Re: [R] R vs SPSS contrasts

2008-10-12 Thread Chuck Cleland
On 10/11/2008 3:31 PM, Ted Harding wrote:
 Hi Folks,
 
 I'm comparing some output from R with output from SPSS.
 The coefficients of the independent variables (which are
 all factors, each at 2 levels) are identical.
 
 However, R's Intercept (using default contr.treatment)
 differs from SPSS's 'constant'. It seems that the contrasts
 were set in SPSS using
 
   /CONTRAST (varname)=Simple(1)
 
 I can get R's Intercept to match SPSS's 'constant' if I use
 contr.sum in R.
 
 Can someone please confirm that that is a correct match for
 the SPSS Simple(1), with identical effect?
 
 And is there a convenient on-line reference where I can look
 up what SPSS's /CONTRAST statements exactly mean?
 I've done a lot of googling, withbout coming up with anything
 satisfactory.
 
 With thanks,
 Ted.

Hi Ted:
  Here are two links with the same content giving a brief description of
SPSS simple contrasts:

http://www.ats.ucla.edu/stat/spss/library/contrast.htm
http://support.spss.com/productsext/spss/documentation/statistics/articles/contrast.htm

  These pages explain how simple contrasts differ from indicator
(contr.treatment) and deviation (contr.sum) contrasts.  For a factor
with 3 levels, I believe you can reproduce SPSS simple contrasts (with
the first category as reference) like this:

 C(warpbreaks$tension, contr=matrix(c(-1/3,2/3,-1/3,-1/3,-1/3,2/3),
ncol=2))
...
attr(,contrasts)
[,1]   [,2]
L -0.333 -0.333
M  0.667 -0.333
H -0.333  0.667
Levels: L M H

  For a factor with 2 levels, like this:

 C(warpbreaks$wool, contr=matrix(c(-1/2,1/2), ncol=1))
...
attr(,contrasts)
  [,1]
A -0.5
B  0.5
Levels: A B

  Your description of the effect of SPSS simple contrasts - intercept
coefficient of contr.sum and non-intercept coefficients of
contr.treatment - sounds accurate to me.

hope this helps,

Chuck

 
 E-Mail: (Ted Harding) [EMAIL PROTECTED]
 Fax-to-email: +44 (0)870 094 0861
 Date: 11-Oct-08   Time: 20:31:53
 -- XFMail --
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code. 

-- 
Chuck Cleland, Ph.D.
NDRI, Inc. (www.ndri.org)
71 West 23rd Street, 8th floor
New York, NY 10010
tel: (212) 845-4495 (Tu, Th)
tel: (732) 512-0171 (M, W, F)
fax: (917) 438-0894

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] R vs SPSS contrasts

2008-10-12 Thread Gabor Grothendieck
Looks like the contrast matrix for indicator is contr.SAS(n),
for deviation is contr.sum(n) and for simple is:

(diag(n) - 1/n)[, -1]

That works at least for the n = 3 example in the link.
Perhaps the others could be checked against SPSS
for a variety of values of n to be sure.

On Sun, Oct 12, 2008 at 12:32 PM, Chuck Cleland [EMAIL PROTECTED] wrote:
 On 10/11/2008 3:31 PM, Ted Harding wrote:
 Hi Folks,

 I'm comparing some output from R with output from SPSS.
 The coefficients of the independent variables (which are
 all factors, each at 2 levels) are identical.

 However, R's Intercept (using default contr.treatment)
 differs from SPSS's 'constant'. It seems that the contrasts
 were set in SPSS using

   /CONTRAST (varname)=Simple(1)

 I can get R's Intercept to match SPSS's 'constant' if I use
 contr.sum in R.

 Can someone please confirm that that is a correct match for
 the SPSS Simple(1), with identical effect?

 And is there a convenient on-line reference where I can look
 up what SPSS's /CONTRAST statements exactly mean?
 I've done a lot of googling, withbout coming up with anything
 satisfactory.

 With thanks,
 Ted.

 Hi Ted:
  Here are two links with the same content giving a brief description of
 SPSS simple contrasts:

 http://www.ats.ucla.edu/stat/spss/library/contrast.htm
 http://support.spss.com/productsext/spss/documentation/statistics/articles/contrast.htm

  These pages explain how simple contrasts differ from indicator
 (contr.treatment) and deviation (contr.sum) contrasts.  For a factor
 with 3 levels, I believe you can reproduce SPSS simple contrasts (with
 the first category as reference) like this:

 C(warpbreaks$tension, contr=matrix(c(-1/3,2/3,-1/3,-1/3,-1/3,2/3),
 ncol=2))
 ...
 attr(,contrasts)
[,1]   [,2]
 L -0.333 -0.333
 M  0.667 -0.333
 H -0.333  0.667
 Levels: L M H

