Re: [R] Summary statistics for matrix columns

2012-11-24 Thread frespider


HI A.k,

I need one more question, if you can answer it please

M - matrix(sample(1:8000),nrow=100)
colnames(M)- paste(Col,1:ncol(M),sep=)
apply(M,2,function(x) c(Min=min(x),1st Qu =quantile(x, 0.25,names=FALSE),
Range = range(x),
Median = quantile(x, 0.5, names=FALSE),
Mean= mean(x),Std=sd(x),
3rd Qu = quantile(x,0.75,names=FALSE),
IQR=IQR(x),Max = max(x)))

why I get two range . isn't range mean the different between the max and min


Thanks 
Date: Fri, 23 Nov 2012 16:08:12 -0800
From: ml-node+s789695n4650613...@n4.nabble.com
To: frespi...@hotmail.com
Subject: Re: Summary statistics for matrix columns



Hi,

No problem.


There are a couple of other libraries which deal with summary statistics:

library(pastecs)

?stat.desc() # 


library(matrixStats) 

#Using the functions from package: matrixStats

fun1-function(x){

res-rbind(colMins(x),colQuantiles(x)[,2],colMedians(x),colMeans(x),colSds(x),colQuantiles(x)[,4],colIQRs(x),colMaxs(x))

row.names(res)-c(Min.,1st Qu.,Median,Mean,sd,3rd Qu.,IQR,Max.)

res}


set.seed(125)

x - matrix(sample(1:80),nrow=8)

colnames(x)- paste(Col,1:ncol(x),sep=)  

fun1(x)

#Col1 Col2 Col3 Col4 Col5 Col6 Col7 Col8

#Min.10.0  1.0 17.0  3.0 18.0 11.0 13.0 15.0

#1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5 34.75000

#Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5 51.5

#Mean42.5 42.75000 41.75000 35.75000 44.87500 26.87500 44.75000 50.12500

#sd  25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239 25.51995

#3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000 70.5

#IQR 43.0 29.0 24.0 55.5 14.25000 13.0 28.75000 35.75000

#Max.74.0 77.0 76.0 70.0 65.0 63.0 79.0 80.0

 #   Col9Col10

#Min. 2.0  6.0

#1st Qu. 24.5 12.5

#Median  33.5 48.0

#Mean34.87500 40.75000

#sd  24.39811 28.21727

#3rd Qu. 45.25000 63.0

#IQR 20.75000 50.5

#Max.71.0 72.0


I thought this could be faster than the previous methods.  But, it was the 
slowest.


set.seed(125)

x1 - matrix(sample(1:80),nrow=1000)

colnames(x)- paste(Col,1:ncol(x1),sep=)


system.time(fun1(x1))

#   user  system elapsed 

 # 0.968   0.000   0.956 

A.K.











From: Fares Said [hidden email]

To: arun [hidden email] 

Cc: Pete Brecknock [hidden email]; R help [hidden email] 

Sent: Friday, November 23, 2012 10:23 AM

Subject: Re: [R] Summary statistics for matrix columns


Thank you all 


Sent from my iPhone


On 2012-11-23, at 10:19, arun [hidden email] wrote:


 HI,

 You are right.

 It is slower when compared to Pete's solution:

 set.seed(125)

 x - matrix(sample(1:80),nrow=1000)

 colnames(x)- paste(Col,1:ncol(x),sep=)

 

 system.time({

 res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))

  res1-as.matrix(res) 

 res2-res1[c(1:4,7,5,8,6),] })

 # user  system elapsed 

 #  0.596   0.000   0.597 

 

 system.time({

 res-apply(x,2,function(x) c(Min=min(x),

 1st Qu =quantile(x, 0.25,names=FALSE),

 Median = quantile(x, 0.5, names=FALSE),

 Mean= mean(x),

 Sd=sd(x),

 3rd Qu = quantile(x,0.75,names=FALSE),

 IQR=IQR(x),

 Max = max(x))) })

 # user  system elapsed 

  # 0.384   0.000   0.384 

 

 

 A.K.

 

 

 

 - Original Message -

 From: Pete Brecknock [hidden email]

 To: [hidden email]

 Cc: 

 Sent: Friday, November 23, 2012 8:42 AM

 Subject: Re: [R] Summary statistics for matrix columns

 

 frespider wrote

 Hi,

 

 it is possible. but don't you think it will slow the code if you convert

 to data.frame?

 

 Thanks 

 

 Date: Thu, 22 Nov 2012 18:31:35 -0800

 From:

 

 ml-node+s789695n4650500h51@.nabble

 

 To:

 

 frespider@

 

 Subject: RE: Summary statistics for matrix columns

 

 

 

 HI,

 

 Is it possible to use as.matrix()?

