Re: [R] applying ifelse to dataframe

2010-06-22 Thread steven mosher
Thanks, the dataframe, is indeed clever at preserving its dimensions.

I'll try your solution with the real data

On Tue, Jun 22, 2010 at 12:23 M, Petr PIKAL petr.pi...@precheza.cz wrote:

 Hi

 r-help-boun...@r-project.org napsal dne 22.06.2010 08:28:04:

  The following dataframe will illustrate the problem
 
 

 DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep
  (NA,10),x4=seq(20,29,by=1))
   DF$x3[5]-50
 
   # we have a data frame. we are interested in the columns x2,x3,x4 which
  contain sparse
   # values and many NA.
   DF
 name x1 x2 x3 x4
  1 1  A 10 NA 20
  2 1  A 11 NA 21
  3 2  A 12 NA 22
  4 2  A 13 NA 23
  5 3  A 14 50 24
  6 3  A 15 NA 25
  7 4  A 16 NA 26
  8 4  A 17 NA 27
  9 5  A 18 NA 28
  105  A 19 NA 29
 
  # we have a list of target values that we want to search for in the
 data
  frame
  # if the value is in the data frame we want to keep it there, otherwise,
   replace it with NA
 
  targets-c(11,12,13,16,19,50,27,24,22,26)
  # so we apply a test by column to the last 3 columns using the in test
  # this gives us a mask of whether the data frame 'contains' elements in
 the
  # target list
 
  mask-apply(DF[,3:5],2, %in% ,targets)
  mask
 
   x2x3x4
   [1,] FALSE FALSE FALSE
   [2,]  TRUE FALSE FALSE
   [3,]  TRUE FALSE  TRUE
   [4,]  TRUE FALSE FALSE
   [5,] FALSE  TRUE  TRUE
   [6,] FALSE FALSE FALSE
   [7,]  TRUE FALSE  TRUE
   [8,] FALSE FALSE  TRUE
   [9,] FALSE FALSE FALSE
  [10,]  TRUE FALSE FALSE
 
  # and so DF[2,3] is equal to 11 and 11 is in the target list, so the
 mask is
  True
  # now something like DF- ifelse(mask==T,DF,NA) is CONCEPTUALLY what I
 want

 Data frames are quite clever in preserving their dimensions. I would do

 mask=data.frame(a=TRUE, b=TRUE, !mask)

 to add column 1 and 2

 and

 DF[mask]-NA

 Regards
 Petr


  to do
  in the end I'd  Like a result that looks like
 
 name x1 x2 x3 x4
  1 1  A NA NA NA
  2 1  A 11 NA NA
  3 2  A 12 NA 22
  4 2  A 13 NANA
  5 3  A NA 50 24
  6 3  A NA NA NA
  7 4  A 16 NA 26
  8 4  A NA NA 27
  9 5  A NA NA NA
  105  A 19 NA NA
 
  Ive tried forcing the DF and the mask into vectors so that ifelse()
 would
  work
  and have tried apply using ifelse.. without much luck. any thoughts?
 
 [[alternative HTML version deleted]]
 
  __
  R-help@r-project.org mailing list
  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.



[[alternative HTML version deleted]]

__
R-help@r-project.org mailing list
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and provide commented, minimal, self-contained, reproducible code.


