Re: [R] Updating a list.
That would be one source of error. Thank you.
Kevin
"ONKELINX wrote:
>
> Kevin,
>
> Notice the subtle difference between Hadley's and your code:
>
> Hadley
> m2008$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365)
>
> Kevin
> m2007$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365)
>
> Your are using the m2007 object instead of the suggested m2008 object!
>
> HTH,
>
> Thierry
>
>
>
>
>
> ir. Thierry Onkelinx
> Instituut voor natuur- en bosonderzoek / Research Institute for Nature
> and Forest
> Cel biometrie, methodologie en kwaliteitszorg / Section biometrics,
> methodology and quality assurance
> Gaverstraat 4
> 9500 Geraardsbergen
> Belgium
>
> tel. + 32 54/436 185
> [EMAIL PROTECTED]
>
> www.inbo.be
>
>
> To call in the statistician after the experiment is done may be no more
> than asking him to perform a post-mortem examination: he may be able to
> say what the experiment died of.
> ~ Sir Ronald Aylmer Fisher
>
> The plural of anecdote is not data.
> ~ Roger Brinner
>
> The combination of some data and an aching desire for an answer does not
> ensure that a reasonable answer can be extracted from a given body of
> data.
> ~ John Tukey
>
> -Oorspronkelijk bericht-
> Van: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
> Namens [EMAIL PROTECTED]
> Verzonden: donderdag 28 augustus 2008 3:14
> Aan: r-help@r-project.org
> Onderwerp: Re: [R] Updating a list.
>
> Since this didn't work:
>
> > m2007$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365)
> Error in `$<-.data.frame`(`*tmp*`, "DayOfYear", value = c(1L, 1L, 1L, :
>
> replacement has 432267 rows, data has 1592009
>
> Perhaps I need to clarify how the m2007 object was generated.
>
> t2007 <- read.csv("Total2007.dat", header = TRUE)
> m2007 <- melt(t2007,
> id.var=c("DayOfYear","Category","SubCategory","Sku"),
> measure.var=c("Quantity"))
>
> Kevin
>
>
> hadley wickham <[EMAIL PROTECTED]> wrote:
>
> >
>
> > Try this:
> >
>
> > m2008$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365)
> > r2007 <- cast(m2008, DayOfYear ~ variable | Sku, sum, fill = 0)
> >
>
> > Hadley
> >
>
> > --
>
> > http://had.co.nz/
>
> __
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
> Dit bericht en eventuele bijlagen geven enkel de visie van de schrijver weer
> en binden het INBO onder geen enkel beding, zolang dit bericht niet bevestigd
> is door een geldig ondertekend document.
> The views expressed in this message and any annex are purely those of the
> writer and may not be regarded as stating an official position of INBO, as
> long as the message is not confirmed by a duly signed document
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Re: [R] Updating a list.
Kevin,
Notice the subtle difference between Hadley's and your code:
Hadley
m2008$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365)
Kevin
m2007$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365)
Your are using the m2007 object instead of the suggested m2008 object!
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel biometrie, methodologie en kwaliteitszorg / Section biometrics,
methodology and quality assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium
tel. + 32 54/436 185
[EMAIL PROTECTED]
www.inbo.be
To call in the statistician after the experiment is done may be no more
than asking him to perform a post-mortem examination: he may be able to
say what the experiment died of.
~ Sir Ronald Aylmer Fisher
The plural of anecdote is not data.
~ Roger Brinner
The combination of some data and an aching desire for an answer does not
ensure that a reasonable answer can be extracted from a given body of
data.
~ John Tukey
-Oorspronkelijk bericht-
Van: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Namens [EMAIL PROTECTED]
Verzonden: donderdag 28 augustus 2008 3:14
Aan: r-help@r-project.org
Onderwerp: Re: [R] Updating a list.
Since this didn't work:
> m2007$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365)
Error in `$<-.data.frame`(`*tmp*`, "DayOfYear", value = c(1L, 1L, 1L, :
replacement has 432267 rows, data has 1592009
Perhaps I need to clarify how the m2007 object was generated.
t2007 <- read.csv("Total2007.dat", header = TRUE)
m2007 <- melt(t2007,
id.var=c("DayOfYear","Category","SubCategory","Sku"),
measure.var=c("Quantity"))
Kevin
hadley wickham <[EMAIL PROTECTED]> wrote:
>
> Try this:
>
> m2008$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365)
> r2007 <- cast(m2008, DayOfYear ~ variable | Sku, sum, fill = 0)
>
> Hadley
>
> --
> http://had.co.nz/
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Dit bericht en eventuele bijlagen geven enkel de visie van de schrijver weer en
binden het INBO onder geen enkel beding, zolang dit bericht niet bevestigd is
door een geldig ondertekend document.
The views expressed in this message and any annex are purely those of the
writer and may not be regarded as stating an official position of INBO, as long
as the message is not confirmed by a duly signed document
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Updating a list.
Since this didn't work:
> m2007$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365)
Error in `$<-.data.frame`(`*tmp*`, "DayOfYear", value = c(1L, 1L, 1L, :
replacement has 432267 rows, data has 1592009
Perhaps I need to clarify how the m2007 object was generated.
t2007 <- read.csv("Total2007.dat", header = TRUE)
m2007 <- melt(t2007, id.var=c("DayOfYear","Category","SubCategory","Sku"),
measure.var=c("Quantity"))
Kevin
hadley wickham <[EMAIL PROTECTED]> wrote:
>
> Try this:
>
> m2008$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365)
> r2007 <- cast(m2008, DayOfYear ~ variable | Sku, sum, fill = 0)
>
> Hadley
>
> --
> http://had.co.nz/
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Updating a list.
On Wed, Aug 27, 2008 at 6:18 PM, <[EMAIL PROTECTED]> wrote: > I have a list that is generated from the resape package function 'cast'. It > consists of three columns, Sku, DayOfYear, variable it is generated like: > > r2007 <- cast(m2008, DayOfYear ~ variable | Sku, sum) > > Now DayOfYear can range from 1:365 but there are not necessarily that many > rows in the list. What I want to do is make every row in the list of lenght > 365 and have the values correspond to the sum of the DayOfYear in the list if > present and 0 if not. For example the first item in the list looks like: > > $`100026` > DayOfYear Quantity > 1 31 > 2 301 > 31491 > 41561 > 5 3 1 > > Notice that there are not entires for each 'DayOfYear'. I would like to > replace list list maintaining the same data structure with something like: > > $`100026` > DayOfYear Quantity > 1 10 > 2 20 > 3 32 > 4 40 > Try this: m2008$DayOfYear <- factor(m2008$DayOfYear, levels = 1:365) r2007 <- cast(m2008, DayOfYear ~ variable | Sku, sum, fill = 0) Hadley -- http://had.co.nz/ __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
