiversity.org >>>> >>> >>> [[alternative HTML version deleted]] >>> >>>__ >>>R-help@r-project.org mailing list >>>https://stat.ethz.ch/mailman/listinfo/r-help >>>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >>>and provide commented, minimal, self-contained, reproducible code. >>> >>> >> > __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] data manipulation between vector and matrix
Hi, By comparing the different methods: set.seed(5) mat1<-matrix(sample(1:1e6,1e6,replace=TRUE),ncol=1) set.seed(25) x<-sample(1:1e6,1,replace=TRUE) system.time(z1<-sweep(-mat1,2,x,"+")) # user system elapsed # 0.076 0.000 0.069 system.time(z2<-apply(-mat1,1,`+`,x)) # user system elapsed # 0.036 0.000 0.031 system.time(z3<-aaply(-mat1,1,`+`,x)) # user system elapsed # 1.880 0.000 1.704 system.time(z4<- x-t(mat1)) #winner # user system elapsed # 0.004 0.000 0.007 system.time(z5<- t(x-t(mat1))) # user system elapsed # 0.008 0.000 0.009 A.K. From: C W To: arun Cc: R help ; Sarah Goslee Sent: Wednesday, December 5, 2012 4:11 PM Subject: Re: [R] data manipulation between vector and matrix thanks, I knew about apply, but did not you you can put plus signs with quotes. That's a cool tricky, Mike On Wed, Dec 5, 2012 at 4:05 PM, arun wrote: HI, >In addition to ?sweep(), you can use > >apply(-mat,1,`+`,x) > >#or >library(plyr) >aaply(-mat,1,"+",x) > > >A.K. > > > > > > > >- Original Message - >From: C W >To: Sarah Goslee >Cc: r-help >Sent: Wednesday, December 5, 2012 1:51 PM >Subject: Re: [R] data manipulation between vector and matrix > >Thanks, Sarah. First time heard about sweep(), it worked just the way I >wanted. >Mike > >On Wed, Dec 5, 2012 at 1:42 PM, Sarah Goslee wrote: > >> Hi, >> >> On Wed, Dec 5, 2012 at 1:30 PM, C W wrote: >> > Dear list, >> > I was curious how to subtract a vector from matrix? >> > >> > Say, I have >> > >> > mat <- matrix(1:40, nrow=20, ncol=2) >> > >> > x <-c(1,2) >> >> Thanks for the actual reproducible example. >> >> > I want, >> > >> > x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements >> > of x against column elements in mat. >> > >> > But x-mat won't do it. >> >> This will (note the modification to get x - mat): >> > sweep(-mat, 2, x, "+") >> [,1] [,2] >> [1,] 0 -19 >> [2,] -1 -20 >> [3,] -2 -21 >> [4,] -3 -22 >> [5,] -4 -23 >> etc. >> >> -- >> Sarah Goslee >> http://www.functionaldiversity.org >> > > [[alternative HTML version deleted]] > >__ >R-help@r-project.org mailing list >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. > > __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] data manipulation between vector and matrix
Thanks for the benchmark. I actually wanted to go with the winner, except the x-t(mat) output is very different than the others. Mike On Wed, Dec 5, 2012 at 4:40 PM, arun wrote: > Hi, > > By comparing the different methods: > set.seed(5) > mat1<-matrix(sample(1:1e6,1e6,replace=TRUE),ncol=1) > set.seed(25) > x<-sample(1:1e6,1,replace=TRUE) > system.time(z1<-sweep(-mat1,2,x,"+")) > # user system elapsed > # 0.076 0.000 0.069 > system.time(z2<-apply(-mat1,1,`+`,x)) > # user system elapsed > # 0.036 0.000 0.031 > system.time(z3<-aaply(-mat1,1,`+`,x)) > # user system elapsed > # 1.880 0.000 1.704 > system.time(z4<- x-t(mat1)) #winner > # user system elapsed > # 0.004 0.000 0.007 > system.time(z5<- t(x-t(mat1))) > # user system elapsed > # 0.008 0.000 0.009 > > > A.K. > > > > > > ________ > From: C W > To: arun > Cc: R help ; Sarah