Re: [R] applying ifelse to dataframe

2010-06-22 Thread steven mosher
Hmm


DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep(NA,10),x4=seq(20,29,by=1))
  DF$x3[5]-50
 mask-apply(sample,2,%in%, target)
  DF
   name x1 x2 x3 x4
1 1  A 10 NA 20
2 1  A 11 NA 21
3 2  A 12 NA 22
4 2  A 13 NA 23
5 3  A 14 50 24
6 3  A 15 NA 25
7 4  A 16 NA 26
8 4  A 17 NA 27
9 5  A 18 NA 28
105  A 19 NA 29
  mask
  [,1]  [,2]  [,3]  [,4]  [,5]
[1,] FALSE FALSE FALSE FALSE FALSE
[2,] FALSE FALSE FALSE FALSE FALSE
[3,]  TRUE  TRUE FALSE  TRUE FALSE
[4,] FALSE FALSE FALSE FALSE FALSE
[5,]  TRUE FALSE FALSE FALSE FALSE
  mask-data.frame(a=TRUE,b=TRUE,!mask)
  DF[mask]-NA
Error in FUN(X[[1L]], ...) :
  only defined on a data frame with all numeric variables
  DF2-data.frame(DF[,3:5])
  mask-apply(sample,2,%in%, target)
  mask-data.frame(!mask)
  DF2[mask]-NA
Error in FUN(X[[1L]], ...) :
  only defined on a data frame with all numeric variables
  DF2
   x2 x3 x4
1  10 NA 20
2  11 NA 21
3  12 NA 22
4  13 NA 23
5  14 50 24
6  15 NA 25
7  16 NA 26
8  17 NA 27
9  18 NA 28
10 19 NA 29
  mask-apply(DF2,2,%in%, target)
  mask-data.frame(!mask)
  DF2[mask]-NA
Error in FUN(X[[1L]], ...) :
  only defined on a data frame with all numeric variables

On Tue, Jun 22, 2010 at 12:23 AM, Petr PIKAL petr.pi...@precheza.cz wrote:

 Hi

 r-help-boun...@r-project.org napsal dne 22.06.2010 08:28:04:

  The following dataframe will illustrate the problem
 
 

 DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep
  (NA,10),x4=seq(20,29,by=1))
   DF$x3[5]-50
 
   # we have a data frame. we are interested in the columns x2,x3,x4 which
  contain sparse
   # values and many NA.
   DF
 name x1 x2 x3 x4
  1 1  A 10 NA 20
  2 1  A 11 NA 21
  3 2  A 12 NA 22
  4 2  A 13 NA 23
  5 3  A 14 50 24
  6 3  A 15 NA 25
  7 4  A 16 NA 26
  8 4  A 17 NA 27
  9 5  A 18 NA 28
  105  A 19 NA 29
 
  # we have a list of target values that we want to search for in the
 data
  frame
  # if the value is in the data frame we want to keep it there, otherwise,
   replace it with NA
 
  targets-c(11,12,13,16,19,50,27,24,22,26)
  # so we apply a test by column to the last 3 columns using the in test
  # this gives us a mask of whether the data frame 'contains' elements in
 the
  # target list
 
  mask-apply(DF[,3:5],2, %in% ,targets)
  mask
 
   x2x3x4
   [1,] FALSE FALSE FALSE
   [2,]  TRUE FALSE FALSE
   [3,]  TRUE FALSE  TRUE
   [4,]  TRUE FALSE FALSE
   [5,] FALSE  TRUE  TRUE
   [6,] FALSE FALSE FALSE
   [7,]  TRUE FALSE  TRUE
   [8,] FALSE FALSE  TRUE
   [9,] FALSE FALSE FALSE
  [10,]  TRUE FALSE FALSE
 
  # and so DF[2,3] is equal to 11 and 11 is in the target list, so the
 mask is
  True
  # now something like DF- ifelse(mask==T,DF,NA) is CONCEPTUALLY what I
 want

 Data frames are quite clever in preserving their dimensions. I would do

 mask=data.frame(a=TRUE, b=TRUE, !mask)

 to add column 1 and 2

 and

 DF[mask]-NA

 Regards
 Petr


  to do
  in the end I'd  Like a result that looks like
 
 name x1 x2 x3 x4
  1 1  A NA NA NA
  2 1  A 11 NA NA
  3 2  A 12 NA 22
  4 2  A 13 NANA
  5 3  A NA 50 24
  6 3  A NA NA NA
  7 4  A 16 NA 26
  8 4  A NA NA 27
  9 5  A NA NA NA
  105  A 19 NA NA
 
  Ive tried forcing the DF and the mask into vectors so that ifelse()
 would
  work
  and have tried apply using ifelse.. without much luck. any thoughts?
 