  For a factor with 2 levels, like this:

 C(warpbreaks$wool, contr=matrix(c(-1/2,1/2), ncol=1))
 ...
 attr(,contrasts)
  [,1]
 A -0.5
 B  0.5
 Levels: A B

  Your description of the effect of SPSS simple contrasts - intercept
 coefficient of contr.sum and non-intercept coefficients of
 contr.treatment - sounds accurate to me.

 hope this helps,

 Chuck

 
 E-Mail: (Ted Harding) [EMAIL PROTECTED]
 Fax-to-email: +44 (0)870 094 0861
 Date: 11-Oct-08   Time: 20:31:53
 -- XFMail --

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

 --
 Chuck Cleland, Ph.D.
 NDRI, Inc. (www.ndri.org)
 71 West 23rd Street, 8th floor
 New York, NY 10010
 tel: (212) 845-4495 (Tu, Th)
 tel: (732) 512-0171 (M, W, F)
 fax: (917) 438-0894

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] R vs SPSS contrasts

2008-10-12 Thread Gabor Grothendieck
The formula should be (diag(n) - 1/n)[, -n]

On Sun, Oct 12, 2008 at 1:36 PM, Gabor Grothendieck
[EMAIL PROTECTED] wrote:
 Looks like the contrast matrix for indicator is contr.SAS(n),
 for deviation is contr.sum(n) and for simple is:

 (diag(n) - 1/n)[, -1]

 That works at least for the n = 3 example in the link.
 Perhaps the others could be checked against SPSS
 for a variety of values of n to be sure.

 On Sun, Oct 12, 2008 at 12:32 PM, Chuck Cleland [EMAIL PROTECTED] wrote:
 On 10/11/2008 3:31 PM, Ted Harding wrote:
 Hi Folks,

 I'm comparing some output from R with output from SPSS.
 The coefficients of the independent variables (which are
 all factors, each at 2 levels) are identical.

 However, R's Intercept (using default contr.treatment)
 differs from SPSS's 'constant'. It seems that the contrasts
 were set in SPSS using

   /CONTRAST (varname)=Simple(1)

 I can get R's Intercept to match SPSS's 'constant' if I use
 contr.sum in R.

 Can someone please confirm that that is a correct match for
 the SPSS Simple(1), with identical effect?

 And is there a convenient on-line reference where I can look
 up what SPSS's /CONTRAST statements exactly mean?
 I've done a lot of googling, withbout coming up with anything
 satisfactory.

 With thanks,
 Ted.

 Hi Ted:
  Here are two links with the same content giving a brief description of
 SPSS simple contrasts:

 http://www.ats.ucla.edu/stat/spss/library/contrast.htm
 http://support.spss.com/productsext/spss/documentation/statistics/articles/contrast.htm

  These pages explain how simple contrasts differ from indicator
 (contr.treatment) and deviation (contr.sum) contrasts.  For a factor
 with 3 levels, I believe you can reproduce SPSS simple contrasts (with
 the first category as reference) like this:

 C(warpbreaks$tension, contr=matrix(c(-1/3,2/3,-1/3,-1/3,-1/3,2/3),
 ncol=2))
 ...
 attr(,contrasts)
[,1]   [,2]
 L -0.333 -0.333
 M  0.667 -0.333
 H -0.333  0.667
 Levels: L M H

  For a factor with 2 levels, like this:

 C(warpbreaks$wool, contr=matrix(c(-1/2,1/2), ncol=1))
 ...
 attr(,contrasts)
  [,1]
 A -0.5
 B  0.5
 Levels: A B

  Your description of the effect of SPSS simple contrasts - intercept
 coefficient of contr.sum and non-intercept coefficients of
 contr.treatment - sounds accurate to me.

 hope this helps,

 Chuck

 
 E-Mail: (Ted Harding) [EMAIL PROTECTED]
 Fax-to-email: +44 (0)870 094 0861
 Date: 11-Oct-08   Time: 20:31:53
 -- XFMail --

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

 --
 Chuck Cleland, Ph.D.
 NDRI, Inc. (www.ndri.org)
 71 West 23rd Street, 8th floor
 New York, NY 10010
 tel: (212) 845-4495 (Tu, Th)
 tel: (732) 512-0171 (M, W, F)
 fax: (917) 438-0894

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.



__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] R vs SPSS contrasts

2008-10-12 Thread Gabor Grothendieck
I found this link:

http://webs.edinboro.edu/EDocs/SPSS/SPSS%20Regression%20Models%2013.0.pdf

which indicates that the contrast in SPSS that is used
depends not only on the contrast selected but also on the
reference category selected and the two can be chosen
independently.  Thus one could have simple/first, simple/last,
deviation/first, deviation/last, etc.  An R contr.SPSS function
would have to specify both the deviation type and the
first/last in order to handle all SPSS variations.