 

 res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))

 

   res1-as.matrix(res)

 

   is.matrix(res1)

 

 #[1] TRUE

 

 res1[c(1:4,7,5,8,6),]

 

 #Col1 Col2 Col3 Col4 Col5 Col6 Col7

 Col8

 

 #Min.10.0  1.0 17.0  3.0 18.0 11.0 13.0

 15.0

 

 #1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5

 34.75000

 

 #Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5

 51.5

 

 #Mean42.5 42.75000 41.75000 35.75000 44.88000 26.88000 44.75000

 50.12000

 

 #sd  25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239

 25.51995

 

 #3rd

Re: [R] Summary statistics for matrix columns

2012-11-24 Thread William Dunlap
 isn't range mean the different between the max and min

That is one meaning of range.  There are many.  To see what R's definition is 
type
   ? range
or
   help(range)

Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com

 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On 
 Behalf
 Of frespider
 Sent: Saturday, November 24, 2012 4:58 AM
 To: r-help@r-project.org
 Subject: Re: [R] Summary statistics for matrix columns
 
 
 
 HI A.k,
 
 I need one more question, if you can answer it please
 
 M - matrix(sample(1:8000),nrow=100)
 colnames(M)- paste(Col,1:ncol(M),sep=)
 apply(M,2,function(x) c(Min=min(x),1st Qu =quantile(x, 0.25,names=FALSE),
 Range = range(x),
 Median = quantile(x, 0.5, names=FALSE),
 Mean= mean(x),Std=sd(x),
 3rd Qu = quantile(x,0.75,names=FALSE),
 IQR=IQR(x),Max = max(x)))
 
 why I get two range . isn't range mean the different between the max and min
 
 
 Thanks
 Date: Fri, 23 Nov 2012 16:08:12 -0800
 From: ml-node+s789695n4650613...@n4.nabble.com
 To: frespi...@hotmail.com
 Subject: Re: Summary statistics for matrix columns
 
 
 
   Hi,
 
 No problem.
 
 
 There are a couple of other libraries which deal with summary statistics:
 
 library(pastecs)
 
 ?stat.desc() #
 
 
 library(matrixStats)
 
 #Using the functions from package: matrixStats
 
 fun1-function(x){
 
 res-
 rbind(colMins(x),colQuantiles(x)[,2],colMedians(x),colMeans(x),colSds(x),colQuantiles(x)[
 ,4],colIQRs(x),colMaxs(x))
 
 row.names(res)-c(Min.,1st Qu.,Median,Mean,sd,3rd 
 Qu.,IQR,Max.)
 
 res}
 
 
 set.seed(125)
 
 x - matrix(sample(1:80),nrow=8)
 
 colnames(x)- paste(Col,1:ncol(x),sep=)
 
 fun1(x)
 
 #Col1 Col2 Col3 Col4 Col5 Col6 Col7 
 Col8
 
 #Min.10.0  1.0 17.0  3.0 18.0 11.0 13.0 
 15.0
 
 #1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5 
 34.75000
 
 #Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5 
 51.5
 
 #Mean42.5 42.75000 41.75000 35.75000 44.87500 26.87500 44.75000 
 50.12500
 
 #sd  25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239 
 25.51995
 
 #3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000 
 70.5
 
 #IQR 43.0 29.0 24.0 55.5 14.25000 13.0 28.75000 
 35.75000
 
 #Max.74.0 77.0 76.0 70.0 65.0 63.0 79.0 
 80.0
 
  #   Col9Col10
 
 #Min. 2.0  6.0
 
 #1st Qu. 24.5 12.5
 
 #Median  33.5 48.0
 
 #Mean34.87500 40.75000
 
 #sd  24.39811 28.21727
 
 #3rd Qu. 45.25000 63.0
 
 #IQR 20.75000 50.5
 
 #Max.71.0 72.0
 
 
 I thought this could be faster than the previous methods.  But, it was the 
 slowest.
 
 
 set.seed(125)
 
 x1 - matrix(sample(1:80),nrow=1000)
 
 colnames(x)- paste(Col,1:ncol(x1),sep=)
 
 
 system.time(fun1(x1))
 
 #   user  system elapsed
 
  # 0.968   0.000   0.956
 
 A.K.
 
 
 
 
 
 
 
 
 
 
 
 From: Fares Said [hidden email]
 
 To: arun [hidden email]
 
 Cc: Pete Brecknock [hidden email]; R help [hidden email]
 
 Sent: Friday, November 23, 2012 10:23 AM
 
 Subject: Re: [R] Summary statistics for matrix columns
 
 
 Thank you all
 
 
 Sent from my iPhone
 
 
 On 2012-11-23, at 10:19, arun [hidden email] wrote:
 
 
  HI,
 
  You are right.
 
  It is slower when compared to Pete's solution:
 
  set.seed(125)
 
  x - matrix(sample(1:80),nrow=1000)
 
  colnames(x)- paste(Col,1:ncol(x),sep=)
 
 
 
  system.time({
 
  res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))
 
   res1-as.matrix(res)
 
  res2-res1[c(1:4,7,5,8,6),] })
 
  # user  system elapsed
 
  #  0.596   0.000   0.597
 
 
 
  system.time({
 
  res-apply(x,2,function(x) c(Min=min(x),
 
  1st Qu =quantile(x, 0.25,names=FALSE),
 
  Median = quantile(x, 0.5, names=FALSE),
 
  Mean= mean(x),
 
  Sd=sd(x),
 
  3rd Qu = quantile(x,0.75,names=FALSE),
 
  IQR=IQR(x),
 
  Max = max(x))) })
 
  # user  system elapsed
 
   # 0.384   0.000   0.384
 
 
 
 
 
  A.K.
 