 [[alternative HTML version deleted]]
 
  __
  R-help@r-project.org mailing list
  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.



[[alternative HTML version deleted]]

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] applying ifelse to dataframe

2010-06-22 Thread Petr PIKAL
OK

slight modification

DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep(NA,10),x4=seq(20,29,by=1))
DF$x3[5]-50
targets-c(11,12,13,16,19,50,27,24,22,26)
mask-apply(DF[,3:5],2, %in% ,targets)
mask-!mask
DF[,3:5][mask]-NA
DF
   name x1 x2 x3 x4
1 1  A NA NA NA
2 1  A 11 NA NA
3 2  A 12 NA 22
4 2  A 13 NA NA
5 3  A NA 50 24
6 3  A NA NA NA
7 4  A 16 NA 26
8 4  A NA NA 27
9 5  A NA NA NA
105  A 19 NA NA

Regards
Petr

steven mosher mosherste...@gmail.com napsal dne 22.06.2010 09:45:08:

 Hmm
 
  
DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep
 (NA,10),x4=seq(20,29,by=1))
   DF$x3[5]-50
  mask-apply(sample,2,%in%, target)
   DF
name x1 x2 x3 x4
 1 1  A 10 NA 20
 2 1  A 11 NA 21
 3 2  A 12 NA 22
 4 2  A 13 NA 23
 5 3  A 14 50 24
 6 3  A 15 NA 25
 7 4  A 16 NA 26
 8 4  A 17 NA 27
 9 5  A 18 NA 28
 105  A 19 NA 29
   mask
   [,1]  [,2]  [,3]  [,4]  [,5]
 [1,] FALSE FALSE FALSE FALSE FALSE
 [2,] FALSE FALSE FALSE FALSE FALSE
 [3,]  TRUE  TRUE FALSE  TRUE FALSE
 [4,] FALSE FALSE FALSE FALSE FALSE
 [5,]  TRUE FALSE FALSE FALSE FALSE
   mask-data.frame(a=TRUE,b=TRUE,!mask)
   DF[mask]-NA
 Error in FUN(X[[1L]], ...) : 
   only defined on a data frame with all numeric variables
   DF2-data.frame(DF[,3:5])
   mask-apply(sample,2,%in%, target)
   mask-data.frame(!mask)
   DF2[mask]-NA
 Error in FUN(X[[1L]], ...) : 
   only defined on a data frame with all numeric variables
   DF2
x2 x3 x4
 1  10 NA 20
 2  11 NA 21
 3  12 NA 22
 4  13 NA 23
 5  14 50 24
 6  15 NA 25
 7  16 NA 26
 8  17 NA 27
 9  18 NA 28
 10 19 NA 29
   mask-apply(DF2,2,%in%, target)
   mask-data.frame(!mask)
   DF2[mask]-NA
 Error in FUN(X[[1L]], ...) : 
   only defined on a data frame with all numeric variables
 
 On Tue, Jun 22, 2010 at 12:23 AM, Petr PIKAL petr.pi...@precheza.cz 
wrote:
 Hi
 
 r-help-boun...@r-project.org napsal dne 22.06.2010 08:28:04:
 
  The following dataframe will illustrate the problem
 
 
 
DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep
  (NA,10),x4=seq(20,29,by=1))
   DF$x3[5]-50
 
   # we have a data frame. we are interested in the columns x2,x3,x4 
which
  contain sparse
   # values and many NA.
   DF
 name x1 x2 x3 x4
  1 1  A 10 NA 20
  2 1  A 11 NA 21
  3 2  A 12 NA 22
  4 2  A 13 NA 23
  5 3  A 14 50 24
  6 3  A 15 NA 25
  7 4  A 16 NA 26
  8 4  A 17 NA 27
  9 5  A 18 NA 28
  105  A 19 NA 29
 
  # we have a list of target values that we want to search for in the
 data
  frame
  # if the value is in the data frame we want to keep it there, 
otherwise,
   replace it with NA
 
  targets-c(11,12,13,16,19,50,27,24,22,26)
  # so we apply a test by column to the last 3 columns using the in 
test
  # this gives us a mask of whether the data frame 'contains' elements 
in
 the
  # target list
 
  mask-apply(DF[,3:5],2, %in% ,targets)
  mask
 
   x2x3x4
   [1,] FALSE FALSE FALSE
   [2,]  TRUE FALSE FALSE
   [3,]  TRUE FALSE  TRUE
   [4,]  TRUE FALSE FALSE
   [5,] FALSE  TRUE  TRUE
   [6,] FALSE FALSE FALSE
   [7,]  TRUE FALSE  TRUE
   [8,] FALSE FALSE  TRUE
   [9,] FALSE FALSE FALSE
  [10,]  TRUE FALSE FALSE
 
