Use do.call(func, listOfArgs) when you don't
know how many arguments will be passed to func.
E.g.,
> x <- cbind(round(sin(1:10)), round(cos(1:10)), round(tan(1:10)))
> x[do.call("order", split(x, col(x))), , drop=FALSE]
[,1] [,2] [,3]
[1,] -1 -11
[2,] -1 -11
[3,] -10 -3
[4,]0 -10
[5,]0 -10
[6,]010
[7,]10 -7
[8,]10 -2
[9,]111
[10,]112
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of Maxim
> Sent: Friday, September 23, 2011 9:22 AM
> To: r-help
> Subject: [R] sorting multiple columns of a matrix
>
> Hi,
>
>
> I have a question about how to sort a matrix for multiple columns.
>
>
> dat<-sample(0:1,1000,replace=T)
>
> matrix(dat,ncol=5,nrow=200)->x
>
>
> I want to order like the following:
>
>
> x[order(x[,1],x[,2],x[,3],x[,4],x[,5]),]->x
>
>
> My problem: the number of columns of the matrix to be sorted is variable, in
> any way I would like to sort for all columns from 1:ncol(x). How to achieve
> this?
>
>
> Best
>
>
> Maxim
>
> [[alternative HTML version deleted]]
>
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