 
 
 
 
 
 
  - Original Message -
 
  From: Pete Brecknock [hidden email]
 
  To: [hidden email]
 
  Cc:
 
  Sent: Friday, November 23, 2012 8:42 AM
 
  Subject: Re: [R] Summary statistics for matrix columns
 
 
 
  frespider wrote
 
  Hi,
 
 
 
  it is possible. but don't you think it will slow the code if you convert
 
  to data.frame?
 
 
 
  Thanks
 
 
 
  Date: Thu, 22 Nov 2012 18:31:35 -0800
 
  From:
 
 
 
  ml-node+s789695n4650500h51@.nabble
 
 
 
  To:
 
 
 
  frespider@
 
 
 
  Subject: RE: Summary statistics for matrix columns
 
 
 
 
 
 
 
  HI

Re: [R] Summary statistics for matrix columns

2012-11-24 Thread arun
Hi, 

You are right.  Range is supposed to be one value (i.e the 
difference between largest and smallest).  For some reason, the function
 range(x) gives both the values. 
The description for ?range() is: 
Description: 

     ‘range’ returns a vector containing the minimum and maximum of all 
     the given arguments. 
 
I looked for similar function in library(matrixStats) .  There it was 
colRanges(), rowRanges(). 
 set.seed(125) 
 x - matrix(sample(1:80),nrow=8) 
 colnames(x)- paste(Col,1:ncol(x),sep=)   
apply(x,2,function(x) range(x)) 
#     Col1 Col2 Col3 Col4 Col5 Col6 Col7 Col8 Col9 Col10 
#[1,]   10    1   17    3   18   11   13   15    2     6 
#[2,]   74   77   76   70   65   63   79   80   71    72 
library(matrixStats) 
colRanges(x) 
   #   [,1] [,2] 
 #[1,]   10   74 
 #[2,]    1   77 
 #[3,]   17   76 
 - 
You could do this to get the range: 
 apply(x,2,function(x) diff(range(x))) 
 #Col1  Col2  Col3  Col4  Col5  Col6  Col7  Col8  Col9 Col10 
  # 64    76    59    67    47    52    66    65    69    66 
#or i 
 diff(t(colRanges(x))) 
#     [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] 
#[1,]   64   76   59   67   47   52   66   65   69    66 
#or 
rowDiffs(colRanges(x)) 
A.K. 



- Original Message -
From: frespider frespi...@hotmail.com
To: r-help@r-project.org
Cc: 
Sent: Saturday, November 24, 2012 7:58 AM
Subject: Re: [R] Summary statistics for matrix columns



HI A.k,

I need one more question, if you can answer it please

M - matrix(sample(1:8000),nrow=100)
colnames(M)- paste(Col,1:ncol(M),sep=)
apply(M,2,function(x) c(Min=min(x),1st Qu =quantile(x, 0.25,names=FALSE),
                        Range = range(x),
                        Median = quantile(x, 0.5, names=FALSE),
                        Mean= mean(x),Std=sd(x),
                        3rd Qu = quantile(x,0.75,names=FALSE),
                        IQR=IQR(x),Max = max(x)))

why I get two range . isn't range mean the different between the max and min


Thanks 
Date: Fri, 23 Nov 2012 16:08:12 -0800
From: ml-node+s789695n4650613...@n4.nabble.com
To: frespi...@hotmail.com
Subject: Re: Summary statistics for matrix columns



    Hi,

No problem.


There are a couple of other libraries which deal with summary statistics:

library(pastecs)

?stat.desc() # 


library(matrixStats) 

#Using the functions from package: matrixStats

fun1-function(x){

res-rbind(colMins(x),colQuantiles(x)[,2],colMedians(x),colMeans(x),colSds(x),colQuantiles(x)[,4],colIQRs(x),colMaxs(x))

row.names(res)-c(Min.,1st Qu.,Median,Mean,sd,3rd Qu.,IQR,Max.)

res}


set.seed(125)

x - matrix(sample(1:80),nrow=8)

colnames(x)- paste(Col,1:ncol(x),sep=)  

fun1(x)

#            Col1     Col2     Col3     Col4     Col5     Col6     Col7     Col8

#Min.    10.0  1.0 17.0  3.0 18.0 11.0 13.0 15.0

#1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5 34.75000

#Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5 51.5

#Mean    42.5 42.75000 41.75000 35.75000 44.87500 26.87500 44.75000 50.12500

#sd      25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239 25.51995

#3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000 70.5

#IQR     43.0 29.0 24.0 55.5 14.25000 13.0 28.75000 35.75000

#Max.    74.0 77.0 76.0 70.0 65.0 63.0 79.0 80.0

#           Col9    Col10

#Min.     2.0  6.0

#1st Qu. 24.5 12.5

#Median  33.5 48.0

#Mean    34.87500 40.75000

#sd      24.39811 28.21727

#3rd Qu. 45.25000 63.0

#IQR     20.75000 50.5

#Max.    71.0 72.0


I thought this could be faster than the previous methods.  But, it was the 
slowest.


set.seed(125)

x1 - matrix(sample(1:80),nrow=1000)

colnames(x)- paste(Col,1:ncol(x1),sep=)


system.time(fun1(x1))

#   user  system elapsed 

# 0.968   0.000   0.956 

A.K.