On Sun, Oct 12, 2008 at 1:48 PM, Gabor Grothendieck
[EMAIL PROTECTED] wrote:
 The formula should be (diag(n) - 1/n)[, -n]

 On Sun, Oct 12, 2008 at 1:36 PM, Gabor Grothendieck
 [EMAIL PROTECTED] wrote:
 Looks like the contrast matrix for indicator is contr.SAS(n),
 for deviation is contr.sum(n) and for simple is:

 (diag(n) - 1/n)[, -1]

 That works at least for the n = 3 example in the link.
 Perhaps the others could be checked against SPSS
 for a variety of values of n to be sure.

 On Sun, Oct 12, 2008 at 12:32 PM, Chuck Cleland [EMAIL PROTECTED] wrote:
 On 10/11/2008 3:31 PM, Ted Harding wrote:
 Hi Folks,

 I'm comparing some output from R with output from SPSS.
 The coefficients of the independent variables (which are
 all factors, each at 2 levels) are identical.

 However, R's Intercept (using default contr.treatment)
 differs from SPSS's 'constant'. It seems that the contrasts
 were set in SPSS using

   /CONTRAST (varname)=Simple(1)

 I can get R's Intercept to match SPSS's 'constant' if I use
 contr.sum in R.

 Can someone please confirm that that is a correct match for
 the SPSS Simple(1), with identical effect?

 And is there a convenient on-line reference where I can look
 up what SPSS's /CONTRAST statements exactly mean?
 I've done a lot of googling, withbout coming up with anything
 satisfactory.

 With thanks,
 Ted.

 Hi Ted:
  Here are two links with the same content giving a brief description of
 SPSS simple contrasts:

 http://www.ats.ucla.edu/stat/spss/library/contrast.htm
 http://support.spss.com/productsext/spss/documentation/statistics/articles/contrast.htm

  These pages explain how simple contrasts differ from indicator
 (contr.treatment) and deviation (contr.sum) contrasts.  For a factor
 with 3 levels, I believe you can reproduce SPSS simple contrasts (with
 the first category as reference) like this:

 C(warpbreaks$tension, contr=matrix(c(-1/3,2/3,-1/3,-1/3,-1/3,2/3),
 ncol=2))
 ...
 attr(,contrasts)
[,1]   [,2]
 L -0.333 -0.333
 M  0.667 -0.333
 H -0.333  0.667
 Levels: L M H

  For a factor with 2 levels, like this:

 C(warpbreaks$wool, contr=matrix(c(-1/2,1/2), ncol=1))
 ...
 attr(,contrasts)
  [,1]
 A -0.5
 B  0.5
 Levels: A B

  Your description of the effect of SPSS simple contrasts - intercept
 coefficient of contr.sum and non-intercept coefficients of
 contr.treatment - sounds accurate to me.

 hope this helps,

 Chuck

 
 E-Mail: (Ted Harding) [EMAIL PROTECTED]
 Fax-to-email: +44 (0)870 094 0861
 Date: 11-Oct-08   Time: 20:31:53
 -- XFMail --

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide 
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

 --
 Chuck Cleland, Ph.D.
 NDRI, Inc. (www.ndri.org)
 71 West 23rd Street, 8th floor
 New York, NY 10010
 tel: (212) 845-4495 (Tu, Th)
 tel: (732) 512-0171 (M, W, F)
 fax: (917) 438-0894

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.




__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] R vs SPSS contrasts

2008-10-12 Thread Ted Harding
Very many thanks, Chuck and Gabor, for the comments and the
references to on-line explanations. It is beginning to become
clear!

Most grateful.
Ted.

On 12-Oct-08 18:03:53, Gabor Grothendieck wrote:
 I found this link:
 
 http://webs.edinboro.edu/EDocs/SPSS/SPSS%20Regression%20Models%2013.0.pd
 f
 
 which indicates that the contrast in SPSS that is used
 depends not only on the contrast selected but also on the
 reference category selected and the two can be chosen
 independently.  Thus one could have simple/first, simple/last,
 deviation/first, deviation/last, etc.  An R contr.SPSS function
 would have to specify both the deviation type and the
 first/last in order to handle all SPSS variations.
 
 On Sun, Oct 12, 2008 at 1:48 PM, Gabor Grothendieck
 [EMAIL PROTECTED] wrote:
 The formula should be (diag(n) - 1/n)[, -n]

 On Sun, Oct 12, 2008 at 1:36 PM, Gabor Grothendieck
 [EMAIL PROTECTED] wrote:
 Looks like the contrast matrix for indicator is contr.SAS(n),
 for deviation is contr.sum(n) and for simple is:

 (diag(n) - 1/n)[, -1]

 That works at least for the n = 3 example in the link.
 Perhaps the others could be checked against SPSS
 for a variety of values of n to be sure.