  # and so DF[2,3] is equal to 11 and 11 is in the target list, so the
 mask is
  True
  # now something like DF- ifelse(mask==T,DF,NA) is CONCEPTUALLY what I
 want

 Data frames are quite clever in preserving their dimensions. I would do
 
 mask=data.frame(a=TRUE, b=TRUE, !mask)
 
 to add column 1 and 2
 
 and
 
 DF[mask]-NA
 
 Regards
 Petr
 
 
  to do
  in the end I'd  Like a result that looks like
 
 name x1 x2 x3 x4
  1 1  A NA NA NA
  2 1  A 11 NA NA
  3 2  A 12 NA 22
  4 2  A 13 NANA
  5 3  A NA 50 24
  6 3  A NA NA NA
  7 4  A 16 NA 26
  8 4  A NA NA 27
  9 5  A NA NA NA
  105  A 19 NA NA
 
  Ive tried forcing the DF and the mask into vectors so that ifelse()
 would
  work
  and have tried apply using ifelse.. without much luck. any thoughts?
 
 [[alternative HTML version deleted]]
 
  __
  R-help@r-project.org mailing list
  https://stat.ethz.ch/mailman/listinfo/r-help
  PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
  and provide commented, minimal, self-contained, reproducible code.

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] applying ifelse to dataframe

2010-06-22 Thread Peter Ehlers

On 2010-06-22 1:45, steven mosher wrote:

Hmm




DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep(NA,10),x4=seq(20,29,by=1))
   DF$x3[5]-50
  mask-apply(sample,2,%in%, target)


This is getting confusing. What's 'sample'?
What's 'target'? Probably what you originally called 'targets'.


   DF
name x1 x2 x3 x4
1 1  A 10 NA 20
2 1  A 11 NA 21
3 2  A 12 NA 22
4 2  A 13 NA 23
5 3  A 14 50 24
6 3  A 15 NA 25
7 4  A 16 NA 26
8 4  A 17 NA 27
9 5  A 18 NA 28
105  A 19 NA 29
   mask
   [,1]  [,2]  [,3]  [,4]  [,5]
[1,] FALSE FALSE FALSE FALSE FALSE
[2,] FALSE FALSE FALSE FALSE FALSE
[3,]  TRUE  TRUE FALSE  TRUE FALSE
[4,] FALSE FALSE FALSE FALSE FALSE
[5,]  TRUE FALSE FALSE FALSE FALSE



This suggests that 'sample' may be a matrix, not
a dataframe.

Anyway, try this on your original problem:

 targets-c(11,12,13,16,19,50,27,24,22,26)
 mask-apply(DF[,3:5],2, %in% ,targets)
 is.na(DF[3:5]) - !mask

  -Peter Ehlers


   mask-data.frame(a=TRUE,b=TRUE,!mask)
   DF[mask]-NA
Error in FUN(X[[1L]], ...) :
   only defined on a data frame with all numeric variables
   DF2-data.frame(DF[,3:5])
   mask-apply(sample,2,%in%, target)
   mask-data.frame(!mask)
   DF2[mask]-NA
Error in FUN(X[[1L]], ...) :
   only defined on a data frame with all numeric variables
   DF2
x2 x3 x4
1  10 NA 20
2  11 NA 21
3  12 NA 22
4  13 NA 23
5  14 50 24
6  15 NA 25
7  16 NA 26
8  17 NA 27
9  18 NA 28
10 19 NA 29
   mask-apply(DF2,2,%in%, target)
   mask-data.frame(!mask)
   DF2[mask]-NA
Error in FUN(X[[1L]], ...) :
   only defined on a data frame with all numeric variables

On Tue, Jun 22, 2010 at 12:23 AM, Petr PIKALpetr.pi...@precheza.cz  wrote:


