Re: [R] help! - spectral analysis - spec.pgram

2010-05-14 Thread vikrant

series -c(0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10 
,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10) 


Here ain this example after period 4 the pattern repeats. So we can say that
the above series have a period of  4.

Now my question is by using the  function
spec.pgram(series, log=no) 

we will get a graph of power vs frequency. Correct me if I am wrong.



Now from this graph I want to determine the period of seasonality. How
should I determine it??


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Re: [R] help! - spectral analysis - spec.pgram

2010-05-14 Thread Uwe Ligges



On 14.05.2010 06:03, vikrant wrote:


series-c(0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10
,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10)


Here ain this example after period 4 the pattern repeats. So we can say that
the above series have a period of  4.

Now my question is by using the  function
spec.pgram(series, log=no)

we will get a graph of power vs frequency. Correct me if I am wrong.



Now from this graph I want to determine the period of seasonality. How
should I determine it??





You find that the first highest peak is at freq 0.167 hence 
1/0.167 = 6 is your period (not 4).
But as I said before, you need to read a textbook about Fourier analysis 
/ the spectrum...



Uwe Ligges

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Re: [R] help! - spectral analysis - spec.pgram

2010-05-14 Thread vikrant

Really Thanks Uwe . 

I have started reading books about Fourier analysis.

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Re: [R] help! - spectral analysis - spec.pgram

2010-05-13 Thread Uwe Ligges



On 12.05.2010 07:48, vikrant wrote:


Dear Prof Brian,


This is a mailinglist, and I do not know any Prof. Brian so far (or 
maybe I should expect to be called Prof. Uwe ?).




I am new to spectral analysis. I dont know how to obtain period from
spectral periodogram.


Then you should really start to read textbooks about spectral analysis 
rather than asking a mailing list (or Prof. Brian unless he is your 
supervisor).



If u could explain me about how to obtain the period
from periodogram it will be very helpful. U can explain using the above two
examples in the discussiion.



Which examples??



Thanks in advance..



Uwe Ligges

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Re: [R] help! - spectral analysis - spec.pgram

2010-05-12 Thread vikrant

Dear Prof Brian,
I am new to spectral analysis. I dont know how to obtain period from
spectral periodogram. If u could explain me about how to obtain the period
from periodogram it will be very helpful. U can explain using the above two
examples in the discussiion.

Thanks in advance..
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[R] help! - spectral analysis - spec.pgram

2008-03-27 Thread Nuno Prista
Can someone explain me this spec.pgram effect?

 

Code:

 

period.6-c(0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10
,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10)

period.5-c(0,0,0,0,0,10,0,0,0,0,10,0,0,0,0,0,0,10,0,0,0,0,10,0,0,0,0,0,0,10
,0,0,0,0,10,0,0,0,0,0,0,10,0,0,0,0,10,0,0,0,0,0,0,10,0,0,0,0,10,0)

 

par(mfrow=c(2,1))

 

spec.pgram(period.6, log=no)

spec.pgram(period.5, log=no)

 

 

The first series has period 6 and shows its periodicity in 1/6 and
harmonics. In the second series I was expecting to see a signal occurring at
frequency 1/5 but it does not. Can anybody explain me why? 

 

Thanks in advance,

 

Nuno

 

__ 

Centro de Oceanografia - IO-FCUL, Portugal

Center for Quantitative Fisheries Ecology - ODU, USA

email: [EMAIL PROTECTED] ; [EMAIL PROTECTED] 

 


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Re: [R] help! - spectral analysis - spec.pgram

2008-03-27 Thread Prof Brian Ripley
On Thu, 27 Mar 2008, Nuno Prista wrote:

 Can someone explain me this spec.pgram effect?



 Code:



 period.6-c(0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10
 ,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10,0,0,0,0,0,10)

 period.5-c(0,0,0,0,0,10,0,0,0,0,10,0,0,0,0,0,0,10,0,0,0,0,10,0,0,0,0,0,0,10
 ,0,0,0,0,10,0,0,0,0,0,0,10,0,0,0,0,10,0,0,0,0,0,0,10,0,0,0,0,10,0)



 par(mfrow=c(2,1))



 spec.pgram(period.6, log=no)

 spec.pgram(period.5, log=no)





 The first series has period 6 and shows its periodicity in 1/6 and
 harmonics. In the second series I was expecting to see a signal occurring at
 frequency 1/5 but it does not. Can anybody explain me why?

Because it does not have period 5 but 12 

With such short series tapering has some effect. Try

x - rep(c(0,0,0,0,0,10,0,0,0,0,10,0), 100)
spec.pgram(x, log=no)




 Thanks in advance,



 Nuno



 __

 Centro de Oceanografia - IO-FCUL, Portugal

 Center for Quantitative Fisheries Ecology - ODU, USA

 email: [EMAIL PROTECTED] ; [EMAIL PROTECTED]




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Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
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Oxford OX1 3TG, UKFax:  +44 1865 272595

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