?rle
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE: (360) 407-6815
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On Thu, 16 Oct 2014, daniel wrote:
Bart,
Check if the following could help you.
library(xts)
y - c(rnorm(10,25), rnorm(10,32),rnorm(10,25), rnorm(10,20),
rnorm(10,25)); x - seq(c(ISOdate(2000,3,20)), by = hour, length.out =
length(y))
z - xts( y, order.by=as.POSIXct(x))
limit - ifelse( lag(z) 22 | z 27, 1, 0)
Daniel Merino
2014-10-16 15:12 GMT-03:00 Bart Joosen bartjoo...@hotmail.com:
Hi,
I'm currently facing the problem that I need to write a function where I
get a dataframe back which contains the time (in hours) outside the limits
of a temperature sensor, each month, and for how long exactly.
I wrote a for loop which check:- if a datapoint is outside the limit- if
the previous datapoint is outside the limt, then count + 1- if the next
datapoint isn't outside: write in dataframe.
I guess this could be with some vectorisation function, I tried with
seq_along, and match, but couldn't figure it out.
Here some sample data:
y - c(rnorm(10,25), rnorm(10,32),rnorm(10,25), rnorm(10,20),
rnorm(10,25))x - seq(c(ISOdate(2000,3,20)), by = hour, length.out =
length(y))
limits of y: c(22,27)
Thanks
Bart
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Daniel
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