From: Fares Said [hidden email]

To: arun [hidden email] 

Cc: Pete Brecknock [hidden email]; R help [hidden email] 

Sent: Friday, November 23, 2012 10:23 AM

Subject: Re: [R] Summary statistics for matrix columns


Thank you all 


Sent from my iPhone


On 2012-11-23, at 10:19, arun [hidden email] wrote:


 HI,

 You are right.

 It is slower when compared to Pete's solution:

 set.seed(125)

 x - matrix(sample(1:80),nrow=1000)

 colnames(x)- paste(Col,1:ncol(x),sep=)

 

 system.time({

 res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))

  res1-as.matrix(res) 

 res2-res1[c(1:4,7,5,8,6),] })

 # user  system elapsed 

 #  0.596   0.000   0.597 

 

 system.time({

 res-apply(x,2,function(x) c(Min=min(x),

                         1st Qu =quantile(x, 0.25,names=FALSE),

                         Median = quantile(x, 0.5, names=FALSE),

                         Mean= mean(x),

                         Sd=sd(x),

                         3rd Qu = quantile(x,0.75,names=FALSE

Re: [R] Summary statistics for matrix columns

2012-11-24 Thread David Winsemius


On Nov 24, 2012, at 4:58 AM, frespider wrote:




HI A.k,

I need one more question, if you can answer it please

M - matrix(sample(1:8000),nrow=100)
colnames(M)- paste(Col,1:ncol(M),sep=)
apply(M,2,function(x) c(Min=min(x),1st Qu =quantile(x,  
0.25,names=FALSE),

   Range = range(x),
   Median = quantile(x, 0.5, names=FALSE),
   Mean= mean(x),Std=sd(x),
   3rd Qu = quantile(x,0.75,names=FALSE),
   IQR=IQR(x),Max = max(x)))

why I get two range . isn't range mean the different between the max  
and min


If you want the span (what you are calling the range) of the range  
(min and max) you can do this:


myRange = diff(range(x))

--
David






David Winsemius, MD
Alameda, CA, USA

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Summary statistics for matrix columns

2012-11-23 Thread Pete Brecknock
frespider wrote
 Hi,
 
 it is possible. but don't you think it will slow the code if you convert
 to data.frame?
 
 Thanks 
 
 Date: Thu, 22 Nov 2012 18:31:35 -0800
 From: 

 ml-node+s789695n4650500h51@.nabble

 To: 

 frespider@

 Subject: RE: Summary statistics for matrix columns
 
 
 
   HI,
 
 Is it possible to use as.matrix()?
 
 res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))
 
  res1-as.matrix(res)
 
  is.matrix(res1)
 
 #[1] TRUE
 
 res1[c(1:4,7,5,8,6),]
 
 #Col1 Col2 Col3 Col4 Col5 Col6 Col7
 Col8
 
 #Min.10.0  1.0 17.0  3.0 18.0 11.0 13.0
 15.0
 
 #1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5
 34.75000
 
 #Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5
 51.5
 
 #Mean42.5 42.75000 41.75000 35.75000 44.88000 26.88000 44.75000
 50.12000
 
 #sd  25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239
 25.51995
 
 #3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000
 70.5
 
 #IQR 43.0 29.0 24.0 55.5 14.25000 13.0 28.75000
 35.75000
 
 #Max.74.0 77.0 76.0 70.0 65.0 63.0 79.0
 80.0
 
   #  Col9Col10
 
 #Min. 2.0  6.0
 
 #1st Qu. 24.5 12.5
 
 #Median  33.5 48.0
 
 #Mean34.88000 40.75000
 
 #sd  24.39811 28.21727
 
 #3rd Qu. 45.25000 63.0
 
 #IQR 20.75000 50.5
 
 #Max.71.0 72.0
 
 Solves the order and the matrix output!
 
 A.K.
 
 
 
 
 
   
   
   
   
 
   
 
   
   
   If you reply to this email, your message will be added to the 
 discussion
 below:
   
 http://r.789695.n4.nabble.com/Summary-statistics-for-matrix-columns-tp4650489p4650500.html
   
   
   
   To unsubscribe from Summary statistics for matrix columns, 
 click here.
 
   NAML

Then maybe 

x - matrix(sample(1:8000),nrow=100) 
colnames(x)- paste(Col,1:ncol(x),sep=) 

apply(x,2,function(x) c(Min=min(x), 
1st Qu =quantile(x, 0.25,names=FALSE), 
Median = quantile(x, 0.5, names=FALSE),
Mean= mean(x),
Sd=sd(x), 
3rd Qu = quantile(x,0.75,names=FALSE),
IQR=IQR(x),
Max = max(x)))

HTH

Pete



--
View this message in context: 
http://r.789695.n4.nabble.com/Summary-statistics-for-matrix-columns-tp4650489p4650547.html
Sent from the R help mailing list archive at Nabble.com.

