Re: [R] evaluate variable within expression - how?
Hi Mark,
Try also:
plot(1:10)
text(2, 5, "Some text", font = 2)
HTH,
Jorge
On Sun, Feb 14, 2010 at 11:36 AM, Mark Heckmann <> wrote:
> # I want to plot bold text. The text should depend on a variable
> containing a character string.
>
> plot.new()
> text(.5, .5, expression(bold("Some text")))
>
> # now I would like to do the same replacing "some text" by a variable.
>
> plot.new()
> myText <- "some text"
> text(.5, .5, expression(bold(myText)))
>
> # This obviouyls does not work.
> # How can I combine substitute, parse, paste etc. do get what I want?
> # And could someone add a brief explanation what happens, as I find
> parse, expression, deparse, substitute etc. not easy to understand.
>
> Thanks,
> Mark
>
>
> Mark Heckmann
> Dipl. Wirt.-Ing. cand. Psych.
> Vorstraße 93 B01
> 28359 Bremen
> Blog: www.markheckmann.de
> R-Blog: http://ryouready.wordpress.com
>
>
>
>
>
>[[alternative HTML version deleted]]
>
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
[[alternative HTML version deleted]]
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Re: [R] evaluate variable within expression - how?
Try
text(.5, .5, bquote(bold(.(myText
-Peter Ehlers
Mark Heckmann wrote:
# I want to plot bold text. The text should depend on a variable
containing a character string.
plot.new()
text(.5, .5, expression(bold("Some text")))
# now I would like to do the same replacing "some text" by a variable.
plot.new()
myText <- "some text"
text(.5, .5, expression(bold(myText)))
# This obviouyls does not work.
# How can I combine substitute, parse, paste etc. do get what I want?
# And could someone add a brief explanation what happens, as I find
parse, expression, deparse, substitute etc. not easy to understand.
Thanks,
Mark
–––
Mark Heckmann
Dipl. Wirt.-Ing. cand. Psych.
Vorstraße 93 B01
28359 Bremen
Blog: www.markheckmann.de
R-Blog: http://ryouready.wordpress.com
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Peter Ehlers
University of Calgary
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] evaluate variable within expression - how?
Hi,
Try with bquote,
plot.new()
myText <- "some text"
text(.5, .5, bquote(bold(.(myText
basically, bquote( .(myText) ) performs the substitution before
applying bold() (see ?bquote).
HTH,
baptiste
On 14 February 2010 17:36, Mark Heckmann wrote:
> # I want to plot bold text. The text should depend on a variable
> containing a character string.
>
> plot.new()
> text(.5, .5, expression(bold("Some text")))
>
> # now I would like to do the same replacing "some text" by a variable.
>
> plot.new()
> myText <- "some text"
> text(.5, .5, expression(bold(myText)))
>
> # This obviouyls does not work.
> # How can I combine substitute, parse, paste etc. do get what I want?
> # And could someone add a brief explanation what happens, as I find
> parse, expression, deparse, substitute etc. not easy to understand.
>
> Thanks,
> Mark
>
> –––
> Mark Heckmann
> Dipl. Wirt.-Ing. cand. Psych.
> Vorstraße 93 B01
> 28359 Bremen
> Blog: www.markheckmann.de
> R-Blog: http://ryouready.wordpress.com
>
>
>
>
>
> [[alternative HTML version deleted]]
>
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] evaluate variable within expression - how?
# I want to plot bold text. The text should depend on a variable
containing a character string.
plot.new()
text(.5, .5, expression(bold("Some text")))
# now I would like to do the same replacing "some text" by a variable.
plot.new()
myText <- "some text"
text(.5, .5, expression(bold(myText)))
# This obviouyls does not work.
# How can I combine substitute, parse, paste etc. do get what I want?
# And could someone add a brief explanation what happens, as I find
parse, expression, deparse, substitute etc. not easy to understand.
Thanks,
Mark
Mark Heckmann
Dipl. Wirt.-Ing. cand. Psych.
Vorstraße 93 B01
28359 Bremen
Blog: www.markheckmann.de
R-Blog: http://ryouready.wordpress.com
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
