k-c(1,1,1,1,1,3,5,6,2,1,3,9,2,3,1,1,1)
table(k)
k
1 2 3 5 6 9
9 2 3 1 1 1
names(table(k))
[1] 1 2 3 5 6 9
as.numeric(names(table(k)))
[1] 1 2 3 5 6 9
x - table(k)
as.numeric(names(table(k)))[4]
[1] 5
You can always save the (numeric version of the) names as an object, too.
Does that help?
Dennis
2011/3/16 Frédérique Kuiper fre_stam...@hotmail.com
Dear reader,
I have the following problem:
I have some string with numbers like k. I want
to have a table like the function table() gives. However I am not able
to call the first row, the 1, 2, 3, 5, 6 or 9. I tried to do that by a
data.frame, but that doesn't seem to work either. The levels keep
bothering me.
This is an example of the code:
k-c(1,1,1,1,1,3,5,6,2,1,3,9,2,3,1,1,1)
table(k)
k
1 2 3 5 6 9
9 2 3 1 1 1
x-table(k)
dim(x)
[1] 6
x[4] #But I only want to read the five
5
1
x-data.frame(x)
x[4,1] #You are not allowed to use this five for example 3*x[4,1] is
impossible
[1] 5
Levels: 1 2 3 5 6 9
I hope anyone has an idea of using the table
function without this inconvenience. I thought about writing a counter
myself, but that seems complicated.
Because I have to examine very large examples later on, I don't want to
slow the calculations down if possible.
Thanks for your help in advance.
Frederique
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
