Re: [R] median for time data
Hi again. I´m sorry to ask again but I cannot do the boxplot coprrectly. I'm typing: start.posix=as.POSIXct(skiers[,3]) boxplot(start.posix) where skiers[,3] is my time data, and I get this error I have no idea of what that means.. All the other steps are ready, like the median of the time data, but Im really stock trying to do the boxplot with the time data on the y axis to interprete the median Thanks again Jannis v. Buttlar wrote: uvilla schrieb: When I use strptime() I just get NA NA NA I`m new at using R, must finisth this work thoug I guess Im doing totally wrong, actually everytime i try to use POSIXct it doesn`t work If you have a look at help(strptime) you find that you have to specify the format in which you time is written. Try strptime(08:10:10,%H:%M:%S) The stuff after the comma in the is the way to give strptime the format. Now you only have use strptime(vectorwithyourtime,%H:%M:%S) and you should get a vector with R format times out of it. It uses todays date though but for your calculations this should work. This POSIXct format is not very handy to use though, so you perhaps better consider using library(chron) as Gabor suggested. Thanks a lot Jannis wrote: Hi, try to convert this to the R time format POSIXct or POSIXlt via strptime(). Then you can simply substract them. I am not sure whether a median can be calculated though (should be possible as POSIXct stores the value as seconds since 1970) Best Jannis uvilla schrieb: Hi everybody How do I do to calculate the median and average of a colum of time data like this: 8:50:10. I also need to plot the time difference between two colums Thanks a lot __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. :-((:-(( -- View this message in context: http://n4.nabble.com/median-for-time-data-tp932287p947591.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] median for time data
I fear nobody can really help you as we can not really understandd what your problem is. What does the error message read? What values does start.posix have? And what skiers? You should include the code for a reproducable example. include at least 2 values for skiers[,3] in their correct format and class, so we can run the code ourselves and check what is going on. Then we can (hopefully) help you. uvilla schrieb: Hi again. I´m sorry to ask again but I cannot do the boxplot coprrectly. I'm typing: start.posix=as.POSIXct(skiers[,3]) boxplot(start.posix) where skiers[,3] is my time data, and I get this error I have no idea of what that means.. All the other steps are ready, like the median of the time data, but Im really stock trying to do the boxplot with the time data on the y axis to interprete the median Thanks again Jannis v. Buttlar wrote: uvilla schrieb: When I use strptime() I just get NA NA NA I`m new at using R, must finisth this work thoug I guess Im doing totally wrong, actually everytime i try to use POSIXct it doesn`t work If you have a look at help(strptime) you find that you have to specify the format in which you time is written. Try strptime(08:10:10,%H:%M:%S) The stuff after the comma in the is the way to give strptime the format. Now you only have use strptime(vectorwithyourtime,%H:%M:%S) and you should get a vector with R format times out of it. It uses todays date though but for your calculations this should work. This POSIXct format is not very handy to use though, so you perhaps better consider using library(chron) as Gabor suggested. Thanks a lot Jannis wrote: Hi, try to convert this to the R time format POSIXct or POSIXlt via strptime(). Then you can simply substract them. I am not sure whether a median can be calculated though (should be possible as POSIXct stores the value as seconds since 1970) Best Jannis uvilla schrieb: Hi everybody How do I do to calculate the median and average of a colum of time data like this: 8:50:10. I also need to plot the time difference between two colums Thanks a lot __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. :-((:-(( __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] median for time data
Hi everybody How do I do to calculate the median and average of a colum of time data like this: 8:50:10. I also need to plot the time difference between two colums Thanks a lot -- View this message in context: http://n4.nabble.com/median-for-time-data-tp932287p932287.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] median for time data
Hi, try to convert this to the R time format POSIXct or POSIXlt via strptime(). Then you can simply substract them. I am not sure whether a median can be calculated though (should be possible as POSIXct stores the value as seconds since 1970) Best Jannis uvilla schrieb: Hi everybody How do I do to calculate the median and average of a colum of time data like this: 8:50:10. I also need to plot the time difference between two colums Thanks a lot __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] median for time data
