Re: [R] How do I specify a partially completed survival analysis model?

2009-11-23 Thread Marc Schwartz

On Nov 23, 2009, at 12:50 PM, David Winsemius wrote:



On Nov 20, 2009, at 1:27 PM, David Winsemius wrote:



On Nov 20, 2009, at 11:07 AM, RWilliam wrote:



In reply to suggestion by David W., setting an offset parameter  
doesn't seem

to work as R is not recognizing the "X2" part of  coxph(
Surv(Time,Censor)~X1, offset=log(4.3*X2), data= a ). Also, here's  
some

sample data:



The problem, arising as a result of not having a dataset against  
which to test my memories of syntactic niceties, is that glm and  
coxph use different methods of supplying offsets.


It's been pointed out to me that coxph()'s required syntactic  
incorporation of offsets is the same as glm()'s preferred inclusion  
in the formula, and that my erroneous impression that a separate  
offset argument is necessary might have be the result of "SAS  
poisoning".


I suspect that "infection" is the more correct biomedical analogy,  
since I copied my use from another who was probably the index case.  
That usage was also similar to the separate specification of offsets  
(e.g.  $CAL LPY=%LOG(PY) $OFFSET LPY) in GLIM which was my  
statistical upbringing.




Would that be SAS1N1 and is there a vaccine that one can distribute to  
universities and corporations to prevent the spread of the infection?


;-)

Regards,

Marc Schwartz

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Re: [R] How do I specify a partially completed survival analysis model?

2009-11-23 Thread David Winsemius


On Nov 20, 2009, at 1:27 PM, David Winsemius wrote:



On Nov 20, 2009, at 11:07 AM, RWilliam wrote:



In reply to suggestion by David W., setting an offset parameter  
doesn't seem

to work as R is not recognizing the "X2" part of  coxph(
Surv(Time,Censor)~X1, offset=log(4.3*X2), data= a ). Also, here's  
some

sample data:



The problem, arising as a result of not having a dataset against  
which to test my memories of syntactic niceties, is that glm and  
coxph use different methods of supplying offsets.


It's been pointed out to me that coxph()'s required syntactic  
incorporation of offsets is the same as glm()'s preferred inclusion in  
the formula, and that my erroneous impression that a separate offset  
argument is necessary might have be the result of "SAS poisoning".


I suspect that "infection" is the more correct biomedical analogy,  
since I copied my use from another who was probably the index case.  
That usage was also similar to the separate specification of offsets  
(e.g.  $CAL LPY=%LOG(PY) $OFFSET LPY) in GLIM which was my statistical  
upbringing.


--
David.


Thereau and Gramsch's book has examples, but if you did not have the  
book you still had alternatives. A bit of searching with the terms:  
coxph Therneau offset;  produced lots of hits for the occurrence of  
offset in warning messages so adding -warning to that search then  
produced a hit to the Google books look at T&G's text with a worked  
example:


> a$logX2 <- log(a$X2)
> coxph(Surv(Time,Censor)~X1 + offset(logX2), data= a )
Call:
coxph(formula = Surv(Time, Censor) ~ X1 + offset(logX2), data = a)


coef exp(coef) se(coef) zp
X1 -0.885 0.413 1.43 -0.62 0.54

#Or just:

> coxph(Surv(Time,Censor)~X1 + offset(log(4.3*X2)), data= a )




 X1 X2 TimeCensor
1   1 0.40619454  77.00666  0
2   1 0.20717868 100.0  0
3   1 0.77360963  79.03463  1
4   1 0.62221954 100.0  0
5   1 0.32191280 100.0  0
6   1 0.73790704  72.84842  0
7   1 0.65012237 100.0  0
8   1 0.71596105 100.0  0
9   1 0.74787202  84.00172  0
10  1 0.66803790  41.65760  0
11  1 0.79922364  92.41999  0
12  1 0.76433736  90.99983  0
13  1 0.57014524 100.0  0
14  1 0.39642235 100.0  0
15  1 0.55756045 100.0  0
16  0 0.60079340 100.0  0
17  0 0.43630695 100.0  0
18  0 0.09388013 100.0  0
19  0 0.55956791 100.0  0
20  0 0.52491597  97.71884  1

where we set the coefficient of X2 to be 8.



RWilliam wrote:


Sorry for being impatient but is there really no way of doing this  
at all?

It's quite urgent so any help is very much appreciated. Thank you.



RWilliam wrote:


Hello,

I just started using R to do epidemiologic simulation research  
using the
Cox proportional hazard model. I have 2 covariates X1 and X2  
which I want
to model as h(t,X)=h0(t)*exp(b1*X1+b2*X2). I assume independence  
of X

from t.