Goslee > Sent: Wednesday, December 5, 2012 4:11 PM > Subject: Re: [R] data manipulation between vector and matrix > > > thanks, I knew about apply, but did not you you can put plus signs with > quotes. That's a cool tricky, > Mike > > > On Wed, Dec 5, 2012 at 4:05 PM, arun wrote: > > HI, > >In addition to ?sweep(), you can use > > > >apply(-mat,1,`+`,x) > > > >#or > >library(plyr) > >aaply(-mat,1,"+",x) > > > > > >A.K. > > > > > > > > > > > > > > > >- Original Message - > >From: C W > >To: Sarah Goslee > >Cc: r-help > >Sent: Wednesday, December 5, 2012 1:51 PM > >Subject: Re: [R] data manipulation between vector and matrix > > > >Thanks, Sarah. First time heard about sweep(), it worked just the way I > >wanted. > >Mike > > > >On Wed, Dec 5, 2012 at 1:42 PM, Sarah Goslee > wrote: > > > >> Hi, > >> > >> On Wed, Dec 5, 2012 at 1:30 PM, C W wrote: > >> > Dear list, > >> > I was curious how to subtract a vector from matrix? > >> > > >> > Say, I have > >> > > >> > mat <- matrix(1:40, nrow=20, ncol=2) > >> > > >> > x <-c(1,2) > >> > >> Thanks for the actual reproducible example. > >> > >> > I want, > >> > > >> > x-mat[1,] and x-mat[2,], and so on... Basically, subtract column > elements > >> > of x against column elements in mat. > >> > > >> > But x-mat won't do it. > >> > >> This will (note the modification to get x - mat): > >> > sweep(-mat, 2, x, "+") > >> [,1] [,2] > >> [1,]0 -19 > >> [2,] -1 -20 > >> [3,] -2 -21 > >> [4,] -3 -22 > >> [5,] -4 -23 > >> etc. > >> > >> -- > >> Sarah Goslee > >> http://www.functionaldiversity.org > >> > > > >[[alternative HTML version deleted]] > > > >__ > >R-help@r-project.org mailing list > >https://stat.ethz.ch/mailman/listinfo/r-help > >PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > >and provide commented, minimal, self-contained, reproducible code. > > > > > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] data manipulation between vector and matrix
HI, In addition to ?sweep(), you can use apply(-mat,1,`+`,x) #or library(plyr) aaply(-mat,1,"+",x) A.K. - Original Message - From: C W To: Sarah Goslee Cc: r-help Sent: Wednesday, December 5, 2012 1:51 PM Subject: Re: [R] data manipulation between vector and matrix Thanks, Sarah. First time heard about sweep(), it worked just the way I wanted. Mike On Wed, Dec 5, 2012 at 1:42 PM, Sarah Goslee wrote: > Hi, > > On Wed, Dec 5, 2012 at 1:30 PM, C W wrote: > > Dear list, > > I was curious how to subtract a vector from matrix? > > > > Say, I have > > > > mat <- matrix(1:40, nrow=20, ncol=2) > > > > x <-c(1,2) > > Thanks for the actual reproducible example. > > > I want, > > > > x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements > > of x against column elements in mat. > > > > But x-mat won't do it. > > This will (note the modification to get x - mat): > > sweep(-mat, 2, x, "+") > [,1] [,2] > [1,] 0 -19 > [2,] -1 -20 > [3,] -2 -21 > [4,] -3 -22 > [5,] -4 -23 > etc. > > -- > Sarah Goslee > http://www.functionaldiversity.org > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] data manipulation between vector and matrix