Thanks a lot for your answer Jannis. Actually, I should have specified what I`m trying to do. I have a datafame which 3 colums, one is the person ID, second is Anfag and third is Ende. The two time colums are in this way: 8:50:10, so I have to calculate the medan of the Anfag colum and to determine the length of the route. When I use strptime() I just get NA NA NA I`m new at using R, must finisth this work thoug I guess Im doing totally wrong, actually everytime i try to use POSIXct it doesn`t work Thanks a lot Jannis wrote: Hi, try to convert this to the R time format POSIXct or POSIXlt via strptime(). Then you can simply substract them. I am not sure whether a median can be calculated though (should be possible as POSIXct stores the value as seconds since 1970) Best Jannis uvilla schrieb: Hi everybody How do I do to calculate the median and average of a colum of time data like this: 8:50:10. I also need to plot the time difference between two colums Thanks a lot __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://n4.nabble.com/median-for-time-data-tp932287p932402.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] median for time data
# input library(chron) tt - times(c(8:50:10, 9:40:20, 10:55:45)) tt2 - times(c(01:00:00, 02:00:00, 03:00:00)) tt tt2 # calc median and differences (although it will give results as fractions of a day if there are negative results) median(tt) tt - tt2 tt2 - tt On Tue, Dec 1, 2009 at 10:46 AM, uvilla maruchave...@hotmail.com wrote: Hi everybody How do I do to calculate the median and average of a colum of time data like this: 8:50:10. I also need to plot the time difference between two colums Thanks a lot -- View this message in context: http://n4.nabble.com/median-for-time-data-tp932287p932287.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] median for time data
uvilla schrieb: When I use strptime() I just get NA NA NA I`m new at using R, must finisth this work thoug I guess Im doing totally wrong, actually everytime i try to use POSIXct it doesn`t work If you have a look at help(strptime) you find that you have to specify the format in which you time is written. Try strptime(08:10:10,%H:%M:%S) The stuff after the comma in the is the way to give strptime the format. Now you only have use strptime(vectorwithyourtime,%H:%M:%S) and you should get a vector with R format times out of it. It uses todays date though but for your calculations this should work. This POSIXct format is not very handy to use though, so you perhaps better consider using library(chron) as Gabor suggested. Thanks a lot Jannis wrote: Hi, try to convert this to the R time format POSIXct or POSIXlt via strptime(). Then you can simply substract them. I am not sure whether a median can be calculated though (should be possible as POSIXct stores the value as seconds since 1970) Best Jannis uvilla schrieb: Hi everybody How do I do to calculate the median and average of a colum of time data like this: 8:50:10. I also need to plot the time difference between two colums Thanks a lot __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] median for time data
Thanks you both Jannis now it is working!!. I just have one mor request, please! How I'm suppose to make a boxplot with anfang, when working with times, it just have on the y axis some decimal number which make no sense. i need the time to appear in the y axis in order to see the median in the boxplot Thanks again!!! Jannis v. Buttlar wrote: uvilla schrieb: When I use strptime() I just get NA NA NA I`m new at using R, must finisth this work thoug I guess Im doing totally wrong, actually everytime i try to use POSIXct it doesn`t work If you have a look at help(strptime) you find that you have to specify the format in which you time is written. Try strptime(08:10:10,%H:%M:%S) The stuff after the comma in the is the way to give strptime the format. Now you only have use strptime(vectorwithyourtime,%H:%M:%S) and you should get a vector with R format times out of it. It uses todays date though but for your calculations this should work. This POSIXct format is not very handy to use though, so you perhaps better consider using library(chron) as Gabor suggested. Thanks a lot Jannis wrote: Hi, try to convert this to the R time format POSIXct or POSIXlt via strptime(). Then you can simply substract them. I am not sure whether a median can be calculated though (should be possible as POSIXct stores the value as seconds since 1970) Best Jannis uvilla schrieb: Hi everybody How do I do to calculate the median and average of a colum of time data like this: 8:50:10. I also need to plot the time difference between two colums Thanks a lot __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://n4.nabble.com/median-for-time-data-tp932287p932511.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