After I simulate Time and Censor data vectors denoting the  
censoring time
and status respectively, I can call the following function to fit  
the
data into the Cox model (a is a data.frame containing 4 columns  
X1, X2,

Time and Censor):
b = coxph (Surv (Time, Censor) ~ X1 + X2, data = a, method =  
"breslow");


Now the purpose of me doing simulation is that I have another  
mechanism
to generate the number b2. From the given b2 (say it's 4.3), Cox  
model
can be fit to generate b1 and check how feasible the new model  
is. Thus,
my question is, how do I specify such a model that is partially  
completed
(as in b2 is known). I tried things like  
Surv(Time,Censor)~X1+4.3*X2, but

it's not working. Thanks very much.






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and provide commented, minimal, self-contained, reproducible code.


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] How do I specify a partially completed survival analysis model

2009-11-20 Thread Terry Therneau
--- begin inclusion --
After I simulate Time and Censor data vectors denoting the censoring
time
and status respectively, I can call the following function to fit the
data
into the Cox model (a is a data.frame containing 4 columns X1, X2, Time
and
Censor):
b = coxph (Surv (Time, Censor) ~ X1 + X2, data = a, method = "breslow");

Now the purpose of me doing simulation is that I have another mechanism
to
generate the number b2. From the given b2 (say it's 4.3), Cox model can
be
fit to generate b1 and check how feasible the new model is. Thus, my
question is, how do I specify such a model that is partially completed
(as
in b2 is known). I tried things like Surv(Time,Censor)~X1+4.3*X2, but
it's
not working. Thanks very much.

---end inclusion 

1. Use an offset argument.  Anything therein is put into the linear
predictor "as is".
  coxph(Surv(Time, Censor) ~ X1 + offset(X2*b2), data=a)

2.  method='breslow'
 This never ceases to amaze me.  The Efron approximation is uniformly
superior to the Breslow -- that's why it is the default --- but the
inferior method remains more popular to the point that people force the
program to use it.  I suppose because it was easier to program and thus
was the first one implimented.  However, for simulated data there will
not be any ties in "time" so the two are identical.

Terry Therneau

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Re: [R] How do I specify a partially completed survival analysis model?

2009-11-20 Thread David Winsemius


On Nov 20, 2009, at 11:07 AM, RWilliam wrote:



In reply to suggestion by David W., setting an offset parameter  
doesn't seem

to work as R is not recognizing the "X2" part of  coxph(
Surv(Time,Censor)~X1, offset=log(4.3*X2), data= a ). Also, here's some
sample data:



The problem, arising as a result of not having a dataset against which  
to test my memories of syntactic niceties, is that glm and coxph use  
different methods of supplying offsets. Thereau and Gramsch's book has  
examples, but if you did not have the book you still had alternatives.  
A bit of searching with the terms: coxph Therneau offset;  produced  
lots of hits for the occurrence of offset in warning messages so  
adding -warning to that search then produced a hit to the Google books  
look at T&G's text with a worked example:


> a$logX2 <- log(a$X2)
> coxph(Surv(Time,Censor)~X1 + offset(logX2), data= a )
Call:
coxph(formula = Surv(Time, Censor) ~ X1 + offset(logX2), data = a)


 coef exp(coef) se(coef) zp
X1 -0.885 0.413 1.43 -0.62 0.54

#Or just:

> coxph(Surv(Time,Censor)~X1 + offset(log(4.3*X2)), data= a )




  X1 X2 TimeCensor
1   1 0.40619454  77.00666  0
2   1 0.20717868 100.0  0
3   1 0.77360963  79.03463  1
4   1 0.62221954 100.0  0
5   1 0.32191280 100.0  0
6   1 0.73790704  72.84842  0
7   1 0.65012237 100.0  0
8   1 0.71596105 100.0  0
9   1 0.74787202  84.00172  0
10  1 0.66803790  41.65760  0
11  1 0.79922364  92.41999  0
12  1 0.76433736  90.99983  0
13  1 0.57014524 100.0  0
14  1 0.39642235 100.0  0
15  1 0.55756045 100.0  0
16  0 0.60079340 100.0  0
17  0 0.43630695 100.0  0
18  0 0.09388013 100.0  0
19  0 0.55956791 100.0  0
20  0 0.52491597  97.71884  1

where we set the coefficient of X2 to be 8.



RWilliam wrote:


Sorry for being impatient but is there really no way of doing this  
at all?