Hi

r-help-boun...@r-project.org napsal dne 22.06.2010 08:28:04:


The following dataframe will illustrate the problem




DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep

(NA,10),x4=seq(20,29,by=1))
  DF$x3[5]-50

  # we have a data frame. we are interested in the columns x2,x3,x4 which
contain sparse
  # values and many NA.
  DF
name x1 x2 x3 x4
1 1  A 10 NA 20
2 1  A 11 NA 21
3 2  A 12 NA 22
4 2  A 13 NA 23
5 3  A 14 50 24
6 3  A 15 NA 25
7 4  A 16 NA 26
8 4  A 17 NA 27
9 5  A 18 NA 28
105  A 19 NA 29

# we have a list of target values that we want to search for in the

data

frame
# if the value is in the data frame we want to keep it there, otherwise,
  replace it with NA

targets-c(11,12,13,16,19,50,27,24,22,26)
# so we apply a test by column to the last 3 columns using the in test
# this gives us a mask of whether the data frame 'contains' elements in

the

# target list

mask-apply(DF[,3:5],2, %in% ,targets)
mask

  x2x3x4
  [1,] FALSE FALSE FALSE
  [2,]  TRUE FALSE FALSE
  [3,]  TRUE FALSE  TRUE
  [4,]  TRUE FALSE FALSE
  [5,] FALSE  TRUE  TRUE
  [6,] FALSE FALSE FALSE
  [7,]  TRUE FALSE  TRUE
  [8,] FALSE FALSE  TRUE
  [9,] FALSE FALSE FALSE
[10,]  TRUE FALSE FALSE

# and so DF[2,3] is equal to 11 and 11 is in the target list, so the

mask is

True
# now something like DF- ifelse(mask==T,DF,NA) is CONCEPTUALLY what I

want

Data frames are quite clever in preserving their dimensions. I would do

mask=data.frame(a=TRUE, b=TRUE, !mask)

to add column 1 and 2

and

DF[mask]-NA

Regards
Petr



to do
in the end I'd  Like a result that looks like

name x1 x2 x3 x4
1 1  A NA NA NA
2 1  A 11 NA NA
3 2  A 12 NA 22
4 2  A 13 NANA
5 3  A NA 50 24
6 3  A NA NA NA
7 4  A 16 NA 26
8 4  A NA NA 27
9 5  A NA NA NA
105  A 19 NA NA

Ive tried forcing the DF and the mask into vectors so that ifelse()

would

work
and have tried apply using ifelse.. without much luck. any thoughts?

[[alternative HTML version deleted]]

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide

http://www.R-project.org/posting-guide.html

and provide commented, minimal, self-contained, reproducible code.





__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] applying ifelse to dataframe

2010-06-22 Thread steven mosher
Thanks for the solution

On Tue, Jun 22, 2010 at 1:02 AM, Peter Ehlers ehl...@ucalgary.ca wrote:

 On 2010-06-22 1:45, steven mosher wrote:

 Hmm


 DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep(NA,10),x4=seq(20,29,by=1))
   DF$x3[5]-50
  mask-apply(sample,2,%in%, target)


 This is getting confusing. What's 'sample'?
 What's 'target'? Probably what you originally called 'targets'.


DF
name x1 x2 x3 x4
 1 1  A 10 NA 20
 2 1  A 11 NA 21
 3 2  A 12 NA 22
 4 2  A 13 NA 23
 5 3  A 14 50 24
 6 3  A 15 NA 25
 7 4  A 16 NA 26
 8 4  A 17 NA 27
 9 5  A 18 NA 28
 105  A 19 NA 29
   mask
   [,1]  [,2]  [,3]  [,4]  [,5]
 [1,] FALSE FALSE FALSE FALSE FALSE
 [2,] FALSE FALSE FALSE FALSE FALSE
 [3,]  TRUE  TRUE FALSE  TRUE FALSE
 [4,] FALSE FALSE FALSE FALSE FALSE
 [5,]  TRUE FALSE FALSE FALSE FALSE



 This suggests that 'sample' may be a matrix, not
 a dataframe.