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Summary statistics for matrix columns

2012-11-23 Thread Fares Said
Thank you all 

Sent from my iPhone

On 2012-11-23, at 10:19, arun smartpink...@yahoo.com wrote:

 HI,
 You are right.
 It is slower when compared to Pete's solution:
 set.seed(125)
 x - matrix(sample(1:80),nrow=1000)
 colnames(x)- paste(Col,1:ncol(x),sep=)
 
 system.time({
 res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))
  res1-as.matrix(res) 
 res2-res1[c(1:4,7,5,8,6),] })
 # user  system elapsed 
 #  0.596   0.000   0.597 
 
 system.time({
 res-apply(x,2,function(x) c(Min=min(x),
 1st Qu =quantile(x, 0.25,names=FALSE),
 Median = quantile(x, 0.5, names=FALSE),
 Mean= mean(x),
 Sd=sd(x),
 3rd Qu = quantile(x,0.75,names=FALSE),
 IQR=IQR(x),
 Max = max(x))) })
 # user  system elapsed 
  # 0.384   0.000   0.384 
 
 
 A.K.
 
 
 
 - Original Message -
 From: Pete Brecknock peter.breckn...@bp.com
 To: r-help@r-project.org
 Cc: 
 Sent: Friday, November 23, 2012 8:42 AM
 Subject: Re: [R] Summary statistics for matrix columns
 
 frespider wrote
 Hi,
 
 it is possible. but don't you think it will slow the code if you convert
 to data.frame?
 
 Thanks 
 
 Date: Thu, 22 Nov 2012 18:31:35 -0800
 From:
 
 ml-node+s789695n4650500h51@.nabble
 
 To:
 
 frespider@
 
 Subject: RE: Summary statistics for matrix columns
 
 
 
 HI,
 
 Is it possible to use as.matrix()?
 
 res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))
 
   res1-as.matrix(res)
 
   is.matrix(res1)
 
 #[1] TRUE
 
 res1[c(1:4,7,5,8,6),]
 
 #Col1 Col2 Col3 Col4 Col5 Col6 Col7
 Col8
 
 #Min.10.0  1.0 17.0  3.0 18.0 11.0 13.0
 15.0
 
 #1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5
 34.75000
 
 #Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5
 51.5
 
 #Mean42.5 42.75000 41.75000 35.75000 44.88000 26.88000 44.75000
 50.12000
 
 #sd  25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239
 25.51995
 
 #3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000
 70.5
 
 #IQR 43.0 29.0 24.0 55.5 14.25000 13.0 28.75000
 35.75000
 
 #Max.74.0 77.0 76.0 70.0 65.0 63.0 79.0
 80.0
 
#  Col9Col10
 
 #Min. 2.0  6.0
 
 #1st Qu. 24.5 12.5
 
 #Median  33.5 48.0
 
 #Mean34.88000 40.75000
 
 #sd  24.39811 28.21727
 
 #3rd Qu. 45.25000 63.0
 
 #IQR 20.75000 50.5
 
 #Max.71.0 72.0
 
 Solves the order and the matrix output!
 
 A.K.
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 If you reply to this email, your message will be added to the 
 discussion
 below:
 
 http://r.789695.n4.nabble.com/Summary-statistics-for-matrix-columns-tp4650489p4650500.html
 
 
 
 To unsubscribe from Summary statistics for matrix columns, click 
 here.
 
 NAML
 
 Then maybe 
 
 x - matrix(sample(1:8000),nrow=100) 
 colnames(x)- paste(Col,1:ncol(x),sep=) 
 
 apply(x,2,function(x) c(Min=min(x), 
 1st Qu =quantile(x, 0.25,names=FALSE), 
 Median = quantile(x, 0.5, names=FALSE),
 Mean= mean(x),
 Sd=sd(x), 
 3rd Qu = quantile(x,0.75,names=FALSE),
 IQR=IQR(x),
 Max = max(x)))
 
 HTH
 
 Pete
 
 
 
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 View this message in context: 
 http://r.789695.n4.nabble.com/Summary-statistics-for-matrix-columns-tp4650489p4650547.html
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Re: [R] Summary statistics for matrix columns

2012-11-23 Thread arun
HI,
You are right.
It is slower when compared to Pete's solution:
set.seed(125)
x - matrix(sample(1:80),nrow=1000)
colnames(x)- paste(Col,1:ncol(x),sep=)

system.time({
res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))
 res1-as.matrix(res) 
res2-res1[c(1:4,7,5,8,6),] })
# user  system elapsed 
#  0.596   0.000   0.597 

system.time({
res-apply(x,2,function(x) c(Min=min(x),
    1st Qu =quantile(x, 0.25,names=FALSE),
    Median = quantile(x, 0.5, names=FALSE),
    Mean= mean(x),
    Sd=sd(x),
    3rd Qu = quantile(x,0.75,names=FALSE),
    IQR=IQR(x),
    Max = max(x))) })
# user  system elapsed 
 # 0.384   0.000   0.384 


A.K.



- Original Message -
From: Pete Brecknock peter.breckn...@bp.com
To: r-help@r-project.org
Cc: 
Sent: Friday, November 23, 2012 8:42 AM
Subject: Re: [R] Summary statistics for matrix columns

frespider wrote
 Hi,
 
 it is possible. but don't you think it will slow the code if you convert
 to data.frame?
 
