[R] finding chuncks of data that have no NA s

2008-07-18 Thread stephen sefick
I have a data frame that is 122 columns and 7ish rows it is a zoo
object, but could be easily converted or read in as something else.  It is
multiparameter multistation water quality data - there are a lot of NA s.  I
would like to find chuncks of data that are free of NA s to do some
analysis.  All of the data is numeric.  Is there a way besides graphing to
find these NA less chuncks.  I did not include data because of the size of
the data frame, and because I don't know exactly how to tackle this
problem.  I will send a subset of the data to the list if requested and when
I get to work.  As for reproducible code I am not entirly sure how to go
about this, so that too is missing.
Sorry for breaking the rules this early in the morning,

Stephen

-- 
Let's not spend our time and resources thinking about things that are so
little or so large that all they really do for us is puff us up and make us
feel like gods. We are mammals, and have not exhausted the annoying little
problems of being mammals.

-K. Mullis

[[alternative HTML version deleted]]

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] finding chuncks of data that have no NA s

2008-07-18 Thread Gabor Grothendieck
na.contiguous.zoo() will return the longest stretch of non-NA data.
Its a zoo method of the na.contiguous generic in the core of R.

rle(!is.na(rowSums(coredata(z will find all stretches.

On Fri, Jul 18, 2008 at 6:47 AM, stephen sefick [EMAIL PROTECTED] wrote:
 I have a data frame that is 122 columns and 7ish rows it is a zoo
 object, but could be easily converted or read in as something else.  It is
 multiparameter multistation water quality data - there are a lot of NA s.  I
 would like to find chuncks of data that are free of NA s to do some
 analysis.  All of the data is numeric.  Is there a way besides graphing to
 find these NA less chuncks.  I did not include data because of the size of
 the data frame, and because I don't know exactly how to tackle this
 problem.  I will send a subset of the data to the list if requested and when
 I get to work.  As for reproducible code I am not entirly sure how to go
 about this, so that too is missing.
 Sorry for breaking the rules this early in the morning,

 Stephen

 --
 Let's not spend our time and resources thinking about things that are so
 little or so large that all they really do for us is puff us up and make us
 feel like gods. We are mammals, and have not exhausted the annoying little
 problems of being mammals.

 -K. Mullis

[[alternative HTML version deleted]]

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] finding chuncks of data that have no NA s

2008-07-18 Thread stephen sefick
#how do I use the below, sorry for being unsavey.  I would look for when
value = FALSE meaning the there are no NAs and Then look for the longest
value of continuous measurements (or lengths that I am comfortable with)
correct?  How do I subset my original data frame with this information?  How
do I find the values to index the data frame?
f - structure(list(lengths = c(23876L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
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3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
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3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
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3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 8679L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L,
1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L,
1L, 3L, 1L, 3L, 1L, 3L, 1L, 12111L, 297L, 4L, 28L, 3L, 13L, 2L,
25L, 1L, 5L, 2L, 93L, 4L, 44L, 4L, 80L, 4L, 8L, 4L, 272L, 4L,
392L, 4L, 35L, 1L, 124L, 4L, 272L, 4L, 8L, 4L, 182L, 1705L, 129L,
286L, 10L, 4L, 8L, 4L, 8L, 4L, 336L, 4L, 168L, 4L, 16L, 4L, 74L,
1L, 49L, 4L, 24L, 4L, 16L, 424L, 92L, 4L, 68L, 4L, 144L, 4L,
20L, 4L, 140L, 4L, 68L, 4L, 60L, 4L, 76L, 4L, 16L, 4L, 284L,
4L, 12L, 4L, 191L, 882L, 59L, 4L, 122L, 851L, 47L, 4L, 168L,
4L, 40L, 4L, 416L, 4L, 40L, 4L, 28L, 4L, 88L, 4L, 16L, 4L, 20L,
3L, 1L, 3L, 1L, 4L, 216L, 4L, 67L, 1L, 92L, 4L, 24L, 4L, 20L,
1L, 95L, 4L, 24L, 4L, 99L, 9576L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 

Re: [R] finding chuncks of data that have no NA s

2008-07-18 Thread Gabor Grothendieck
It would be appreciated if you cut down your data to
a minimal size before posting.  At any rate, the ends
are the cumsums of the lengths and
the starts are lengths-1 before that, e.g.