 Anyway, try this on your original problem:


  targets-c(11,12,13,16,19,50,27,24,22,26)
  mask-apply(DF[,3:5],2, %in% ,targets)
  is.na(DF[3:5]) - !mask

  -Peter Ehlers


mask-data.frame(a=TRUE,b=TRUE,!mask)
   DF[mask]-NA
 Error in FUN(X[[1L]], ...) :
   only defined on a data frame with all numeric variables
   DF2-data.frame(DF[,3:5])
   mask-apply(sample,2,%in%, target)
   mask-data.frame(!mask)
   DF2[mask]-NA
 Error in FUN(X[[1L]], ...) :
   only defined on a data frame with all numeric variables
   DF2
x2 x3 x4
 1  10 NA 20
 2  11 NA 21
 3  12 NA 22
 4  13 NA 23
 5  14 50 24
 6  15 NA 25
 7  16 NA 26
 8  17 NA 27
 9  18 NA 28
 10 19 NA 29
   mask-apply(DF2,2,%in%, target)
   mask-data.frame(!mask)
   DF2[mask]-NA
 Error in FUN(X[[1L]], ...) :
   only defined on a data frame with all numeric variables

 On Tue, Jun 22, 2010 at 12:23 AM, Petr PIKALpetr.pi...@precheza.cz
  wrote:

  Hi

 r-help-boun...@r-project.org napsal dne 22.06.2010 08:28:04:

  The following dataframe will illustrate the problem




 DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep

 (NA,10),x4=seq(20,29,by=1))
  DF$x3[5]-50

  # we have a data frame. we are interested in the columns x2,x3,x4 which
 contain sparse
  # values and many NA.
  DF
name x1 x2 x3 x4
 1 1  A 10 NA 20
 2 1  A 11 NA 21
 3 2  A 12 NA 22
 4 2  A 13 NA 23
 5 3  A 14 50 24
 6 3  A 15 NA 25
 7 4  A 16 NA 26
 8 4  A 17 NA 27
 9 5  A 18 NA 28
 105  A 19 NA 29

 # we have a list of target values that we want to search for in the

 data

 frame
 # if the value is in the data frame we want to keep it there, otherwise,
  replace it with NA

 targets-c(11,12,13,16,19,50,27,24,22,26)
 # so we apply a test by column to the last 3 columns using the in test
 # this gives us a mask of whether the data frame 'contains' elements in

 the

 # target list

 mask-apply(DF[,3:5],2, %in% ,targets)
 mask

  x2x3x4
  [1,] FALSE FALSE FALSE
  [2,]  TRUE FALSE FALSE
  [3,]  TRUE FALSE  TRUE
  [4,]  TRUE FALSE FALSE
  [5,] FALSE  TRUE  TRUE
  [6,] FALSE FALSE FALSE
  [7,]  TRUE FALSE  TRUE
  [8,] FALSE FALSE  TRUE
  [9,] FALSE FALSE FALSE
 [10,]  TRUE FALSE FALSE

 # and so DF[2,3] is equal to 11 and 11 is in the target list, so the

 mask is

 True
 # now something like DF- ifelse(mask==T,DF,NA) is CONCEPTUALLY what I

 want

 Data frames are quite clever in preserving their dimensions. I would do

 mask=data.frame(a=TRUE, b=TRUE, !mask)

 to add column 1 and 2

 and

 DF[mask]-NA

 Regards
 Petr


  to do
 in the end I'd  Like a result that looks like

name x1 x2 x3 x4
 1 1  A NA NA NA
 2 1  A 11 NA NA
 3 2  A 12 NA 22
 4 2  A 13 NANA
 5 3  A NA 50 24
 6 3  A NA NA NA
 7 4  A 16 NA 26
 8 4  A NA NA 27
 9 5  A NA NA NA
 105  A 19 NA NA

 Ive tried forcing the DF and the mask into vectors so that ifelse()

 would

 work
 and have tried apply using ifelse.. without much luck. any thoughts?

[[alternative HTML version deleted]]

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide

 http://www.R-project.org/posting-guide.html

 and provide commented, minimal, self-contained, reproducible code.





[[alternative HTML version deleted]]

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.