Re: [R] how to make this sequence: 1,2,3,4,5,4,3,2,1
On 03/06/2010 09:35 AM, j verzani wrote: ... Sorry about that one. On the errata page I have: page 16, exercise 1.12 #5 This one is most easily done using c() and the sequence operator :. (Please ignore request to use just seq and rep.) And all over the world, perhaps even on other planets where anonymous R helpers lurk, the readers of the list can cease their trichotillomania and get a good night's sleep. Jim __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to make this sequence: 1,2,3,4,5,4,3,2,1
On Sun, Mar 7, 2010 at 4:28 AM, Jim Lemon j...@bitwrit.com.au wrote: On 03/06/2010 09:35 AM, j verzani wrote: ... Sorry about that one. On the errata page I have: page 16, exercise 1.12 #5 This one is most easily done using c() and the sequence operator :. (Please ignore request to use just seq and rep.) And all over the world, perhaps even on other planets where anonymous R helpers lurk, the readers of the list can cease their trichotillomania and get a good night's sleep. Thank goodness. Anyways freed from that constraint here is another solution: pmin(1:9, 9:1) This does not use c or rep but does use seq and pmin and has a certain pleasing symmetry to it. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to make this sequence: 1,2,3,4,5,4,3,2,1
c(x - 1:5, rev(x[-length(x)])) On 5 March 2010 07:04, kensuguro magronb...@gmail.com wrote: I'm just beginning R, with book Using R for Introductory Statistics, and one of the early questions has me baffled. The question is, create the sequence: 1,2,3,4,5,4,3,2,1 using seq() and rep(). Now, as a programmer, I am punching myself to not be able to figure it out.. I mean, as simple as a for loop, but using seq, I am stumped. I would think c(1:5, 4:1) would be the brute force method with very non intelligent coding.. there has to be a way to make the turning point (in this case 5) parametric right? So you could change it later and the sequence will reflect it. -- View this message in context: http://n4.nabble.com/how-to-make-this-sequence-1-2-3-4-5-4-3-2-1-tp1579245p1579245.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Baptiste Auguié Departamento de Química Física, Universidade de Vigo, Campus Universitario, 36310, Vigo, Spain tel: +34 9868 18617 http://webs.uvigo.es/coloides __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to make this sequence: 1,2,3,4,5,4,3,2,1
On 05-Mar-10 06:04:51, kensuguro wrote:
I'm just beginning R, with book Using R for Introductory Statistics,
and one of the early questions has me baffled. The question is,
create the sequence: 1,2,3,4,5,4,3,2,1 using seq() and rep().
Now, as a programmer, I am punching myself to not be able to figure
it out..
I mean, as simple as a for loop, but using seq, I am stumped.
I would think c(1:5, 4:1) would be the brute force method with very
non intelligent coding.. there has to be a way to make the turning
point (in this case 5) parametric right? So you could change it
later and the sequence will reflect it.
--
View this message in context:
http://n4.nabble.com/how-to-make-this-sequence-1-2-3-4-5-4-3-2-1-tp15792
45p1579245.html
Sent from the R help mailing list archive at Nabble.com.
You can indeed do it using seq(), and with rep() plus a little
help from something else:
seq():
c(seq(1,5,1),seq(4,1,-1))
rep():
cumsum(c(rep(1,5),rep(-1,4)))
Parametrised 1,2,...,n,(n-1),...,2,1:
updown1 - function(n){ c(seq(1,n,1),seq((n-1),1,-1)) }
updown2 - function(n){ cumsum(c(rep(1,n),rep(-1,(n-1 }
updown1(10)
# [1] 1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1
updown2(10)
# [1] 1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1
Ted.