It's quite urgent so any help is very much appreciated. Thank you.



RWilliam wrote:


Hello,

I just started using R to do epidemiologic simulation research  
using the
Cox proportional hazard model. I have 2 covariates X1 and X2 which  
I want
to model as h(t,X)=h0(t)*exp(b1*X1+b2*X2). I assume independence  
of X

from t.

After I simulate Time and Censor data vectors denoting the  
censoring time
and status respectively, I can call the following function to fit  
the
data into the Cox model (a is a data.frame containing 4 columns  
X1, X2,

Time and Censor):
b = coxph (Surv (Time, Censor) ~ X1 + X2, data = a, method =  
"breslow");


Now the purpose of me doing simulation is that I have another  
mechanism
to generate the number b2. From the given b2 (say it's 4.3), Cox  
model
can be fit to generate b1 and check how feasible the new model is.  
Thus,
my question is, how do I specify such a model that is partially  
completed
(as in b2 is known). I tried things like  
Surv(Time,Censor)~X1+4.3*X2, but

it's not working. Thanks very much.






--
View this message in context: 
http://old.nabble.com/How-do-I-specify-a-partially-completed-survival-analysis-model--tp26421391p26443562.html
Sent from the R help mailing list archive at Nabble.com.

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] How do I specify a partially completed survival analysis model?

2009-11-20 Thread RWilliam

In reply to suggestion by David W., setting an offset parameter doesn't seem
to work as R is not recognizing the "X2" part of  coxph(
Surv(Time,Censor)~X1, offset=log(4.3*X2), data= a ). Also, here's some
sample data:

   X1 X2 TimeCensor
1   1 0.40619454  77.00666  0
2   1 0.20717868 100.0  0
3   1 0.77360963  79.03463  1
4   1 0.62221954 100.0  0
5   1 0.32191280 100.0  0
6   1 0.73790704  72.84842  0
7   1 0.65012237 100.0  0
8   1 0.71596105 100.0  0
9   1 0.74787202  84.00172  0
10  1 0.66803790  41.65760  0
11  1 0.79922364  92.41999  0
12  1 0.76433736  90.99983  0
13  1 0.57014524 100.0  0
14  1 0.39642235 100.0  0
15  1 0.55756045 100.0  0
16  0 0.60079340 100.0  0
17  0 0.43630695 100.0  0
18  0 0.09388013 100.0  0
19  0 0.55956791 100.0  0
20  0 0.52491597  97.71884  1

where we set the coefficient of X2 to be 8.



RWilliam wrote:
> 
> Sorry for being impatient but is there really no way of doing this at all?
> It's quite urgent so any help is very much appreciated. Thank you.
> 
> 
> 
> RWilliam wrote:
>> 
>> Hello,
>> 
>> I just started using R to do epidemiologic simulation research using the
>> Cox proportional hazard model. I have 2 covariates X1 and X2 which I want
>> to model as h(t,X)=h0(t)*exp(b1*X1+b2*X2). I assume independence of X
>> from t. 
>> 
>> After I simulate Time and Censor data vectors denoting the censoring time
>> and status respectively, I can call the following function to fit the
>> data into the Cox model (a is a data.frame containing 4 columns X1, X2,
>> Time and Censor):
>> b = coxph (Surv (Time, Censor) ~ X1 + X2, data = a, method = "breslow");
>> 
>> Now the purpose of me doing simulation is that I have another mechanism
>> to generate the number b2. From the given b2 (say it's 4.3), Cox model
>> can be fit to generate b1 and check how feasible the new model is. Thus,
>> my question is, how do I specify such a model that is partially completed
>> (as in b2 is known). I tried things like Surv(Time,Censor)~X1+4.3*X2, but
>> it's not working. Thanks very much.
>> 
> 
> 

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Re: [R] How do I specify a partially completed survival analysis model?

2009-11-20 Thread David Winsemius


On Nov 20, 2009, at 9:57 AM, David Winsemius wrote:



On Nov 20, 2009, at 9:46 AM, RWilliam wrote:



Sorry for being impatient but is there really no way of doing this  
at all?

It's quite urgent so any help is very much appreciated. Thank you.



The general method with glm's to specify a model with fixed  
coefficients is to use an offset. I believe that the coxph function  
also has that facility and seem to remember that Therneau uses  
offsets in some of the examples he offers in his books and technical  
reports.


Perhaps:
cmod <- coxph( Surv(Time,Censor)~X1, offset=4.3*X2, data=   )


Or much more likely:
cmod <- coxph( Surv(Time,Censor)~X1, offset=log(4.3*X2), data=  
  )


I forgot what scale I should be thinking on. Sorry.