thanks, I knew about apply, but did not you you can put plus signs with quotes. That's a cool tricky, Mike On Wed, Dec 5, 2012 at 4:05 PM, arun wrote: > HI, > In addition to ?sweep(), you can use > > apply(-mat,1,`+`,x) > > #or > library(plyr) > aaply(-mat,1,"+",x) > > > A.K. > > > > > > > - Original Message - > From: C W > To: Sarah Goslee > Cc: r-help > Sent: Wednesday, December 5, 2012 1:51 PM > Subject: Re: [R] data manipulation between vector and matrix > > Thanks, Sarah. First time heard about sweep(), it worked just the way I > wanted. > Mike > > On Wed, Dec 5, 2012 at 1:42 PM, Sarah Goslee > wrote: > > > Hi, > > > > On Wed, Dec 5, 2012 at 1:30 PM, C W wrote: > > > Dear list, > > > I was curious how to subtract a vector from matrix? > > > > > > Say, I have > > > > > > mat <- matrix(1:40, nrow=20, ncol=2) > > > > > > x <-c(1,2) > > > > Thanks for the actual reproducible example. > > > > > I want, > > > > > > x-mat[1,] and x-mat[2,], and so on... Basically, subtract column > elements > > > of x against column elements in mat. > > > > > > But x-mat won't do it. > > > > This will (note the modification to get x - mat): > > > sweep(-mat, 2, x, "+") > > [,1] [,2] > > [1,]0 -19 > > [2,] -1 -20 > > [3,] -2 -21 > > [4,] -3 -22 > > [5,] -4 -23 > > etc. > > > > -- > > Sarah Goslee > > http://www.functionaldiversity.org > > > > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] data manipulation between vector and matrix
Thanks, Sarah. First time heard about sweep(), it worked just the way I wanted. Mike On Wed, Dec 5, 2012 at 1:42 PM, Sarah Goslee wrote: > Hi, > > On Wed, Dec 5, 2012 at 1:30 PM, C W wrote: > > Dear list, > > I was curious how to subtract a vector from matrix? > > > > Say, I have > > > > mat <- matrix(1:40, nrow=20, ncol=2) > > > > x <-c(1,2) > > Thanks for the actual reproducible example. > > > I want, > > > > x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements > > of x against column elements in mat. > > > > But x-mat won't do it. > > This will (note the modification to get x - mat): > > sweep(-mat, 2, x, "+") > [,1] [,2] > [1,]0 -19 > [2,] -1 -20 > [3,] -2 -21 > [4,] -3 -22 > [5,] -4 -23 > etc. > > -- > Sarah Goslee > http://www.functionaldiversity.org > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] data manipulation between vector and matrix
Hi, On Wed, Dec 5, 2012 at 1:30 PM, C W wrote: > Dear list, > I was curious how to subtract a vector from matrix? > > Say, I have > > mat <- matrix(1:40, nrow=20, ncol=2) > > x <-c(1,2) Thanks for the actual reproducible example. > I want, > > x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements > of x against column elements in mat. > > But x-mat won't do it. This will (note the modification to get x - mat): > sweep(-mat, 2, x, "+") [,1] [,2] [1,]0 -19 [2,] -1 -20 [3,] -2 -21 [4,] -3 -22 [5,] -4 -23 etc. -- Sarah Goslee http://www.functionaldiversity.org __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] data manipulation between vector and matrix
The only solution I found was x-t(mu) Is there a better way? Mike On Wed, Dec 5, 2012 at 1:30 PM, C W wrote: > Dear list, > I was curious how to subtract a vector from matrix? > > Say, I have > > mat <- matrix(1:40, nrow=20, ncol=2) > > x <-c(1,2) > > I want, > > x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements > of x against column elements in mat. > > But x-mat won't do it. > > Thanks, > > Mike > > [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] data manipulation between vector and matrix
Dear list, I was curious how to subtract a vector from matrix? Say, I have mat <- matrix(1:40, nrow=20, ncol=2) x <-c(1,2) I want, x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements of x against column elements in mat. But x-mat won't do it. Thanks, Mike [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
