Re: [R] R: extract data.frames from a list
try this, do.call(rbind, tmp) baptiste 2009/7/17 Angel Spassov anspas...@googlemail.com Dear useRs and developeRs, I am struggling with a simple but not obviously solvable issue. Suppose I have the following list of data.frames called 'tmp': a - data.frame(a=rnorm(10),b=letters[1:10]) (tmp - list(a,a[1:4,],a[1:7,])) It is known that all data.frames in this list have the same number of columns (and this is a good thing). I want to build a bigger data.frame consisting of all list-members, e.g. the result should look like: (res - rbind(tmp[[1]],tmp[[2]],tmp[[3]])) The question is how could I do this most efficiently? My real list consist of about 700 data.frames, each with with exactly 10 columns and plenty of rows. The obvious for-loop solution is rather time consuming and therefore I'm looking for something more efficient. Thank you in advance, AS. ps: 'sapply' should somehow do the trick, doesn't it? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- _ Baptiste Auguié School of Physics University of Exeter Stocker Road, Exeter, Devon, EX4 4QL, UK Phone: +44 1392 264187 http://newton.ex.ac.uk/research/emag __ [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R: extract data.frames from a list
do.call(rbind, tmp) On Fri, Jul 17, 2009 at 10:55 AM, Angel Spassov anspas...@googlemail.comwrote: Dear useRs and developeRs, I am struggling with a simple but not obviously solvable issue. Suppose I have the following list of data.frames called 'tmp': a - data.frame(a=rnorm(10),b=letters[1:10]) (tmp - list(a,a[1:4,],a[1:7,])) It is known that all data.frames in this list have the same number of columns (and this is a good thing). I want to build a bigger data.frame consisting of all list-members, e.g. the result should look like: (res - rbind(tmp[[1]],tmp[[2]],tmp[[3]])) The question is how could I do this most efficiently? My real list consist of about 700 data.frames, each with with exactly 10 columns and plenty of rows. The obvious for-loop solution is rather time consuming and therefore I'm looking for something more efficient. Thank you in advance, AS. ps: 'sapply' should somehow do the trick, doesn't it? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] R: extract data.frames from a list
Right on target! Very appreciated. Thanks. Cheers, AS On Fri, Jul 17, 2009 at 4:39 PM, Henrique Dallazuanna www...@gmail.comwrote: do.call(rbind, tmp) On Fri, Jul 17, 2009 at 10:55 AM, Angel Spassov anspas...@googlemail.comwrote: Dear useRs and developeRs, I am struggling with a simple but not obviously solvable issue. Suppose I have the following list of data.frames called 'tmp': a - data.frame(a=rnorm(10),b=letters[1:10]) (tmp - list(a,a[1:4,],a[1:7,])) It is known that all data.frames in this list have the same number of columns (and this is a good thing). I want to build a bigger data.frame consisting of all list-members, e.g. the result should look like: (res - rbind(tmp[[1]],tmp[[2]],tmp[[3]])) The question is how could I do this most efficiently? My real list consist of about 700 data.frames, each with with exactly 10 columns and plenty of rows. The obvious for-loop solution is rather time consuming and therefore I'm looking for something more efficient. Thank you in advance, AS. ps: 'sapply' should somehow do the trick, doesn't it? [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40 S 49° 16' 22 O [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