 Thanks 
 
 Date: Thu, 22 Nov 2012 18:31:35 -0800
 From: 

 ml-node+s789695n4650500h51@.nabble

 To: 

 frespider@

 Subject: RE: Summary statistics for matrix columns
 
 
 
     HI,
 
 Is it possible to use as.matrix()?
 
 res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))
 
  res1-as.matrix(res)
 
  is.matrix(res1)
 
 #[1] TRUE
 
 res1[c(1:4,7,5,8,6),]
 
 #            Col1     Col2     Col3     Col4     Col5     Col6     Col7    
 Col8
 
 #Min.    10.0  1.0 17.0  3.0 18.0 11.0 13.0
 15.0
 
 #1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5
 34.75000
 
 #Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5
 51.5
 
 #Mean    42.5 42.75000 41.75000 35.75000 44.88000 26.88000 44.75000
 50.12000
 
 #sd      25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239
 25.51995
 
 #3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000
 70.5
 
 #IQR     43.0 29.0 24.0 55.5 14.25000 13.0 28.75000
 35.75000
 
 #Max.    74.0 77.0 76.0 70.0 65.0 63.0 79.0
 80.0
 
   #          Col9    Col10
 
 #Min.     2.0  6.0
 
 #1st Qu. 24.5 12.5
 
 #Median  33.5 48.0
 
 #Mean    34.88000 40.75000
 
 #sd      24.39811 28.21727
 
 #3rd Qu. 45.25000 63.0
 
 #IQR     20.75000 50.5
 
 #Max.    71.0 72.0
 
 Solves the order and the matrix output!
 
 A.K.
 
 
 
 
 
     
     
     
     
 
     
 
     
     
         If you reply to this email, your message will be added to the 
 discussion
 below:
     
 http://r.789695.n4.nabble.com/Summary-statistics-for-matrix-columns-tp4650489p4650500.html
     
     
         
         To unsubscribe from Summary statistics for matrix columns, click here.
 
         NAML

Then maybe 

x - matrix(sample(1:8000),nrow=100) 
colnames(x)- paste(Col,1:ncol(x),sep=) 

apply(x,2,function(x) c(Min=min(x), 
                        1st Qu =quantile(x, 0.25,names=FALSE), 
                        Median = quantile(x, 0.5, names=FALSE),
                        Mean= mean(x),
                        Sd=sd(x), 
                        3rd Qu = quantile(x,0.75,names=FALSE),
                        IQR=IQR(x),
                        Max = max(x)))

HTH

Pete



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Re: [R] Summary statistics for matrix columns

2012-11-23 Thread arun
Hi,
No problem.

There are a couple of other libraries which deal with summary statistics:
library(pastecs)
?stat.desc() # 

library(matrixStats) 
#Using the functions from package: matrixStats
fun1-function(x){
res-rbind(colMins(x),colQuantiles(x)[,2],colMedians(x),colMeans(x),colSds(x),colQuantiles(x)[,4],colIQRs(x),colMaxs(x))
row.names(res)-c(Min.,1st Qu.,Median,Mean,sd,3rd Qu.,IQR,Max.)
res}

set.seed(125)
x - matrix(sample(1:80),nrow=8)
colnames(x)- paste(Col,1:ncol(x),sep=)  
fun1(x)
#    Col1 Col2 Col3 Col4 Col5 Col6 Col7 Col8
#Min.    10.0  1.0 17.0  3.0 18.0 11.0 13.0 15.0
#1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5 34.75000
#Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5 51.5
#Mean    42.5 42.75000 41.75000 35.75000 44.87500 26.87500 44.75000 50.12500
#sd  25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239 25.51995
#3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000 70.5
#IQR 43.0 29.0 24.0 55.5 14.25000 13.0 28.75000 35.75000
#Max.    74.0 77.0 76.0 70.0 65.0 63.0 79.0 80.0
 #   Col9    Col10
#Min. 2.0  6.0
#1st Qu. 24.5 12.5
#Median  33.5 48.0
#Mean    34.87500 40.75000
#sd  24.39811 28.21727
#3rd Qu. 45.25000 63.0
#IQR 20.75000 50.5
#Max.    71.0 72.0

I thought this could be faster than the previous methods.  But, it was the 
slowest.

set.seed(125)
x1 - matrix(sample(1:80),nrow=1000)
colnames(x)- paste(Col,1:ncol(x1),sep=)

system.time(fun1(x1))
#   user  system elapsed 
 # 0.968   0.000   0.956 
A.K.









From: Fares Said frespi...@hotmail.com
To: arun smartpink...@yahoo.com 
Cc: Pete Brecknock peter.breckn...@bp.com; R help r-help@r-project.org 
Sent: Friday, November 23, 2012 10:23 AM
Subject: Re: [R] Summary statistics for matrix columns

Thank you all 

Sent from my iPhone

On 2012-11-23, at 10:19, arun smartpink...@yahoo.com wrote:

 HI,
 You are right.
 It is slower when compared to Pete's solution:
 set.seed(125)
 x - matrix(sample(1:80),nrow=1000)
 colnames(x)- paste(Col,1:ncol(x),sep=)
 
 system.time({
 res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))
  res1-as.matrix(res) 
 res2-res1[c(1:4,7,5,8,6),] })
 # user  system elapsed 
 #  0.596   0.000   0.597 
 
 system.time({
 res-apply(x,2,function(x) c(Min=min(x),
                         1st Qu =quantile(x, 0.25,names=FALSE),
                         Median = quantile(x, 0.5, names=FALSE),
                         Mean= mean(x),
                         Sd=sd(x),
                         3rd Qu = quantile(x,0.75,names=FALSE),
                         IQR=IQR(x),
                         Max = max(x))) })
 # user  system elapsed 
  # 0.384   0.000   0.384 
 
 
 A.K.
 