E-Mail: (Ted Harding) ted.hard...@manchester.ac.uk
Fax-to-email: +44 (0)870 094 0861
Date: 05-Mar-10 Time: 08:14:53
-- XFMail --
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Re: [R] how to make this sequence: 1,2,3,4,5,4,3,2,1
try this: 5 - abs(-4:4) I hope it helps. Best, Dimitris On 3/5/2010 7:04 AM, kensuguro wrote: I'm just beginning R, with book Using R for Introductory Statistics, and one of the early questions has me baffled. The question is, create the sequence: 1,2,3,4,5,4,3,2,1 using seq() and rep(). Now, as a programmer, I am punching myself to not be able to figure it out.. I mean, as simple as a for loop, but using seq, I am stumped. I would think c(1:5, 4:1) would be the brute force method with very non intelligent coding.. there has to be a way to make the turning point (in this case 5) parametric right? So you could change it later and the sequence will reflect it. -- Dimitris Rizopoulos Assistant Professor Department of Biostatistics Erasmus University Medical Center Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands Tel: +31/(0)10/7043478 Fax: +31/(0)10/7043014 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to make this sequence: 1,2,3,4,5,4,3,2,1
so basically, it's impossible to do with just seq() and rep().. Doesn't seem like a good question for chapter 1... Also, problem 1.13 is even more crazy.. it asks you to build the fibonacci sequence. Now I'm a programmer, and so went way ahead in the book to see how functions were written, and just wrote my own function, but again, in chapter 1? (only covered c(), seq(), and rep() at this point) What away kick start a book. Is Using R project for Introductory Statistics known to jump around or have out of sequence practice problems? Otherwise it seems to be written very well. -- View this message in context: http://n4.nabble.com/how-to-make-this-sequence-1-2-3-4-5-4-3-2-1-tp1579245p1579654.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to make this sequence: 1,2,3,4,5,4,3,2,1
kensuguro magronbass at gmail.com writes: so basically, it's impossible to do with just seq() and rep().. Doesn't seem like a good question for chapter 1... Also, problem 1.13 is even more crazy.. it asks you to build the fibonacci sequence. Now I'm a programmer, and so went way ahead in the book to see how functions were written, and just wrote my own function, but again, in chapter 1? (only covered c(), seq(), and rep() at this point) What away kick start a book. Is Using R project for Introductory Statistics known to jump around or have out of sequence practice problems? Otherwise it seems to be written very well. Sorry about that one. On the errata page I have: page 16, exercise 1.12 #5 This one is most easily done using c() and the sequence operator :. (Please ignore request to use just seq and rep.) As for 1.13, I just wanted someone to use c() for that one. I don't even define the Fibonacci sequence, I only wanted some context to a sequence of numbers that is not an arithmetic progression. Not sure if the rest of the book jumps around, but if it seems to to you, I'm very open to comments about improvements. Just email. John __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] how to make this sequence: 1,2,3,4,5,4,3,2,1
c(x,(x-1:5)[4:1]) -Original Message- From: baptiste auguie [mailto:baptiste.aug...@googlemail.com] Sent: Friday, March 05, 2010 1:08 AM To: kensuguro Cc: r-help@r-project.org Subject: Re: [R] how to make this sequence: 1,2,3,4,5,4,3,2,1 c(x - 1:5, rev(x[-length(x)])) On 5 March 2010 07:04, kensuguro magronb...@gmail.com wrote: I'm just beginning R, with book Using R for Introductory Statistics, and one of the early questions has me baffled. The question is, create the sequence: 1,2,3,4,5,4,3,2,1 using seq() and rep(). Now, as a programmer, I am punching myself to not be able to figure it out.. I mean, as simple as a for loop, but using seq, I am stumped. I would think c(1:5, 4:1) would be the brute force method with very non intelligent coding.. there has to be a way to make the turning point (in this case 5) parametric right? So you could change it later and the sequence will reflect it. -- View this message in context: http://n4.nabble.com/how-to-make-this-sequence-1-2-3-4-5-4-3-2-1-tp157 9245p1579245.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Baptiste Auguié Departamento de Química Física, Universidade de Vigo, Campus Universitario, 36310, Vigo, Spain tel: +34 9868 18617 http://webs.uvigo.es/coloides __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] how to make this sequence: 1,2,3,4,5,4,3,2,1
I'm just beginning R, with book Using R for Introductory Statistics, and one of the early questions has me baffled. The question is, create the sequence: 1,2,3,4,5,4,3,2,1 using seq() and rep(). Now, as a programmer, I am punching myself to not be able to figure it out.. I mean, as simple as a for loop, but using seq, I am stumped. I would think c(1:5, 4:1) would be the brute force method with very non intelligent coding.. there has to be a way to make the turning point (in this case 5) parametric right? So you could change it later and the sequence will reflect it. -- View this message in context: http://n4.nabble.com/how-to-make-this-sequence-1-2-3-4-5-4-3-2-1-tp1579245p1579245.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