 On Sun, Oct 12, 2008 at 12:32 PM, Chuck Cleland
 [EMAIL PROTECTED] wrote:
 On 10/11/2008 3:31 PM, Ted Harding wrote:
 Hi Folks,

 I'm comparing some output from R with output from SPSS.
 The coefficients of the independent variables (which are
 all factors, each at 2 levels) are identical.

 However, R's Intercept (using default contr.treatment)
 differs from SPSS's 'constant'. It seems that the contrasts
 were set in SPSS using

   /CONTRAST (varname)=Simple(1)

 I can get R's Intercept to match SPSS's 'constant' if I use
 contr.sum in R.

 Can someone please confirm that that is a correct match for
 the SPSS Simple(1), with identical effect?

 And is there a convenient on-line reference where I can look
 up what SPSS's /CONTRAST statements exactly mean?
 I've done a lot of googling, withbout coming up with anything
 satisfactory.

 With thanks,
 Ted.

 Hi Ted:
  Here are two links with the same content giving a brief description
  of
 SPSS simple contrasts:

 http://www.ats.ucla.edu/stat/spss/library/contrast.htm
 http://support.spss.com/productsext/spss/documentation/statistics/art
 icles/contrast.htm

  These pages explain how simple contrasts differ from indicator
 (contr.treatment) and deviation (contr.sum) contrasts.  For a factor
 with 3 levels, I believe you can reproduce SPSS simple contrasts
 (with
 the first category as reference) like this:

 C(warpbreaks$tension, contr=matrix(c(-1/3,2/3,-1/3,-1/3,-1/3,2/3),
 ncol=2))
 ...
 attr(,contrasts)
[,1]   [,2]
 L -0.333 -0.333
 M  0.667 -0.333
 H -0.333  0.667
 Levels: L M H

  For a factor with 2 levels, like this:

 C(warpbreaks$wool, contr=matrix(c(-1/2,1/2), ncol=1))
 ...
 attr(,contrasts)
  [,1]
 A -0.5
 B  0.5
 Levels: A B

  Your description of the effect of SPSS simple contrasts - intercept
 coefficient of contr.sum and non-intercept coefficients of
 contr.treatment - sounds accurate to me.

 hope this helps,

 Chuck

 
 E-Mail: (Ted Harding) [EMAIL PROTECTED]
 Fax-to-email: +44 (0)870 094 0861
 Date: 11-Oct-08   Time:
 20:31:53
 -- XFMail
 --

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

 --
 Chuck Cleland, Ph.D.
 NDRI, Inc. (www.ndri.org)
 71 West 23rd Street, 8th floor
 New York, NY 10010
 tel: (212) 845-4495 (Tu, Th)
 tel: (732) 512-0171 (M, W, F)
 fax: (917) 438-0894

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.



 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


E-Mail: (Ted Harding) [EMAIL PROTECTED]
Fax-to-email: +44 (0)870 094 0861
Date: 12-Oct-08   Time: 21:04:48
-- XFMail --

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, 

Re: [R] R vs SPSS contrasts

2008-10-11 Thread Gabor Grothendieck
Don't know but perhaps you could just use each of:
contr.helmert, contr.poly, contr.sum, contr.treatment, contr.SAS
in turn on the R side until you get one that matches.  Once you
find out adding a contr.SPSS to R might be nice.

On Sat, Oct 11, 2008 at 3:31 PM, Ted Harding
[EMAIL PROTECTED] wrote:
 Hi Folks,

 I'm comparing some output from R with output from SPSS.
 The coefficients of the independent variables (which are
 all factors, each at 2 levels) are identical.

 However, R's Intercept (using default contr.treatment)
 differs from SPSS's 'constant'. It seems that the contrasts
 were set in SPSS using

  /CONTRAST (varname)=Simple(1)

 I can get R's Intercept to match SPSS's 'constant' if I use
 contr.sum in R.

 Can someone please confirm that that is a correct match for
 the SPSS Simple(1), with identical effect?

 And is there a convenient on-line reference where I can look
 up what SPSS's /CONTRAST statements exactly mean?
 I've done a lot of googling, withbout coming up with anything
 satisfactory.

 With thanks,
 Ted.

 
 E-Mail: (Ted Harding) [EMAIL PROTECTED]
 Fax-to-email: +44 (0)870 094 0861
 Date: 11-Oct-08   Time: 20:31:53
 -- XFMail --

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.


__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.