Re: [R] Is there an equivalent * operator?
Hi Robin, to answer your question: I think you are looking for a regular expression, have a look at regex(). In your particular case, where all the strings show the same structure, you can also use substr() to cut out the substring of interest. More generally, you could consider to convert your your string-dates to real date information with strptime(). After doing so, you can easily calculate functions on various date combinations with format() and tapply(). > date<-strptime(data$date,format="%d-%B-%y") > tapply(data$temperature,format(date,format="%m"),FUN=mean,na.rm=F) > # or, if you only want the results for september, use which() > mean(data$temperature[which(format(date,format="%m")==9)]) Read the help files on the details. :) Cheers, René > -Ursprüngliche Nachricht- > Von: "Williams, Robin" <[EMAIL PROTECTED]> > Gesendet: 24.07.08 14:18:13 > An: > Betreff: [R] Is there an equivalent * operator? > Hi all, > Is there an equivalent to the general * operator in R, where * can > represent any character? > I have a dataset, one column being date, date ranging between > April-September, 97-06. I would like to be able to acquire the data for > a specific month, say September, so that I can take average temperatures > for the month, etc. I thought I would be able to do something like > data.s1 <- subset(data,date=="**-Sep-**") > data.s1 > but when I do > data.s1 > I get "0 rows or 0-length row.names". > Any idea of a simple way I can perform this task? > All dates are in the form xx-xxx-xx, EG 30-Sep-06. > Thanks for any assistance. > > > Robin Williams > Met Office summer intern - Health Forecasting > [EMAIL PROTECTED] > > > > [[alternative HTML version deleted]] > > __ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > Ihre Messenger, Communities und E-Mails jetzt in einem Programm! __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Is there an equivalent * operator?
If you really want to work with character strings, you could do something like
data.s1 <- data$date[grep(".*-Sep-.*", date)]
(see ?regexp for more on pattern matching)
but there are better ways to handle dates. You should convert the
character strings into Date objects: see ?Date. And check out the zoo
package.
-Felix
On Thu, Jul 24, 2008 at 8:30 PM, Williams, Robin
<[EMAIL PROTECTED]> wrote:
> Hi all,
> Is there an equivalent to the general * operator in R, where * can
> represent any character?
> I have a dataset, one column being date, date ranging between
> April-September, 97-06. I would like to be able to acquire the data for
> a specific month, say September, so that I can take average temperatures
> for the month, etc. I thought I would be able to do something like
> data.s1 <- subset(data,date=="**-Sep-**")
> data.s1
> but when I do
> data.s1
> I get "0 rows or 0-length row.names".
> Any idea of a simple way I can perform this task?
> All dates are in the form xx-xxx-xx, EG 30-Sep-06.
> Thanks for any assistance.
>
>
> Robin Williams
> Met Office summer intern - Health Forecasting
> [EMAIL PROTECTED]
>
>
>
>[[alternative HTML version deleted]]
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Felix Andrews / 安福立
PhD candidate
Integrated Catchment Assessment and Management Centre
The Fenner School of Environment and Society
The Australian National University (Building 48A), ACT 0200
Beijing Bag, Locked Bag 40, Kingston ACT 2604
http://www.neurofractal.org/felix/
3358 543D AAC6 22C2 D336 80D9 360B 72DD 3E4C F5D8
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Is there an equivalent * operator?
Williams, Robin wrote: Hi all, Is there an equivalent to the general * operator in R, where * can represent any character? I have a dataset, one column being date, date ranging between April-September, 97-06. I would like to be able to acquire the data for a specific month, say September, so that I can take average temperatures for the month, etc. I thought I would be able to do something like data.s1 <- subset(data,date=="**-Sep-**") data.s1 but when I do data.s1 I get "0 rows or 0-length row.names". Any idea of a simple way I can perform this task? All dates are in the form xx-xxx-xx, EG 30-Sep-06. Thanks for any assistance. grep() and related functions described on the same man page can match general regular expressions. The pattern you want would be "^..-Sep-..$". Read the man page; they have several options for output format. They work on character vectors; if your data has already been converted to a date format, there are likely other options, e.g. converting the date with format %b (see ?strftime) so only the month is included. Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Is there an equivalent * operator?
Something like this might do what you want:
dates<-paste(c("2008"), c("Jan", "Feb", "Sep", "Sep", "Dec"), 1:3,
sep="")
temp<-rnorm(length(dates))*30
data1<-data.frame(Dates=dates, Temp=temp)
data.s1<-data1[grep("Sep", data1[["Dates"]]),]
> data.s1
Dates Temp
3 2008Sep3 22.263627
4 2008Sep1 9.854643
Regards
JS
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Williams, Robin
Sent: 24 July 2008 11:31
To: r-help@r-project.org
Subject: [R] Is there an equivalent * operator?
Hi all,
Is there an equivalent to the general * operator in R, where * can
represent any character?
I have a dataset, one column being date, date ranging between
April-September, 97-06. I would like to be able to acquire the data for
a specific month, say September, so that I can take average temperatures
for the month, etc. I thought I would be able to do something like
data.s1 <- subset(data,date=="**-Sep-**")
data.s1
but when I do
data.s1
I get "0 rows or 0-length row.names".
Any idea of a simple way I can perform this task?
All dates are in the form xx-xxx-xx, EG 30-Sep-06.
Thanks for any assistance.
Robin Williams
Met Office summer intern - Health Forecasting
[EMAIL PROTECTED]
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