 
 
 - Original Message -
 From: Pete Brecknock peter.breckn...@bp.com
 To: r-help@r-project.org
 Cc: 
 Sent: Friday, November 23, 2012 8:42 AM
 Subject: Re: [R] Summary statistics for matrix columns
 
 frespider wrote
 Hi,
 
 it is possible. but don't you think it will slow the code if you convert
 to data.frame?
 
 Thanks 
 
 Date: Thu, 22 Nov 2012 18:31:35 -0800
 From:
 
 ml-node+s789695n4650500h51@.nabble
 
 To:
 
 frespider@
 
 Subject: RE: Summary statistics for matrix columns
 
 
 
     HI,
 
 Is it possible to use as.matrix()?
 
 res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))
 
   res1-as.matrix(res)
 
   is.matrix(res1)
 
 #[1] TRUE
 
 res1[c(1:4,7,5,8,6),]
 
 #            Col1     Col2     Col3     Col4     Col5     Col6     Col7    
 Col8
 
 #Min.    10.0  1.0 17.0  3.0 18.0 11.0 13.0
 15.0
 
 #1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5
 34.75000
 
 #Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5
 51.5
 
 #Mean    42.5 42.75000 41.75000 35.75000 44.88000 26.88000 44.75000
 50.12000
 
 #sd      25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239
 25.51995
 
 #3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000
 70.5
 
 #IQR     43.0 29.0 24.0 55.5 14.25000 13.0 28.75000
 35.75000
 
 #Max.    74.0 77.0 76.0 70.0 65.0 63.0 79.0
 80.0
 
    #          Col9    Col10
 
 #Min.     2.0  6.0
 
 #1st Qu. 24.5 12.5
 
 #Median  33.5 48.0
 
 #Mean    34.88000 40.75000
 
 #sd      24.39811 28.21727
 
 #3rd Qu. 45.25000 63.0
 
 #IQR     20.75000 50.5
 
 #Max.    71.0 72.0
 
 Solves the order and the matrix output!
 
 A.K.
 
 
 
 
 
    
    
    
    
 
    
 
    
    
         If you reply to this email, your message will be added to the 
discussion
 below:
    
 http://r.789695.n4.nabble.com/Summary-statistics-for-matrix-columns-tp4650489p4650500.html

Re: [R] Summary statistics for matrix columns

2012-11-22 Thread Pete Brecknock
frespider wrote
 Hi,
 
 is there a way I can calculate a summary statistics for a columns matrix
  let say we have this matrix 
 x - matrix(sample(1:8000),nrow=100)
 colnames(x)- paste(Col,1:ncol(x),sep=)
 
 if I used summary 
 summary(x) 
 
 i get the output for each column but I need the output to be in matrix
 with rownames  and all the columns beside it 
 
 this how I want it 
 
 Col76 Col77
  Min.  :739  
  1st Qu. :1846   1630   
  Median :   3631   3376   
  Mean:   3804   3617 
 Sd  :   
  3rd Qu.:5772   5544  
 IQR:
  Max.   :79527779  
 
 Is there an easy way?
 
 Thanks

How about ...

x - matrix(sample(1:8000),nrow=100)
colnames(x)- paste(Col,1:ncol(x),sep=)

apply(x,2,function(x) c(summary(x), sd=sd(x), IQR=IQR(x)))

HTH

Pete



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Re: [R] Summary statistics for matrix columns

2012-11-22 Thread frespider

I also don't like to use split function because I have like around 800 columns 

Date: Thu, 22 Nov 2012 18:08:54 -0800
From: ml-node+s789695n4650496...@n4.nabble.com
To: frespi...@hotmail.com
Subject: RE: Summary statistics for matrix columns

Hi,

How about this:

res-do.call(cbind,lapply(split(x,col(x)),function(x) 
c(summary(x),sd=sd(x),IQR=IQR(x

 colnames(res)-colnames(x)

 is.matrix(res)

[1] TRUE

 res

Col1 Col2 Col3 Col4 Col5 Col6 Col7 Col8

Min.10.0  1.0 17.0  3.0 18.0 11.0 13.0 15.0

1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5 34.75000

Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5 51.5

Mean42.5 42.75000 41.75000 35.75000 44.88000 26.88000 44.75000 50.12000

3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000 70.5

Max.74.0 77.0 76.0 70.0 65.0 63.0 79.0 80.0

sd  25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239 25.51995

IQR 43.0 29.0 24.0 55.5 14.25000 13.0 28.75000 35.75000

Col9Col10

Min. 2.0  6.0

1st Qu. 24.5 12.5

Median  33.5 48.0

Mean34.88000 40.75000

3rd Qu. 45.25000 63.0

Max.71.0 72.0

sd  24.39811 28.21727

IQR 20.75000 50.5

A.K.