# data
library(zoo)
z - zoo(c(1, 2, NA, 3, 4, 5, NA, 6))
z - cbind(z, z)

z.rle - rle(!is.na(rowSums(coredata(z

# row indexes
ends - cumsum(z.rle$lengths)
starts - ends - z.rle$lengths + 1

indexes - with(z.rle, data.frame(starts, ends, lengths, values))
indexes.sort - indexes[order(-indexes$lengths), ]
indexes.sort[indexes.sort$values, ]


On Fri, Jul 18, 2008 at 8:25 AM, stephen sefick [EMAIL PROTECTED] wrote:
 #how do I use the below, sorry for being unsavey.  I would look for when
 value = FALSE meaning the there are no NAs and Then look for the longest
 value of continuous measurements (or lengths that I am comfortable with)
 correct?  How do I subset my original data frame with this information?  How
 do I find the values to index the data frame?
 f - structure(list(lengths = c(23876L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
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 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
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 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
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 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
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 3L, 1L, 3L, 1L, 3L, 1L, 8679L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L,
 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L,
 1L, 3L, 1L, 3L, 1L, 3L, 1L, 12111L, 297L, 4L, 28L, 3L, 13L, 2L,
 25L, 1L, 5L, 2L, 93L, 4L, 44L, 4L, 80L, 4L, 8L, 4L, 272L, 4L,
 392L, 4L, 35L, 1L, 124L, 4L, 272L, 4L, 8L, 4L, 182L, 1705L, 129L,
 286L, 10L, 4L, 8L, 4L, 8L, 4L, 336L, 4L, 168L, 4L, 16L, 4L, 74L,
 1L, 49L, 4L, 24L, 4L, 16L, 424L, 92L, 4L, 68L, 4L, 144L, 4L,
 20L, 4L, 140L, 4L, 68L, 4L, 60L, 4L, 76L, 4L, 16L, 4L, 284L,
 4L, 12L, 4L, 191L, 882L, 59L, 4L, 122L, 851L, 47L, 4L, 168L,
 4L, 40L, 4L, 416L, 4L, 40L, 4L, 28L, 4L, 88L, 4L, 16L, 4L, 20L,
 3L, 1L, 3L, 1L, 4L, 216L, 4L, 67L, 1L, 92L, 4L, 24L, 4L, 20L,
 1L, 95L, 4L, 24L, 4L, 99L, 9576L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
 3L, 1L, 3L, 1L, 3L, 1L, 

Re: [R] finding chuncks of data that have no NA s

2008-07-18 Thread stephen sefick
minimal, minimal, minimal, I will have to remind myself.

contiguous.zoo - function(x)
{
z.rle - rle(!is.na(rowSums(coredata(x
# row indexes
ends - cumsum(z.rle$lengths)
starts - ends - z.rle$lengths + 1
indexes - with(z.rle, data.frame(starts, ends, lengths, values))
indexes.sort - indexes[order(-indexes$lengths), ]
indexes.sort[indexes.sort$values, ]
}

This is what I used to accomplish the task.  This is just Gabor's example
made into a function.
many thanks Gabor et. al

Stephen

On Fri, Jul 18, 2008 at 8:49 AM, Gabor Grothendieck [EMAIL PROTECTED]
wrote:

 It would be appreciated if you cut down your data to
 a minimal size before posting.  At any rate, the ends
 are the cumsums of the lengths and
 the starts are lengths-1 before that, e.g.

 # data
 library(zoo)
 z - zoo(c(1, 2, NA, 3, 4, 5, NA, 6))
 z - cbind(z, z)

 z.rle - rle(!is.na(rowSums(coredata(z

 # row indexes
 ends - cumsum(z.rle$lengths)
 starts - ends - z.rle$lengths + 1

 indexes - with(z.rle, data.frame(starts, ends, lengths, values))
 indexes.sort - indexes[order(-indexes$lengths), ]
 indexes.sort[indexes.sort$values, ]


 On Fri, Jul 18, 2008 at 8:25 AM, stephen sefick [EMAIL PROTECTED] wrote:
  #how do I use the below, sorry for being unsavey.  I would look for when
  value = FALSE meaning the there are no NAs and Then look for the longest
  value of continuous measurements (or lengths that I am comfortable with)
  correct?  How do I subset my original data frame with this information?
  How
  do I find the values to index the data frame?
  f - structure(list(lengths = c(23876L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L,
  3L, 1L, 3L, 1L, 3L, 1L, 8679L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L,
  1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L, 1L, 3L,
  1L, 3L, 1L, 3L, 1L, 3L, 1L, 12111L, 297L, 4L, 28L, 3L, 13L, 2L,
  25L, 1L, 5L, 2L, 93L, 4L, 44L, 4L, 80L, 4L, 8L, 4L, 272L, 4L,
  392L, 4L, 35L, 1L, 124L, 4L, 272L, 4L, 8L, 4L, 182L, 1705L, 129L,
  286L, 10L, 4L,