--
David



Further requests about specifics should be accompanied (as suggested  
by the Posting Guide) by some code that sets up a reproducible  
example.


--
David.



RWilliam wrote:


Hello,

I just started using R to do epidemiologic simulation research  
using the
Cox proportional hazard model. I have 2 covariates X1 and X2 which  
I want
to model as h(t,X)=h0(t)*exp(b1*X1+b2*X2). I assume independence  
of X from

t.

After I simulate Time and Censor data vectors denoting the  
censoring time
and status respectively, I can call the following function to fit  
the data
into the Cox model (a is a data.frame containing 4 columns X1, X2,  
Time

and Censor):
b = coxph (Surv (Time, Censor) ~ X1 + X2, data = a, method =  
"breslow");


Now the purpose of me doing simulation is that I have another  
mechanism to
generate the number b2. From the given b2 (say it's 4.3), Cox  
model can be

fit to generate b1 and check how feasible the new model is. Thus, my
question is, how do I specify such a model that is partially  
completed (as
in b2 is known). I tried things like Surv(Time,Censor)~X1+4.3*X2,  
but it's

not working. Thanks very much.



--
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http://old.nabble.com/How-do-I-specify-a-partially-completed-survival-analysis-model--tp26421391p26441878.html
Sent from the R help mailing list archive at Nabble.com.

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] How do I specify a partially completed survival analysis model?

2009-11-20 Thread David Winsemius


On Nov 20, 2009, at 9:46 AM, RWilliam wrote:



Sorry for being impatient but is there really no way of doing this  
at all?

It's quite urgent so any help is very much appreciated. Thank you.



The general method with glm's to specify a model with fixed  
coefficients is to use an offset. I believe that the coxph function  
also has that facility and seem to remember that Therneau uses offsets  
in some of the examples he offers in his books and technical reports.


Perhaps:
cmod <- coxph( Surv(Time,Censor)~X1, offset=4.3*X2, data=   )

Further requests about specifics should be accompanied (as suggested  
by the Posting Guide) by some code that sets up a reproducible example.


--
David.



RWilliam wrote:


Hello,

I just started using R to do epidemiologic simulation research  
using the
Cox proportional hazard model. I have 2 covariates X1 and X2 which  
I want
to model as h(t,X)=h0(t)*exp(b1*X1+b2*X2). I assume independence of  
X from

t.

After I simulate Time and Censor data vectors denoting the  
censoring time
and status respectively, I can call the following function to fit  
the data
into the Cox model (a is a data.frame containing 4 columns X1, X2,  
Time

and Censor):
b = coxph (Surv (Time, Censor) ~ X1 + X2, data = a, method =  
"breslow");


Now the purpose of me doing simulation is that I have another  
mechanism to
generate the number b2. From the given b2 (say it's 4.3), Cox model  
can be

fit to generate b1 and check how feasible the new model is. Thus, my
question is, how do I specify such a model that is partially  
completed (as
in b2 is known). I tried things like Surv(Time,Censor)~X1+4.3*X2,  
but it's

not working. Thanks very much.



--
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__
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and provide commented, minimal, self-contained, reproducible code.


David Winsemius, MD
Heritage Laboratories
West Hartford, CT

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] How do I specify a partially completed survival analysis model?

2009-11-20 Thread RWilliam

Sorry for being impatient but is there really no way of doing this at all?
It's quite urgent so any help is very much appreciated. Thank you.



RWilliam wrote:
> 
> Hello,
> 
> I just started using R to do epidemiologic simulation research using the
> Cox proportional hazard model. I have 2 covariates X1 and X2 which I want
> to model as h(t,X)=h0(t)*exp(b1*X1+b2*X2). I assume independence of X from
> t. 
> 
> After I simulate Time and Censor data vectors denoting the censoring time
> and status respectively, I can call the following function to fit the data
> into the Cox model (a is a data.frame containing 4 columns X1, X2, Time
> and Censor):
> b = coxph (Surv (Time, Censor) ~ X1 + X2, data = a, method = "breslow");
> 
> Now the purpose of me doing simulation is that I have another mechanism to
> generate the number b2. From the given b2 (say it's 4.3), Cox model can be
> fit to generate b1 and check how feasible the new model is. Thus, my
> question is, how do I specify such a model that is partially completed (as
> in b2 is known). I tried things like Surv(Time,Censor)~X1+4.3*X2, but it's
> not working. Thanks very much.
> 

-- 
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