When I run your code, I get a different error:
j=10; ss=150; r=array(0 , c( j , ss )); rr=array(0 , c( j , ss ));
r1=array(0 , c( j-1 , ss )); r2=array(0 , c( j-1 , ss ));
r3=array(0 , c( 2 , ss ))
for(i in 1:j-1){
+r1[ i , ] - r[ j+1, ]-r[ j, ]; r2[ i , ] - rr[
j+1, ]-rr[ j, ]
+r3[ i,]=rbind(r1[ i, ], r2[ i, ])
+}
Error: subscript out of bounds
This is probably due to 'r' being dimensioned (j,ss) and you are referencing
'r[j+1,]' which is r[11,]. Also I think you want for(i in 1:(j-1)),
notice the difference:
1:j-1
[1] 0 1 2 3 4 5 6 7 8 9
1:(j-1)
[1] 1 2 3 4 5 6 7 8 9
On Tue, Jun 3, 2008 at 1:58 PM, Muhammad Azam [EMAIL PROTECTED] wrote:
Dear R users
I tried a lot to solve the following problem but could not. I have two
arrays having same order i.e 1 by 150.
j=10; ss=150; r=array(0 , c( j , ss )); rr=array(0 , c( j , ss ));
r1=array(0 , c( j-1 , ss )); r2=array(0 , c( j-1 , ss ));
r3=array(0 , c( 2 , ss ))
for(i in 1:j-1){
r1[ i , ] - r[ j+1, ]-r[ j, ]; r2[ i , ] - rr[
j+1, ]-rr[ j, ]
}
Now i want to rbind the results of r1 and r2 for each time. Now the order
of r3[ j, ] will become 2 by 150. I used the following form in the loop
r3[ i,]=rbind(r1[ i, ], r2[ i, ])
But there is an error message
Error in r3[i, ] = rbind(r1[i, ], r2[i, ]) : number of items to replace is
not a multiple of replacement length
I am looking for some suggestion to solve the problem. Thanks and
best regards
Muhammad Azam
Ph.D. Student
Department of Medical Statistics,
Informatics and Health Economics
University of Innsbruck, Austria
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What is the problem you are trying to solve?
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