If you reply to this email, your message will be added to the discussion below:
http://r.789695.n4.nabble.com/Summary-statistics-for-matrix-columns-tp4650489p4650496.html


This email was sent by arun kirshna (via Nabble)


  



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Re: [R] Summary statistics for matrix columns

2012-11-22 Thread frespider
Hi peter,

but this doesn't give me them in the order I want.

Is there a better approach 

Thanks 



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Re: [R] Summary statistics for matrix columns

2012-11-22 Thread frespider

There is still missing some statistics, 
like sd and IQR and I prefer the output to be matrix 

Thanks 

Date: Thu, 22 Nov 2012 18:00:20 -0800
From: ml-node+s789695n4650493...@n4.nabble.com
To: frespi...@hotmail.com
Subject: Re: Summary statistics for matrix columns



HI,

You could try this:

set.seed(125)

x - matrix(sample(1:80),nrow=8)

colnames(x)- paste(Col,1:ncol(x),sep=) 

 sapply(data.frame(x),function(x) summary(x))

# Col1  Col2  Col3  Col4  Col5  Col6  Col7  Col8  Col9 Col10

#Min.10.00  1.00 17.00  3.00 18.00 11.00 13.00 15.00  2.00  6.00

#1st Qu. 24.75 29.50 26.00  7.75 40.00 17.25 27.50 34.75 24.50 12.50

#Median  34.00 46.00 42.50 35.50 49.50 23.50 51.50 51.50 33.50 48.00

#Mean42.50 42.75 41.75 35.75 44.88 26.88 44.75 50.12 34.88 40.75

#3rd Qu. 67.75 58.50 50.00 63.25 54.25 30.25 56.25 70.50 45.25 63.00

#Max.74.00 77.00 76.00 70.00 65.00 63.00 79.00 80.00 71.00 72.00

A.K.










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click here.

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Re: [R] Summary statistics for matrix columns

2012-11-22 Thread frespider

HI,

but Sd and IQR not in the order I want ,

Thanks 

Date: Thu, 22 Nov 2012 18:08:57 -0800
From: ml-node+s789695n4650496...@n4.nabble.com
To: frespi...@hotmail.com
Subject: RE: Summary statistics for matrix columns



Hi,

How about this:

res-do.call(cbind,lapply(split(x,col(x)),function(x) 
c(summary(x),sd=sd(x),IQR=IQR(x

 colnames(res)-colnames(x)

 is.matrix(res)

[1] TRUE

 res

Col1 Col2 Col3 Col4 Col5 Col6 Col7 Col8

Min.10.0  1.0 17.0  3.0 18.0 11.0 13.0 15.0

1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5 34.75000

Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5 51.5

Mean42.5 42.75000 41.75000 35.75000 44.88000 26.88000 44.75000 50.12000

3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000 70.5

Max.74.0 77.0 76.0 70.0 65.0 63.0 79.0 80.0

sd  25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239 25.51995

IQR 43.0 29.0 24.0 55.5 14.25000 13.0 28.75000 35.75000

Col9Col10

Min. 2.0  6.0

1st Qu. 24.5 12.5

Median  33.5 48.0

Mean34.88000 40.75000

3rd Qu. 45.25000 63.0

Max.71.0 72.0

sd  24.39811 28.21727

IQR 20.75000 50.5

A.K.










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Re: [R] Summary statistics for matrix columns

2012-11-22 Thread frespider

Hi,

it is possible. but don't you think it will slow the code if you convert to 
data.frame?

Thanks 

Date: Thu, 22 Nov 2012 18:31:35 -0800
From: ml-node+s789695n4650500...@n4.nabble.com
To: frespi...@hotmail.com
Subject: RE: Summary statistics for matrix columns



HI,

Is it possible to use as.matrix()?

res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))

 res1-as.matrix(res)

 is.matrix(res1)

#[1] TRUE

res1[c(1:4,7,5,8,6),]

#Col1 Col2 Col3 Col4 Col5 Col6 Col7 Col8

#Min.10.0  1.0 17.0  3.0 18.0 11.0 13.0 15.0

#1st Qu. 24.75000 29.5 26.0  7.75000 40.0 17.25000 27.5 34.75000

#Median  34.0 46.0 42.5 35.5 49.5 23.5 51.5 51.5

#Mean42.5 42.75000 41.75000 35.75000 44.88000 26.88000 44.75000 50.12000

#sd  25.05993 27.77846 19.57221 28.40397 16.39196 16.60841 21.97239 25.51995

#3rd Qu. 67.75000 58.5 50.0 63.25000 54.25000 30.25000 56.25000 70.5

#IQR 43.0 29.0 24.0 55.5 14.25000 13.0 28.75000 35.75000

#Max.74.0 77.0 76.0 70.0 65.0 63.0 79.0 80.0

  #  Col9Col10

#Min. 2.0  6.0

#1st Qu. 24.5 12.5

#Median  33.5 48.0

#Mean34.88000 40.75000

#sd  24.39811 28.21727

#3rd Qu. 45.25000 63.0

#IQR 20.75000 50.5

#Max.71.0 72.0

Solves the order and the matrix output!

A.K.














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